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Who Wants To Be A Who Wants To Be A College Algebra College Algebra Millionaire? Millionaire?

Who Wants To Be A College Algebra Millionaire? Question 9 (Worth $1,000)

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Page 1: Who Wants To Be A College Algebra Millionaire? Question 9 (Worth $1,000)

Who Wants To Be A Who Wants To Be A College AlgebraCollege Algebra

Millionaire? Millionaire?

Page 2: Who Wants To Be A College Algebra Millionaire? Question 9 (Worth $1,000)

Question 9(Worth $1,000)

Page 3: Who Wants To Be A College Algebra Millionaire? Question 9 (Worth $1,000)

Find B + E.

9. B0 1 3

1 2 4

3 1 2

E

2 0 1

3 4 2

0 6 4

A 6B 3C 9D 20

BE 2 2 3

1 2 5

2 2 6

BE 2 1 2

2 2 2

3 5 6

BE 2 1 4

4 6 6

3 7 2

BE 0 0 3

3 8 8

0 6 8

Page 4: Who Wants To Be A College Algebra Millionaire? Question 9 (Worth $1,000)

A (B (C (D (

The Solution:

BE 2 1 2

2 2 2

3 5 6

9. B0 1 3

1 2 4

3 1 2

E

2 0 1

3 4 2

0 6 4

BE 2 2 3

1 2 5

2 2 6

BE 2 1 4

4 6 6

3 7 2

BE 0 0 3

3 8 8

0 6 8

Page 5: Who Wants To Be A College Algebra Millionaire? Question 9 (Worth $1,000)

$1,000

Page 6: Who Wants To Be A College Algebra Millionaire? Question 9 (Worth $1,000)

Question 11(Worth $2,000)

Page 7: Who Wants To Be A College Algebra Millionaire? Question 9 (Worth $1,000)

11. Find -2A.

A 6B 3C 9D 20

A2 1

1 3

4 3

2A 4 2

2 6

8 6

2A 4 2

2 6

8 6

2A0 3

3 1

2 5

2A 4 2 8

2 6 6

Page 8: Who Wants To Be A College Algebra Millionaire? Question 9 (Worth $1,000)

Solution -2A:

A 6B 3C 9D 20

2A 4 2

2 6

8 6

2A 4 2

2 6

8 6

2A0 3

3 1

2 5

2A 4 2 8

2 6 6

A2 1

1 3

4 3

Page 9: Who Wants To Be A College Algebra Millionaire? Question 9 (Worth $1,000)

$2,000

Page 10: Who Wants To Be A College Algebra Millionaire? Question 9 (Worth $1,000)

Question 12(Worth $4,000)

Page 11: Who Wants To Be A College Algebra Millionaire? Question 9 (Worth $1,000)

12. Find D - A.

A 3B 9C 1D 2

D5 2

1 3

A

2 1

1 3

4 3

Not Possible

D A3 1

0 6

D A12 11

1 8

D A 3 1

0 6

5 0

Page 12: Who Wants To Be A College Algebra Millionaire? Question 9 (Worth $1,000)

A 3B 9C 1D 2

D5 2

1 3

A

2 1

1 3

4 3

Solution D - A.

D A3 1

0 6

D A12 11

1 8

Not Possible

D A 3 1

0 6

5 0

Page 13: Who Wants To Be A College Algebra Millionaire? Question 9 (Worth $1,000)

$4,000

Page 14: Who Wants To Be A College Algebra Millionaire? Question 9 (Worth $1,000)

Question 14(Worth $8,000)

Page 15: Who Wants To Be A College Algebra Millionaire? Question 9 (Worth $1,000)

A -7B -13C -15D -17

14. Find |D|.

D5 2

1 3

Page 16: Who Wants To Be A College Algebra Millionaire? Question 9 (Worth $1,000)

A -7B -13C -15D -17

D5 2

1 3

Solution |D|.

15 2 17

Page 17: Who Wants To Be A College Algebra Millionaire? Question 9 (Worth $1,000)

$8,000

Page 18: Who Wants To Be A College Algebra Millionaire? Question 9 (Worth $1,000)

Question 15(Worth $16,000)

Page 19: Who Wants To Be A College Algebra Millionaire? Question 9 (Worth $1,000)

A 26B 24C 50D 74

15. Find |E|.

E 2 0 1

3 4 2

0 6 4

Page 20: Who Wants To Be A College Algebra Millionaire? Question 9 (Worth $1,000)

A 26B 24C 50D 74

E 2 0 1

3 4 2

0 6 4

2 0

3 4

0 6

(32018) (024 0)

50 24

26

15. Solution |E|.

Page 21: Who Wants To Be A College Algebra Millionaire? Question 9 (Worth $1,000)

$16,000

Page 22: Who Wants To Be A College Algebra Millionaire? Question 9 (Worth $1,000)

Question 17(Worth $32,000)

Page 23: Who Wants To Be A College Algebra Millionaire? Question 9 (Worth $1,000)

A (-17B (C (D (

17. Find D-

1.

