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International Journal of Mathematical Analysis Vol. 9, 2015, no. 33, 1645 - 1659
HIKARI Ltd, www.m-hikari.com
http://dx.doi.org/10.12988/ijma.2015.53106
Weighted Composition Operators
G. Balaji 1, C. V. Seshaiah 2, B. Vennila2 and K. Meenambika3
1 Thangavelu Engineering College
Chennai, Tamil Nadu, India
2 Sri Ramakrishna Engineering College
Coimbatore-641022, Tamil Nadu, India
3 Sengunthar Engineering College
Namakkal, Tamil Nadu, India
Copyright © 2015 G. Balaji et al. This article is distributed under the Creative Commons
Attribution License, which permits unrestricted use, distribution, and reproduction in any medium,
provided the original work is properly cited.
Abstract
Weighted composition operators have been related to products of
composition operators and their adjoints and to isometries of Hardy spaces. In this
paper, we identify the Hermitian weighted composition operators on H2 and
compute their spectral measures. Some relevant semigroups are studied. The
resulting ideas can be used to find the polar decomposition, the absolute value,
and the Aluthge transform of some composition operators on H2.
Mathematics Subject Classification: 39B52, 26A33
Keywords: The distributor function; Radon-Nikodym derivative; Non-atomic
measure; Lorentz space
1. Introduction
The purpose of this paper is to study the weighted composition operators:
S.C. Arora, G. Batt and S. Verma studies boundedness, compactness and closed-
ness of ranges of weighted composition operators on ,p qL .
In this paper, we study the weighted compositon operators on weighted
Bergman spaces of bounded symmetric domains. The necessary and sufficient
conditions for a weighted composition operator Wϕ,ψ to be bounded and compact
are studied by using the Carleson measure techniques.
1646 G. Balaji et al.
1.1: (Weighted Composition Operator)
Let , , be a - finite measurable space. Let :T be
measurable non – singular transformation and u be a complex – valued
measurable function defined on . The weighted composition operator induced
by u and T is defined by
,
, , , p q
u TW f x u x f T x for x f L (1.1)
1.1 Boundedness Theorem 1.1.1
Let , , be a - finite measurable space and :u a
measurable function. Let :T be a non – singular measurable
transformation such that the Randon - Nikodym derivative 1
Tf d T d is
in .L Suppose ,u L then the weighted composition operator
, : .u TW f u f T is bounded on , ,1 ,1p qL p q
Proof:
Suppose .Tb f
Then for f in , ,p qL consider the distribution function of
, .u TWf W f u f T
:Wf s x u x f Tx s
:x u f T x s
1 :T x u f x s
(1.2)
:Tf x u f x s
ub s
Therefore, for each 0,t we have
0 : 0 :f
fus s t b s s t
It follows that
*
inf 0 : fWf t s s t
inf 0 :f
s u s t b
inf 0 : :s x u f x s t b
inf 0 : :u s x f x s t b
*u f t b
For 1 ,1p q
Weighted composition operators 1647
*1
,
0
qq p
p q
dtWf t Wf t
t
*1
0
qp dt
t u f t bt
1 *
0
qq p dtu t f t b
t
,
q qq b
p qb u f
That is,
1
, ,
p
p q p qWf b u f
(1.3)
Therefore W is bounded for 1 ,p q
*1
,0
sup p
pt
Wf t Wf t
1 *
0
sup p
t
t u f t b
1
,
p
pb u f
(1.4)
It follows that W is also bounded.
The following example shows that u need not be bounded in order to have
a bounded weighted composite on operator , .u TW
Example 1.1.2
Let 0,1 2 , where 0,1 has the Lebesgue measure and 2 is an
atom with unit mass. Let 1u x x and 2T x for every .x Then u is
not bounded on 0,1 , but u and T define a bounded weighted composition
operator
,u T
f zW f u x f Tx
x on ' .L Notice
that , ,1u T u TW f W f d
1
20
2fd
x
1
1 12 2 2
2 2f f
where 1 denotes the norm of '.L
1648 G. Balaji et al.
Under some conditions on u and ,, u TT W is bounded and implied that
.u L
Theorem 1.1.3
Let , , be a finite measurable space. Let :u be a measurable
function and :T a non – singular measurable transformation such that
r rT E E for each 0,r where : .rE x u x r If ,u T is bounded on
, ,1 ,1 ,p qL p q then u L .
Proof:
Assume that ,u T is bounded i.e.,
, ,,u T p qp qf C f (1.5)
For all ,p qf L and some constant C.
If possible, suppose u is not in .L For each x . Let
:nE x u x x
Using the fact that ,n nT E E we have
1 ,
n nE T E
and
1: :
n nE x T E
x s x u x x ns
Therefore,
1
*
inf 0 : :E nn n
E T EW t s x u x x ns t
inf 0 : :nEn s x u x T x ns t
1inf 0 : :
nT En s x u x x ns t
inf 0 : :nEn s x x s t
* .nEn t
This gives,
,,
,n nE E
p qp qW x
which contradicts the boundedness of .
