Upload
wesley-day
View
213
Download
0
Tags:
Embed Size (px)
Citation preview
Warm-UP
What do you think is happening to this cell
Homework10 Key IdeasSection 121
AP Test Money DUE NEXT FRIDAY 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Topicsbull Concept 131 What are the advantages to sexualasexual reproduction
What is the relationship between a gene a chromosome and DNA
bull Concept 132 What happens to a cell during meiosis Compare mitosis and meiosis Why bother doing meiosis
bull Concept 134 When is genetic diversity increased during meiosis How What is the advantage to this
bull Concept 141 How can we predict the offspring of parents using punnett squares (monohybrid dihybrid) Explain why some traits are dominant to others Explain how variation is increased due to independent assortment
bull Concept 142 Use probability laws to solve punnett squares predicting the outcomes of crosses where many traits are involved
bull Concept 143 Inheritance patterns are more complex that simple dominancerecessive incomplete dominance blood types codominance
bull Concept 144 Use a pedigree analysis of a family to make predictions about future offspring
bull Concept 151 What did Morgan tell us that Mendel couldnrsquot How do chromosomes explain Mendelrsquos 31 ratio
bull Concept 152 Explain how sex is determined Why do some diseases show in boys more often than girls
bull Concept 153 How do linked genes complicate Mendelrsquos findings
Essential Knowledge
bull 3a2 In eukaryotes heritable info is passed to the next generation via mitosis and meiosis
bull 3a3 The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from parent to offspring
bull 3a4 The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
bull 3c2 Biological systems have multiple processes that increase genetic variation
Unit 7 Inheritance
Big Idea In eukaryotic organisms heritable information is passed to the next generation via mitosis and meiosis which has multiple processes that increases genetic variation The inheritance pattern of many traits cannot be explained by simple Mendelian genetics The chromosomal basis of inheritance explains pattern of transmission of genes from parent to offspring
Time (seconds) Drawing Description025 ndash
030 ndash
035ndash
040 ndash
045 ndash
050-
In eukaryotic organisms heritable information is passed to the next generation via mitosis and meiosis
Chromosome Model
Materialsbull pipe cleanersbull beadsbull cotton ballsbull tapebull string
Procedure1 add 3-5 beads to a pipe cleaner to
model genes2 twist a 2nd pipe cleaner to the 1st to
model the double helix3 tie string to the beads to model
mRNA4 wrap the whole model around a
cotton ball to represent how DNA supercoils around histones in order to get smaller
5 replicate the 1st to model a sister chromatid
6 tape it to the 1st at about the middle to model the centromere
Chromosome Model
Procedure1 add 3-5 beads to a pipe cleaner
to model genes2 twist a 2nd pipe cleaner to the
1st to model the double helix3 tie string to the beads to model
mRNA transcribing DNA4 wrap the whole model around
a cotton ball to represent how DNA supercoils around histones in order to get smaller
5 replicate the 1st to model a sister chromatid
6 tape it to the 1st at about the middle to model the centromere
Partsbull chromosome tightly coiled DNAbull double helix DNA is 2 strands of
nucleotides twisted togetherbull gene small sections of DNA that
encode traitsbull histone proteins that DNA supercoils
around makes the DNA smaller so that it can fit in our cells
bull sister chromatid a duplicated copy of the original DNA still connected to the 1st
bull centromere the place where the 2 sister chromatids are connected (DNA Replication not quite finished)
bull mRNA copies of DNA that read genes
Chromosome Model
Materialsbull pipe cleanersbull beadsbull cotton ballsbull tape
Partsbull chromosome tightly coiled DNAbull double helix DNA is 2 strands of
nucleotides twisted togetherbull gene small sections of DNA that
encode traitsbull histone proteins that DNA
supercoils around makes the DNA smaller so that it can fit in our cells
bull sister chromatid a duplicated copy of the original DNA still connected to the 1st
bull centromere the place where the 2 sister chromatids are connected
bull mRNA copies of DNA that read genes
Chromosome Model
Materialsbull pipe cleanersbull beadsbull cotton ballsbull tape
Partsbull chromosome tightly coiled DNAbull double helix DNA is 2 strands of
nucleotides twisted togetherbull gene small sections of DNA that
encode traitsbull histone proteins that DNA
supercoils around makes the DNA smaller so that it can fit in our cells
bull sister chromatid a duplicated copy of the original DNA still connected to the 1st
bull centromere the place where the 2 sister chromatids are connected
bull mRNA copies of DNA that read genes
Chromosome Model
Materialsbull pipe cleanersbull beadsbull cotton ballsbull tape
Partsbull chromosome tightly coiled DNAbull double helix DNA is 2 strands of
nucleotides twisted togetherbull gene small sections of DNA that
encode traitsbull histone proteins that DNA
supercoils around makes the DNA smaller so that it can fit in our cells
bull sister chromatid a duplicated copy of the original DNA still connected to the 1st
bull centromere the place where the 2 sister chromatids are connected
bull mRNA copies of DNA that read genes
Warm-UP Can you ldquounwindrdquo your model like in the picture to show the parts Sketch and label your model (or the picture of the model) Labels histone mRNA DNA sister chromatid centromere
AP Test Money DUE 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework for Tonight Mitosis Worksheet
UNIT 78 TEST March 19th
Inheritance and Regulation
Due Now Stamp Sheet
Warm-UP
1 Is blowing up a balloon a good model for how cells or organisms grow Explain
2 In what ways are cells different than each other the same
AP Test Money DUE 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework for Tonight 122
UNIT 78 TEST March 19th
Inheritance and Regulation
AP Test Money DUE 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework for Tonight
Warm-UP
1 Is blowing up a balloon a good model for how cells or organisms grow Explain
2 In what ways are cells different than each other the same
AP Test Money DUE 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework for Tonight
Warm-UP
1 Is blowing up a balloon a good model for how cells or organisms grow Explain
2 In what ways are cells different than each other the same
AP Test Money DUE 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework for Tonight
Warm-UP
1 Is blowing up a balloon a good model for how cells or organisms grow Explain
2 In what ways are cells different than each other the same
In eukaryotic organisms heritable information is passed to the next generation via mitosis and
meiosis
Cell Division 2 Types Mitosis and Meiosis
Mitosisbull Purpose
growth repair asexual reproduction (actually
binary fission in prokaryotes)bull occurs after DNA replicationbull is followed by cytokinesisbull 2 genetically identical daughter cells
(clones)bull Steps
1 Replication2 Alignment3 Separation
1 Draw a big cell with a nucleus inside2 Add homologous pairs of chromosomes
ndash 1 big yellow 1 big whitendash 1 medium yellow 1 medium whitendash 1 small yellow 1 small white
3 Clone each chromosome (DNA Replication) (making sister chromatids)
4 Nucleus breaks down (erase it)5 Clones separate one to each side of cell6 Cytokinesis cell membrane grows between the 2
halves7 Nucleus grows around chromosomes
Mitosis Modeling
When yoursquore confident on the process show Mr Jones
bull When yoursquore confident on the process show Mr Jones
bull In your notebookTable 127 Stages of Mitosis p232At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid
Mitosis Modeling
Analysis
1 What is the outcome of mitosis2 What steps of mitosis ensure a perfect
outcome3 If the first cell has 46 chromosomes (before
cloning) how many does each daughter cell have
4 Why do cells go through mitosis
Mitosis Modeling
Words to Knowbull Nucleusbull DNAbull Histonesbull Chromatinbull Chromosomebull Chromatidbull Centromere
Copyright copy 2002 Pearson Education Inc publishing as Benjamin Cummings
Interphase ldquoSrdquo phase
Mitosis
Warm-UP
1Advantages of Sex
2Disadvantages of Sex
AP Test Money DUE 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Thurs Meiosis Wksht
UNIT 78 TEST March 19th
Inheritance and Regulation
Fig 13-2
Bacteria
Parent
Bud
05 mmAsexual Reproduction
Advantages1 Can be done in isolation2 If you are perfect why change
Best when an organism is ldquoperfectlyrdquo suited for its environment
3 Less ldquomachineryrdquo needed no waste on flowers ldquonewrdquo types of cells or other secondary sexual characteristics
Disadvantages1 Less variety Poor option in a
changing environmentPlants
Fig 13-2
Parent
Bud
05 mmAsexual Reproduction
Advantages1 Can be done in isolation2 If you are perfect why change
Best when an organism is ldquoperfectlyrdquo suited for its environment
3 Less ldquomachineryrdquo needed no waste on flowers ldquonewrdquo types of cells or other secondary sexual characteristics
Disadvantages1 Less variety Poor option in a
changing environment
Fig 13-2
Parent
Bud
05 mmAsexual Reproduction
Advantages1 Can be done in isolation2 If you are perfect why change
Best when an organism is ldquoperfectlyrdquo suited for its environment
3 Less ldquomachineryrdquo needed no waste on flowers ldquonewrdquo types of cells or other secondary sexual characteristics
Disadvantages1 Less variety Poor option in a
changing environment
Aspen
Fig 13-1
Sexual ReproductionAdvantages1 Increased variety Best when
environment is changing
Increased Variety is DUE TObull random fertilizationbull meiosis
bull independent assortmentbull crossing-over
Disadvantages1 Resource investment
bull specialized cells gametesbull secondary sexual
characteristics mate attraction2 Requires a partner (except when
plants self-fertilize)
In eukaryotic organisms heritable information is passed to the next generation via mitosis and
meiosisCell Division 2 Types
Meiosis sex cells (gametes) (spermeggs)bull Purpose
ensures that each gamete receives one complete haploid (1n) set of chromosomes
Ensures chromosome number stays the same each offspring receives frac12 (1n) of the full set for the species (2n)
bull Steps1 DNA Replication2 homologous pairs form a tetrad
(independent assortment) (genetic variation increases)
3 cross over between homologous chromosomes may occur (genetic variation increases)
4 Meiosis I homologous pairs separate5 Meiosis II sister chromatids separate
In eukaryotic organisms heritable information is passed to the next generation via mitosis and
meiosisCell Division 2 Types
Meiosis sex cells (gametes) (spermeggs)bull Purpose
ensures that each gamete receives one complete haploid (1n) set of chromosomes
Ensures chromosome number stays the same each offspring receives frac12 (1n) of the full set for the species (2n)
bull Steps1 DNA Replication2 homologous pairs form a tetrad
(independent assortment) (genetic variation increases)
3 cross over between homologous chromosomes may occur (genetic variation increases)
4 Meiosis I homologous pairs separate5 Meiosis II sister chromatids separate
In eukaryotic organisms heritable information is passed to the next generation via mitosis and
meiosisCell Division 2 Types
Meiosis sex cells (gametes) (spermeggs)bull Purpose
ensures that each gamete receives one complete haploid (1n) set of chromosomes
Ensures chromosome number stays the same each offspring receives frac12 (1n) of the full set for the species (2n)
bull Steps1 DNA Replication2 homologous pairs form a tetrad
(independent assortment) (genetic variation increases)
3 cross over between homologous chromosomes may occur (genetic variation increases)
4 Meiosis I homologous pairs separate5 Meiosis II sister chromatids separate
1 Build your diploid cell (an homologous pair for each chromosome)a Draw a big cell with a nucleus insideb Add homologous pairs of chromosomes
bull 1 big white 1 big yellowbull 1 medium white 1 medium yellowbull 1 small white 1 small yellow
2 Clone each chromosome (DNA Replication) (making sister chromatids)3 Nucleus breaks down (erase it)4 Homologous pairs form a tetrad crossing over may occur (note do not model crossing
over for now)5 Homologous pairs separate one to each side of cell all paternal (or all maternal) do NOT
have to go together (independent assortment)6 Cytokinesis cell membrane grows between the 2 halves7 Clones (sister chromatids) separate (centromere ldquobreaksrdquo as DNA polymerization
completes) one to each side of cell8 Cytokinesis cell membrane grows between the 2 halves9 Nucleus grows around chromosomes 4 cells made (gametes which have half the
number of chromosomes (haploids)
Meiosis Modeling
When yoursquore confident on the process show Mr Jones
Meiosis Modelingbull When yoursquore confident on the process show Mr Jones
bull In your notebookTable 138 Stages of Meiosis p255At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid crossing over recombinant chromosome independent assortment Meiosis I Meiosis II
Meiosis Modeling
Analysis
1 What is the outcome of meiosis2 What steps of meiosis cause variation3 If the first cell has 46 chromosomes (before
cloning) how many does each daughter cell have4 How many unique gametes did you form How
many could have formed5 Why do cells go through meiosis
Warm-UP 1 Why do meiosis2 How does meiosis increase variation in organisms
AP Test Money DUE 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Tomorrow Meiosis Wksht
UNIT 78 TEST March 19th
Inheritance and Regulation
Meiosis has multiple processes that increases genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Meiosis has multiple processes that increase genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Meiosis has multiple processes that increase genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Meiosis has multiple processes that increases genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Warm-UP Watch the video What is happening Why does this happen How does this increase variation
AP Test Money DUE TOMORROW 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Tomorrow
UNIT 78 TEST March 19th
Inheritance and Regulation
Fig 13-9a
MITOSIS MEIOSIS
MEIOSIS I
Prophase I
Chiasma
Chromosomereplication
Homologouschromosomepair
Chromosomereplication
2n = 6
Parent cell
Prophase
Replicated chromosome
Metaphase Metaphase I
Anaphase ITelophase I
Haploid n = 3
Daughter cells ofmeiosis I
MEIOSIS II
Daughter cells of meiosis II
nnnn
2n2n
Daughter cellsof mitosis
AnaphaseTelophase
Compare
Contrast
Independent Assortment
Crossing-over Sexual Fertilization Mutation
Types of Changes to Cells Think About what where when how how much variation created
Warm-UP Now we need to keep track of the genes on the chromosomes that are inherited Notice the letters on the chromosomes They represent different alleles for Huntingtons Barbie has Huntingtons What is the chance her child will get Huntingtons
AP Test Money DUE 36 TOMORROWRemember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Tomorrow 141 5 Key Ideas AND Concept Check 1-3
H=dominant (remember Huntingtonrsquos is dominant)
h=recessive (no Huntingtonrsquos)
Homework DUE Monday Test Corrections for 10 Make-UP
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
AP Test Money DUE 36 TODAYRemember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
DUE next Thursday Monohybrid Crosses
Homework DUE Monday Test Corrections for 10 Make-UP
Warm-UP Now we need to keep track of TWO UNLINKED genes on the chromosomes that are inherited Notice the letters on the chromosomes They represent different alleles for Huntingtons and red hair color Barbie has Huntingtons and is a blond (but a carrier) Ken does not have Huntingtonrsquos and is also a carrier for red hair What is the chance their child will get Huntingtons and red hair
Homework DUE Tomorrow 142 5 Key Ideas AND Concept Check 1-3
H= Huntingtonrsquosh=no HuntingtonrsquosR= no red hairr= red hair
DUE Now Test Corrections for 10 Make-UP
UNIT 78 TEST March 19th
Inheritance and Regulation
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
Homework DUE Tomorrow 143 5 Key Ideas AND Concept Check 1-3
DUE Now 142DUE Thursday Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
UNIT 78 TEST March 19th
Inheritance and Regulation
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoods
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with RrYy
1 Chance of baby with Rr 052 Chance of baby with Yy 053 Chance of baby with RrYy 025
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with both dominant phenotypes
1 Chance of baby with at least one R 0752 Chance of baby with at least one Y 0753 Chance of baby with RrYy 05625 (916)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with both dominant phenotypes
1 Chance of baby with at least one R 10
2 Chance of baby with at least one Y 10
3 Chance of baby with both dominant phenotypes 10
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
Homework DUE Tomorrow Linked vs Unlinked Genes AND Monohybrid Crosses to tunritincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with
vestigial wings and cinnabar eyes Predict the phenotypic ratio of the F2 individuals
Homework DUE Tomorrow 153 5 Key Ideas and Concept Check 1-3DUE Thursday Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with vestigial wings and cinnabar eyes Predict the
phenotypic ratio of the F2 individuals
3 The results of the cross from 2 show the following outcome Individuals of each phenotype are shown in the table Which of the following is the most likely explanation of the results a The two genes are located on two different chromosomes b The two genes are sex-linked c The two genes are located on mitochondrial DNA d The two genes are linked on an autosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
1 Build your diploid cell (an homologous pair for each chromosome)a Draw a big cell with a nucleus insideb DRAW homologous pairs of chromosomes
bull 1 big blue 1 big redbull 1 small blue 1 small red
ndash Add genes to your chromosomebull Write an H and an R on big blue and an h and an r on big redbull Write a T on small blue and a t on small red
2 Clone each chromosome (DNA Replication) (making sister chromatids)3 Nucleus breaks down (erase it)4 Homologous pairs form a tetrad crossing over may occur (note do not model
crossing over for now)5 Finish meiosis (see notes for help)6 Nucleus grows around chromosomes 4 cells made (gametes which have half
the number of chromosomes (haploids)7 Repeat Steps 1-6 this time at Step 4 include ONE crossover event
Recombination Modeling
When yoursquore confident on the process show Mr Jones
bull When yoursquore confident on the process show Mr Jones
bull In your notebookFigure 1510 Recombination p295At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid crossing over recombinant chromosome independent assortment Meiosis I Meiosis II
Recombination Modeling
Analysis
1 How does recombination increase the variety of gametes formed
2 Which types of gametes were more likely Gametes with recombinant chromosomes or ones without
3 Recombination is a random process How might it benefithurt the survival of an individualspecies
Recombination Modeling
Warm-UP
1 How could you calculate recombination frequency2 What would the recombination frequency tell you about the relative position of
genes on a chromosome3 Genes A B and C are on the same chromosome Testcrosses show that the
recombination frequency between A and B is 28 and between A and C is 12 Can you determine the linear order of these genes
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP What can we learn about inheritance from looking at a pedigree (use example of the Royal Family of Europe from the early 1900s)
Warm-UP In the following human pedigree squares represent males circles represent females and shaded symbols indicate individuals affected with a disorder One of the affected males from the third generation has a child with a female who is a carrier For the pedigree shown which of the following best expresses the probability that the couplersquos first son will be affected with the disorder
(A) 25 (B) 50 (C) 75 (D) 100
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Is a widowrsquos peak a dominant or recessive trait
Is a widowrsquos peak a dominant or recessive trait
Fig 14-UN5
George
Sandra Tom Sam
Arlene
Wilma Ann Michael
Carla
Daniel Alan Tina
Christopher
A heterozygous tall and a homozygous purple flowered plant is crossed with a short and white flowered plant Predict the offspring Assume independent assortment
1
P=purplep=whiteT=tallt=short
For a plant with the genotype WwXxYyZz what is the probability that the plant will produce a gamete with a haploid genotype of Wxyz Give your answer as a fraction or as a value between 0 and 1 to four decimal places
2
A completely-plated stickleback from a marine population was mated to a low-plated stickleback from a freshwater population The resulting F1 hybrids all displayed a completely plated phenotype When the F1 hybrids were allowed to interbreed the resulting F2 generation included completely plated offspring and low-plated offspring in an approximate 31 ratio Which of the following conclusions is best supported by the results of the breeding experiments
a Phenotypic variation in the F2 generation suggests that armor morphology is controlled by many alleles of a single gene
b The completely-plated phenotype is controlled by a dominant allele of a single gene
c Armor loss is an acquired characteristic that is affected by one or more environmental factors
d Patterns of armor plating in stickleback populations are regulated by sex-specific signals
3
If a man with type AB blood marries a woman with type O what blood types would you expect in their children What fraction would you expect of each type
4
IA= Type AIB= Type Bi= Type O
If a King marries a Queen that is a carrier of hemophilia (sex-linked recessive disease that is historically fatal before adulthood) what is the chance of the Kingdom having an heir to the kingrsquos throne assuming only one child is born
5
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
7 Gregor Mendelrsquos pioneering genetic experiments with pea plants occurred before the discovery of the structure and function of chromosomes Which of the following observations about inheritance in pea plants could be explained only after the discovery that genes may be linked on a chromosome
a Pea color and pea shape display independent inheritance patterns b Offspring of a given cross show all possible combinations of traits in
equal proportions c Most offspring of a given cross have a combination of traits that is
identical to that of either one parent or the other d Recessive phenotypes can skip a generation showing up only in the
parental and F 2 generations
8
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Based on the data in Table I which of the following best explains why there are no individuals with constricted pods in the F 1 generation a Inflated pod shape is dominant to constricted pod shape b The inflated-pod offspring in the F sub one generation are
homozygous c Constricted pod shape typically arises from a new mutation in the F 1
generation d The constricted-pod offspring are carriers for the inflated pod shape
allele
9
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table I the ratio of phenotypes in the offspring from the testcross with F 1 plants that had purple flowers and inflated pods suggests that the genes for flower color and pod shape are located a close together on the same autosome b on the X chromosome c on different chromosomes d on a mitochondrial chromosome
10
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Which of the following provides the best justification for an assumption that might have been used in the computer simulation (Table II) a The broad allele is recessive to the narrow allele because broad
leaves appear in every generation b The purple allele is dominant to the white allele because all the
offspring from the cross of purple-flowered and white-flowered plants had purple flowers
c The narrow allele is codominant with the purple allele because the purple-flower trait and the narrow-leaf trait segregate together
d The white allele is dominant to both the broad and narrow alleles because plants with either type of leaf shape can have white flowers
11
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table II the F 1 offspring of the cross between broad-leaved white-flowered plants with narrow-leaved purple-flowered plants have a phenotype that differs from that of either parent However many testcross offspring have the same phenotype as one of the two plants in the parental cross but relatively few testcross offspring have the same phenotype as the F 1 offspring Which of the following best explains the observation a Recombination between the leaf-shape and flower-color genes resulted in
chromosomes carrying a dominant allele of both genes b Recombination between the broad and narrow alleles of the leaf-shape gene resulted in
chromosomes carrying three different alleles at the same genetic locus c Independent assortment of homologous chromosomes resulted in the combinations of
alleles present in the parental generation d The computer model cannot capture the possible assortments of gametes when
multiple genes are considered
Topicsbull Concept 131 What are the advantages to sexualasexual reproduction
What is the relationship between a gene a chromosome and DNA
bull Concept 132 What happens to a cell during meiosis Compare mitosis and meiosis Why bother doing meiosis
bull Concept 134 When is genetic diversity increased during meiosis How What is the advantage to this
bull Concept 141 How can we predict the offspring of parents using punnett squares (monohybrid dihybrid) Explain why some traits are dominant to others Explain how variation is increased due to independent assortment
bull Concept 142 Use probability laws to solve punnett squares predicting the outcomes of crosses where many traits are involved
bull Concept 143 Inheritance patterns are more complex that simple dominancerecessive incomplete dominance blood types codominance
bull Concept 144 Use a pedigree analysis of a family to make predictions about future offspring
bull Concept 151 What did Morgan tell us that Mendel couldnrsquot How do chromosomes explain Mendelrsquos 31 ratio
bull Concept 152 Explain how sex is determined Why do some diseases show in boys more often than girls
bull Concept 153 How do linked genes complicate Mendelrsquos findings
Essential Knowledge
bull 3a2 In eukaryotes heritable info is passed to the next generation via mitosis and meiosis
bull 3a3 The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from parent to offspring
bull 3a4 The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
bull 3c2 Biological systems have multiple processes that increase genetic variation
Unit 7 Inheritance
Big Idea In eukaryotic organisms heritable information is passed to the next generation via mitosis and meiosis which has multiple processes that increases genetic variation The inheritance pattern of many traits cannot be explained by simple Mendelian genetics The chromosomal basis of inheritance explains pattern of transmission of genes from parent to offspring
Time (seconds) Drawing Description025 ndash
030 ndash
035ndash
040 ndash
045 ndash
050-
In eukaryotic organisms heritable information is passed to the next generation via mitosis and meiosis
Chromosome Model
Materialsbull pipe cleanersbull beadsbull cotton ballsbull tapebull string
Procedure1 add 3-5 beads to a pipe cleaner to
model genes2 twist a 2nd pipe cleaner to the 1st to
model the double helix3 tie string to the beads to model
mRNA4 wrap the whole model around a
cotton ball to represent how DNA supercoils around histones in order to get smaller
5 replicate the 1st to model a sister chromatid
6 tape it to the 1st at about the middle to model the centromere
Chromosome Model
Procedure1 add 3-5 beads to a pipe cleaner
to model genes2 twist a 2nd pipe cleaner to the
1st to model the double helix3 tie string to the beads to model
mRNA transcribing DNA4 wrap the whole model around
a cotton ball to represent how DNA supercoils around histones in order to get smaller
5 replicate the 1st to model a sister chromatid
6 tape it to the 1st at about the middle to model the centromere
Partsbull chromosome tightly coiled DNAbull double helix DNA is 2 strands of
nucleotides twisted togetherbull gene small sections of DNA that
encode traitsbull histone proteins that DNA supercoils
around makes the DNA smaller so that it can fit in our cells
bull sister chromatid a duplicated copy of the original DNA still connected to the 1st
bull centromere the place where the 2 sister chromatids are connected (DNA Replication not quite finished)
bull mRNA copies of DNA that read genes
Chromosome Model
Materialsbull pipe cleanersbull beadsbull cotton ballsbull tape
Partsbull chromosome tightly coiled DNAbull double helix DNA is 2 strands of
nucleotides twisted togetherbull gene small sections of DNA that
encode traitsbull histone proteins that DNA
supercoils around makes the DNA smaller so that it can fit in our cells
bull sister chromatid a duplicated copy of the original DNA still connected to the 1st
bull centromere the place where the 2 sister chromatids are connected
bull mRNA copies of DNA that read genes
Chromosome Model
Materialsbull pipe cleanersbull beadsbull cotton ballsbull tape
Partsbull chromosome tightly coiled DNAbull double helix DNA is 2 strands of
nucleotides twisted togetherbull gene small sections of DNA that
encode traitsbull histone proteins that DNA
supercoils around makes the DNA smaller so that it can fit in our cells
bull sister chromatid a duplicated copy of the original DNA still connected to the 1st
bull centromere the place where the 2 sister chromatids are connected
bull mRNA copies of DNA that read genes
Chromosome Model
Materialsbull pipe cleanersbull beadsbull cotton ballsbull tape
Partsbull chromosome tightly coiled DNAbull double helix DNA is 2 strands of
nucleotides twisted togetherbull gene small sections of DNA that
encode traitsbull histone proteins that DNA
supercoils around makes the DNA smaller so that it can fit in our cells
bull sister chromatid a duplicated copy of the original DNA still connected to the 1st
bull centromere the place where the 2 sister chromatids are connected
bull mRNA copies of DNA that read genes
Warm-UP Can you ldquounwindrdquo your model like in the picture to show the parts Sketch and label your model (or the picture of the model) Labels histone mRNA DNA sister chromatid centromere
AP Test Money DUE 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework for Tonight Mitosis Worksheet
UNIT 78 TEST March 19th
Inheritance and Regulation
Due Now Stamp Sheet
Warm-UP
1 Is blowing up a balloon a good model for how cells or organisms grow Explain
2 In what ways are cells different than each other the same
AP Test Money DUE 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework for Tonight 122
UNIT 78 TEST March 19th
Inheritance and Regulation
AP Test Money DUE 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework for Tonight
Warm-UP
1 Is blowing up a balloon a good model for how cells or organisms grow Explain
2 In what ways are cells different than each other the same
AP Test Money DUE 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework for Tonight
Warm-UP
1 Is blowing up a balloon a good model for how cells or organisms grow Explain
2 In what ways are cells different than each other the same
AP Test Money DUE 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework for Tonight
Warm-UP
1 Is blowing up a balloon a good model for how cells or organisms grow Explain
2 In what ways are cells different than each other the same
In eukaryotic organisms heritable information is passed to the next generation via mitosis and
meiosis
Cell Division 2 Types Mitosis and Meiosis
Mitosisbull Purpose
growth repair asexual reproduction (actually
binary fission in prokaryotes)bull occurs after DNA replicationbull is followed by cytokinesisbull 2 genetically identical daughter cells
(clones)bull Steps
1 Replication2 Alignment3 Separation
1 Draw a big cell with a nucleus inside2 Add homologous pairs of chromosomes
ndash 1 big yellow 1 big whitendash 1 medium yellow 1 medium whitendash 1 small yellow 1 small white
3 Clone each chromosome (DNA Replication) (making sister chromatids)
4 Nucleus breaks down (erase it)5 Clones separate one to each side of cell6 Cytokinesis cell membrane grows between the 2
halves7 Nucleus grows around chromosomes
Mitosis Modeling
When yoursquore confident on the process show Mr Jones
bull When yoursquore confident on the process show Mr Jones
bull In your notebookTable 127 Stages of Mitosis p232At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid
Mitosis Modeling
Analysis
1 What is the outcome of mitosis2 What steps of mitosis ensure a perfect
outcome3 If the first cell has 46 chromosomes (before
cloning) how many does each daughter cell have
4 Why do cells go through mitosis
Mitosis Modeling
Words to Knowbull Nucleusbull DNAbull Histonesbull Chromatinbull Chromosomebull Chromatidbull Centromere
Copyright copy 2002 Pearson Education Inc publishing as Benjamin Cummings
Interphase ldquoSrdquo phase
Mitosis
Warm-UP
1Advantages of Sex
2Disadvantages of Sex
AP Test Money DUE 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Thurs Meiosis Wksht
UNIT 78 TEST March 19th
Inheritance and Regulation
Fig 13-2
Bacteria
Parent
Bud
05 mmAsexual Reproduction
Advantages1 Can be done in isolation2 If you are perfect why change
Best when an organism is ldquoperfectlyrdquo suited for its environment
3 Less ldquomachineryrdquo needed no waste on flowers ldquonewrdquo types of cells or other secondary sexual characteristics
Disadvantages1 Less variety Poor option in a
changing environmentPlants
Fig 13-2
Parent
Bud
05 mmAsexual Reproduction
Advantages1 Can be done in isolation2 If you are perfect why change
Best when an organism is ldquoperfectlyrdquo suited for its environment
3 Less ldquomachineryrdquo needed no waste on flowers ldquonewrdquo types of cells or other secondary sexual characteristics
Disadvantages1 Less variety Poor option in a
changing environment
Fig 13-2
Parent
Bud
05 mmAsexual Reproduction
Advantages1 Can be done in isolation2 If you are perfect why change
Best when an organism is ldquoperfectlyrdquo suited for its environment
3 Less ldquomachineryrdquo needed no waste on flowers ldquonewrdquo types of cells or other secondary sexual characteristics
Disadvantages1 Less variety Poor option in a
changing environment
Aspen
Fig 13-1
Sexual ReproductionAdvantages1 Increased variety Best when
environment is changing
Increased Variety is DUE TObull random fertilizationbull meiosis
bull independent assortmentbull crossing-over
Disadvantages1 Resource investment
bull specialized cells gametesbull secondary sexual
characteristics mate attraction2 Requires a partner (except when
plants self-fertilize)
In eukaryotic organisms heritable information is passed to the next generation via mitosis and
meiosisCell Division 2 Types
Meiosis sex cells (gametes) (spermeggs)bull Purpose
ensures that each gamete receives one complete haploid (1n) set of chromosomes
Ensures chromosome number stays the same each offspring receives frac12 (1n) of the full set for the species (2n)
bull Steps1 DNA Replication2 homologous pairs form a tetrad
(independent assortment) (genetic variation increases)
3 cross over between homologous chromosomes may occur (genetic variation increases)
4 Meiosis I homologous pairs separate5 Meiosis II sister chromatids separate
In eukaryotic organisms heritable information is passed to the next generation via mitosis and
meiosisCell Division 2 Types
Meiosis sex cells (gametes) (spermeggs)bull Purpose
ensures that each gamete receives one complete haploid (1n) set of chromosomes
Ensures chromosome number stays the same each offspring receives frac12 (1n) of the full set for the species (2n)
bull Steps1 DNA Replication2 homologous pairs form a tetrad
(independent assortment) (genetic variation increases)
3 cross over between homologous chromosomes may occur (genetic variation increases)
4 Meiosis I homologous pairs separate5 Meiosis II sister chromatids separate
In eukaryotic organisms heritable information is passed to the next generation via mitosis and
meiosisCell Division 2 Types
Meiosis sex cells (gametes) (spermeggs)bull Purpose
ensures that each gamete receives one complete haploid (1n) set of chromosomes
Ensures chromosome number stays the same each offspring receives frac12 (1n) of the full set for the species (2n)
bull Steps1 DNA Replication2 homologous pairs form a tetrad
(independent assortment) (genetic variation increases)
3 cross over between homologous chromosomes may occur (genetic variation increases)
4 Meiosis I homologous pairs separate5 Meiosis II sister chromatids separate
1 Build your diploid cell (an homologous pair for each chromosome)a Draw a big cell with a nucleus insideb Add homologous pairs of chromosomes
bull 1 big white 1 big yellowbull 1 medium white 1 medium yellowbull 1 small white 1 small yellow
2 Clone each chromosome (DNA Replication) (making sister chromatids)3 Nucleus breaks down (erase it)4 Homologous pairs form a tetrad crossing over may occur (note do not model crossing
over for now)5 Homologous pairs separate one to each side of cell all paternal (or all maternal) do NOT
have to go together (independent assortment)6 Cytokinesis cell membrane grows between the 2 halves7 Clones (sister chromatids) separate (centromere ldquobreaksrdquo as DNA polymerization
completes) one to each side of cell8 Cytokinesis cell membrane grows between the 2 halves9 Nucleus grows around chromosomes 4 cells made (gametes which have half the
number of chromosomes (haploids)
Meiosis Modeling
When yoursquore confident on the process show Mr Jones
Meiosis Modelingbull When yoursquore confident on the process show Mr Jones
bull In your notebookTable 138 Stages of Meiosis p255At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid crossing over recombinant chromosome independent assortment Meiosis I Meiosis II
Meiosis Modeling
Analysis
1 What is the outcome of meiosis2 What steps of meiosis cause variation3 If the first cell has 46 chromosomes (before
cloning) how many does each daughter cell have4 How many unique gametes did you form How
many could have formed5 Why do cells go through meiosis
Warm-UP 1 Why do meiosis2 How does meiosis increase variation in organisms
AP Test Money DUE 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Tomorrow Meiosis Wksht
UNIT 78 TEST March 19th
Inheritance and Regulation
Meiosis has multiple processes that increases genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Meiosis has multiple processes that increase genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Meiosis has multiple processes that increase genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Meiosis has multiple processes that increases genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Warm-UP Watch the video What is happening Why does this happen How does this increase variation
AP Test Money DUE TOMORROW 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Tomorrow
UNIT 78 TEST March 19th
Inheritance and Regulation
Fig 13-9a
MITOSIS MEIOSIS
MEIOSIS I
Prophase I
Chiasma
Chromosomereplication
Homologouschromosomepair
Chromosomereplication
2n = 6
Parent cell
Prophase
Replicated chromosome
Metaphase Metaphase I
Anaphase ITelophase I
Haploid n = 3
Daughter cells ofmeiosis I
MEIOSIS II
Daughter cells of meiosis II
nnnn
2n2n
Daughter cellsof mitosis
AnaphaseTelophase
Compare
Contrast
Independent Assortment
Crossing-over Sexual Fertilization Mutation
Types of Changes to Cells Think About what where when how how much variation created
Warm-UP Now we need to keep track of the genes on the chromosomes that are inherited Notice the letters on the chromosomes They represent different alleles for Huntingtons Barbie has Huntingtons What is the chance her child will get Huntingtons
AP Test Money DUE 36 TOMORROWRemember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Tomorrow 141 5 Key Ideas AND Concept Check 1-3
H=dominant (remember Huntingtonrsquos is dominant)
h=recessive (no Huntingtonrsquos)
Homework DUE Monday Test Corrections for 10 Make-UP
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
AP Test Money DUE 36 TODAYRemember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
DUE next Thursday Monohybrid Crosses
Homework DUE Monday Test Corrections for 10 Make-UP
Warm-UP Now we need to keep track of TWO UNLINKED genes on the chromosomes that are inherited Notice the letters on the chromosomes They represent different alleles for Huntingtons and red hair color Barbie has Huntingtons and is a blond (but a carrier) Ken does not have Huntingtonrsquos and is also a carrier for red hair What is the chance their child will get Huntingtons and red hair
Homework DUE Tomorrow 142 5 Key Ideas AND Concept Check 1-3
H= Huntingtonrsquosh=no HuntingtonrsquosR= no red hairr= red hair
DUE Now Test Corrections for 10 Make-UP
UNIT 78 TEST March 19th
Inheritance and Regulation
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
Homework DUE Tomorrow 143 5 Key Ideas AND Concept Check 1-3
DUE Now 142DUE Thursday Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
UNIT 78 TEST March 19th
Inheritance and Regulation
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoods
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with RrYy
1 Chance of baby with Rr 052 Chance of baby with Yy 053 Chance of baby with RrYy 025
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with both dominant phenotypes
1 Chance of baby with at least one R 0752 Chance of baby with at least one Y 0753 Chance of baby with RrYy 05625 (916)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with both dominant phenotypes
1 Chance of baby with at least one R 10
2 Chance of baby with at least one Y 10
3 Chance of baby with both dominant phenotypes 10
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
Homework DUE Tomorrow Linked vs Unlinked Genes AND Monohybrid Crosses to tunritincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with
vestigial wings and cinnabar eyes Predict the phenotypic ratio of the F2 individuals
Homework DUE Tomorrow 153 5 Key Ideas and Concept Check 1-3DUE Thursday Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with vestigial wings and cinnabar eyes Predict the
phenotypic ratio of the F2 individuals
3 The results of the cross from 2 show the following outcome Individuals of each phenotype are shown in the table Which of the following is the most likely explanation of the results a The two genes are located on two different chromosomes b The two genes are sex-linked c The two genes are located on mitochondrial DNA d The two genes are linked on an autosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
1 Build your diploid cell (an homologous pair for each chromosome)a Draw a big cell with a nucleus insideb DRAW homologous pairs of chromosomes
bull 1 big blue 1 big redbull 1 small blue 1 small red
ndash Add genes to your chromosomebull Write an H and an R on big blue and an h and an r on big redbull Write a T on small blue and a t on small red
2 Clone each chromosome (DNA Replication) (making sister chromatids)3 Nucleus breaks down (erase it)4 Homologous pairs form a tetrad crossing over may occur (note do not model
crossing over for now)5 Finish meiosis (see notes for help)6 Nucleus grows around chromosomes 4 cells made (gametes which have half
the number of chromosomes (haploids)7 Repeat Steps 1-6 this time at Step 4 include ONE crossover event
Recombination Modeling
When yoursquore confident on the process show Mr Jones
bull When yoursquore confident on the process show Mr Jones
bull In your notebookFigure 1510 Recombination p295At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid crossing over recombinant chromosome independent assortment Meiosis I Meiosis II
Recombination Modeling
Analysis
1 How does recombination increase the variety of gametes formed
2 Which types of gametes were more likely Gametes with recombinant chromosomes or ones without
3 Recombination is a random process How might it benefithurt the survival of an individualspecies
Recombination Modeling
Warm-UP
1 How could you calculate recombination frequency2 What would the recombination frequency tell you about the relative position of
genes on a chromosome3 Genes A B and C are on the same chromosome Testcrosses show that the
recombination frequency between A and B is 28 and between A and C is 12 Can you determine the linear order of these genes
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP What can we learn about inheritance from looking at a pedigree (use example of the Royal Family of Europe from the early 1900s)
Warm-UP In the following human pedigree squares represent males circles represent females and shaded symbols indicate individuals affected with a disorder One of the affected males from the third generation has a child with a female who is a carrier For the pedigree shown which of the following best expresses the probability that the couplersquos first son will be affected with the disorder
(A) 25 (B) 50 (C) 75 (D) 100
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Is a widowrsquos peak a dominant or recessive trait
Is a widowrsquos peak a dominant or recessive trait
Fig 14-UN5
George
Sandra Tom Sam
Arlene
Wilma Ann Michael
Carla
Daniel Alan Tina
Christopher
A heterozygous tall and a homozygous purple flowered plant is crossed with a short and white flowered plant Predict the offspring Assume independent assortment
1
P=purplep=whiteT=tallt=short
For a plant with the genotype WwXxYyZz what is the probability that the plant will produce a gamete with a haploid genotype of Wxyz Give your answer as a fraction or as a value between 0 and 1 to four decimal places
2
A completely-plated stickleback from a marine population was mated to a low-plated stickleback from a freshwater population The resulting F1 hybrids all displayed a completely plated phenotype When the F1 hybrids were allowed to interbreed the resulting F2 generation included completely plated offspring and low-plated offspring in an approximate 31 ratio Which of the following conclusions is best supported by the results of the breeding experiments
a Phenotypic variation in the F2 generation suggests that armor morphology is controlled by many alleles of a single gene
b The completely-plated phenotype is controlled by a dominant allele of a single gene
c Armor loss is an acquired characteristic that is affected by one or more environmental factors
d Patterns of armor plating in stickleback populations are regulated by sex-specific signals
3
If a man with type AB blood marries a woman with type O what blood types would you expect in their children What fraction would you expect of each type
4
IA= Type AIB= Type Bi= Type O
If a King marries a Queen that is a carrier of hemophilia (sex-linked recessive disease that is historically fatal before adulthood) what is the chance of the Kingdom having an heir to the kingrsquos throne assuming only one child is born
5
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
7 Gregor Mendelrsquos pioneering genetic experiments with pea plants occurred before the discovery of the structure and function of chromosomes Which of the following observations about inheritance in pea plants could be explained only after the discovery that genes may be linked on a chromosome
a Pea color and pea shape display independent inheritance patterns b Offspring of a given cross show all possible combinations of traits in
equal proportions c Most offspring of a given cross have a combination of traits that is
identical to that of either one parent or the other d Recessive phenotypes can skip a generation showing up only in the
parental and F 2 generations
8
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Based on the data in Table I which of the following best explains why there are no individuals with constricted pods in the F 1 generation a Inflated pod shape is dominant to constricted pod shape b The inflated-pod offspring in the F sub one generation are
homozygous c Constricted pod shape typically arises from a new mutation in the F 1
generation d The constricted-pod offspring are carriers for the inflated pod shape
allele
9
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table I the ratio of phenotypes in the offspring from the testcross with F 1 plants that had purple flowers and inflated pods suggests that the genes for flower color and pod shape are located a close together on the same autosome b on the X chromosome c on different chromosomes d on a mitochondrial chromosome
10
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Which of the following provides the best justification for an assumption that might have been used in the computer simulation (Table II) a The broad allele is recessive to the narrow allele because broad
leaves appear in every generation b The purple allele is dominant to the white allele because all the
offspring from the cross of purple-flowered and white-flowered plants had purple flowers
c The narrow allele is codominant with the purple allele because the purple-flower trait and the narrow-leaf trait segregate together
d The white allele is dominant to both the broad and narrow alleles because plants with either type of leaf shape can have white flowers
11
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table II the F 1 offspring of the cross between broad-leaved white-flowered plants with narrow-leaved purple-flowered plants have a phenotype that differs from that of either parent However many testcross offspring have the same phenotype as one of the two plants in the parental cross but relatively few testcross offspring have the same phenotype as the F 1 offspring Which of the following best explains the observation a Recombination between the leaf-shape and flower-color genes resulted in
chromosomes carrying a dominant allele of both genes b Recombination between the broad and narrow alleles of the leaf-shape gene resulted in
chromosomes carrying three different alleles at the same genetic locus c Independent assortment of homologous chromosomes resulted in the combinations of
alleles present in the parental generation d The computer model cannot capture the possible assortments of gametes when
multiple genes are considered
Unit 7 Inheritance
Big Idea In eukaryotic organisms heritable information is passed to the next generation via mitosis and meiosis which has multiple processes that increases genetic variation The inheritance pattern of many traits cannot be explained by simple Mendelian genetics The chromosomal basis of inheritance explains pattern of transmission of genes from parent to offspring
Time (seconds) Drawing Description025 ndash
030 ndash
035ndash
040 ndash
045 ndash
050-
In eukaryotic organisms heritable information is passed to the next generation via mitosis and meiosis
Chromosome Model
Materialsbull pipe cleanersbull beadsbull cotton ballsbull tapebull string
Procedure1 add 3-5 beads to a pipe cleaner to
model genes2 twist a 2nd pipe cleaner to the 1st to
model the double helix3 tie string to the beads to model
mRNA4 wrap the whole model around a
cotton ball to represent how DNA supercoils around histones in order to get smaller
5 replicate the 1st to model a sister chromatid
6 tape it to the 1st at about the middle to model the centromere
Chromosome Model
Procedure1 add 3-5 beads to a pipe cleaner
to model genes2 twist a 2nd pipe cleaner to the
1st to model the double helix3 tie string to the beads to model
mRNA transcribing DNA4 wrap the whole model around
a cotton ball to represent how DNA supercoils around histones in order to get smaller
5 replicate the 1st to model a sister chromatid
6 tape it to the 1st at about the middle to model the centromere
Partsbull chromosome tightly coiled DNAbull double helix DNA is 2 strands of
nucleotides twisted togetherbull gene small sections of DNA that
encode traitsbull histone proteins that DNA supercoils
around makes the DNA smaller so that it can fit in our cells
bull sister chromatid a duplicated copy of the original DNA still connected to the 1st
bull centromere the place where the 2 sister chromatids are connected (DNA Replication not quite finished)
bull mRNA copies of DNA that read genes
Chromosome Model
Materialsbull pipe cleanersbull beadsbull cotton ballsbull tape
Partsbull chromosome tightly coiled DNAbull double helix DNA is 2 strands of
nucleotides twisted togetherbull gene small sections of DNA that
encode traitsbull histone proteins that DNA
supercoils around makes the DNA smaller so that it can fit in our cells
bull sister chromatid a duplicated copy of the original DNA still connected to the 1st
bull centromere the place where the 2 sister chromatids are connected
bull mRNA copies of DNA that read genes
Chromosome Model
Materialsbull pipe cleanersbull beadsbull cotton ballsbull tape
Partsbull chromosome tightly coiled DNAbull double helix DNA is 2 strands of
nucleotides twisted togetherbull gene small sections of DNA that
encode traitsbull histone proteins that DNA
supercoils around makes the DNA smaller so that it can fit in our cells
bull sister chromatid a duplicated copy of the original DNA still connected to the 1st
bull centromere the place where the 2 sister chromatids are connected
bull mRNA copies of DNA that read genes
Chromosome Model
Materialsbull pipe cleanersbull beadsbull cotton ballsbull tape
Partsbull chromosome tightly coiled DNAbull double helix DNA is 2 strands of
nucleotides twisted togetherbull gene small sections of DNA that
encode traitsbull histone proteins that DNA
supercoils around makes the DNA smaller so that it can fit in our cells
bull sister chromatid a duplicated copy of the original DNA still connected to the 1st
bull centromere the place where the 2 sister chromatids are connected
bull mRNA copies of DNA that read genes
Warm-UP Can you ldquounwindrdquo your model like in the picture to show the parts Sketch and label your model (or the picture of the model) Labels histone mRNA DNA sister chromatid centromere
AP Test Money DUE 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework for Tonight Mitosis Worksheet
UNIT 78 TEST March 19th
Inheritance and Regulation
Due Now Stamp Sheet
Warm-UP
1 Is blowing up a balloon a good model for how cells or organisms grow Explain
2 In what ways are cells different than each other the same
AP Test Money DUE 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework for Tonight 122
UNIT 78 TEST March 19th
Inheritance and Regulation
AP Test Money DUE 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework for Tonight
Warm-UP
1 Is blowing up a balloon a good model for how cells or organisms grow Explain
2 In what ways are cells different than each other the same
AP Test Money DUE 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework for Tonight
Warm-UP
1 Is blowing up a balloon a good model for how cells or organisms grow Explain
2 In what ways are cells different than each other the same
AP Test Money DUE 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework for Tonight
Warm-UP
1 Is blowing up a balloon a good model for how cells or organisms grow Explain
2 In what ways are cells different than each other the same
In eukaryotic organisms heritable information is passed to the next generation via mitosis and
meiosis
Cell Division 2 Types Mitosis and Meiosis
Mitosisbull Purpose
growth repair asexual reproduction (actually
binary fission in prokaryotes)bull occurs after DNA replicationbull is followed by cytokinesisbull 2 genetically identical daughter cells
(clones)bull Steps
1 Replication2 Alignment3 Separation
1 Draw a big cell with a nucleus inside2 Add homologous pairs of chromosomes
ndash 1 big yellow 1 big whitendash 1 medium yellow 1 medium whitendash 1 small yellow 1 small white
3 Clone each chromosome (DNA Replication) (making sister chromatids)
4 Nucleus breaks down (erase it)5 Clones separate one to each side of cell6 Cytokinesis cell membrane grows between the 2
halves7 Nucleus grows around chromosomes
Mitosis Modeling
When yoursquore confident on the process show Mr Jones
bull When yoursquore confident on the process show Mr Jones
bull In your notebookTable 127 Stages of Mitosis p232At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid
Mitosis Modeling
Analysis
1 What is the outcome of mitosis2 What steps of mitosis ensure a perfect
outcome3 If the first cell has 46 chromosomes (before
cloning) how many does each daughter cell have
4 Why do cells go through mitosis
Mitosis Modeling
Words to Knowbull Nucleusbull DNAbull Histonesbull Chromatinbull Chromosomebull Chromatidbull Centromere
Copyright copy 2002 Pearson Education Inc publishing as Benjamin Cummings
Interphase ldquoSrdquo phase
Mitosis
Warm-UP
1Advantages of Sex
2Disadvantages of Sex
AP Test Money DUE 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Thurs Meiosis Wksht
UNIT 78 TEST March 19th
Inheritance and Regulation
Fig 13-2
Bacteria
Parent
Bud
05 mmAsexual Reproduction
Advantages1 Can be done in isolation2 If you are perfect why change
Best when an organism is ldquoperfectlyrdquo suited for its environment
3 Less ldquomachineryrdquo needed no waste on flowers ldquonewrdquo types of cells or other secondary sexual characteristics
Disadvantages1 Less variety Poor option in a
changing environmentPlants
Fig 13-2
Parent
Bud
05 mmAsexual Reproduction
Advantages1 Can be done in isolation2 If you are perfect why change
Best when an organism is ldquoperfectlyrdquo suited for its environment
3 Less ldquomachineryrdquo needed no waste on flowers ldquonewrdquo types of cells or other secondary sexual characteristics
Disadvantages1 Less variety Poor option in a
changing environment
Fig 13-2
Parent
Bud
05 mmAsexual Reproduction
Advantages1 Can be done in isolation2 If you are perfect why change
Best when an organism is ldquoperfectlyrdquo suited for its environment
3 Less ldquomachineryrdquo needed no waste on flowers ldquonewrdquo types of cells or other secondary sexual characteristics
Disadvantages1 Less variety Poor option in a
changing environment
Aspen
Fig 13-1
Sexual ReproductionAdvantages1 Increased variety Best when
environment is changing
Increased Variety is DUE TObull random fertilizationbull meiosis
bull independent assortmentbull crossing-over
Disadvantages1 Resource investment
bull specialized cells gametesbull secondary sexual
characteristics mate attraction2 Requires a partner (except when
plants self-fertilize)
In eukaryotic organisms heritable information is passed to the next generation via mitosis and
meiosisCell Division 2 Types
Meiosis sex cells (gametes) (spermeggs)bull Purpose
ensures that each gamete receives one complete haploid (1n) set of chromosomes
Ensures chromosome number stays the same each offspring receives frac12 (1n) of the full set for the species (2n)
bull Steps1 DNA Replication2 homologous pairs form a tetrad
(independent assortment) (genetic variation increases)
3 cross over between homologous chromosomes may occur (genetic variation increases)
4 Meiosis I homologous pairs separate5 Meiosis II sister chromatids separate
In eukaryotic organisms heritable information is passed to the next generation via mitosis and
meiosisCell Division 2 Types
Meiosis sex cells (gametes) (spermeggs)bull Purpose
ensures that each gamete receives one complete haploid (1n) set of chromosomes
Ensures chromosome number stays the same each offspring receives frac12 (1n) of the full set for the species (2n)
bull Steps1 DNA Replication2 homologous pairs form a tetrad
(independent assortment) (genetic variation increases)
3 cross over between homologous chromosomes may occur (genetic variation increases)
4 Meiosis I homologous pairs separate5 Meiosis II sister chromatids separate
In eukaryotic organisms heritable information is passed to the next generation via mitosis and
meiosisCell Division 2 Types
Meiosis sex cells (gametes) (spermeggs)bull Purpose
ensures that each gamete receives one complete haploid (1n) set of chromosomes
Ensures chromosome number stays the same each offspring receives frac12 (1n) of the full set for the species (2n)
bull Steps1 DNA Replication2 homologous pairs form a tetrad
(independent assortment) (genetic variation increases)
3 cross over between homologous chromosomes may occur (genetic variation increases)
4 Meiosis I homologous pairs separate5 Meiosis II sister chromatids separate
1 Build your diploid cell (an homologous pair for each chromosome)a Draw a big cell with a nucleus insideb Add homologous pairs of chromosomes
bull 1 big white 1 big yellowbull 1 medium white 1 medium yellowbull 1 small white 1 small yellow
2 Clone each chromosome (DNA Replication) (making sister chromatids)3 Nucleus breaks down (erase it)4 Homologous pairs form a tetrad crossing over may occur (note do not model crossing
over for now)5 Homologous pairs separate one to each side of cell all paternal (or all maternal) do NOT
have to go together (independent assortment)6 Cytokinesis cell membrane grows between the 2 halves7 Clones (sister chromatids) separate (centromere ldquobreaksrdquo as DNA polymerization
completes) one to each side of cell8 Cytokinesis cell membrane grows between the 2 halves9 Nucleus grows around chromosomes 4 cells made (gametes which have half the
number of chromosomes (haploids)
Meiosis Modeling
When yoursquore confident on the process show Mr Jones
Meiosis Modelingbull When yoursquore confident on the process show Mr Jones
bull In your notebookTable 138 Stages of Meiosis p255At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid crossing over recombinant chromosome independent assortment Meiosis I Meiosis II
Meiosis Modeling
Analysis
1 What is the outcome of meiosis2 What steps of meiosis cause variation3 If the first cell has 46 chromosomes (before
cloning) how many does each daughter cell have4 How many unique gametes did you form How
many could have formed5 Why do cells go through meiosis
Warm-UP 1 Why do meiosis2 How does meiosis increase variation in organisms
AP Test Money DUE 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Tomorrow Meiosis Wksht
UNIT 78 TEST March 19th
Inheritance and Regulation
Meiosis has multiple processes that increases genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Meiosis has multiple processes that increase genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Meiosis has multiple processes that increase genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Meiosis has multiple processes that increases genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Warm-UP Watch the video What is happening Why does this happen How does this increase variation
AP Test Money DUE TOMORROW 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Tomorrow
UNIT 78 TEST March 19th
Inheritance and Regulation
Fig 13-9a
MITOSIS MEIOSIS
MEIOSIS I
Prophase I
Chiasma
Chromosomereplication
Homologouschromosomepair
Chromosomereplication
2n = 6
Parent cell
Prophase
Replicated chromosome
Metaphase Metaphase I
Anaphase ITelophase I
Haploid n = 3
Daughter cells ofmeiosis I
MEIOSIS II
Daughter cells of meiosis II
nnnn
2n2n
Daughter cellsof mitosis
AnaphaseTelophase
Compare
Contrast
Independent Assortment
Crossing-over Sexual Fertilization Mutation
Types of Changes to Cells Think About what where when how how much variation created
Warm-UP Now we need to keep track of the genes on the chromosomes that are inherited Notice the letters on the chromosomes They represent different alleles for Huntingtons Barbie has Huntingtons What is the chance her child will get Huntingtons
AP Test Money DUE 36 TOMORROWRemember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Tomorrow 141 5 Key Ideas AND Concept Check 1-3
H=dominant (remember Huntingtonrsquos is dominant)
h=recessive (no Huntingtonrsquos)
Homework DUE Monday Test Corrections for 10 Make-UP
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
AP Test Money DUE 36 TODAYRemember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
DUE next Thursday Monohybrid Crosses
Homework DUE Monday Test Corrections for 10 Make-UP
Warm-UP Now we need to keep track of TWO UNLINKED genes on the chromosomes that are inherited Notice the letters on the chromosomes They represent different alleles for Huntingtons and red hair color Barbie has Huntingtons and is a blond (but a carrier) Ken does not have Huntingtonrsquos and is also a carrier for red hair What is the chance their child will get Huntingtons and red hair
Homework DUE Tomorrow 142 5 Key Ideas AND Concept Check 1-3
H= Huntingtonrsquosh=no HuntingtonrsquosR= no red hairr= red hair
DUE Now Test Corrections for 10 Make-UP
UNIT 78 TEST March 19th
Inheritance and Regulation
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
Homework DUE Tomorrow 143 5 Key Ideas AND Concept Check 1-3
DUE Now 142DUE Thursday Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
UNIT 78 TEST March 19th
Inheritance and Regulation
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoods
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with RrYy
1 Chance of baby with Rr 052 Chance of baby with Yy 053 Chance of baby with RrYy 025
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with both dominant phenotypes
1 Chance of baby with at least one R 0752 Chance of baby with at least one Y 0753 Chance of baby with RrYy 05625 (916)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with both dominant phenotypes
1 Chance of baby with at least one R 10
2 Chance of baby with at least one Y 10
3 Chance of baby with both dominant phenotypes 10
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
Homework DUE Tomorrow Linked vs Unlinked Genes AND Monohybrid Crosses to tunritincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with
vestigial wings and cinnabar eyes Predict the phenotypic ratio of the F2 individuals
Homework DUE Tomorrow 153 5 Key Ideas and Concept Check 1-3DUE Thursday Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with vestigial wings and cinnabar eyes Predict the
phenotypic ratio of the F2 individuals
3 The results of the cross from 2 show the following outcome Individuals of each phenotype are shown in the table Which of the following is the most likely explanation of the results a The two genes are located on two different chromosomes b The two genes are sex-linked c The two genes are located on mitochondrial DNA d The two genes are linked on an autosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
1 Build your diploid cell (an homologous pair for each chromosome)a Draw a big cell with a nucleus insideb DRAW homologous pairs of chromosomes
bull 1 big blue 1 big redbull 1 small blue 1 small red
ndash Add genes to your chromosomebull Write an H and an R on big blue and an h and an r on big redbull Write a T on small blue and a t on small red
2 Clone each chromosome (DNA Replication) (making sister chromatids)3 Nucleus breaks down (erase it)4 Homologous pairs form a tetrad crossing over may occur (note do not model
crossing over for now)5 Finish meiosis (see notes for help)6 Nucleus grows around chromosomes 4 cells made (gametes which have half
the number of chromosomes (haploids)7 Repeat Steps 1-6 this time at Step 4 include ONE crossover event
Recombination Modeling
When yoursquore confident on the process show Mr Jones
bull When yoursquore confident on the process show Mr Jones
bull In your notebookFigure 1510 Recombination p295At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid crossing over recombinant chromosome independent assortment Meiosis I Meiosis II
Recombination Modeling
Analysis
1 How does recombination increase the variety of gametes formed
2 Which types of gametes were more likely Gametes with recombinant chromosomes or ones without
3 Recombination is a random process How might it benefithurt the survival of an individualspecies
Recombination Modeling
Warm-UP
1 How could you calculate recombination frequency2 What would the recombination frequency tell you about the relative position of
genes on a chromosome3 Genes A B and C are on the same chromosome Testcrosses show that the
recombination frequency between A and B is 28 and between A and C is 12 Can you determine the linear order of these genes
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP What can we learn about inheritance from looking at a pedigree (use example of the Royal Family of Europe from the early 1900s)
Warm-UP In the following human pedigree squares represent males circles represent females and shaded symbols indicate individuals affected with a disorder One of the affected males from the third generation has a child with a female who is a carrier For the pedigree shown which of the following best expresses the probability that the couplersquos first son will be affected with the disorder
(A) 25 (B) 50 (C) 75 (D) 100
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Is a widowrsquos peak a dominant or recessive trait
Is a widowrsquos peak a dominant or recessive trait
Fig 14-UN5
George
Sandra Tom Sam
Arlene
Wilma Ann Michael
Carla
Daniel Alan Tina
Christopher
A heterozygous tall and a homozygous purple flowered plant is crossed with a short and white flowered plant Predict the offspring Assume independent assortment
1
P=purplep=whiteT=tallt=short
For a plant with the genotype WwXxYyZz what is the probability that the plant will produce a gamete with a haploid genotype of Wxyz Give your answer as a fraction or as a value between 0 and 1 to four decimal places
2
A completely-plated stickleback from a marine population was mated to a low-plated stickleback from a freshwater population The resulting F1 hybrids all displayed a completely plated phenotype When the F1 hybrids were allowed to interbreed the resulting F2 generation included completely plated offspring and low-plated offspring in an approximate 31 ratio Which of the following conclusions is best supported by the results of the breeding experiments
a Phenotypic variation in the F2 generation suggests that armor morphology is controlled by many alleles of a single gene
b The completely-plated phenotype is controlled by a dominant allele of a single gene
c Armor loss is an acquired characteristic that is affected by one or more environmental factors
d Patterns of armor plating in stickleback populations are regulated by sex-specific signals
3
If a man with type AB blood marries a woman with type O what blood types would you expect in their children What fraction would you expect of each type
4
IA= Type AIB= Type Bi= Type O
If a King marries a Queen that is a carrier of hemophilia (sex-linked recessive disease that is historically fatal before adulthood) what is the chance of the Kingdom having an heir to the kingrsquos throne assuming only one child is born
5
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
7 Gregor Mendelrsquos pioneering genetic experiments with pea plants occurred before the discovery of the structure and function of chromosomes Which of the following observations about inheritance in pea plants could be explained only after the discovery that genes may be linked on a chromosome
a Pea color and pea shape display independent inheritance patterns b Offspring of a given cross show all possible combinations of traits in
equal proportions c Most offspring of a given cross have a combination of traits that is
identical to that of either one parent or the other d Recessive phenotypes can skip a generation showing up only in the
parental and F 2 generations
8
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Based on the data in Table I which of the following best explains why there are no individuals with constricted pods in the F 1 generation a Inflated pod shape is dominant to constricted pod shape b The inflated-pod offspring in the F sub one generation are
homozygous c Constricted pod shape typically arises from a new mutation in the F 1
generation d The constricted-pod offspring are carriers for the inflated pod shape
allele
9
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table I the ratio of phenotypes in the offspring from the testcross with F 1 plants that had purple flowers and inflated pods suggests that the genes for flower color and pod shape are located a close together on the same autosome b on the X chromosome c on different chromosomes d on a mitochondrial chromosome
10
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Which of the following provides the best justification for an assumption that might have been used in the computer simulation (Table II) a The broad allele is recessive to the narrow allele because broad
leaves appear in every generation b The purple allele is dominant to the white allele because all the
offspring from the cross of purple-flowered and white-flowered plants had purple flowers
c The narrow allele is codominant with the purple allele because the purple-flower trait and the narrow-leaf trait segregate together
d The white allele is dominant to both the broad and narrow alleles because plants with either type of leaf shape can have white flowers
11
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table II the F 1 offspring of the cross between broad-leaved white-flowered plants with narrow-leaved purple-flowered plants have a phenotype that differs from that of either parent However many testcross offspring have the same phenotype as one of the two plants in the parental cross but relatively few testcross offspring have the same phenotype as the F 1 offspring Which of the following best explains the observation a Recombination between the leaf-shape and flower-color genes resulted in
chromosomes carrying a dominant allele of both genes b Recombination between the broad and narrow alleles of the leaf-shape gene resulted in
chromosomes carrying three different alleles at the same genetic locus c Independent assortment of homologous chromosomes resulted in the combinations of
alleles present in the parental generation d The computer model cannot capture the possible assortments of gametes when
multiple genes are considered
Time (seconds) Drawing Description025 ndash
030 ndash
035ndash
040 ndash
045 ndash
050-
In eukaryotic organisms heritable information is passed to the next generation via mitosis and meiosis
Chromosome Model
Materialsbull pipe cleanersbull beadsbull cotton ballsbull tapebull string
Procedure1 add 3-5 beads to a pipe cleaner to
model genes2 twist a 2nd pipe cleaner to the 1st to
model the double helix3 tie string to the beads to model
mRNA4 wrap the whole model around a
cotton ball to represent how DNA supercoils around histones in order to get smaller
5 replicate the 1st to model a sister chromatid
6 tape it to the 1st at about the middle to model the centromere
Chromosome Model
Procedure1 add 3-5 beads to a pipe cleaner
to model genes2 twist a 2nd pipe cleaner to the
1st to model the double helix3 tie string to the beads to model
mRNA transcribing DNA4 wrap the whole model around
a cotton ball to represent how DNA supercoils around histones in order to get smaller
5 replicate the 1st to model a sister chromatid
6 tape it to the 1st at about the middle to model the centromere
Partsbull chromosome tightly coiled DNAbull double helix DNA is 2 strands of
nucleotides twisted togetherbull gene small sections of DNA that
encode traitsbull histone proteins that DNA supercoils
around makes the DNA smaller so that it can fit in our cells
bull sister chromatid a duplicated copy of the original DNA still connected to the 1st
bull centromere the place where the 2 sister chromatids are connected (DNA Replication not quite finished)
bull mRNA copies of DNA that read genes
Chromosome Model
Materialsbull pipe cleanersbull beadsbull cotton ballsbull tape
Partsbull chromosome tightly coiled DNAbull double helix DNA is 2 strands of
nucleotides twisted togetherbull gene small sections of DNA that
encode traitsbull histone proteins that DNA
supercoils around makes the DNA smaller so that it can fit in our cells
bull sister chromatid a duplicated copy of the original DNA still connected to the 1st
bull centromere the place where the 2 sister chromatids are connected
bull mRNA copies of DNA that read genes
Chromosome Model
Materialsbull pipe cleanersbull beadsbull cotton ballsbull tape
Partsbull chromosome tightly coiled DNAbull double helix DNA is 2 strands of
nucleotides twisted togetherbull gene small sections of DNA that