D5 2

1 3

D 1 117

3 2

1 5

D 1 3 2

1 5

D 1 117

5 2

1 3

Page 24: Who Wants To Be A College Algebra Millionaire? Question 9 (Worth $1,000)

D5 2

1 3

17. Solution D-

1.

A (-17B (C (D (

D 1 3 2

1 5

D 1 117

3 2

1 5

D 1 117

5 2

1 3

D 15 2 17

NegateSwitch

Page 25: Who Wants To Be A College Algebra Millionaire? Question 9 (Worth $1,000)

$32,000

Page 26: Who Wants To Be A College Algebra Millionaire? Question 9 (Worth $1,000)

Question 10(Worth $64,000)

Page 27: Who Wants To Be A College Algebra Millionaire? Question 9 (Worth $1,000)

10. Find AC:

A .B .

C .D .

A 2 1

1 3

4 3

C

3 2 1

2 3 0

AC 8 7 2

9 11 1

18 17 4

AC 8 7

9 11

AC 8 9 18

7 11 17

2 1 4

AC 4 6

7 11

Page 28: Who Wants To Be A College Algebra Millionaire? Question 9 (Worth $1,000)

Solution AC:

A DB DC DD D

A 2 1

1 3

4 3

C

3 2 1

2 3 0

AC 4 6

7 11

AC 8 9 18

7 11 17

2 1 4

AC 8 7

9 11

AC 8 7 2

9 11 1

18 17 4

Page 29: Who Wants To Be A College Algebra Millionaire? Question 9 (Worth $1,000)

$64,000

Page 30: Who Wants To Be A College Algebra Millionaire? Question 9 (Worth $1,000)

Question 13(Worth $125,000)

Page 31: Who Wants To Be A College Algebra Millionaire? Question 9 (Worth $1,000)

A yB yC yD y

13. Find D2 + 2D:

D 5 2

1 3

D 37 8

4 5

D 27 4

2 11

D 10 4

2 6

D 35 0

1 3

Page 32: Who Wants To Be A College Algebra Millionaire? Question 9 (Worth $1,000)

A yB yC yD y

Solution D2 + 2D:

D 5 2

1 3

D 27 4

2 11

D 37 8

4 5

D 10 4

2 6

D 35 0

1 3

Page 33: Who Wants To Be A College Algebra Millionaire? Question 9 (Worth $1,000)

$125,000

Page 34: Who Wants To Be A College Algebra Millionaire? Question 9 (Worth $1,000)

Question 1(Worth $250,000)

Page 35: Who Wants To Be A College Algebra Millionaire? Question 9 (Worth $1,000)

A No IntersectionB (1,-3)C (-3,5) and (1, -3)D (3, 5) and (-1, -3)

1.Solve the system:

y + 4 = x2

2x + y = -1

Page 36: Who Wants To Be A College Algebra Millionaire? Question 9 (Worth $1,000)

A No IntersectionB (1,-3)C (-3,5) and (1, -3)D (3, 5) and (-1, -3)

1.Solve the system:

y + 4 = x2

2x + y = -1

Page 37: Who Wants To Be A College Algebra Millionaire? Question 9 (Worth $1,000)

$250,000

Page 38: Who Wants To Be A College Algebra Millionaire? Question 9 (Worth $1,000)

Question 2(Worth $500,000)

Page 39: Who Wants To Be A College Algebra Millionaire? Question 9 (Worth $1,000)

A No IntersectionB (4,3) and (3,4)C (-4,3) and (-3,4)D (4,-3) and (3,-4)

2. Solve the system:

x2 + y2 = 25x - y = 7

Page 40: Who Wants To Be A College Algebra Millionaire? Question 9 (Worth $1,000)

2. Solve the system:

x2 + y2 = 25 x - y = 7

A No IntersectionB (4,3) and (3,4)C (-4,3) and (-3,4)D (4,-3) and (3,-4)

Page 41: Who Wants To Be A College Algebra Millionaire? Question 9 (Worth $1,000)

$500,000

Page 42: Who Wants To Be A College Algebra Millionaire? Question 9 (Worth $1,000)

Question 19(Worth $1,000,000)

Page 43: Who Wants To Be A College Algebra Millionaire? Question 9 (Worth $1,000)

A 1B 1C 2D 2

19. Use Cramer’s Rule to solve the system:

5x - 6y = 4

3x + 7y = 8

7653

,2853

20

17,52

17

2053

,5253

76

17,28

17

Page 44: Who Wants To Be A College Algebra Millionaire? Question 9 (Worth $1,000)

19. Use Cramer’s Rule to solve the system:

5x - 6y = 4

3x + 7y = 8

A 1B 1C 2D 2

7653

,2853

20

17,52

17

2053

,5253

76

17,28

17

Page 45: Who Wants To Be A College Algebra Millionaire? Question 9 (Worth $1,000)

$1,000,000

Page 46: Who Wants To Be A College Algebra Millionaire? Question 9 (Worth $1,000)

Congratulations…Congratulations…You win!You win!