Therefore .u L
Weighted composition operators 1649
Conclusion
Theorem 1.1.4
Let , , be a finite measurable space and :u a measurable
function. Let :u be a non – singular measurable transformation such that
the Radon – Nikodym derivative 1
Tf d T d is in L and r rT E E
for each 0,r where :rE x u x r .
Then the weighted composition operator , :u TW f u f T is bounded on
, ,1 ,1p qL p q if and only if u L .
Proof:
Based on the previous theorems, all we need to do is to show that
u L implied the boundedness of ,u TW write sup : ,u u x x
and
consider,
:f s x u x f Tx s
:x u f Tx s
: /y f y s u
/f s u
Hence,
*
inf 0 : fWf t s s t
inf 0 : fs s u t
inf : fu s u s u t
*u f t
1
*1
,
0
p
p q
dtWf t Wf t
t
1
1 *
0
q
qp dt
t u f tt
,
.p q
u f
This implies that ,u T is bounded on , .p qL
1650 G. Balaji et al.
1.2 Compactness
Theorem 1.2.1
Let ,u TW W be a weighted composition operator on the Lorentz space
, ,p qL for 1 ,1 ,p q induced by a non – singular measurable
transformation T on and a measurable : .u C Decompose into two
disjoint sets 1 and 2 , where 1 does not possess any atom and 2 is a
countable union of atoms of finite measure. If is compact, then
,
,
0,n p q
n
n p q
W Ab x
A
(1.6)
Where nA are all the atoms of 2 with 0,nA for each x. If more
over, u is bounded below, we also have
1
1 0T
Proof:
To prove 0,nb assume to the contrary that nb 0, then without loss of
generality, there exists some 0 such that nb for all n. For each .n Let
,
,n
An
A
n
p q
fW
Then ,
,
,
n
An
Ap q
n p q
p q
fW
1
The sequence of nf is bounded sequence in ,p qL with an upper bound 1
.
However, ,
,
,
1An
An
p q
n p q
p q
W
WfW
.
Since nWf and mWf have supports with ,n m ,n m n m p q
Wf Wf Wf Wf .
Hence,
,
1 11
2 2n m n m m n p q
Wf Wf Wf Wf Wf Wf
, ,
1
2n m n mp q p q
Wf Wf Wf Wf
, , ,
1
2n m n m n mp q p q p q
Wf Wf Wf Wf Wf Wf
Weighted composition operators 1651
This means nWf does not admit any convergent subsequence with the
bounded sequence .nf It is a contradiction to the compactness of W. Therefore
0 as 0nb n .
Since, 1 ,T the Random – Nikodym derivative 1
Tf d T d satisfies
1 , for .T
E
T E f t d E (1.7)
If 1
1 0,T by (1.7), there exists some 1 such that the set
1 : 1TE x f x
has positive measure. Since 1 is non – atomic we can find a sequence nE of
measurable subsets of E such that 1 ,n nE E
, 0 .n n
aE a E
z
Let
,
n
n
E
n
Ep q
e
,
Then ne is a bounded sequence in , .p qL For , , let andm m N m n
be the lower bound of u , then for 0.t
*
n mWe We t
1inf 0 : : n ms x u x e Tx u x e Tx s t
1inf 0 : : n ms x e Tx e Tx s t
1inf 0 : :n n ms T y E e y e y s t
inf 0 : :n n ms y E e y e y s t
inf 0 : :n n ms y E e y e y s t
inf 0 : :n m n ms y E E e y e y s t
Using the same method in (2.11), we have,
*
*
,
(n m
n
E E
n m
Ep q
tWe We t
which implies
1652 G. Balaji et al.
1
*1
,
0
q
p
n m n mp q
dtWe We t We We t
t
1
1 *
0,
n m
n
q
qp
E E
Ep q
dtt t
t
1
1 *
0,
n m
n
p
E E
Ep q
d ss s
s
1 1
1 1
1 1p p
n m
p p
n
E E
E z
Thus nWe does not admit a convergent subsequence, which contradicts
the compactness of W. Hence 0Tf a e on 1 and
1
1
1 0TT f d
Hence 1
1 0T .
Condition (1.6) gives us a simple criteria for checking the non –
compactness of ,u TW in the following examples.
Example 1.2.2
Let , 1 and the measure on where it is the induced
Lebesgue measure on the interval ,1 and each n is an atom with mass
21 .
n
Define :T by if or 1,T x n x n x n n and :u
by 21u x
x for all .x Then the weighted composition operator
,u TW is
well – defined on ' .L Indeed for each 'f L ,
, 211
1n
u T
n N n
W f f x u x dx u nn
4
1 1
1n N
f nn n n
Now for each n,
, 4 211
1 1 1and
1u T n nW
n n n n
.
we have,
Weighted composition operators 1653
, 1
2
1
11
1
u T n
n
n
n n
So that
,u T is not compact.