encode traitsbull histone proteins that DNA
supercoils around makes the DNA smaller so that it can fit in our cells
bull sister chromatid a duplicated copy of the original DNA still connected to the 1st
bull centromere the place where the 2 sister chromatids are connected
bull mRNA copies of DNA that read genes
Chromosome Model
Materialsbull pipe cleanersbull beadsbull cotton ballsbull tape
Partsbull chromosome tightly coiled DNAbull double helix DNA is 2 strands of
nucleotides twisted togetherbull gene small sections of DNA that
encode traitsbull histone proteins that DNA
supercoils around makes the DNA smaller so that it can fit in our cells
bull sister chromatid a duplicated copy of the original DNA still connected to the 1st
bull centromere the place where the 2 sister chromatids are connected
bull mRNA copies of DNA that read genes
Warm-UP Can you ldquounwindrdquo your model like in the picture to show the parts Sketch and label your model (or the picture of the model) Labels histone mRNA DNA sister chromatid centromere
AP Test Money DUE 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework for Tonight Mitosis Worksheet
UNIT 78 TEST March 19th
Inheritance and Regulation
Due Now Stamp Sheet
Warm-UP
1 Is blowing up a balloon a good model for how cells or organisms grow Explain
2 In what ways are cells different than each other the same
AP Test Money DUE 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework for Tonight 122
UNIT 78 TEST March 19th
Inheritance and Regulation
AP Test Money DUE 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework for Tonight
Warm-UP
1 Is blowing up a balloon a good model for how cells or organisms grow Explain
2 In what ways are cells different than each other the same
AP Test Money DUE 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework for Tonight
Warm-UP
1 Is blowing up a balloon a good model for how cells or organisms grow Explain
2 In what ways are cells different than each other the same
AP Test Money DUE 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework for Tonight
Warm-UP
1 Is blowing up a balloon a good model for how cells or organisms grow Explain
2 In what ways are cells different than each other the same
In eukaryotic organisms heritable information is passed to the next generation via mitosis and
meiosis
Cell Division 2 Types Mitosis and Meiosis
Mitosisbull Purpose
growth repair asexual reproduction (actually
binary fission in prokaryotes)bull occurs after DNA replicationbull is followed by cytokinesisbull 2 genetically identical daughter cells
(clones)bull Steps
1 Replication2 Alignment3 Separation
1 Draw a big cell with a nucleus inside2 Add homologous pairs of chromosomes
ndash 1 big yellow 1 big whitendash 1 medium yellow 1 medium whitendash 1 small yellow 1 small white
3 Clone each chromosome (DNA Replication) (making sister chromatids)
4 Nucleus breaks down (erase it)5 Clones separate one to each side of cell6 Cytokinesis cell membrane grows between the 2
halves7 Nucleus grows around chromosomes
Mitosis Modeling
When yoursquore confident on the process show Mr Jones
bull When yoursquore confident on the process show Mr Jones
bull In your notebookTable 127 Stages of Mitosis p232At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid
Mitosis Modeling
Analysis
1 What is the outcome of mitosis2 What steps of mitosis ensure a perfect
outcome3 If the first cell has 46 chromosomes (before
cloning) how many does each daughter cell have
4 Why do cells go through mitosis
Mitosis Modeling
Words to Knowbull Nucleusbull DNAbull Histonesbull Chromatinbull Chromosomebull Chromatidbull Centromere
Copyright copy 2002 Pearson Education Inc publishing as Benjamin Cummings
Interphase ldquoSrdquo phase
Mitosis
Warm-UP
1Advantages of Sex
2Disadvantages of Sex
AP Test Money DUE 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Thurs Meiosis Wksht
UNIT 78 TEST March 19th
Inheritance and Regulation
Fig 13-2
Bacteria
Parent
Bud
05 mmAsexual Reproduction
Advantages1 Can be done in isolation2 If you are perfect why change
Best when an organism is ldquoperfectlyrdquo suited for its environment
3 Less ldquomachineryrdquo needed no waste on flowers ldquonewrdquo types of cells or other secondary sexual characteristics
Disadvantages1 Less variety Poor option in a
changing environmentPlants
Fig 13-2
Parent
Bud
05 mmAsexual Reproduction
Advantages1 Can be done in isolation2 If you are perfect why change
Best when an organism is ldquoperfectlyrdquo suited for its environment
3 Less ldquomachineryrdquo needed no waste on flowers ldquonewrdquo types of cells or other secondary sexual characteristics
Disadvantages1 Less variety Poor option in a
changing environment
Fig 13-2
Parent
Bud
05 mmAsexual Reproduction
Advantages1 Can be done in isolation2 If you are perfect why change
Best when an organism is ldquoperfectlyrdquo suited for its environment
3 Less ldquomachineryrdquo needed no waste on flowers ldquonewrdquo types of cells or other secondary sexual characteristics
Disadvantages1 Less variety Poor option in a
changing environment
Aspen
Fig 13-1
Sexual ReproductionAdvantages1 Increased variety Best when
environment is changing
Increased Variety is DUE TObull random fertilizationbull meiosis
bull independent assortmentbull crossing-over
Disadvantages1 Resource investment
bull specialized cells gametesbull secondary sexual
characteristics mate attraction2 Requires a partner (except when
plants self-fertilize)
In eukaryotic organisms heritable information is passed to the next generation via mitosis and
meiosisCell Division 2 Types
Meiosis sex cells (gametes) (spermeggs)bull Purpose
ensures that each gamete receives one complete haploid (1n) set of chromosomes
Ensures chromosome number stays the same each offspring receives frac12 (1n) of the full set for the species (2n)
bull Steps1 DNA Replication2 homologous pairs form a tetrad
(independent assortment) (genetic variation increases)
3 cross over between homologous chromosomes may occur (genetic variation increases)
4 Meiosis I homologous pairs separate5 Meiosis II sister chromatids separate
In eukaryotic organisms heritable information is passed to the next generation via mitosis and
meiosisCell Division 2 Types
Meiosis sex cells (gametes) (spermeggs)bull Purpose
ensures that each gamete receives one complete haploid (1n) set of chromosomes
Ensures chromosome number stays the same each offspring receives frac12 (1n) of the full set for the species (2n)
bull Steps1 DNA Replication2 homologous pairs form a tetrad
(independent assortment) (genetic variation increases)
3 cross over between homologous chromosomes may occur (genetic variation increases)
4 Meiosis I homologous pairs separate5 Meiosis II sister chromatids separate
In eukaryotic organisms heritable information is passed to the next generation via mitosis and
meiosisCell Division 2 Types
Meiosis sex cells (gametes) (spermeggs)bull Purpose
ensures that each gamete receives one complete haploid (1n) set of chromosomes
Ensures chromosome number stays the same each offspring receives frac12 (1n) of the full set for the species (2n)
bull Steps1 DNA Replication2 homologous pairs form a tetrad
(independent assortment) (genetic variation increases)
3 cross over between homologous chromosomes may occur (genetic variation increases)
4 Meiosis I homologous pairs separate5 Meiosis II sister chromatids separate
1 Build your diploid cell (an homologous pair for each chromosome)a Draw a big cell with a nucleus insideb Add homologous pairs of chromosomes
bull 1 big white 1 big yellowbull 1 medium white 1 medium yellowbull 1 small white 1 small yellow
2 Clone each chromosome (DNA Replication) (making sister chromatids)3 Nucleus breaks down (erase it)4 Homologous pairs form a tetrad crossing over may occur (note do not model crossing
over for now)5 Homologous pairs separate one to each side of cell all paternal (or all maternal) do NOT
have to go together (independent assortment)6 Cytokinesis cell membrane grows between the 2 halves7 Clones (sister chromatids) separate (centromere ldquobreaksrdquo as DNA polymerization
completes) one to each side of cell8 Cytokinesis cell membrane grows between the 2 halves9 Nucleus grows around chromosomes 4 cells made (gametes which have half the
number of chromosomes (haploids)
Meiosis Modeling
When yoursquore confident on the process show Mr Jones
Meiosis Modelingbull When yoursquore confident on the process show Mr Jones
bull In your notebookTable 138 Stages of Meiosis p255At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid crossing over recombinant chromosome independent assortment Meiosis I Meiosis II
Meiosis Modeling
Analysis
1 What is the outcome of meiosis2 What steps of meiosis cause variation3 If the first cell has 46 chromosomes (before
cloning) how many does each daughter cell have4 How many unique gametes did you form How
many could have formed5 Why do cells go through meiosis
Warm-UP 1 Why do meiosis2 How does meiosis increase variation in organisms
AP Test Money DUE 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Tomorrow Meiosis Wksht
UNIT 78 TEST March 19th
Inheritance and Regulation
Meiosis has multiple processes that increases genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Meiosis has multiple processes that increase genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Meiosis has multiple processes that increase genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Meiosis has multiple processes that increases genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Warm-UP Watch the video What is happening Why does this happen How does this increase variation
AP Test Money DUE TOMORROW 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Tomorrow
UNIT 78 TEST March 19th
Inheritance and Regulation
Fig 13-9a
MITOSIS MEIOSIS
MEIOSIS I
Prophase I
Chiasma
Chromosomereplication
Homologouschromosomepair
Chromosomereplication
2n = 6
Parent cell
Prophase
Replicated chromosome
Metaphase Metaphase I
Anaphase ITelophase I
Haploid n = 3
Daughter cells ofmeiosis I
MEIOSIS II
Daughter cells of meiosis II
nnnn
2n2n
Daughter cellsof mitosis
AnaphaseTelophase
Compare
Contrast
Independent Assortment
Crossing-over Sexual Fertilization Mutation
Types of Changes to Cells Think About what where when how how much variation created
Warm-UP Now we need to keep track of the genes on the chromosomes that are inherited Notice the letters on the chromosomes They represent different alleles for Huntingtons Barbie has Huntingtons What is the chance her child will get Huntingtons
AP Test Money DUE 36 TOMORROWRemember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Tomorrow 141 5 Key Ideas AND Concept Check 1-3
H=dominant (remember Huntingtonrsquos is dominant)
h=recessive (no Huntingtonrsquos)
Homework DUE Monday Test Corrections for 10 Make-UP
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
AP Test Money DUE 36 TODAYRemember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
DUE next Thursday Monohybrid Crosses
Homework DUE Monday Test Corrections for 10 Make-UP
Warm-UP Now we need to keep track of TWO UNLINKED genes on the chromosomes that are inherited Notice the letters on the chromosomes They represent different alleles for Huntingtons and red hair color Barbie has Huntingtons and is a blond (but a carrier) Ken does not have Huntingtonrsquos and is also a carrier for red hair What is the chance their child will get Huntingtons and red hair
Homework DUE Tomorrow 142 5 Key Ideas AND Concept Check 1-3
H= Huntingtonrsquosh=no HuntingtonrsquosR= no red hairr= red hair
DUE Now Test Corrections for 10 Make-UP
UNIT 78 TEST March 19th
Inheritance and Regulation
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
Homework DUE Tomorrow 143 5 Key Ideas AND Concept Check 1-3
DUE Now 142DUE Thursday Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
UNIT 78 TEST March 19th
Inheritance and Regulation
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoods
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with RrYy
1 Chance of baby with Rr 052 Chance of baby with Yy 053 Chance of baby with RrYy 025
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with both dominant phenotypes
1 Chance of baby with at least one R 0752 Chance of baby with at least one Y 0753 Chance of baby with RrYy 05625 (916)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with both dominant phenotypes
1 Chance of baby with at least one R 10
2 Chance of baby with at least one Y 10
3 Chance of baby with both dominant phenotypes 10
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
Homework DUE Tomorrow Linked vs Unlinked Genes AND Monohybrid Crosses to tunritincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with
vestigial wings and cinnabar eyes Predict the phenotypic ratio of the F2 individuals
Homework DUE Tomorrow 153 5 Key Ideas and Concept Check 1-3DUE Thursday Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with vestigial wings and cinnabar eyes Predict the
phenotypic ratio of the F2 individuals
3 The results of the cross from 2 show the following outcome Individuals of each phenotype are shown in the table Which of the following is the most likely explanation of the results a The two genes are located on two different chromosomes b The two genes are sex-linked c The two genes are located on mitochondrial DNA d The two genes are linked on an autosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
1 Build your diploid cell (an homologous pair for each chromosome)a Draw a big cell with a nucleus insideb DRAW homologous pairs of chromosomes
bull 1 big blue 1 big redbull 1 small blue 1 small red
ndash Add genes to your chromosomebull Write an H and an R on big blue and an h and an r on big redbull Write a T on small blue and a t on small red
2 Clone each chromosome (DNA Replication) (making sister chromatids)3 Nucleus breaks down (erase it)4 Homologous pairs form a tetrad crossing over may occur (note do not model
crossing over for now)5 Finish meiosis (see notes for help)6 Nucleus grows around chromosomes 4 cells made (gametes which have half
the number of chromosomes (haploids)7 Repeat Steps 1-6 this time at Step 4 include ONE crossover event
Recombination Modeling
When yoursquore confident on the process show Mr Jones
bull When yoursquore confident on the process show Mr Jones
bull In your notebookFigure 1510 Recombination p295At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid crossing over recombinant chromosome independent assortment Meiosis I Meiosis II
Recombination Modeling
Analysis
1 How does recombination increase the variety of gametes formed
2 Which types of gametes were more likely Gametes with recombinant chromosomes or ones without
3 Recombination is a random process How might it benefithurt the survival of an individualspecies
Recombination Modeling
Warm-UP
1 How could you calculate recombination frequency2 What would the recombination frequency tell you about the relative position of
genes on a chromosome3 Genes A B and C are on the same chromosome Testcrosses show that the
recombination frequency between A and B is 28 and between A and C is 12 Can you determine the linear order of these genes
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP What can we learn about inheritance from looking at a pedigree (use example of the Royal Family of Europe from the early 1900s)
Warm-UP In the following human pedigree squares represent males circles represent females and shaded symbols indicate individuals affected with a disorder One of the affected males from the third generation has a child with a female who is a carrier For the pedigree shown which of the following best expresses the probability that the couplersquos first son will be affected with the disorder
(A) 25 (B) 50 (C) 75 (D) 100
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Is a widowrsquos peak a dominant or recessive trait
Is a widowrsquos peak a dominant or recessive trait
Fig 14-UN5
George
Sandra Tom Sam
Arlene
Wilma Ann Michael
Carla
Daniel Alan Tina
Christopher
A heterozygous tall and a homozygous purple flowered plant is crossed with a short and white flowered plant Predict the offspring Assume independent assortment
1
P=purplep=whiteT=tallt=short
For a plant with the genotype WwXxYyZz what is the probability that the plant will produce a gamete with a haploid genotype of Wxyz Give your answer as a fraction or as a value between 0 and 1 to four decimal places
2
A completely-plated stickleback from a marine population was mated to a low-plated stickleback from a freshwater population The resulting F1 hybrids all displayed a completely plated phenotype When the F1 hybrids were allowed to interbreed the resulting F2 generation included completely plated offspring and low-plated offspring in an approximate 31 ratio Which of the following conclusions is best supported by the results of the breeding experiments
a Phenotypic variation in the F2 generation suggests that armor morphology is controlled by many alleles of a single gene
b The completely-plated phenotype is controlled by a dominant allele of a single gene
c Armor loss is an acquired characteristic that is affected by one or more environmental factors
d Patterns of armor plating in stickleback populations are regulated by sex-specific signals
3
If a man with type AB blood marries a woman with type O what blood types would you expect in their children What fraction would you expect of each type
4
IA= Type AIB= Type Bi= Type O
If a King marries a Queen that is a carrier of hemophilia (sex-linked recessive disease that is historically fatal before adulthood) what is the chance of the Kingdom having an heir to the kingrsquos throne assuming only one child is born
5
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
7 Gregor Mendelrsquos pioneering genetic experiments with pea plants occurred before the discovery of the structure and function of chromosomes Which of the following observations about inheritance in pea plants could be explained only after the discovery that genes may be linked on a chromosome
a Pea color and pea shape display independent inheritance patterns b Offspring of a given cross show all possible combinations of traits in
equal proportions c Most offspring of a given cross have a combination of traits that is
identical to that of either one parent or the other d Recessive phenotypes can skip a generation showing up only in the
parental and F 2 generations
8
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Based on the data in Table I which of the following best explains why there are no individuals with constricted pods in the F 1 generation a Inflated pod shape is dominant to constricted pod shape b The inflated-pod offspring in the F sub one generation are
homozygous c Constricted pod shape typically arises from a new mutation in the F 1
generation d The constricted-pod offspring are carriers for the inflated pod shape
allele
9
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table I the ratio of phenotypes in the offspring from the testcross with F 1 plants that had purple flowers and inflated pods suggests that the genes for flower color and pod shape are located a close together on the same autosome b on the X chromosome c on different chromosomes d on a mitochondrial chromosome
10
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Which of the following provides the best justification for an assumption that might have been used in the computer simulation (Table II) a The broad allele is recessive to the narrow allele because broad
leaves appear in every generation b The purple allele is dominant to the white allele because all the
offspring from the cross of purple-flowered and white-flowered plants had purple flowers
c The narrow allele is codominant with the purple allele because the purple-flower trait and the narrow-leaf trait segregate together
d The white allele is dominant to both the broad and narrow alleles because plants with either type of leaf shape can have white flowers
11
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table II the F 1 offspring of the cross between broad-leaved white-flowered plants with narrow-leaved purple-flowered plants have a phenotype that differs from that of either parent However many testcross offspring have the same phenotype as one of the two plants in the parental cross but relatively few testcross offspring have the same phenotype as the F 1 offspring Which of the following best explains the observation a Recombination between the leaf-shape and flower-color genes resulted in
chromosomes carrying a dominant allele of both genes b Recombination between the broad and narrow alleles of the leaf-shape gene resulted in
chromosomes carrying three different alleles at the same genetic locus c Independent assortment of homologous chromosomes resulted in the combinations of
alleles present in the parental generation d The computer model cannot capture the possible assortments of gametes when
multiple genes are considered
Chromosome Model
Materialsbull pipe cleanersbull beadsbull cotton ballsbull tapebull string
Procedure1 add 3-5 beads to a pipe cleaner to
model genes2 twist a 2nd pipe cleaner to the 1st to
model the double helix3 tie string to the beads to model
mRNA4 wrap the whole model around a
cotton ball to represent how DNA supercoils around histones in order to get smaller
5 replicate the 1st to model a sister chromatid
6 tape it to the 1st at about the middle to model the centromere
Chromosome Model
Procedure1 add 3-5 beads to a pipe cleaner
to model genes2 twist a 2nd pipe cleaner to the
1st to model the double helix3 tie string to the beads to model
mRNA transcribing DNA4 wrap the whole model around
a cotton ball to represent how DNA supercoils around histones in order to get smaller
5 replicate the 1st to model a sister chromatid
6 tape it to the 1st at about the middle to model the centromere
Partsbull chromosome tightly coiled DNAbull double helix DNA is 2 strands of
nucleotides twisted togetherbull gene small sections of DNA that
encode traitsbull histone proteins that DNA supercoils
around makes the DNA smaller so that it can fit in our cells
bull sister chromatid a duplicated copy of the original DNA still connected to the 1st
bull centromere the place where the 2 sister chromatids are connected (DNA Replication not quite finished)
bull mRNA copies of DNA that read genes
Chromosome Model
Materialsbull pipe cleanersbull beadsbull cotton ballsbull tape
Partsbull chromosome tightly coiled DNAbull double helix DNA is 2 strands of
nucleotides twisted togetherbull gene small sections of DNA that
encode traitsbull histone proteins that DNA
supercoils around makes the DNA smaller so that it can fit in our cells
bull sister chromatid a duplicated copy of the original DNA still connected to the 1st
bull centromere the place where the 2 sister chromatids are connected
bull mRNA copies of DNA that read genes
Chromosome Model
Materialsbull pipe cleanersbull beadsbull cotton ballsbull tape
Partsbull chromosome tightly coiled DNAbull double helix DNA is 2 strands of
nucleotides twisted togetherbull gene small sections of DNA that
encode traitsbull histone proteins that DNA
supercoils around makes the DNA smaller so that it can fit in our cells
bull sister chromatid a duplicated copy of the original DNA still connected to the 1st
bull centromere the place where the 2 sister chromatids are connected
bull mRNA copies of DNA that read genes
Chromosome Model
Materialsbull pipe cleanersbull beadsbull cotton ballsbull tape
Partsbull chromosome tightly coiled DNAbull double helix DNA is 2 strands of
nucleotides twisted togetherbull gene small sections of DNA that
encode traitsbull histone proteins that DNA
supercoils around makes the DNA smaller so that it can fit in our cells
bull sister chromatid a duplicated copy of the original DNA still connected to the 1st
bull centromere the place where the 2 sister chromatids are connected
bull mRNA copies of DNA that read genes
Warm-UP Can you ldquounwindrdquo your model like in the picture to show the parts Sketch and label your model (or the picture of the model) Labels histone mRNA DNA sister chromatid centromere
AP Test Money DUE 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework for Tonight Mitosis Worksheet
UNIT 78 TEST March 19th
Inheritance and Regulation
Due Now Stamp Sheet
Warm-UP
1 Is blowing up a balloon a good model for how cells or organisms grow Explain
2 In what ways are cells different than each other the same
AP Test Money DUE 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework for Tonight 122
UNIT 78 TEST March 19th
Inheritance and Regulation
AP Test Money DUE 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework for Tonight
Warm-UP
1 Is blowing up a balloon a good model for how cells or organisms grow Explain
2 In what ways are cells different than each other the same
AP Test Money DUE 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework for Tonight
Warm-UP
1 Is blowing up a balloon a good model for how cells or organisms grow Explain
2 In what ways are cells different than each other the same
AP Test Money DUE 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework for Tonight
Warm-UP
1 Is blowing up a balloon a good model for how cells or organisms grow Explain
2 In what ways are cells different than each other the same
In eukaryotic organisms heritable information is passed to the next generation via mitosis and
meiosis
Cell Division 2 Types Mitosis and Meiosis
Mitosisbull Purpose
growth repair asexual reproduction (actually
binary fission in prokaryotes)bull occurs after DNA replicationbull is followed by cytokinesisbull 2 genetically identical daughter cells
(clones)bull Steps
1 Replication2 Alignment3 Separation
1 Draw a big cell with a nucleus inside2 Add homologous pairs of chromosomes
ndash 1 big yellow 1 big whitendash 1 medium yellow 1 medium whitendash 1 small yellow 1 small white
3 Clone each chromosome (DNA Replication) (making sister chromatids)
4 Nucleus breaks down (erase it)5 Clones separate one to each side of cell6 Cytokinesis cell membrane grows between the 2
halves7 Nucleus grows around chromosomes
Mitosis Modeling
When yoursquore confident on the process show Mr Jones
bull When yoursquore confident on the process show Mr Jones
bull In your notebookTable 127 Stages of Mitosis p232At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid
Mitosis Modeling
Analysis
1 What is the outcome of mitosis2 What steps of mitosis ensure a perfect
outcome3 If the first cell has 46 chromosomes (before
cloning) how many does each daughter cell have
4 Why do cells go through mitosis
Mitosis Modeling
Words to Knowbull Nucleusbull DNAbull Histonesbull Chromatinbull Chromosomebull Chromatidbull Centromere
Copyright copy 2002 Pearson Education Inc publishing as Benjamin Cummings
Interphase ldquoSrdquo phase
Mitosis
Warm-UP
1Advantages of Sex
2Disadvantages of Sex
AP Test Money DUE 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Thurs Meiosis Wksht
UNIT 78 TEST March 19th
Inheritance and Regulation
Fig 13-2
Bacteria
Parent
Bud
05 mmAsexual Reproduction
Advantages1 Can be done in isolation2 If you are perfect why change
Best when an organism is ldquoperfectlyrdquo suited for its environment
3 Less ldquomachineryrdquo needed no waste on flowers ldquonewrdquo types of cells or other secondary sexual characteristics
Disadvantages1 Less variety Poor option in a
changing environmentPlants
Fig 13-2
Parent
Bud
05 mmAsexual Reproduction
Advantages1 Can be done in isolation2 If you are perfect why change
Best when an organism is ldquoperfectlyrdquo suited for its environment
3 Less ldquomachineryrdquo needed no waste on flowers ldquonewrdquo types of cells or other secondary sexual characteristics
Disadvantages1 Less variety Poor option in a
changing environment
Fig 13-2
Parent
Bud
05 mmAsexual Reproduction
Advantages1 Can be done in isolation2 If you are perfect why change
Best when an organism is ldquoperfectlyrdquo suited for its environment
3 Less ldquomachineryrdquo needed no waste on flowers ldquonewrdquo types of cells or other secondary sexual characteristics
Disadvantages1 Less variety Poor option in a
changing environment
Aspen
Fig 13-1
Sexual ReproductionAdvantages1 Increased variety Best when
environment is changing
Increased Variety is DUE TObull random fertilizationbull meiosis
bull independent assortmentbull crossing-over
Disadvantages1 Resource investment
bull specialized cells gametesbull secondary sexual
characteristics mate attraction2 Requires a partner (except when
plants self-fertilize)
In eukaryotic organisms heritable information is passed to the next generation via mitosis and
meiosisCell Division 2 Types
Meiosis sex cells (gametes) (spermeggs)bull Purpose
ensures that each gamete receives one complete haploid (1n) set of chromosomes
Ensures chromosome number stays the same each offspring receives frac12 (1n) of the full set for the species (2n)
bull Steps1 DNA Replication2 homologous pairs form a tetrad
(independent assortment) (genetic variation increases)
3 cross over between homologous chromosomes may occur (genetic variation increases)
4 Meiosis I homologous pairs separate5 Meiosis II sister chromatids separate
In eukaryotic organisms heritable information is passed to the next generation via mitosis and
meiosisCell Division 2 Types
Meiosis sex cells (gametes) (spermeggs)bull Purpose
ensures that each gamete receives one complete haploid (1n) set of chromosomes
Ensures chromosome number stays the same each offspring receives frac12 (1n) of the full set for the species (2n)
bull Steps1 DNA Replication2 homologous pairs form a tetrad
(independent assortment) (genetic variation increases)
3 cross over between homologous chromosomes may occur (genetic variation increases)
4 Meiosis I homologous pairs separate5 Meiosis II sister chromatids separate
In eukaryotic organisms heritable information is passed to the next generation via mitosis and
meiosisCell Division 2 Types
Meiosis sex cells (gametes) (spermeggs)bull Purpose
ensures that each gamete receives one complete haploid (1n) set of chromosomes
Ensures chromosome number stays the same each offspring receives frac12 (1n) of the full set for the species (2n)
bull Steps1 DNA Replication2 homologous pairs form a tetrad
(independent assortment) (genetic variation increases)
3 cross over between homologous chromosomes may occur (genetic variation increases)
4 Meiosis I homologous pairs separate5 Meiosis II sister chromatids separate
1 Build your diploid cell (an homologous pair for each chromosome)a Draw a big cell with a nucleus insideb Add homologous pairs of chromosomes
bull 1 big white 1 big yellowbull 1 medium white 1 medium yellowbull 1 small white 1 small yellow
2 Clone each chromosome (DNA Replication) (making sister chromatids)3 Nucleus breaks down (erase it)4 Homologous pairs form a tetrad crossing over may occur (note do not model crossing
over for now)5 Homologous pairs separate one to each side of cell all paternal (or all maternal) do NOT
have to go together (independent assortment)6 Cytokinesis cell membrane grows between the 2 halves7 Clones (sister chromatids) separate (centromere ldquobreaksrdquo as DNA polymerization
completes) one to each side of cell8 Cytokinesis cell membrane grows between the 2 halves9 Nucleus grows around chromosomes 4 cells made (gametes which have half the
number of chromosomes (haploids)
Meiosis Modeling
When yoursquore confident on the process show Mr Jones
Meiosis Modelingbull When yoursquore confident on the process show Mr Jones
bull In your notebookTable 138 Stages of Meiosis p255At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid crossing over recombinant chromosome independent assortment Meiosis I Meiosis II
Meiosis Modeling
Analysis
1 What is the outcome of meiosis2 What steps of meiosis cause variation3 If the first cell has 46 chromosomes (before
cloning) how many does each daughter cell have4 How many unique gametes did you form How
many could have formed5 Why do cells go through meiosis
Warm-UP 1 Why do meiosis2 How does meiosis increase variation in organisms
AP Test Money DUE 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Tomorrow Meiosis Wksht
UNIT 78 TEST March 19th
Inheritance and Regulation
Meiosis has multiple processes that increases genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Meiosis has multiple processes that increase genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Meiosis has multiple processes that increase genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Meiosis has multiple processes that increases genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Warm-UP Watch the video What is happening Why does this happen How does this increase variation
AP Test Money DUE TOMORROW 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Tomorrow
UNIT 78 TEST March 19th
Inheritance and Regulation
Fig 13-9a
MITOSIS MEIOSIS
MEIOSIS I
Prophase I
Chiasma
Chromosomereplication
Homologouschromosomepair
Chromosomereplication
2n = 6
Parent cell
Prophase
Replicated chromosome
Metaphase Metaphase I
Anaphase ITelophase I
Haploid n = 3
Daughter cells ofmeiosis I
MEIOSIS II
Daughter cells of meiosis II
nnnn
2n2n
Daughter cellsof mitosis
AnaphaseTelophase
Compare
Contrast
Independent Assortment
Crossing-over Sexual Fertilization Mutation
Types of Changes to Cells Think About what where when how how much variation created
Warm-UP Now we need to keep track of the genes on the chromosomes that are inherited Notice the letters on the chromosomes They represent different alleles for Huntingtons Barbie has Huntingtons What is the chance her child will get Huntingtons
AP Test Money DUE 36 TOMORROWRemember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Tomorrow 141 5 Key Ideas AND Concept Check 1-3
H=dominant (remember Huntingtonrsquos is dominant)
h=recessive (no Huntingtonrsquos)
Homework DUE Monday Test Corrections for 10 Make-UP
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
AP Test Money DUE 36 TODAYRemember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
DUE next Thursday Monohybrid Crosses
Homework DUE Monday Test Corrections for 10 Make-UP
Warm-UP Now we need to keep track of TWO UNLINKED genes on the chromosomes that are inherited Notice the letters on the chromosomes They represent different alleles for Huntingtons and red hair color Barbie has Huntingtons and is a blond (but a carrier) Ken does not have Huntingtonrsquos and is also a carrier for red hair What is the chance their child will get Huntingtons and red hair
Homework DUE Tomorrow 142 5 Key Ideas AND Concept Check 1-3
H= Huntingtonrsquosh=no HuntingtonrsquosR= no red hairr= red hair
DUE Now Test Corrections for 10 Make-UP
UNIT 78 TEST March 19th
Inheritance and Regulation
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
Homework DUE Tomorrow 143 5 Key Ideas AND Concept Check 1-3
DUE Now 142DUE Thursday Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
UNIT 78 TEST March 19th
Inheritance and Regulation
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoods
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with RrYy
1 Chance of baby with Rr 052 Chance of baby with Yy 053 Chance of baby with RrYy 025
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with both dominant phenotypes
1 Chance of baby with at least one R 0752 Chance of baby with at least one Y 0753 Chance of baby with RrYy 05625 (916)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with both dominant phenotypes
1 Chance of baby with at least one R 10
2 Chance of baby with at least one Y 10
3 Chance of baby with both dominant phenotypes 10
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
Homework DUE Tomorrow Linked vs Unlinked Genes AND Monohybrid Crosses to tunritincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with
vestigial wings and cinnabar eyes Predict the phenotypic ratio of the F2 individuals
Homework DUE Tomorrow 153 5 Key Ideas and Concept Check 1-3DUE Thursday Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with vestigial wings and cinnabar eyes Predict the
phenotypic ratio of the F2 individuals
3 The results of the cross from 2 show the following outcome Individuals of each phenotype are shown in the table Which of the following is the most likely explanation of the results a The two genes are located on two different chromosomes b The two genes are sex-linked c The two genes are located on mitochondrial DNA d The two genes are linked on an autosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
1 Build your diploid cell (an homologous pair for each chromosome)a Draw a big cell with a nucleus insideb DRAW homologous pairs of chromosomes
bull 1 big blue 1 big redbull 1 small blue 1 small red
ndash Add genes to your chromosomebull Write an H and an R on big blue and an h and an r on big redbull Write a T on small blue and a t on small red
2 Clone each chromosome (DNA Replication) (making sister chromatids)3 Nucleus breaks down (erase it)4 Homologous pairs form a tetrad crossing over may occur (note do not model
crossing over for now)5 Finish meiosis (see notes for help)6 Nucleus grows around chromosomes 4 cells made (gametes which have half
the number of chromosomes (haploids)7 Repeat Steps 1-6 this time at Step 4 include ONE crossover event
Recombination Modeling
When yoursquore confident on the process show Mr Jones
bull When yoursquore confident on the process show Mr Jones
bull In your notebookFigure 1510 Recombination p295At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid crossing over recombinant chromosome independent assortment Meiosis I Meiosis II
Recombination Modeling
Analysis
1 How does recombination increase the variety of gametes formed
2 Which types of gametes were more likely Gametes with recombinant chromosomes or ones without
3 Recombination is a random process How might it benefithurt the survival of an individualspecies
Recombination Modeling
Warm-UP
1 How could you calculate recombination frequency2 What would the recombination frequency tell you about the relative position of
genes on a chromosome3 Genes A B and C are on the same chromosome Testcrosses show that the
recombination frequency between A and B is 28 and between A and C is 12 Can you determine the linear order of these genes
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP What can we learn about inheritance from looking at a pedigree (use example of the Royal Family of Europe from the early 1900s)
Warm-UP In the following human pedigree squares represent males circles represent females and shaded symbols indicate individuals affected with a disorder One of the affected males from the third generation has a child with a female who is a carrier For the pedigree shown which of the following best expresses the probability that the couplersquos first son will be affected with the disorder
(A) 25 (B) 50 (C) 75 (D) 100
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Is a widowrsquos peak a dominant or recessive trait
Is a widowrsquos peak a dominant or recessive trait
Fig 14-UN5
George
Sandra Tom Sam
Arlene
Wilma Ann Michael
Carla
Daniel Alan Tina
Christopher
A heterozygous tall and a homozygous purple flowered plant is crossed with a short and white flowered plant Predict the offspring Assume independent assortment
1
P=purplep=whiteT=tallt=short
For a plant with the genotype WwXxYyZz what is the probability that the plant will produce a gamete with a haploid genotype of Wxyz Give your answer as a fraction or as a value between 0 and 1 to four decimal places
2
A completely-plated stickleback from a marine population was mated to a low-plated stickleback from a freshwater population The resulting F1 hybrids all displayed a completely plated phenotype When the F1 hybrids were allowed to interbreed the resulting F2 generation included completely plated offspring and low-plated offspring in an approximate 31 ratio Which of the following conclusions is best supported by the results of the breeding experiments
a Phenotypic variation in the F2 generation suggests that armor morphology is controlled by many alleles of a single gene
b The completely-plated phenotype is controlled by a dominant allele of a single gene
c Armor loss is an acquired characteristic that is affected by one or more environmental factors
d Patterns of armor plating in stickleback populations are regulated by sex-specific signals
3
If a man with type AB blood marries a woman with type O what blood types would you expect in their children What fraction would you expect of each type
4
IA= Type AIB= Type Bi= Type O
If a King marries a Queen that is a carrier of hemophilia (sex-linked recessive disease that is historically fatal before adulthood) what is the chance of the Kingdom having an heir to the kingrsquos throne assuming only one child is born
5
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
7 Gregor Mendelrsquos pioneering genetic experiments with pea plants occurred before the discovery of the structure and function of chromosomes Which of the following observations about inheritance in pea plants could be explained only after the discovery that genes may be linked on a chromosome
a Pea color and pea shape display independent inheritance patterns b Offspring of a given cross show all possible combinations of traits in
equal proportions c Most offspring of a given cross have a combination of traits that is
identical to that of either one parent or the other d Recessive phenotypes can skip a generation showing up only in the
parental and F 2 generations
8
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Based on the data in Table I which of the following best explains why there are no individuals with constricted pods in the F 1 generation a Inflated pod shape is dominant to constricted pod shape b The inflated-pod offspring in the F sub one generation are
homozygous c Constricted pod shape typically arises from a new mutation in the F 1
generation d The constricted-pod offspring are carriers for the inflated pod shape
allele
9
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table I the ratio of phenotypes in the offspring from the testcross with F 1 plants that had purple flowers and inflated pods suggests that the genes for flower color and pod shape are located a close together on the same autosome b on the X chromosome c on different chromosomes d on a mitochondrial chromosome
10
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Which of the following provides the best justification for an assumption that might have been used in the computer simulation (Table II) a The broad allele is recessive to the narrow allele because broad
leaves appear in every generation b The purple allele is dominant to the white allele because all the
offspring from the cross of purple-flowered and white-flowered plants had purple flowers
c The narrow allele is codominant with the purple allele because the purple-flower trait and the narrow-leaf trait segregate together
d The white allele is dominant to both the broad and narrow alleles because plants with either type of leaf shape can have white flowers
11
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table II the F 1 offspring of the cross between broad-leaved white-flowered plants with narrow-leaved purple-flowered plants have a phenotype that differs from that of either parent However many testcross offspring have the same phenotype as one of the two plants in the parental cross but relatively few testcross offspring have the same phenotype as the F 1 offspring Which of the following best explains the observation a Recombination between the leaf-shape and flower-color genes resulted in
chromosomes carrying a dominant allele of both genes b Recombination between the broad and narrow alleles of the leaf-shape gene resulted in
chromosomes carrying three different alleles at the same genetic locus c Independent assortment of homologous chromosomes resulted in the combinations of
alleles present in the parental generation d The computer model cannot capture the possible assortments of gametes when
multiple genes are considered
Chromosome Model
Procedure1 add 3-5 beads to a pipe cleaner
to model genes2 twist a 2nd pipe cleaner to the
1st to model the double helix3 tie string to the beads to model
mRNA transcribing DNA4 wrap the whole model around
a cotton ball to represent how DNA supercoils around histones in order to get smaller
5 replicate the 1st to model a sister chromatid
6 tape it to the 1st at about the middle to model the centromere
Partsbull chromosome tightly coiled DNAbull double helix DNA is 2 strands of
nucleotides twisted togetherbull gene small sections of DNA that
encode traitsbull histone proteins that DNA supercoils
around makes the DNA smaller so that it can fit in our cells
bull sister chromatid a duplicated copy of the original DNA still connected to the 1st
bull centromere the place where the 2 sister chromatids are connected (DNA Replication not quite finished)
bull mRNA copies of DNA that read genes
Chromosome Model
Materialsbull pipe cleanersbull beadsbull cotton ballsbull tape
Partsbull chromosome tightly coiled DNAbull double helix DNA is 2 strands of
nucleotides twisted togetherbull gene small sections of DNA that
encode traitsbull histone proteins that DNA
supercoils around makes the DNA smaller so that it can fit in our cells
bull sister chromatid a duplicated copy of the original DNA still connected to the 1st
bull centromere the place where the 2 sister chromatids are connected
bull mRNA copies of DNA that read genes
Chromosome Model
Materialsbull pipe cleanersbull beadsbull cotton ballsbull tape
Partsbull chromosome tightly coiled DNAbull double helix DNA is 2 strands of
nucleotides twisted togetherbull gene small sections of DNA that
encode traitsbull histone proteins that DNA
supercoils around makes the DNA smaller so that it can fit in our cells
bull sister chromatid a duplicated copy of the original DNA still connected to the 1st
bull centromere the place where the 2 sister chromatids are connected
bull mRNA copies of DNA that read genes
Chromosome Model
Materialsbull pipe cleanersbull beadsbull cotton ballsbull tape
Partsbull chromosome tightly coiled DNAbull double helix DNA is 2 strands of
nucleotides twisted togetherbull gene small sections of DNA that
encode traitsbull histone proteins that DNA
supercoils around makes the DNA smaller so that it can fit in our cells
bull sister chromatid a duplicated copy of the original DNA still connected to the 1st
bull centromere the place where the 2 sister chromatids are connected
bull mRNA copies of DNA that read genes
Warm-UP Can you ldquounwindrdquo your model like in the picture to show the parts Sketch and label your model (or the picture of the model) Labels histone mRNA DNA sister chromatid centromere
AP Test Money DUE 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework for Tonight Mitosis Worksheet
UNIT 78 TEST March 19th
Inheritance and Regulation
Due Now Stamp Sheet
Warm-UP
1 Is blowing up a balloon a good model for how cells or organisms grow Explain
2 In what ways are cells different than each other the same
AP Test Money DUE 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework for Tonight 122
UNIT 78 TEST March 19th
Inheritance and Regulation
AP Test Money DUE 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework for Tonight
Warm-UP
1 Is blowing up a balloon a good model for how cells or organisms grow Explain
2 In what ways are cells different than each other the same
AP Test Money DUE 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework for Tonight
Warm-UP
1 Is blowing up a balloon a good model for how cells or organisms grow Explain
2 In what ways are cells different than each other the same
AP Test Money DUE 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework for Tonight
Warm-UP
1 Is blowing up a balloon a good model for how cells or organisms grow Explain
2 In what ways are cells different than each other the same
In eukaryotic organisms heritable information is passed to the next generation via mitosis and
meiosis
Cell Division 2 Types Mitosis and Meiosis
Mitosisbull Purpose
growth repair asexual reproduction (actually
binary fission in prokaryotes)bull occurs after DNA replicationbull is followed by cytokinesisbull 2 genetically identical daughter cells
(clones)bull Steps
1 Replication2 Alignment3 Separation
1 Draw a big cell with a nucleus inside2 Add homologous pairs of chromosomes
ndash 1 big yellow 1 big whitendash 1 medium yellow 1 medium whitendash 1 small yellow 1 small white
3 Clone each chromosome (DNA Replication) (making sister chromatids)
4 Nucleus breaks down (erase it)5 Clones separate one to each side of cell6 Cytokinesis cell membrane grows between the 2
halves7 Nucleus grows around chromosomes
Mitosis Modeling
When yoursquore confident on the process show Mr Jones
bull When yoursquore confident on the process show Mr Jones
bull In your notebookTable 127 Stages of Mitosis p232At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid
Mitosis Modeling
Analysis
1 What is the outcome of mitosis2 What steps of mitosis ensure a perfect
outcome3 If the first cell has 46 chromosomes (before
cloning) how many does each daughter cell have
4 Why do cells go through mitosis
Mitosis Modeling
Words to Knowbull Nucleusbull DNAbull Histonesbull Chromatinbull Chromosomebull Chromatidbull Centromere
Copyright copy 2002 Pearson Education Inc publishing as Benjamin Cummings
Interphase ldquoSrdquo phase
Mitosis
Warm-UP
1Advantages of Sex
2Disadvantages of Sex
AP Test Money DUE 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Thurs Meiosis Wksht
UNIT 78 TEST March 19th
Inheritance and Regulation
Fig 13-2
Bacteria
Parent
Bud
05 mmAsexual Reproduction
Advantages1 Can be done in isolation2 If you are perfect why change
Best when an organism is ldquoperfectlyrdquo suited for its environment
3 Less ldquomachineryrdquo needed no waste on flowers ldquonewrdquo types of cells or other secondary sexual characteristics
Disadvantages1 Less variety Poor option in a
changing environmentPlants
Fig 13-2
Parent
Bud
05 mmAsexual Reproduction
Advantages1 Can be done in isolation2 If you are perfect why change
Best when an organism is ldquoperfectlyrdquo suited for its environment
3 Less ldquomachineryrdquo needed no waste on flowers ldquonewrdquo types of cells or other secondary sexual characteristics
Disadvantages1 Less variety Poor option in a
changing environment
Fig 13-2
Parent
Bud
05 mmAsexual Reproduction
Advantages1 Can be done in isolation2 If you are perfect why change
Best when an organism is ldquoperfectlyrdquo suited for its environment
3 Less ldquomachineryrdquo needed no waste on flowers ldquonewrdquo types of cells or other secondary sexual characteristics
Disadvantages1 Less variety Poor option in a
changing environment
Aspen
Fig 13-1
Sexual ReproductionAdvantages1 Increased variety Best when
environment is changing
Increased Variety is DUE TObull random fertilizationbull meiosis
bull independent assortmentbull crossing-over
Disadvantages1 Resource investment
bull specialized cells gametesbull secondary sexual
characteristics mate attraction2 Requires a partner (except when
plants self-fertilize)
In eukaryotic organisms heritable information is passed to the next generation via mitosis and
meiosisCell Division 2 Types
Meiosis sex cells (gametes) (spermeggs)bull Purpose
ensures that each gamete receives one complete haploid (1n) set of chromosomes
Ensures chromosome number stays the same each offspring receives frac12 (1n) of the full set for the species (2n)
bull Steps1 DNA Replication2 homologous pairs form a tetrad
(independent assortment) (genetic variation increases)
3 cross over between homologous chromosomes may occur (genetic variation increases)
4 Meiosis I homologous pairs separate5 Meiosis II sister chromatids separate
In eukaryotic organisms heritable information is passed to the next generation via mitosis and
meiosisCell Division 2 Types
Meiosis sex cells (gametes) (spermeggs)bull Purpose
ensures that each gamete receives one complete haploid (1n) set of chromosomes
Ensures chromosome number stays the same each offspring receives frac12 (1n) of the full set for the species (2n)
bull Steps1 DNA Replication2 homologous pairs form a tetrad
(independent assortment) (genetic variation increases)
3 cross over between homologous chromosomes may occur (genetic variation increases)
4 Meiosis I homologous pairs separate5 Meiosis II sister chromatids separate
In eukaryotic organisms heritable information is passed to the next generation via mitosis and
meiosisCell Division 2 Types
Meiosis sex cells (gametes) (spermeggs)bull Purpose
ensures that each gamete receives one complete haploid (1n) set of chromosomes
Ensures chromosome number stays the same each offspring receives frac12 (1n) of the full set for the species (2n)
bull Steps1 DNA Replication2 homologous pairs form a tetrad
(independent assortment) (genetic variation increases)
3 cross over between homologous chromosomes may occur (genetic variation increases)
4 Meiosis I homologous pairs separate5 Meiosis II sister chromatids separate
1 Build your diploid cell (an homologous pair for each chromosome)a Draw a big cell with a nucleus insideb Add homologous pairs of chromosomes
bull 1 big white 1 big yellowbull 1 medium white 1 medium yellowbull 1 small white 1 small yellow
2 Clone each chromosome (DNA Replication) (making sister chromatids)3 Nucleus breaks down (erase it)4 Homologous pairs form a tetrad crossing over may occur (note do not model crossing
over for now)5 Homologous pairs separate one to each side of cell all paternal (or all maternal) do NOT
have to go together (independent assortment)6 Cytokinesis cell membrane grows between the 2 halves7 Clones (sister chromatids) separate (centromere ldquobreaksrdquo as DNA polymerization
completes) one to each side of cell8 Cytokinesis cell membrane grows between the 2 halves9 Nucleus grows around chromosomes 4 cells made (gametes which have half the
number of chromosomes (haploids)
Meiosis Modeling
When yoursquore confident on the process show Mr Jones
Meiosis Modelingbull When yoursquore confident on the process show Mr Jones
bull In your notebookTable 138 Stages of Meiosis p255At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid crossing over recombinant chromosome independent assortment Meiosis I Meiosis II
Meiosis Modeling
Analysis
1 What is the outcome of meiosis2 What steps of meiosis cause variation3 If the first cell has 46 chromosomes (before
cloning) how many does each daughter cell have4 How many unique gametes did you form How
many could have formed5 Why do cells go through meiosis
Warm-UP 1 Why do meiosis2 How does meiosis increase variation in organisms
AP Test Money DUE 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Tomorrow Meiosis Wksht
UNIT 78 TEST March 19th
Inheritance and Regulation
Meiosis has multiple processes that increases genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Meiosis has multiple processes that increase genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Meiosis has multiple processes that increase genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Meiosis has multiple processes that increases genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Warm-UP Watch the video What is happening Why does this happen How does this increase variation
AP Test Money DUE TOMORROW 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Tomorrow
UNIT 78 TEST March 19th
Inheritance and Regulation
Fig 13-9a
MITOSIS MEIOSIS
MEIOSIS I
Prophase I
Chiasma
Chromosomereplication
Homologouschromosomepair
Chromosomereplication
2n = 6
Parent cell
Prophase
Replicated chromosome
Metaphase Metaphase I
Anaphase ITelophase I
Haploid n = 3
Daughter cells ofmeiosis I
MEIOSIS II
Daughter cells of meiosis II
nnnn
2n2n
Daughter cellsof mitosis
AnaphaseTelophase
Compare
Contrast
Independent Assortment
Crossing-over Sexual Fertilization Mutation
Types of Changes to Cells Think About what where when how how much variation created
Warm-UP Now we need to keep track of the genes on the chromosomes that are inherited Notice the letters on the chromosomes They represent different alleles for Huntingtons Barbie has Huntingtons What is the chance her child will get Huntingtons
AP Test Money DUE 36 TOMORROWRemember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Tomorrow 141 5 Key Ideas AND Concept Check 1-3
H=dominant (remember Huntingtonrsquos is dominant)
h=recessive (no Huntingtonrsquos)
Homework DUE Monday Test Corrections for 10 Make-UP
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
AP Test Money DUE 36 TODAYRemember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
DUE next Thursday Monohybrid Crosses
Homework DUE Monday Test Corrections for 10 Make-UP
Warm-UP Now we need to keep track of TWO UNLINKED genes on the chromosomes that are inherited Notice the letters on the chromosomes They represent different alleles for Huntingtons and red hair color Barbie has Huntingtons and is a blond (but a carrier) Ken does not have Huntingtonrsquos and is also a carrier for red hair What is the chance their child will get Huntingtons and red hair
Homework DUE Tomorrow 142 5 Key Ideas AND Concept Check 1-3
H= Huntingtonrsquosh=no HuntingtonrsquosR= no red hairr= red hair
DUE Now Test Corrections for 10 Make-UP
UNIT 78 TEST March 19th
Inheritance and Regulation
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
Homework DUE Tomorrow 143 5 Key Ideas AND Concept Check 1-3
DUE Now 142DUE Thursday Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
UNIT 78 TEST March 19th
Inheritance and Regulation
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoods
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with RrYy
1 Chance of baby with Rr 052 Chance of baby with Yy 053 Chance of baby with RrYy 025
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with both dominant phenotypes
1 Chance of baby with at least one R 0752 Chance of baby with at least one Y 0753 Chance of baby with RrYy 05625 (916)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with both dominant phenotypes
1 Chance of baby with at least one R 10
2 Chance of baby with at least one Y 10
3 Chance of baby with both dominant phenotypes 10
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
Homework DUE Tomorrow Linked vs Unlinked Genes AND Monohybrid Crosses to tunritincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with
vestigial wings and cinnabar eyes Predict the phenotypic ratio of the F2 individuals
Homework DUE Tomorrow 153 5 Key Ideas and Concept Check 1-3DUE Thursday Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with vestigial wings and cinnabar eyes Predict the
phenotypic ratio of the F2 individuals
3 The results of the cross from 2 show the following outcome Individuals of each phenotype are shown in the table Which of the following is the most likely explanation of the results a The two genes are located on two different chromosomes b The two genes are sex-linked c The two genes are located on mitochondrial DNA d The two genes are linked on an autosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
1 Build your diploid cell (an homologous pair for each chromosome)a Draw a big cell with a nucleus insideb DRAW homologous pairs of chromosomes
bull 1 big blue 1 big redbull 1 small blue 1 small red
ndash Add genes to your chromosomebull Write an H and an R on big blue and an h and an r on big redbull Write a T on small blue and a t on small red
2 Clone each chromosome (DNA Replication) (making sister chromatids)3 Nucleus breaks down (erase it)4 Homologous pairs form a tetrad crossing over may occur (note do not model
crossing over for now)5 Finish meiosis (see notes for help)6 Nucleus grows around chromosomes 4 cells made (gametes which have half
the number of chromosomes (haploids)7 Repeat Steps 1-6 this time at Step 4 include ONE crossover event
Recombination Modeling
When yoursquore confident on the process show Mr Jones
bull When yoursquore confident on the process show Mr Jones
bull In your notebookFigure 1510 Recombination p295At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid crossing over recombinant chromosome independent assortment Meiosis I Meiosis II
Recombination Modeling
Analysis
1 How does recombination increase the variety of gametes formed
2 Which types of gametes were more likely Gametes with recombinant chromosomes or ones without
3 Recombination is a random process How might it benefithurt the survival of an individualspecies
Recombination Modeling
Warm-UP
1 How could you calculate recombination frequency2 What would the recombination frequency tell you about the relative position of
genes on a chromosome3 Genes A B and C are on the same chromosome Testcrosses show that the
recombination frequency between A and B is 28 and between A and C is 12 Can you determine the linear order of these genes
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP What can we learn about inheritance from looking at a pedigree (use example of the Royal Family of Europe from the early 1900s)
Warm-UP In the following human pedigree squares represent males circles represent females and shaded symbols indicate individuals affected with a disorder One of the affected males from the third generation has a child with a female who is a carrier For the pedigree shown which of the following best expresses the probability that the couplersquos first son will be affected with the disorder
(A) 25 (B) 50 (C) 75 (D) 100
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Is a widowrsquos peak a dominant or recessive trait
Is a widowrsquos peak a dominant or recessive trait
Fig 14-UN5
George
Sandra Tom Sam
Arlene
Wilma Ann Michael
Carla
Daniel Alan Tina
Christopher
A heterozygous tall and a homozygous purple flowered plant is crossed with a short and white flowered plant Predict the offspring Assume independent assortment
1
P=purplep=whiteT=tallt=short
For a plant with the genotype WwXxYyZz what is the probability that the plant will produce a gamete with a haploid genotype of Wxyz Give your answer as a fraction or as a value between 0 and 1 to four decimal places
2
A completely-plated stickleback from a marine population was mated to a low-plated stickleback from a freshwater population The resulting F1 hybrids all displayed a completely plated phenotype When the F1 hybrids were allowed to interbreed the resulting F2 generation included completely plated offspring and low-plated offspring in an approximate 31 ratio Which of the following conclusions is best supported by the results of the breeding experiments
a Phenotypic variation in the F2 generation suggests that armor morphology is controlled by many alleles of a single gene
b The completely-plated phenotype is controlled by a dominant allele of a single gene
c Armor loss is an acquired characteristic that is affected by one or more environmental factors
d Patterns of armor plating in stickleback populations are regulated by sex-specific signals
3
If a man with type AB blood marries a woman with type O what blood types would you expect in their children What fraction would you expect of each type
4
IA= Type AIB= Type Bi= Type O
If a King marries a Queen that is a carrier of hemophilia (sex-linked recessive disease that is historically fatal before adulthood) what is the chance of the Kingdom having an heir to the kingrsquos throne assuming only one child is born
5
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
7 Gregor Mendelrsquos pioneering genetic experiments with pea plants occurred before the discovery of the structure and function of chromosomes Which of the following observations about inheritance in pea plants could be explained only after the discovery that genes may be linked on a chromosome
a Pea color and pea shape display independent inheritance patterns b Offspring of a given cross show all possible combinations of traits in
equal proportions c Most offspring of a given cross have a combination of traits that is
identical to that of either one parent or the other d Recessive phenotypes can skip a generation showing up only in the
parental and F 2 generations
8
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Based on the data in Table I which of the following best explains why there are no individuals with constricted pods in the F 1 generation a Inflated pod shape is dominant to constricted pod shape b The inflated-pod offspring in the F sub one generation are
homozygous c Constricted pod shape typically arises from a new mutation in the F 1
generation d The constricted-pod offspring are carriers for the inflated pod shape
allele
9
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table I the ratio of phenotypes in the offspring from the testcross with F 1 plants that had purple flowers and inflated pods suggests that the genes for flower color and pod shape are located a close together on the same autosome b on the X chromosome c on different chromosomes d on a mitochondrial chromosome
10
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Which of the following provides the best justification for an assumption that might have been used in the computer simulation (Table II) a The broad allele is recessive to the narrow allele because broad
leaves appear in every generation b The purple allele is dominant to the white allele because all the
offspring from the cross of purple-flowered and white-flowered plants had purple flowers
c The narrow allele is codominant with the purple allele because the purple-flower trait and the narrow-leaf trait segregate together
d The white allele is dominant to both the broad and narrow alleles because plants with either type of leaf shape can have white flowers
11
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table II the F 1 offspring of the cross between broad-leaved white-flowered plants with narrow-leaved purple-flowered plants have a phenotype that differs from that of either parent However many testcross offspring have the same phenotype as one of the two plants in the parental cross but relatively few testcross offspring have the same phenotype as the F 1 offspring Which of the following best explains the observation a Recombination between the leaf-shape and flower-color genes resulted in
chromosomes carrying a dominant allele of both genes b Recombination between the broad and narrow alleles of the leaf-shape gene resulted in
chromosomes carrying three different alleles at the same genetic locus c Independent assortment of homologous chromosomes resulted in the combinations of
alleles present in the parental generation d The computer model cannot capture the possible assortments of gametes when
multiple genes are considered
Chromosome Model
Materialsbull pipe cleanersbull beadsbull cotton ballsbull tape
Partsbull chromosome tightly coiled DNAbull double helix DNA is 2 strands of
nucleotides twisted togetherbull gene small sections of DNA that
encode traitsbull histone proteins that DNA
supercoils around makes the DNA smaller so that it can fit in our cells
bull sister chromatid a duplicated copy of the original DNA still connected to the 1st
bull centromere the place where the 2 sister chromatids are connected
bull mRNA copies of DNA that read genes
Chromosome Model
Materialsbull pipe cleanersbull beadsbull cotton ballsbull tape
Partsbull chromosome tightly coiled DNAbull double helix DNA is 2 strands of
nucleotides twisted togetherbull gene small sections of DNA that
encode traitsbull histone proteins that DNA
supercoils around makes the DNA smaller so that it can fit in our cells
bull sister chromatid a duplicated copy of the original DNA still connected to the 1st
bull centromere the place where the 2 sister chromatids are connected
bull mRNA copies of DNA that read genes
Chromosome Model
Materialsbull pipe cleanersbull beadsbull cotton ballsbull tape
Partsbull chromosome tightly coiled DNAbull double helix DNA is 2 strands of
nucleotides twisted togetherbull gene small sections of DNA that
encode traitsbull histone proteins that DNA
supercoils around makes the DNA smaller so that it can fit in our cells
bull sister chromatid a duplicated copy of the original DNA still connected to the 1st
bull centromere the place where the 2 sister chromatids are connected
bull mRNA copies of DNA that read genes
Warm-UP Can you ldquounwindrdquo your model like in the picture to show the parts Sketch and label your model (or the picture of the model) Labels histone mRNA DNA sister chromatid centromere
AP Test Money DUE 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework for Tonight Mitosis Worksheet
UNIT 78 TEST March 19th
Inheritance and Regulation
Due Now Stamp Sheet
Warm-UP
1 Is blowing up a balloon a good model for how cells or organisms grow Explain
2 In what ways are cells different than each other the same
AP Test Money DUE 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework for Tonight 122
UNIT 78 TEST March 19th
Inheritance and Regulation
AP Test Money DUE 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework for Tonight
Warm-UP
1 Is blowing up a balloon a good model for how cells or organisms grow Explain
2 In what ways are cells different than each other the same
AP Test Money DUE 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework for Tonight
Warm-UP
1 Is blowing up a balloon a good model for how cells or organisms grow Explain
2 In what ways are cells different than each other the same
AP Test Money DUE 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework for Tonight
Warm-UP
1 Is blowing up a balloon a good model for how cells or organisms grow Explain
2 In what ways are cells different than each other the same
In eukaryotic organisms heritable information is passed to the next generation via mitosis and
meiosis
Cell Division 2 Types Mitosis and Meiosis
Mitosisbull Purpose
growth repair asexual reproduction (actually
binary fission in prokaryotes)bull occurs after DNA replicationbull is followed by cytokinesisbull 2 genetically identical daughter cells
(clones)bull Steps
1 Replication2 Alignment3 Separation
1 Draw a big cell with a nucleus inside2 Add homologous pairs of chromosomes
ndash 1 big yellow 1 big whitendash 1 medium yellow 1 medium whitendash 1 small yellow 1 small white
3 Clone each chromosome (DNA Replication) (making sister chromatids)
4 Nucleus breaks down (erase it)5 Clones separate one to each side of cell6 Cytokinesis cell membrane grows between the 2
halves7 Nucleus grows around chromosomes
Mitosis Modeling
When yoursquore confident on the process show Mr Jones
bull When yoursquore confident on the process show Mr Jones
bull In your notebookTable 127 Stages of Mitosis p232At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid
Mitosis Modeling
Analysis
1 What is the outcome of mitosis2 What steps of mitosis ensure a perfect
outcome3 If the first cell has 46 chromosomes (before
cloning) how many does each daughter cell have
4 Why do cells go through mitosis
Mitosis Modeling
Words to Knowbull Nucleusbull DNAbull Histonesbull Chromatinbull Chromosomebull Chromatidbull Centromere
Copyright copy 2002 Pearson Education Inc publishing as Benjamin Cummings
Interphase ldquoSrdquo phase
Mitosis
Warm-UP
1Advantages of Sex
2Disadvantages of Sex
AP Test Money DUE 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Thurs Meiosis Wksht
UNIT 78 TEST March 19th
Inheritance and Regulation
Fig 13-2
Bacteria
Parent
Bud
05 mmAsexual Reproduction
Advantages1 Can be done in isolation2 If you are perfect why change
Best when an organism is ldquoperfectlyrdquo suited for its environment
3 Less ldquomachineryrdquo needed no waste on flowers ldquonewrdquo types of cells or other secondary sexual characteristics
Disadvantages1 Less variety Poor option in a
changing environmentPlants
Fig 13-2
Parent
Bud
05 mmAsexual Reproduction
Advantages1 Can be done in isolation2 If you are perfect why change
Best when an organism is ldquoperfectlyrdquo suited for its environment
3 Less ldquomachineryrdquo needed no waste on flowers ldquonewrdquo types of cells or other secondary sexual characteristics
Disadvantages1 Less variety Poor option in a
changing environment
Fig 13-2
Parent
Bud
05 mmAsexual Reproduction
Advantages1 Can be done in isolation2 If you are perfect why change
Best when an organism is ldquoperfectlyrdquo suited for its environment
3 Less ldquomachineryrdquo needed no waste on flowers ldquonewrdquo types of cells or other secondary sexual characteristics
Disadvantages1 Less variety Poor option in a
changing environment
Aspen
Fig 13-1
Sexual ReproductionAdvantages1 Increased variety Best when
environment is changing
Increased Variety is DUE TObull random fertilizationbull meiosis
bull independent assortmentbull crossing-over
Disadvantages1 Resource investment
bull specialized cells gametesbull secondary sexual
characteristics mate attraction2 Requires a partner (except when
plants self-fertilize)
In eukaryotic organisms heritable information is passed to the next generation via mitosis and
meiosisCell Division 2 Types
Meiosis sex cells (gametes) (spermeggs)bull Purpose
ensures that each gamete receives one complete haploid (1n) set of chromosomes
Ensures chromosome number stays the same each offspring receives frac12 (1n) of the full set for the species (2n)
bull Steps1 DNA Replication2 homologous pairs form a tetrad
(independent assortment) (genetic variation increases)
3 cross over between homologous chromosomes may occur (genetic variation increases)
4 Meiosis I homologous pairs separate5 Meiosis II sister chromatids separate
In eukaryotic organisms heritable information is passed to the next generation via mitosis and
meiosisCell Division 2 Types
Meiosis sex cells (gametes) (spermeggs)bull Purpose
ensures that each gamete receives one complete haploid (1n) set of chromosomes
Ensures chromosome number stays the same each offspring receives frac12 (1n) of the full set for the species (2n)
bull Steps1 DNA Replication2 homologous pairs form a tetrad
(independent assortment) (genetic variation increases)
3 cross over between homologous chromosomes may occur (genetic variation increases)
4 Meiosis I homologous pairs separate5 Meiosis II sister chromatids separate
In eukaryotic organisms heritable information is passed to the next generation via mitosis and
meiosisCell Division 2 Types
Meiosis sex cells (gametes) (spermeggs)bull Purpose
ensures that each gamete receives one complete haploid (1n) set of chromosomes
Ensures chromosome number stays the same each offspring receives frac12 (1n) of the full set for the species (2n)
bull Steps1 DNA Replication2 homologous pairs form a tetrad
(independent assortment) (genetic variation increases)
3 cross over between homologous chromosomes may occur (genetic variation increases)
4 Meiosis I homologous pairs separate5 Meiosis II sister chromatids separate
1 Build your diploid cell (an homologous pair for each chromosome)a Draw a big cell with a nucleus insideb Add homologous pairs of chromosomes
bull 1 big white 1 big yellowbull 1 medium white 1 medium yellowbull 1 small white 1 small yellow
2 Clone each chromosome (DNA Replication) (making sister chromatids)3 Nucleus breaks down (erase it)4 Homologous pairs form a tetrad crossing over may occur (note do not model crossing
over for now)5 Homologous pairs separate one to each side of cell all paternal (or all maternal) do NOT
have to go together (independent assortment)6 Cytokinesis cell membrane grows between the 2 halves7 Clones (sister chromatids) separate (centromere ldquobreaksrdquo as DNA polymerization
completes) one to each side of cell8 Cytokinesis cell membrane grows between the 2 halves9 Nucleus grows around chromosomes 4 cells made (gametes which have half the
number of chromosomes (haploids)
Meiosis Modeling
When yoursquore confident on the process show Mr Jones
Meiosis Modelingbull When yoursquore confident on the process show Mr Jones
bull In your notebookTable 138 Stages of Meiosis p255At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid crossing over recombinant chromosome independent assortment Meiosis I Meiosis II
Meiosis Modeling
Analysis
1 What is the outcome of meiosis2 What steps of meiosis cause variation3 If the first cell has 46 chromosomes (before
cloning) how many does each daughter cell have4 How many unique gametes did you form How
many could have formed5 Why do cells go through meiosis
Warm-UP 1 Why do meiosis2 How does meiosis increase variation in organisms
AP Test Money DUE 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Tomorrow Meiosis Wksht
UNIT 78 TEST March 19th
Inheritance and Regulation