Theorem 1.2.3:
Let ,u TW W be a weighted composition operator on the Lorentz space
,p qL u for 1 ,1 ,p q induced by a non – singular measurable
transformation T on and a measurable : :u
Decompose into two disjoint sets 1 2and where 1 does not
possess any atom and 2 is a countable union of atoms of finite measure. Then
is compact is the following statements are true:
(i) .u L
(ii) 1
1 0T
(iii)
1
0,n
n
n
T AC
A
where nA
are all the atoms of 2 with 0nA , for each n.
Proof:
Suppose 1
1 0T and 2 1 nnA
.
Let 1
n
N
n T An N
W f f A u
Then,
:
N
N
W W fx W W f x
1 :n n
n N
x T A f A u x
1 :n n
n N
x T A f A u
1
, n
n
n N f A u
T A
, n
n n
n N f A u
C A
,
sup ,n
n nn N n N n N f A u
C A
0
supn
n nn f A u
C A
sup .n fn N
C u
1654 G. Balaji et al.
Hence,
* sup 0 :N N
fW W f t W W t
sup 0 : sup n fn N
C u t
sup 0 : supf nn N
u u u t C
* sup n
n N
u f t C
and
1
*1
,0
N Np
p q
dtW W f t W W f t
t
1
,sup .
p
n p qn N
u C f
Equivalently,
1
sup 0 as 0.
pN
nn N
W W b N
Moreover, consider
:N
W N fx W f x
1 :n n
n N
x T A f A u x
1 :n n
n N
x T A f A u
1
, n
n
n N f A u
T A
, n
n n
n N f A u
C A
supn
n n
f A u
C A
sup .n fC u
for every N . Hence,
* sup 0 : N
N
fW f t t
sup 0 :sup n fC u t
sup 0 : supf nu u u t C
* sup nu f t C
,
and
Weighted composition operators 1655
1*
1
,0
N Np
p q
dtW f t W f t
t
1
1 *
0
sup
q
qp
n
dtt u f t C
t
1
1 *
0
sup
q
qp
n
dtu t f t C
t
1
,sup
p
n p qu C f
This implied
,p qN
W is bounded for every .N N Since W is the limit of
bounded finite rank operators ,
NW it is compact.
Observations:
1. Conditions (i) and (iii) are not necessary for the weighted composition operator
to be compact. For (i), see example 1.1.2. For (iii), consider the mapping on 'l
defined by .n nx x n It is a weighted composition operator with T the
identity function and u the function 1 .n x Since 1 ,T n n (iii) is clearly not
satisfied.
To see that W is compact, define 1 2 3, 2, 3,..., ,0,...N
n NW x x x x x N
Then
1
NN n
nl
n
xW x
n
1
N
n n ln
x x
.
Hence N
W is bounded. Moreover, consider
1
N N i
nl i
xW W x
N i
1
1 1 N i
i
N x
1
1 1 n
n
N x
1 1 n lN x
we have,
1 1 0.N
W W N
1656 G. Balaji et al.
Hence W is the limit of bounded finite rank operators and is therefore
compact.
2. Conditions (i) and (iii) together imply 0nb , where nb is the sequence in
Theorem 1.2.1
In fact,
,
,
nAp q
n
n p q
Wb
A
1
*1
0
11
n
p
A
pq
n
dtt u T t
t
p q A
11 1
11
pq
n
pq
n
u p q T A
p q A
11
p
n
n
T Au
A
1
0p
nu C
If (i) and (iii) hold.
1.3 Closedness of Ranges
Theorem 1.3.1
Let :T be a non – singular injective transformation such that the
Radon – Nikodym derivative 1
Tf d T d is in L and is bounded
below.
Let :u be a measurable function such that ,u TW is bounded and
injective on the Lorentz space , ,1 ,1 .p qL p q Then ,u TW has a
closed range if and only if there exists a 0 such that u x such that
.u x a e on : 0 ,S x u x the support of u.
Proof:
Suppose that ,u TW W has a closed range. Then there exists and 0
such that
, ,p q p q
Wf f (1.8)
for all ,p qf L
Choose 1
.p
fT
We claim that u x a e otherwise, there is a measurable subset
Weighted composition operators 1657
: 0F x u x such that
0 .F Let .E T F
Since T is non – singular, E too has positive measure. In fact, if 0,E
then by the non – singularity of 1, 0T F T E
Also 1
T
E
T E f d
T
E
f d
Tf E
Therefore,
,,E E T p qp q
W u
1
,T E
p q
u
1
,T E
p q
1
11
qpp
T Eq
1
1q
p
T
pf E
q
1
,
p
T E p qf
,E p q
This contradicts (1.8). Hence u x a e on S. Conversely if
u x a e on S, then for each ,E consider the norm of :E
W
,,E E p qp q
W u T
1
,T E
p q
u
1
,T E
p q
11 pq
T
E
pf d
q
1
1
'
q
ppE
q
1
,'
p
E p q
1658 G. Balaji et al.
Where ' is a lower bound of Tf . For each , ,p qf L using increasing
simple functions to approximate f. Then f satisfy, 1
, ,'
p
p q p qWf f as well.
Therefore ,u TW has a closed range.
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Received: April 1, 2015; Published: June 17, 2015