Meiosis has multiple processes that increases genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Meiosis has multiple processes that increase genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Meiosis has multiple processes that increase genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Meiosis has multiple processes that increases genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Warm-UP Watch the video What is happening Why does this happen How does this increase variation
AP Test Money DUE TOMORROW 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Tomorrow
UNIT 78 TEST March 19th
Inheritance and Regulation
Fig 13-9a
MITOSIS MEIOSIS
MEIOSIS I
Prophase I
Chiasma
Chromosomereplication
Homologouschromosomepair
Chromosomereplication
2n = 6
Parent cell
Prophase
Replicated chromosome
Metaphase Metaphase I
Anaphase ITelophase I
Haploid n = 3
Daughter cells ofmeiosis I
MEIOSIS II
Daughter cells of meiosis II
nnnn
2n2n
Daughter cellsof mitosis
AnaphaseTelophase
Compare
Contrast
Independent Assortment
Crossing-over Sexual Fertilization Mutation
Types of Changes to Cells Think About what where when how how much variation created
Warm-UP Now we need to keep track of the genes on the chromosomes that are inherited Notice the letters on the chromosomes They represent different alleles for Huntingtons Barbie has Huntingtons What is the chance her child will get Huntingtons
AP Test Money DUE 36 TOMORROWRemember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Tomorrow 141 5 Key Ideas AND Concept Check 1-3
H=dominant (remember Huntingtonrsquos is dominant)
h=recessive (no Huntingtonrsquos)
Homework DUE Monday Test Corrections for 10 Make-UP
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
AP Test Money DUE 36 TODAYRemember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
DUE next Thursday Monohybrid Crosses
Homework DUE Monday Test Corrections for 10 Make-UP
Warm-UP Now we need to keep track of TWO UNLINKED genes on the chromosomes that are inherited Notice the letters on the chromosomes They represent different alleles for Huntingtons and red hair color Barbie has Huntingtons and is a blond (but a carrier) Ken does not have Huntingtonrsquos and is also a carrier for red hair What is the chance their child will get Huntingtons and red hair
Homework DUE Tomorrow 142 5 Key Ideas AND Concept Check 1-3
H= Huntingtonrsquosh=no HuntingtonrsquosR= no red hairr= red hair
DUE Now Test Corrections for 10 Make-UP
UNIT 78 TEST March 19th
Inheritance and Regulation
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
Homework DUE Tomorrow 143 5 Key Ideas AND Concept Check 1-3
DUE Now 142DUE Thursday Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
UNIT 78 TEST March 19th
Inheritance and Regulation
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoods
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with RrYy
1 Chance of baby with Rr 052 Chance of baby with Yy 053 Chance of baby with RrYy 025
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with both dominant phenotypes
1 Chance of baby with at least one R 0752 Chance of baby with at least one Y 0753 Chance of baby with RrYy 05625 (916)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with both dominant phenotypes
1 Chance of baby with at least one R 10
2 Chance of baby with at least one Y 10
3 Chance of baby with both dominant phenotypes 10
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
Homework DUE Tomorrow Linked vs Unlinked Genes AND Monohybrid Crosses to tunritincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with
vestigial wings and cinnabar eyes Predict the phenotypic ratio of the F2 individuals
Homework DUE Tomorrow 153 5 Key Ideas and Concept Check 1-3DUE Thursday Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with vestigial wings and cinnabar eyes Predict the
phenotypic ratio of the F2 individuals
3 The results of the cross from 2 show the following outcome Individuals of each phenotype are shown in the table Which of the following is the most likely explanation of the results a The two genes are located on two different chromosomes b The two genes are sex-linked c The two genes are located on mitochondrial DNA d The two genes are linked on an autosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
1 Build your diploid cell (an homologous pair for each chromosome)a Draw a big cell with a nucleus insideb DRAW homologous pairs of chromosomes
bull 1 big blue 1 big redbull 1 small blue 1 small red
ndash Add genes to your chromosomebull Write an H and an R on big blue and an h and an r on big redbull Write a T on small blue and a t on small red
2 Clone each chromosome (DNA Replication) (making sister chromatids)3 Nucleus breaks down (erase it)4 Homologous pairs form a tetrad crossing over may occur (note do not model
crossing over for now)5 Finish meiosis (see notes for help)6 Nucleus grows around chromosomes 4 cells made (gametes which have half
the number of chromosomes (haploids)7 Repeat Steps 1-6 this time at Step 4 include ONE crossover event
Recombination Modeling
When yoursquore confident on the process show Mr Jones
bull When yoursquore confident on the process show Mr Jones
bull In your notebookFigure 1510 Recombination p295At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid crossing over recombinant chromosome independent assortment Meiosis I Meiosis II
Recombination Modeling
Analysis
1 How does recombination increase the variety of gametes formed
2 Which types of gametes were more likely Gametes with recombinant chromosomes or ones without
3 Recombination is a random process How might it benefithurt the survival of an individualspecies
Recombination Modeling
Warm-UP
1 How could you calculate recombination frequency2 What would the recombination frequency tell you about the relative position of
genes on a chromosome3 Genes A B and C are on the same chromosome Testcrosses show that the
recombination frequency between A and B is 28 and between A and C is 12 Can you determine the linear order of these genes
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP What can we learn about inheritance from looking at a pedigree (use example of the Royal Family of Europe from the early 1900s)
Warm-UP In the following human pedigree squares represent males circles represent females and shaded symbols indicate individuals affected with a disorder One of the affected males from the third generation has a child with a female who is a carrier For the pedigree shown which of the following best expresses the probability that the couplersquos first son will be affected with the disorder
(A) 25 (B) 50 (C) 75 (D) 100
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Is a widowrsquos peak a dominant or recessive trait
Is a widowrsquos peak a dominant or recessive trait
Fig 14-UN5
George
Sandra Tom Sam
Arlene
Wilma Ann Michael
Carla
Daniel Alan Tina
Christopher
A heterozygous tall and a homozygous purple flowered plant is crossed with a short and white flowered plant Predict the offspring Assume independent assortment
1
P=purplep=whiteT=tallt=short
For a plant with the genotype WwXxYyZz what is the probability that the plant will produce a gamete with a haploid genotype of Wxyz Give your answer as a fraction or as a value between 0 and 1 to four decimal places
2
A completely-plated stickleback from a marine population was mated to a low-plated stickleback from a freshwater population The resulting F1 hybrids all displayed a completely plated phenotype When the F1 hybrids were allowed to interbreed the resulting F2 generation included completely plated offspring and low-plated offspring in an approximate 31 ratio Which of the following conclusions is best supported by the results of the breeding experiments
a Phenotypic variation in the F2 generation suggests that armor morphology is controlled by many alleles of a single gene
b The completely-plated phenotype is controlled by a dominant allele of a single gene
c Armor loss is an acquired characteristic that is affected by one or more environmental factors
d Patterns of armor plating in stickleback populations are regulated by sex-specific signals
3
If a man with type AB blood marries a woman with type O what blood types would you expect in their children What fraction would you expect of each type
4
IA= Type AIB= Type Bi= Type O
If a King marries a Queen that is a carrier of hemophilia (sex-linked recessive disease that is historically fatal before adulthood) what is the chance of the Kingdom having an heir to the kingrsquos throne assuming only one child is born
5
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
7 Gregor Mendelrsquos pioneering genetic experiments with pea plants occurred before the discovery of the structure and function of chromosomes Which of the following observations about inheritance in pea plants could be explained only after the discovery that genes may be linked on a chromosome
a Pea color and pea shape display independent inheritance patterns b Offspring of a given cross show all possible combinations of traits in
equal proportions c Most offspring of a given cross have a combination of traits that is
identical to that of either one parent or the other d Recessive phenotypes can skip a generation showing up only in the
parental and F 2 generations
8
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Based on the data in Table I which of the following best explains why there are no individuals with constricted pods in the F 1 generation a Inflated pod shape is dominant to constricted pod shape b The inflated-pod offspring in the F sub one generation are
homozygous c Constricted pod shape typically arises from a new mutation in the F 1
generation d The constricted-pod offspring are carriers for the inflated pod shape
allele
9
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table I the ratio of phenotypes in the offspring from the testcross with F 1 plants that had purple flowers and inflated pods suggests that the genes for flower color and pod shape are located a close together on the same autosome b on the X chromosome c on different chromosomes d on a mitochondrial chromosome
10
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Which of the following provides the best justification for an assumption that might have been used in the computer simulation (Table II) a The broad allele is recessive to the narrow allele because broad
leaves appear in every generation b The purple allele is dominant to the white allele because all the
offspring from the cross of purple-flowered and white-flowered plants had purple flowers
c The narrow allele is codominant with the purple allele because the purple-flower trait and the narrow-leaf trait segregate together
d The white allele is dominant to both the broad and narrow alleles because plants with either type of leaf shape can have white flowers
11
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table II the F 1 offspring of the cross between broad-leaved white-flowered plants with narrow-leaved purple-flowered plants have a phenotype that differs from that of either parent However many testcross offspring have the same phenotype as one of the two plants in the parental cross but relatively few testcross offspring have the same phenotype as the F 1 offspring Which of the following best explains the observation a Recombination between the leaf-shape and flower-color genes resulted in
chromosomes carrying a dominant allele of both genes b Recombination between the broad and narrow alleles of the leaf-shape gene resulted in
chromosomes carrying three different alleles at the same genetic locus c Independent assortment of homologous chromosomes resulted in the combinations of
alleles present in the parental generation d The computer model cannot capture the possible assortments of gametes when
multiple genes are considered
Chromosome Model
Materialsbull pipe cleanersbull beadsbull cotton ballsbull tape
Partsbull chromosome tightly coiled DNAbull double helix DNA is 2 strands of
nucleotides twisted togetherbull gene small sections of DNA that
encode traitsbull histone proteins that DNA
supercoils around makes the DNA smaller so that it can fit in our cells
bull sister chromatid a duplicated copy of the original DNA still connected to the 1st
bull centromere the place where the 2 sister chromatids are connected
bull mRNA copies of DNA that read genes
Chromosome Model
Materialsbull pipe cleanersbull beadsbull cotton ballsbull tape
Partsbull chromosome tightly coiled DNAbull double helix DNA is 2 strands of
nucleotides twisted togetherbull gene small sections of DNA that
encode traitsbull histone proteins that DNA
supercoils around makes the DNA smaller so that it can fit in our cells
bull sister chromatid a duplicated copy of the original DNA still connected to the 1st
bull centromere the place where the 2 sister chromatids are connected
bull mRNA copies of DNA that read genes
Warm-UP Can you ldquounwindrdquo your model like in the picture to show the parts Sketch and label your model (or the picture of the model) Labels histone mRNA DNA sister chromatid centromere
AP Test Money DUE 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework for Tonight Mitosis Worksheet
UNIT 78 TEST March 19th
Inheritance and Regulation
Due Now Stamp Sheet
Warm-UP
1 Is blowing up a balloon a good model for how cells or organisms grow Explain
2 In what ways are cells different than each other the same
AP Test Money DUE 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework for Tonight 122
UNIT 78 TEST March 19th
Inheritance and Regulation
AP Test Money DUE 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework for Tonight
Warm-UP
1 Is blowing up a balloon a good model for how cells or organisms grow Explain
2 In what ways are cells different than each other the same
AP Test Money DUE 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework for Tonight
Warm-UP
1 Is blowing up a balloon a good model for how cells or organisms grow Explain
2 In what ways are cells different than each other the same
AP Test Money DUE 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework for Tonight
Warm-UP
1 Is blowing up a balloon a good model for how cells or organisms grow Explain
2 In what ways are cells different than each other the same
In eukaryotic organisms heritable information is passed to the next generation via mitosis and
meiosis
Cell Division 2 Types Mitosis and Meiosis
Mitosisbull Purpose
growth repair asexual reproduction (actually
binary fission in prokaryotes)bull occurs after DNA replicationbull is followed by cytokinesisbull 2 genetically identical daughter cells
(clones)bull Steps
1 Replication2 Alignment3 Separation
1 Draw a big cell with a nucleus inside2 Add homologous pairs of chromosomes
ndash 1 big yellow 1 big whitendash 1 medium yellow 1 medium whitendash 1 small yellow 1 small white
3 Clone each chromosome (DNA Replication) (making sister chromatids)
4 Nucleus breaks down (erase it)5 Clones separate one to each side of cell6 Cytokinesis cell membrane grows between the 2
halves7 Nucleus grows around chromosomes
Mitosis Modeling
When yoursquore confident on the process show Mr Jones
bull When yoursquore confident on the process show Mr Jones
bull In your notebookTable 127 Stages of Mitosis p232At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid
Mitosis Modeling
Analysis
1 What is the outcome of mitosis2 What steps of mitosis ensure a perfect
outcome3 If the first cell has 46 chromosomes (before
cloning) how many does each daughter cell have
4 Why do cells go through mitosis
Mitosis Modeling
Words to Knowbull Nucleusbull DNAbull Histonesbull Chromatinbull Chromosomebull Chromatidbull Centromere
Copyright copy 2002 Pearson Education Inc publishing as Benjamin Cummings
Interphase ldquoSrdquo phase
Mitosis
Warm-UP
1Advantages of Sex
2Disadvantages of Sex
AP Test Money DUE 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Thurs Meiosis Wksht
UNIT 78 TEST March 19th
Inheritance and Regulation
Fig 13-2
Bacteria
Parent
Bud
05 mmAsexual Reproduction
Advantages1 Can be done in isolation2 If you are perfect why change
Best when an organism is ldquoperfectlyrdquo suited for its environment
3 Less ldquomachineryrdquo needed no waste on flowers ldquonewrdquo types of cells or other secondary sexual characteristics
Disadvantages1 Less variety Poor option in a
changing environmentPlants
Fig 13-2
Parent
Bud
05 mmAsexual Reproduction
Advantages1 Can be done in isolation2 If you are perfect why change
Best when an organism is ldquoperfectlyrdquo suited for its environment
3 Less ldquomachineryrdquo needed no waste on flowers ldquonewrdquo types of cells or other secondary sexual characteristics
Disadvantages1 Less variety Poor option in a
changing environment
Fig 13-2
Parent
Bud
05 mmAsexual Reproduction
Advantages1 Can be done in isolation2 If you are perfect why change
Best when an organism is ldquoperfectlyrdquo suited for its environment
3 Less ldquomachineryrdquo needed no waste on flowers ldquonewrdquo types of cells or other secondary sexual characteristics
Disadvantages1 Less variety Poor option in a
changing environment
Aspen
Fig 13-1
Sexual ReproductionAdvantages1 Increased variety Best when
environment is changing
Increased Variety is DUE TObull random fertilizationbull meiosis
bull independent assortmentbull crossing-over
Disadvantages1 Resource investment
bull specialized cells gametesbull secondary sexual
characteristics mate attraction2 Requires a partner (except when
plants self-fertilize)
In eukaryotic organisms heritable information is passed to the next generation via mitosis and
meiosisCell Division 2 Types
Meiosis sex cells (gametes) (spermeggs)bull Purpose
ensures that each gamete receives one complete haploid (1n) set of chromosomes
Ensures chromosome number stays the same each offspring receives frac12 (1n) of the full set for the species (2n)
bull Steps1 DNA Replication2 homologous pairs form a tetrad
(independent assortment) (genetic variation increases)
3 cross over between homologous chromosomes may occur (genetic variation increases)
4 Meiosis I homologous pairs separate5 Meiosis II sister chromatids separate
In eukaryotic organisms heritable information is passed to the next generation via mitosis and
meiosisCell Division 2 Types
Meiosis sex cells (gametes) (spermeggs)bull Purpose
ensures that each gamete receives one complete haploid (1n) set of chromosomes
Ensures chromosome number stays the same each offspring receives frac12 (1n) of the full set for the species (2n)
bull Steps1 DNA Replication2 homologous pairs form a tetrad
(independent assortment) (genetic variation increases)
3 cross over between homologous chromosomes may occur (genetic variation increases)
4 Meiosis I homologous pairs separate5 Meiosis II sister chromatids separate
In eukaryotic organisms heritable information is passed to the next generation via mitosis and
meiosisCell Division 2 Types
Meiosis sex cells (gametes) (spermeggs)bull Purpose
ensures that each gamete receives one complete haploid (1n) set of chromosomes
Ensures chromosome number stays the same each offspring receives frac12 (1n) of the full set for the species (2n)
bull Steps1 DNA Replication2 homologous pairs form a tetrad
(independent assortment) (genetic variation increases)
3 cross over between homologous chromosomes may occur (genetic variation increases)
4 Meiosis I homologous pairs separate5 Meiosis II sister chromatids separate
1 Build your diploid cell (an homologous pair for each chromosome)a Draw a big cell with a nucleus insideb Add homologous pairs of chromosomes
bull 1 big white 1 big yellowbull 1 medium white 1 medium yellowbull 1 small white 1 small yellow
2 Clone each chromosome (DNA Replication) (making sister chromatids)3 Nucleus breaks down (erase it)4 Homologous pairs form a tetrad crossing over may occur (note do not model crossing
over for now)5 Homologous pairs separate one to each side of cell all paternal (or all maternal) do NOT
have to go together (independent assortment)6 Cytokinesis cell membrane grows between the 2 halves7 Clones (sister chromatids) separate (centromere ldquobreaksrdquo as DNA polymerization
completes) one to each side of cell8 Cytokinesis cell membrane grows between the 2 halves9 Nucleus grows around chromosomes 4 cells made (gametes which have half the
number of chromosomes (haploids)
Meiosis Modeling
When yoursquore confident on the process show Mr Jones
Meiosis Modelingbull When yoursquore confident on the process show Mr Jones
bull In your notebookTable 138 Stages of Meiosis p255At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid crossing over recombinant chromosome independent assortment Meiosis I Meiosis II
Meiosis Modeling
Analysis
1 What is the outcome of meiosis2 What steps of meiosis cause variation3 If the first cell has 46 chromosomes (before
cloning) how many does each daughter cell have4 How many unique gametes did you form How
many could have formed5 Why do cells go through meiosis
Warm-UP 1 Why do meiosis2 How does meiosis increase variation in organisms
AP Test Money DUE 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Tomorrow Meiosis Wksht
UNIT 78 TEST March 19th
Inheritance and Regulation
Meiosis has multiple processes that increases genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Meiosis has multiple processes that increase genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Meiosis has multiple processes that increase genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Meiosis has multiple processes that increases genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Warm-UP Watch the video What is happening Why does this happen How does this increase variation
AP Test Money DUE TOMORROW 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Tomorrow
UNIT 78 TEST March 19th
Inheritance and Regulation
Fig 13-9a
MITOSIS MEIOSIS
MEIOSIS I
Prophase I
Chiasma
Chromosomereplication
Homologouschromosomepair
Chromosomereplication
2n = 6
Parent cell
Prophase
Replicated chromosome
Metaphase Metaphase I
Anaphase ITelophase I
Haploid n = 3
Daughter cells ofmeiosis I
MEIOSIS II
Daughter cells of meiosis II
nnnn
2n2n
Daughter cellsof mitosis
AnaphaseTelophase
Compare
Contrast
Independent Assortment
Crossing-over Sexual Fertilization Mutation
Types of Changes to Cells Think About what where when how how much variation created
Warm-UP Now we need to keep track of the genes on the chromosomes that are inherited Notice the letters on the chromosomes They represent different alleles for Huntingtons Barbie has Huntingtons What is the chance her child will get Huntingtons
AP Test Money DUE 36 TOMORROWRemember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Tomorrow 141 5 Key Ideas AND Concept Check 1-3
H=dominant (remember Huntingtonrsquos is dominant)
h=recessive (no Huntingtonrsquos)
Homework DUE Monday Test Corrections for 10 Make-UP
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
AP Test Money DUE 36 TODAYRemember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
DUE next Thursday Monohybrid Crosses
Homework DUE Monday Test Corrections for 10 Make-UP
Warm-UP Now we need to keep track of TWO UNLINKED genes on the chromosomes that are inherited Notice the letters on the chromosomes They represent different alleles for Huntingtons and red hair color Barbie has Huntingtons and is a blond (but a carrier) Ken does not have Huntingtonrsquos and is also a carrier for red hair What is the chance their child will get Huntingtons and red hair
Homework DUE Tomorrow 142 5 Key Ideas AND Concept Check 1-3
H= Huntingtonrsquosh=no HuntingtonrsquosR= no red hairr= red hair
DUE Now Test Corrections for 10 Make-UP
UNIT 78 TEST March 19th
Inheritance and Regulation
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
Homework DUE Tomorrow 143 5 Key Ideas AND Concept Check 1-3
DUE Now 142DUE Thursday Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
UNIT 78 TEST March 19th
Inheritance and Regulation
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoods
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with RrYy
1 Chance of baby with Rr 052 Chance of baby with Yy 053 Chance of baby with RrYy 025
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with both dominant phenotypes
1 Chance of baby with at least one R 0752 Chance of baby with at least one Y 0753 Chance of baby with RrYy 05625 (916)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with both dominant phenotypes
1 Chance of baby with at least one R 10
2 Chance of baby with at least one Y 10
3 Chance of baby with both dominant phenotypes 10
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
Homework DUE Tomorrow Linked vs Unlinked Genes AND Monohybrid Crosses to tunritincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with
vestigial wings and cinnabar eyes Predict the phenotypic ratio of the F2 individuals
Homework DUE Tomorrow 153 5 Key Ideas and Concept Check 1-3DUE Thursday Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with vestigial wings and cinnabar eyes Predict the
phenotypic ratio of the F2 individuals
3 The results of the cross from 2 show the following outcome Individuals of each phenotype are shown in the table Which of the following is the most likely explanation of the results a The two genes are located on two different chromosomes b The two genes are sex-linked c The two genes are located on mitochondrial DNA d The two genes are linked on an autosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
1 Build your diploid cell (an homologous pair for each chromosome)a Draw a big cell with a nucleus insideb DRAW homologous pairs of chromosomes
bull 1 big blue 1 big redbull 1 small blue 1 small red
ndash Add genes to your chromosomebull Write an H and an R on big blue and an h and an r on big redbull Write a T on small blue and a t on small red
2 Clone each chromosome (DNA Replication) (making sister chromatids)3 Nucleus breaks down (erase it)4 Homologous pairs form a tetrad crossing over may occur (note do not model
crossing over for now)5 Finish meiosis (see notes for help)6 Nucleus grows around chromosomes 4 cells made (gametes which have half
the number of chromosomes (haploids)7 Repeat Steps 1-6 this time at Step 4 include ONE crossover event
Recombination Modeling
When yoursquore confident on the process show Mr Jones
bull When yoursquore confident on the process show Mr Jones
bull In your notebookFigure 1510 Recombination p295At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid crossing over recombinant chromosome independent assortment Meiosis I Meiosis II
Recombination Modeling
Analysis
1 How does recombination increase the variety of gametes formed
2 Which types of gametes were more likely Gametes with recombinant chromosomes or ones without
3 Recombination is a random process How might it benefithurt the survival of an individualspecies
Recombination Modeling
Warm-UP
1 How could you calculate recombination frequency2 What would the recombination frequency tell you about the relative position of
genes on a chromosome3 Genes A B and C are on the same chromosome Testcrosses show that the
recombination frequency between A and B is 28 and between A and C is 12 Can you determine the linear order of these genes
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP What can we learn about inheritance from looking at a pedigree (use example of the Royal Family of Europe from the early 1900s)
Warm-UP In the following human pedigree squares represent males circles represent females and shaded symbols indicate individuals affected with a disorder One of the affected males from the third generation has a child with a female who is a carrier For the pedigree shown which of the following best expresses the probability that the couplersquos first son will be affected with the disorder
(A) 25 (B) 50 (C) 75 (D) 100
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Is a widowrsquos peak a dominant or recessive trait
Is a widowrsquos peak a dominant or recessive trait
Fig 14-UN5
George
Sandra Tom Sam
Arlene
Wilma Ann Michael
Carla
Daniel Alan Tina
Christopher
A heterozygous tall and a homozygous purple flowered plant is crossed with a short and white flowered plant Predict the offspring Assume independent assortment
1
P=purplep=whiteT=tallt=short
For a plant with the genotype WwXxYyZz what is the probability that the plant will produce a gamete with a haploid genotype of Wxyz Give your answer as a fraction or as a value between 0 and 1 to four decimal places
2
A completely-plated stickleback from a marine population was mated to a low-plated stickleback from a freshwater population The resulting F1 hybrids all displayed a completely plated phenotype When the F1 hybrids were allowed to interbreed the resulting F2 generation included completely plated offspring and low-plated offspring in an approximate 31 ratio Which of the following conclusions is best supported by the results of the breeding experiments
a Phenotypic variation in the F2 generation suggests that armor morphology is controlled by many alleles of a single gene
b The completely-plated phenotype is controlled by a dominant allele of a single gene
c Armor loss is an acquired characteristic that is affected by one or more environmental factors
d Patterns of armor plating in stickleback populations are regulated by sex-specific signals
3
If a man with type AB blood marries a woman with type O what blood types would you expect in their children What fraction would you expect of each type
4
IA= Type AIB= Type Bi= Type O
If a King marries a Queen that is a carrier of hemophilia (sex-linked recessive disease that is historically fatal before adulthood) what is the chance of the Kingdom having an heir to the kingrsquos throne assuming only one child is born
5
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
7 Gregor Mendelrsquos pioneering genetic experiments with pea plants occurred before the discovery of the structure and function of chromosomes Which of the following observations about inheritance in pea plants could be explained only after the discovery that genes may be linked on a chromosome
a Pea color and pea shape display independent inheritance patterns b Offspring of a given cross show all possible combinations of traits in
equal proportions c Most offspring of a given cross have a combination of traits that is
identical to that of either one parent or the other d Recessive phenotypes can skip a generation showing up only in the
parental and F 2 generations
8
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Based on the data in Table I which of the following best explains why there are no individuals with constricted pods in the F 1 generation a Inflated pod shape is dominant to constricted pod shape b The inflated-pod offspring in the F sub one generation are
homozygous c Constricted pod shape typically arises from a new mutation in the F 1
generation d The constricted-pod offspring are carriers for the inflated pod shape
allele
9
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table I the ratio of phenotypes in the offspring from the testcross with F 1 plants that had purple flowers and inflated pods suggests that the genes for flower color and pod shape are located a close together on the same autosome b on the X chromosome c on different chromosomes d on a mitochondrial chromosome
10
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Which of the following provides the best justification for an assumption that might have been used in the computer simulation (Table II) a The broad allele is recessive to the narrow allele because broad
leaves appear in every generation b The purple allele is dominant to the white allele because all the
offspring from the cross of purple-flowered and white-flowered plants had purple flowers
c The narrow allele is codominant with the purple allele because the purple-flower trait and the narrow-leaf trait segregate together
d The white allele is dominant to both the broad and narrow alleles because plants with either type of leaf shape can have white flowers
11
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table II the F 1 offspring of the cross between broad-leaved white-flowered plants with narrow-leaved purple-flowered plants have a phenotype that differs from that of either parent However many testcross offspring have the same phenotype as one of the two plants in the parental cross but relatively few testcross offspring have the same phenotype as the F 1 offspring Which of the following best explains the observation a Recombination between the leaf-shape and flower-color genes resulted in
chromosomes carrying a dominant allele of both genes b Recombination between the broad and narrow alleles of the leaf-shape gene resulted in
chromosomes carrying three different alleles at the same genetic locus c Independent assortment of homologous chromosomes resulted in the combinations of
alleles present in the parental generation d The computer model cannot capture the possible assortments of gametes when
multiple genes are considered
Chromosome Model
Materialsbull pipe cleanersbull beadsbull cotton ballsbull tape
Partsbull chromosome tightly coiled DNAbull double helix DNA is 2 strands of
nucleotides twisted togetherbull gene small sections of DNA that
encode traitsbull histone proteins that DNA
supercoils around makes the DNA smaller so that it can fit in our cells
bull sister chromatid a duplicated copy of the original DNA still connected to the 1st
bull centromere the place where the 2 sister chromatids are connected
bull mRNA copies of DNA that read genes
Warm-UP Can you ldquounwindrdquo your model like in the picture to show the parts Sketch and label your model (or the picture of the model) Labels histone mRNA DNA sister chromatid centromere
AP Test Money DUE 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework for Tonight Mitosis Worksheet
UNIT 78 TEST March 19th
Inheritance and Regulation
Due Now Stamp Sheet
Warm-UP
1 Is blowing up a balloon a good model for how cells or organisms grow Explain
2 In what ways are cells different than each other the same
AP Test Money DUE 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework for Tonight 122
UNIT 78 TEST March 19th
Inheritance and Regulation
AP Test Money DUE 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework for Tonight
Warm-UP
1 Is blowing up a balloon a good model for how cells or organisms grow Explain
2 In what ways are cells different than each other the same
AP Test Money DUE 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework for Tonight
Warm-UP
1 Is blowing up a balloon a good model for how cells or organisms grow Explain
2 In what ways are cells different than each other the same
AP Test Money DUE 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework for Tonight
Warm-UP
1 Is blowing up a balloon a good model for how cells or organisms grow Explain
2 In what ways are cells different than each other the same
In eukaryotic organisms heritable information is passed to the next generation via mitosis and
meiosis
Cell Division 2 Types Mitosis and Meiosis
Mitosisbull Purpose
growth repair asexual reproduction (actually
binary fission in prokaryotes)bull occurs after DNA replicationbull is followed by cytokinesisbull 2 genetically identical daughter cells
(clones)bull Steps
1 Replication2 Alignment3 Separation
1 Draw a big cell with a nucleus inside2 Add homologous pairs of chromosomes
ndash 1 big yellow 1 big whitendash 1 medium yellow 1 medium whitendash 1 small yellow 1 small white
3 Clone each chromosome (DNA Replication) (making sister chromatids)
4 Nucleus breaks down (erase it)5 Clones separate one to each side of cell6 Cytokinesis cell membrane grows between the 2
halves7 Nucleus grows around chromosomes
Mitosis Modeling
When yoursquore confident on the process show Mr Jones
bull When yoursquore confident on the process show Mr Jones
bull In your notebookTable 127 Stages of Mitosis p232At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid
Mitosis Modeling
Analysis
1 What is the outcome of mitosis2 What steps of mitosis ensure a perfect
outcome3 If the first cell has 46 chromosomes (before
cloning) how many does each daughter cell have
4 Why do cells go through mitosis
Mitosis Modeling
Words to Knowbull Nucleusbull DNAbull Histonesbull Chromatinbull Chromosomebull Chromatidbull Centromere
Copyright copy 2002 Pearson Education Inc publishing as Benjamin Cummings
Interphase ldquoSrdquo phase
Mitosis
Warm-UP
1Advantages of Sex
2Disadvantages of Sex
AP Test Money DUE 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Thurs Meiosis Wksht
UNIT 78 TEST March 19th
Inheritance and Regulation
Fig 13-2
Bacteria
Parent
Bud
05 mmAsexual Reproduction
Advantages1 Can be done in isolation2 If you are perfect why change
Best when an organism is ldquoperfectlyrdquo suited for its environment
3 Less ldquomachineryrdquo needed no waste on flowers ldquonewrdquo types of cells or other secondary sexual characteristics
Disadvantages1 Less variety Poor option in a
changing environmentPlants
Fig 13-2
Parent
Bud
05 mmAsexual Reproduction
Advantages1 Can be done in isolation2 If you are perfect why change
Best when an organism is ldquoperfectlyrdquo suited for its environment
3 Less ldquomachineryrdquo needed no waste on flowers ldquonewrdquo types of cells or other secondary sexual characteristics
Disadvantages1 Less variety Poor option in a
changing environment
Fig 13-2
Parent
Bud
05 mmAsexual Reproduction
Advantages1 Can be done in isolation2 If you are perfect why change
Best when an organism is ldquoperfectlyrdquo suited for its environment
3 Less ldquomachineryrdquo needed no waste on flowers ldquonewrdquo types of cells or other secondary sexual characteristics
Disadvantages1 Less variety Poor option in a
changing environment
Aspen
Fig 13-1
Sexual ReproductionAdvantages1 Increased variety Best when
environment is changing
Increased Variety is DUE TObull random fertilizationbull meiosis
bull independent assortmentbull crossing-over
Disadvantages1 Resource investment
bull specialized cells gametesbull secondary sexual
characteristics mate attraction2 Requires a partner (except when
plants self-fertilize)
In eukaryotic organisms heritable information is passed to the next generation via mitosis and
meiosisCell Division 2 Types
Meiosis sex cells (gametes) (spermeggs)bull Purpose
ensures that each gamete receives one complete haploid (1n) set of chromosomes
Ensures chromosome number stays the same each offspring receives frac12 (1n) of the full set for the species (2n)
bull Steps1 DNA Replication2 homologous pairs form a tetrad
(independent assortment) (genetic variation increases)
3 cross over between homologous chromosomes may occur (genetic variation increases)
4 Meiosis I homologous pairs separate5 Meiosis II sister chromatids separate
In eukaryotic organisms heritable information is passed to the next generation via mitosis and
meiosisCell Division 2 Types
Meiosis sex cells (gametes) (spermeggs)bull Purpose
ensures that each gamete receives one complete haploid (1n) set of chromosomes
Ensures chromosome number stays the same each offspring receives frac12 (1n) of the full set for the species (2n)
bull Steps1 DNA Replication2 homologous pairs form a tetrad
(independent assortment) (genetic variation increases)
3 cross over between homologous chromosomes may occur (genetic variation increases)
4 Meiosis I homologous pairs separate5 Meiosis II sister chromatids separate
In eukaryotic organisms heritable information is passed to the next generation via mitosis and
meiosisCell Division 2 Types
Meiosis sex cells (gametes) (spermeggs)bull Purpose
ensures that each gamete receives one complete haploid (1n) set of chromosomes
Ensures chromosome number stays the same each offspring receives frac12 (1n) of the full set for the species (2n)
bull Steps1 DNA Replication2 homologous pairs form a tetrad
(independent assortment) (genetic variation increases)
3 cross over between homologous chromosomes may occur (genetic variation increases)
4 Meiosis I homologous pairs separate5 Meiosis II sister chromatids separate
1 Build your diploid cell (an homologous pair for each chromosome)a Draw a big cell with a nucleus insideb Add homologous pairs of chromosomes
bull 1 big white 1 big yellowbull 1 medium white 1 medium yellowbull 1 small white 1 small yellow
2 Clone each chromosome (DNA Replication) (making sister chromatids)3 Nucleus breaks down (erase it)4 Homologous pairs form a tetrad crossing over may occur (note do not model crossing
over for now)5 Homologous pairs separate one to each side of cell all paternal (or all maternal) do NOT
have to go together (independent assortment)6 Cytokinesis cell membrane grows between the 2 halves7 Clones (sister chromatids) separate (centromere ldquobreaksrdquo as DNA polymerization
completes) one to each side of cell8 Cytokinesis cell membrane grows between the 2 halves9 Nucleus grows around chromosomes 4 cells made (gametes which have half the
number of chromosomes (haploids)
Meiosis Modeling
When yoursquore confident on the process show Mr Jones
Meiosis Modelingbull When yoursquore confident on the process show Mr Jones
bull In your notebookTable 138 Stages of Meiosis p255At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid crossing over recombinant chromosome independent assortment Meiosis I Meiosis II
Meiosis Modeling
Analysis
1 What is the outcome of meiosis2 What steps of meiosis cause variation3 If the first cell has 46 chromosomes (before
cloning) how many does each daughter cell have4 How many unique gametes did you form How
many could have formed5 Why do cells go through meiosis
Warm-UP 1 Why do meiosis2 How does meiosis increase variation in organisms
AP Test Money DUE 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Tomorrow Meiosis Wksht
UNIT 78 TEST March 19th
Inheritance and Regulation
Meiosis has multiple processes that increases genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Meiosis has multiple processes that increase genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Meiosis has multiple processes that increase genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Meiosis has multiple processes that increases genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Warm-UP Watch the video What is happening Why does this happen How does this increase variation
AP Test Money DUE TOMORROW 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Tomorrow
UNIT 78 TEST March 19th
Inheritance and Regulation
Fig 13-9a
MITOSIS MEIOSIS
MEIOSIS I
Prophase I
Chiasma
Chromosomereplication
Homologouschromosomepair
Chromosomereplication
2n = 6
Parent cell
Prophase
Replicated chromosome
Metaphase Metaphase I
Anaphase ITelophase I
Haploid n = 3
Daughter cells ofmeiosis I
MEIOSIS II
Daughter cells of meiosis II
nnnn
2n2n
Daughter cellsof mitosis
AnaphaseTelophase
Compare
Contrast
Independent Assortment
Crossing-over Sexual Fertilization Mutation
Types of Changes to Cells Think About what where when how how much variation created
Warm-UP Now we need to keep track of the genes on the chromosomes that are inherited Notice the letters on the chromosomes They represent different alleles for Huntingtons Barbie has Huntingtons What is the chance her child will get Huntingtons
AP Test Money DUE 36 TOMORROWRemember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Tomorrow 141 5 Key Ideas AND Concept Check 1-3
H=dominant (remember Huntingtonrsquos is dominant)
h=recessive (no Huntingtonrsquos)
Homework DUE Monday Test Corrections for 10 Make-UP
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
AP Test Money DUE 36 TODAYRemember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
DUE next Thursday Monohybrid Crosses
Homework DUE Monday Test Corrections for 10 Make-UP
Warm-UP Now we need to keep track of TWO UNLINKED genes on the chromosomes that are inherited Notice the letters on the chromosomes They represent different alleles for Huntingtons and red hair color Barbie has Huntingtons and is a blond (but a carrier) Ken does not have Huntingtonrsquos and is also a carrier for red hair What is the chance their child will get Huntingtons and red hair
Homework DUE Tomorrow 142 5 Key Ideas AND Concept Check 1-3
H= Huntingtonrsquosh=no HuntingtonrsquosR= no red hairr= red hair
DUE Now Test Corrections for 10 Make-UP
UNIT 78 TEST March 19th
Inheritance and Regulation
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
Homework DUE Tomorrow 143 5 Key Ideas AND Concept Check 1-3
DUE Now 142DUE Thursday Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
UNIT 78 TEST March 19th
Inheritance and Regulation
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoods
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with RrYy
1 Chance of baby with Rr 052 Chance of baby with Yy 053 Chance of baby with RrYy 025
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with both dominant phenotypes
1 Chance of baby with at least one R 0752 Chance of baby with at least one Y 0753 Chance of baby with RrYy 05625 (916)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with both dominant phenotypes
1 Chance of baby with at least one R 10
2 Chance of baby with at least one Y 10
3 Chance of baby with both dominant phenotypes 10
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
Homework DUE Tomorrow Linked vs Unlinked Genes AND Monohybrid Crosses to tunritincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with
vestigial wings and cinnabar eyes Predict the phenotypic ratio of the F2 individuals
Homework DUE Tomorrow 153 5 Key Ideas and Concept Check 1-3DUE Thursday Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with vestigial wings and cinnabar eyes Predict the
phenotypic ratio of the F2 individuals
3 The results of the cross from 2 show the following outcome Individuals of each phenotype are shown in the table Which of the following is the most likely explanation of the results a The two genes are located on two different chromosomes b The two genes are sex-linked c The two genes are located on mitochondrial DNA d The two genes are linked on an autosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
1 Build your diploid cell (an homologous pair for each chromosome)a Draw a big cell with a nucleus insideb DRAW homologous pairs of chromosomes
bull 1 big blue 1 big redbull 1 small blue 1 small red
ndash Add genes to your chromosomebull Write an H and an R on big blue and an h and an r on big redbull Write a T on small blue and a t on small red
2 Clone each chromosome (DNA Replication) (making sister chromatids)3 Nucleus breaks down (erase it)4 Homologous pairs form a tetrad crossing over may occur (note do not model
crossing over for now)5 Finish meiosis (see notes for help)6 Nucleus grows around chromosomes 4 cells made (gametes which have half
the number of chromosomes (haploids)7 Repeat Steps 1-6 this time at Step 4 include ONE crossover event
Recombination Modeling
When yoursquore confident on the process show Mr Jones
bull When yoursquore confident on the process show Mr Jones
bull In your notebookFigure 1510 Recombination p295At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid crossing over recombinant chromosome independent assortment Meiosis I Meiosis II
Recombination Modeling
Analysis
1 How does recombination increase the variety of gametes formed
2 Which types of gametes were more likely Gametes with recombinant chromosomes or ones without
3 Recombination is a random process How might it benefithurt the survival of an individualspecies
Recombination Modeling
Warm-UP
1 How could you calculate recombination frequency2 What would the recombination frequency tell you about the relative position of
genes on a chromosome3 Genes A B and C are on the same chromosome Testcrosses show that the
recombination frequency between A and B is 28 and between A and C is 12 Can you determine the linear order of these genes
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP What can we learn about inheritance from looking at a pedigree (use example of the Royal Family of Europe from the early 1900s)
Warm-UP In the following human pedigree squares represent males circles represent females and shaded symbols indicate individuals affected with a disorder One of the affected males from the third generation has a child with a female who is a carrier For the pedigree shown which of the following best expresses the probability that the couplersquos first son will be affected with the disorder
(A) 25 (B) 50 (C) 75 (D) 100
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Is a widowrsquos peak a dominant or recessive trait
Is a widowrsquos peak a dominant or recessive trait
Fig 14-UN5
George
Sandra Tom Sam
Arlene
Wilma Ann Michael
Carla
Daniel Alan Tina
Christopher
A heterozygous tall and a homozygous purple flowered plant is crossed with a short and white flowered plant Predict the offspring Assume independent assortment
1
P=purplep=whiteT=tallt=short
For a plant with the genotype WwXxYyZz what is the probability that the plant will produce a gamete with a haploid genotype of Wxyz Give your answer as a fraction or as a value between 0 and 1 to four decimal places
2
A completely-plated stickleback from a marine population was mated to a low-plated stickleback from a freshwater population The resulting F1 hybrids all displayed a completely plated phenotype When the F1 hybrids were allowed to interbreed the resulting F2 generation included completely plated offspring and low-plated offspring in an approximate 31 ratio Which of the following conclusions is best supported by the results of the breeding experiments
a Phenotypic variation in the F2 generation suggests that armor morphology is controlled by many alleles of a single gene
b The completely-plated phenotype is controlled by a dominant allele of a single gene
c Armor loss is an acquired characteristic that is affected by one or more environmental factors
d Patterns of armor plating in stickleback populations are regulated by sex-specific signals
3
If a man with type AB blood marries a woman with type O what blood types would you expect in their children What fraction would you expect of each type
4
IA= Type AIB= Type Bi= Type O
If a King marries a Queen that is a carrier of hemophilia (sex-linked recessive disease that is historically fatal before adulthood) what is the chance of the Kingdom having an heir to the kingrsquos throne assuming only one child is born
5
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
7 Gregor Mendelrsquos pioneering genetic experiments with pea plants occurred before the discovery of the structure and function of chromosomes Which of the following observations about inheritance in pea plants could be explained only after the discovery that genes may be linked on a chromosome
a Pea color and pea shape display independent inheritance patterns b Offspring of a given cross show all possible combinations of traits in
equal proportions c Most offspring of a given cross have a combination of traits that is
identical to that of either one parent or the other d Recessive phenotypes can skip a generation showing up only in the
parental and F 2 generations
8
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Based on the data in Table I which of the following best explains why there are no individuals with constricted pods in the F 1 generation a Inflated pod shape is dominant to constricted pod shape b The inflated-pod offspring in the F sub one generation are
homozygous c Constricted pod shape typically arises from a new mutation in the F 1
generation d The constricted-pod offspring are carriers for the inflated pod shape
allele
9
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table I the ratio of phenotypes in the offspring from the testcross with F 1 plants that had purple flowers and inflated pods suggests that the genes for flower color and pod shape are located a close together on the same autosome b on the X chromosome c on different chromosomes d on a mitochondrial chromosome
10
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Which of the following provides the best justification for an assumption that might have been used in the computer simulation (Table II) a The broad allele is recessive to the narrow allele because broad
leaves appear in every generation b The purple allele is dominant to the white allele because all the
offspring from the cross of purple-flowered and white-flowered plants had purple flowers
c The narrow allele is codominant with the purple allele because the purple-flower trait and the narrow-leaf trait segregate together
d The white allele is dominant to both the broad and narrow alleles because plants with either type of leaf shape can have white flowers
11
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table II the F 1 offspring of the cross between broad-leaved white-flowered plants with narrow-leaved purple-flowered plants have a phenotype that differs from that of either parent However many testcross offspring have the same phenotype as one of the two plants in the parental cross but relatively few testcross offspring have the same phenotype as the F 1 offspring Which of the following best explains the observation a Recombination between the leaf-shape and flower-color genes resulted in
chromosomes carrying a dominant allele of both genes b Recombination between the broad and narrow alleles of the leaf-shape gene resulted in
chromosomes carrying three different alleles at the same genetic locus c Independent assortment of homologous chromosomes resulted in the combinations of
alleles present in the parental generation d The computer model cannot capture the possible assortments of gametes when
multiple genes are considered
Warm-UP Can you ldquounwindrdquo your model like in the picture to show the parts Sketch and label your model (or the picture of the model) Labels histone mRNA DNA sister chromatid centromere
AP Test Money DUE 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework for Tonight Mitosis Worksheet
UNIT 78 TEST March 19th
Inheritance and Regulation
Due Now Stamp Sheet
Warm-UP
1 Is blowing up a balloon a good model for how cells or organisms grow Explain
2 In what ways are cells different than each other the same
AP Test Money DUE 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework for Tonight 122
UNIT 78 TEST March 19th
Inheritance and Regulation
AP Test Money DUE 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework for Tonight
Warm-UP
1 Is blowing up a balloon a good model for how cells or organisms grow Explain
2 In what ways are cells different than each other the same
AP Test Money DUE 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework for Tonight
Warm-UP
1 Is blowing up a balloon a good model for how cells or organisms grow Explain
2 In what ways are cells different than each other the same
AP Test Money DUE 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework for Tonight
Warm-UP
1 Is blowing up a balloon a good model for how cells or organisms grow Explain
2 In what ways are cells different than each other the same
In eukaryotic organisms heritable information is passed to the next generation via mitosis and
meiosis
Cell Division 2 Types Mitosis and Meiosis
Mitosisbull Purpose
growth repair asexual reproduction (actually
binary fission in prokaryotes)bull occurs after DNA replicationbull is followed by cytokinesisbull 2 genetically identical daughter cells
(clones)bull Steps
1 Replication2 Alignment3 Separation
1 Draw a big cell with a nucleus inside2 Add homologous pairs of chromosomes
ndash 1 big yellow 1 big whitendash 1 medium yellow 1 medium whitendash 1 small yellow 1 small white
3 Clone each chromosome (DNA Replication) (making sister chromatids)
4 Nucleus breaks down (erase it)5 Clones separate one to each side of cell6 Cytokinesis cell membrane grows between the 2
halves7 Nucleus grows around chromosomes
Mitosis Modeling
When yoursquore confident on the process show Mr Jones
bull When yoursquore confident on the process show Mr Jones
bull In your notebookTable 127 Stages of Mitosis p232At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid
Mitosis Modeling
Analysis
1 What is the outcome of mitosis2 What steps of mitosis ensure a perfect
outcome3 If the first cell has 46 chromosomes (before
cloning) how many does each daughter cell have
4 Why do cells go through mitosis
Mitosis Modeling
Words to Knowbull Nucleusbull DNAbull Histonesbull Chromatinbull Chromosomebull Chromatidbull Centromere
Copyright copy 2002 Pearson Education Inc publishing as Benjamin Cummings
Interphase ldquoSrdquo phase
Mitosis
Warm-UP
1Advantages of Sex
2Disadvantages of Sex
AP Test Money DUE 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Thurs Meiosis Wksht
UNIT 78 TEST March 19th
Inheritance and Regulation
Fig 13-2
Bacteria
Parent
Bud
05 mmAsexual Reproduction
Advantages1 Can be done in isolation2 If you are perfect why change
Best when an organism is ldquoperfectlyrdquo suited for its environment
3 Less ldquomachineryrdquo needed no waste on flowers ldquonewrdquo types of cells or other secondary sexual characteristics
Disadvantages1 Less variety Poor option in a
changing environmentPlants
Fig 13-2
Parent
Bud
05 mmAsexual Reproduction
Advantages1 Can be done in isolation2 If you are perfect why change
Best when an organism is ldquoperfectlyrdquo suited for its environment
3 Less ldquomachineryrdquo needed no waste on flowers ldquonewrdquo types of cells or other secondary sexual characteristics
Disadvantages1 Less variety Poor option in a
changing environment
Fig 13-2
Parent
Bud
05 mmAsexual Reproduction
Advantages1 Can be done in isolation2 If you are perfect why change
Best when an organism is ldquoperfectlyrdquo suited for its environment
3 Less ldquomachineryrdquo needed no waste on flowers ldquonewrdquo types of cells or other secondary sexual characteristics
Disadvantages1 Less variety Poor option in a
changing environment
Aspen
Fig 13-1
Sexual ReproductionAdvantages1 Increased variety Best when
environment is changing
Increased Variety is DUE TObull random fertilizationbull meiosis
bull independent assortmentbull crossing-over
Disadvantages1 Resource investment
bull specialized cells gametesbull secondary sexual
characteristics mate attraction2 Requires a partner (except when
plants self-fertilize)
In eukaryotic organisms heritable information is passed to the next generation via mitosis and
meiosisCell Division 2 Types
Meiosis sex cells (gametes) (spermeggs)bull Purpose
ensures that each gamete receives one complete haploid (1n) set of chromosomes
Ensures chromosome number stays the same each offspring receives frac12 (1n) of the full set for the species (2n)
bull Steps1 DNA Replication2 homologous pairs form a tetrad
(independent assortment) (genetic variation increases)
3 cross over between homologous chromosomes may occur (genetic variation increases)
4 Meiosis I homologous pairs separate5 Meiosis II sister chromatids separate
In eukaryotic organisms heritable information is passed to the next generation via mitosis and
meiosisCell Division 2 Types
Meiosis sex cells (gametes) (spermeggs)bull Purpose
ensures that each gamete receives one complete haploid (1n) set of chromosomes
Ensures chromosome number stays the same each offspring receives frac12 (1n) of the full set for the species (2n)
bull Steps1 DNA Replication2 homologous pairs form a tetrad
(independent assortment) (genetic variation increases)
3 cross over between homologous chromosomes may occur (genetic variation increases)
4 Meiosis I homologous pairs separate5 Meiosis II sister chromatids separate
In eukaryotic organisms heritable information is passed to the next generation via mitosis and
meiosisCell Division 2 Types
Meiosis sex cells (gametes) (spermeggs)bull Purpose
ensures that each gamete receives one complete haploid (1n) set of chromosomes
Ensures chromosome number stays the same each offspring receives frac12 (1n) of the full set for the species (2n)
bull Steps1 DNA Replication2 homologous pairs form a tetrad
(independent assortment) (genetic variation increases)
3 cross over between homologous chromosomes may occur (genetic variation increases)
4 Meiosis I homologous pairs separate5 Meiosis II sister chromatids separate
1 Build your diploid cell (an homologous pair for each chromosome)a Draw a big cell with a nucleus insideb Add homologous pairs of chromosomes
bull 1 big white 1 big yellowbull 1 medium white 1 medium yellowbull 1 small white 1 small yellow
2 Clone each chromosome (DNA Replication) (making sister chromatids)3 Nucleus breaks down (erase it)4 Homologous pairs form a tetrad crossing over may occur (note do not model crossing
over for now)5 Homologous pairs separate one to each side of cell all paternal (or all maternal) do NOT
have to go together (independent assortment)6 Cytokinesis cell membrane grows between the 2 halves7 Clones (sister chromatids) separate (centromere ldquobreaksrdquo as DNA polymerization
completes) one to each side of cell8 Cytokinesis cell membrane grows between the 2 halves9 Nucleus grows around chromosomes 4 cells made (gametes which have half the
number of chromosomes (haploids)
Meiosis Modeling
When yoursquore confident on the process show Mr Jones
Meiosis Modelingbull When yoursquore confident on the process show Mr Jones
bull In your notebookTable 138 Stages of Meiosis p255At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid crossing over recombinant chromosome independent assortment Meiosis I Meiosis II
Meiosis Modeling
Analysis
1 What is the outcome of meiosis2 What steps of meiosis cause variation3 If the first cell has 46 chromosomes (before
cloning) how many does each daughter cell have4 How many unique gametes did you form How
many could have formed5 Why do cells go through meiosis
Warm-UP 1 Why do meiosis2 How does meiosis increase variation in organisms
AP Test Money DUE 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Tomorrow Meiosis Wksht
UNIT 78 TEST March 19th
Inheritance and Regulation
Meiosis has multiple processes that increases genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Meiosis has multiple processes that increase genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Meiosis has multiple processes that increase genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Meiosis has multiple processes that increases genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Warm-UP Watch the video What is happening Why does this happen How does this increase variation
AP Test Money DUE TOMORROW 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Tomorrow
UNIT 78 TEST March 19th
Inheritance and Regulation
Fig 13-9a
MITOSIS MEIOSIS
MEIOSIS I
Prophase I
Chiasma
Chromosomereplication
Homologouschromosomepair
Chromosomereplication
2n = 6
Parent cell
Prophase
Replicated chromosome
Metaphase Metaphase I
Anaphase ITelophase I
Haploid n = 3
Daughter cells ofmeiosis I
MEIOSIS II
Daughter cells of meiosis II
nnnn
2n2n
Daughter cellsof mitosis
AnaphaseTelophase
Compare
Contrast
Independent Assortment
Crossing-over Sexual Fertilization Mutation
Types of Changes to Cells Think About what where when how how much variation created
Warm-UP Now we need to keep track of the genes on the chromosomes that are inherited Notice the letters on the chromosomes They represent different alleles for Huntingtons Barbie has Huntingtons What is the chance her child will get Huntingtons
AP Test Money DUE 36 TOMORROWRemember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Tomorrow 141 5 Key Ideas AND Concept Check 1-3
H=dominant (remember Huntingtonrsquos is dominant)
h=recessive (no Huntingtonrsquos)
Homework DUE Monday Test Corrections for 10 Make-UP
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
AP Test Money DUE 36 TODAYRemember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
DUE next Thursday Monohybrid Crosses
Homework DUE Monday Test Corrections for 10 Make-UP
Warm-UP Now we need to keep track of TWO UNLINKED genes on the chromosomes that are inherited Notice the letters on the chromosomes They represent different alleles for Huntingtons and red hair color Barbie has Huntingtons and is a blond (but a carrier) Ken does not have Huntingtonrsquos and is also a carrier for red hair What is the chance their child will get Huntingtons and red hair
Homework DUE Tomorrow 142 5 Key Ideas AND Concept Check 1-3
H= Huntingtonrsquosh=no HuntingtonrsquosR= no red hairr= red hair
DUE Now Test Corrections for 10 Make-UP
UNIT 78 TEST March 19th
Inheritance and Regulation
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
Homework DUE Tomorrow 143 5 Key Ideas AND Concept Check 1-3
DUE Now 142DUE Thursday Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
UNIT 78 TEST March 19th
Inheritance and Regulation
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoods
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with RrYy
1 Chance of baby with Rr 052 Chance of baby with Yy 053 Chance of baby with RrYy 025
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with both dominant phenotypes
1 Chance of baby with at least one R 0752 Chance of baby with at least one Y 0753 Chance of baby with RrYy 05625 (916)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with both dominant phenotypes
1 Chance of baby with at least one R 10
2 Chance of baby with at least one Y 10
3 Chance of baby with both dominant phenotypes 10
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
Homework DUE Tomorrow Linked vs Unlinked Genes AND Monohybrid Crosses to tunritincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with
vestigial wings and cinnabar eyes Predict the phenotypic ratio of the F2 individuals
Homework DUE Tomorrow 153 5 Key Ideas and Concept Check 1-3DUE Thursday Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with vestigial wings and cinnabar eyes Predict the
phenotypic ratio of the F2 individuals
3 The results of the cross from 2 show the following outcome Individuals of each phenotype are shown in the table Which of the following is the most likely explanation of the results a The two genes are located on two different chromosomes b The two genes are sex-linked c The two genes are located on mitochondrial DNA d The two genes are linked on an autosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
1 Build your diploid cell (an homologous pair for each chromosome)a Draw a big cell with a nucleus insideb DRAW homologous pairs of chromosomes
bull 1 big blue 1 big redbull 1 small blue 1 small red
ndash Add genes to your chromosomebull Write an H and an R on big blue and an h and an r on big redbull Write a T on small blue and a t on small red
2 Clone each chromosome (DNA Replication) (making sister chromatids)3 Nucleus breaks down (erase it)4 Homologous pairs form a tetrad crossing over may occur (note do not model
crossing over for now)5 Finish meiosis (see notes for help)6 Nucleus grows around chromosomes 4 cells made (gametes which have half
the number of chromosomes (haploids)7 Repeat Steps 1-6 this time at Step 4 include ONE crossover event
Recombination Modeling
When yoursquore confident on the process show Mr Jones
bull When yoursquore confident on the process show Mr Jones
bull In your notebookFigure 1510 Recombination p295At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid crossing over recombinant chromosome independent assortment Meiosis I Meiosis II
Recombination Modeling
Analysis
1 How does recombination increase the variety of gametes formed
2 Which types of gametes were more likely Gametes with recombinant chromosomes or ones without
3 Recombination is a random process How might it benefithurt the survival of an individualspecies
Recombination Modeling
Warm-UP
1 How could you calculate recombination frequency2 What would the recombination frequency tell you about the relative position of
genes on a chromosome3 Genes A B and C are on the same chromosome Testcrosses show that the
recombination frequency between A and B is 28 and between A and C is 12 Can you determine the linear order of these genes
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP What can we learn about inheritance from looking at a pedigree (use example of the Royal Family of Europe from the early 1900s)
Warm-UP In the following human pedigree squares represent males circles represent females and shaded symbols indicate individuals affected with a disorder One of the affected males from the third generation has a child with a female who is a carrier For the pedigree shown which of the following best expresses the probability that the couplersquos first son will be affected with the disorder
(A) 25 (B) 50 (C) 75 (D) 100
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Is a widowrsquos peak a dominant or recessive trait
Is a widowrsquos peak a dominant or recessive trait
Fig 14-UN5
George
Sandra Tom Sam
Arlene
Wilma Ann Michael
Carla
Daniel Alan Tina
Christopher
A heterozygous tall and a homozygous purple flowered plant is crossed with a short and white flowered plant Predict the offspring Assume independent assortment
1
P=purplep=whiteT=tallt=short
For a plant with the genotype WwXxYyZz what is the probability that the plant will produce a gamete with a haploid genotype of Wxyz Give your answer as a fraction or as a value between 0 and 1 to four decimal places
2
A completely-plated stickleback from a marine population was mated to a low-plated stickleback from a freshwater population The resulting F1 hybrids all displayed a completely plated phenotype When the F1 hybrids were allowed to interbreed the resulting F2 generation included completely plated offspring and low-plated offspring in an approximate 31 ratio Which of the following conclusions is best supported by the results of the breeding experiments
a Phenotypic variation in the F2 generation suggests that armor morphology is controlled by many alleles of a single gene
b The completely-plated phenotype is controlled by a dominant allele of a single gene
c Armor loss is an acquired characteristic that is affected by one or more environmental factors
d Patterns of armor plating in stickleback populations are regulated by sex-specific signals
3
If a man with type AB blood marries a woman with type O what blood types would you expect in their children What fraction would you expect of each type
4
IA= Type AIB= Type Bi= Type O
If a King marries a Queen that is a carrier of hemophilia (sex-linked recessive disease that is historically fatal before adulthood) what is the chance of the Kingdom having an heir to the kingrsquos throne assuming only one child is born
5
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
7 Gregor Mendelrsquos pioneering genetic experiments with pea plants occurred before the discovery of the structure and function of chromosomes Which of the following observations about inheritance in pea plants could be explained only after the discovery that genes may be linked on a chromosome
a Pea color and pea shape display independent inheritance patterns b Offspring of a given cross show all possible combinations of traits in
equal proportions c Most offspring of a given cross have a combination of traits that is
identical to that of either one parent or the other d Recessive phenotypes can skip a generation showing up only in the
parental and F 2 generations
8
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Based on the data in Table I which of the following best explains why there are no individuals with constricted pods in the F 1 generation a Inflated pod shape is dominant to constricted pod shape b The inflated-pod offspring in the F sub one generation are
homozygous c Constricted pod shape typically arises from a new mutation in the F 1
generation d The constricted-pod offspring are carriers for the inflated pod shape
allele
9
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table I the ratio of phenotypes in the offspring from the testcross with F 1 plants that had purple flowers and inflated pods suggests that the genes for flower color and pod shape are located a close together on the same autosome b on the X chromosome c on different chromosomes d on a mitochondrial chromosome
10
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Which of the following provides the best justification for an assumption that might have been used in the computer simulation (Table II) a The broad allele is recessive to the narrow allele because broad
leaves appear in every generation b The purple allele is dominant to the white allele because all the
offspring from the cross of purple-flowered and white-flowered plants had purple flowers
c The narrow allele is codominant with the purple allele because the purple-flower trait and the narrow-leaf trait segregate together
d The white allele is dominant to both the broad and narrow alleles because plants with either type of leaf shape can have white flowers
11
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table II the F 1 offspring of the cross between broad-leaved white-flowered plants with narrow-leaved purple-flowered plants have a phenotype that differs from that of either parent However many testcross offspring have the same phenotype as one of the two plants in the parental cross but relatively few testcross offspring have the same phenotype as the F 1 offspring Which of the following best explains the observation a Recombination between the leaf-shape and flower-color genes resulted in
chromosomes carrying a dominant allele of both genes b Recombination between the broad and narrow alleles of the leaf-shape gene resulted in
chromosomes carrying three different alleles at the same genetic locus c Independent assortment of homologous chromosomes resulted in the combinations of
alleles present in the parental generation d The computer model cannot capture the possible assortments of gametes when
multiple genes are considered
Warm-UP
1 Is blowing up a balloon a good model for how cells or organisms grow Explain
2 In what ways are cells different than each other the same
AP Test Money DUE 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework for Tonight 122
UNIT 78 TEST March 19th
Inheritance and Regulation
AP Test Money DUE 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework for Tonight
Warm-UP
1 Is blowing up a balloon a good model for how cells or organisms grow Explain
2 In what ways are cells different than each other the same
AP Test Money DUE 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework for Tonight
Warm-UP
1 Is blowing up a balloon a good model for how cells or organisms grow Explain
2 In what ways are cells different than each other the same
AP Test Money DUE 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework for Tonight
Warm-UP
1 Is blowing up a balloon a good model for how cells or organisms grow Explain
2 In what ways are cells different than each other the same
In eukaryotic organisms heritable information is passed to the next generation via mitosis and
meiosis
Cell Division 2 Types Mitosis and Meiosis
Mitosisbull Purpose
growth repair asexual reproduction (actually
binary fission in prokaryotes)bull occurs after DNA replicationbull is followed by cytokinesisbull 2 genetically identical daughter cells
(clones)bull Steps
1 Replication2 Alignment3 Separation
1 Draw a big cell with a nucleus inside2 Add homologous pairs of chromosomes
ndash 1 big yellow 1 big whitendash 1 medium yellow 1 medium whitendash 1 small yellow 1 small white
3 Clone each chromosome (DNA Replication) (making sister chromatids)
4 Nucleus breaks down (erase it)5 Clones separate one to each side of cell6 Cytokinesis cell membrane grows between the 2
halves7 Nucleus grows around chromosomes
Mitosis Modeling
When yoursquore confident on the process show Mr Jones
bull When yoursquore confident on the process show Mr Jones
bull In your notebookTable 127 Stages of Mitosis p232At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid
Mitosis Modeling
Analysis
1 What is the outcome of mitosis2 What steps of mitosis ensure a perfect
outcome3 If the first cell has 46 chromosomes (before
cloning) how many does each daughter cell have
4 Why do cells go through mitosis
Mitosis Modeling
Words to Knowbull Nucleusbull DNAbull Histonesbull Chromatinbull Chromosomebull Chromatidbull Centromere
Copyright copy 2002 Pearson Education Inc publishing as Benjamin Cummings
Interphase ldquoSrdquo phase
Mitosis
Warm-UP
1Advantages of Sex
2Disadvantages of Sex
AP Test Money DUE 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Thurs Meiosis Wksht
UNIT 78 TEST March 19th
Inheritance and Regulation
Fig 13-2
Bacteria
Parent
Bud
05 mmAsexual Reproduction
Advantages1 Can be done in isolation2 If you are perfect why change
Best when an organism is ldquoperfectlyrdquo suited for its environment
3 Less ldquomachineryrdquo needed no waste on flowers ldquonewrdquo types of cells or other secondary sexual characteristics
Disadvantages1 Less variety Poor option in a
changing environmentPlants
Fig 13-2
Parent
Bud
05 mmAsexual Reproduction
Advantages1 Can be done in isolation2 If you are perfect why change
Best when an organism is ldquoperfectlyrdquo suited for its environment
3 Less ldquomachineryrdquo needed no waste on flowers ldquonewrdquo types of cells or other secondary sexual characteristics
Disadvantages1 Less variety Poor option in a
changing environment
Fig 13-2
Parent
Bud
05 mmAsexual Reproduction
Advantages1 Can be done in isolation2 If you are perfect why change
Best when an organism is ldquoperfectlyrdquo suited for its environment
3 Less ldquomachineryrdquo needed no waste on flowers ldquonewrdquo types of cells or other secondary sexual characteristics
Disadvantages1 Less variety Poor option in a
changing environment
Aspen
Fig 13-1
Sexual ReproductionAdvantages1 Increased variety Best when
environment is changing
Increased Variety is DUE TObull random fertilizationbull meiosis
bull independent assortmentbull crossing-over
Disadvantages1 Resource investment
bull specialized cells gametesbull secondary sexual
characteristics mate attraction2 Requires a partner (except when
plants self-fertilize)
In eukaryotic organisms heritable information is passed to the next generation via mitosis and
meiosisCell Division 2 Types
Meiosis sex cells (gametes) (spermeggs)bull Purpose
ensures that each gamete receives one complete haploid (1n) set of chromosomes
Ensures chromosome number stays the same each offspring receives frac12 (1n) of the full set for the species (2n)
bull Steps1 DNA Replication2 homologous pairs form a tetrad
(independent assortment) (genetic variation increases)
3 cross over between homologous chromosomes may occur (genetic variation increases)
4 Meiosis I homologous pairs separate5 Meiosis II sister chromatids separate
In eukaryotic organisms heritable information is passed to the next generation via mitosis and
meiosisCell Division 2 Types
Meiosis sex cells (gametes) (spermeggs)bull Purpose
ensures that each gamete receives one complete haploid (1n) set of chromosomes
Ensures chromosome number stays the same each offspring receives frac12 (1n) of the full set for the species (2n)
bull Steps1 DNA Replication2 homologous pairs form a tetrad
(independent assortment) (genetic variation increases)
3 cross over between homologous chromosomes may occur (genetic variation increases)
4 Meiosis I homologous pairs separate5 Meiosis II sister chromatids separate
In eukaryotic organisms heritable information is passed to the next generation via mitosis and
meiosisCell Division 2 Types
Meiosis sex cells (gametes) (spermeggs)bull Purpose
ensures that each gamete receives one complete haploid (1n) set of chromosomes
Ensures chromosome number stays the same each offspring receives frac12 (1n) of the full set for the species (2n)
bull Steps1 DNA Replication2 homologous pairs form a tetrad
(independent assortment) (genetic variation increases)
3 cross over between homologous chromosomes may occur (genetic variation increases)
4 Meiosis I homologous pairs separate5 Meiosis II sister chromatids separate
1 Build your diploid cell (an homologous pair for each chromosome)a Draw a big cell with a nucleus insideb Add homologous pairs of chromosomes
bull 1 big white 1 big yellowbull 1 medium white 1 medium yellowbull 1 small white 1 small yellow
2 Clone each chromosome (DNA Replication) (making sister chromatids)3 Nucleus breaks down (erase it)4 Homologous pairs form a tetrad crossing over may occur (note do not model crossing
over for now)5 Homologous pairs separate one to each side of cell all paternal (or all maternal) do NOT
have to go together (independent assortment)6 Cytokinesis cell membrane grows between the 2 halves7 Clones (sister chromatids) separate (centromere ldquobreaksrdquo as DNA polymerization
completes) one to each side of cell8 Cytokinesis cell membrane grows between the 2 halves9 Nucleus grows around chromosomes 4 cells made (gametes which have half the
number of chromosomes (haploids)
Meiosis Modeling
When yoursquore confident on the process show Mr Jones
Meiosis Modelingbull When yoursquore confident on the process show Mr Jones
bull In your notebookTable 138 Stages of Meiosis p255At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid crossing over recombinant chromosome independent assortment Meiosis I Meiosis II
Meiosis Modeling
Analysis
1 What is the outcome of meiosis2 What steps of meiosis cause variation3 If the first cell has 46 chromosomes (before
cloning) how many does each daughter cell have4 How many unique gametes did you form How
many could have formed5 Why do cells go through meiosis
Warm-UP 1 Why do meiosis2 How does meiosis increase variation in organisms
AP Test Money DUE 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Tomorrow Meiosis Wksht
UNIT 78 TEST March 19th
Inheritance and Regulation
Meiosis has multiple processes that increases genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Meiosis has multiple processes that increase genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Meiosis has multiple processes that increase genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Meiosis has multiple processes that increases genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Warm-UP Watch the video What is happening Why does this happen How does this increase variation
AP Test Money DUE TOMORROW 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Tomorrow
UNIT 78 TEST March 19th
Inheritance and Regulation
Fig 13-9a
MITOSIS MEIOSIS
MEIOSIS I
Prophase I
Chiasma
Chromosomereplication
Homologouschromosomepair
Chromosomereplication
2n = 6
Parent cell
Prophase
Replicated chromosome
Metaphase Metaphase I
Anaphase ITelophase I
Haploid n = 3
Daughter cells ofmeiosis I
MEIOSIS II
Daughter cells of meiosis II
nnnn
2n2n
Daughter cellsof mitosis
AnaphaseTelophase
Compare
Contrast
Independent Assortment
Crossing-over Sexual Fertilization Mutation
Types of Changes to Cells Think About what where when how how much variation created
Warm-UP Now we need to keep track of the genes on the chromosomes that are inherited Notice the letters on the chromosomes They represent different alleles for Huntingtons Barbie has Huntingtons What is the chance her child will get Huntingtons
AP Test Money DUE 36 TOMORROWRemember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Tomorrow 141 5 Key Ideas AND Concept Check 1-3
H=dominant (remember Huntingtonrsquos is dominant)
h=recessive (no Huntingtonrsquos)
Homework DUE Monday Test Corrections for 10 Make-UP
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
AP Test Money DUE 36 TODAYRemember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
DUE next Thursday Monohybrid Crosses
Homework DUE Monday Test Corrections for 10 Make-UP
Warm-UP Now we need to keep track of TWO UNLINKED genes on the chromosomes that are inherited Notice the letters on the chromosomes They represent different alleles for Huntingtons and red hair color Barbie has Huntingtons and is a blond (but a carrier) Ken does not have Huntingtonrsquos and is also a carrier for red hair What is the chance their child will get Huntingtons and red hair
Homework DUE Tomorrow 142 5 Key Ideas AND Concept Check 1-3
H= Huntingtonrsquosh=no HuntingtonrsquosR= no red hairr= red hair
DUE Now Test Corrections for 10 Make-UP
UNIT 78 TEST March 19th
Inheritance and Regulation
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
Homework DUE Tomorrow 143 5 Key Ideas AND Concept Check 1-3
DUE Now 142DUE Thursday Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
UNIT 78 TEST March 19th
Inheritance and Regulation
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoods
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with RrYy
1 Chance of baby with Rr 052 Chance of baby with Yy 053 Chance of baby with RrYy 025
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with both dominant phenotypes
1 Chance of baby with at least one R 0752 Chance of baby with at least one Y 0753 Chance of baby with RrYy 05625 (916)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with both dominant phenotypes
1 Chance of baby with at least one R 10
2 Chance of baby with at least one Y 10
3 Chance of baby with both dominant phenotypes 10
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
Homework DUE Tomorrow Linked vs Unlinked Genes AND Monohybrid Crosses to tunritincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with
vestigial wings and cinnabar eyes Predict the phenotypic ratio of the F2 individuals
Homework DUE Tomorrow 153 5 Key Ideas and Concept Check 1-3DUE Thursday Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with vestigial wings and cinnabar eyes Predict the
phenotypic ratio of the F2 individuals
3 The results of the cross from 2 show the following outcome Individuals of each phenotype are shown in the table Which of the following is the most likely explanation of the results a The two genes are located on two different chromosomes b The two genes are sex-linked c The two genes are located on mitochondrial DNA d The two genes are linked on an autosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
1 Build your diploid cell (an homologous pair for each chromosome)a Draw a big cell with a nucleus insideb DRAW homologous pairs of chromosomes
bull 1 big blue 1 big redbull 1 small blue 1 small red
ndash Add genes to your chromosomebull Write an H and an R on big blue and an h and an r on big redbull Write a T on small blue and a t on small red
2 Clone each chromosome (DNA Replication) (making sister chromatids)3 Nucleus breaks down (erase it)4 Homologous pairs form a tetrad crossing over may occur (note do not model
crossing over for now)5 Finish meiosis (see notes for help)6 Nucleus grows around chromosomes 4 cells made (gametes which have half
the number of chromosomes (haploids)7 Repeat Steps 1-6 this time at Step 4 include ONE crossover event
Recombination Modeling
When yoursquore confident on the process show Mr Jones
bull When yoursquore confident on the process show Mr Jones
bull In your notebookFigure 1510 Recombination p295At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid crossing over recombinant chromosome independent assortment Meiosis I Meiosis II
Recombination Modeling
Analysis
1 How does recombination increase the variety of gametes formed
2 Which types of gametes were more likely Gametes with recombinant chromosomes or ones without
3 Recombination is a random process How might it benefithurt the survival of an individualspecies
Recombination Modeling
Warm-UP
1 How could you calculate recombination frequency2 What would the recombination frequency tell you about the relative position of
genes on a chromosome3 Genes A B and C are on the same chromosome Testcrosses show that the
recombination frequency between A and B is 28 and between A and C is 12 Can you determine the linear order of these genes
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP What can we learn about inheritance from looking at a pedigree (use example of the Royal Family of Europe from the early 1900s)
Warm-UP In the following human pedigree squares represent males circles represent females and shaded symbols indicate individuals affected with a disorder One of the affected males from the third generation has a child with a female who is a carrier For the pedigree shown which of the following best expresses the probability that the couplersquos first son will be affected with the disorder
(A) 25 (B) 50 (C) 75 (D) 100
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Is a widowrsquos peak a dominant or recessive trait
Is a widowrsquos peak a dominant or recessive trait
Fig 14-UN5
George
Sandra Tom Sam
Arlene
Wilma Ann Michael
Carla
Daniel Alan Tina
Christopher
A heterozygous tall and a homozygous purple flowered plant is crossed with a short and white flowered plant Predict the offspring Assume independent assortment
1
P=purplep=whiteT=tallt=short
For a plant with the genotype WwXxYyZz what is the probability that the plant will produce a gamete with a haploid genotype of Wxyz Give your answer as a fraction or as a value between 0 and 1 to four decimal places
2
A completely-plated stickleback from a marine population was mated to a low-plated stickleback from a freshwater population The resulting F1 hybrids all displayed a completely plated phenotype When the F1 hybrids were allowed to interbreed the resulting F2 generation included completely plated offspring and low-plated offspring in an approximate 31 ratio Which of the following conclusions is best supported by the results of the breeding experiments
a Phenotypic variation in the F2 generation suggests that armor morphology is controlled by many alleles of a single gene
b The completely-plated phenotype is controlled by a dominant allele of a single gene
c Armor loss is an acquired characteristic that is affected by one or more environmental factors
d Patterns of armor plating in stickleback populations are regulated by sex-specific signals
3
If a man with type AB blood marries a woman with type O what blood types would you expect in their children What fraction would you expect of each type
4
IA= Type AIB= Type Bi= Type O
If a King marries a Queen that is a carrier of hemophilia (sex-linked recessive disease that is historically fatal before adulthood) what is the chance of the Kingdom having an heir to the kingrsquos throne assuming only one child is born
5
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
7 Gregor Mendelrsquos pioneering genetic experiments with pea plants occurred before the discovery of the structure and function of chromosomes Which of the following observations about inheritance in pea plants could be explained only after the discovery that genes may be linked on a chromosome
a Pea color and pea shape display independent inheritance patterns b Offspring of a given cross show all possible combinations of traits in
equal proportions c Most offspring of a given cross have a combination of traits that is
identical to that of either one parent or the other d Recessive phenotypes can skip a generation showing up only in the
parental and F 2 generations
8
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Based on the data in Table I which of the following best explains why there are no individuals with constricted pods in the F 1 generation a Inflated pod shape is dominant to constricted pod shape b The inflated-pod offspring in the F sub one generation are
homozygous c Constricted pod shape typically arises from a new mutation in the F 1
generation d The constricted-pod offspring are carriers for the inflated pod shape
allele
9
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table I the ratio of phenotypes in the offspring from the testcross with F 1 plants that had purple flowers and inflated pods suggests that the genes for flower color and pod shape are located a close together on the same autosome b on the X chromosome c on different chromosomes d on a mitochondrial chromosome
10
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Which of the following provides the best justification for an assumption that might have been used in the computer simulation (Table II) a The broad allele is recessive to the narrow allele because broad
leaves appear in every generation b The purple allele is dominant to the white allele because all the
offspring from the cross of purple-flowered and white-flowered plants had purple flowers
c The narrow allele is codominant with the purple allele because the purple-flower trait and the narrow-leaf trait segregate together
d The white allele is dominant to both the broad and narrow alleles because plants with either type of leaf shape can have white flowers
11
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table II the F 1 offspring of the cross between broad-leaved white-flowered plants with narrow-leaved purple-flowered plants have a phenotype that differs from that of either parent However many testcross offspring have the same phenotype as one of the two plants in the parental cross but relatively few testcross offspring have the same phenotype as the F 1 offspring Which of the following best explains the observation a Recombination between the leaf-shape and flower-color genes resulted in
chromosomes carrying a dominant allele of both genes b Recombination between the broad and narrow alleles of the leaf-shape gene resulted in
chromosomes carrying three different alleles at the same genetic locus c Independent assortment of homologous chromosomes resulted in the combinations of
alleles present in the parental generation d The computer model cannot capture the possible assortments of gametes when
multiple genes are considered
AP Test Money DUE 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework for Tonight
Warm-UP
1 Is blowing up a balloon a good model for how cells or organisms grow Explain
2 In what ways are cells different than each other the same
AP Test Money DUE 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework for Tonight
Warm-UP
1 Is blowing up a balloon a good model for how cells or organisms grow Explain
2 In what ways are cells different than each other the same
AP Test Money DUE 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework for Tonight
Warm-UP
1 Is blowing up a balloon a good model for how cells or organisms grow Explain
2 In what ways are cells different than each other the same
In eukaryotic organisms heritable information is passed to the next generation via mitosis and
meiosis
Cell Division 2 Types Mitosis and Meiosis
Mitosisbull Purpose
growth repair asexual reproduction (actually
binary fission in prokaryotes)bull occurs after DNA replicationbull is followed by cytokinesisbull 2 genetically identical daughter cells
(clones)bull Steps
1 Replication2 Alignment3 Separation
1 Draw a big cell with a nucleus inside2 Add homologous pairs of chromosomes
ndash 1 big yellow 1 big whitendash 1 medium yellow 1 medium whitendash 1 small yellow 1 small white
3 Clone each chromosome (DNA Replication) (making sister chromatids)
4 Nucleus breaks down (erase it)5 Clones separate one to each side of cell6 Cytokinesis cell membrane grows between the 2
halves7 Nucleus grows around chromosomes
Mitosis Modeling
When yoursquore confident on the process show Mr Jones
bull When yoursquore confident on the process show Mr Jones
bull In your notebookTable 127 Stages of Mitosis p232At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid
Mitosis Modeling
Analysis
1 What is the outcome of mitosis2 What steps of mitosis ensure a perfect
outcome3 If the first cell has 46 chromosomes (before
cloning) how many does each daughter cell have
4 Why do cells go through mitosis
Mitosis Modeling
Words to Knowbull Nucleusbull DNAbull Histonesbull Chromatinbull Chromosomebull Chromatidbull Centromere
Copyright copy 2002 Pearson Education Inc publishing as Benjamin Cummings
Interphase ldquoSrdquo phase
Mitosis
Warm-UP
1Advantages of Sex
2Disadvantages of Sex
AP Test Money DUE 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Thurs Meiosis Wksht
UNIT 78 TEST March 19th
Inheritance and Regulation
Fig 13-2
Bacteria
Parent
Bud
05 mmAsexual Reproduction
Advantages1 Can be done in isolation2 If you are perfect why change
Best when an organism is ldquoperfectlyrdquo suited for its environment
3 Less ldquomachineryrdquo needed no waste on flowers ldquonewrdquo types of cells or other secondary sexual characteristics
Disadvantages1 Less variety Poor option in a
changing environmentPlants
Fig 13-2
Parent
Bud
05 mmAsexual Reproduction
Advantages1 Can be done in isolation2 If you are perfect why change
Best when an organism is ldquoperfectlyrdquo suited for its environment
3 Less ldquomachineryrdquo needed no waste on flowers ldquonewrdquo types of cells or other secondary sexual characteristics
Disadvantages1 Less variety Poor option in a
changing environment
Fig 13-2
Parent
Bud
05 mmAsexual Reproduction
Advantages1 Can be done in isolation2 If you are perfect why change
Best when an organism is ldquoperfectlyrdquo suited for its environment
3 Less ldquomachineryrdquo needed no waste on flowers ldquonewrdquo types of cells or other secondary sexual characteristics
Disadvantages1 Less variety Poor option in a
changing environment
Aspen
Fig 13-1
Sexual ReproductionAdvantages1 Increased variety Best when
environment is changing
Increased Variety is DUE TObull random fertilizationbull meiosis
bull independent assortmentbull crossing-over
Disadvantages1 Resource investment
bull specialized cells gametesbull secondary sexual
characteristics mate attraction2 Requires a partner (except when
plants self-fertilize)
In eukaryotic organisms heritable information is passed to the next generation via mitosis and
meiosisCell Division 2 Types
Meiosis sex cells (gametes) (spermeggs)bull Purpose
ensures that each gamete receives one complete haploid (1n) set of chromosomes
Ensures chromosome number stays the same each offspring receives frac12 (1n) of the full set for the species (2n)
bull Steps1 DNA Replication2 homologous pairs form a tetrad
(independent assortment) (genetic variation increases)
3 cross over between homologous chromosomes may occur (genetic variation increases)
4 Meiosis I homologous pairs separate5 Meiosis II sister chromatids separate
In eukaryotic organisms heritable information is passed to the next generation via mitosis and
meiosisCell Division 2 Types
Meiosis sex cells (gametes) (spermeggs)bull Purpose
ensures that each gamete receives one complete haploid (1n) set of chromosomes
Ensures chromosome number stays the same each offspring receives frac12 (1n) of the full set for the species (2n)
bull Steps1 DNA Replication2 homologous pairs form a tetrad
(independent assortment) (genetic variation increases)
3 cross over between homologous chromosomes may occur (genetic variation increases)
4 Meiosis I homologous pairs separate5 Meiosis II sister chromatids separate
In eukaryotic organisms heritable information is passed to the next generation via mitosis and
meiosisCell Division 2 Types
Meiosis sex cells (gametes) (spermeggs)bull Purpose
ensures that each gamete receives one complete haploid (1n) set of chromosomes
Ensures chromosome number stays the same each offspring receives frac12 (1n) of the full set for the species (2n)
bull Steps1 DNA Replication2 homologous pairs form a tetrad
(independent assortment) (genetic variation increases)
3 cross over between homologous chromosomes may occur (genetic variation increases)
4 Meiosis I homologous pairs separate5 Meiosis II sister chromatids separate
1 Build your diploid cell (an homologous pair for each chromosome)a Draw a big cell with a nucleus insideb Add homologous pairs of chromosomes
bull 1 big white 1 big yellowbull 1 medium white 1 medium yellowbull 1 small white 1 small yellow
2 Clone each chromosome (DNA Replication) (making sister chromatids)3 Nucleus breaks down (erase it)4 Homologous pairs form a tetrad crossing over may occur (note do not model crossing
over for now)5 Homologous pairs separate one to each side of cell all paternal (or all maternal) do NOT
have to go together (independent assortment)6 Cytokinesis cell membrane grows between the 2 halves7 Clones (sister chromatids) separate (centromere ldquobreaksrdquo as DNA polymerization
completes) one to each side of cell8 Cytokinesis cell membrane grows between the 2 halves9 Nucleus grows around chromosomes 4 cells made (gametes which have half the
number of chromosomes (haploids)
Meiosis Modeling
When yoursquore confident on the process show Mr Jones
Meiosis Modelingbull When yoursquore confident on the process show Mr Jones
bull In your notebookTable 138 Stages of Meiosis p255At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid crossing over recombinant chromosome independent assortment Meiosis I Meiosis II
Meiosis Modeling
Analysis
1 What is the outcome of meiosis2 What steps of meiosis cause variation3 If the first cell has 46 chromosomes (before
cloning) how many does each daughter cell have4 How many unique gametes did you form How
many could have formed5 Why do cells go through meiosis
Warm-UP 1 Why do meiosis2 How does meiosis increase variation in organisms
AP Test Money DUE 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Tomorrow Meiosis Wksht
UNIT 78 TEST March 19th
Inheritance and Regulation
Meiosis has multiple processes that increases genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Meiosis has multiple processes that increase genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Meiosis has multiple processes that increase genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Meiosis has multiple processes that increases genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Warm-UP Watch the video What is happening Why does this happen How does this increase variation
AP Test Money DUE TOMORROW 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Tomorrow
UNIT 78 TEST March 19th
Inheritance and Regulation
Fig 13-9a
MITOSIS MEIOSIS
MEIOSIS I
Prophase I
Chiasma
Chromosomereplication
Homologouschromosomepair
Chromosomereplication
2n = 6
Parent cell
Prophase
Replicated chromosome
Metaphase Metaphase I
Anaphase ITelophase I
Haploid n = 3
Daughter cells ofmeiosis I
MEIOSIS II
Daughter cells of meiosis II
nnnn
2n2n
Daughter cellsof mitosis
AnaphaseTelophase
Compare
Contrast
Independent Assortment
Crossing-over Sexual Fertilization Mutation
Types of Changes to Cells Think About what where when how how much variation created
Warm-UP Now we need to keep track of the genes on the chromosomes that are inherited Notice the letters on the chromosomes They represent different alleles for Huntingtons Barbie has Huntingtons What is the chance her child will get Huntingtons
AP Test Money DUE 36 TOMORROWRemember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Tomorrow 141 5 Key Ideas AND Concept Check 1-3
H=dominant (remember Huntingtonrsquos is dominant)
h=recessive (no Huntingtonrsquos)
Homework DUE Monday Test Corrections for 10 Make-UP
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
AP Test Money DUE 36 TODAYRemember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
DUE next Thursday Monohybrid Crosses
Homework DUE Monday Test Corrections for 10 Make-UP
Warm-UP Now we need to keep track of TWO UNLINKED genes on the chromosomes that are inherited Notice the letters on the chromosomes They represent different alleles for Huntingtons and red hair color Barbie has Huntingtons and is a blond (but a carrier) Ken does not have Huntingtonrsquos and is also a carrier for red hair What is the chance their child will get Huntingtons and red hair
Homework DUE Tomorrow 142 5 Key Ideas AND Concept Check 1-3
H= Huntingtonrsquosh=no HuntingtonrsquosR= no red hairr= red hair
DUE Now Test Corrections for 10 Make-UP
UNIT 78 TEST March 19th
Inheritance and Regulation
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
Homework DUE Tomorrow 143 5 Key Ideas AND Concept Check 1-3
DUE Now 142DUE Thursday Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
UNIT 78 TEST March 19th
Inheritance and Regulation
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoods
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with RrYy
1 Chance of baby with Rr 052 Chance of baby with Yy 053 Chance of baby with RrYy 025
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with both dominant phenotypes
1 Chance of baby with at least one R 0752 Chance of baby with at least one Y 0753 Chance of baby with RrYy 05625 (916)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with both dominant phenotypes
1 Chance of baby with at least one R 10
2 Chance of baby with at least one Y 10
3 Chance of baby with both dominant phenotypes 10
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
Homework DUE Tomorrow Linked vs Unlinked Genes AND Monohybrid Crosses to tunritincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with
vestigial wings and cinnabar eyes Predict the phenotypic ratio of the F2 individuals
Homework DUE Tomorrow 153 5 Key Ideas and Concept Check 1-3DUE Thursday Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with vestigial wings and cinnabar eyes Predict the
phenotypic ratio of the F2 individuals
3 The results of the cross from 2 show the following outcome Individuals of each phenotype are shown in the table Which of the following is the most likely explanation of the results a The two genes are located on two different chromosomes b The two genes are sex-linked c The two genes are located on mitochondrial DNA d The two genes are linked on an autosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
1 Build your diploid cell (an homologous pair for each chromosome)a Draw a big cell with a nucleus insideb DRAW homologous pairs of chromosomes
bull 1 big blue 1 big redbull 1 small blue 1 small red
ndash Add genes to your chromosomebull Write an H and an R on big blue and an h and an r on big redbull Write a T on small blue and a t on small red
2 Clone each chromosome (DNA Replication) (making sister chromatids)3 Nucleus breaks down (erase it)4 Homologous pairs form a tetrad crossing over may occur (note do not model
crossing over for now)5 Finish meiosis (see notes for help)6 Nucleus grows around chromosomes 4 cells made (gametes which have half
the number of chromosomes (haploids)7 Repeat Steps 1-6 this time at Step 4 include ONE crossover event
Recombination Modeling
When yoursquore confident on the process show Mr Jones
bull When yoursquore confident on the process show Mr Jones
bull In your notebookFigure 1510 Recombination p295At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid crossing over recombinant chromosome independent assortment Meiosis I Meiosis II
Recombination Modeling
Analysis
1 How does recombination increase the variety of gametes formed
2 Which types of gametes were more likely Gametes with recombinant chromosomes or ones without
3 Recombination is a random process How might it benefithurt the survival of an individualspecies
Recombination Modeling
Warm-UP
1 How could you calculate recombination frequency2 What would the recombination frequency tell you about the relative position of
genes on a chromosome3 Genes A B and C are on the same chromosome Testcrosses show that the
recombination frequency between A and B is 28 and between A and C is 12 Can you determine the linear order of these genes
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP What can we learn about inheritance from looking at a pedigree (use example of the Royal Family of Europe from the early 1900s)
Warm-UP In the following human pedigree squares represent males circles represent females and shaded symbols indicate individuals affected with a disorder One of the affected males from the third generation has a child with a female who is a carrier For the pedigree shown which of the following best expresses the probability that the couplersquos first son will be affected with the disorder
(A) 25 (B) 50 (C) 75 (D) 100
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Is a widowrsquos peak a dominant or recessive trait
Is a widowrsquos peak a dominant or recessive trait
Fig 14-UN5
George
Sandra Tom Sam
Arlene
Wilma Ann Michael
Carla
Daniel Alan Tina
Christopher
A heterozygous tall and a homozygous purple flowered plant is crossed with a short and white flowered plant Predict the offspring Assume independent assortment
1
P=purplep=whiteT=tallt=short
For a plant with the genotype WwXxYyZz what is the probability that the plant will produce a gamete with a haploid genotype of Wxyz Give your answer as a fraction or as a value between 0 and 1 to four decimal places
2
A completely-plated stickleback from a marine population was mated to a low-plated stickleback from a freshwater population The resulting F1 hybrids all displayed a completely plated phenotype When the F1 hybrids were allowed to interbreed the resulting F2 generation included completely plated offspring and low-plated offspring in an approximate 31 ratio Which of the following conclusions is best supported by the results of the breeding experiments
a Phenotypic variation in the F2 generation suggests that armor morphology is controlled by many alleles of a single gene
b The completely-plated phenotype is controlled by a dominant allele of a single gene
c Armor loss is an acquired characteristic that is affected by one or more environmental factors
d Patterns of armor plating in stickleback populations are regulated by sex-specific signals
3
If a man with type AB blood marries a woman with type O what blood types would you expect in their children What fraction would you expect of each type
4
IA= Type AIB= Type Bi= Type O
If a King marries a Queen that is a carrier of hemophilia (sex-linked recessive disease that is historically fatal before adulthood) what is the chance of the Kingdom having an heir to the kingrsquos throne assuming only one child is born
5
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
7 Gregor Mendelrsquos pioneering genetic experiments with pea plants occurred before the discovery of the structure and function of chromosomes Which of the following observations about inheritance in pea plants could be explained only after the discovery that genes may be linked on a chromosome
a Pea color and pea shape display independent inheritance patterns b Offspring of a given cross show all possible combinations of traits in
equal proportions c Most offspring of a given cross have a combination of traits that is
identical to that of either one parent or the other d Recessive phenotypes can skip a generation showing up only in the
parental and F 2 generations
8
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Based on the data in Table I which of the following best explains why there are no individuals with constricted pods in the F 1 generation a Inflated pod shape is dominant to constricted pod shape b The inflated-pod offspring in the F sub one generation are
homozygous c Constricted pod shape typically arises from a new mutation in the F 1
generation d The constricted-pod offspring are carriers for the inflated pod shape
allele
9
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table I the ratio of phenotypes in the offspring from the testcross with F 1 plants that had purple flowers and inflated pods suggests that the genes for flower color and pod shape are located a close together on the same autosome b on the X chromosome c on different chromosomes d on a mitochondrial chromosome
10
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Which of the following provides the best justification for an assumption that might have been used in the computer simulation (Table II) a The broad allele is recessive to the narrow allele because broad
leaves appear in every generation b The purple allele is dominant to the white allele because all the
offspring from the cross of purple-flowered and white-flowered plants had purple flowers
c The narrow allele is codominant with the purple allele because the purple-flower trait and the narrow-leaf trait segregate together
d The white allele is dominant to both the broad and narrow alleles because plants with either type of leaf shape can have white flowers
11
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table II the F 1 offspring of the cross between broad-leaved white-flowered plants with narrow-leaved purple-flowered plants have a phenotype that differs from that of either parent However many testcross offspring have the same phenotype as one of the two plants in the parental cross but relatively few testcross offspring have the same phenotype as the F 1 offspring Which of the following best explains the observation a Recombination between the leaf-shape and flower-color genes resulted in
chromosomes carrying a dominant allele of both genes b Recombination between the broad and narrow alleles of the leaf-shape gene resulted in
chromosomes carrying three different alleles at the same genetic locus c Independent assortment of homologous chromosomes resulted in the combinations of
alleles present in the parental generation d The computer model cannot capture the possible assortments of gametes when
multiple genes are considered
AP Test Money DUE 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework for Tonight
Warm-UP
1 Is blowing up a balloon a good model for how cells or organisms grow Explain
2 In what ways are cells different than each other the same
AP Test Money DUE 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework for Tonight
Warm-UP
1 Is blowing up a balloon a good model for how cells or organisms grow Explain
2 In what ways are cells different than each other the same
In eukaryotic organisms heritable information is passed to the next generation via mitosis and
meiosis
Cell Division 2 Types Mitosis and Meiosis
Mitosisbull Purpose
growth repair asexual reproduction (actually
binary fission in prokaryotes)bull occurs after DNA replicationbull is followed by cytokinesisbull 2 genetically identical daughter cells
(clones)bull Steps
1 Replication2 Alignment3 Separation
1 Draw a big cell with a nucleus inside2 Add homologous pairs of chromosomes
ndash 1 big yellow 1 big whitendash 1 medium yellow 1 medium whitendash 1 small yellow 1 small white
3 Clone each chromosome (DNA Replication) (making sister chromatids)
4 Nucleus breaks down (erase it)5 Clones separate one to each side of cell6 Cytokinesis cell membrane grows between the 2
halves7 Nucleus grows around chromosomes
Mitosis Modeling
When yoursquore confident on the process show Mr Jones
bull When yoursquore confident on the process show Mr Jones
bull In your notebookTable 127 Stages of Mitosis p232At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid
Mitosis Modeling
Analysis
1 What is the outcome of mitosis2 What steps of mitosis ensure a perfect
outcome3 If the first cell has 46 chromosomes (before
cloning) how many does each daughter cell have
4 Why do cells go through mitosis
Mitosis Modeling
Words to Knowbull Nucleusbull DNAbull Histonesbull Chromatinbull Chromosomebull Chromatidbull Centromere
Copyright copy 2002 Pearson Education Inc publishing as Benjamin Cummings
Interphase ldquoSrdquo phase
Mitosis
Warm-UP
1Advantages of Sex
2Disadvantages of Sex
AP Test Money DUE 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Thurs Meiosis Wksht
UNIT 78 TEST March 19th
Inheritance and Regulation
Fig 13-2
Bacteria
Parent
Bud
05 mmAsexual Reproduction
Advantages1 Can be done in isolation2 If you are perfect why change
Best when an organism is ldquoperfectlyrdquo suited for its environment
3 Less ldquomachineryrdquo needed no waste on flowers ldquonewrdquo types of cells or other secondary sexual characteristics
Disadvantages1 Less variety Poor option in a
changing environmentPlants
Fig 13-2
Parent
Bud
05 mmAsexual Reproduction
Advantages1 Can be done in isolation2 If you are perfect why change
Best when an organism is ldquoperfectlyrdquo suited for its environment
3 Less ldquomachineryrdquo needed no waste on flowers ldquonewrdquo types of cells or other secondary sexual characteristics
Disadvantages1 Less variety Poor option in a
changing environment
Fig 13-2
Parent
Bud
05 mmAsexual Reproduction
Advantages1 Can be done in isolation2 If you are perfect why change
Best when an organism is ldquoperfectlyrdquo suited for its environment
3 Less ldquomachineryrdquo needed no waste on flowers ldquonewrdquo types of cells or other secondary sexual characteristics
Disadvantages1 Less variety Poor option in a
changing environment
Aspen
Fig 13-1
Sexual ReproductionAdvantages1 Increased variety Best when
environment is changing
Increased Variety is DUE TObull random fertilizationbull meiosis
bull independent assortmentbull crossing-over
Disadvantages1 Resource investment
bull specialized cells gametesbull secondary sexual
characteristics mate attraction2 Requires a partner (except when
plants self-fertilize)
In eukaryotic organisms heritable information is passed to the next generation via mitosis and
meiosisCell Division 2 Types
Meiosis sex cells (gametes) (spermeggs)bull Purpose
ensures that each gamete receives one complete haploid (1n) set of chromosomes
Ensures chromosome number stays the same each offspring receives frac12 (1n) of the full set for the species (2n)
bull Steps1 DNA Replication2 homologous pairs form a tetrad
(independent assortment) (genetic variation increases)
3 cross over between homologous chromosomes may occur (genetic variation increases)
4 Meiosis I homologous pairs separate5 Meiosis II sister chromatids separate
In eukaryotic organisms heritable information is passed to the next generation via mitosis and
meiosisCell Division 2 Types
Meiosis sex cells (gametes) (spermeggs)bull Purpose
ensures that each gamete receives one complete haploid (1n) set of chromosomes
Ensures chromosome number stays the same each offspring receives frac12 (1n) of the full set for the species (2n)
bull Steps1 DNA Replication2 homologous pairs form a tetrad
(independent assortment) (genetic variation increases)
3 cross over between homologous chromosomes may occur (genetic variation increases)
4 Meiosis I homologous pairs separate5 Meiosis II sister chromatids separate
In eukaryotic organisms heritable information is passed to the next generation via mitosis and
meiosisCell Division 2 Types
Meiosis sex cells (gametes) (spermeggs)bull Purpose
ensures that each gamete receives one complete haploid (1n) set of chromosomes
Ensures chromosome number stays the same each offspring receives frac12 (1n) of the full set for the species (2n)
bull Steps1 DNA Replication2 homologous pairs form a tetrad
(independent assortment) (genetic variation increases)
3 cross over between homologous chromosomes may occur (genetic variation increases)
4 Meiosis I homologous pairs separate5 Meiosis II sister chromatids separate
1 Build your diploid cell (an homologous pair for each chromosome)a Draw a big cell with a nucleus insideb Add homologous pairs of chromosomes
bull 1 big white 1 big yellowbull 1 medium white 1 medium yellowbull 1 small white 1 small yellow
2 Clone each chromosome (DNA Replication) (making sister chromatids)3 Nucleus breaks down (erase it)4 Homologous pairs form a tetrad crossing over may occur (note do not model crossing
over for now)5 Homologous pairs separate one to each side of cell all paternal (or all maternal) do NOT
have to go together (independent assortment)6 Cytokinesis cell membrane grows between the 2 halves7 Clones (sister chromatids) separate (centromere ldquobreaksrdquo as DNA polymerization
completes) one to each side of cell8 Cytokinesis cell membrane grows between the 2 halves9 Nucleus grows around chromosomes 4 cells made (gametes which have half the
number of chromosomes (haploids)
Meiosis Modeling
When yoursquore confident on the process show Mr Jones
Meiosis Modelingbull When yoursquore confident on the process show Mr Jones
bull In your notebookTable 138 Stages of Meiosis p255At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid crossing over recombinant chromosome independent assortment Meiosis I Meiosis II
Meiosis Modeling
Analysis
1 What is the outcome of meiosis2 What steps of meiosis cause variation3 If the first cell has 46 chromosomes (before
cloning) how many does each daughter cell have4 How many unique gametes did you form How
many could have formed5 Why do cells go through meiosis
Warm-UP 1 Why do meiosis2 How does meiosis increase variation in organisms
AP Test Money DUE 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Tomorrow Meiosis Wksht
UNIT 78 TEST March 19th
Inheritance and Regulation
Meiosis has multiple processes that increases genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Meiosis has multiple processes that increase genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Meiosis has multiple processes that increase genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Meiosis has multiple processes that increases genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Warm-UP Watch the video What is happening Why does this happen How does this increase variation
AP Test Money DUE TOMORROW 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Tomorrow
UNIT 78 TEST March 19th
Inheritance and Regulation
Fig 13-9a
MITOSIS MEIOSIS
MEIOSIS I
Prophase I
Chiasma
Chromosomereplication
Homologouschromosomepair
Chromosomereplication
2n = 6
Parent cell
Prophase
Replicated chromosome
Metaphase Metaphase I
Anaphase ITelophase I
Haploid n = 3
Daughter cells ofmeiosis I
MEIOSIS II
Daughter cells of meiosis II
nnnn
2n2n
Daughter cellsof mitosis
AnaphaseTelophase
Compare
Contrast
Independent Assortment
Crossing-over Sexual Fertilization Mutation
Types of Changes to Cells Think About what where when how how much variation created
Warm-UP Now we need to keep track of the genes on the chromosomes that are inherited Notice the letters on the chromosomes They represent different alleles for Huntingtons Barbie has Huntingtons What is the chance her child will get Huntingtons
AP Test Money DUE 36 TOMORROWRemember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Tomorrow 141 5 Key Ideas AND Concept Check 1-3
H=dominant (remember Huntingtonrsquos is dominant)
h=recessive (no Huntingtonrsquos)
Homework DUE Monday Test Corrections for 10 Make-UP
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
AP Test Money DUE 36 TODAYRemember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
DUE next Thursday Monohybrid Crosses
Homework DUE Monday Test Corrections for 10 Make-UP
Warm-UP Now we need to keep track of TWO UNLINKED genes on the chromosomes that are inherited Notice the letters on the chromosomes They represent different alleles for Huntingtons and red hair color Barbie has Huntingtons and is a blond (but a carrier) Ken does not have Huntingtonrsquos and is also a carrier for red hair What is the chance their child will get Huntingtons and red hair
Homework DUE Tomorrow 142 5 Key Ideas AND Concept Check 1-3
H= Huntingtonrsquosh=no HuntingtonrsquosR= no red hairr= red hair
DUE Now Test Corrections for 10 Make-UP
UNIT 78 TEST March 19th
Inheritance and Regulation
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
Homework DUE Tomorrow 143 5 Key Ideas AND Concept Check 1-3
DUE Now 142DUE Thursday Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
UNIT 78 TEST March 19th
Inheritance and Regulation
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoods
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with RrYy
1 Chance of baby with Rr 052 Chance of baby with Yy 053 Chance of baby with RrYy 025
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with both dominant phenotypes
1 Chance of baby with at least one R 0752 Chance of baby with at least one Y 0753 Chance of baby with RrYy 05625 (916)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with both dominant phenotypes
1 Chance of baby with at least one R 10
2 Chance of baby with at least one Y 10
3 Chance of baby with both dominant phenotypes 10
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
Homework DUE Tomorrow Linked vs Unlinked Genes AND Monohybrid Crosses to tunritincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with
vestigial wings and cinnabar eyes Predict the phenotypic ratio of the F2 individuals
Homework DUE Tomorrow 153 5 Key Ideas and Concept Check 1-3DUE Thursday Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with vestigial wings and cinnabar eyes Predict the
phenotypic ratio of the F2 individuals
3 The results of the cross from 2 show the following outcome Individuals of each phenotype are shown in the table Which of the following is the most likely explanation of the results a The two genes are located on two different chromosomes b The two genes are sex-linked c The two genes are located on mitochondrial DNA d The two genes are linked on an autosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
1 Build your diploid cell (an homologous pair for each chromosome)a Draw a big cell with a nucleus insideb DRAW homologous pairs of chromosomes
bull 1 big blue 1 big redbull 1 small blue 1 small red
ndash Add genes to your chromosomebull Write an H and an R on big blue and an h and an r on big redbull Write a T on small blue and a t on small red
2 Clone each chromosome (DNA Replication) (making sister chromatids)3 Nucleus breaks down (erase it)4 Homologous pairs form a tetrad crossing over may occur (note do not model
crossing over for now)5 Finish meiosis (see notes for help)6 Nucleus grows around chromosomes 4 cells made (gametes which have half
the number of chromosomes (haploids)7 Repeat Steps 1-6 this time at Step 4 include ONE crossover event
Recombination Modeling
When yoursquore confident on the process show Mr Jones
bull When yoursquore confident on the process show Mr Jones
bull In your notebookFigure 1510 Recombination p295At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid crossing over recombinant chromosome independent assortment Meiosis I Meiosis II
Recombination Modeling
Analysis
1 How does recombination increase the variety of gametes formed
2 Which types of gametes were more likely Gametes with recombinant chromosomes or ones without
3 Recombination is a random process How might it benefithurt the survival of an individualspecies
Recombination Modeling
Warm-UP
1 How could you calculate recombination frequency2 What would the recombination frequency tell you about the relative position of
genes on a chromosome3 Genes A B and C are on the same chromosome Testcrosses show that the
recombination frequency between A and B is 28 and between A and C is 12 Can you determine the linear order of these genes
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP What can we learn about inheritance from looking at a pedigree (use example of the Royal Family of Europe from the early 1900s)
Warm-UP In the following human pedigree squares represent males circles represent females and shaded symbols indicate individuals affected with a disorder One of the affected males from the third generation has a child with a female who is a carrier For the pedigree shown which of the following best expresses the probability that the couplersquos first son will be affected with the disorder
(A) 25 (B) 50 (C) 75 (D) 100
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Is a widowrsquos peak a dominant or recessive trait
Is a widowrsquos peak a dominant or recessive trait
Fig 14-UN5
George
Sandra Tom Sam
Arlene
Wilma Ann Michael
Carla
Daniel Alan Tina
Christopher
A heterozygous tall and a homozygous purple flowered plant is crossed with a short and white flowered plant Predict the offspring Assume independent assortment
1
P=purplep=whiteT=tallt=short
For a plant with the genotype WwXxYyZz what is the probability that the plant will produce a gamete with a haploid genotype of Wxyz Give your answer as a fraction or as a value between 0 and 1 to four decimal places
2
A completely-plated stickleback from a marine population was mated to a low-plated stickleback from a freshwater population The resulting F1 hybrids all displayed a completely plated phenotype When the F1 hybrids were allowed to interbreed the resulting F2 generation included completely plated offspring and low-plated offspring in an approximate 31 ratio Which of the following conclusions is best supported by the results of the breeding experiments
a Phenotypic variation in the F2 generation suggests that armor morphology is controlled by many alleles of a single gene
b The completely-plated phenotype is controlled by a dominant allele of a single gene
c Armor loss is an acquired characteristic that is affected by one or more environmental factors
d Patterns of armor plating in stickleback populations are regulated by sex-specific signals
3
If a man with type AB blood marries a woman with type O what blood types would you expect in their children What fraction would you expect of each type
4
IA= Type AIB= Type Bi= Type O
If a King marries a Queen that is a carrier of hemophilia (sex-linked recessive disease that is historically fatal before adulthood) what is the chance of the Kingdom having an heir to the kingrsquos throne assuming only one child is born
5
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
7 Gregor Mendelrsquos pioneering genetic experiments with pea plants occurred before the discovery of the structure and function of chromosomes Which of the following observations about inheritance in pea plants could be explained only after the discovery that genes may be linked on a chromosome
a Pea color and pea shape display independent inheritance patterns b Offspring of a given cross show all possible combinations of traits in
equal proportions c Most offspring of a given cross have a combination of traits that is
identical to that of either one parent or the other d Recessive phenotypes can skip a generation showing up only in the
parental and F 2 generations
8
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Based on the data in Table I which of the following best explains why there are no individuals with constricted pods in the F 1 generation a Inflated pod shape is dominant to constricted pod shape b The inflated-pod offspring in the F sub one generation are
homozygous c Constricted pod shape typically arises from a new mutation in the F 1
generation d The constricted-pod offspring are carriers for the inflated pod shape
allele
9
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table I the ratio of phenotypes in the offspring from the testcross with F 1 plants that had purple flowers and inflated pods suggests that the genes for flower color and pod shape are located a close together on the same autosome b on the X chromosome c on different chromosomes d on a mitochondrial chromosome
10
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Which of the following provides the best justification for an assumption that might have been used in the computer simulation (Table II) a The broad allele is recessive to the narrow allele because broad
leaves appear in every generation b The purple allele is dominant to the white allele because all the
offspring from the cross of purple-flowered and white-flowered plants had purple flowers
c The narrow allele is codominant with the purple allele because the purple-flower trait and the narrow-leaf trait segregate together
d The white allele is dominant to both the broad and narrow alleles because plants with either type of leaf shape can have white flowers
11
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table II the F 1 offspring of the cross between broad-leaved white-flowered plants with narrow-leaved purple-flowered plants have a phenotype that differs from that of either parent However many testcross offspring have the same phenotype as one of the two plants in the parental cross but relatively few testcross offspring have the same phenotype as the F 1 offspring Which of the following best explains the observation a Recombination between the leaf-shape and flower-color genes resulted in
chromosomes carrying a dominant allele of both genes b Recombination between the broad and narrow alleles of the leaf-shape gene resulted in
chromosomes carrying three different alleles at the same genetic locus c Independent assortment of homologous chromosomes resulted in the combinations of
alleles present in the parental generation d The computer model cannot capture the possible assortments of gametes when
multiple genes are considered
AP Test Money DUE 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework for Tonight
Warm-UP
1 Is blowing up a balloon a good model for how cells or organisms grow Explain
2 In what ways are cells different than each other the same
In eukaryotic organisms heritable information is passed to the next generation via mitosis and
meiosis
Cell Division 2 Types Mitosis and Meiosis
Mitosisbull Purpose
growth repair asexual reproduction (actually
binary fission in prokaryotes)bull occurs after DNA replicationbull is followed by cytokinesisbull 2 genetically identical daughter cells
(clones)bull Steps
1 Replication2 Alignment3 Separation
1 Draw a big cell with a nucleus inside2 Add homologous pairs of chromosomes
ndash 1 big yellow 1 big whitendash 1 medium yellow 1 medium whitendash 1 small yellow 1 small white
3 Clone each chromosome (DNA Replication) (making sister chromatids)
4 Nucleus breaks down (erase it)5 Clones separate one to each side of cell6 Cytokinesis cell membrane grows between the 2
halves7 Nucleus grows around chromosomes
Mitosis Modeling
When yoursquore confident on the process show Mr Jones
bull When yoursquore confident on the process show Mr Jones
bull In your notebookTable 127 Stages of Mitosis p232At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid
Mitosis Modeling
Analysis
1 What is the outcome of mitosis2 What steps of mitosis ensure a perfect
outcome3 If the first cell has 46 chromosomes (before
cloning) how many does each daughter cell have
4 Why do cells go through mitosis
Mitosis Modeling
Words to Knowbull Nucleusbull DNAbull Histonesbull Chromatinbull Chromosomebull Chromatidbull Centromere
Copyright copy 2002 Pearson Education Inc publishing as Benjamin Cummings
Interphase ldquoSrdquo phase
Mitosis
Warm-UP
1Advantages of Sex
2Disadvantages of Sex
AP Test Money DUE 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Thurs Meiosis Wksht
UNIT 78 TEST March 19th
Inheritance and Regulation
Fig 13-2
Bacteria
Parent
Bud
05 mmAsexual Reproduction
Advantages1 Can be done in isolation2 If you are perfect why change
Best when an organism is ldquoperfectlyrdquo suited for its environment
3 Less ldquomachineryrdquo needed no waste on flowers ldquonewrdquo types of cells or other secondary sexual characteristics
Disadvantages1 Less variety Poor option in a
changing environmentPlants
Fig 13-2
Parent
Bud
05 mmAsexual Reproduction
Advantages1 Can be done in isolation2 If you are perfect why change
Best when an organism is ldquoperfectlyrdquo suited for its environment
3 Less ldquomachineryrdquo needed no waste on flowers ldquonewrdquo types of cells or other secondary sexual characteristics
Disadvantages1 Less variety Poor option in a
changing environment
Fig 13-2
Parent
Bud
05 mmAsexual Reproduction
Advantages1 Can be done in isolation2 If you are perfect why change
Best when an organism is ldquoperfectlyrdquo suited for its environment
3 Less ldquomachineryrdquo needed no waste on flowers ldquonewrdquo types of cells or other secondary sexual characteristics
Disadvantages1 Less variety Poor option in a
changing environment
Aspen
Fig 13-1
Sexual ReproductionAdvantages1 Increased variety Best when
environment is changing
Increased Variety is DUE TObull random fertilizationbull meiosis
bull independent assortmentbull crossing-over
Disadvantages1 Resource investment
bull specialized cells gametesbull secondary sexual
characteristics mate attraction2 Requires a partner (except when
plants self-fertilize)
In eukaryotic organisms heritable information is passed to the next generation via mitosis and
meiosisCell Division 2 Types
Meiosis sex cells (gametes) (spermeggs)bull Purpose
ensures that each gamete receives one complete haploid (1n) set of chromosomes
Ensures chromosome number stays the same each offspring receives frac12 (1n) of the full set for the species (2n)
bull Steps1 DNA Replication2 homologous pairs form a tetrad
(independent assortment) (genetic variation increases)
3 cross over between homologous chromosomes may occur (genetic variation increases)
4 Meiosis I homologous pairs separate5 Meiosis II sister chromatids separate
In eukaryotic organisms heritable information is passed to the next generation via mitosis and
meiosisCell Division 2 Types
Meiosis sex cells (gametes) (spermeggs)bull Purpose
ensures that each gamete receives one complete haploid (1n) set of chromosomes
Ensures chromosome number stays the same each offspring receives frac12 (1n) of the full set for the species (2n)
bull Steps1 DNA Replication2 homologous pairs form a tetrad
(independent assortment) (genetic variation increases)
3 cross over between homologous chromosomes may occur (genetic variation increases)
4 Meiosis I homologous pairs separate5 Meiosis II sister chromatids separate
In eukaryotic organisms heritable information is passed to the next generation via mitosis and
meiosisCell Division 2 Types
Meiosis sex cells (gametes) (spermeggs)bull Purpose
ensures that each gamete receives one complete haploid (1n) set of chromosomes
Ensures chromosome number stays the same each offspring receives frac12 (1n) of the full set for the species (2n)
bull Steps1 DNA Replication2 homologous pairs form a tetrad
(independent assortment) (genetic variation increases)
3 cross over between homologous chromosomes may occur (genetic variation increases)
4 Meiosis I homologous pairs separate5 Meiosis II sister chromatids separate
1 Build your diploid cell (an homologous pair for each chromosome)a Draw a big cell with a nucleus insideb Add homologous pairs of chromosomes
bull 1 big white 1 big yellowbull 1 medium white 1 medium yellowbull 1 small white 1 small yellow
2 Clone each chromosome (DNA Replication) (making sister chromatids)3 Nucleus breaks down (erase it)4 Homologous pairs form a tetrad crossing over may occur (note do not model crossing
over for now)5 Homologous pairs separate one to each side of cell all paternal (or all maternal) do NOT
have to go together (independent assortment)6 Cytokinesis cell membrane grows between the 2 halves7 Clones (sister chromatids) separate (centromere ldquobreaksrdquo as DNA polymerization
completes) one to each side of cell8 Cytokinesis cell membrane grows between the 2 halves9 Nucleus grows around chromosomes 4 cells made (gametes which have half the
number of chromosomes (haploids)
Meiosis Modeling
When yoursquore confident on the process show Mr Jones
Meiosis Modelingbull When yoursquore confident on the process show Mr Jones
bull In your notebookTable 138 Stages of Meiosis p255At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid crossing over recombinant chromosome independent assortment Meiosis I Meiosis II
Meiosis Modeling
Analysis
1 What is the outcome of meiosis2 What steps of meiosis cause variation3 If the first cell has 46 chromosomes (before
cloning) how many does each daughter cell have4 How many unique gametes did you form How
many could have formed5 Why do cells go through meiosis
Warm-UP 1 Why do meiosis2 How does meiosis increase variation in organisms
AP Test Money DUE 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Tomorrow Meiosis Wksht
UNIT 78 TEST March 19th
Inheritance and Regulation
Meiosis has multiple processes that increases genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Meiosis has multiple processes that increase genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Meiosis has multiple processes that increase genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Meiosis has multiple processes that increases genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Warm-UP Watch the video What is happening Why does this happen How does this increase variation
AP Test Money DUE TOMORROW 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Tomorrow
UNIT 78 TEST March 19th
Inheritance and Regulation
Fig 13-9a
MITOSIS MEIOSIS
MEIOSIS I
Prophase I
Chiasma
Chromosomereplication
Homologouschromosomepair
Chromosomereplication
2n = 6
Parent cell
Prophase
Replicated chromosome
Metaphase Metaphase I
Anaphase ITelophase I
Haploid n = 3
Daughter cells ofmeiosis I
MEIOSIS II
Daughter cells of meiosis II
nnnn
2n2n
Daughter cellsof mitosis
AnaphaseTelophase
Compare
Contrast
Independent Assortment
Crossing-over Sexual Fertilization Mutation
Types of Changes to Cells Think About what where when how how much variation created
Warm-UP Now we need to keep track of the genes on the chromosomes that are inherited Notice the letters on the chromosomes They represent different alleles for Huntingtons Barbie has Huntingtons What is the chance her child will get Huntingtons
AP Test Money DUE 36 TOMORROWRemember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Tomorrow 141 5 Key Ideas AND Concept Check 1-3
H=dominant (remember Huntingtonrsquos is dominant)
h=recessive (no Huntingtonrsquos)
Homework DUE Monday Test Corrections for 10 Make-UP
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
AP Test Money DUE 36 TODAYRemember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
DUE next Thursday Monohybrid Crosses
Homework DUE Monday Test Corrections for 10 Make-UP
Warm-UP Now we need to keep track of TWO UNLINKED genes on the chromosomes that are inherited Notice the letters on the chromosomes They represent different alleles for Huntingtons and red hair color Barbie has Huntingtons and is a blond (but a carrier) Ken does not have Huntingtonrsquos and is also a carrier for red hair What is the chance their child will get Huntingtons and red hair
Homework DUE Tomorrow 142 5 Key Ideas AND Concept Check 1-3
H= Huntingtonrsquosh=no HuntingtonrsquosR= no red hairr= red hair
DUE Now Test Corrections for 10 Make-UP
UNIT 78 TEST March 19th
Inheritance and Regulation
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
Homework DUE Tomorrow 143 5 Key Ideas AND Concept Check 1-3
DUE Now 142DUE Thursday Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
UNIT 78 TEST March 19th
Inheritance and Regulation
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoods
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with RrYy
1 Chance of baby with Rr 052 Chance of baby with Yy 053 Chance of baby with RrYy 025
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with both dominant phenotypes
1 Chance of baby with at least one R 0752 Chance of baby with at least one Y 0753 Chance of baby with RrYy 05625 (916)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with both dominant phenotypes
1 Chance of baby with at least one R 10
2 Chance of baby with at least one Y 10
3 Chance of baby with both dominant phenotypes 10
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
Homework DUE Tomorrow Linked vs Unlinked Genes AND Monohybrid Crosses to tunritincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with
vestigial wings and cinnabar eyes Predict the phenotypic ratio of the F2 individuals
Homework DUE Tomorrow 153 5 Key Ideas and Concept Check 1-3DUE Thursday Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with vestigial wings and cinnabar eyes Predict the
phenotypic ratio of the F2 individuals
3 The results of the cross from 2 show the following outcome Individuals of each phenotype are shown in the table Which of the following is the most likely explanation of the results a The two genes are located on two different chromosomes b The two genes are sex-linked c The two genes are located on mitochondrial DNA d The two genes are linked on an autosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
1 Build your diploid cell (an homologous pair for each chromosome)a Draw a big cell with a nucleus insideb DRAW homologous pairs of chromosomes
bull 1 big blue 1 big redbull 1 small blue 1 small red
ndash Add genes to your chromosomebull Write an H and an R on big blue and an h and an r on big redbull Write a T on small blue and a t on small red
2 Clone each chromosome (DNA Replication) (making sister chromatids)3 Nucleus breaks down (erase it)4 Homologous pairs form a tetrad crossing over may occur (note do not model
crossing over for now)5 Finish meiosis (see notes for help)6 Nucleus grows around chromosomes 4 cells made (gametes which have half
the number of chromosomes (haploids)7 Repeat Steps 1-6 this time at Step 4 include ONE crossover event
Recombination Modeling
When yoursquore confident on the process show Mr Jones
bull When yoursquore confident on the process show Mr Jones
bull In your notebookFigure 1510 Recombination p295At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid crossing over recombinant chromosome independent assortment Meiosis I Meiosis II
Recombination Modeling
Analysis
1 How does recombination increase the variety of gametes formed
2 Which types of gametes were more likely Gametes with recombinant chromosomes or ones without
3 Recombination is a random process How might it benefithurt the survival of an individualspecies
Recombination Modeling
Warm-UP
1 How could you calculate recombination frequency2 What would the recombination frequency tell you about the relative position of
genes on a chromosome3 Genes A B and C are on the same chromosome Testcrosses show that the
recombination frequency between A and B is 28 and between A and C is 12 Can you determine the linear order of these genes
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP What can we learn about inheritance from looking at a pedigree (use example of the Royal Family of Europe from the early 1900s)
Warm-UP In the following human pedigree squares represent males circles represent females and shaded symbols indicate individuals affected with a disorder One of the affected males from the third generation has a child with a female who is a carrier For the pedigree shown which of the following best expresses the probability that the couplersquos first son will be affected with the disorder
(A) 25 (B) 50 (C) 75 (D) 100
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Is a widowrsquos peak a dominant or recessive trait
Is a widowrsquos peak a dominant or recessive trait
Fig 14-UN5
George
Sandra Tom Sam
Arlene
Wilma Ann Michael
Carla
Daniel Alan Tina
Christopher
A heterozygous tall and a homozygous purple flowered plant is crossed with a short and white flowered plant Predict the offspring Assume independent assortment
1
P=purplep=whiteT=tallt=short
For a plant with the genotype WwXxYyZz what is the probability that the plant will produce a gamete with a haploid genotype of Wxyz Give your answer as a fraction or as a value between 0 and 1 to four decimal places
2
A completely-plated stickleback from a marine population was mated to a low-plated stickleback from a freshwater population The resulting F1 hybrids all displayed a completely plated phenotype When the F1 hybrids were allowed to interbreed the resulting F2 generation included completely plated offspring and low-plated offspring in an approximate 31 ratio Which of the following conclusions is best supported by the results of the breeding experiments
a Phenotypic variation in the F2 generation suggests that armor morphology is controlled by many alleles of a single gene
b The completely-plated phenotype is controlled by a dominant allele of a single gene
c Armor loss is an acquired characteristic that is affected by one or more environmental factors
d Patterns of armor plating in stickleback populations are regulated by sex-specific signals
3
If a man with type AB blood marries a woman with type O what blood types would you expect in their children What fraction would you expect of each type
4
IA= Type AIB= Type Bi= Type O
If a King marries a Queen that is a carrier of hemophilia (sex-linked recessive disease that is historically fatal before adulthood) what is the chance of the Kingdom having an heir to the kingrsquos throne assuming only one child is born
5
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
7 Gregor Mendelrsquos pioneering genetic experiments with pea plants occurred before the discovery of the structure and function of chromosomes Which of the following observations about inheritance in pea plants could be explained only after the discovery that genes may be linked on a chromosome
a Pea color and pea shape display independent inheritance patterns b Offspring of a given cross show all possible combinations of traits in
equal proportions c Most offspring of a given cross have a combination of traits that is
identical to that of either one parent or the other d Recessive phenotypes can skip a generation showing up only in the
parental and F 2 generations
8
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Based on the data in Table I which of the following best explains why there are no individuals with constricted pods in the F 1 generation a Inflated pod shape is dominant to constricted pod shape b The inflated-pod offspring in the F sub one generation are
homozygous c Constricted pod shape typically arises from a new mutation in the F 1
generation d The constricted-pod offspring are carriers for the inflated pod shape
allele
9
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table I the ratio of phenotypes in the offspring from the testcross with F 1 plants that had purple flowers and inflated pods suggests that the genes for flower color and pod shape are located a close together on the same autosome b on the X chromosome c on different chromosomes d on a mitochondrial chromosome
10
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Which of the following provides the best justification for an assumption that might have been used in the computer simulation (Table II) a The broad allele is recessive to the narrow allele because broad
leaves appear in every generation b The purple allele is dominant to the white allele because all the
offspring from the cross of purple-flowered and white-flowered plants had purple flowers
c The narrow allele is codominant with the purple allele because the purple-flower trait and the narrow-leaf trait segregate together
d The white allele is dominant to both the broad and narrow alleles because plants with either type of leaf shape can have white flowers
11
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table II the F 1 offspring of the cross between broad-leaved white-flowered plants with narrow-leaved purple-flowered plants have a phenotype that differs from that of either parent However many testcross offspring have the same phenotype as one of the two plants in the parental cross but relatively few testcross offspring have the same phenotype as the F 1 offspring Which of the following best explains the observation a Recombination between the leaf-shape and flower-color genes resulted in
chromosomes carrying a dominant allele of both genes b Recombination between the broad and narrow alleles of the leaf-shape gene resulted in
chromosomes carrying three different alleles at the same genetic locus c Independent assortment of homologous chromosomes resulted in the combinations of
alleles present in the parental generation d The computer model cannot capture the possible assortments of gametes when
multiple genes are considered
In eukaryotic organisms heritable information is passed to the next generation via mitosis and
meiosis
Cell Division 2 Types Mitosis and Meiosis
Mitosisbull Purpose
growth repair asexual reproduction (actually
binary fission in prokaryotes)bull occurs after DNA replicationbull is followed by cytokinesisbull 2 genetically identical daughter cells
(clones)bull Steps
1 Replication2 Alignment3 Separation
1 Draw a big cell with a nucleus inside2 Add homologous pairs of chromosomes
ndash 1 big yellow 1 big whitendash 1 medium yellow 1 medium whitendash 1 small yellow 1 small white
3 Clone each chromosome (DNA Replication) (making sister chromatids)
4 Nucleus breaks down (erase it)5 Clones separate one to each side of cell6 Cytokinesis cell membrane grows between the 2
halves7 Nucleus grows around chromosomes
Mitosis Modeling
When yoursquore confident on the process show Mr Jones
bull When yoursquore confident on the process show Mr Jones
bull In your notebookTable 127 Stages of Mitosis p232At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid
Mitosis Modeling
Analysis
1 What is the outcome of mitosis2 What steps of mitosis ensure a perfect
outcome3 If the first cell has 46 chromosomes (before
cloning) how many does each daughter cell have
4 Why do cells go through mitosis
Mitosis Modeling
Words to Knowbull Nucleusbull DNAbull Histonesbull Chromatinbull Chromosomebull Chromatidbull Centromere
Copyright copy 2002 Pearson Education Inc publishing as Benjamin Cummings
Interphase ldquoSrdquo phase
Mitosis
Warm-UP
1Advantages of Sex
2Disadvantages of Sex
AP Test Money DUE 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Thurs Meiosis Wksht
UNIT 78 TEST March 19th
Inheritance and Regulation
Fig 13-2
Bacteria
Parent
Bud
05 mmAsexual Reproduction
Advantages1 Can be done in isolation2 If you are perfect why change
Best when an organism is ldquoperfectlyrdquo suited for its environment
3 Less ldquomachineryrdquo needed no waste on flowers ldquonewrdquo types of cells or other secondary sexual characteristics
Disadvantages1 Less variety Poor option in a
changing environmentPlants
Fig 13-2
Parent
Bud
05 mmAsexual Reproduction
Advantages1 Can be done in isolation2 If you are perfect why change
Best when an organism is ldquoperfectlyrdquo suited for its environment
3 Less ldquomachineryrdquo needed no waste on flowers ldquonewrdquo types of cells or other secondary sexual characteristics
Disadvantages1 Less variety Poor option in a
changing environment
Fig 13-2
Parent
Bud
05 mmAsexual Reproduction
Advantages1 Can be done in isolation2 If you are perfect why change
Best when an organism is ldquoperfectlyrdquo suited for its environment
3 Less ldquomachineryrdquo needed no waste on flowers ldquonewrdquo types of cells or other secondary sexual characteristics
Disadvantages1 Less variety Poor option in a
changing environment
Aspen
Fig 13-1
Sexual ReproductionAdvantages1 Increased variety Best when
environment is changing
Increased Variety is DUE TObull random fertilizationbull meiosis
bull independent assortmentbull crossing-over
Disadvantages1 Resource investment
bull specialized cells gametesbull secondary sexual
characteristics mate attraction2 Requires a partner (except when
plants self-fertilize)
In eukaryotic organisms heritable information is passed to the next generation via mitosis and
meiosisCell Division 2 Types
Meiosis sex cells (gametes) (spermeggs)bull Purpose
ensures that each gamete receives one complete haploid (1n) set of chromosomes
Ensures chromosome number stays the same each offspring receives frac12 (1n) of the full set for the species (2n)
bull Steps1 DNA Replication2 homologous pairs form a tetrad
(independent assortment) (genetic variation increases)
3 cross over between homologous chromosomes may occur (genetic variation increases)
4 Meiosis I homologous pairs separate5 Meiosis II sister chromatids separate
In eukaryotic organisms heritable information is passed to the next generation via mitosis and
meiosisCell Division 2 Types
Meiosis sex cells (gametes) (spermeggs)bull Purpose
ensures that each gamete receives one complete haploid (1n) set of chromosomes
Ensures chromosome number stays the same each offspring receives frac12 (1n) of the full set for the species (2n)
bull Steps1 DNA Replication2 homologous pairs form a tetrad
(independent assortment) (genetic variation increases)
3 cross over between homologous chromosomes may occur (genetic variation increases)
4 Meiosis I homologous pairs separate5 Meiosis II sister chromatids separate
In eukaryotic organisms heritable information is passed to the next generation via mitosis and
meiosisCell Division 2 Types
Meiosis sex cells (gametes) (spermeggs)bull Purpose
ensures that each gamete receives one complete haploid (1n) set of chromosomes
Ensures chromosome number stays the same each offspring receives frac12 (1n) of the full set for the species (2n)
bull Steps1 DNA Replication2 homologous pairs form a tetrad
(independent assortment) (genetic variation increases)
3 cross over between homologous chromosomes may occur (genetic variation increases)
4 Meiosis I homologous pairs separate5 Meiosis II sister chromatids separate
1 Build your diploid cell (an homologous pair for each chromosome)a Draw a big cell with a nucleus insideb Add homologous pairs of chromosomes
bull 1 big white 1 big yellowbull 1 medium white 1 medium yellowbull 1 small white 1 small yellow
2 Clone each chromosome (DNA Replication) (making sister chromatids)3 Nucleus breaks down (erase it)4 Homologous pairs form a tetrad crossing over may occur (note do not model crossing
over for now)5 Homologous pairs separate one to each side of cell all paternal (or all maternal) do NOT
have to go together (independent assortment)6 Cytokinesis cell membrane grows between the 2 halves7 Clones (sister chromatids) separate (centromere ldquobreaksrdquo as DNA polymerization
completes) one to each side of cell8 Cytokinesis cell membrane grows between the 2 halves9 Nucleus grows around chromosomes 4 cells made (gametes which have half the
number of chromosomes (haploids)
Meiosis Modeling
When yoursquore confident on the process show Mr Jones
Meiosis Modelingbull When yoursquore confident on the process show Mr Jones
bull In your notebookTable 138 Stages of Meiosis p255At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid crossing over recombinant chromosome independent assortment Meiosis I Meiosis II
Meiosis Modeling
Analysis
1 What is the outcome of meiosis2 What steps of meiosis cause variation3 If the first cell has 46 chromosomes (before
cloning) how many does each daughter cell have4 How many unique gametes did you form How
many could have formed5 Why do cells go through meiosis
Warm-UP 1 Why do meiosis2 How does meiosis increase variation in organisms
AP Test Money DUE 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Tomorrow Meiosis Wksht
UNIT 78 TEST March 19th
Inheritance and Regulation
Meiosis has multiple processes that increases genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Meiosis has multiple processes that increase genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Meiosis has multiple processes that increase genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Meiosis has multiple processes that increases genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Warm-UP Watch the video What is happening Why does this happen How does this increase variation
AP Test Money DUE TOMORROW 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Tomorrow
UNIT 78 TEST March 19th
Inheritance and Regulation
Fig 13-9a
MITOSIS MEIOSIS
MEIOSIS I
Prophase I
Chiasma
Chromosomereplication
Homologouschromosomepair
Chromosomereplication
2n = 6
Parent cell
Prophase
Replicated chromosome
Metaphase Metaphase I
Anaphase ITelophase I
Haploid n = 3
Daughter cells ofmeiosis I
MEIOSIS II
Daughter cells of meiosis II
nnnn
2n2n
Daughter cellsof mitosis
AnaphaseTelophase
Compare
Contrast
Independent Assortment
Crossing-over Sexual Fertilization Mutation
Types of Changes to Cells Think About what where when how how much variation created
Warm-UP Now we need to keep track of the genes on the chromosomes that are inherited Notice the letters on the chromosomes They represent different alleles for Huntingtons Barbie has Huntingtons What is the chance her child will get Huntingtons
AP Test Money DUE 36 TOMORROWRemember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Tomorrow 141 5 Key Ideas AND Concept Check 1-3
H=dominant (remember Huntingtonrsquos is dominant)
h=recessive (no Huntingtonrsquos)
Homework DUE Monday Test Corrections for 10 Make-UP
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
AP Test Money DUE 36 TODAYRemember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
DUE next Thursday Monohybrid Crosses
Homework DUE Monday Test Corrections for 10 Make-UP
Warm-UP Now we need to keep track of TWO UNLINKED genes on the chromosomes that are inherited Notice the letters on the chromosomes They represent different alleles for Huntingtons and red hair color Barbie has Huntingtons and is a blond (but a carrier) Ken does not have Huntingtonrsquos and is also a carrier for red hair What is the chance their child will get Huntingtons and red hair
Homework DUE Tomorrow 142 5 Key Ideas AND Concept Check 1-3
H= Huntingtonrsquosh=no HuntingtonrsquosR= no red hairr= red hair
DUE Now Test Corrections for 10 Make-UP
UNIT 78 TEST March 19th
Inheritance and Regulation
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
Homework DUE Tomorrow 143 5 Key Ideas AND Concept Check 1-3
DUE Now 142DUE Thursday Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
UNIT 78 TEST March 19th
Inheritance and Regulation
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoods
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with RrYy
1 Chance of baby with Rr 052 Chance of baby with Yy 053 Chance of baby with RrYy 025
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with both dominant phenotypes
1 Chance of baby with at least one R 0752 Chance of baby with at least one Y 0753 Chance of baby with RrYy 05625 (916)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with both dominant phenotypes
1 Chance of baby with at least one R 10
2 Chance of baby with at least one Y 10
3 Chance of baby with both dominant phenotypes 10
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
Homework DUE Tomorrow Linked vs Unlinked Genes AND Monohybrid Crosses to tunritincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with
vestigial wings and cinnabar eyes Predict the phenotypic ratio of the F2 individuals
Homework DUE Tomorrow 153 5 Key Ideas and Concept Check 1-3DUE Thursday Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with vestigial wings and cinnabar eyes Predict the
phenotypic ratio of the F2 individuals
3 The results of the cross from 2 show the following outcome Individuals of each phenotype are shown in the table Which of the following is the most likely explanation of the results a The two genes are located on two different chromosomes b The two genes are sex-linked c The two genes are located on mitochondrial DNA d The two genes are linked on an autosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
1 Build your diploid cell (an homologous pair for each chromosome)a Draw a big cell with a nucleus insideb DRAW homologous pairs of chromosomes
bull 1 big blue 1 big redbull 1 small blue 1 small red
ndash Add genes to your chromosomebull Write an H and an R on big blue and an h and an r on big redbull Write a T on small blue and a t on small red
2 Clone each chromosome (DNA Replication) (making sister chromatids)3 Nucleus breaks down (erase it)4 Homologous pairs form a tetrad crossing over may occur (note do not model
crossing over for now)5 Finish meiosis (see notes for help)6 Nucleus grows around chromosomes 4 cells made (gametes which have half
the number of chromosomes (haploids)7 Repeat Steps 1-6 this time at Step 4 include ONE crossover event
Recombination Modeling
When yoursquore confident on the process show Mr Jones
bull When yoursquore confident on the process show Mr Jones
bull In your notebookFigure 1510 Recombination p295At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid crossing over recombinant chromosome independent assortment Meiosis I Meiosis II
Recombination Modeling
Analysis
1 How does recombination increase the variety of gametes formed
2 Which types of gametes were more likely Gametes with recombinant chromosomes or ones without
3 Recombination is a random process How might it benefithurt the survival of an individualspecies
Recombination Modeling
Warm-UP
1 How could you calculate recombination frequency2 What would the recombination frequency tell you about the relative position of
genes on a chromosome3 Genes A B and C are on the same chromosome Testcrosses show that the
recombination frequency between A and B is 28 and between A and C is 12 Can you determine the linear order of these genes
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP What can we learn about inheritance from looking at a pedigree (use example of the Royal Family of Europe from the early 1900s)
Warm-UP In the following human pedigree squares represent males circles represent females and shaded symbols indicate individuals affected with a disorder One of the affected males from the third generation has a child with a female who is a carrier For the pedigree shown which of the following best expresses the probability that the couplersquos first son will be affected with the disorder
(A) 25 (B) 50 (C) 75 (D) 100
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Is a widowrsquos peak a dominant or recessive trait
Is a widowrsquos peak a dominant or recessive trait
Fig 14-UN5
George
Sandra Tom Sam
Arlene
Wilma Ann Michael
Carla
Daniel Alan Tina
Christopher
A heterozygous tall and a homozygous purple flowered plant is crossed with a short and white flowered plant Predict the offspring Assume independent assortment
1
P=purplep=whiteT=tallt=short
For a plant with the genotype WwXxYyZz what is the probability that the plant will produce a gamete with a haploid genotype of Wxyz Give your answer as a fraction or as a value between 0 and 1 to four decimal places
2
A completely-plated stickleback from a marine population was mated to a low-plated stickleback from a freshwater population The resulting F1 hybrids all displayed a completely plated phenotype When the F1 hybrids were allowed to interbreed the resulting F2 generation included completely plated offspring and low-plated offspring in an approximate 31 ratio Which of the following conclusions is best supported by the results of the breeding experiments
a Phenotypic variation in the F2 generation suggests that armor morphology is controlled by many alleles of a single gene
b The completely-plated phenotype is controlled by a dominant allele of a single gene
c Armor loss is an acquired characteristic that is affected by one or more environmental factors
d Patterns of armor plating in stickleback populations are regulated by sex-specific signals
3
If a man with type AB blood marries a woman with type O what blood types would you expect in their children What fraction would you expect of each type
4
IA= Type AIB= Type Bi= Type O
If a King marries a Queen that is a carrier of hemophilia (sex-linked recessive disease that is historically fatal before adulthood) what is the chance of the Kingdom having an heir to the kingrsquos throne assuming only one child is born
5
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
7 Gregor Mendelrsquos pioneering genetic experiments with pea plants occurred before the discovery of the structure and function of chromosomes Which of the following observations about inheritance in pea plants could be explained only after the discovery that genes may be linked on a chromosome
a Pea color and pea shape display independent inheritance patterns b Offspring of a given cross show all possible combinations of traits in
equal proportions c Most offspring of a given cross have a combination of traits that is
identical to that of either one parent or the other d Recessive phenotypes can skip a generation showing up only in the
parental and F 2 generations
8
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Based on the data in Table I which of the following best explains why there are no individuals with constricted pods in the F 1 generation a Inflated pod shape is dominant to constricted pod shape b The inflated-pod offspring in the F sub one generation are
homozygous c Constricted pod shape typically arises from a new mutation in the F 1
generation d The constricted-pod offspring are carriers for the inflated pod shape
allele
9
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table I the ratio of phenotypes in the offspring from the testcross with F 1 plants that had purple flowers and inflated pods suggests that the genes for flower color and pod shape are located a close together on the same autosome b on the X chromosome c on different chromosomes d on a mitochondrial chromosome
10
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Which of the following provides the best justification for an assumption that might have been used in the computer simulation (Table II) a The broad allele is recessive to the narrow allele because broad
leaves appear in every generation b The purple allele is dominant to the white allele because all the
offspring from the cross of purple-flowered and white-flowered plants had purple flowers
c The narrow allele is codominant with the purple allele because the purple-flower trait and the narrow-leaf trait segregate together
d The white allele is dominant to both the broad and narrow alleles because plants with either type of leaf shape can have white flowers
11
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table II the F 1 offspring of the cross between broad-leaved white-flowered plants with narrow-leaved purple-flowered plants have a phenotype that differs from that of either parent However many testcross offspring have the same phenotype as one of the two plants in the parental cross but relatively few testcross offspring have the same phenotype as the F 1 offspring Which of the following best explains the observation a Recombination between the leaf-shape and flower-color genes resulted in
chromosomes carrying a dominant allele of both genes b Recombination between the broad and narrow alleles of the leaf-shape gene resulted in
chromosomes carrying three different alleles at the same genetic locus c Independent assortment of homologous chromosomes resulted in the combinations of
alleles present in the parental generation d The computer model cannot capture the possible assortments of gametes when
multiple genes are considered
1 Draw a big cell with a nucleus inside2 Add homologous pairs of chromosomes
ndash 1 big yellow 1 big whitendash 1 medium yellow 1 medium whitendash 1 small yellow 1 small white
3 Clone each chromosome (DNA Replication) (making sister chromatids)
4 Nucleus breaks down (erase it)5 Clones separate one to each side of cell6 Cytokinesis cell membrane grows between the 2
halves7 Nucleus grows around chromosomes
Mitosis Modeling
When yoursquore confident on the process show Mr Jones
bull When yoursquore confident on the process show Mr Jones
bull In your notebookTable 127 Stages of Mitosis p232At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid
Mitosis Modeling
Analysis
1 What is the outcome of mitosis2 What steps of mitosis ensure a perfect
outcome3 If the first cell has 46 chromosomes (before
cloning) how many does each daughter cell have
4 Why do cells go through mitosis
Mitosis Modeling
Words to Knowbull Nucleusbull DNAbull Histonesbull Chromatinbull Chromosomebull Chromatidbull Centromere
Copyright copy 2002 Pearson Education Inc publishing as Benjamin Cummings
Interphase ldquoSrdquo phase
Mitosis
Warm-UP
1Advantages of Sex
2Disadvantages of Sex
AP Test Money DUE 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Thurs Meiosis Wksht
UNIT 78 TEST March 19th
Inheritance and Regulation
Fig 13-2
Bacteria
Parent
Bud
05 mmAsexual Reproduction
Advantages1 Can be done in isolation2 If you are perfect why change
Best when an organism is ldquoperfectlyrdquo suited for its environment
3 Less ldquomachineryrdquo needed no waste on flowers ldquonewrdquo types of cells or other secondary sexual characteristics
Disadvantages1 Less variety Poor option in a
changing environmentPlants
Fig 13-2
Parent
Bud
05 mmAsexual Reproduction
Advantages1 Can be done in isolation2 If you are perfect why change
Best when an organism is ldquoperfectlyrdquo suited for its environment
3 Less ldquomachineryrdquo needed no waste on flowers ldquonewrdquo types of cells or other secondary sexual characteristics
Disadvantages1 Less variety Poor option in a
changing environment
Fig 13-2
Parent
Bud
05 mmAsexual Reproduction
Advantages1 Can be done in isolation2 If you are perfect why change
Best when an organism is ldquoperfectlyrdquo suited for its environment
3 Less ldquomachineryrdquo needed no waste on flowers ldquonewrdquo types of cells or other secondary sexual characteristics
Disadvantages1 Less variety Poor option in a
changing environment
Aspen
Fig 13-1
Sexual ReproductionAdvantages1 Increased variety Best when
environment is changing
Increased Variety is DUE TObull random fertilizationbull meiosis
bull independent assortmentbull crossing-over
Disadvantages1 Resource investment
bull specialized cells gametesbull secondary sexual
characteristics mate attraction2 Requires a partner (except when
plants self-fertilize)
In eukaryotic organisms heritable information is passed to the next generation via mitosis and
meiosisCell Division 2 Types
Meiosis sex cells (gametes) (spermeggs)bull Purpose
ensures that each gamete receives one complete haploid (1n) set of chromosomes
Ensures chromosome number stays the same each offspring receives frac12 (1n) of the full set for the species (2n)
bull Steps1 DNA Replication2 homologous pairs form a tetrad
(independent assortment) (genetic variation increases)
3 cross over between homologous chromosomes may occur (genetic variation increases)
4 Meiosis I homologous pairs separate5 Meiosis II sister chromatids separate
In eukaryotic organisms heritable information is passed to the next generation via mitosis and
meiosisCell Division 2 Types
Meiosis sex cells (gametes) (spermeggs)bull Purpose
ensures that each gamete receives one complete haploid (1n) set of chromosomes
Ensures chromosome number stays the same each offspring receives frac12 (1n) of the full set for the species (2n)
bull Steps1 DNA Replication2 homologous pairs form a tetrad
(independent assortment) (genetic variation increases)
3 cross over between homologous chromosomes may occur (genetic variation increases)
4 Meiosis I homologous pairs separate5 Meiosis II sister chromatids separate
In eukaryotic organisms heritable information is passed to the next generation via mitosis and
meiosisCell Division 2 Types
Meiosis sex cells (gametes) (spermeggs)bull Purpose
ensures that each gamete receives one complete haploid (1n) set of chromosomes
Ensures chromosome number stays the same each offspring receives frac12 (1n) of the full set for the species (2n)
bull Steps1 DNA Replication2 homologous pairs form a tetrad
(independent assortment) (genetic variation increases)
3 cross over between homologous chromosomes may occur (genetic variation increases)
4 Meiosis I homologous pairs separate5 Meiosis II sister chromatids separate
1 Build your diploid cell (an homologous pair for each chromosome)a Draw a big cell with a nucleus insideb Add homologous pairs of chromosomes
bull 1 big white 1 big yellowbull 1 medium white 1 medium yellowbull 1 small white 1 small yellow
2 Clone each chromosome (DNA Replication) (making sister chromatids)3 Nucleus breaks down (erase it)4 Homologous pairs form a tetrad crossing over may occur (note do not model crossing
over for now)5 Homologous pairs separate one to each side of cell all paternal (or all maternal) do NOT
have to go together (independent assortment)6 Cytokinesis cell membrane grows between the 2 halves7 Clones (sister chromatids) separate (centromere ldquobreaksrdquo as DNA polymerization
completes) one to each side of cell8 Cytokinesis cell membrane grows between the 2 halves9 Nucleus grows around chromosomes 4 cells made (gametes which have half the
number of chromosomes (haploids)
Meiosis Modeling
When yoursquore confident on the process show Mr Jones
Meiosis Modelingbull When yoursquore confident on the process show Mr Jones
bull In your notebookTable 138 Stages of Meiosis p255At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid crossing over recombinant chromosome independent assortment Meiosis I Meiosis II
Meiosis Modeling
Analysis
1 What is the outcome of meiosis2 What steps of meiosis cause variation3 If the first cell has 46 chromosomes (before
cloning) how many does each daughter cell have4 How many unique gametes did you form How
many could have formed5 Why do cells go through meiosis
Warm-UP 1 Why do meiosis2 How does meiosis increase variation in organisms
AP Test Money DUE 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Tomorrow Meiosis Wksht
UNIT 78 TEST March 19th
Inheritance and Regulation
Meiosis has multiple processes that increases genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Meiosis has multiple processes that increase genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Meiosis has multiple processes that increase genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Meiosis has multiple processes that increases genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Warm-UP Watch the video What is happening Why does this happen How does this increase variation
AP Test Money DUE TOMORROW 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Tomorrow
UNIT 78 TEST March 19th
Inheritance and Regulation
Fig 13-9a
MITOSIS MEIOSIS
MEIOSIS I
Prophase I
Chiasma
Chromosomereplication
Homologouschromosomepair
Chromosomereplication
2n = 6
Parent cell
Prophase
Replicated chromosome
Metaphase Metaphase I
Anaphase ITelophase I
Haploid n = 3
Daughter cells ofmeiosis I
MEIOSIS II
Daughter cells of meiosis II
nnnn
2n2n
Daughter cellsof mitosis
AnaphaseTelophase
Compare
Contrast
Independent Assortment
Crossing-over Sexual Fertilization Mutation
Types of Changes to Cells Think About what where when how how much variation created
Warm-UP Now we need to keep track of the genes on the chromosomes that are inherited Notice the letters on the chromosomes They represent different alleles for Huntingtons Barbie has Huntingtons What is the chance her child will get Huntingtons
AP Test Money DUE 36 TOMORROWRemember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Tomorrow 141 5 Key Ideas AND Concept Check 1-3
H=dominant (remember Huntingtonrsquos is dominant)
h=recessive (no Huntingtonrsquos)
Homework DUE Monday Test Corrections for 10 Make-UP
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
AP Test Money DUE 36 TODAYRemember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
DUE next Thursday Monohybrid Crosses
Homework DUE Monday Test Corrections for 10 Make-UP
Warm-UP Now we need to keep track of TWO UNLINKED genes on the chromosomes that are inherited Notice the letters on the chromosomes They represent different alleles for Huntingtons and red hair color Barbie has Huntingtons and is a blond (but a carrier) Ken does not have Huntingtonrsquos and is also a carrier for red hair What is the chance their child will get Huntingtons and red hair
Homework DUE Tomorrow 142 5 Key Ideas AND Concept Check 1-3
H= Huntingtonrsquosh=no HuntingtonrsquosR= no red hairr= red hair
DUE Now Test Corrections for 10 Make-UP
UNIT 78 TEST March 19th
Inheritance and Regulation
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
Homework DUE Tomorrow 143 5 Key Ideas AND Concept Check 1-3
DUE Now 142DUE Thursday Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
UNIT 78 TEST March 19th
Inheritance and Regulation
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoods
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with RrYy
1 Chance of baby with Rr 052 Chance of baby with Yy 053 Chance of baby with RrYy 025
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with both dominant phenotypes
1 Chance of baby with at least one R 0752 Chance of baby with at least one Y 0753 Chance of baby with RrYy 05625 (916)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with both dominant phenotypes
1 Chance of baby with at least one R 10
2 Chance of baby with at least one Y 10
3 Chance of baby with both dominant phenotypes 10
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
Homework DUE Tomorrow Linked vs Unlinked Genes AND Monohybrid Crosses to tunritincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with
vestigial wings and cinnabar eyes Predict the phenotypic ratio of the F2 individuals
Homework DUE Tomorrow 153 5 Key Ideas and Concept Check 1-3DUE Thursday Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with vestigial wings and cinnabar eyes Predict the
phenotypic ratio of the F2 individuals
3 The results of the cross from 2 show the following outcome Individuals of each phenotype are shown in the table Which of the following is the most likely explanation of the results a The two genes are located on two different chromosomes b The two genes are sex-linked c The two genes are located on mitochondrial DNA d The two genes are linked on an autosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
1 Build your diploid cell (an homologous pair for each chromosome)a Draw a big cell with a nucleus insideb DRAW homologous pairs of chromosomes
bull 1 big blue 1 big redbull 1 small blue 1 small red
ndash Add genes to your chromosomebull Write an H and an R on big blue and an h and an r on big redbull Write a T on small blue and a t on small red
2 Clone each chromosome (DNA Replication) (making sister chromatids)3 Nucleus breaks down (erase it)4 Homologous pairs form a tetrad crossing over may occur (note do not model
crossing over for now)5 Finish meiosis (see notes for help)6 Nucleus grows around chromosomes 4 cells made (gametes which have half
the number of chromosomes (haploids)7 Repeat Steps 1-6 this time at Step 4 include ONE crossover event
Recombination Modeling
When yoursquore confident on the process show Mr Jones
bull When yoursquore confident on the process show Mr Jones
bull In your notebookFigure 1510 Recombination p295At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid crossing over recombinant chromosome independent assortment Meiosis I Meiosis II
Recombination Modeling
Analysis
1 How does recombination increase the variety of gametes formed
2 Which types of gametes were more likely Gametes with recombinant chromosomes or ones without
3 Recombination is a random process How might it benefithurt the survival of an individualspecies
Recombination Modeling
Warm-UP
1 How could you calculate recombination frequency2 What would the recombination frequency tell you about the relative position of
genes on a chromosome3 Genes A B and C are on the same chromosome Testcrosses show that the
recombination frequency between A and B is 28 and between A and C is 12 Can you determine the linear order of these genes
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP What can we learn about inheritance from looking at a pedigree (use example of the Royal Family of Europe from the early 1900s)
Warm-UP In the following human pedigree squares represent males circles represent females and shaded symbols indicate individuals affected with a disorder One of the affected males from the third generation has a child with a female who is a carrier For the pedigree shown which of the following best expresses the probability that the couplersquos first son will be affected with the disorder
(A) 25 (B) 50 (C) 75 (D) 100
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Is a widowrsquos peak a dominant or recessive trait
Is a widowrsquos peak a dominant or recessive trait
Fig 14-UN5
George
Sandra Tom Sam
Arlene
Wilma Ann Michael
Carla
Daniel Alan Tina
Christopher
A heterozygous tall and a homozygous purple flowered plant is crossed with a short and white flowered plant Predict the offspring Assume independent assortment
1
P=purplep=whiteT=tallt=short
For a plant with the genotype WwXxYyZz what is the probability that the plant will produce a gamete with a haploid genotype of Wxyz Give your answer as a fraction or as a value between 0 and 1 to four decimal places
2
A completely-plated stickleback from a marine population was mated to a low-plated stickleback from a freshwater population The resulting F1 hybrids all displayed a completely plated phenotype When the F1 hybrids were allowed to interbreed the resulting F2 generation included completely plated offspring and low-plated offspring in an approximate 31 ratio Which of the following conclusions is best supported by the results of the breeding experiments
a Phenotypic variation in the F2 generation suggests that armor morphology is controlled by many alleles of a single gene
b The completely-plated phenotype is controlled by a dominant allele of a single gene
c Armor loss is an acquired characteristic that is affected by one or more environmental factors
d Patterns of armor plating in stickleback populations are regulated by sex-specific signals
3
If a man with type AB blood marries a woman with type O what blood types would you expect in their children What fraction would you expect of each type
4
IA= Type AIB= Type Bi= Type O
If a King marries a Queen that is a carrier of hemophilia (sex-linked recessive disease that is historically fatal before adulthood) what is the chance of the Kingdom having an heir to the kingrsquos throne assuming only one child is born
5
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
7 Gregor Mendelrsquos pioneering genetic experiments with pea plants occurred before the discovery of the structure and function of chromosomes Which of the following observations about inheritance in pea plants could be explained only after the discovery that genes may be linked on a chromosome
a Pea color and pea shape display independent inheritance patterns b Offspring of a given cross show all possible combinations of traits in
equal proportions c Most offspring of a given cross have a combination of traits that is
identical to that of either one parent or the other d Recessive phenotypes can skip a generation showing up only in the
parental and F 2 generations
8
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Based on the data in Table I which of the following best explains why there are no individuals with constricted pods in the F 1 generation a Inflated pod shape is dominant to constricted pod shape b The inflated-pod offspring in the F sub one generation are
homozygous c Constricted pod shape typically arises from a new mutation in the F 1
generation d The constricted-pod offspring are carriers for the inflated pod shape
allele
9
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table I the ratio of phenotypes in the offspring from the testcross with F 1 plants that had purple flowers and inflated pods suggests that the genes for flower color and pod shape are located a close together on the same autosome b on the X chromosome c on different chromosomes d on a mitochondrial chromosome
10
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Which of the following provides the best justification for an assumption that might have been used in the computer simulation (Table II) a The broad allele is recessive to the narrow allele because broad
leaves appear in every generation b The purple allele is dominant to the white allele because all the
offspring from the cross of purple-flowered and white-flowered plants had purple flowers
c The narrow allele is codominant with the purple allele because the purple-flower trait and the narrow-leaf trait segregate together
d The white allele is dominant to both the broad and narrow alleles because plants with either type of leaf shape can have white flowers
11
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table II the F 1 offspring of the cross between broad-leaved white-flowered plants with narrow-leaved purple-flowered plants have a phenotype that differs from that of either parent However many testcross offspring have the same phenotype as one of the two plants in the parental cross but relatively few testcross offspring have the same phenotype as the F 1 offspring Which of the following best explains the observation a Recombination between the leaf-shape and flower-color genes resulted in
chromosomes carrying a dominant allele of both genes b Recombination between the broad and narrow alleles of the leaf-shape gene resulted in
chromosomes carrying three different alleles at the same genetic locus c Independent assortment of homologous chromosomes resulted in the combinations of
alleles present in the parental generation d The computer model cannot capture the possible assortments of gametes when
multiple genes are considered
bull When yoursquore confident on the process show Mr Jones
bull In your notebookTable 127 Stages of Mitosis p232At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid
Mitosis Modeling
Analysis
1 What is the outcome of mitosis2 What steps of mitosis ensure a perfect
outcome3 If the first cell has 46 chromosomes (before
cloning) how many does each daughter cell have
4 Why do cells go through mitosis
Mitosis Modeling
Words to Knowbull Nucleusbull DNAbull Histonesbull Chromatinbull Chromosomebull Chromatidbull Centromere
Copyright copy 2002 Pearson Education Inc publishing as Benjamin Cummings
Interphase ldquoSrdquo phase
Mitosis
Warm-UP
1Advantages of Sex
2Disadvantages of Sex
AP Test Money DUE 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Thurs Meiosis Wksht
UNIT 78 TEST March 19th
Inheritance and Regulation
Fig 13-2
Bacteria
Parent
Bud
05 mmAsexual Reproduction
Advantages1 Can be done in isolation2 If you are perfect why change
Best when an organism is ldquoperfectlyrdquo suited for its environment
3 Less ldquomachineryrdquo needed no waste on flowers ldquonewrdquo types of cells or other secondary sexual characteristics
Disadvantages1 Less variety Poor option in a
changing environmentPlants
Fig 13-2
Parent
Bud
05 mmAsexual Reproduction
Advantages1 Can be done in isolation2 If you are perfect why change
Best when an organism is ldquoperfectlyrdquo suited for its environment
3 Less ldquomachineryrdquo needed no waste on flowers ldquonewrdquo types of cells or other secondary sexual characteristics
Disadvantages1 Less variety Poor option in a
changing environment
Fig 13-2
Parent
Bud
05 mmAsexual Reproduction
Advantages1 Can be done in isolation2 If you are perfect why change
Best when an organism is ldquoperfectlyrdquo suited for its environment
3 Less ldquomachineryrdquo needed no waste on flowers ldquonewrdquo types of cells or other secondary sexual characteristics
Disadvantages1 Less variety Poor option in a
changing environment
Aspen
Fig 13-1
Sexual ReproductionAdvantages1 Increased variety Best when
environment is changing
Increased Variety is DUE TObull random fertilizationbull meiosis
bull independent assortmentbull crossing-over
Disadvantages1 Resource investment
bull specialized cells gametesbull secondary sexual
characteristics mate attraction2 Requires a partner (except when
plants self-fertilize)
In eukaryotic organisms heritable information is passed to the next generation via mitosis and
meiosisCell Division 2 Types
Meiosis sex cells (gametes) (spermeggs)bull Purpose
ensures that each gamete receives one complete haploid (1n) set of chromosomes
Ensures chromosome number stays the same each offspring receives frac12 (1n) of the full set for the species (2n)
bull Steps1 DNA Replication2 homologous pairs form a tetrad
(independent assortment) (genetic variation increases)
3 cross over between homologous chromosomes may occur (genetic variation increases)
4 Meiosis I homologous pairs separate5 Meiosis II sister chromatids separate
In eukaryotic organisms heritable information is passed to the next generation via mitosis and
meiosisCell Division 2 Types
Meiosis sex cells (gametes) (spermeggs)bull Purpose
ensures that each gamete receives one complete haploid (1n) set of chromosomes
Ensures chromosome number stays the same each offspring receives frac12 (1n) of the full set for the species (2n)
bull Steps1 DNA Replication2 homologous pairs form a tetrad
(independent assortment) (genetic variation increases)
3 cross over between homologous chromosomes may occur (genetic variation increases)
4 Meiosis I homologous pairs separate5 Meiosis II sister chromatids separate
In eukaryotic organisms heritable information is passed to the next generation via mitosis and
meiosisCell Division 2 Types
Meiosis sex cells (gametes) (spermeggs)bull Purpose
ensures that each gamete receives one complete haploid (1n) set of chromosomes
Ensures chromosome number stays the same each offspring receives frac12 (1n) of the full set for the species (2n)
bull Steps1 DNA Replication2 homologous pairs form a tetrad
(independent assortment) (genetic variation increases)
3 cross over between homologous chromosomes may occur (genetic variation increases)
4 Meiosis I homologous pairs separate5 Meiosis II sister chromatids separate
1 Build your diploid cell (an homologous pair for each chromosome)a Draw a big cell with a nucleus insideb Add homologous pairs of chromosomes
bull 1 big white 1 big yellowbull 1 medium white 1 medium yellowbull 1 small white 1 small yellow
2 Clone each chromosome (DNA Replication) (making sister chromatids)3 Nucleus breaks down (erase it)4 Homologous pairs form a tetrad crossing over may occur (note do not model crossing
over for now)5 Homologous pairs separate one to each side of cell all paternal (or all maternal) do NOT
have to go together (independent assortment)6 Cytokinesis cell membrane grows between the 2 halves7 Clones (sister chromatids) separate (centromere ldquobreaksrdquo as DNA polymerization
completes) one to each side of cell8 Cytokinesis cell membrane grows between the 2 halves9 Nucleus grows around chromosomes 4 cells made (gametes which have half the
number of chromosomes (haploids)
Meiosis Modeling
When yoursquore confident on the process show Mr Jones
Meiosis Modelingbull When yoursquore confident on the process show Mr Jones
bull In your notebookTable 138 Stages of Meiosis p255At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid crossing over recombinant chromosome independent assortment Meiosis I Meiosis II
Meiosis Modeling
Analysis
1 What is the outcome of meiosis2 What steps of meiosis cause variation3 If the first cell has 46 chromosomes (before
cloning) how many does each daughter cell have4 How many unique gametes did you form How
many could have formed5 Why do cells go through meiosis
Warm-UP 1 Why do meiosis2 How does meiosis increase variation in organisms
AP Test Money DUE 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Tomorrow Meiosis Wksht
UNIT 78 TEST March 19th
Inheritance and Regulation
Meiosis has multiple processes that increases genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Meiosis has multiple processes that increase genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Meiosis has multiple processes that increase genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Meiosis has multiple processes that increases genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Warm-UP Watch the video What is happening Why does this happen How does this increase variation
AP Test Money DUE TOMORROW 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Tomorrow
UNIT 78 TEST March 19th
Inheritance and Regulation
Fig 13-9a
MITOSIS MEIOSIS
MEIOSIS I
Prophase I
Chiasma
Chromosomereplication
Homologouschromosomepair
Chromosomereplication
2n = 6
Parent cell
Prophase
Replicated chromosome
Metaphase Metaphase I
Anaphase ITelophase I
Haploid n = 3
Daughter cells ofmeiosis I
MEIOSIS II
Daughter cells of meiosis II
nnnn
2n2n
Daughter cellsof mitosis
AnaphaseTelophase
Compare
Contrast
Independent Assortment
Crossing-over Sexual Fertilization Mutation
Types of Changes to Cells Think About what where when how how much variation created
Warm-UP Now we need to keep track of the genes on the chromosomes that are inherited Notice the letters on the chromosomes They represent different alleles for Huntingtons Barbie has Huntingtons What is the chance her child will get Huntingtons
AP Test Money DUE 36 TOMORROWRemember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Tomorrow 141 5 Key Ideas AND Concept Check 1-3
H=dominant (remember Huntingtonrsquos is dominant)
h=recessive (no Huntingtonrsquos)
Homework DUE Monday Test Corrections for 10 Make-UP
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
AP Test Money DUE 36 TODAYRemember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
DUE next Thursday Monohybrid Crosses
Homework DUE Monday Test Corrections for 10 Make-UP
Warm-UP Now we need to keep track of TWO UNLINKED genes on the chromosomes that are inherited Notice the letters on the chromosomes They represent different alleles for Huntingtons and red hair color Barbie has Huntingtons and is a blond (but a carrier) Ken does not have Huntingtonrsquos and is also a carrier for red hair What is the chance their child will get Huntingtons and red hair
Homework DUE Tomorrow 142 5 Key Ideas AND Concept Check 1-3
H= Huntingtonrsquosh=no HuntingtonrsquosR= no red hairr= red hair
DUE Now Test Corrections for 10 Make-UP
UNIT 78 TEST March 19th
Inheritance and Regulation
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
Homework DUE Tomorrow 143 5 Key Ideas AND Concept Check 1-3
DUE Now 142DUE Thursday Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
UNIT 78 TEST March 19th
Inheritance and Regulation
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoods
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with RrYy
1 Chance of baby with Rr 052 Chance of baby with Yy 053 Chance of baby with RrYy 025
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with both dominant phenotypes
1 Chance of baby with at least one R 0752 Chance of baby with at least one Y 0753 Chance of baby with RrYy 05625 (916)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with both dominant phenotypes
1 Chance of baby with at least one R 10
2 Chance of baby with at least one Y 10
3 Chance of baby with both dominant phenotypes 10
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
Homework DUE Tomorrow Linked vs Unlinked Genes AND Monohybrid Crosses to tunritincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with
vestigial wings and cinnabar eyes Predict the phenotypic ratio of the F2 individuals
Homework DUE Tomorrow 153 5 Key Ideas and Concept Check 1-3DUE Thursday Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with vestigial wings and cinnabar eyes Predict the
phenotypic ratio of the F2 individuals
3 The results of the cross from 2 show the following outcome Individuals of each phenotype are shown in the table Which of the following is the most likely explanation of the results a The two genes are located on two different chromosomes b The two genes are sex-linked c The two genes are located on mitochondrial DNA d The two genes are linked on an autosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
1 Build your diploid cell (an homologous pair for each chromosome)a Draw a big cell with a nucleus insideb DRAW homologous pairs of chromosomes
bull 1 big blue 1 big redbull 1 small blue 1 small red
ndash Add genes to your chromosomebull Write an H and an R on big blue and an h and an r on big redbull Write a T on small blue and a t on small red
2 Clone each chromosome (DNA Replication) (making sister chromatids)3 Nucleus breaks down (erase it)4 Homologous pairs form a tetrad crossing over may occur (note do not model
crossing over for now)5 Finish meiosis (see notes for help)6 Nucleus grows around chromosomes 4 cells made (gametes which have half
the number of chromosomes (haploids)7 Repeat Steps 1-6 this time at Step 4 include ONE crossover event
Recombination Modeling
When yoursquore confident on the process show Mr Jones
bull When yoursquore confident on the process show Mr Jones
bull In your notebookFigure 1510 Recombination p295At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid crossing over recombinant chromosome independent assortment Meiosis I Meiosis II
Recombination Modeling
Analysis
1 How does recombination increase the variety of gametes formed
2 Which types of gametes were more likely Gametes with recombinant chromosomes or ones without
3 Recombination is a random process How might it benefithurt the survival of an individualspecies
Recombination Modeling
Warm-UP
1 How could you calculate recombination frequency2 What would the recombination frequency tell you about the relative position of
genes on a chromosome3 Genes A B and C are on the same chromosome Testcrosses show that the
recombination frequency between A and B is 28 and between A and C is 12 Can you determine the linear order of these genes
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP What can we learn about inheritance from looking at a pedigree (use example of the Royal Family of Europe from the early 1900s)
Warm-UP In the following human pedigree squares represent males circles represent females and shaded symbols indicate individuals affected with a disorder One of the affected males from the third generation has a child with a female who is a carrier For the pedigree shown which of the following best expresses the probability that the couplersquos first son will be affected with the disorder
(A) 25 (B) 50 (C) 75 (D) 100
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Is a widowrsquos peak a dominant or recessive trait
Is a widowrsquos peak a dominant or recessive trait
Fig 14-UN5
George
Sandra Tom Sam
Arlene
Wilma Ann Michael
Carla
Daniel Alan Tina
Christopher
A heterozygous tall and a homozygous purple flowered plant is crossed with a short and white flowered plant Predict the offspring Assume independent assortment
1
P=purplep=whiteT=tallt=short
For a plant with the genotype WwXxYyZz what is the probability that the plant will produce a gamete with a haploid genotype of Wxyz Give your answer as a fraction or as a value between 0 and 1 to four decimal places
2
A completely-plated stickleback from a marine population was mated to a low-plated stickleback from a freshwater population The resulting F1 hybrids all displayed a completely plated phenotype When the F1 hybrids were allowed to interbreed the resulting F2 generation included completely plated offspring and low-plated offspring in an approximate 31 ratio Which of the following conclusions is best supported by the results of the breeding experiments
a Phenotypic variation in the F2 generation suggests that armor morphology is controlled by many alleles of a single gene
b The completely-plated phenotype is controlled by a dominant allele of a single gene
c Armor loss is an acquired characteristic that is affected by one or more environmental factors
d Patterns of armor plating in stickleback populations are regulated by sex-specific signals
3
If a man with type AB blood marries a woman with type O what blood types would you expect in their children What fraction would you expect of each type
4
IA= Type AIB= Type Bi= Type O
If a King marries a Queen that is a carrier of hemophilia (sex-linked recessive disease that is historically fatal before adulthood) what is the chance of the Kingdom having an heir to the kingrsquos throne assuming only one child is born
5
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
7 Gregor Mendelrsquos pioneering genetic experiments with pea plants occurred before the discovery of the structure and function of chromosomes Which of the following observations about inheritance in pea plants could be explained only after the discovery that genes may be linked on a chromosome
a Pea color and pea shape display independent inheritance patterns b Offspring of a given cross show all possible combinations of traits in
equal proportions c Most offspring of a given cross have a combination of traits that is
identical to that of either one parent or the other d Recessive phenotypes can skip a generation showing up only in the
parental and F 2 generations
8
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Based on the data in Table I which of the following best explains why there are no individuals with constricted pods in the F 1 generation a Inflated pod shape is dominant to constricted pod shape b The inflated-pod offspring in the F sub one generation are
homozygous c Constricted pod shape typically arises from a new mutation in the F 1
generation d The constricted-pod offspring are carriers for the inflated pod shape
allele
9
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table I the ratio of phenotypes in the offspring from the testcross with F 1 plants that had purple flowers and inflated pods suggests that the genes for flower color and pod shape are located a close together on the same autosome b on the X chromosome c on different chromosomes d on a mitochondrial chromosome
10
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Which of the following provides the best justification for an assumption that might have been used in the computer simulation (Table II) a The broad allele is recessive to the narrow allele because broad
leaves appear in every generation b The purple allele is dominant to the white allele because all the
offspring from the cross of purple-flowered and white-flowered plants had purple flowers
c The narrow allele is codominant with the purple allele because the purple-flower trait and the narrow-leaf trait segregate together
d The white allele is dominant to both the broad and narrow alleles because plants with either type of leaf shape can have white flowers
11
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table II the F 1 offspring of the cross between broad-leaved white-flowered plants with narrow-leaved purple-flowered plants have a phenotype that differs from that of either parent However many testcross offspring have the same phenotype as one of the two plants in the parental cross but relatively few testcross offspring have the same phenotype as the F 1 offspring Which of the following best explains the observation a Recombination between the leaf-shape and flower-color genes resulted in
chromosomes carrying a dominant allele of both genes b Recombination between the broad and narrow alleles of the leaf-shape gene resulted in
chromosomes carrying three different alleles at the same genetic locus c Independent assortment of homologous chromosomes resulted in the combinations of
alleles present in the parental generation d The computer model cannot capture the possible assortments of gametes when
multiple genes are considered
Analysis
1 What is the outcome of mitosis2 What steps of mitosis ensure a perfect
outcome3 If the first cell has 46 chromosomes (before
cloning) how many does each daughter cell have
4 Why do cells go through mitosis
Mitosis Modeling
Words to Knowbull Nucleusbull DNAbull Histonesbull Chromatinbull Chromosomebull Chromatidbull Centromere
Copyright copy 2002 Pearson Education Inc publishing as Benjamin Cummings
Interphase ldquoSrdquo phase
Mitosis
Warm-UP
1Advantages of Sex
2Disadvantages of Sex
AP Test Money DUE 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Thurs Meiosis Wksht
UNIT 78 TEST March 19th
Inheritance and Regulation
Fig 13-2
Bacteria
Parent
Bud
05 mmAsexual Reproduction
Advantages1 Can be done in isolation2 If you are perfect why change
Best when an organism is ldquoperfectlyrdquo suited for its environment
3 Less ldquomachineryrdquo needed no waste on flowers ldquonewrdquo types of cells or other secondary sexual characteristics
Disadvantages1 Less variety Poor option in a
changing environmentPlants
Fig 13-2
Parent
Bud
05 mmAsexual Reproduction
Advantages1 Can be done in isolation2 If you are perfect why change
Best when an organism is ldquoperfectlyrdquo suited for its environment
3 Less ldquomachineryrdquo needed no waste on flowers ldquonewrdquo types of cells or other secondary sexual characteristics
Disadvantages1 Less variety Poor option in a
changing environment
Fig 13-2
Parent
Bud
05 mmAsexual Reproduction
Advantages1 Can be done in isolation2 If you are perfect why change
Best when an organism is ldquoperfectlyrdquo suited for its environment
3 Less ldquomachineryrdquo needed no waste on flowers ldquonewrdquo types of cells or other secondary sexual characteristics
Disadvantages1 Less variety Poor option in a
changing environment
Aspen
Fig 13-1
Sexual ReproductionAdvantages1 Increased variety Best when
environment is changing
Increased Variety is DUE TObull random fertilizationbull meiosis
bull independent assortmentbull crossing-over
Disadvantages1 Resource investment
bull specialized cells gametesbull secondary sexual
characteristics mate attraction2 Requires a partner (except when
plants self-fertilize)
In eukaryotic organisms heritable information is passed to the next generation via mitosis and
meiosisCell Division 2 Types
Meiosis sex cells (gametes) (spermeggs)bull Purpose
ensures that each gamete receives one complete haploid (1n) set of chromosomes
Ensures chromosome number stays the same each offspring receives frac12 (1n) of the full set for the species (2n)
bull Steps1 DNA Replication2 homologous pairs form a tetrad
(independent assortment) (genetic variation increases)
3 cross over between homologous chromosomes may occur (genetic variation increases)
4 Meiosis I homologous pairs separate5 Meiosis II sister chromatids separate
In eukaryotic organisms heritable information is passed to the next generation via mitosis and
meiosisCell Division 2 Types
Meiosis sex cells (gametes) (spermeggs)bull Purpose
ensures that each gamete receives one complete haploid (1n) set of chromosomes
Ensures chromosome number stays the same each offspring receives frac12 (1n) of the full set for the species (2n)
bull Steps1 DNA Replication2 homologous pairs form a tetrad
(independent assortment) (genetic variation increases)
3 cross over between homologous chromosomes may occur (genetic variation increases)
4 Meiosis I homologous pairs separate5 Meiosis II sister chromatids separate
In eukaryotic organisms heritable information is passed to the next generation via mitosis and
meiosisCell Division 2 Types
Meiosis sex cells (gametes) (spermeggs)bull Purpose
ensures that each gamete receives one complete haploid (1n) set of chromosomes
Ensures chromosome number stays the same each offspring receives frac12 (1n) of the full set for the species (2n)
bull Steps1 DNA Replication2 homologous pairs form a tetrad
(independent assortment) (genetic variation increases)
3 cross over between homologous chromosomes may occur (genetic variation increases)
4 Meiosis I homologous pairs separate5 Meiosis II sister chromatids separate
1 Build your diploid cell (an homologous pair for each chromosome)a Draw a big cell with a nucleus insideb Add homologous pairs of chromosomes
bull 1 big white 1 big yellowbull 1 medium white 1 medium yellowbull 1 small white 1 small yellow
2 Clone each chromosome (DNA Replication) (making sister chromatids)3 Nucleus breaks down (erase it)4 Homologous pairs form a tetrad crossing over may occur (note do not model crossing
over for now)5 Homologous pairs separate one to each side of cell all paternal (or all maternal) do NOT
have to go together (independent assortment)6 Cytokinesis cell membrane grows between the 2 halves7 Clones (sister chromatids) separate (centromere ldquobreaksrdquo as DNA polymerization
completes) one to each side of cell8 Cytokinesis cell membrane grows between the 2 halves9 Nucleus grows around chromosomes 4 cells made (gametes which have half the
number of chromosomes (haploids)
Meiosis Modeling
When yoursquore confident on the process show Mr Jones
Meiosis Modelingbull When yoursquore confident on the process show Mr Jones
bull In your notebookTable 138 Stages of Meiosis p255At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid crossing over recombinant chromosome independent assortment Meiosis I Meiosis II
Meiosis Modeling
Analysis
1 What is the outcome of meiosis2 What steps of meiosis cause variation3 If the first cell has 46 chromosomes (before
cloning) how many does each daughter cell have4 How many unique gametes did you form How
many could have formed5 Why do cells go through meiosis
Warm-UP 1 Why do meiosis2 How does meiosis increase variation in organisms
AP Test Money DUE 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Tomorrow Meiosis Wksht
UNIT 78 TEST March 19th
Inheritance and Regulation
Meiosis has multiple processes that increases genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Meiosis has multiple processes that increase genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Meiosis has multiple processes that increase genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Meiosis has multiple processes that increases genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Warm-UP Watch the video What is happening Why does this happen How does this increase variation
AP Test Money DUE TOMORROW 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Tomorrow
UNIT 78 TEST March 19th
Inheritance and Regulation
Fig 13-9a
MITOSIS MEIOSIS
MEIOSIS I
Prophase I
Chiasma
Chromosomereplication
Homologouschromosomepair
Chromosomereplication
2n = 6
Parent cell
Prophase
Replicated chromosome
Metaphase Metaphase I
Anaphase ITelophase I
Haploid n = 3
Daughter cells ofmeiosis I
MEIOSIS II
Daughter cells of meiosis II
nnnn
2n2n
Daughter cellsof mitosis
AnaphaseTelophase
Compare
Contrast
Independent Assortment
Crossing-over Sexual Fertilization Mutation
Types of Changes to Cells Think About what where when how how much variation created
Warm-UP Now we need to keep track of the genes on the chromosomes that are inherited Notice the letters on the chromosomes They represent different alleles for Huntingtons Barbie has Huntingtons What is the chance her child will get Huntingtons
AP Test Money DUE 36 TOMORROWRemember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Tomorrow 141 5 Key Ideas AND Concept Check 1-3
H=dominant (remember Huntingtonrsquos is dominant)
h=recessive (no Huntingtonrsquos)
Homework DUE Monday Test Corrections for 10 Make-UP
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
AP Test Money DUE 36 TODAYRemember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
DUE next Thursday Monohybrid Crosses
Homework DUE Monday Test Corrections for 10 Make-UP
Warm-UP Now we need to keep track of TWO UNLINKED genes on the chromosomes that are inherited Notice the letters on the chromosomes They represent different alleles for Huntingtons and red hair color Barbie has Huntingtons and is a blond (but a carrier) Ken does not have Huntingtonrsquos and is also a carrier for red hair What is the chance their child will get Huntingtons and red hair
Homework DUE Tomorrow 142 5 Key Ideas AND Concept Check 1-3
H= Huntingtonrsquosh=no HuntingtonrsquosR= no red hairr= red hair
DUE Now Test Corrections for 10 Make-UP
UNIT 78 TEST March 19th
Inheritance and Regulation
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
Homework DUE Tomorrow 143 5 Key Ideas AND Concept Check 1-3
DUE Now 142DUE Thursday Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
UNIT 78 TEST March 19th
Inheritance and Regulation
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoods
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with RrYy
1 Chance of baby with Rr 052 Chance of baby with Yy 053 Chance of baby with RrYy 025
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with both dominant phenotypes
1 Chance of baby with at least one R 0752 Chance of baby with at least one Y 0753 Chance of baby with RrYy 05625 (916)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with both dominant phenotypes
1 Chance of baby with at least one R 10
2 Chance of baby with at least one Y 10
3 Chance of baby with both dominant phenotypes 10
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
Homework DUE Tomorrow Linked vs Unlinked Genes AND Monohybrid Crosses to tunritincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with
vestigial wings and cinnabar eyes Predict the phenotypic ratio of the F2 individuals
Homework DUE Tomorrow 153 5 Key Ideas and Concept Check 1-3DUE Thursday Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with vestigial wings and cinnabar eyes Predict the
phenotypic ratio of the F2 individuals
3 The results of the cross from 2 show the following outcome Individuals of each phenotype are shown in the table Which of the following is the most likely explanation of the results a The two genes are located on two different chromosomes b The two genes are sex-linked c The two genes are located on mitochondrial DNA d The two genes are linked on an autosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
1 Build your diploid cell (an homologous pair for each chromosome)a Draw a big cell with a nucleus insideb DRAW homologous pairs of chromosomes
bull 1 big blue 1 big redbull 1 small blue 1 small red
ndash Add genes to your chromosomebull Write an H and an R on big blue and an h and an r on big redbull Write a T on small blue and a t on small red
2 Clone each chromosome (DNA Replication) (making sister chromatids)3 Nucleus breaks down (erase it)4 Homologous pairs form a tetrad crossing over may occur (note do not model
crossing over for now)5 Finish meiosis (see notes for help)6 Nucleus grows around chromosomes 4 cells made (gametes which have half
the number of chromosomes (haploids)7 Repeat Steps 1-6 this time at Step 4 include ONE crossover event
Recombination Modeling
When yoursquore confident on the process show Mr Jones
bull When yoursquore confident on the process show Mr Jones
bull In your notebookFigure 1510 Recombination p295At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid crossing over recombinant chromosome independent assortment Meiosis I Meiosis II
Recombination Modeling
Analysis
1 How does recombination increase the variety of gametes formed
2 Which types of gametes were more likely Gametes with recombinant chromosomes or ones without
3 Recombination is a random process How might it benefithurt the survival of an individualspecies
Recombination Modeling
Warm-UP
1 How could you calculate recombination frequency2 What would the recombination frequency tell you about the relative position of
genes on a chromosome3 Genes A B and C are on the same chromosome Testcrosses show that the
recombination frequency between A and B is 28 and between A and C is 12 Can you determine the linear order of these genes
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP What can we learn about inheritance from looking at a pedigree (use example of the Royal Family of Europe from the early 1900s)
Warm-UP In the following human pedigree squares represent males circles represent females and shaded symbols indicate individuals affected with a disorder One of the affected males from the third generation has a child with a female who is a carrier For the pedigree shown which of the following best expresses the probability that the couplersquos first son will be affected with the disorder
(A) 25 (B) 50 (C) 75 (D) 100
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Is a widowrsquos peak a dominant or recessive trait
Is a widowrsquos peak a dominant or recessive trait
Fig 14-UN5
George
Sandra Tom Sam
Arlene
Wilma Ann Michael
Carla
Daniel Alan Tina
Christopher
A heterozygous tall and a homozygous purple flowered plant is crossed with a short and white flowered plant Predict the offspring Assume independent assortment
1
P=purplep=whiteT=tallt=short
For a plant with the genotype WwXxYyZz what is the probability that the plant will produce a gamete with a haploid genotype of Wxyz Give your answer as a fraction or as a value between 0 and 1 to four decimal places
2
A completely-plated stickleback from a marine population was mated to a low-plated stickleback from a freshwater population The resulting F1 hybrids all displayed a completely plated phenotype When the F1 hybrids were allowed to interbreed the resulting F2 generation included completely plated offspring and low-plated offspring in an approximate 31 ratio Which of the following conclusions is best supported by the results of the breeding experiments
a Phenotypic variation in the F2 generation suggests that armor morphology is controlled by many alleles of a single gene
b The completely-plated phenotype is controlled by a dominant allele of a single gene
c Armor loss is an acquired characteristic that is affected by one or more environmental factors
d Patterns of armor plating in stickleback populations are regulated by sex-specific signals
3
If a man with type AB blood marries a woman with type O what blood types would you expect in their children What fraction would you expect of each type
4
IA= Type AIB= Type Bi= Type O
If a King marries a Queen that is a carrier of hemophilia (sex-linked recessive disease that is historically fatal before adulthood) what is the chance of the Kingdom having an heir to the kingrsquos throne assuming only one child is born
5
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
7 Gregor Mendelrsquos pioneering genetic experiments with pea plants occurred before the discovery of the structure and function of chromosomes Which of the following observations about inheritance in pea plants could be explained only after the discovery that genes may be linked on a chromosome
a Pea color and pea shape display independent inheritance patterns b Offspring of a given cross show all possible combinations of traits in
equal proportions c Most offspring of a given cross have a combination of traits that is
identical to that of either one parent or the other d Recessive phenotypes can skip a generation showing up only in the
parental and F 2 generations
8
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Based on the data in Table I which of the following best explains why there are no individuals with constricted pods in the F 1 generation a Inflated pod shape is dominant to constricted pod shape b The inflated-pod offspring in the F sub one generation are
homozygous c Constricted pod shape typically arises from a new mutation in the F 1
generation d The constricted-pod offspring are carriers for the inflated pod shape
allele
9
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table I the ratio of phenotypes in the offspring from the testcross with F 1 plants that had purple flowers and inflated pods suggests that the genes for flower color and pod shape are located a close together on the same autosome b on the X chromosome c on different chromosomes d on a mitochondrial chromosome
10
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Which of the following provides the best justification for an assumption that might have been used in the computer simulation (Table II) a The broad allele is recessive to the narrow allele because broad
leaves appear in every generation b The purple allele is dominant to the white allele because all the
offspring from the cross of purple-flowered and white-flowered plants had purple flowers
c The narrow allele is codominant with the purple allele because the purple-flower trait and the narrow-leaf trait segregate together
d The white allele is dominant to both the broad and narrow alleles because plants with either type of leaf shape can have white flowers
11
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table II the F 1 offspring of the cross between broad-leaved white-flowered plants with narrow-leaved purple-flowered plants have a phenotype that differs from that of either parent However many testcross offspring have the same phenotype as one of the two plants in the parental cross but relatively few testcross offspring have the same phenotype as the F 1 offspring Which of the following best explains the observation a Recombination between the leaf-shape and flower-color genes resulted in
chromosomes carrying a dominant allele of both genes b Recombination between the broad and narrow alleles of the leaf-shape gene resulted in
chromosomes carrying three different alleles at the same genetic locus c Independent assortment of homologous chromosomes resulted in the combinations of
alleles present in the parental generation d The computer model cannot capture the possible assortments of gametes when
multiple genes are considered
Words to Knowbull Nucleusbull DNAbull Histonesbull Chromatinbull Chromosomebull Chromatidbull Centromere
Copyright copy 2002 Pearson Education Inc publishing as Benjamin Cummings
Interphase ldquoSrdquo phase
Mitosis
Warm-UP
1Advantages of Sex
2Disadvantages of Sex
AP Test Money DUE 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Thurs Meiosis Wksht
UNIT 78 TEST March 19th
Inheritance and Regulation
Fig 13-2
Bacteria
Parent
Bud
05 mmAsexual Reproduction
Advantages1 Can be done in isolation2 If you are perfect why change
Best when an organism is ldquoperfectlyrdquo suited for its environment
3 Less ldquomachineryrdquo needed no waste on flowers ldquonewrdquo types of cells or other secondary sexual characteristics
Disadvantages1 Less variety Poor option in a
changing environmentPlants
Fig 13-2
Parent
Bud
05 mmAsexual Reproduction
Advantages1 Can be done in isolation2 If you are perfect why change
Best when an organism is ldquoperfectlyrdquo suited for its environment
3 Less ldquomachineryrdquo needed no waste on flowers ldquonewrdquo types of cells or other secondary sexual characteristics
Disadvantages1 Less variety Poor option in a
changing environment
Fig 13-2
Parent
Bud
05 mmAsexual Reproduction
Advantages1 Can be done in isolation2 If you are perfect why change
Best when an organism is ldquoperfectlyrdquo suited for its environment
3 Less ldquomachineryrdquo needed no waste on flowers ldquonewrdquo types of cells or other secondary sexual characteristics
Disadvantages1 Less variety Poor option in a
changing environment
Aspen
Fig 13-1
Sexual ReproductionAdvantages1 Increased variety Best when
environment is changing
Increased Variety is DUE TObull random fertilizationbull meiosis
bull independent assortmentbull crossing-over
Disadvantages1 Resource investment
bull specialized cells gametesbull secondary sexual
characteristics mate attraction2 Requires a partner (except when
plants self-fertilize)
In eukaryotic organisms heritable information is passed to the next generation via mitosis and
meiosisCell Division 2 Types
Meiosis sex cells (gametes) (spermeggs)bull Purpose
ensures that each gamete receives one complete haploid (1n) set of chromosomes
Ensures chromosome number stays the same each offspring receives frac12 (1n) of the full set for the species (2n)
bull Steps1 DNA Replication2 homologous pairs form a tetrad
(independent assortment) (genetic variation increases)
3 cross over between homologous chromosomes may occur (genetic variation increases)
4 Meiosis I homologous pairs separate5 Meiosis II sister chromatids separate
In eukaryotic organisms heritable information is passed to the next generation via mitosis and
meiosisCell Division 2 Types
Meiosis sex cells (gametes) (spermeggs)bull Purpose
ensures that each gamete receives one complete haploid (1n) set of chromosomes
Ensures chromosome number stays the same each offspring receives frac12 (1n) of the full set for the species (2n)
bull Steps1 DNA Replication2 homologous pairs form a tetrad
(independent assortment) (genetic variation increases)
3 cross over between homologous chromosomes may occur (genetic variation increases)
4 Meiosis I homologous pairs separate5 Meiosis II sister chromatids separate
In eukaryotic organisms heritable information is passed to the next generation via mitosis and
meiosisCell Division 2 Types
Meiosis sex cells (gametes) (spermeggs)bull Purpose
ensures that each gamete receives one complete haploid (1n) set of chromosomes
Ensures chromosome number stays the same each offspring receives frac12 (1n) of the full set for the species (2n)
bull Steps1 DNA Replication2 homologous pairs form a tetrad
(independent assortment) (genetic variation increases)
3 cross over between homologous chromosomes may occur (genetic variation increases)
4 Meiosis I homologous pairs separate5 Meiosis II sister chromatids separate
1 Build your diploid cell (an homologous pair for each chromosome)a Draw a big cell with a nucleus insideb Add homologous pairs of chromosomes
bull 1 big white 1 big yellowbull 1 medium white 1 medium yellowbull 1 small white 1 small yellow
2 Clone each chromosome (DNA Replication) (making sister chromatids)3 Nucleus breaks down (erase it)4 Homologous pairs form a tetrad crossing over may occur (note do not model crossing
over for now)5 Homologous pairs separate one to each side of cell all paternal (or all maternal) do NOT
have to go together (independent assortment)6 Cytokinesis cell membrane grows between the 2 halves7 Clones (sister chromatids) separate (centromere ldquobreaksrdquo as DNA polymerization
completes) one to each side of cell8 Cytokinesis cell membrane grows between the 2 halves9 Nucleus grows around chromosomes 4 cells made (gametes which have half the
number of chromosomes (haploids)
Meiosis Modeling
When yoursquore confident on the process show Mr Jones
Meiosis Modelingbull When yoursquore confident on the process show Mr Jones
bull In your notebookTable 138 Stages of Meiosis p255At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid crossing over recombinant chromosome independent assortment Meiosis I Meiosis II
Meiosis Modeling
Analysis
1 What is the outcome of meiosis2 What steps of meiosis cause variation3 If the first cell has 46 chromosomes (before
cloning) how many does each daughter cell have4 How many unique gametes did you form How
many could have formed5 Why do cells go through meiosis
Warm-UP 1 Why do meiosis2 How does meiosis increase variation in organisms
AP Test Money DUE 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Tomorrow Meiosis Wksht
UNIT 78 TEST March 19th
Inheritance and Regulation
Meiosis has multiple processes that increases genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Meiosis has multiple processes that increase genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Meiosis has multiple processes that increase genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Meiosis has multiple processes that increases genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Warm-UP Watch the video What is happening Why does this happen How does this increase variation
AP Test Money DUE TOMORROW 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Tomorrow
UNIT 78 TEST March 19th
Inheritance and Regulation
Fig 13-9a
MITOSIS MEIOSIS
MEIOSIS I
Prophase I
Chiasma
Chromosomereplication
Homologouschromosomepair
Chromosomereplication
2n = 6
Parent cell
Prophase
Replicated chromosome
Metaphase Metaphase I
Anaphase ITelophase I
Haploid n = 3
Daughter cells ofmeiosis I
MEIOSIS II
Daughter cells of meiosis II
nnnn
2n2n
Daughter cellsof mitosis
AnaphaseTelophase
Compare
Contrast
Independent Assortment
Crossing-over Sexual Fertilization Mutation
Types of Changes to Cells Think About what where when how how much variation created
Warm-UP Now we need to keep track of the genes on the chromosomes that are inherited Notice the letters on the chromosomes They represent different alleles for Huntingtons Barbie has Huntingtons What is the chance her child will get Huntingtons
AP Test Money DUE 36 TOMORROWRemember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Tomorrow 141 5 Key Ideas AND Concept Check 1-3
H=dominant (remember Huntingtonrsquos is dominant)
h=recessive (no Huntingtonrsquos)
Homework DUE Monday Test Corrections for 10 Make-UP
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
AP Test Money DUE 36 TODAYRemember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
DUE next Thursday Monohybrid Crosses
Homework DUE Monday Test Corrections for 10 Make-UP
Warm-UP Now we need to keep track of TWO UNLINKED genes on the chromosomes that are inherited Notice the letters on the chromosomes They represent different alleles for Huntingtons and red hair color Barbie has Huntingtons and is a blond (but a carrier) Ken does not have Huntingtonrsquos and is also a carrier for red hair What is the chance their child will get Huntingtons and red hair
Homework DUE Tomorrow 142 5 Key Ideas AND Concept Check 1-3
H= Huntingtonrsquosh=no HuntingtonrsquosR= no red hairr= red hair
DUE Now Test Corrections for 10 Make-UP
UNIT 78 TEST March 19th
Inheritance and Regulation
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
Homework DUE Tomorrow 143 5 Key Ideas AND Concept Check 1-3
DUE Now 142DUE Thursday Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
UNIT 78 TEST March 19th
Inheritance and Regulation
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoods
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with RrYy
1 Chance of baby with Rr 052 Chance of baby with Yy 053 Chance of baby with RrYy 025
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with both dominant phenotypes
1 Chance of baby with at least one R 0752 Chance of baby with at least one Y 0753 Chance of baby with RrYy 05625 (916)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with both dominant phenotypes
1 Chance of baby with at least one R 10
2 Chance of baby with at least one Y 10
3 Chance of baby with both dominant phenotypes 10
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
Homework DUE Tomorrow Linked vs Unlinked Genes AND Monohybrid Crosses to tunritincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with
vestigial wings and cinnabar eyes Predict the phenotypic ratio of the F2 individuals
Homework DUE Tomorrow 153 5 Key Ideas and Concept Check 1-3DUE Thursday Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with vestigial wings and cinnabar eyes Predict the
phenotypic ratio of the F2 individuals
3 The results of the cross from 2 show the following outcome Individuals of each phenotype are shown in the table Which of the following is the most likely explanation of the results a The two genes are located on two different chromosomes b The two genes are sex-linked c The two genes are located on mitochondrial DNA d The two genes are linked on an autosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
1 Build your diploid cell (an homologous pair for each chromosome)a Draw a big cell with a nucleus insideb DRAW homologous pairs of chromosomes
bull 1 big blue 1 big redbull 1 small blue 1 small red
ndash Add genes to your chromosomebull Write an H and an R on big blue and an h and an r on big redbull Write a T on small blue and a t on small red
2 Clone each chromosome (DNA Replication) (making sister chromatids)3 Nucleus breaks down (erase it)4 Homologous pairs form a tetrad crossing over may occur (note do not model
crossing over for now)5 Finish meiosis (see notes for help)6 Nucleus grows around chromosomes 4 cells made (gametes which have half
the number of chromosomes (haploids)7 Repeat Steps 1-6 this time at Step 4 include ONE crossover event
Recombination Modeling
When yoursquore confident on the process show Mr Jones
bull When yoursquore confident on the process show Mr Jones
bull In your notebookFigure 1510 Recombination p295At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid crossing over recombinant chromosome independent assortment Meiosis I Meiosis II
Recombination Modeling
Analysis
1 How does recombination increase the variety of gametes formed
2 Which types of gametes were more likely Gametes with recombinant chromosomes or ones without
3 Recombination is a random process How might it benefithurt the survival of an individualspecies
Recombination Modeling
Warm-UP
1 How could you calculate recombination frequency2 What would the recombination frequency tell you about the relative position of
genes on a chromosome3 Genes A B and C are on the same chromosome Testcrosses show that the
recombination frequency between A and B is 28 and between A and C is 12 Can you determine the linear order of these genes
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP What can we learn about inheritance from looking at a pedigree (use example of the Royal Family of Europe from the early 1900s)
Warm-UP In the following human pedigree squares represent males circles represent females and shaded symbols indicate individuals affected with a disorder One of the affected males from the third generation has a child with a female who is a carrier For the pedigree shown which of the following best expresses the probability that the couplersquos first son will be affected with the disorder
(A) 25 (B) 50 (C) 75 (D) 100
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Is a widowrsquos peak a dominant or recessive trait
Is a widowrsquos peak a dominant or recessive trait
Fig 14-UN5
George
Sandra Tom Sam
Arlene
Wilma Ann Michael
Carla
Daniel Alan Tina
Christopher
A heterozygous tall and a homozygous purple flowered plant is crossed with a short and white flowered plant Predict the offspring Assume independent assortment
1
P=purplep=whiteT=tallt=short
For a plant with the genotype WwXxYyZz what is the probability that the plant will produce a gamete with a haploid genotype of Wxyz Give your answer as a fraction or as a value between 0 and 1 to four decimal places
2
A completely-plated stickleback from a marine population was mated to a low-plated stickleback from a freshwater population The resulting F1 hybrids all displayed a completely plated phenotype When the F1 hybrids were allowed to interbreed the resulting F2 generation included completely plated offspring and low-plated offspring in an approximate 31 ratio Which of the following conclusions is best supported by the results of the breeding experiments
a Phenotypic variation in the F2 generation suggests that armor morphology is controlled by many alleles of a single gene
b The completely-plated phenotype is controlled by a dominant allele of a single gene
c Armor loss is an acquired characteristic that is affected by one or more environmental factors
d Patterns of armor plating in stickleback populations are regulated by sex-specific signals
3
If a man with type AB blood marries a woman with type O what blood types would you expect in their children What fraction would you expect of each type
4
IA= Type AIB= Type Bi= Type O
If a King marries a Queen that is a carrier of hemophilia (sex-linked recessive disease that is historically fatal before adulthood) what is the chance of the Kingdom having an heir to the kingrsquos throne assuming only one child is born
5
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
7 Gregor Mendelrsquos pioneering genetic experiments with pea plants occurred before the discovery of the structure and function of chromosomes Which of the following observations about inheritance in pea plants could be explained only after the discovery that genes may be linked on a chromosome
a Pea color and pea shape display independent inheritance patterns b Offspring of a given cross show all possible combinations of traits in
equal proportions c Most offspring of a given cross have a combination of traits that is
identical to that of either one parent or the other d Recessive phenotypes can skip a generation showing up only in the
parental and F 2 generations
8
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Based on the data in Table I which of the following best explains why there are no individuals with constricted pods in the F 1 generation a Inflated pod shape is dominant to constricted pod shape b The inflated-pod offspring in the F sub one generation are
homozygous c Constricted pod shape typically arises from a new mutation in the F 1
generation d The constricted-pod offspring are carriers for the inflated pod shape
allele
9
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table I the ratio of phenotypes in the offspring from the testcross with F 1 plants that had purple flowers and inflated pods suggests that the genes for flower color and pod shape are located a close together on the same autosome b on the X chromosome c on different chromosomes d on a mitochondrial chromosome
10
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Which of the following provides the best justification for an assumption that might have been used in the computer simulation (Table II) a The broad allele is recessive to the narrow allele because broad
leaves appear in every generation b The purple allele is dominant to the white allele because all the
offspring from the cross of purple-flowered and white-flowered plants had purple flowers
c The narrow allele is codominant with the purple allele because the purple-flower trait and the narrow-leaf trait segregate together
d The white allele is dominant to both the broad and narrow alleles because plants with either type of leaf shape can have white flowers
11
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table II the F 1 offspring of the cross between broad-leaved white-flowered plants with narrow-leaved purple-flowered plants have a phenotype that differs from that of either parent However many testcross offspring have the same phenotype as one of the two plants in the parental cross but relatively few testcross offspring have the same phenotype as the F 1 offspring Which of the following best explains the observation a Recombination between the leaf-shape and flower-color genes resulted in
chromosomes carrying a dominant allele of both genes b Recombination between the broad and narrow alleles of the leaf-shape gene resulted in
chromosomes carrying three different alleles at the same genetic locus c Independent assortment of homologous chromosomes resulted in the combinations of
alleles present in the parental generation d The computer model cannot capture the possible assortments of gametes when
multiple genes are considered
Warm-UP
1Advantages of Sex
2Disadvantages of Sex
AP Test Money DUE 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Thurs Meiosis Wksht
UNIT 78 TEST March 19th
Inheritance and Regulation
Fig 13-2
Bacteria
Parent
Bud
05 mmAsexual Reproduction
Advantages1 Can be done in isolation2 If you are perfect why change
Best when an organism is ldquoperfectlyrdquo suited for its environment
3 Less ldquomachineryrdquo needed no waste on flowers ldquonewrdquo types of cells or other secondary sexual characteristics
Disadvantages1 Less variety Poor option in a
changing environmentPlants
Fig 13-2
Parent
Bud
05 mmAsexual Reproduction
Advantages1 Can be done in isolation2 If you are perfect why change
Best when an organism is ldquoperfectlyrdquo suited for its environment
3 Less ldquomachineryrdquo needed no waste on flowers ldquonewrdquo types of cells or other secondary sexual characteristics
Disadvantages1 Less variety Poor option in a
changing environment
Fig 13-2
Parent
Bud
05 mmAsexual Reproduction
Advantages1 Can be done in isolation2 If you are perfect why change
Best when an organism is ldquoperfectlyrdquo suited for its environment
3 Less ldquomachineryrdquo needed no waste on flowers ldquonewrdquo types of cells or other secondary sexual characteristics
Disadvantages1 Less variety Poor option in a
changing environment
Aspen
Fig 13-1
Sexual ReproductionAdvantages1 Increased variety Best when
environment is changing
Increased Variety is DUE TObull random fertilizationbull meiosis
bull independent assortmentbull crossing-over
Disadvantages1 Resource investment
bull specialized cells gametesbull secondary sexual
characteristics mate attraction2 Requires a partner (except when
plants self-fertilize)
In eukaryotic organisms heritable information is passed to the next generation via mitosis and
meiosisCell Division 2 Types
Meiosis sex cells (gametes) (spermeggs)bull Purpose
ensures that each gamete receives one complete haploid (1n) set of chromosomes
Ensures chromosome number stays the same each offspring receives frac12 (1n) of the full set for the species (2n)
bull Steps1 DNA Replication2 homologous pairs form a tetrad
(independent assortment) (genetic variation increases)
3 cross over between homologous chromosomes may occur (genetic variation increases)
4 Meiosis I homologous pairs separate5 Meiosis II sister chromatids separate
In eukaryotic organisms heritable information is passed to the next generation via mitosis and
meiosisCell Division 2 Types
Meiosis sex cells (gametes) (spermeggs)bull Purpose
ensures that each gamete receives one complete haploid (1n) set of chromosomes
Ensures chromosome number stays the same each offspring receives frac12 (1n) of the full set for the species (2n)
bull Steps1 DNA Replication2 homologous pairs form a tetrad
(independent assortment) (genetic variation increases)
3 cross over between homologous chromosomes may occur (genetic variation increases)
4 Meiosis I homologous pairs separate5 Meiosis II sister chromatids separate
In eukaryotic organisms heritable information is passed to the next generation via mitosis and
meiosisCell Division 2 Types
Meiosis sex cells (gametes) (spermeggs)bull Purpose
ensures that each gamete receives one complete haploid (1n) set of chromosomes
Ensures chromosome number stays the same each offspring receives frac12 (1n) of the full set for the species (2n)
bull Steps1 DNA Replication2 homologous pairs form a tetrad
(independent assortment) (genetic variation increases)
3 cross over between homologous chromosomes may occur (genetic variation increases)
4 Meiosis I homologous pairs separate5 Meiosis II sister chromatids separate
1 Build your diploid cell (an homologous pair for each chromosome)a Draw a big cell with a nucleus insideb Add homologous pairs of chromosomes
bull 1 big white 1 big yellowbull 1 medium white 1 medium yellowbull 1 small white 1 small yellow
2 Clone each chromosome (DNA Replication) (making sister chromatids)3 Nucleus breaks down (erase it)4 Homologous pairs form a tetrad crossing over may occur (note do not model crossing
over for now)5 Homologous pairs separate one to each side of cell all paternal (or all maternal) do NOT
have to go together (independent assortment)6 Cytokinesis cell membrane grows between the 2 halves7 Clones (sister chromatids) separate (centromere ldquobreaksrdquo as DNA polymerization
completes) one to each side of cell8 Cytokinesis cell membrane grows between the 2 halves9 Nucleus grows around chromosomes 4 cells made (gametes which have half the
number of chromosomes (haploids)
Meiosis Modeling
When yoursquore confident on the process show Mr Jones
Meiosis Modelingbull When yoursquore confident on the process show Mr Jones
bull In your notebookTable 138 Stages of Meiosis p255At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid crossing over recombinant chromosome independent assortment Meiosis I Meiosis II
Meiosis Modeling
Analysis
1 What is the outcome of meiosis2 What steps of meiosis cause variation3 If the first cell has 46 chromosomes (before
cloning) how many does each daughter cell have4 How many unique gametes did you form How
many could have formed5 Why do cells go through meiosis
Warm-UP 1 Why do meiosis2 How does meiosis increase variation in organisms
AP Test Money DUE 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Tomorrow Meiosis Wksht
UNIT 78 TEST March 19th
Inheritance and Regulation
Meiosis has multiple processes that increases genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Meiosis has multiple processes that increase genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Meiosis has multiple processes that increase genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Meiosis has multiple processes that increases genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Warm-UP Watch the video What is happening Why does this happen How does this increase variation
AP Test Money DUE TOMORROW 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Tomorrow
UNIT 78 TEST March 19th
Inheritance and Regulation
Fig 13-9a
MITOSIS MEIOSIS
MEIOSIS I
Prophase I
Chiasma
Chromosomereplication
Homologouschromosomepair
Chromosomereplication
2n = 6
Parent cell
Prophase
Replicated chromosome
Metaphase Metaphase I
Anaphase ITelophase I
Haploid n = 3
Daughter cells ofmeiosis I
MEIOSIS II
Daughter cells of meiosis II
nnnn
2n2n
Daughter cellsof mitosis
AnaphaseTelophase
Compare
Contrast
Independent Assortment
Crossing-over Sexual Fertilization Mutation
Types of Changes to Cells Think About what where when how how much variation created
Warm-UP Now we need to keep track of the genes on the chromosomes that are inherited Notice the letters on the chromosomes They represent different alleles for Huntingtons Barbie has Huntingtons What is the chance her child will get Huntingtons
AP Test Money DUE 36 TOMORROWRemember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Tomorrow 141 5 Key Ideas AND Concept Check 1-3
H=dominant (remember Huntingtonrsquos is dominant)
h=recessive (no Huntingtonrsquos)
Homework DUE Monday Test Corrections for 10 Make-UP
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
AP Test Money DUE 36 TODAYRemember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
DUE next Thursday Monohybrid Crosses
Homework DUE Monday Test Corrections for 10 Make-UP
Warm-UP Now we need to keep track of TWO UNLINKED genes on the chromosomes that are inherited Notice the letters on the chromosomes They represent different alleles for Huntingtons and red hair color Barbie has Huntingtons and is a blond (but a carrier) Ken does not have Huntingtonrsquos and is also a carrier for red hair What is the chance their child will get Huntingtons and red hair
Homework DUE Tomorrow 142 5 Key Ideas AND Concept Check 1-3
H= Huntingtonrsquosh=no HuntingtonrsquosR= no red hairr= red hair
DUE Now Test Corrections for 10 Make-UP
UNIT 78 TEST March 19th
Inheritance and Regulation
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
Homework DUE Tomorrow 143 5 Key Ideas AND Concept Check 1-3
DUE Now 142DUE Thursday Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
UNIT 78 TEST March 19th
Inheritance and Regulation
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoods
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with RrYy
1 Chance of baby with Rr 052 Chance of baby with Yy 053 Chance of baby with RrYy 025
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with both dominant phenotypes
1 Chance of baby with at least one R 0752 Chance of baby with at least one Y 0753 Chance of baby with RrYy 05625 (916)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with both dominant phenotypes
1 Chance of baby with at least one R 10
2 Chance of baby with at least one Y 10
3 Chance of baby with both dominant phenotypes 10
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
Homework DUE Tomorrow Linked vs Unlinked Genes AND Monohybrid Crosses to tunritincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with
vestigial wings and cinnabar eyes Predict the phenotypic ratio of the F2 individuals
Homework DUE Tomorrow 153 5 Key Ideas and Concept Check 1-3DUE Thursday Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with vestigial wings and cinnabar eyes Predict the
phenotypic ratio of the F2 individuals
3 The results of the cross from 2 show the following outcome Individuals of each phenotype are shown in the table Which of the following is the most likely explanation of the results a The two genes are located on two different chromosomes b The two genes are sex-linked c The two genes are located on mitochondrial DNA d The two genes are linked on an autosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
1 Build your diploid cell (an homologous pair for each chromosome)a Draw a big cell with a nucleus insideb DRAW homologous pairs of chromosomes
bull 1 big blue 1 big redbull 1 small blue 1 small red
ndash Add genes to your chromosomebull Write an H and an R on big blue and an h and an r on big redbull Write a T on small blue and a t on small red
2 Clone each chromosome (DNA Replication) (making sister chromatids)3 Nucleus breaks down (erase it)4 Homologous pairs form a tetrad crossing over may occur (note do not model
crossing over for now)5 Finish meiosis (see notes for help)6 Nucleus grows around chromosomes 4 cells made (gametes which have half
the number of chromosomes (haploids)7 Repeat Steps 1-6 this time at Step 4 include ONE crossover event
Recombination Modeling
When yoursquore confident on the process show Mr Jones
bull When yoursquore confident on the process show Mr Jones
bull In your notebookFigure 1510 Recombination p295At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid crossing over recombinant chromosome independent assortment Meiosis I Meiosis II
Recombination Modeling
Analysis
1 How does recombination increase the variety of gametes formed
2 Which types of gametes were more likely Gametes with recombinant chromosomes or ones without
3 Recombination is a random process How might it benefithurt the survival of an individualspecies
Recombination Modeling
Warm-UP
1 How could you calculate recombination frequency2 What would the recombination frequency tell you about the relative position of
genes on a chromosome3 Genes A B and C are on the same chromosome Testcrosses show that the
recombination frequency between A and B is 28 and between A and C is 12 Can you determine the linear order of these genes
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP What can we learn about inheritance from looking at a pedigree (use example of the Royal Family of Europe from the early 1900s)
Warm-UP In the following human pedigree squares represent males circles represent females and shaded symbols indicate individuals affected with a disorder One of the affected males from the third generation has a child with a female who is a carrier For the pedigree shown which of the following best expresses the probability that the couplersquos first son will be affected with the disorder
(A) 25 (B) 50 (C) 75 (D) 100
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Is a widowrsquos peak a dominant or recessive trait
Is a widowrsquos peak a dominant or recessive trait
Fig 14-UN5
George
Sandra Tom Sam
Arlene
Wilma Ann Michael
Carla
Daniel Alan Tina
Christopher
A heterozygous tall and a homozygous purple flowered plant is crossed with a short and white flowered plant Predict the offspring Assume independent assortment
1
P=purplep=whiteT=tallt=short
For a plant with the genotype WwXxYyZz what is the probability that the plant will produce a gamete with a haploid genotype of Wxyz Give your answer as a fraction or as a value between 0 and 1 to four decimal places
2
A completely-plated stickleback from a marine population was mated to a low-plated stickleback from a freshwater population The resulting F1 hybrids all displayed a completely plated phenotype When the F1 hybrids were allowed to interbreed the resulting F2 generation included completely plated offspring and low-plated offspring in an approximate 31 ratio Which of the following conclusions is best supported by the results of the breeding experiments
a Phenotypic variation in the F2 generation suggests that armor morphology is controlled by many alleles of a single gene
b The completely-plated phenotype is controlled by a dominant allele of a single gene
c Armor loss is an acquired characteristic that is affected by one or more environmental factors
d Patterns of armor plating in stickleback populations are regulated by sex-specific signals
3
If a man with type AB blood marries a woman with type O what blood types would you expect in their children What fraction would you expect of each type
4
IA= Type AIB= Type Bi= Type O
If a King marries a Queen that is a carrier of hemophilia (sex-linked recessive disease that is historically fatal before adulthood) what is the chance of the Kingdom having an heir to the kingrsquos throne assuming only one child is born
5
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
7 Gregor Mendelrsquos pioneering genetic experiments with pea plants occurred before the discovery of the structure and function of chromosomes Which of the following observations about inheritance in pea plants could be explained only after the discovery that genes may be linked on a chromosome
a Pea color and pea shape display independent inheritance patterns b Offspring of a given cross show all possible combinations of traits in
equal proportions c Most offspring of a given cross have a combination of traits that is
identical to that of either one parent or the other d Recessive phenotypes can skip a generation showing up only in the
parental and F 2 generations
8
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Based on the data in Table I which of the following best explains why there are no individuals with constricted pods in the F 1 generation a Inflated pod shape is dominant to constricted pod shape b The inflated-pod offspring in the F sub one generation are
homozygous c Constricted pod shape typically arises from a new mutation in the F 1
generation d The constricted-pod offspring are carriers for the inflated pod shape
allele
9
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table I the ratio of phenotypes in the offspring from the testcross with F 1 plants that had purple flowers and inflated pods suggests that the genes for flower color and pod shape are located a close together on the same autosome b on the X chromosome c on different chromosomes d on a mitochondrial chromosome
10
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Which of the following provides the best justification for an assumption that might have been used in the computer simulation (Table II) a The broad allele is recessive to the narrow allele because broad
leaves appear in every generation b The purple allele is dominant to the white allele because all the
offspring from the cross of purple-flowered and white-flowered plants had purple flowers
c The narrow allele is codominant with the purple allele because the purple-flower trait and the narrow-leaf trait segregate together
d The white allele is dominant to both the broad and narrow alleles because plants with either type of leaf shape can have white flowers
11
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table II the F 1 offspring of the cross between broad-leaved white-flowered plants with narrow-leaved purple-flowered plants have a phenotype that differs from that of either parent However many testcross offspring have the same phenotype as one of the two plants in the parental cross but relatively few testcross offspring have the same phenotype as the F 1 offspring Which of the following best explains the observation a Recombination between the leaf-shape and flower-color genes resulted in
chromosomes carrying a dominant allele of both genes b Recombination between the broad and narrow alleles of the leaf-shape gene resulted in
chromosomes carrying three different alleles at the same genetic locus c Independent assortment of homologous chromosomes resulted in the combinations of
alleles present in the parental generation d The computer model cannot capture the possible assortments of gametes when
multiple genes are considered
Fig 13-2
Bacteria
Parent
Bud
05 mmAsexual Reproduction
Advantages1 Can be done in isolation2 If you are perfect why change
Best when an organism is ldquoperfectlyrdquo suited for its environment
3 Less ldquomachineryrdquo needed no waste on flowers ldquonewrdquo types of cells or other secondary sexual characteristics
Disadvantages1 Less variety Poor option in a
changing environmentPlants
Fig 13-2
Parent
Bud
05 mmAsexual Reproduction
Advantages1 Can be done in isolation2 If you are perfect why change
Best when an organism is ldquoperfectlyrdquo suited for its environment
3 Less ldquomachineryrdquo needed no waste on flowers ldquonewrdquo types of cells or other secondary sexual characteristics
Disadvantages1 Less variety Poor option in a
changing environment
Fig 13-2
Parent
Bud
05 mmAsexual Reproduction
Advantages1 Can be done in isolation2 If you are perfect why change
Best when an organism is ldquoperfectlyrdquo suited for its environment
3 Less ldquomachineryrdquo needed no waste on flowers ldquonewrdquo types of cells or other secondary sexual characteristics
Disadvantages1 Less variety Poor option in a
changing environment
Aspen
Fig 13-1
Sexual ReproductionAdvantages1 Increased variety Best when
environment is changing
Increased Variety is DUE TObull random fertilizationbull meiosis
bull independent assortmentbull crossing-over
Disadvantages1 Resource investment
bull specialized cells gametesbull secondary sexual
characteristics mate attraction2 Requires a partner (except when
plants self-fertilize)
In eukaryotic organisms heritable information is passed to the next generation via mitosis and
meiosisCell Division 2 Types
Meiosis sex cells (gametes) (spermeggs)bull Purpose
ensures that each gamete receives one complete haploid (1n) set of chromosomes
Ensures chromosome number stays the same each offspring receives frac12 (1n) of the full set for the species (2n)
bull Steps1 DNA Replication2 homologous pairs form a tetrad
(independent assortment) (genetic variation increases)
3 cross over between homologous chromosomes may occur (genetic variation increases)
4 Meiosis I homologous pairs separate5 Meiosis II sister chromatids separate
In eukaryotic organisms heritable information is passed to the next generation via mitosis and
meiosisCell Division 2 Types
Meiosis sex cells (gametes) (spermeggs)bull Purpose
ensures that each gamete receives one complete haploid (1n) set of chromosomes
Ensures chromosome number stays the same each offspring receives frac12 (1n) of the full set for the species (2n)
bull Steps1 DNA Replication2 homologous pairs form a tetrad
(independent assortment) (genetic variation increases)
3 cross over between homologous chromosomes may occur (genetic variation increases)
4 Meiosis I homologous pairs separate5 Meiosis II sister chromatids separate
In eukaryotic organisms heritable information is passed to the next generation via mitosis and
meiosisCell Division 2 Types
Meiosis sex cells (gametes) (spermeggs)bull Purpose
ensures that each gamete receives one complete haploid (1n) set of chromosomes
Ensures chromosome number stays the same each offspring receives frac12 (1n) of the full set for the species (2n)
bull Steps1 DNA Replication2 homologous pairs form a tetrad
(independent assortment) (genetic variation increases)
3 cross over between homologous chromosomes may occur (genetic variation increases)
4 Meiosis I homologous pairs separate5 Meiosis II sister chromatids separate
1 Build your diploid cell (an homologous pair for each chromosome)a Draw a big cell with a nucleus insideb Add homologous pairs of chromosomes
bull 1 big white 1 big yellowbull 1 medium white 1 medium yellowbull 1 small white 1 small yellow
2 Clone each chromosome (DNA Replication) (making sister chromatids)3 Nucleus breaks down (erase it)4 Homologous pairs form a tetrad crossing over may occur (note do not model crossing
over for now)5 Homologous pairs separate one to each side of cell all paternal (or all maternal) do NOT
have to go together (independent assortment)6 Cytokinesis cell membrane grows between the 2 halves7 Clones (sister chromatids) separate (centromere ldquobreaksrdquo as DNA polymerization
completes) one to each side of cell8 Cytokinesis cell membrane grows between the 2 halves9 Nucleus grows around chromosomes 4 cells made (gametes which have half the
number of chromosomes (haploids)
Meiosis Modeling
When yoursquore confident on the process show Mr Jones
Meiosis Modelingbull When yoursquore confident on the process show Mr Jones
bull In your notebookTable 138 Stages of Meiosis p255At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid crossing over recombinant chromosome independent assortment Meiosis I Meiosis II
Meiosis Modeling
Analysis
1 What is the outcome of meiosis2 What steps of meiosis cause variation3 If the first cell has 46 chromosomes (before
cloning) how many does each daughter cell have4 How many unique gametes did you form How
many could have formed5 Why do cells go through meiosis
Warm-UP 1 Why do meiosis2 How does meiosis increase variation in organisms
AP Test Money DUE 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Tomorrow Meiosis Wksht
UNIT 78 TEST March 19th
Inheritance and Regulation
Meiosis has multiple processes that increases genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Meiosis has multiple processes that increase genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Meiosis has multiple processes that increase genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Meiosis has multiple processes that increases genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Warm-UP Watch the video What is happening Why does this happen How does this increase variation
AP Test Money DUE TOMORROW 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Tomorrow
UNIT 78 TEST March 19th
Inheritance and Regulation
Fig 13-9a
MITOSIS MEIOSIS
MEIOSIS I
Prophase I
Chiasma
Chromosomereplication
Homologouschromosomepair
Chromosomereplication
2n = 6
Parent cell
Prophase
Replicated chromosome
Metaphase Metaphase I
Anaphase ITelophase I
Haploid n = 3
Daughter cells ofmeiosis I
MEIOSIS II
Daughter cells of meiosis II
nnnn
2n2n
Daughter cellsof mitosis
AnaphaseTelophase
Compare
Contrast
Independent Assortment
Crossing-over Sexual Fertilization Mutation
Types of Changes to Cells Think About what where when how how much variation created
Warm-UP Now we need to keep track of the genes on the chromosomes that are inherited Notice the letters on the chromosomes They represent different alleles for Huntingtons Barbie has Huntingtons What is the chance her child will get Huntingtons
AP Test Money DUE 36 TOMORROWRemember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Tomorrow 141 5 Key Ideas AND Concept Check 1-3
H=dominant (remember Huntingtonrsquos is dominant)
h=recessive (no Huntingtonrsquos)
Homework DUE Monday Test Corrections for 10 Make-UP
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
AP Test Money DUE 36 TODAYRemember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
DUE next Thursday Monohybrid Crosses
Homework DUE Monday Test Corrections for 10 Make-UP
Warm-UP Now we need to keep track of TWO UNLINKED genes on the chromosomes that are inherited Notice the letters on the chromosomes They represent different alleles for Huntingtons and red hair color Barbie has Huntingtons and is a blond (but a carrier) Ken does not have Huntingtonrsquos and is also a carrier for red hair What is the chance their child will get Huntingtons and red hair
Homework DUE Tomorrow 142 5 Key Ideas AND Concept Check 1-3
H= Huntingtonrsquosh=no HuntingtonrsquosR= no red hairr= red hair
DUE Now Test Corrections for 10 Make-UP
UNIT 78 TEST March 19th
Inheritance and Regulation
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
Homework DUE Tomorrow 143 5 Key Ideas AND Concept Check 1-3
DUE Now 142DUE Thursday Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
UNIT 78 TEST March 19th
Inheritance and Regulation
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoods
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with RrYy
1 Chance of baby with Rr 052 Chance of baby with Yy 053 Chance of baby with RrYy 025
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with both dominant phenotypes
1 Chance of baby with at least one R 0752 Chance of baby with at least one Y 0753 Chance of baby with RrYy 05625 (916)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with both dominant phenotypes
1 Chance of baby with at least one R 10
2 Chance of baby with at least one Y 10
3 Chance of baby with both dominant phenotypes 10
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
Homework DUE Tomorrow Linked vs Unlinked Genes AND Monohybrid Crosses to tunritincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with
vestigial wings and cinnabar eyes Predict the phenotypic ratio of the F2 individuals
Homework DUE Tomorrow 153 5 Key Ideas and Concept Check 1-3DUE Thursday Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with vestigial wings and cinnabar eyes Predict the
phenotypic ratio of the F2 individuals
3 The results of the cross from 2 show the following outcome Individuals of each phenotype are shown in the table Which of the following is the most likely explanation of the results a The two genes are located on two different chromosomes b The two genes are sex-linked c The two genes are located on mitochondrial DNA d The two genes are linked on an autosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
1 Build your diploid cell (an homologous pair for each chromosome)a Draw a big cell with a nucleus insideb DRAW homologous pairs of chromosomes
bull 1 big blue 1 big redbull 1 small blue 1 small red
ndash Add genes to your chromosomebull Write an H and an R on big blue and an h and an r on big redbull Write a T on small blue and a t on small red
2 Clone each chromosome (DNA Replication) (making sister chromatids)3 Nucleus breaks down (erase it)4 Homologous pairs form a tetrad crossing over may occur (note do not model
crossing over for now)5 Finish meiosis (see notes for help)6 Nucleus grows around chromosomes 4 cells made (gametes which have half
the number of chromosomes (haploids)7 Repeat Steps 1-6 this time at Step 4 include ONE crossover event
Recombination Modeling
When yoursquore confident on the process show Mr Jones
bull When yoursquore confident on the process show Mr Jones
bull In your notebookFigure 1510 Recombination p295At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid crossing over recombinant chromosome independent assortment Meiosis I Meiosis II
Recombination Modeling
Analysis
1 How does recombination increase the variety of gametes formed
2 Which types of gametes were more likely Gametes with recombinant chromosomes or ones without
3 Recombination is a random process How might it benefithurt the survival of an individualspecies
Recombination Modeling
Warm-UP
1 How could you calculate recombination frequency2 What would the recombination frequency tell you about the relative position of
genes on a chromosome3 Genes A B and C are on the same chromosome Testcrosses show that the
recombination frequency between A and B is 28 and between A and C is 12 Can you determine the linear order of these genes
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP What can we learn about inheritance from looking at a pedigree (use example of the Royal Family of Europe from the early 1900s)
Warm-UP In the following human pedigree squares represent males circles represent females and shaded symbols indicate individuals affected with a disorder One of the affected males from the third generation has a child with a female who is a carrier For the pedigree shown which of the following best expresses the probability that the couplersquos first son will be affected with the disorder
(A) 25 (B) 50 (C) 75 (D) 100
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Is a widowrsquos peak a dominant or recessive trait
Is a widowrsquos peak a dominant or recessive trait
Fig 14-UN5
George
Sandra Tom Sam
Arlene
Wilma Ann Michael
Carla
Daniel Alan Tina
Christopher
A heterozygous tall and a homozygous purple flowered plant is crossed with a short and white flowered plant Predict the offspring Assume independent assortment
1
P=purplep=whiteT=tallt=short
For a plant with the genotype WwXxYyZz what is the probability that the plant will produce a gamete with a haploid genotype of Wxyz Give your answer as a fraction or as a value between 0 and 1 to four decimal places
2
A completely-plated stickleback from a marine population was mated to a low-plated stickleback from a freshwater population The resulting F1 hybrids all displayed a completely plated phenotype When the F1 hybrids were allowed to interbreed the resulting F2 generation included completely plated offspring and low-plated offspring in an approximate 31 ratio Which of the following conclusions is best supported by the results of the breeding experiments
a Phenotypic variation in the F2 generation suggests that armor morphology is controlled by many alleles of a single gene
b The completely-plated phenotype is controlled by a dominant allele of a single gene
c Armor loss is an acquired characteristic that is affected by one or more environmental factors
d Patterns of armor plating in stickleback populations are regulated by sex-specific signals
3
If a man with type AB blood marries a woman with type O what blood types would you expect in their children What fraction would you expect of each type
4
IA= Type AIB= Type Bi= Type O
If a King marries a Queen that is a carrier of hemophilia (sex-linked recessive disease that is historically fatal before adulthood) what is the chance of the Kingdom having an heir to the kingrsquos throne assuming only one child is born
5
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
7 Gregor Mendelrsquos pioneering genetic experiments with pea plants occurred before the discovery of the structure and function of chromosomes Which of the following observations about inheritance in pea plants could be explained only after the discovery that genes may be linked on a chromosome
a Pea color and pea shape display independent inheritance patterns b Offspring of a given cross show all possible combinations of traits in
equal proportions c Most offspring of a given cross have a combination of traits that is
identical to that of either one parent or the other d Recessive phenotypes can skip a generation showing up only in the
parental and F 2 generations
8
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Based on the data in Table I which of the following best explains why there are no individuals with constricted pods in the F 1 generation a Inflated pod shape is dominant to constricted pod shape b The inflated-pod offspring in the F sub one generation are
homozygous c Constricted pod shape typically arises from a new mutation in the F 1
generation d The constricted-pod offspring are carriers for the inflated pod shape
allele
9
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table I the ratio of phenotypes in the offspring from the testcross with F 1 plants that had purple flowers and inflated pods suggests that the genes for flower color and pod shape are located a close together on the same autosome b on the X chromosome c on different chromosomes d on a mitochondrial chromosome
10
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Which of the following provides the best justification for an assumption that might have been used in the computer simulation (Table II) a The broad allele is recessive to the narrow allele because broad
leaves appear in every generation b The purple allele is dominant to the white allele because all the
offspring from the cross of purple-flowered and white-flowered plants had purple flowers
c The narrow allele is codominant with the purple allele because the purple-flower trait and the narrow-leaf trait segregate together
d The white allele is dominant to both the broad and narrow alleles because plants with either type of leaf shape can have white flowers
11
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table II the F 1 offspring of the cross between broad-leaved white-flowered plants with narrow-leaved purple-flowered plants have a phenotype that differs from that of either parent However many testcross offspring have the same phenotype as one of the two plants in the parental cross but relatively few testcross offspring have the same phenotype as the F 1 offspring Which of the following best explains the observation a Recombination between the leaf-shape and flower-color genes resulted in
chromosomes carrying a dominant allele of both genes b Recombination between the broad and narrow alleles of the leaf-shape gene resulted in
chromosomes carrying three different alleles at the same genetic locus c Independent assortment of homologous chromosomes resulted in the combinations of
alleles present in the parental generation d The computer model cannot capture the possible assortments of gametes when
multiple genes are considered
Fig 13-2
Parent
Bud
05 mmAsexual Reproduction
Advantages1 Can be done in isolation2 If you are perfect why change
Best when an organism is ldquoperfectlyrdquo suited for its environment
3 Less ldquomachineryrdquo needed no waste on flowers ldquonewrdquo types of cells or other secondary sexual characteristics
Disadvantages1 Less variety Poor option in a
changing environment
Fig 13-2
Parent
Bud
05 mmAsexual Reproduction
Advantages1 Can be done in isolation2 If you are perfect why change
Best when an organism is ldquoperfectlyrdquo suited for its environment
3 Less ldquomachineryrdquo needed no waste on flowers ldquonewrdquo types of cells or other secondary sexual characteristics
Disadvantages1 Less variety Poor option in a
changing environment
Aspen
Fig 13-1
Sexual ReproductionAdvantages1 Increased variety Best when
environment is changing
Increased Variety is DUE TObull random fertilizationbull meiosis
bull independent assortmentbull crossing-over
Disadvantages1 Resource investment
bull specialized cells gametesbull secondary sexual
characteristics mate attraction2 Requires a partner (except when
plants self-fertilize)
In eukaryotic organisms heritable information is passed to the next generation via mitosis and
meiosisCell Division 2 Types
Meiosis sex cells (gametes) (spermeggs)bull Purpose
ensures that each gamete receives one complete haploid (1n) set of chromosomes
Ensures chromosome number stays the same each offspring receives frac12 (1n) of the full set for the species (2n)
bull Steps1 DNA Replication2 homologous pairs form a tetrad
(independent assortment) (genetic variation increases)
3 cross over between homologous chromosomes may occur (genetic variation increases)
4 Meiosis I homologous pairs separate5 Meiosis II sister chromatids separate
In eukaryotic organisms heritable information is passed to the next generation via mitosis and
meiosisCell Division 2 Types
Meiosis sex cells (gametes) (spermeggs)bull Purpose
ensures that each gamete receives one complete haploid (1n) set of chromosomes
Ensures chromosome number stays the same each offspring receives frac12 (1n) of the full set for the species (2n)
bull Steps1 DNA Replication2 homologous pairs form a tetrad
(independent assortment) (genetic variation increases)
3 cross over between homologous chromosomes may occur (genetic variation increases)
4 Meiosis I homologous pairs separate5 Meiosis II sister chromatids separate
In eukaryotic organisms heritable information is passed to the next generation via mitosis and
meiosisCell Division 2 Types
Meiosis sex cells (gametes) (spermeggs)bull Purpose
ensures that each gamete receives one complete haploid (1n) set of chromosomes
Ensures chromosome number stays the same each offspring receives frac12 (1n) of the full set for the species (2n)
bull Steps1 DNA Replication2 homologous pairs form a tetrad
(independent assortment) (genetic variation increases)
3 cross over between homologous chromosomes may occur (genetic variation increases)
4 Meiosis I homologous pairs separate5 Meiosis II sister chromatids separate
1 Build your diploid cell (an homologous pair for each chromosome)a Draw a big cell with a nucleus insideb Add homologous pairs of chromosomes
bull 1 big white 1 big yellowbull 1 medium white 1 medium yellowbull 1 small white 1 small yellow
2 Clone each chromosome (DNA Replication) (making sister chromatids)3 Nucleus breaks down (erase it)4 Homologous pairs form a tetrad crossing over may occur (note do not model crossing
over for now)5 Homologous pairs separate one to each side of cell all paternal (or all maternal) do NOT
have to go together (independent assortment)6 Cytokinesis cell membrane grows between the 2 halves7 Clones (sister chromatids) separate (centromere ldquobreaksrdquo as DNA polymerization
completes) one to each side of cell8 Cytokinesis cell membrane grows between the 2 halves9 Nucleus grows around chromosomes 4 cells made (gametes which have half the
number of chromosomes (haploids)
Meiosis Modeling
When yoursquore confident on the process show Mr Jones
Meiosis Modelingbull When yoursquore confident on the process show Mr Jones
bull In your notebookTable 138 Stages of Meiosis p255At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid crossing over recombinant chromosome independent assortment Meiosis I Meiosis II
Meiosis Modeling
Analysis
1 What is the outcome of meiosis2 What steps of meiosis cause variation3 If the first cell has 46 chromosomes (before
cloning) how many does each daughter cell have4 How many unique gametes did you form How
many could have formed5 Why do cells go through meiosis
Warm-UP 1 Why do meiosis2 How does meiosis increase variation in organisms
AP Test Money DUE 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Tomorrow Meiosis Wksht
UNIT 78 TEST March 19th
Inheritance and Regulation
Meiosis has multiple processes that increases genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Meiosis has multiple processes that increase genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Meiosis has multiple processes that increase genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Meiosis has multiple processes that increases genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Warm-UP Watch the video What is happening Why does this happen How does this increase variation
AP Test Money DUE TOMORROW 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Tomorrow
UNIT 78 TEST March 19th
Inheritance and Regulation
Fig 13-9a
MITOSIS MEIOSIS
MEIOSIS I
Prophase I
Chiasma
Chromosomereplication
Homologouschromosomepair
Chromosomereplication
2n = 6
Parent cell
Prophase
Replicated chromosome
Metaphase Metaphase I
Anaphase ITelophase I
Haploid n = 3
Daughter cells ofmeiosis I
MEIOSIS II
Daughter cells of meiosis II
nnnn
2n2n
Daughter cellsof mitosis
AnaphaseTelophase
Compare
Contrast
Independent Assortment
Crossing-over Sexual Fertilization Mutation
Types of Changes to Cells Think About what where when how how much variation created
Warm-UP Now we need to keep track of the genes on the chromosomes that are inherited Notice the letters on the chromosomes They represent different alleles for Huntingtons Barbie has Huntingtons What is the chance her child will get Huntingtons
AP Test Money DUE 36 TOMORROWRemember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Tomorrow 141 5 Key Ideas AND Concept Check 1-3
H=dominant (remember Huntingtonrsquos is dominant)
h=recessive (no Huntingtonrsquos)
Homework DUE Monday Test Corrections for 10 Make-UP
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
AP Test Money DUE 36 TODAYRemember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
DUE next Thursday Monohybrid Crosses
Homework DUE Monday Test Corrections for 10 Make-UP
Warm-UP Now we need to keep track of TWO UNLINKED genes on the chromosomes that are inherited Notice the letters on the chromosomes They represent different alleles for Huntingtons and red hair color Barbie has Huntingtons and is a blond (but a carrier) Ken does not have Huntingtonrsquos and is also a carrier for red hair What is the chance their child will get Huntingtons and red hair
Homework DUE Tomorrow 142 5 Key Ideas AND Concept Check 1-3
H= Huntingtonrsquosh=no HuntingtonrsquosR= no red hairr= red hair
DUE Now Test Corrections for 10 Make-UP
UNIT 78 TEST March 19th
Inheritance and Regulation
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
Homework DUE Tomorrow 143 5 Key Ideas AND Concept Check 1-3
DUE Now 142DUE Thursday Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
UNIT 78 TEST March 19th
Inheritance and Regulation
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoods
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with RrYy
1 Chance of baby with Rr 052 Chance of baby with Yy 053 Chance of baby with RrYy 025
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with both dominant phenotypes
1 Chance of baby with at least one R 0752 Chance of baby with at least one Y 0753 Chance of baby with RrYy 05625 (916)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with both dominant phenotypes
1 Chance of baby with at least one R 10
2 Chance of baby with at least one Y 10
3 Chance of baby with both dominant phenotypes 10
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
Homework DUE Tomorrow Linked vs Unlinked Genes AND Monohybrid Crosses to tunritincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with
vestigial wings and cinnabar eyes Predict the phenotypic ratio of the F2 individuals
Homework DUE Tomorrow 153 5 Key Ideas and Concept Check 1-3DUE Thursday Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with vestigial wings and cinnabar eyes Predict the
phenotypic ratio of the F2 individuals
3 The results of the cross from 2 show the following outcome Individuals of each phenotype are shown in the table Which of the following is the most likely explanation of the results a The two genes are located on two different chromosomes b The two genes are sex-linked c The two genes are located on mitochondrial DNA d The two genes are linked on an autosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
1 Build your diploid cell (an homologous pair for each chromosome)a Draw a big cell with a nucleus insideb DRAW homologous pairs of chromosomes
bull 1 big blue 1 big redbull 1 small blue 1 small red
ndash Add genes to your chromosomebull Write an H and an R on big blue and an h and an r on big redbull Write a T on small blue and a t on small red
2 Clone each chromosome (DNA Replication) (making sister chromatids)3 Nucleus breaks down (erase it)4 Homologous pairs form a tetrad crossing over may occur (note do not model
crossing over for now)5 Finish meiosis (see notes for help)6 Nucleus grows around chromosomes 4 cells made (gametes which have half
the number of chromosomes (haploids)7 Repeat Steps 1-6 this time at Step 4 include ONE crossover event
Recombination Modeling
When yoursquore confident on the process show Mr Jones
bull When yoursquore confident on the process show Mr Jones
bull In your notebookFigure 1510 Recombination p295At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid crossing over recombinant chromosome independent assortment Meiosis I Meiosis II
Recombination Modeling
Analysis
1 How does recombination increase the variety of gametes formed
2 Which types of gametes were more likely Gametes with recombinant chromosomes or ones without
3 Recombination is a random process How might it benefithurt the survival of an individualspecies
Recombination Modeling
Warm-UP
1 How could you calculate recombination frequency2 What would the recombination frequency tell you about the relative position of
genes on a chromosome3 Genes A B and C are on the same chromosome Testcrosses show that the
recombination frequency between A and B is 28 and between A and C is 12 Can you determine the linear order of these genes
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP What can we learn about inheritance from looking at a pedigree (use example of the Royal Family of Europe from the early 1900s)
Warm-UP In the following human pedigree squares represent males circles represent females and shaded symbols indicate individuals affected with a disorder One of the affected males from the third generation has a child with a female who is a carrier For the pedigree shown which of the following best expresses the probability that the couplersquos first son will be affected with the disorder
(A) 25 (B) 50 (C) 75 (D) 100
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Is a widowrsquos peak a dominant or recessive trait
Is a widowrsquos peak a dominant or recessive trait
Fig 14-UN5
George
Sandra Tom Sam
Arlene
Wilma Ann Michael
Carla
Daniel Alan Tina
Christopher
A heterozygous tall and a homozygous purple flowered plant is crossed with a short and white flowered plant Predict the offspring Assume independent assortment
1
P=purplep=whiteT=tallt=short
For a plant with the genotype WwXxYyZz what is the probability that the plant will produce a gamete with a haploid genotype of Wxyz Give your answer as a fraction or as a value between 0 and 1 to four decimal places
2
A completely-plated stickleback from a marine population was mated to a low-plated stickleback from a freshwater population The resulting F1 hybrids all displayed a completely plated phenotype When the F1 hybrids were allowed to interbreed the resulting F2 generation included completely plated offspring and low-plated offspring in an approximate 31 ratio Which of the following conclusions is best supported by the results of the breeding experiments
a Phenotypic variation in the F2 generation suggests that armor morphology is controlled by many alleles of a single gene
b The completely-plated phenotype is controlled by a dominant allele of a single gene
c Armor loss is an acquired characteristic that is affected by one or more environmental factors
d Patterns of armor plating in stickleback populations are regulated by sex-specific signals
3
If a man with type AB blood marries a woman with type O what blood types would you expect in their children What fraction would you expect of each type
4
IA= Type AIB= Type Bi= Type O
If a King marries a Queen that is a carrier of hemophilia (sex-linked recessive disease that is historically fatal before adulthood) what is the chance of the Kingdom having an heir to the kingrsquos throne assuming only one child is born
5
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
7 Gregor Mendelrsquos pioneering genetic experiments with pea plants occurred before the discovery of the structure and function of chromosomes Which of the following observations about inheritance in pea plants could be explained only after the discovery that genes may be linked on a chromosome
a Pea color and pea shape display independent inheritance patterns b Offspring of a given cross show all possible combinations of traits in
equal proportions c Most offspring of a given cross have a combination of traits that is
identical to that of either one parent or the other d Recessive phenotypes can skip a generation showing up only in the
parental and F 2 generations
8
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Based on the data in Table I which of the following best explains why there are no individuals with constricted pods in the F 1 generation a Inflated pod shape is dominant to constricted pod shape b The inflated-pod offspring in the F sub one generation are
homozygous c Constricted pod shape typically arises from a new mutation in the F 1
generation d The constricted-pod offspring are carriers for the inflated pod shape
allele
9
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table I the ratio of phenotypes in the offspring from the testcross with F 1 plants that had purple flowers and inflated pods suggests that the genes for flower color and pod shape are located a close together on the same autosome b on the X chromosome c on different chromosomes d on a mitochondrial chromosome
10
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Which of the following provides the best justification for an assumption that might have been used in the computer simulation (Table II) a The broad allele is recessive to the narrow allele because broad
leaves appear in every generation b The purple allele is dominant to the white allele because all the
offspring from the cross of purple-flowered and white-flowered plants had purple flowers
c The narrow allele is codominant with the purple allele because the purple-flower trait and the narrow-leaf trait segregate together
d The white allele is dominant to both the broad and narrow alleles because plants with either type of leaf shape can have white flowers
11
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table II the F 1 offspring of the cross between broad-leaved white-flowered plants with narrow-leaved purple-flowered plants have a phenotype that differs from that of either parent However many testcross offspring have the same phenotype as one of the two plants in the parental cross but relatively few testcross offspring have the same phenotype as the F 1 offspring Which of the following best explains the observation a Recombination between the leaf-shape and flower-color genes resulted in
chromosomes carrying a dominant allele of both genes b Recombination between the broad and narrow alleles of the leaf-shape gene resulted in
chromosomes carrying three different alleles at the same genetic locus c Independent assortment of homologous chromosomes resulted in the combinations of
alleles present in the parental generation d The computer model cannot capture the possible assortments of gametes when
multiple genes are considered
Fig 13-2
Parent
Bud
05 mmAsexual Reproduction
Advantages1 Can be done in isolation2 If you are perfect why change
Best when an organism is ldquoperfectlyrdquo suited for its environment
3 Less ldquomachineryrdquo needed no waste on flowers ldquonewrdquo types of cells or other secondary sexual characteristics
Disadvantages1 Less variety Poor option in a
changing environment
Aspen
Fig 13-1
Sexual ReproductionAdvantages1 Increased variety Best when
environment is changing
Increased Variety is DUE TObull random fertilizationbull meiosis
bull independent assortmentbull crossing-over
Disadvantages1 Resource investment
bull specialized cells gametesbull secondary sexual
characteristics mate attraction2 Requires a partner (except when
plants self-fertilize)
In eukaryotic organisms heritable information is passed to the next generation via mitosis and
meiosisCell Division 2 Types
Meiosis sex cells (gametes) (spermeggs)bull Purpose
ensures that each gamete receives one complete haploid (1n) set of chromosomes
Ensures chromosome number stays the same each offspring receives frac12 (1n) of the full set for the species (2n)
bull Steps1 DNA Replication2 homologous pairs form a tetrad
(independent assortment) (genetic variation increases)
3 cross over between homologous chromosomes may occur (genetic variation increases)
4 Meiosis I homologous pairs separate5 Meiosis II sister chromatids separate
In eukaryotic organisms heritable information is passed to the next generation via mitosis and
meiosisCell Division 2 Types
Meiosis sex cells (gametes) (spermeggs)bull Purpose
ensures that each gamete receives one complete haploid (1n) set of chromosomes
Ensures chromosome number stays the same each offspring receives frac12 (1n) of the full set for the species (2n)
bull Steps1 DNA Replication2 homologous pairs form a tetrad
(independent assortment) (genetic variation increases)
3 cross over between homologous chromosomes may occur (genetic variation increases)
4 Meiosis I homologous pairs separate5 Meiosis II sister chromatids separate
In eukaryotic organisms heritable information is passed to the next generation via mitosis and
meiosisCell Division 2 Types
Meiosis sex cells (gametes) (spermeggs)bull Purpose
ensures that each gamete receives one complete haploid (1n) set of chromosomes
Ensures chromosome number stays the same each offspring receives frac12 (1n) of the full set for the species (2n)
bull Steps1 DNA Replication2 homologous pairs form a tetrad
(independent assortment) (genetic variation increases)
3 cross over between homologous chromosomes may occur (genetic variation increases)
4 Meiosis I homologous pairs separate5 Meiosis II sister chromatids separate
1 Build your diploid cell (an homologous pair for each chromosome)a Draw a big cell with a nucleus insideb Add homologous pairs of chromosomes
bull 1 big white 1 big yellowbull 1 medium white 1 medium yellowbull 1 small white 1 small yellow
2 Clone each chromosome (DNA Replication) (making sister chromatids)3 Nucleus breaks down (erase it)4 Homologous pairs form a tetrad crossing over may occur (note do not model crossing
over for now)5 Homologous pairs separate one to each side of cell all paternal (or all maternal) do NOT
have to go together (independent assortment)6 Cytokinesis cell membrane grows between the 2 halves7 Clones (sister chromatids) separate (centromere ldquobreaksrdquo as DNA polymerization
completes) one to each side of cell8 Cytokinesis cell membrane grows between the 2 halves9 Nucleus grows around chromosomes 4 cells made (gametes which have half the
number of chromosomes (haploids)
Meiosis Modeling
When yoursquore confident on the process show Mr Jones
Meiosis Modelingbull When yoursquore confident on the process show Mr Jones
bull In your notebookTable 138 Stages of Meiosis p255At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid crossing over recombinant chromosome independent assortment Meiosis I Meiosis II
Meiosis Modeling
Analysis
1 What is the outcome of meiosis2 What steps of meiosis cause variation3 If the first cell has 46 chromosomes (before
cloning) how many does each daughter cell have4 How many unique gametes did you form How
many could have formed5 Why do cells go through meiosis
Warm-UP 1 Why do meiosis2 How does meiosis increase variation in organisms
AP Test Money DUE 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Tomorrow Meiosis Wksht
UNIT 78 TEST March 19th
Inheritance and Regulation
Meiosis has multiple processes that increases genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Meiosis has multiple processes that increase genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Meiosis has multiple processes that increase genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Meiosis has multiple processes that increases genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Warm-UP Watch the video What is happening Why does this happen How does this increase variation
AP Test Money DUE TOMORROW 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Tomorrow
UNIT 78 TEST March 19th
Inheritance and Regulation
Fig 13-9a
MITOSIS MEIOSIS
MEIOSIS I
Prophase I
Chiasma
Chromosomereplication
Homologouschromosomepair
Chromosomereplication
2n = 6
Parent cell
Prophase
Replicated chromosome
Metaphase Metaphase I
Anaphase ITelophase I
Haploid n = 3
Daughter cells ofmeiosis I
MEIOSIS II
Daughter cells of meiosis II
nnnn
2n2n
Daughter cellsof mitosis
AnaphaseTelophase
Compare
Contrast
Independent Assortment
Crossing-over Sexual Fertilization Mutation
Types of Changes to Cells Think About what where when how how much variation created
Warm-UP Now we need to keep track of the genes on the chromosomes that are inherited Notice the letters on the chromosomes They represent different alleles for Huntingtons Barbie has Huntingtons What is the chance her child will get Huntingtons
AP Test Money DUE 36 TOMORROWRemember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Tomorrow 141 5 Key Ideas AND Concept Check 1-3
H=dominant (remember Huntingtonrsquos is dominant)
h=recessive (no Huntingtonrsquos)
Homework DUE Monday Test Corrections for 10 Make-UP
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
AP Test Money DUE 36 TODAYRemember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
DUE next Thursday Monohybrid Crosses
Homework DUE Monday Test Corrections for 10 Make-UP
Warm-UP Now we need to keep track of TWO UNLINKED genes on the chromosomes that are inherited Notice the letters on the chromosomes They represent different alleles for Huntingtons and red hair color Barbie has Huntingtons and is a blond (but a carrier) Ken does not have Huntingtonrsquos and is also a carrier for red hair What is the chance their child will get Huntingtons and red hair
Homework DUE Tomorrow 142 5 Key Ideas AND Concept Check 1-3
H= Huntingtonrsquosh=no HuntingtonrsquosR= no red hairr= red hair
DUE Now Test Corrections for 10 Make-UP
UNIT 78 TEST March 19th
Inheritance and Regulation
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
Homework DUE Tomorrow 143 5 Key Ideas AND Concept Check 1-3
DUE Now 142DUE Thursday Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
UNIT 78 TEST March 19th
Inheritance and Regulation
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoods
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with RrYy
1 Chance of baby with Rr 052 Chance of baby with Yy 053 Chance of baby with RrYy 025
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with both dominant phenotypes
1 Chance of baby with at least one R 0752 Chance of baby with at least one Y 0753 Chance of baby with RrYy 05625 (916)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with both dominant phenotypes
1 Chance of baby with at least one R 10
2 Chance of baby with at least one Y 10
3 Chance of baby with both dominant phenotypes 10
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
Homework DUE Tomorrow Linked vs Unlinked Genes AND Monohybrid Crosses to tunritincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with
vestigial wings and cinnabar eyes Predict the phenotypic ratio of the F2 individuals
Homework DUE Tomorrow 153 5 Key Ideas and Concept Check 1-3DUE Thursday Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with vestigial wings and cinnabar eyes Predict the
phenotypic ratio of the F2 individuals
3 The results of the cross from 2 show the following outcome Individuals of each phenotype are shown in the table Which of the following is the most likely explanation of the results a The two genes are located on two different chromosomes b The two genes are sex-linked c The two genes are located on mitochondrial DNA d The two genes are linked on an autosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
1 Build your diploid cell (an homologous pair for each chromosome)a Draw a big cell with a nucleus insideb DRAW homologous pairs of chromosomes
bull 1 big blue 1 big redbull 1 small blue 1 small red
ndash Add genes to your chromosomebull Write an H and an R on big blue and an h and an r on big redbull Write a T on small blue and a t on small red
2 Clone each chromosome (DNA Replication) (making sister chromatids)3 Nucleus breaks down (erase it)4 Homologous pairs form a tetrad crossing over may occur (note do not model
crossing over for now)5 Finish meiosis (see notes for help)6 Nucleus grows around chromosomes 4 cells made (gametes which have half
the number of chromosomes (haploids)7 Repeat Steps 1-6 this time at Step 4 include ONE crossover event
Recombination Modeling
When yoursquore confident on the process show Mr Jones
bull When yoursquore confident on the process show Mr Jones
bull In your notebookFigure 1510 Recombination p295At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid crossing over recombinant chromosome independent assortment Meiosis I Meiosis II
Recombination Modeling
Analysis
1 How does recombination increase the variety of gametes formed
2 Which types of gametes were more likely Gametes with recombinant chromosomes or ones without
3 Recombination is a random process How might it benefithurt the survival of an individualspecies
Recombination Modeling
Warm-UP
1 How could you calculate recombination frequency2 What would the recombination frequency tell you about the relative position of
genes on a chromosome3 Genes A B and C are on the same chromosome Testcrosses show that the
recombination frequency between A and B is 28 and between A and C is 12 Can you determine the linear order of these genes
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP What can we learn about inheritance from looking at a pedigree (use example of the Royal Family of Europe from the early 1900s)
Warm-UP In the following human pedigree squares represent males circles represent females and shaded symbols indicate individuals affected with a disorder One of the affected males from the third generation has a child with a female who is a carrier For the pedigree shown which of the following best expresses the probability that the couplersquos first son will be affected with the disorder
(A) 25 (B) 50 (C) 75 (D) 100
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Is a widowrsquos peak a dominant or recessive trait
Is a widowrsquos peak a dominant or recessive trait
Fig 14-UN5
George
Sandra Tom Sam
Arlene
Wilma Ann Michael
Carla
Daniel Alan Tina
Christopher
A heterozygous tall and a homozygous purple flowered plant is crossed with a short and white flowered plant Predict the offspring Assume independent assortment
1
P=purplep=whiteT=tallt=short
For a plant with the genotype WwXxYyZz what is the probability that the plant will produce a gamete with a haploid genotype of Wxyz Give your answer as a fraction or as a value between 0 and 1 to four decimal places
2
A completely-plated stickleback from a marine population was mated to a low-plated stickleback from a freshwater population The resulting F1 hybrids all displayed a completely plated phenotype When the F1 hybrids were allowed to interbreed the resulting F2 generation included completely plated offspring and low-plated offspring in an approximate 31 ratio Which of the following conclusions is best supported by the results of the breeding experiments
a Phenotypic variation in the F2 generation suggests that armor morphology is controlled by many alleles of a single gene
b The completely-plated phenotype is controlled by a dominant allele of a single gene
c Armor loss is an acquired characteristic that is affected by one or more environmental factors
d Patterns of armor plating in stickleback populations are regulated by sex-specific signals
3
If a man with type AB blood marries a woman with type O what blood types would you expect in their children What fraction would you expect of each type
4
IA= Type AIB= Type Bi= Type O
If a King marries a Queen that is a carrier of hemophilia (sex-linked recessive disease that is historically fatal before adulthood) what is the chance of the Kingdom having an heir to the kingrsquos throne assuming only one child is born
5
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
7 Gregor Mendelrsquos pioneering genetic experiments with pea plants occurred before the discovery of the structure and function of chromosomes Which of the following observations about inheritance in pea plants could be explained only after the discovery that genes may be linked on a chromosome
a Pea color and pea shape display independent inheritance patterns b Offspring of a given cross show all possible combinations of traits in
equal proportions c Most offspring of a given cross have a combination of traits that is
identical to that of either one parent or the other d Recessive phenotypes can skip a generation showing up only in the
parental and F 2 generations
8
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Based on the data in Table I which of the following best explains why there are no individuals with constricted pods in the F 1 generation a Inflated pod shape is dominant to constricted pod shape b The inflated-pod offspring in the F sub one generation are
homozygous c Constricted pod shape typically arises from a new mutation in the F 1
generation d The constricted-pod offspring are carriers for the inflated pod shape
allele
9
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table I the ratio of phenotypes in the offspring from the testcross with F 1 plants that had purple flowers and inflated pods suggests that the genes for flower color and pod shape are located a close together on the same autosome b on the X chromosome c on different chromosomes d on a mitochondrial chromosome
10
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Which of the following provides the best justification for an assumption that might have been used in the computer simulation (Table II) a The broad allele is recessive to the narrow allele because broad
leaves appear in every generation b The purple allele is dominant to the white allele because all the
offspring from the cross of purple-flowered and white-flowered plants had purple flowers
c The narrow allele is codominant with the purple allele because the purple-flower trait and the narrow-leaf trait segregate together
d The white allele is dominant to both the broad and narrow alleles because plants with either type of leaf shape can have white flowers
11
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table II the F 1 offspring of the cross between broad-leaved white-flowered plants with narrow-leaved purple-flowered plants have a phenotype that differs from that of either parent However many testcross offspring have the same phenotype as one of the two plants in the parental cross but relatively few testcross offspring have the same phenotype as the F 1 offspring Which of the following best explains the observation a Recombination between the leaf-shape and flower-color genes resulted in
chromosomes carrying a dominant allele of both genes b Recombination between the broad and narrow alleles of the leaf-shape gene resulted in
chromosomes carrying three different alleles at the same genetic locus c Independent assortment of homologous chromosomes resulted in the combinations of
alleles present in the parental generation d The computer model cannot capture the possible assortments of gametes when
multiple genes are considered
Fig 13-1
Sexual ReproductionAdvantages1 Increased variety Best when
environment is changing
Increased Variety is DUE TObull random fertilizationbull meiosis
bull independent assortmentbull crossing-over
Disadvantages1 Resource investment
bull specialized cells gametesbull secondary sexual
characteristics mate attraction2 Requires a partner (except when
plants self-fertilize)
In eukaryotic organisms heritable information is passed to the next generation via mitosis and
meiosisCell Division 2 Types
Meiosis sex cells (gametes) (spermeggs)bull Purpose
ensures that each gamete receives one complete haploid (1n) set of chromosomes
Ensures chromosome number stays the same each offspring receives frac12 (1n) of the full set for the species (2n)
bull Steps1 DNA Replication2 homologous pairs form a tetrad
(independent assortment) (genetic variation increases)
3 cross over between homologous chromosomes may occur (genetic variation increases)
4 Meiosis I homologous pairs separate5 Meiosis II sister chromatids separate
In eukaryotic organisms heritable information is passed to the next generation via mitosis and
meiosisCell Division 2 Types
Meiosis sex cells (gametes) (spermeggs)bull Purpose
ensures that each gamete receives one complete haploid (1n) set of chromosomes
Ensures chromosome number stays the same each offspring receives frac12 (1n) of the full set for the species (2n)
bull Steps1 DNA Replication2 homologous pairs form a tetrad
(independent assortment) (genetic variation increases)
3 cross over between homologous chromosomes may occur (genetic variation increases)
4 Meiosis I homologous pairs separate5 Meiosis II sister chromatids separate
In eukaryotic organisms heritable information is passed to the next generation via mitosis and
meiosisCell Division 2 Types
Meiosis sex cells (gametes) (spermeggs)bull Purpose
ensures that each gamete receives one complete haploid (1n) set of chromosomes
Ensures chromosome number stays the same each offspring receives frac12 (1n) of the full set for the species (2n)
bull Steps1 DNA Replication2 homologous pairs form a tetrad
(independent assortment) (genetic variation increases)
3 cross over between homologous chromosomes may occur (genetic variation increases)
4 Meiosis I homologous pairs separate5 Meiosis II sister chromatids separate
1 Build your diploid cell (an homologous pair for each chromosome)a Draw a big cell with a nucleus insideb Add homologous pairs of chromosomes
bull 1 big white 1 big yellowbull 1 medium white 1 medium yellowbull 1 small white 1 small yellow
2 Clone each chromosome (DNA Replication) (making sister chromatids)3 Nucleus breaks down (erase it)4 Homologous pairs form a tetrad crossing over may occur (note do not model crossing
over for now)5 Homologous pairs separate one to each side of cell all paternal (or all maternal) do NOT
have to go together (independent assortment)6 Cytokinesis cell membrane grows between the 2 halves7 Clones (sister chromatids) separate (centromere ldquobreaksrdquo as DNA polymerization
completes) one to each side of cell8 Cytokinesis cell membrane grows between the 2 halves9 Nucleus grows around chromosomes 4 cells made (gametes which have half the
number of chromosomes (haploids)
Meiosis Modeling
When yoursquore confident on the process show Mr Jones
Meiosis Modelingbull When yoursquore confident on the process show Mr Jones
bull In your notebookTable 138 Stages of Meiosis p255At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid crossing over recombinant chromosome independent assortment Meiosis I Meiosis II
Meiosis Modeling
Analysis
1 What is the outcome of meiosis2 What steps of meiosis cause variation3 If the first cell has 46 chromosomes (before
cloning) how many does each daughter cell have4 How many unique gametes did you form How
many could have formed5 Why do cells go through meiosis
Warm-UP 1 Why do meiosis2 How does meiosis increase variation in organisms
AP Test Money DUE 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Tomorrow Meiosis Wksht
UNIT 78 TEST March 19th
Inheritance and Regulation
Meiosis has multiple processes that increases genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Meiosis has multiple processes that increase genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Meiosis has multiple processes that increase genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Meiosis has multiple processes that increases genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Warm-UP Watch the video What is happening Why does this happen How does this increase variation
AP Test Money DUE TOMORROW 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Tomorrow
UNIT 78 TEST March 19th
Inheritance and Regulation
Fig 13-9a
MITOSIS MEIOSIS
MEIOSIS I
Prophase I
Chiasma
Chromosomereplication
Homologouschromosomepair
Chromosomereplication
2n = 6
Parent cell
Prophase
Replicated chromosome
Metaphase Metaphase I
Anaphase ITelophase I
Haploid n = 3
Daughter cells ofmeiosis I
MEIOSIS II
Daughter cells of meiosis II
nnnn
2n2n
Daughter cellsof mitosis
AnaphaseTelophase
Compare
Contrast
Independent Assortment
Crossing-over Sexual Fertilization Mutation
Types of Changes to Cells Think About what where when how how much variation created
Warm-UP Now we need to keep track of the genes on the chromosomes that are inherited Notice the letters on the chromosomes They represent different alleles for Huntingtons Barbie has Huntingtons What is the chance her child will get Huntingtons
AP Test Money DUE 36 TOMORROWRemember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Tomorrow 141 5 Key Ideas AND Concept Check 1-3
H=dominant (remember Huntingtonrsquos is dominant)
h=recessive (no Huntingtonrsquos)
Homework DUE Monday Test Corrections for 10 Make-UP
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
AP Test Money DUE 36 TODAYRemember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
DUE next Thursday Monohybrid Crosses
Homework DUE Monday Test Corrections for 10 Make-UP
Warm-UP Now we need to keep track of TWO UNLINKED genes on the chromosomes that are inherited Notice the letters on the chromosomes They represent different alleles for Huntingtons and red hair color Barbie has Huntingtons and is a blond (but a carrier) Ken does not have Huntingtonrsquos and is also a carrier for red hair What is the chance their child will get Huntingtons and red hair
Homework DUE Tomorrow 142 5 Key Ideas AND Concept Check 1-3
H= Huntingtonrsquosh=no HuntingtonrsquosR= no red hairr= red hair
DUE Now Test Corrections for 10 Make-UP
UNIT 78 TEST March 19th
Inheritance and Regulation
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
Homework DUE Tomorrow 143 5 Key Ideas AND Concept Check 1-3
DUE Now 142DUE Thursday Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
UNIT 78 TEST March 19th
Inheritance and Regulation
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoods
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with RrYy
1 Chance of baby with Rr 052 Chance of baby with Yy 053 Chance of baby with RrYy 025
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with both dominant phenotypes
1 Chance of baby with at least one R 0752 Chance of baby with at least one Y 0753 Chance of baby with RrYy 05625 (916)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with both dominant phenotypes
1 Chance of baby with at least one R 10
2 Chance of baby with at least one Y 10
3 Chance of baby with both dominant phenotypes 10
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
Homework DUE Tomorrow Linked vs Unlinked Genes AND Monohybrid Crosses to tunritincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with
vestigial wings and cinnabar eyes Predict the phenotypic ratio of the F2 individuals
Homework DUE Tomorrow 153 5 Key Ideas and Concept Check 1-3DUE Thursday Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with vestigial wings and cinnabar eyes Predict the
phenotypic ratio of the F2 individuals
3 The results of the cross from 2 show the following outcome Individuals of each phenotype are shown in the table Which of the following is the most likely explanation of the results a The two genes are located on two different chromosomes b The two genes are sex-linked c The two genes are located on mitochondrial DNA d The two genes are linked on an autosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
1 Build your diploid cell (an homologous pair for each chromosome)a Draw a big cell with a nucleus insideb DRAW homologous pairs of chromosomes
bull 1 big blue 1 big redbull 1 small blue 1 small red
ndash Add genes to your chromosomebull Write an H and an R on big blue and an h and an r on big redbull Write a T on small blue and a t on small red
2 Clone each chromosome (DNA Replication) (making sister chromatids)3 Nucleus breaks down (erase it)4 Homologous pairs form a tetrad crossing over may occur (note do not model
crossing over for now)5 Finish meiosis (see notes for help)6 Nucleus grows around chromosomes 4 cells made (gametes which have half
the number of chromosomes (haploids)7 Repeat Steps 1-6 this time at Step 4 include ONE crossover event
Recombination Modeling
When yoursquore confident on the process show Mr Jones
bull When yoursquore confident on the process show Mr Jones
bull In your notebookFigure 1510 Recombination p295At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid crossing over recombinant chromosome independent assortment Meiosis I Meiosis II
Recombination Modeling
Analysis
1 How does recombination increase the variety of gametes formed
2 Which types of gametes were more likely Gametes with recombinant chromosomes or ones without
3 Recombination is a random process How might it benefithurt the survival of an individualspecies
Recombination Modeling
Warm-UP
1 How could you calculate recombination frequency2 What would the recombination frequency tell you about the relative position of
genes on a chromosome3 Genes A B and C are on the same chromosome Testcrosses show that the
recombination frequency between A and B is 28 and between A and C is 12 Can you determine the linear order of these genes
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP What can we learn about inheritance from looking at a pedigree (use example of the Royal Family of Europe from the early 1900s)
Warm-UP In the following human pedigree squares represent males circles represent females and shaded symbols indicate individuals affected with a disorder One of the affected males from the third generation has a child with a female who is a carrier For the pedigree shown which of the following best expresses the probability that the couplersquos first son will be affected with the disorder
(A) 25 (B) 50 (C) 75 (D) 100
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Is a widowrsquos peak a dominant or recessive trait
Is a widowrsquos peak a dominant or recessive trait
Fig 14-UN5
George
Sandra Tom Sam
Arlene
Wilma Ann Michael
Carla
Daniel Alan Tina
Christopher
A heterozygous tall and a homozygous purple flowered plant is crossed with a short and white flowered plant Predict the offspring Assume independent assortment
1
P=purplep=whiteT=tallt=short
For a plant with the genotype WwXxYyZz what is the probability that the plant will produce a gamete with a haploid genotype of Wxyz Give your answer as a fraction or as a value between 0 and 1 to four decimal places
2
A completely-plated stickleback from a marine population was mated to a low-plated stickleback from a freshwater population The resulting F1 hybrids all displayed a completely plated phenotype When the F1 hybrids were allowed to interbreed the resulting F2 generation included completely plated offspring and low-plated offspring in an approximate 31 ratio Which of the following conclusions is best supported by the results of the breeding experiments
a Phenotypic variation in the F2 generation suggests that armor morphology is controlled by many alleles of a single gene
b The completely-plated phenotype is controlled by a dominant allele of a single gene
c Armor loss is an acquired characteristic that is affected by one or more environmental factors
d Patterns of armor plating in stickleback populations are regulated by sex-specific signals
3
If a man with type AB blood marries a woman with type O what blood types would you expect in their children What fraction would you expect of each type
4
IA= Type AIB= Type Bi= Type O
If a King marries a Queen that is a carrier of hemophilia (sex-linked recessive disease that is historically fatal before adulthood) what is the chance of the Kingdom having an heir to the kingrsquos throne assuming only one child is born
5
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
7 Gregor Mendelrsquos pioneering genetic experiments with pea plants occurred before the discovery of the structure and function of chromosomes Which of the following observations about inheritance in pea plants could be explained only after the discovery that genes may be linked on a chromosome
a Pea color and pea shape display independent inheritance patterns b Offspring of a given cross show all possible combinations of traits in
equal proportions c Most offspring of a given cross have a combination of traits that is
identical to that of either one parent or the other d Recessive phenotypes can skip a generation showing up only in the
parental and F 2 generations
8
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Based on the data in Table I which of the following best explains why there are no individuals with constricted pods in the F 1 generation a Inflated pod shape is dominant to constricted pod shape b The inflated-pod offspring in the F sub one generation are
homozygous c Constricted pod shape typically arises from a new mutation in the F 1
generation d The constricted-pod offspring are carriers for the inflated pod shape
allele
9
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table I the ratio of phenotypes in the offspring from the testcross with F 1 plants that had purple flowers and inflated pods suggests that the genes for flower color and pod shape are located a close together on the same autosome b on the X chromosome c on different chromosomes d on a mitochondrial chromosome
10
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Which of the following provides the best justification for an assumption that might have been used in the computer simulation (Table II) a The broad allele is recessive to the narrow allele because broad
leaves appear in every generation b The purple allele is dominant to the white allele because all the
offspring from the cross of purple-flowered and white-flowered plants had purple flowers
c The narrow allele is codominant with the purple allele because the purple-flower trait and the narrow-leaf trait segregate together
d The white allele is dominant to both the broad and narrow alleles because plants with either type of leaf shape can have white flowers
11
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table II the F 1 offspring of the cross between broad-leaved white-flowered plants with narrow-leaved purple-flowered plants have a phenotype that differs from that of either parent However many testcross offspring have the same phenotype as one of the two plants in the parental cross but relatively few testcross offspring have the same phenotype as the F 1 offspring Which of the following best explains the observation a Recombination between the leaf-shape and flower-color genes resulted in
chromosomes carrying a dominant allele of both genes b Recombination between the broad and narrow alleles of the leaf-shape gene resulted in
chromosomes carrying three different alleles at the same genetic locus c Independent assortment of homologous chromosomes resulted in the combinations of
alleles present in the parental generation d The computer model cannot capture the possible assortments of gametes when
multiple genes are considered
In eukaryotic organisms heritable information is passed to the next generation via mitosis and
meiosisCell Division 2 Types
Meiosis sex cells (gametes) (spermeggs)bull Purpose
ensures that each gamete receives one complete haploid (1n) set of chromosomes
Ensures chromosome number stays the same each offspring receives frac12 (1n) of the full set for the species (2n)
bull Steps1 DNA Replication2 homologous pairs form a tetrad
(independent assortment) (genetic variation increases)
3 cross over between homologous chromosomes may occur (genetic variation increases)
4 Meiosis I homologous pairs separate5 Meiosis II sister chromatids separate
In eukaryotic organisms heritable information is passed to the next generation via mitosis and
meiosisCell Division 2 Types
Meiosis sex cells (gametes) (spermeggs)bull Purpose
ensures that each gamete receives one complete haploid (1n) set of chromosomes
Ensures chromosome number stays the same each offspring receives frac12 (1n) of the full set for the species (2n)
bull Steps1 DNA Replication2 homologous pairs form a tetrad
(independent assortment) (genetic variation increases)
3 cross over between homologous chromosomes may occur (genetic variation increases)
4 Meiosis I homologous pairs separate5 Meiosis II sister chromatids separate
In eukaryotic organisms heritable information is passed to the next generation via mitosis and
meiosisCell Division 2 Types
Meiosis sex cells (gametes) (spermeggs)bull Purpose
ensures that each gamete receives one complete haploid (1n) set of chromosomes
Ensures chromosome number stays the same each offspring receives frac12 (1n) of the full set for the species (2n)
bull Steps1 DNA Replication2 homologous pairs form a tetrad
(independent assortment) (genetic variation increases)
3 cross over between homologous chromosomes may occur (genetic variation increases)
4 Meiosis I homologous pairs separate5 Meiosis II sister chromatids separate
1 Build your diploid cell (an homologous pair for each chromosome)a Draw a big cell with a nucleus insideb Add homologous pairs of chromosomes
bull 1 big white 1 big yellowbull 1 medium white 1 medium yellowbull 1 small white 1 small yellow
2 Clone each chromosome (DNA Replication) (making sister chromatids)3 Nucleus breaks down (erase it)4 Homologous pairs form a tetrad crossing over may occur (note do not model crossing
over for now)5 Homologous pairs separate one to each side of cell all paternal (or all maternal) do NOT
have to go together (independent assortment)6 Cytokinesis cell membrane grows between the 2 halves7 Clones (sister chromatids) separate (centromere ldquobreaksrdquo as DNA polymerization
completes) one to each side of cell8 Cytokinesis cell membrane grows between the 2 halves9 Nucleus grows around chromosomes 4 cells made (gametes which have half the
number of chromosomes (haploids)
Meiosis Modeling
When yoursquore confident on the process show Mr Jones
Meiosis Modelingbull When yoursquore confident on the process show Mr Jones
bull In your notebookTable 138 Stages of Meiosis p255At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid crossing over recombinant chromosome independent assortment Meiosis I Meiosis II
Meiosis Modeling
Analysis
1 What is the outcome of meiosis2 What steps of meiosis cause variation3 If the first cell has 46 chromosomes (before
cloning) how many does each daughter cell have4 How many unique gametes did you form How
many could have formed5 Why do cells go through meiosis
Warm-UP 1 Why do meiosis2 How does meiosis increase variation in organisms
AP Test Money DUE 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Tomorrow Meiosis Wksht
UNIT 78 TEST March 19th
Inheritance and Regulation
Meiosis has multiple processes that increases genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Meiosis has multiple processes that increase genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Meiosis has multiple processes that increase genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Meiosis has multiple processes that increases genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Warm-UP Watch the video What is happening Why does this happen How does this increase variation
AP Test Money DUE TOMORROW 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Tomorrow
UNIT 78 TEST March 19th
Inheritance and Regulation
Fig 13-9a
MITOSIS MEIOSIS
MEIOSIS I
Prophase I
Chiasma
Chromosomereplication
Homologouschromosomepair
Chromosomereplication
2n = 6
Parent cell
Prophase
Replicated chromosome
Metaphase Metaphase I
Anaphase ITelophase I
Haploid n = 3
Daughter cells ofmeiosis I
MEIOSIS II
Daughter cells of meiosis II
nnnn
2n2n
Daughter cellsof mitosis
AnaphaseTelophase
Compare
Contrast
Independent Assortment
Crossing-over Sexual Fertilization Mutation
Types of Changes to Cells Think About what where when how how much variation created
Warm-UP Now we need to keep track of the genes on the chromosomes that are inherited Notice the letters on the chromosomes They represent different alleles for Huntingtons Barbie has Huntingtons What is the chance her child will get Huntingtons
AP Test Money DUE 36 TOMORROWRemember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Tomorrow 141 5 Key Ideas AND Concept Check 1-3
H=dominant (remember Huntingtonrsquos is dominant)
h=recessive (no Huntingtonrsquos)
Homework DUE Monday Test Corrections for 10 Make-UP
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
AP Test Money DUE 36 TODAYRemember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
DUE next Thursday Monohybrid Crosses
Homework DUE Monday Test Corrections for 10 Make-UP
Warm-UP Now we need to keep track of TWO UNLINKED genes on the chromosomes that are inherited Notice the letters on the chromosomes They represent different alleles for Huntingtons and red hair color Barbie has Huntingtons and is a blond (but a carrier) Ken does not have Huntingtonrsquos and is also a carrier for red hair What is the chance their child will get Huntingtons and red hair
Homework DUE Tomorrow 142 5 Key Ideas AND Concept Check 1-3
H= Huntingtonrsquosh=no HuntingtonrsquosR= no red hairr= red hair
DUE Now Test Corrections for 10 Make-UP
UNIT 78 TEST March 19th
Inheritance and Regulation
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
Homework DUE Tomorrow 143 5 Key Ideas AND Concept Check 1-3
DUE Now 142DUE Thursday Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
UNIT 78 TEST March 19th
Inheritance and Regulation
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoods
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with RrYy
1 Chance of baby with Rr 052 Chance of baby with Yy 053 Chance of baby with RrYy 025
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with both dominant phenotypes
1 Chance of baby with at least one R 0752 Chance of baby with at least one Y 0753 Chance of baby with RrYy 05625 (916)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with both dominant phenotypes
1 Chance of baby with at least one R 10
2 Chance of baby with at least one Y 10
3 Chance of baby with both dominant phenotypes 10
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
Homework DUE Tomorrow Linked vs Unlinked Genes AND Monohybrid Crosses to tunritincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with
vestigial wings and cinnabar eyes Predict the phenotypic ratio of the F2 individuals
Homework DUE Tomorrow 153 5 Key Ideas and Concept Check 1-3DUE Thursday Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with vestigial wings and cinnabar eyes Predict the
phenotypic ratio of the F2 individuals
3 The results of the cross from 2 show the following outcome Individuals of each phenotype are shown in the table Which of the following is the most likely explanation of the results a The two genes are located on two different chromosomes b The two genes are sex-linked c The two genes are located on mitochondrial DNA d The two genes are linked on an autosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
1 Build your diploid cell (an homologous pair for each chromosome)a Draw a big cell with a nucleus insideb DRAW homologous pairs of chromosomes
bull 1 big blue 1 big redbull 1 small blue 1 small red
ndash Add genes to your chromosomebull Write an H and an R on big blue and an h and an r on big redbull Write a T on small blue and a t on small red
2 Clone each chromosome (DNA Replication) (making sister chromatids)3 Nucleus breaks down (erase it)4 Homologous pairs form a tetrad crossing over may occur (note do not model
crossing over for now)5 Finish meiosis (see notes for help)6 Nucleus grows around chromosomes 4 cells made (gametes which have half
the number of chromosomes (haploids)7 Repeat Steps 1-6 this time at Step 4 include ONE crossover event
Recombination Modeling
When yoursquore confident on the process show Mr Jones
bull When yoursquore confident on the process show Mr Jones
bull In your notebookFigure 1510 Recombination p295At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid crossing over recombinant chromosome independent assortment Meiosis I Meiosis II
Recombination Modeling
Analysis
1 How does recombination increase the variety of gametes formed
2 Which types of gametes were more likely Gametes with recombinant chromosomes or ones without
3 Recombination is a random process How might it benefithurt the survival of an individualspecies
Recombination Modeling
Warm-UP
1 How could you calculate recombination frequency2 What would the recombination frequency tell you about the relative position of
genes on a chromosome3 Genes A B and C are on the same chromosome Testcrosses show that the
recombination frequency between A and B is 28 and between A and C is 12 Can you determine the linear order of these genes
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP What can we learn about inheritance from looking at a pedigree (use example of the Royal Family of Europe from the early 1900s)
Warm-UP In the following human pedigree squares represent males circles represent females and shaded symbols indicate individuals affected with a disorder One of the affected males from the third generation has a child with a female who is a carrier For the pedigree shown which of the following best expresses the probability that the couplersquos first son will be affected with the disorder
(A) 25 (B) 50 (C) 75 (D) 100
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Is a widowrsquos peak a dominant or recessive trait
Is a widowrsquos peak a dominant or recessive trait
Fig 14-UN5
George
Sandra Tom Sam
Arlene
Wilma Ann Michael
Carla
Daniel Alan Tina
Christopher
A heterozygous tall and a homozygous purple flowered plant is crossed with a short and white flowered plant Predict the offspring Assume independent assortment
1
P=purplep=whiteT=tallt=short
For a plant with the genotype WwXxYyZz what is the probability that the plant will produce a gamete with a haploid genotype of Wxyz Give your answer as a fraction or as a value between 0 and 1 to four decimal places
2
A completely-plated stickleback from a marine population was mated to a low-plated stickleback from a freshwater population The resulting F1 hybrids all displayed a completely plated phenotype When the F1 hybrids were allowed to interbreed the resulting F2 generation included completely plated offspring and low-plated offspring in an approximate 31 ratio Which of the following conclusions is best supported by the results of the breeding experiments
a Phenotypic variation in the F2 generation suggests that armor morphology is controlled by many alleles of a single gene
b The completely-plated phenotype is controlled by a dominant allele of a single gene
c Armor loss is an acquired characteristic that is affected by one or more environmental factors
d Patterns of armor plating in stickleback populations are regulated by sex-specific signals
3
If a man with type AB blood marries a woman with type O what blood types would you expect in their children What fraction would you expect of each type
4
IA= Type AIB= Type Bi= Type O
If a King marries a Queen that is a carrier of hemophilia (sex-linked recessive disease that is historically fatal before adulthood) what is the chance of the Kingdom having an heir to the kingrsquos throne assuming only one child is born
5
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
7 Gregor Mendelrsquos pioneering genetic experiments with pea plants occurred before the discovery of the structure and function of chromosomes Which of the following observations about inheritance in pea plants could be explained only after the discovery that genes may be linked on a chromosome
a Pea color and pea shape display independent inheritance patterns b Offspring of a given cross show all possible combinations of traits in
equal proportions c Most offspring of a given cross have a combination of traits that is
identical to that of either one parent or the other d Recessive phenotypes can skip a generation showing up only in the
parental and F 2 generations
8
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Based on the data in Table I which of the following best explains why there are no individuals with constricted pods in the F 1 generation a Inflated pod shape is dominant to constricted pod shape b The inflated-pod offspring in the F sub one generation are
homozygous c Constricted pod shape typically arises from a new mutation in the F 1
generation d The constricted-pod offspring are carriers for the inflated pod shape
allele
9
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table I the ratio of phenotypes in the offspring from the testcross with F 1 plants that had purple flowers and inflated pods suggests that the genes for flower color and pod shape are located a close together on the same autosome b on the X chromosome c on different chromosomes d on a mitochondrial chromosome
10
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Which of the following provides the best justification for an assumption that might have been used in the computer simulation (Table II) a The broad allele is recessive to the narrow allele because broad
leaves appear in every generation b The purple allele is dominant to the white allele because all the
offspring from the cross of purple-flowered and white-flowered plants had purple flowers
c The narrow allele is codominant with the purple allele because the purple-flower trait and the narrow-leaf trait segregate together
d The white allele is dominant to both the broad and narrow alleles because plants with either type of leaf shape can have white flowers
11
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table II the F 1 offspring of the cross between broad-leaved white-flowered plants with narrow-leaved purple-flowered plants have a phenotype that differs from that of either parent However many testcross offspring have the same phenotype as one of the two plants in the parental cross but relatively few testcross offspring have the same phenotype as the F 1 offspring Which of the following best explains the observation a Recombination between the leaf-shape and flower-color genes resulted in
chromosomes carrying a dominant allele of both genes b Recombination between the broad and narrow alleles of the leaf-shape gene resulted in
chromosomes carrying three different alleles at the same genetic locus c Independent assortment of homologous chromosomes resulted in the combinations of
alleles present in the parental generation d The computer model cannot capture the possible assortments of gametes when
multiple genes are considered
In eukaryotic organisms heritable information is passed to the next generation via mitosis and
meiosisCell Division 2 Types
Meiosis sex cells (gametes) (spermeggs)bull Purpose
ensures that each gamete receives one complete haploid (1n) set of chromosomes
Ensures chromosome number stays the same each offspring receives frac12 (1n) of the full set for the species (2n)
bull Steps1 DNA Replication2 homologous pairs form a tetrad
(independent assortment) (genetic variation increases)
3 cross over between homologous chromosomes may occur (genetic variation increases)
4 Meiosis I homologous pairs separate5 Meiosis II sister chromatids separate
In eukaryotic organisms heritable information is passed to the next generation via mitosis and
meiosisCell Division 2 Types
Meiosis sex cells (gametes) (spermeggs)bull Purpose
ensures that each gamete receives one complete haploid (1n) set of chromosomes
Ensures chromosome number stays the same each offspring receives frac12 (1n) of the full set for the species (2n)
bull Steps1 DNA Replication2 homologous pairs form a tetrad
(independent assortment) (genetic variation increases)
3 cross over between homologous chromosomes may occur (genetic variation increases)
4 Meiosis I homologous pairs separate5 Meiosis II sister chromatids separate
1 Build your diploid cell (an homologous pair for each chromosome)a Draw a big cell with a nucleus insideb Add homologous pairs of chromosomes
bull 1 big white 1 big yellowbull 1 medium white 1 medium yellowbull 1 small white 1 small yellow
2 Clone each chromosome (DNA Replication) (making sister chromatids)3 Nucleus breaks down (erase it)4 Homologous pairs form a tetrad crossing over may occur (note do not model crossing
over for now)5 Homologous pairs separate one to each side of cell all paternal (or all maternal) do NOT
have to go together (independent assortment)6 Cytokinesis cell membrane grows between the 2 halves7 Clones (sister chromatids) separate (centromere ldquobreaksrdquo as DNA polymerization
completes) one to each side of cell8 Cytokinesis cell membrane grows between the 2 halves9 Nucleus grows around chromosomes 4 cells made (gametes which have half the
number of chromosomes (haploids)
Meiosis Modeling
When yoursquore confident on the process show Mr Jones
Meiosis Modelingbull When yoursquore confident on the process show Mr Jones
bull In your notebookTable 138 Stages of Meiosis p255At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid crossing over recombinant chromosome independent assortment Meiosis I Meiosis II
Meiosis Modeling
Analysis
1 What is the outcome of meiosis2 What steps of meiosis cause variation3 If the first cell has 46 chromosomes (before
cloning) how many does each daughter cell have4 How many unique gametes did you form How
many could have formed5 Why do cells go through meiosis
Warm-UP 1 Why do meiosis2 How does meiosis increase variation in organisms
AP Test Money DUE 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Tomorrow Meiosis Wksht
UNIT 78 TEST March 19th
Inheritance and Regulation
Meiosis has multiple processes that increases genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Meiosis has multiple processes that increase genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Meiosis has multiple processes that increase genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Meiosis has multiple processes that increases genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Warm-UP Watch the video What is happening Why does this happen How does this increase variation
AP Test Money DUE TOMORROW 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Tomorrow
UNIT 78 TEST March 19th
Inheritance and Regulation
Fig 13-9a
MITOSIS MEIOSIS
MEIOSIS I
Prophase I
Chiasma
Chromosomereplication
Homologouschromosomepair
Chromosomereplication
2n = 6
Parent cell
Prophase
Replicated chromosome
Metaphase Metaphase I
Anaphase ITelophase I
Haploid n = 3
Daughter cells ofmeiosis I
MEIOSIS II
Daughter cells of meiosis II
nnnn
2n2n
Daughter cellsof mitosis
AnaphaseTelophase
Compare
Contrast
Independent Assortment
Crossing-over Sexual Fertilization Mutation
Types of Changes to Cells Think About what where when how how much variation created
Warm-UP Now we need to keep track of the genes on the chromosomes that are inherited Notice the letters on the chromosomes They represent different alleles for Huntingtons Barbie has Huntingtons What is the chance her child will get Huntingtons
AP Test Money DUE 36 TOMORROWRemember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Tomorrow 141 5 Key Ideas AND Concept Check 1-3
H=dominant (remember Huntingtonrsquos is dominant)
h=recessive (no Huntingtonrsquos)
Homework DUE Monday Test Corrections for 10 Make-UP
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
AP Test Money DUE 36 TODAYRemember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
DUE next Thursday Monohybrid Crosses
Homework DUE Monday Test Corrections for 10 Make-UP
Warm-UP Now we need to keep track of TWO UNLINKED genes on the chromosomes that are inherited Notice the letters on the chromosomes They represent different alleles for Huntingtons and red hair color Barbie has Huntingtons and is a blond (but a carrier) Ken does not have Huntingtonrsquos and is also a carrier for red hair What is the chance their child will get Huntingtons and red hair
Homework DUE Tomorrow 142 5 Key Ideas AND Concept Check 1-3
H= Huntingtonrsquosh=no HuntingtonrsquosR= no red hairr= red hair
DUE Now Test Corrections for 10 Make-UP
UNIT 78 TEST March 19th
Inheritance and Regulation
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
Homework DUE Tomorrow 143 5 Key Ideas AND Concept Check 1-3
DUE Now 142DUE Thursday Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
UNIT 78 TEST March 19th
Inheritance and Regulation
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoods
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with RrYy
1 Chance of baby with Rr 052 Chance of baby with Yy 053 Chance of baby with RrYy 025
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with both dominant phenotypes
1 Chance of baby with at least one R 0752 Chance of baby with at least one Y 0753 Chance of baby with RrYy 05625 (916)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with both dominant phenotypes
1 Chance of baby with at least one R 10
2 Chance of baby with at least one Y 10
3 Chance of baby with both dominant phenotypes 10
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
Homework DUE Tomorrow Linked vs Unlinked Genes AND Monohybrid Crosses to tunritincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with
vestigial wings and cinnabar eyes Predict the phenotypic ratio of the F2 individuals
Homework DUE Tomorrow 153 5 Key Ideas and Concept Check 1-3DUE Thursday Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with vestigial wings and cinnabar eyes Predict the
phenotypic ratio of the F2 individuals
3 The results of the cross from 2 show the following outcome Individuals of each phenotype are shown in the table Which of the following is the most likely explanation of the results a The two genes are located on two different chromosomes b The two genes are sex-linked c The two genes are located on mitochondrial DNA d The two genes are linked on an autosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
1 Build your diploid cell (an homologous pair for each chromosome)a Draw a big cell with a nucleus insideb DRAW homologous pairs of chromosomes
bull 1 big blue 1 big redbull 1 small blue 1 small red
ndash Add genes to your chromosomebull Write an H and an R on big blue and an h and an r on big redbull Write a T on small blue and a t on small red
2 Clone each chromosome (DNA Replication) (making sister chromatids)3 Nucleus breaks down (erase it)4 Homologous pairs form a tetrad crossing over may occur (note do not model
crossing over for now)5 Finish meiosis (see notes for help)6 Nucleus grows around chromosomes 4 cells made (gametes which have half
the number of chromosomes (haploids)7 Repeat Steps 1-6 this time at Step 4 include ONE crossover event
Recombination Modeling
When yoursquore confident on the process show Mr Jones
bull When yoursquore confident on the process show Mr Jones
bull In your notebookFigure 1510 Recombination p295At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid crossing over recombinant chromosome independent assortment Meiosis I Meiosis II
Recombination Modeling
Analysis
1 How does recombination increase the variety of gametes formed
2 Which types of gametes were more likely Gametes with recombinant chromosomes or ones without
3 Recombination is a random process How might it benefithurt the survival of an individualspecies
Recombination Modeling
Warm-UP
1 How could you calculate recombination frequency2 What would the recombination frequency tell you about the relative position of
genes on a chromosome3 Genes A B and C are on the same chromosome Testcrosses show that the
recombination frequency between A and B is 28 and between A and C is 12 Can you determine the linear order of these genes
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP What can we learn about inheritance from looking at a pedigree (use example of the Royal Family of Europe from the early 1900s)
Warm-UP In the following human pedigree squares represent males circles represent females and shaded symbols indicate individuals affected with a disorder One of the affected males from the third generation has a child with a female who is a carrier For the pedigree shown which of the following best expresses the probability that the couplersquos first son will be affected with the disorder
(A) 25 (B) 50 (C) 75 (D) 100
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Is a widowrsquos peak a dominant or recessive trait
Is a widowrsquos peak a dominant or recessive trait
Fig 14-UN5
George
Sandra Tom Sam
Arlene
Wilma Ann Michael
Carla
Daniel Alan Tina
Christopher
A heterozygous tall and a homozygous purple flowered plant is crossed with a short and white flowered plant Predict the offspring Assume independent assortment
1
P=purplep=whiteT=tallt=short
For a plant with the genotype WwXxYyZz what is the probability that the plant will produce a gamete with a haploid genotype of Wxyz Give your answer as a fraction or as a value between 0 and 1 to four decimal places
2
A completely-plated stickleback from a marine population was mated to a low-plated stickleback from a freshwater population The resulting F1 hybrids all displayed a completely plated phenotype When the F1 hybrids were allowed to interbreed the resulting F2 generation included completely plated offspring and low-plated offspring in an approximate 31 ratio Which of the following conclusions is best supported by the results of the breeding experiments
a Phenotypic variation in the F2 generation suggests that armor morphology is controlled by many alleles of a single gene
b The completely-plated phenotype is controlled by a dominant allele of a single gene
c Armor loss is an acquired characteristic that is affected by one or more environmental factors
d Patterns of armor plating in stickleback populations are regulated by sex-specific signals
3
If a man with type AB blood marries a woman with type O what blood types would you expect in their children What fraction would you expect of each type
4
IA= Type AIB= Type Bi= Type O
If a King marries a Queen that is a carrier of hemophilia (sex-linked recessive disease that is historically fatal before adulthood) what is the chance of the Kingdom having an heir to the kingrsquos throne assuming only one child is born
5
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
7 Gregor Mendelrsquos pioneering genetic experiments with pea plants occurred before the discovery of the structure and function of chromosomes Which of the following observations about inheritance in pea plants could be explained only after the discovery that genes may be linked on a chromosome
a Pea color and pea shape display independent inheritance patterns b Offspring of a given cross show all possible combinations of traits in
equal proportions c Most offspring of a given cross have a combination of traits that is
identical to that of either one parent or the other d Recessive phenotypes can skip a generation showing up only in the
parental and F 2 generations
8
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Based on the data in Table I which of the following best explains why there are no individuals with constricted pods in the F 1 generation a Inflated pod shape is dominant to constricted pod shape b The inflated-pod offspring in the F sub one generation are
homozygous c Constricted pod shape typically arises from a new mutation in the F 1
generation d The constricted-pod offspring are carriers for the inflated pod shape
allele
9
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table I the ratio of phenotypes in the offspring from the testcross with F 1 plants that had purple flowers and inflated pods suggests that the genes for flower color and pod shape are located a close together on the same autosome b on the X chromosome c on different chromosomes d on a mitochondrial chromosome
10
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Which of the following provides the best justification for an assumption that might have been used in the computer simulation (Table II) a The broad allele is recessive to the narrow allele because broad
leaves appear in every generation b The purple allele is dominant to the white allele because all the
offspring from the cross of purple-flowered and white-flowered plants had purple flowers
c The narrow allele is codominant with the purple allele because the purple-flower trait and the narrow-leaf trait segregate together
d The white allele is dominant to both the broad and narrow alleles because plants with either type of leaf shape can have white flowers
11
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table II the F 1 offspring of the cross between broad-leaved white-flowered plants with narrow-leaved purple-flowered plants have a phenotype that differs from that of either parent However many testcross offspring have the same phenotype as one of the two plants in the parental cross but relatively few testcross offspring have the same phenotype as the F 1 offspring Which of the following best explains the observation a Recombination between the leaf-shape and flower-color genes resulted in
chromosomes carrying a dominant allele of both genes b Recombination between the broad and narrow alleles of the leaf-shape gene resulted in
chromosomes carrying three different alleles at the same genetic locus c Independent assortment of homologous chromosomes resulted in the combinations of
alleles present in the parental generation d The computer model cannot capture the possible assortments of gametes when
multiple genes are considered
In eukaryotic organisms heritable information is passed to the next generation via mitosis and
meiosisCell Division 2 Types
Meiosis sex cells (gametes) (spermeggs)bull Purpose
ensures that each gamete receives one complete haploid (1n) set of chromosomes
Ensures chromosome number stays the same each offspring receives frac12 (1n) of the full set for the species (2n)
bull Steps1 DNA Replication2 homologous pairs form a tetrad
(independent assortment) (genetic variation increases)
3 cross over between homologous chromosomes may occur (genetic variation increases)
4 Meiosis I homologous pairs separate5 Meiosis II sister chromatids separate
1 Build your diploid cell (an homologous pair for each chromosome)a Draw a big cell with a nucleus insideb Add homologous pairs of chromosomes
bull 1 big white 1 big yellowbull 1 medium white 1 medium yellowbull 1 small white 1 small yellow
2 Clone each chromosome (DNA Replication) (making sister chromatids)3 Nucleus breaks down (erase it)4 Homologous pairs form a tetrad crossing over may occur (note do not model crossing
over for now)5 Homologous pairs separate one to each side of cell all paternal (or all maternal) do NOT
have to go together (independent assortment)6 Cytokinesis cell membrane grows between the 2 halves7 Clones (sister chromatids) separate (centromere ldquobreaksrdquo as DNA polymerization
completes) one to each side of cell8 Cytokinesis cell membrane grows between the 2 halves9 Nucleus grows around chromosomes 4 cells made (gametes which have half the
number of chromosomes (haploids)
Meiosis Modeling
When yoursquore confident on the process show Mr Jones
Meiosis Modelingbull When yoursquore confident on the process show Mr Jones
bull In your notebookTable 138 Stages of Meiosis p255At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid crossing over recombinant chromosome independent assortment Meiosis I Meiosis II
Meiosis Modeling
Analysis
1 What is the outcome of meiosis2 What steps of meiosis cause variation3 If the first cell has 46 chromosomes (before
cloning) how many does each daughter cell have4 How many unique gametes did you form How
many could have formed5 Why do cells go through meiosis
Warm-UP 1 Why do meiosis2 How does meiosis increase variation in organisms
AP Test Money DUE 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Tomorrow Meiosis Wksht
UNIT 78 TEST March 19th
Inheritance and Regulation
Meiosis has multiple processes that increases genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Meiosis has multiple processes that increase genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Meiosis has multiple processes that increase genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Meiosis has multiple processes that increases genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Warm-UP Watch the video What is happening Why does this happen How does this increase variation
AP Test Money DUE TOMORROW 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Tomorrow
UNIT 78 TEST March 19th
Inheritance and Regulation
Fig 13-9a
MITOSIS MEIOSIS
MEIOSIS I
Prophase I
Chiasma
Chromosomereplication
Homologouschromosomepair
Chromosomereplication
2n = 6
Parent cell
Prophase
Replicated chromosome
Metaphase Metaphase I
Anaphase ITelophase I
Haploid n = 3
Daughter cells ofmeiosis I
MEIOSIS II
Daughter cells of meiosis II
nnnn
2n2n
Daughter cellsof mitosis
AnaphaseTelophase
Compare
Contrast
Independent Assortment
Crossing-over Sexual Fertilization Mutation
Types of Changes to Cells Think About what where when how how much variation created
Warm-UP Now we need to keep track of the genes on the chromosomes that are inherited Notice the letters on the chromosomes They represent different alleles for Huntingtons Barbie has Huntingtons What is the chance her child will get Huntingtons
AP Test Money DUE 36 TOMORROWRemember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Tomorrow 141 5 Key Ideas AND Concept Check 1-3
H=dominant (remember Huntingtonrsquos is dominant)
h=recessive (no Huntingtonrsquos)
Homework DUE Monday Test Corrections for 10 Make-UP
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
AP Test Money DUE 36 TODAYRemember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
DUE next Thursday Monohybrid Crosses
Homework DUE Monday Test Corrections for 10 Make-UP
Warm-UP Now we need to keep track of TWO UNLINKED genes on the chromosomes that are inherited Notice the letters on the chromosomes They represent different alleles for Huntingtons and red hair color Barbie has Huntingtons and is a blond (but a carrier) Ken does not have Huntingtonrsquos and is also a carrier for red hair What is the chance their child will get Huntingtons and red hair
Homework DUE Tomorrow 142 5 Key Ideas AND Concept Check 1-3
H= Huntingtonrsquosh=no HuntingtonrsquosR= no red hairr= red hair
DUE Now Test Corrections for 10 Make-UP
UNIT 78 TEST March 19th
Inheritance and Regulation
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
Homework DUE Tomorrow 143 5 Key Ideas AND Concept Check 1-3
DUE Now 142DUE Thursday Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
UNIT 78 TEST March 19th
Inheritance and Regulation
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoods
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with RrYy
1 Chance of baby with Rr 052 Chance of baby with Yy 053 Chance of baby with RrYy 025
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with both dominant phenotypes
1 Chance of baby with at least one R 0752 Chance of baby with at least one Y 0753 Chance of baby with RrYy 05625 (916)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with both dominant phenotypes
1 Chance of baby with at least one R 10
2 Chance of baby with at least one Y 10
3 Chance of baby with both dominant phenotypes 10
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
Homework DUE Tomorrow Linked vs Unlinked Genes AND Monohybrid Crosses to tunritincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with
vestigial wings and cinnabar eyes Predict the phenotypic ratio of the F2 individuals
Homework DUE Tomorrow 153 5 Key Ideas and Concept Check 1-3DUE Thursday Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with vestigial wings and cinnabar eyes Predict the
phenotypic ratio of the F2 individuals
3 The results of the cross from 2 show the following outcome Individuals of each phenotype are shown in the table Which of the following is the most likely explanation of the results a The two genes are located on two different chromosomes b The two genes are sex-linked c The two genes are located on mitochondrial DNA d The two genes are linked on an autosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
1 Build your diploid cell (an homologous pair for each chromosome)a Draw a big cell with a nucleus insideb DRAW homologous pairs of chromosomes
bull 1 big blue 1 big redbull 1 small blue 1 small red
ndash Add genes to your chromosomebull Write an H and an R on big blue and an h and an r on big redbull Write a T on small blue and a t on small red
2 Clone each chromosome (DNA Replication) (making sister chromatids)3 Nucleus breaks down (erase it)4 Homologous pairs form a tetrad crossing over may occur (note do not model
crossing over for now)5 Finish meiosis (see notes for help)6 Nucleus grows around chromosomes 4 cells made (gametes which have half
the number of chromosomes (haploids)7 Repeat Steps 1-6 this time at Step 4 include ONE crossover event
Recombination Modeling
When yoursquore confident on the process show Mr Jones
bull When yoursquore confident on the process show Mr Jones
bull In your notebookFigure 1510 Recombination p295At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid crossing over recombinant chromosome independent assortment Meiosis I Meiosis II
Recombination Modeling
Analysis
1 How does recombination increase the variety of gametes formed
2 Which types of gametes were more likely Gametes with recombinant chromosomes or ones without
3 Recombination is a random process How might it benefithurt the survival of an individualspecies
Recombination Modeling
Warm-UP
1 How could you calculate recombination frequency2 What would the recombination frequency tell you about the relative position of
genes on a chromosome3 Genes A B and C are on the same chromosome Testcrosses show that the
recombination frequency between A and B is 28 and between A and C is 12 Can you determine the linear order of these genes
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP What can we learn about inheritance from looking at a pedigree (use example of the Royal Family of Europe from the early 1900s)
Warm-UP In the following human pedigree squares represent males circles represent females and shaded symbols indicate individuals affected with a disorder One of the affected males from the third generation has a child with a female who is a carrier For the pedigree shown which of the following best expresses the probability that the couplersquos first son will be affected with the disorder
(A) 25 (B) 50 (C) 75 (D) 100
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Is a widowrsquos peak a dominant or recessive trait
Is a widowrsquos peak a dominant or recessive trait
Fig 14-UN5
George
Sandra Tom Sam
Arlene
Wilma Ann Michael
Carla
Daniel Alan Tina
Christopher
A heterozygous tall and a homozygous purple flowered plant is crossed with a short and white flowered plant Predict the offspring Assume independent assortment
1
P=purplep=whiteT=tallt=short
For a plant with the genotype WwXxYyZz what is the probability that the plant will produce a gamete with a haploid genotype of Wxyz Give your answer as a fraction or as a value between 0 and 1 to four decimal places
2
A completely-plated stickleback from a marine population was mated to a low-plated stickleback from a freshwater population The resulting F1 hybrids all displayed a completely plated phenotype When the F1 hybrids were allowed to interbreed the resulting F2 generation included completely plated offspring and low-plated offspring in an approximate 31 ratio Which of the following conclusions is best supported by the results of the breeding experiments
a Phenotypic variation in the F2 generation suggests that armor morphology is controlled by many alleles of a single gene
b The completely-plated phenotype is controlled by a dominant allele of a single gene
c Armor loss is an acquired characteristic that is affected by one or more environmental factors
d Patterns of armor plating in stickleback populations are regulated by sex-specific signals
3
If a man with type AB blood marries a woman with type O what blood types would you expect in their children What fraction would you expect of each type
4
IA= Type AIB= Type Bi= Type O
If a King marries a Queen that is a carrier of hemophilia (sex-linked recessive disease that is historically fatal before adulthood) what is the chance of the Kingdom having an heir to the kingrsquos throne assuming only one child is born
5
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
7 Gregor Mendelrsquos pioneering genetic experiments with pea plants occurred before the discovery of the structure and function of chromosomes Which of the following observations about inheritance in pea plants could be explained only after the discovery that genes may be linked on a chromosome
a Pea color and pea shape display independent inheritance patterns b Offspring of a given cross show all possible combinations of traits in
equal proportions c Most offspring of a given cross have a combination of traits that is
identical to that of either one parent or the other d Recessive phenotypes can skip a generation showing up only in the
parental and F 2 generations
8
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Based on the data in Table I which of the following best explains why there are no individuals with constricted pods in the F 1 generation a Inflated pod shape is dominant to constricted pod shape b The inflated-pod offspring in the F sub one generation are
homozygous c Constricted pod shape typically arises from a new mutation in the F 1
generation d The constricted-pod offspring are carriers for the inflated pod shape
allele
9
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table I the ratio of phenotypes in the offspring from the testcross with F 1 plants that had purple flowers and inflated pods suggests that the genes for flower color and pod shape are located a close together on the same autosome b on the X chromosome c on different chromosomes d on a mitochondrial chromosome
10
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Which of the following provides the best justification for an assumption that might have been used in the computer simulation (Table II) a The broad allele is recessive to the narrow allele because broad
leaves appear in every generation b The purple allele is dominant to the white allele because all the
offspring from the cross of purple-flowered and white-flowered plants had purple flowers
c The narrow allele is codominant with the purple allele because the purple-flower trait and the narrow-leaf trait segregate together
d The white allele is dominant to both the broad and narrow alleles because plants with either type of leaf shape can have white flowers
11
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table II the F 1 offspring of the cross between broad-leaved white-flowered plants with narrow-leaved purple-flowered plants have a phenotype that differs from that of either parent However many testcross offspring have the same phenotype as one of the two plants in the parental cross but relatively few testcross offspring have the same phenotype as the F 1 offspring Which of the following best explains the observation a Recombination between the leaf-shape and flower-color genes resulted in
chromosomes carrying a dominant allele of both genes b Recombination between the broad and narrow alleles of the leaf-shape gene resulted in
chromosomes carrying three different alleles at the same genetic locus c Independent assortment of homologous chromosomes resulted in the combinations of
alleles present in the parental generation d The computer model cannot capture the possible assortments of gametes when
multiple genes are considered
1 Build your diploid cell (an homologous pair for each chromosome)a Draw a big cell with a nucleus insideb Add homologous pairs of chromosomes
bull 1 big white 1 big yellowbull 1 medium white 1 medium yellowbull 1 small white 1 small yellow
2 Clone each chromosome (DNA Replication) (making sister chromatids)3 Nucleus breaks down (erase it)4 Homologous pairs form a tetrad crossing over may occur (note do not model crossing
over for now)5 Homologous pairs separate one to each side of cell all paternal (or all maternal) do NOT
have to go together (independent assortment)6 Cytokinesis cell membrane grows between the 2 halves7 Clones (sister chromatids) separate (centromere ldquobreaksrdquo as DNA polymerization
completes) one to each side of cell8 Cytokinesis cell membrane grows between the 2 halves9 Nucleus grows around chromosomes 4 cells made (gametes which have half the
number of chromosomes (haploids)
Meiosis Modeling
When yoursquore confident on the process show Mr Jones
Meiosis Modelingbull When yoursquore confident on the process show Mr Jones
bull In your notebookTable 138 Stages of Meiosis p255At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid crossing over recombinant chromosome independent assortment Meiosis I Meiosis II
Meiosis Modeling
Analysis
1 What is the outcome of meiosis2 What steps of meiosis cause variation3 If the first cell has 46 chromosomes (before
cloning) how many does each daughter cell have4 How many unique gametes did you form How
many could have formed5 Why do cells go through meiosis
Warm-UP 1 Why do meiosis2 How does meiosis increase variation in organisms
AP Test Money DUE 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Tomorrow Meiosis Wksht
UNIT 78 TEST March 19th
Inheritance and Regulation
Meiosis has multiple processes that increases genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Meiosis has multiple processes that increase genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Meiosis has multiple processes that increase genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Meiosis has multiple processes that increases genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Warm-UP Watch the video What is happening Why does this happen How does this increase variation
AP Test Money DUE TOMORROW 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Tomorrow
UNIT 78 TEST March 19th
Inheritance and Regulation
Fig 13-9a
MITOSIS MEIOSIS
MEIOSIS I
Prophase I
Chiasma
Chromosomereplication
Homologouschromosomepair
Chromosomereplication
2n = 6
Parent cell
Prophase
Replicated chromosome
Metaphase Metaphase I
Anaphase ITelophase I
Haploid n = 3
Daughter cells ofmeiosis I
MEIOSIS II
Daughter cells of meiosis II
nnnn
2n2n
Daughter cellsof mitosis
AnaphaseTelophase
Compare
Contrast
Independent Assortment
Crossing-over Sexual Fertilization Mutation
Types of Changes to Cells Think About what where when how how much variation created
Warm-UP Now we need to keep track of the genes on the chromosomes that are inherited Notice the letters on the chromosomes They represent different alleles for Huntingtons Barbie has Huntingtons What is the chance her child will get Huntingtons
AP Test Money DUE 36 TOMORROWRemember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Tomorrow 141 5 Key Ideas AND Concept Check 1-3
H=dominant (remember Huntingtonrsquos is dominant)
h=recessive (no Huntingtonrsquos)
Homework DUE Monday Test Corrections for 10 Make-UP
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
AP Test Money DUE 36 TODAYRemember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
DUE next Thursday Monohybrid Crosses
Homework DUE Monday Test Corrections for 10 Make-UP
Warm-UP Now we need to keep track of TWO UNLINKED genes on the chromosomes that are inherited Notice the letters on the chromosomes They represent different alleles for Huntingtons and red hair color Barbie has Huntingtons and is a blond (but a carrier) Ken does not have Huntingtonrsquos and is also a carrier for red hair What is the chance their child will get Huntingtons and red hair
Homework DUE Tomorrow 142 5 Key Ideas AND Concept Check 1-3
H= Huntingtonrsquosh=no HuntingtonrsquosR= no red hairr= red hair
DUE Now Test Corrections for 10 Make-UP
UNIT 78 TEST March 19th
Inheritance and Regulation
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
Homework DUE Tomorrow 143 5 Key Ideas AND Concept Check 1-3
DUE Now 142DUE Thursday Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
UNIT 78 TEST March 19th
Inheritance and Regulation
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoods
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with RrYy
1 Chance of baby with Rr 052 Chance of baby with Yy 053 Chance of baby with RrYy 025
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with both dominant phenotypes
1 Chance of baby with at least one R 0752 Chance of baby with at least one Y 0753 Chance of baby with RrYy 05625 (916)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with both dominant phenotypes
1 Chance of baby with at least one R 10
2 Chance of baby with at least one Y 10
3 Chance of baby with both dominant phenotypes 10
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
Homework DUE Tomorrow Linked vs Unlinked Genes AND Monohybrid Crosses to tunritincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with
vestigial wings and cinnabar eyes Predict the phenotypic ratio of the F2 individuals
Homework DUE Tomorrow 153 5 Key Ideas and Concept Check 1-3DUE Thursday Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with vestigial wings and cinnabar eyes Predict the
phenotypic ratio of the F2 individuals
3 The results of the cross from 2 show the following outcome Individuals of each phenotype are shown in the table Which of the following is the most likely explanation of the results a The two genes are located on two different chromosomes b The two genes are sex-linked c The two genes are located on mitochondrial DNA d The two genes are linked on an autosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
1 Build your diploid cell (an homologous pair for each chromosome)a Draw a big cell with a nucleus insideb DRAW homologous pairs of chromosomes
bull 1 big blue 1 big redbull 1 small blue 1 small red
ndash Add genes to your chromosomebull Write an H and an R on big blue and an h and an r on big redbull Write a T on small blue and a t on small red
2 Clone each chromosome (DNA Replication) (making sister chromatids)3 Nucleus breaks down (erase it)4 Homologous pairs form a tetrad crossing over may occur (note do not model
crossing over for now)5 Finish meiosis (see notes for help)6 Nucleus grows around chromosomes 4 cells made (gametes which have half
the number of chromosomes (haploids)7 Repeat Steps 1-6 this time at Step 4 include ONE crossover event
Recombination Modeling
When yoursquore confident on the process show Mr Jones
bull When yoursquore confident on the process show Mr Jones
bull In your notebookFigure 1510 Recombination p295At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid crossing over recombinant chromosome independent assortment Meiosis I Meiosis II
Recombination Modeling
Analysis
1 How does recombination increase the variety of gametes formed
2 Which types of gametes were more likely Gametes with recombinant chromosomes or ones without
3 Recombination is a random process How might it benefithurt the survival of an individualspecies
Recombination Modeling
Warm-UP
1 How could you calculate recombination frequency2 What would the recombination frequency tell you about the relative position of
genes on a chromosome3 Genes A B and C are on the same chromosome Testcrosses show that the
recombination frequency between A and B is 28 and between A and C is 12 Can you determine the linear order of these genes
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP What can we learn about inheritance from looking at a pedigree (use example of the Royal Family of Europe from the early 1900s)
Warm-UP In the following human pedigree squares represent males circles represent females and shaded symbols indicate individuals affected with a disorder One of the affected males from the third generation has a child with a female who is a carrier For the pedigree shown which of the following best expresses the probability that the couplersquos first son will be affected with the disorder
(A) 25 (B) 50 (C) 75 (D) 100
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Is a widowrsquos peak a dominant or recessive trait
Is a widowrsquos peak a dominant or recessive trait
Fig 14-UN5
George
Sandra Tom Sam
Arlene
Wilma Ann Michael
Carla
Daniel Alan Tina
Christopher
A heterozygous tall and a homozygous purple flowered plant is crossed with a short and white flowered plant Predict the offspring Assume independent assortment
1
P=purplep=whiteT=tallt=short
For a plant with the genotype WwXxYyZz what is the probability that the plant will produce a gamete with a haploid genotype of Wxyz Give your answer as a fraction or as a value between 0 and 1 to four decimal places
2
A completely-plated stickleback from a marine population was mated to a low-plated stickleback from a freshwater population The resulting F1 hybrids all displayed a completely plated phenotype When the F1 hybrids were allowed to interbreed the resulting F2 generation included completely plated offspring and low-plated offspring in an approximate 31 ratio Which of the following conclusions is best supported by the results of the breeding experiments
a Phenotypic variation in the F2 generation suggests that armor morphology is controlled by many alleles of a single gene
b The completely-plated phenotype is controlled by a dominant allele of a single gene
c Armor loss is an acquired characteristic that is affected by one or more environmental factors
d Patterns of armor plating in stickleback populations are regulated by sex-specific signals
3
If a man with type AB blood marries a woman with type O what blood types would you expect in their children What fraction would you expect of each type
4
IA= Type AIB= Type Bi= Type O
If a King marries a Queen that is a carrier of hemophilia (sex-linked recessive disease that is historically fatal before adulthood) what is the chance of the Kingdom having an heir to the kingrsquos throne assuming only one child is born
5
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
7 Gregor Mendelrsquos pioneering genetic experiments with pea plants occurred before the discovery of the structure and function of chromosomes Which of the following observations about inheritance in pea plants could be explained only after the discovery that genes may be linked on a chromosome
a Pea color and pea shape display independent inheritance patterns b Offspring of a given cross show all possible combinations of traits in
equal proportions c Most offspring of a given cross have a combination of traits that is
identical to that of either one parent or the other d Recessive phenotypes can skip a generation showing up only in the
parental and F 2 generations
8
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Based on the data in Table I which of the following best explains why there are no individuals with constricted pods in the F 1 generation a Inflated pod shape is dominant to constricted pod shape b The inflated-pod offspring in the F sub one generation are
homozygous c Constricted pod shape typically arises from a new mutation in the F 1
generation d The constricted-pod offspring are carriers for the inflated pod shape
allele
9
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table I the ratio of phenotypes in the offspring from the testcross with F 1 plants that had purple flowers and inflated pods suggests that the genes for flower color and pod shape are located a close together on the same autosome b on the X chromosome c on different chromosomes d on a mitochondrial chromosome
10
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Which of the following provides the best justification for an assumption that might have been used in the computer simulation (Table II) a The broad allele is recessive to the narrow allele because broad
leaves appear in every generation b The purple allele is dominant to the white allele because all the
offspring from the cross of purple-flowered and white-flowered plants had purple flowers
c The narrow allele is codominant with the purple allele because the purple-flower trait and the narrow-leaf trait segregate together
d The white allele is dominant to both the broad and narrow alleles because plants with either type of leaf shape can have white flowers
11
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table II the F 1 offspring of the cross between broad-leaved white-flowered plants with narrow-leaved purple-flowered plants have a phenotype that differs from that of either parent However many testcross offspring have the same phenotype as one of the two plants in the parental cross but relatively few testcross offspring have the same phenotype as the F 1 offspring Which of the following best explains the observation a Recombination between the leaf-shape and flower-color genes resulted in
chromosomes carrying a dominant allele of both genes b Recombination between the broad and narrow alleles of the leaf-shape gene resulted in
chromosomes carrying three different alleles at the same genetic locus c Independent assortment of homologous chromosomes resulted in the combinations of
alleles present in the parental generation d The computer model cannot capture the possible assortments of gametes when
multiple genes are considered
Meiosis Modelingbull When yoursquore confident on the process show Mr Jones
bull In your notebookTable 138 Stages of Meiosis p255At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid crossing over recombinant chromosome independent assortment Meiosis I Meiosis II
Meiosis Modeling
Analysis
1 What is the outcome of meiosis2 What steps of meiosis cause variation3 If the first cell has 46 chromosomes (before
cloning) how many does each daughter cell have4 How many unique gametes did you form How
many could have formed5 Why do cells go through meiosis
Warm-UP 1 Why do meiosis2 How does meiosis increase variation in organisms
AP Test Money DUE 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Tomorrow Meiosis Wksht
UNIT 78 TEST March 19th
Inheritance and Regulation
Meiosis has multiple processes that increases genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Meiosis has multiple processes that increase genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Meiosis has multiple processes that increase genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Meiosis has multiple processes that increases genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Warm-UP Watch the video What is happening Why does this happen How does this increase variation
AP Test Money DUE TOMORROW 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Tomorrow
UNIT 78 TEST March 19th
Inheritance and Regulation
Fig 13-9a
MITOSIS MEIOSIS
MEIOSIS I
Prophase I
Chiasma
Chromosomereplication
Homologouschromosomepair
Chromosomereplication
2n = 6
Parent cell
Prophase
Replicated chromosome
Metaphase Metaphase I
Anaphase ITelophase I
Haploid n = 3
Daughter cells ofmeiosis I
MEIOSIS II
Daughter cells of meiosis II
nnnn
2n2n
Daughter cellsof mitosis
AnaphaseTelophase
Compare
Contrast
Independent Assortment
Crossing-over Sexual Fertilization Mutation
Types of Changes to Cells Think About what where when how how much variation created
Warm-UP Now we need to keep track of the genes on the chromosomes that are inherited Notice the letters on the chromosomes They represent different alleles for Huntingtons Barbie has Huntingtons What is the chance her child will get Huntingtons
AP Test Money DUE 36 TOMORROWRemember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Tomorrow 141 5 Key Ideas AND Concept Check 1-3
H=dominant (remember Huntingtonrsquos is dominant)
h=recessive (no Huntingtonrsquos)
Homework DUE Monday Test Corrections for 10 Make-UP
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
AP Test Money DUE 36 TODAYRemember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
DUE next Thursday Monohybrid Crosses
Homework DUE Monday Test Corrections for 10 Make-UP
Warm-UP Now we need to keep track of TWO UNLINKED genes on the chromosomes that are inherited Notice the letters on the chromosomes They represent different alleles for Huntingtons and red hair color Barbie has Huntingtons and is a blond (but a carrier) Ken does not have Huntingtonrsquos and is also a carrier for red hair What is the chance their child will get Huntingtons and red hair
Homework DUE Tomorrow 142 5 Key Ideas AND Concept Check 1-3
H= Huntingtonrsquosh=no HuntingtonrsquosR= no red hairr= red hair
DUE Now Test Corrections for 10 Make-UP
UNIT 78 TEST March 19th
Inheritance and Regulation
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
Homework DUE Tomorrow 143 5 Key Ideas AND Concept Check 1-3
DUE Now 142DUE Thursday Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
UNIT 78 TEST March 19th
Inheritance and Regulation
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoods
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with RrYy
1 Chance of baby with Rr 052 Chance of baby with Yy 053 Chance of baby with RrYy 025
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with both dominant phenotypes
1 Chance of baby with at least one R 0752 Chance of baby with at least one Y 0753 Chance of baby with RrYy 05625 (916)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with both dominant phenotypes
1 Chance of baby with at least one R 10
2 Chance of baby with at least one Y 10
3 Chance of baby with both dominant phenotypes 10
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
Homework DUE Tomorrow Linked vs Unlinked Genes AND Monohybrid Crosses to tunritincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with
vestigial wings and cinnabar eyes Predict the phenotypic ratio of the F2 individuals
Homework DUE Tomorrow 153 5 Key Ideas and Concept Check 1-3DUE Thursday Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with vestigial wings and cinnabar eyes Predict the
phenotypic ratio of the F2 individuals
3 The results of the cross from 2 show the following outcome Individuals of each phenotype are shown in the table Which of the following is the most likely explanation of the results a The two genes are located on two different chromosomes b The two genes are sex-linked c The two genes are located on mitochondrial DNA d The two genes are linked on an autosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
1 Build your diploid cell (an homologous pair for each chromosome)a Draw a big cell with a nucleus insideb DRAW homologous pairs of chromosomes
bull 1 big blue 1 big redbull 1 small blue 1 small red
ndash Add genes to your chromosomebull Write an H and an R on big blue and an h and an r on big redbull Write a T on small blue and a t on small red
2 Clone each chromosome (DNA Replication) (making sister chromatids)3 Nucleus breaks down (erase it)4 Homologous pairs form a tetrad crossing over may occur (note do not model
crossing over for now)5 Finish meiosis (see notes for help)6 Nucleus grows around chromosomes 4 cells made (gametes which have half
the number of chromosomes (haploids)7 Repeat Steps 1-6 this time at Step 4 include ONE crossover event
Recombination Modeling
When yoursquore confident on the process show Mr Jones
bull When yoursquore confident on the process show Mr Jones
bull In your notebookFigure 1510 Recombination p295At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid crossing over recombinant chromosome independent assortment Meiosis I Meiosis II
Recombination Modeling
Analysis
1 How does recombination increase the variety of gametes formed
2 Which types of gametes were more likely Gametes with recombinant chromosomes or ones without
3 Recombination is a random process How might it benefithurt the survival of an individualspecies
Recombination Modeling
Warm-UP
1 How could you calculate recombination frequency2 What would the recombination frequency tell you about the relative position of
genes on a chromosome3 Genes A B and C are on the same chromosome Testcrosses show that the
recombination frequency between A and B is 28 and between A and C is 12 Can you determine the linear order of these genes
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP What can we learn about inheritance from looking at a pedigree (use example of the Royal Family of Europe from the early 1900s)
Warm-UP In the following human pedigree squares represent males circles represent females and shaded symbols indicate individuals affected with a disorder One of the affected males from the third generation has a child with a female who is a carrier For the pedigree shown which of the following best expresses the probability that the couplersquos first son will be affected with the disorder
(A) 25 (B) 50 (C) 75 (D) 100
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Is a widowrsquos peak a dominant or recessive trait
Is a widowrsquos peak a dominant or recessive trait
Fig 14-UN5
George
Sandra Tom Sam
Arlene
Wilma Ann Michael
Carla
Daniel Alan Tina
Christopher
A heterozygous tall and a homozygous purple flowered plant is crossed with a short and white flowered plant Predict the offspring Assume independent assortment
1
P=purplep=whiteT=tallt=short
For a plant with the genotype WwXxYyZz what is the probability that the plant will produce a gamete with a haploid genotype of Wxyz Give your answer as a fraction or as a value between 0 and 1 to four decimal places
2
A completely-plated stickleback from a marine population was mated to a low-plated stickleback from a freshwater population The resulting F1 hybrids all displayed a completely plated phenotype When the F1 hybrids were allowed to interbreed the resulting F2 generation included completely plated offspring and low-plated offspring in an approximate 31 ratio Which of the following conclusions is best supported by the results of the breeding experiments
a Phenotypic variation in the F2 generation suggests that armor morphology is controlled by many alleles of a single gene
b The completely-plated phenotype is controlled by a dominant allele of a single gene
c Armor loss is an acquired characteristic that is affected by one or more environmental factors
d Patterns of armor plating in stickleback populations are regulated by sex-specific signals
3
If a man with type AB blood marries a woman with type O what blood types would you expect in their children What fraction would you expect of each type
4
IA= Type AIB= Type Bi= Type O
If a King marries a Queen that is a carrier of hemophilia (sex-linked recessive disease that is historically fatal before adulthood) what is the chance of the Kingdom having an heir to the kingrsquos throne assuming only one child is born
5
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
7 Gregor Mendelrsquos pioneering genetic experiments with pea plants occurred before the discovery of the structure and function of chromosomes Which of the following observations about inheritance in pea plants could be explained only after the discovery that genes may be linked on a chromosome
a Pea color and pea shape display independent inheritance patterns b Offspring of a given cross show all possible combinations of traits in
equal proportions c Most offspring of a given cross have a combination of traits that is
identical to that of either one parent or the other d Recessive phenotypes can skip a generation showing up only in the
parental and F 2 generations
8
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Based on the data in Table I which of the following best explains why there are no individuals with constricted pods in the F 1 generation a Inflated pod shape is dominant to constricted pod shape b The inflated-pod offspring in the F sub one generation are
homozygous c Constricted pod shape typically arises from a new mutation in the F 1
generation d The constricted-pod offspring are carriers for the inflated pod shape
allele
9
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table I the ratio of phenotypes in the offspring from the testcross with F 1 plants that had purple flowers and inflated pods suggests that the genes for flower color and pod shape are located a close together on the same autosome b on the X chromosome c on different chromosomes d on a mitochondrial chromosome
10
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Which of the following provides the best justification for an assumption that might have been used in the computer simulation (Table II) a The broad allele is recessive to the narrow allele because broad
leaves appear in every generation b The purple allele is dominant to the white allele because all the
offspring from the cross of purple-flowered and white-flowered plants had purple flowers
c The narrow allele is codominant with the purple allele because the purple-flower trait and the narrow-leaf trait segregate together
d The white allele is dominant to both the broad and narrow alleles because plants with either type of leaf shape can have white flowers
11
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table II the F 1 offspring of the cross between broad-leaved white-flowered plants with narrow-leaved purple-flowered plants have a phenotype that differs from that of either parent However many testcross offspring have the same phenotype as one of the two plants in the parental cross but relatively few testcross offspring have the same phenotype as the F 1 offspring Which of the following best explains the observation a Recombination between the leaf-shape and flower-color genes resulted in
chromosomes carrying a dominant allele of both genes b Recombination between the broad and narrow alleles of the leaf-shape gene resulted in
chromosomes carrying three different alleles at the same genetic locus c Independent assortment of homologous chromosomes resulted in the combinations of
alleles present in the parental generation d The computer model cannot capture the possible assortments of gametes when
multiple genes are considered
Meiosis Modeling
Analysis
1 What is the outcome of meiosis2 What steps of meiosis cause variation3 If the first cell has 46 chromosomes (before
cloning) how many does each daughter cell have4 How many unique gametes did you form How
many could have formed5 Why do cells go through meiosis
Warm-UP 1 Why do meiosis2 How does meiosis increase variation in organisms
AP Test Money DUE 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Tomorrow Meiosis Wksht
UNIT 78 TEST March 19th
Inheritance and Regulation
Meiosis has multiple processes that increases genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Meiosis has multiple processes that increase genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Meiosis has multiple processes that increase genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Meiosis has multiple processes that increases genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Warm-UP Watch the video What is happening Why does this happen How does this increase variation
AP Test Money DUE TOMORROW 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Tomorrow
UNIT 78 TEST March 19th
Inheritance and Regulation
Fig 13-9a
MITOSIS MEIOSIS
MEIOSIS I
Prophase I
Chiasma
Chromosomereplication
Homologouschromosomepair
Chromosomereplication
2n = 6
Parent cell
Prophase
Replicated chromosome
Metaphase Metaphase I
Anaphase ITelophase I
Haploid n = 3
Daughter cells ofmeiosis I
MEIOSIS II
Daughter cells of meiosis II
nnnn
2n2n
Daughter cellsof mitosis
AnaphaseTelophase
Compare
Contrast
Independent Assortment
Crossing-over Sexual Fertilization Mutation
Types of Changes to Cells Think About what where when how how much variation created
Warm-UP Now we need to keep track of the genes on the chromosomes that are inherited Notice the letters on the chromosomes They represent different alleles for Huntingtons Barbie has Huntingtons What is the chance her child will get Huntingtons
AP Test Money DUE 36 TOMORROWRemember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Tomorrow 141 5 Key Ideas AND Concept Check 1-3
H=dominant (remember Huntingtonrsquos is dominant)
h=recessive (no Huntingtonrsquos)
Homework DUE Monday Test Corrections for 10 Make-UP
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
AP Test Money DUE 36 TODAYRemember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
DUE next Thursday Monohybrid Crosses
Homework DUE Monday Test Corrections for 10 Make-UP
Warm-UP Now we need to keep track of TWO UNLINKED genes on the chromosomes that are inherited Notice the letters on the chromosomes They represent different alleles for Huntingtons and red hair color Barbie has Huntingtons and is a blond (but a carrier) Ken does not have Huntingtonrsquos and is also a carrier for red hair What is the chance their child will get Huntingtons and red hair
Homework DUE Tomorrow 142 5 Key Ideas AND Concept Check 1-3
H= Huntingtonrsquosh=no HuntingtonrsquosR= no red hairr= red hair
DUE Now Test Corrections for 10 Make-UP
UNIT 78 TEST March 19th
Inheritance and Regulation
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
Homework DUE Tomorrow 143 5 Key Ideas AND Concept Check 1-3
DUE Now 142DUE Thursday Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
UNIT 78 TEST March 19th
Inheritance and Regulation
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoods
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with RrYy
1 Chance of baby with Rr 052 Chance of baby with Yy 053 Chance of baby with RrYy 025
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with both dominant phenotypes
1 Chance of baby with at least one R 0752 Chance of baby with at least one Y 0753 Chance of baby with RrYy 05625 (916)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with both dominant phenotypes
1 Chance of baby with at least one R 10
2 Chance of baby with at least one Y 10
3 Chance of baby with both dominant phenotypes 10
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
Homework DUE Tomorrow Linked vs Unlinked Genes AND Monohybrid Crosses to tunritincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with
vestigial wings and cinnabar eyes Predict the phenotypic ratio of the F2 individuals
Homework DUE Tomorrow 153 5 Key Ideas and Concept Check 1-3DUE Thursday Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with vestigial wings and cinnabar eyes Predict the
phenotypic ratio of the F2 individuals
3 The results of the cross from 2 show the following outcome Individuals of each phenotype are shown in the table Which of the following is the most likely explanation of the results a The two genes are located on two different chromosomes b The two genes are sex-linked c The two genes are located on mitochondrial DNA d The two genes are linked on an autosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
1 Build your diploid cell (an homologous pair for each chromosome)a Draw a big cell with a nucleus insideb DRAW homologous pairs of chromosomes
bull 1 big blue 1 big redbull 1 small blue 1 small red
ndash Add genes to your chromosomebull Write an H and an R on big blue and an h and an r on big redbull Write a T on small blue and a t on small red
2 Clone each chromosome (DNA Replication) (making sister chromatids)3 Nucleus breaks down (erase it)4 Homologous pairs form a tetrad crossing over may occur (note do not model
crossing over for now)5 Finish meiosis (see notes for help)6 Nucleus grows around chromosomes 4 cells made (gametes which have half
the number of chromosomes (haploids)7 Repeat Steps 1-6 this time at Step 4 include ONE crossover event
Recombination Modeling
When yoursquore confident on the process show Mr Jones
bull When yoursquore confident on the process show Mr Jones
bull In your notebookFigure 1510 Recombination p295At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid crossing over recombinant chromosome independent assortment Meiosis I Meiosis II
Recombination Modeling
Analysis
1 How does recombination increase the variety of gametes formed
2 Which types of gametes were more likely Gametes with recombinant chromosomes or ones without
3 Recombination is a random process How might it benefithurt the survival of an individualspecies
Recombination Modeling
Warm-UP
1 How could you calculate recombination frequency2 What would the recombination frequency tell you about the relative position of
genes on a chromosome3 Genes A B and C are on the same chromosome Testcrosses show that the
recombination frequency between A and B is 28 and between A and C is 12 Can you determine the linear order of these genes
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP What can we learn about inheritance from looking at a pedigree (use example of the Royal Family of Europe from the early 1900s)
Warm-UP In the following human pedigree squares represent males circles represent females and shaded symbols indicate individuals affected with a disorder One of the affected males from the third generation has a child with a female who is a carrier For the pedigree shown which of the following best expresses the probability that the couplersquos first son will be affected with the disorder
(A) 25 (B) 50 (C) 75 (D) 100
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Is a widowrsquos peak a dominant or recessive trait
Is a widowrsquos peak a dominant or recessive trait
Fig 14-UN5
George
Sandra Tom Sam
Arlene
Wilma Ann Michael
Carla
Daniel Alan Tina
Christopher
A heterozygous tall and a homozygous purple flowered plant is crossed with a short and white flowered plant Predict the offspring Assume independent assortment
1
P=purplep=whiteT=tallt=short
For a plant with the genotype WwXxYyZz what is the probability that the plant will produce a gamete with a haploid genotype of Wxyz Give your answer as a fraction or as a value between 0 and 1 to four decimal places
2
A completely-plated stickleback from a marine population was mated to a low-plated stickleback from a freshwater population The resulting F1 hybrids all displayed a completely plated phenotype When the F1 hybrids were allowed to interbreed the resulting F2 generation included completely plated offspring and low-plated offspring in an approximate 31 ratio Which of the following conclusions is best supported by the results of the breeding experiments
a Phenotypic variation in the F2 generation suggests that armor morphology is controlled by many alleles of a single gene
b The completely-plated phenotype is controlled by a dominant allele of a single gene
c Armor loss is an acquired characteristic that is affected by one or more environmental factors
d Patterns of armor plating in stickleback populations are regulated by sex-specific signals
3
If a man with type AB blood marries a woman with type O what blood types would you expect in their children What fraction would you expect of each type
4
IA= Type AIB= Type Bi= Type O
If a King marries a Queen that is a carrier of hemophilia (sex-linked recessive disease that is historically fatal before adulthood) what is the chance of the Kingdom having an heir to the kingrsquos throne assuming only one child is born
5
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
7 Gregor Mendelrsquos pioneering genetic experiments with pea plants occurred before the discovery of the structure and function of chromosomes Which of the following observations about inheritance in pea plants could be explained only after the discovery that genes may be linked on a chromosome
a Pea color and pea shape display independent inheritance patterns b Offspring of a given cross show all possible combinations of traits in
equal proportions c Most offspring of a given cross have a combination of traits that is
identical to that of either one parent or the other d Recessive phenotypes can skip a generation showing up only in the
parental and F 2 generations
8
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Based on the data in Table I which of the following best explains why there are no individuals with constricted pods in the F 1 generation a Inflated pod shape is dominant to constricted pod shape b The inflated-pod offspring in the F sub one generation are
homozygous c Constricted pod shape typically arises from a new mutation in the F 1
generation d The constricted-pod offspring are carriers for the inflated pod shape
allele
9
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table I the ratio of phenotypes in the offspring from the testcross with F 1 plants that had purple flowers and inflated pods suggests that the genes for flower color and pod shape are located a close together on the same autosome b on the X chromosome c on different chromosomes d on a mitochondrial chromosome
10
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Which of the following provides the best justification for an assumption that might have been used in the computer simulation (Table II) a The broad allele is recessive to the narrow allele because broad
leaves appear in every generation b The purple allele is dominant to the white allele because all the
offspring from the cross of purple-flowered and white-flowered plants had purple flowers
c The narrow allele is codominant with the purple allele because the purple-flower trait and the narrow-leaf trait segregate together
d The white allele is dominant to both the broad and narrow alleles because plants with either type of leaf shape can have white flowers
11
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table II the F 1 offspring of the cross between broad-leaved white-flowered plants with narrow-leaved purple-flowered plants have a phenotype that differs from that of either parent However many testcross offspring have the same phenotype as one of the two plants in the parental cross but relatively few testcross offspring have the same phenotype as the F 1 offspring Which of the following best explains the observation a Recombination between the leaf-shape and flower-color genes resulted in
chromosomes carrying a dominant allele of both genes b Recombination between the broad and narrow alleles of the leaf-shape gene resulted in
chromosomes carrying three different alleles at the same genetic locus c Independent assortment of homologous chromosomes resulted in the combinations of
alleles present in the parental generation d The computer model cannot capture the possible assortments of gametes when
multiple genes are considered
Warm-UP 1 Why do meiosis2 How does meiosis increase variation in organisms
AP Test Money DUE 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Tomorrow Meiosis Wksht
UNIT 78 TEST March 19th
Inheritance and Regulation
Meiosis has multiple processes that increases genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Meiosis has multiple processes that increase genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Meiosis has multiple processes that increase genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Meiosis has multiple processes that increases genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Warm-UP Watch the video What is happening Why does this happen How does this increase variation
AP Test Money DUE TOMORROW 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Tomorrow
UNIT 78 TEST March 19th
Inheritance and Regulation
Fig 13-9a
MITOSIS MEIOSIS
MEIOSIS I
Prophase I
Chiasma
Chromosomereplication
Homologouschromosomepair
Chromosomereplication
2n = 6
Parent cell
Prophase
Replicated chromosome
Metaphase Metaphase I
Anaphase ITelophase I
Haploid n = 3
Daughter cells ofmeiosis I
MEIOSIS II
Daughter cells of meiosis II
nnnn
2n2n
Daughter cellsof mitosis
AnaphaseTelophase
Compare
Contrast
Independent Assortment
Crossing-over Sexual Fertilization Mutation
Types of Changes to Cells Think About what where when how how much variation created
Warm-UP Now we need to keep track of the genes on the chromosomes that are inherited Notice the letters on the chromosomes They represent different alleles for Huntingtons Barbie has Huntingtons What is the chance her child will get Huntingtons
AP Test Money DUE 36 TOMORROWRemember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Tomorrow 141 5 Key Ideas AND Concept Check 1-3
H=dominant (remember Huntingtonrsquos is dominant)
h=recessive (no Huntingtonrsquos)
Homework DUE Monday Test Corrections for 10 Make-UP
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
AP Test Money DUE 36 TODAYRemember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
DUE next Thursday Monohybrid Crosses
Homework DUE Monday Test Corrections for 10 Make-UP
Warm-UP Now we need to keep track of TWO UNLINKED genes on the chromosomes that are inherited Notice the letters on the chromosomes They represent different alleles for Huntingtons and red hair color Barbie has Huntingtons and is a blond (but a carrier) Ken does not have Huntingtonrsquos and is also a carrier for red hair What is the chance their child will get Huntingtons and red hair
Homework DUE Tomorrow 142 5 Key Ideas AND Concept Check 1-3
H= Huntingtonrsquosh=no HuntingtonrsquosR= no red hairr= red hair
DUE Now Test Corrections for 10 Make-UP
UNIT 78 TEST March 19th
Inheritance and Regulation
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
Homework DUE Tomorrow 143 5 Key Ideas AND Concept Check 1-3
DUE Now 142DUE Thursday Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
UNIT 78 TEST March 19th
Inheritance and Regulation
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoods
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with RrYy
1 Chance of baby with Rr 052 Chance of baby with Yy 053 Chance of baby with RrYy 025
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with both dominant phenotypes
1 Chance of baby with at least one R 0752 Chance of baby with at least one Y 0753 Chance of baby with RrYy 05625 (916)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with both dominant phenotypes
1 Chance of baby with at least one R 10
2 Chance of baby with at least one Y 10
3 Chance of baby with both dominant phenotypes 10
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
Homework DUE Tomorrow Linked vs Unlinked Genes AND Monohybrid Crosses to tunritincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with
vestigial wings and cinnabar eyes Predict the phenotypic ratio of the F2 individuals
Homework DUE Tomorrow 153 5 Key Ideas and Concept Check 1-3DUE Thursday Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with vestigial wings and cinnabar eyes Predict the
phenotypic ratio of the F2 individuals
3 The results of the cross from 2 show the following outcome Individuals of each phenotype are shown in the table Which of the following is the most likely explanation of the results a The two genes are located on two different chromosomes b The two genes are sex-linked c The two genes are located on mitochondrial DNA d The two genes are linked on an autosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
1 Build your diploid cell (an homologous pair for each chromosome)a Draw a big cell with a nucleus insideb DRAW homologous pairs of chromosomes
bull 1 big blue 1 big redbull 1 small blue 1 small red
ndash Add genes to your chromosomebull Write an H and an R on big blue and an h and an r on big redbull Write a T on small blue and a t on small red
2 Clone each chromosome (DNA Replication) (making sister chromatids)3 Nucleus breaks down (erase it)4 Homologous pairs form a tetrad crossing over may occur (note do not model
crossing over for now)5 Finish meiosis (see notes for help)6 Nucleus grows around chromosomes 4 cells made (gametes which have half
the number of chromosomes (haploids)7 Repeat Steps 1-6 this time at Step 4 include ONE crossover event
Recombination Modeling
When yoursquore confident on the process show Mr Jones
bull When yoursquore confident on the process show Mr Jones
bull In your notebookFigure 1510 Recombination p295At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid crossing over recombinant chromosome independent assortment Meiosis I Meiosis II
Recombination Modeling
Analysis
1 How does recombination increase the variety of gametes formed
2 Which types of gametes were more likely Gametes with recombinant chromosomes or ones without
3 Recombination is a random process How might it benefithurt the survival of an individualspecies
Recombination Modeling
Warm-UP
1 How could you calculate recombination frequency2 What would the recombination frequency tell you about the relative position of
genes on a chromosome3 Genes A B and C are on the same chromosome Testcrosses show that the
recombination frequency between A and B is 28 and between A and C is 12 Can you determine the linear order of these genes
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP What can we learn about inheritance from looking at a pedigree (use example of the Royal Family of Europe from the early 1900s)
Warm-UP In the following human pedigree squares represent males circles represent females and shaded symbols indicate individuals affected with a disorder One of the affected males from the third generation has a child with a female who is a carrier For the pedigree shown which of the following best expresses the probability that the couplersquos first son will be affected with the disorder
(A) 25 (B) 50 (C) 75 (D) 100
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Is a widowrsquos peak a dominant or recessive trait
Is a widowrsquos peak a dominant or recessive trait
Fig 14-UN5
George
Sandra Tom Sam
Arlene
Wilma Ann Michael
Carla
Daniel Alan Tina
Christopher
A heterozygous tall and a homozygous purple flowered plant is crossed with a short and white flowered plant Predict the offspring Assume independent assortment
1
P=purplep=whiteT=tallt=short
For a plant with the genotype WwXxYyZz what is the probability that the plant will produce a gamete with a haploid genotype of Wxyz Give your answer as a fraction or as a value between 0 and 1 to four decimal places
2
A completely-plated stickleback from a marine population was mated to a low-plated stickleback from a freshwater population The resulting F1 hybrids all displayed a completely plated phenotype When the F1 hybrids were allowed to interbreed the resulting F2 generation included completely plated offspring and low-plated offspring in an approximate 31 ratio Which of the following conclusions is best supported by the results of the breeding experiments
a Phenotypic variation in the F2 generation suggests that armor morphology is controlled by many alleles of a single gene
b The completely-plated phenotype is controlled by a dominant allele of a single gene
c Armor loss is an acquired characteristic that is affected by one or more environmental factors
d Patterns of armor plating in stickleback populations are regulated by sex-specific signals
3
If a man with type AB blood marries a woman with type O what blood types would you expect in their children What fraction would you expect of each type
4
IA= Type AIB= Type Bi= Type O
If a King marries a Queen that is a carrier of hemophilia (sex-linked recessive disease that is historically fatal before adulthood) what is the chance of the Kingdom having an heir to the kingrsquos throne assuming only one child is born
5
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
7 Gregor Mendelrsquos pioneering genetic experiments with pea plants occurred before the discovery of the structure and function of chromosomes Which of the following observations about inheritance in pea plants could be explained only after the discovery that genes may be linked on a chromosome
a Pea color and pea shape display independent inheritance patterns b Offspring of a given cross show all possible combinations of traits in
equal proportions c Most offspring of a given cross have a combination of traits that is
identical to that of either one parent or the other d Recessive phenotypes can skip a generation showing up only in the
parental and F 2 generations
8
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Based on the data in Table I which of the following best explains why there are no individuals with constricted pods in the F 1 generation a Inflated pod shape is dominant to constricted pod shape b The inflated-pod offspring in the F sub one generation are
homozygous c Constricted pod shape typically arises from a new mutation in the F 1
generation d The constricted-pod offspring are carriers for the inflated pod shape
allele
9
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table I the ratio of phenotypes in the offspring from the testcross with F 1 plants that had purple flowers and inflated pods suggests that the genes for flower color and pod shape are located a close together on the same autosome b on the X chromosome c on different chromosomes d on a mitochondrial chromosome
10
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Which of the following provides the best justification for an assumption that might have been used in the computer simulation (Table II) a The broad allele is recessive to the narrow allele because broad
leaves appear in every generation b The purple allele is dominant to the white allele because all the
offspring from the cross of purple-flowered and white-flowered plants had purple flowers
c The narrow allele is codominant with the purple allele because the purple-flower trait and the narrow-leaf trait segregate together
d The white allele is dominant to both the broad and narrow alleles because plants with either type of leaf shape can have white flowers
11
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table II the F 1 offspring of the cross between broad-leaved white-flowered plants with narrow-leaved purple-flowered plants have a phenotype that differs from that of either parent However many testcross offspring have the same phenotype as one of the two plants in the parental cross but relatively few testcross offspring have the same phenotype as the F 1 offspring Which of the following best explains the observation a Recombination between the leaf-shape and flower-color genes resulted in
chromosomes carrying a dominant allele of both genes b Recombination between the broad and narrow alleles of the leaf-shape gene resulted in
chromosomes carrying three different alleles at the same genetic locus c Independent assortment of homologous chromosomes resulted in the combinations of
alleles present in the parental generation d The computer model cannot capture the possible assortments of gametes when
multiple genes are considered
Meiosis has multiple processes that increases genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Meiosis has multiple processes that increase genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Meiosis has multiple processes that increase genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Meiosis has multiple processes that increases genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Warm-UP Watch the video What is happening Why does this happen How does this increase variation
AP Test Money DUE TOMORROW 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Tomorrow
UNIT 78 TEST March 19th
Inheritance and Regulation
Fig 13-9a
MITOSIS MEIOSIS
MEIOSIS I
Prophase I
Chiasma
Chromosomereplication
Homologouschromosomepair
Chromosomereplication
2n = 6
Parent cell
Prophase
Replicated chromosome
Metaphase Metaphase I
Anaphase ITelophase I
Haploid n = 3
Daughter cells ofmeiosis I
MEIOSIS II
Daughter cells of meiosis II
nnnn
2n2n
Daughter cellsof mitosis
AnaphaseTelophase
Compare
Contrast
Independent Assortment
Crossing-over Sexual Fertilization Mutation
Types of Changes to Cells Think About what where when how how much variation created
Warm-UP Now we need to keep track of the genes on the chromosomes that are inherited Notice the letters on the chromosomes They represent different alleles for Huntingtons Barbie has Huntingtons What is the chance her child will get Huntingtons
AP Test Money DUE 36 TOMORROWRemember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Tomorrow 141 5 Key Ideas AND Concept Check 1-3
H=dominant (remember Huntingtonrsquos is dominant)
h=recessive (no Huntingtonrsquos)
Homework DUE Monday Test Corrections for 10 Make-UP
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
AP Test Money DUE 36 TODAYRemember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
DUE next Thursday Monohybrid Crosses
Homework DUE Monday Test Corrections for 10 Make-UP
Warm-UP Now we need to keep track of TWO UNLINKED genes on the chromosomes that are inherited Notice the letters on the chromosomes They represent different alleles for Huntingtons and red hair color Barbie has Huntingtons and is a blond (but a carrier) Ken does not have Huntingtonrsquos and is also a carrier for red hair What is the chance their child will get Huntingtons and red hair
Homework DUE Tomorrow 142 5 Key Ideas AND Concept Check 1-3
H= Huntingtonrsquosh=no HuntingtonrsquosR= no red hairr= red hair
DUE Now Test Corrections for 10 Make-UP
UNIT 78 TEST March 19th
Inheritance and Regulation
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
Homework DUE Tomorrow 143 5 Key Ideas AND Concept Check 1-3
DUE Now 142DUE Thursday Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
UNIT 78 TEST March 19th
Inheritance and Regulation
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoods
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with RrYy
1 Chance of baby with Rr 052 Chance of baby with Yy 053 Chance of baby with RrYy 025
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with both dominant phenotypes
1 Chance of baby with at least one R 0752 Chance of baby with at least one Y 0753 Chance of baby with RrYy 05625 (916)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with both dominant phenotypes
1 Chance of baby with at least one R 10
2 Chance of baby with at least one Y 10
3 Chance of baby with both dominant phenotypes 10
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
Homework DUE Tomorrow Linked vs Unlinked Genes AND Monohybrid Crosses to tunritincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with
vestigial wings and cinnabar eyes Predict the phenotypic ratio of the F2 individuals
Homework DUE Tomorrow 153 5 Key Ideas and Concept Check 1-3DUE Thursday Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with vestigial wings and cinnabar eyes Predict the
phenotypic ratio of the F2 individuals
3 The results of the cross from 2 show the following outcome Individuals of each phenotype are shown in the table Which of the following is the most likely explanation of the results a The two genes are located on two different chromosomes b The two genes are sex-linked c The two genes are located on mitochondrial DNA d The two genes are linked on an autosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
1 Build your diploid cell (an homologous pair for each chromosome)a Draw a big cell with a nucleus insideb DRAW homologous pairs of chromosomes
bull 1 big blue 1 big redbull 1 small blue 1 small red
ndash Add genes to your chromosomebull Write an H and an R on big blue and an h and an r on big redbull Write a T on small blue and a t on small red
2 Clone each chromosome (DNA Replication) (making sister chromatids)3 Nucleus breaks down (erase it)4 Homologous pairs form a tetrad crossing over may occur (note do not model
crossing over for now)5 Finish meiosis (see notes for help)6 Nucleus grows around chromosomes 4 cells made (gametes which have half
the number of chromosomes (haploids)7 Repeat Steps 1-6 this time at Step 4 include ONE crossover event
Recombination Modeling
When yoursquore confident on the process show Mr Jones
bull When yoursquore confident on the process show Mr Jones
bull In your notebookFigure 1510 Recombination p295At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid crossing over recombinant chromosome independent assortment Meiosis I Meiosis II
Recombination Modeling
Analysis
1 How does recombination increase the variety of gametes formed
2 Which types of gametes were more likely Gametes with recombinant chromosomes or ones without
3 Recombination is a random process How might it benefithurt the survival of an individualspecies
Recombination Modeling
Warm-UP
1 How could you calculate recombination frequency2 What would the recombination frequency tell you about the relative position of
genes on a chromosome3 Genes A B and C are on the same chromosome Testcrosses show that the
recombination frequency between A and B is 28 and between A and C is 12 Can you determine the linear order of these genes
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP What can we learn about inheritance from looking at a pedigree (use example of the Royal Family of Europe from the early 1900s)
Warm-UP In the following human pedigree squares represent males circles represent females and shaded symbols indicate individuals affected with a disorder One of the affected males from the third generation has a child with a female who is a carrier For the pedigree shown which of the following best expresses the probability that the couplersquos first son will be affected with the disorder
(A) 25 (B) 50 (C) 75 (D) 100
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Is a widowrsquos peak a dominant or recessive trait
Is a widowrsquos peak a dominant or recessive trait
Fig 14-UN5
George
Sandra Tom Sam
Arlene
Wilma Ann Michael
Carla
Daniel Alan Tina
Christopher
A heterozygous tall and a homozygous purple flowered plant is crossed with a short and white flowered plant Predict the offspring Assume independent assortment
1
P=purplep=whiteT=tallt=short
For a plant with the genotype WwXxYyZz what is the probability that the plant will produce a gamete with a haploid genotype of Wxyz Give your answer as a fraction or as a value between 0 and 1 to four decimal places
2
A completely-plated stickleback from a marine population was mated to a low-plated stickleback from a freshwater population The resulting F1 hybrids all displayed a completely plated phenotype When the F1 hybrids were allowed to interbreed the resulting F2 generation included completely plated offspring and low-plated offspring in an approximate 31 ratio Which of the following conclusions is best supported by the results of the breeding experiments
a Phenotypic variation in the F2 generation suggests that armor morphology is controlled by many alleles of a single gene
b The completely-plated phenotype is controlled by a dominant allele of a single gene
c Armor loss is an acquired characteristic that is affected by one or more environmental factors
d Patterns of armor plating in stickleback populations are regulated by sex-specific signals
3
If a man with type AB blood marries a woman with type O what blood types would you expect in their children What fraction would you expect of each type
4
IA= Type AIB= Type Bi= Type O
If a King marries a Queen that is a carrier of hemophilia (sex-linked recessive disease that is historically fatal before adulthood) what is the chance of the Kingdom having an heir to the kingrsquos throne assuming only one child is born
5
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
7 Gregor Mendelrsquos pioneering genetic experiments with pea plants occurred before the discovery of the structure and function of chromosomes Which of the following observations about inheritance in pea plants could be explained only after the discovery that genes may be linked on a chromosome
a Pea color and pea shape display independent inheritance patterns b Offspring of a given cross show all possible combinations of traits in
equal proportions c Most offspring of a given cross have a combination of traits that is
identical to that of either one parent or the other d Recessive phenotypes can skip a generation showing up only in the
parental and F 2 generations
8
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Based on the data in Table I which of the following best explains why there are no individuals with constricted pods in the F 1 generation a Inflated pod shape is dominant to constricted pod shape b The inflated-pod offspring in the F sub one generation are
homozygous c Constricted pod shape typically arises from a new mutation in the F 1
generation d The constricted-pod offspring are carriers for the inflated pod shape
allele
9
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table I the ratio of phenotypes in the offspring from the testcross with F 1 plants that had purple flowers and inflated pods suggests that the genes for flower color and pod shape are located a close together on the same autosome b on the X chromosome c on different chromosomes d on a mitochondrial chromosome
10
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Which of the following provides the best justification for an assumption that might have been used in the computer simulation (Table II) a The broad allele is recessive to the narrow allele because broad
leaves appear in every generation b The purple allele is dominant to the white allele because all the
offspring from the cross of purple-flowered and white-flowered plants had purple flowers
c The narrow allele is codominant with the purple allele because the purple-flower trait and the narrow-leaf trait segregate together
d The white allele is dominant to both the broad and narrow alleles because plants with either type of leaf shape can have white flowers
11
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table II the F 1 offspring of the cross between broad-leaved white-flowered plants with narrow-leaved purple-flowered plants have a phenotype that differs from that of either parent However many testcross offspring have the same phenotype as one of the two plants in the parental cross but relatively few testcross offspring have the same phenotype as the F 1 offspring Which of the following best explains the observation a Recombination between the leaf-shape and flower-color genes resulted in
chromosomes carrying a dominant allele of both genes b Recombination between the broad and narrow alleles of the leaf-shape gene resulted in
chromosomes carrying three different alleles at the same genetic locus c Independent assortment of homologous chromosomes resulted in the combinations of
alleles present in the parental generation d The computer model cannot capture the possible assortments of gametes when
multiple genes are considered
Meiosis has multiple processes that increase genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Meiosis has multiple processes that increase genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Meiosis has multiple processes that increases genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Warm-UP Watch the video What is happening Why does this happen How does this increase variation
AP Test Money DUE TOMORROW 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Tomorrow
UNIT 78 TEST March 19th
Inheritance and Regulation
Fig 13-9a
MITOSIS MEIOSIS
MEIOSIS I
Prophase I
Chiasma
Chromosomereplication
Homologouschromosomepair
Chromosomereplication
2n = 6
Parent cell
Prophase
Replicated chromosome
Metaphase Metaphase I
Anaphase ITelophase I
Haploid n = 3
Daughter cells ofmeiosis I
MEIOSIS II
Daughter cells of meiosis II
nnnn
2n2n
Daughter cellsof mitosis
AnaphaseTelophase
Compare
Contrast
Independent Assortment
Crossing-over Sexual Fertilization Mutation
Types of Changes to Cells Think About what where when how how much variation created
Warm-UP Now we need to keep track of the genes on the chromosomes that are inherited Notice the letters on the chromosomes They represent different alleles for Huntingtons Barbie has Huntingtons What is the chance her child will get Huntingtons
AP Test Money DUE 36 TOMORROWRemember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Tomorrow 141 5 Key Ideas AND Concept Check 1-3
H=dominant (remember Huntingtonrsquos is dominant)
h=recessive (no Huntingtonrsquos)
Homework DUE Monday Test Corrections for 10 Make-UP
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
AP Test Money DUE 36 TODAYRemember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
DUE next Thursday Monohybrid Crosses
Homework DUE Monday Test Corrections for 10 Make-UP
Warm-UP Now we need to keep track of TWO UNLINKED genes on the chromosomes that are inherited Notice the letters on the chromosomes They represent different alleles for Huntingtons and red hair color Barbie has Huntingtons and is a blond (but a carrier) Ken does not have Huntingtonrsquos and is also a carrier for red hair What is the chance their child will get Huntingtons and red hair
Homework DUE Tomorrow 142 5 Key Ideas AND Concept Check 1-3
H= Huntingtonrsquosh=no HuntingtonrsquosR= no red hairr= red hair
DUE Now Test Corrections for 10 Make-UP
UNIT 78 TEST March 19th
Inheritance and Regulation
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
Homework DUE Tomorrow 143 5 Key Ideas AND Concept Check 1-3
DUE Now 142DUE Thursday Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
UNIT 78 TEST March 19th
Inheritance and Regulation
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoods
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with RrYy
1 Chance of baby with Rr 052 Chance of baby with Yy 053 Chance of baby with RrYy 025
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with both dominant phenotypes
1 Chance of baby with at least one R 0752 Chance of baby with at least one Y 0753 Chance of baby with RrYy 05625 (916)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with both dominant phenotypes
1 Chance of baby with at least one R 10
2 Chance of baby with at least one Y 10
3 Chance of baby with both dominant phenotypes 10
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
Homework DUE Tomorrow Linked vs Unlinked Genes AND Monohybrid Crosses to tunritincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with
vestigial wings and cinnabar eyes Predict the phenotypic ratio of the F2 individuals
Homework DUE Tomorrow 153 5 Key Ideas and Concept Check 1-3DUE Thursday Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with vestigial wings and cinnabar eyes Predict the
phenotypic ratio of the F2 individuals
3 The results of the cross from 2 show the following outcome Individuals of each phenotype are shown in the table Which of the following is the most likely explanation of the results a The two genes are located on two different chromosomes b The two genes are sex-linked c The two genes are located on mitochondrial DNA d The two genes are linked on an autosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
1 Build your diploid cell (an homologous pair for each chromosome)a Draw a big cell with a nucleus insideb DRAW homologous pairs of chromosomes
bull 1 big blue 1 big redbull 1 small blue 1 small red
ndash Add genes to your chromosomebull Write an H and an R on big blue and an h and an r on big redbull Write a T on small blue and a t on small red
2 Clone each chromosome (DNA Replication) (making sister chromatids)3 Nucleus breaks down (erase it)4 Homologous pairs form a tetrad crossing over may occur (note do not model
crossing over for now)5 Finish meiosis (see notes for help)6 Nucleus grows around chromosomes 4 cells made (gametes which have half
the number of chromosomes (haploids)7 Repeat Steps 1-6 this time at Step 4 include ONE crossover event
Recombination Modeling
When yoursquore confident on the process show Mr Jones
bull When yoursquore confident on the process show Mr Jones
bull In your notebookFigure 1510 Recombination p295At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid crossing over recombinant chromosome independent assortment Meiosis I Meiosis II
Recombination Modeling
Analysis
1 How does recombination increase the variety of gametes formed
2 Which types of gametes were more likely Gametes with recombinant chromosomes or ones without
3 Recombination is a random process How might it benefithurt the survival of an individualspecies
Recombination Modeling
Warm-UP
1 How could you calculate recombination frequency2 What would the recombination frequency tell you about the relative position of
genes on a chromosome3 Genes A B and C are on the same chromosome Testcrosses show that the
recombination frequency between A and B is 28 and between A and C is 12 Can you determine the linear order of these genes
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP What can we learn about inheritance from looking at a pedigree (use example of the Royal Family of Europe from the early 1900s)
Warm-UP In the following human pedigree squares represent males circles represent females and shaded symbols indicate individuals affected with a disorder One of the affected males from the third generation has a child with a female who is a carrier For the pedigree shown which of the following best expresses the probability that the couplersquos first son will be affected with the disorder
(A) 25 (B) 50 (C) 75 (D) 100
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Is a widowrsquos peak a dominant or recessive trait
Is a widowrsquos peak a dominant or recessive trait
Fig 14-UN5
George
Sandra Tom Sam
Arlene
Wilma Ann Michael
Carla
Daniel Alan Tina
Christopher
A heterozygous tall and a homozygous purple flowered plant is crossed with a short and white flowered plant Predict the offspring Assume independent assortment
1
P=purplep=whiteT=tallt=short
For a plant with the genotype WwXxYyZz what is the probability that the plant will produce a gamete with a haploid genotype of Wxyz Give your answer as a fraction or as a value between 0 and 1 to four decimal places
2
A completely-plated stickleback from a marine population was mated to a low-plated stickleback from a freshwater population The resulting F1 hybrids all displayed a completely plated phenotype When the F1 hybrids were allowed to interbreed the resulting F2 generation included completely plated offspring and low-plated offspring in an approximate 31 ratio Which of the following conclusions is best supported by the results of the breeding experiments
a Phenotypic variation in the F2 generation suggests that armor morphology is controlled by many alleles of a single gene
b The completely-plated phenotype is controlled by a dominant allele of a single gene
c Armor loss is an acquired characteristic that is affected by one or more environmental factors
d Patterns of armor plating in stickleback populations are regulated by sex-specific signals
3
If a man with type AB blood marries a woman with type O what blood types would you expect in their children What fraction would you expect of each type
4
IA= Type AIB= Type Bi= Type O
If a King marries a Queen that is a carrier of hemophilia (sex-linked recessive disease that is historically fatal before adulthood) what is the chance of the Kingdom having an heir to the kingrsquos throne assuming only one child is born
5
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
7 Gregor Mendelrsquos pioneering genetic experiments with pea plants occurred before the discovery of the structure and function of chromosomes Which of the following observations about inheritance in pea plants could be explained only after the discovery that genes may be linked on a chromosome
a Pea color and pea shape display independent inheritance patterns b Offspring of a given cross show all possible combinations of traits in
equal proportions c Most offspring of a given cross have a combination of traits that is
identical to that of either one parent or the other d Recessive phenotypes can skip a generation showing up only in the
parental and F 2 generations
8
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Based on the data in Table I which of the following best explains why there are no individuals with constricted pods in the F 1 generation a Inflated pod shape is dominant to constricted pod shape b The inflated-pod offspring in the F sub one generation are
homozygous c Constricted pod shape typically arises from a new mutation in the F 1
generation d The constricted-pod offspring are carriers for the inflated pod shape
allele
9
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table I the ratio of phenotypes in the offspring from the testcross with F 1 plants that had purple flowers and inflated pods suggests that the genes for flower color and pod shape are located a close together on the same autosome b on the X chromosome c on different chromosomes d on a mitochondrial chromosome
10
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Which of the following provides the best justification for an assumption that might have been used in the computer simulation (Table II) a The broad allele is recessive to the narrow allele because broad
leaves appear in every generation b The purple allele is dominant to the white allele because all the
offspring from the cross of purple-flowered and white-flowered plants had purple flowers
c The narrow allele is codominant with the purple allele because the purple-flower trait and the narrow-leaf trait segregate together
d The white allele is dominant to both the broad and narrow alleles because plants with either type of leaf shape can have white flowers
11
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table II the F 1 offspring of the cross between broad-leaved white-flowered plants with narrow-leaved purple-flowered plants have a phenotype that differs from that of either parent However many testcross offspring have the same phenotype as one of the two plants in the parental cross but relatively few testcross offspring have the same phenotype as the F 1 offspring Which of the following best explains the observation a Recombination between the leaf-shape and flower-color genes resulted in
chromosomes carrying a dominant allele of both genes b Recombination between the broad and narrow alleles of the leaf-shape gene resulted in
chromosomes carrying three different alleles at the same genetic locus c Independent assortment of homologous chromosomes resulted in the combinations of
alleles present in the parental generation d The computer model cannot capture the possible assortments of gametes when
multiple genes are considered
Meiosis has multiple processes that increase genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Meiosis has multiple processes that increases genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Warm-UP Watch the video What is happening Why does this happen How does this increase variation
AP Test Money DUE TOMORROW 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Tomorrow
UNIT 78 TEST March 19th
Inheritance and Regulation
Fig 13-9a
MITOSIS MEIOSIS
MEIOSIS I
Prophase I
Chiasma
Chromosomereplication
Homologouschromosomepair
Chromosomereplication
2n = 6
Parent cell
Prophase
Replicated chromosome
Metaphase Metaphase I
Anaphase ITelophase I
Haploid n = 3
Daughter cells ofmeiosis I
MEIOSIS II
Daughter cells of meiosis II
nnnn
2n2n
Daughter cellsof mitosis
AnaphaseTelophase
Compare
Contrast
Independent Assortment
Crossing-over Sexual Fertilization Mutation
Types of Changes to Cells Think About what where when how how much variation created
Warm-UP Now we need to keep track of the genes on the chromosomes that are inherited Notice the letters on the chromosomes They represent different alleles for Huntingtons Barbie has Huntingtons What is the chance her child will get Huntingtons
AP Test Money DUE 36 TOMORROWRemember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Tomorrow 141 5 Key Ideas AND Concept Check 1-3
H=dominant (remember Huntingtonrsquos is dominant)
h=recessive (no Huntingtonrsquos)
Homework DUE Monday Test Corrections for 10 Make-UP
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
AP Test Money DUE 36 TODAYRemember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
DUE next Thursday Monohybrid Crosses
Homework DUE Monday Test Corrections for 10 Make-UP
Warm-UP Now we need to keep track of TWO UNLINKED genes on the chromosomes that are inherited Notice the letters on the chromosomes They represent different alleles for Huntingtons and red hair color Barbie has Huntingtons and is a blond (but a carrier) Ken does not have Huntingtonrsquos and is also a carrier for red hair What is the chance their child will get Huntingtons and red hair
Homework DUE Tomorrow 142 5 Key Ideas AND Concept Check 1-3
H= Huntingtonrsquosh=no HuntingtonrsquosR= no red hairr= red hair
DUE Now Test Corrections for 10 Make-UP
UNIT 78 TEST March 19th
Inheritance and Regulation
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
Homework DUE Tomorrow 143 5 Key Ideas AND Concept Check 1-3
DUE Now 142DUE Thursday Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
UNIT 78 TEST March 19th
Inheritance and Regulation
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoods
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with RrYy
1 Chance of baby with Rr 052 Chance of baby with Yy 053 Chance of baby with RrYy 025
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with both dominant phenotypes
1 Chance of baby with at least one R 0752 Chance of baby with at least one Y 0753 Chance of baby with RrYy 05625 (916)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with both dominant phenotypes
1 Chance of baby with at least one R 10
2 Chance of baby with at least one Y 10
3 Chance of baby with both dominant phenotypes 10
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
Homework DUE Tomorrow Linked vs Unlinked Genes AND Monohybrid Crosses to tunritincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with
vestigial wings and cinnabar eyes Predict the phenotypic ratio of the F2 individuals
Homework DUE Tomorrow 153 5 Key Ideas and Concept Check 1-3DUE Thursday Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with vestigial wings and cinnabar eyes Predict the
phenotypic ratio of the F2 individuals
3 The results of the cross from 2 show the following outcome Individuals of each phenotype are shown in the table Which of the following is the most likely explanation of the results a The two genes are located on two different chromosomes b The two genes are sex-linked c The two genes are located on mitochondrial DNA d The two genes are linked on an autosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
1 Build your diploid cell (an homologous pair for each chromosome)a Draw a big cell with a nucleus insideb DRAW homologous pairs of chromosomes
bull 1 big blue 1 big redbull 1 small blue 1 small red
ndash Add genes to your chromosomebull Write an H and an R on big blue and an h and an r on big redbull Write a T on small blue and a t on small red
2 Clone each chromosome (DNA Replication) (making sister chromatids)3 Nucleus breaks down (erase it)4 Homologous pairs form a tetrad crossing over may occur (note do not model
crossing over for now)5 Finish meiosis (see notes for help)6 Nucleus grows around chromosomes 4 cells made (gametes which have half
the number of chromosomes (haploids)7 Repeat Steps 1-6 this time at Step 4 include ONE crossover event
Recombination Modeling
When yoursquore confident on the process show Mr Jones
bull When yoursquore confident on the process show Mr Jones
bull In your notebookFigure 1510 Recombination p295At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid crossing over recombinant chromosome independent assortment Meiosis I Meiosis II
Recombination Modeling
Analysis
1 How does recombination increase the variety of gametes formed
2 Which types of gametes were more likely Gametes with recombinant chromosomes or ones without
3 Recombination is a random process How might it benefithurt the survival of an individualspecies
Recombination Modeling
Warm-UP
1 How could you calculate recombination frequency2 What would the recombination frequency tell you about the relative position of
genes on a chromosome3 Genes A B and C are on the same chromosome Testcrosses show that the
recombination frequency between A and B is 28 and between A and C is 12 Can you determine the linear order of these genes
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP What can we learn about inheritance from looking at a pedigree (use example of the Royal Family of Europe from the early 1900s)
Warm-UP In the following human pedigree squares represent males circles represent females and shaded symbols indicate individuals affected with a disorder One of the affected males from the third generation has a child with a female who is a carrier For the pedigree shown which of the following best expresses the probability that the couplersquos first son will be affected with the disorder
(A) 25 (B) 50 (C) 75 (D) 100
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Is a widowrsquos peak a dominant or recessive trait
Is a widowrsquos peak a dominant or recessive trait
Fig 14-UN5
George
Sandra Tom Sam
Arlene
Wilma Ann Michael
Carla
Daniel Alan Tina
Christopher
A heterozygous tall and a homozygous purple flowered plant is crossed with a short and white flowered plant Predict the offspring Assume independent assortment
1
P=purplep=whiteT=tallt=short
For a plant with the genotype WwXxYyZz what is the probability that the plant will produce a gamete with a haploid genotype of Wxyz Give your answer as a fraction or as a value between 0 and 1 to four decimal places
2
A completely-plated stickleback from a marine population was mated to a low-plated stickleback from a freshwater population The resulting F1 hybrids all displayed a completely plated phenotype When the F1 hybrids were allowed to interbreed the resulting F2 generation included completely plated offspring and low-plated offspring in an approximate 31 ratio Which of the following conclusions is best supported by the results of the breeding experiments
a Phenotypic variation in the F2 generation suggests that armor morphology is controlled by many alleles of a single gene
b The completely-plated phenotype is controlled by a dominant allele of a single gene
c Armor loss is an acquired characteristic that is affected by one or more environmental factors
d Patterns of armor plating in stickleback populations are regulated by sex-specific signals
3
If a man with type AB blood marries a woman with type O what blood types would you expect in their children What fraction would you expect of each type
4
IA= Type AIB= Type Bi= Type O
If a King marries a Queen that is a carrier of hemophilia (sex-linked recessive disease that is historically fatal before adulthood) what is the chance of the Kingdom having an heir to the kingrsquos throne assuming only one child is born
5
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
7 Gregor Mendelrsquos pioneering genetic experiments with pea plants occurred before the discovery of the structure and function of chromosomes Which of the following observations about inheritance in pea plants could be explained only after the discovery that genes may be linked on a chromosome
a Pea color and pea shape display independent inheritance patterns b Offspring of a given cross show all possible combinations of traits in
equal proportions c Most offspring of a given cross have a combination of traits that is
identical to that of either one parent or the other d Recessive phenotypes can skip a generation showing up only in the
parental and F 2 generations
8
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Based on the data in Table I which of the following best explains why there are no individuals with constricted pods in the F 1 generation a Inflated pod shape is dominant to constricted pod shape b The inflated-pod offspring in the F sub one generation are
homozygous c Constricted pod shape typically arises from a new mutation in the F 1
generation d The constricted-pod offspring are carriers for the inflated pod shape
allele
9
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table I the ratio of phenotypes in the offspring from the testcross with F 1 plants that had purple flowers and inflated pods suggests that the genes for flower color and pod shape are located a close together on the same autosome b on the X chromosome c on different chromosomes d on a mitochondrial chromosome
10
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Which of the following provides the best justification for an assumption that might have been used in the computer simulation (Table II) a The broad allele is recessive to the narrow allele because broad
leaves appear in every generation b The purple allele is dominant to the white allele because all the
offspring from the cross of purple-flowered and white-flowered plants had purple flowers
c The narrow allele is codominant with the purple allele because the purple-flower trait and the narrow-leaf trait segregate together
d The white allele is dominant to both the broad and narrow alleles because plants with either type of leaf shape can have white flowers
11
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table II the F 1 offspring of the cross between broad-leaved white-flowered plants with narrow-leaved purple-flowered plants have a phenotype that differs from that of either parent However many testcross offspring have the same phenotype as one of the two plants in the parental cross but relatively few testcross offspring have the same phenotype as the F 1 offspring Which of the following best explains the observation a Recombination between the leaf-shape and flower-color genes resulted in
chromosomes carrying a dominant allele of both genes b Recombination between the broad and narrow alleles of the leaf-shape gene resulted in
chromosomes carrying three different alleles at the same genetic locus c Independent assortment of homologous chromosomes resulted in the combinations of
alleles present in the parental generation d The computer model cannot capture the possible assortments of gametes when
multiple genes are considered
Meiosis has multiple processes that increases genetic variation
Genetic Variation is due to
Mutations (last unit)
Meiosisbull Independent assortment of chromosomes paternal (red)
chromosomes maymay not move together during Meiosis Indash causes an organism with n homologous pairs to be able to
produce 2n varieties of gametes instead of only 2ndash ex humans 223=8388608
bull Crossing over swapping of sections of homologous pairs during Meiosis I produces recombinant chromosomesndash causes ldquolinkedrdquo genes to become ldquounlinkedrdquo 2 alleles on
the same chromosome maymay not move together during Meiosis I
ndash recombinant chromosomes have unique combinations of alleles
Random fertilization the particular combination of egg and sperm that results in the offspring is not predictable
ndash ex humans dadrsquos varieites of sperm (8388608) and momrsquos varieites of eggs (8388608) can produce varieties 70368744177664 offpring
Warm-UP Watch the video What is happening Why does this happen How does this increase variation
AP Test Money DUE TOMORROW 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Tomorrow
UNIT 78 TEST March 19th
Inheritance and Regulation
Fig 13-9a
MITOSIS MEIOSIS
MEIOSIS I
Prophase I
Chiasma
Chromosomereplication
Homologouschromosomepair
Chromosomereplication
2n = 6
Parent cell
Prophase
Replicated chromosome
Metaphase Metaphase I
Anaphase ITelophase I
Haploid n = 3
Daughter cells ofmeiosis I
MEIOSIS II
Daughter cells of meiosis II
nnnn
2n2n
Daughter cellsof mitosis
AnaphaseTelophase
Compare
Contrast
Independent Assortment
Crossing-over Sexual Fertilization Mutation
Types of Changes to Cells Think About what where when how how much variation created
Warm-UP Now we need to keep track of the genes on the chromosomes that are inherited Notice the letters on the chromosomes They represent different alleles for Huntingtons Barbie has Huntingtons What is the chance her child will get Huntingtons
AP Test Money DUE 36 TOMORROWRemember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Tomorrow 141 5 Key Ideas AND Concept Check 1-3
H=dominant (remember Huntingtonrsquos is dominant)
h=recessive (no Huntingtonrsquos)
Homework DUE Monday Test Corrections for 10 Make-UP
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
AP Test Money DUE 36 TODAYRemember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
DUE next Thursday Monohybrid Crosses
Homework DUE Monday Test Corrections for 10 Make-UP
Warm-UP Now we need to keep track of TWO UNLINKED genes on the chromosomes that are inherited Notice the letters on the chromosomes They represent different alleles for Huntingtons and red hair color Barbie has Huntingtons and is a blond (but a carrier) Ken does not have Huntingtonrsquos and is also a carrier for red hair What is the chance their child will get Huntingtons and red hair
Homework DUE Tomorrow 142 5 Key Ideas AND Concept Check 1-3
H= Huntingtonrsquosh=no HuntingtonrsquosR= no red hairr= red hair
DUE Now Test Corrections for 10 Make-UP
UNIT 78 TEST March 19th
Inheritance and Regulation
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
Homework DUE Tomorrow 143 5 Key Ideas AND Concept Check 1-3
DUE Now 142DUE Thursday Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
UNIT 78 TEST March 19th
Inheritance and Regulation
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoods
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with RrYy
1 Chance of baby with Rr 052 Chance of baby with Yy 053 Chance of baby with RrYy 025
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with both dominant phenotypes
1 Chance of baby with at least one R 0752 Chance of baby with at least one Y 0753 Chance of baby with RrYy 05625 (916)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with both dominant phenotypes
1 Chance of baby with at least one R 10
2 Chance of baby with at least one Y 10
3 Chance of baby with both dominant phenotypes 10
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
Homework DUE Tomorrow Linked vs Unlinked Genes AND Monohybrid Crosses to tunritincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with
vestigial wings and cinnabar eyes Predict the phenotypic ratio of the F2 individuals
Homework DUE Tomorrow 153 5 Key Ideas and Concept Check 1-3DUE Thursday Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with vestigial wings and cinnabar eyes Predict the
phenotypic ratio of the F2 individuals
3 The results of the cross from 2 show the following outcome Individuals of each phenotype are shown in the table Which of the following is the most likely explanation of the results a The two genes are located on two different chromosomes b The two genes are sex-linked c The two genes are located on mitochondrial DNA d The two genes are linked on an autosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
1 Build your diploid cell (an homologous pair for each chromosome)a Draw a big cell with a nucleus insideb DRAW homologous pairs of chromosomes
bull 1 big blue 1 big redbull 1 small blue 1 small red
ndash Add genes to your chromosomebull Write an H and an R on big blue and an h and an r on big redbull Write a T on small blue and a t on small red
2 Clone each chromosome (DNA Replication) (making sister chromatids)3 Nucleus breaks down (erase it)4 Homologous pairs form a tetrad crossing over may occur (note do not model
crossing over for now)5 Finish meiosis (see notes for help)6 Nucleus grows around chromosomes 4 cells made (gametes which have half
the number of chromosomes (haploids)7 Repeat Steps 1-6 this time at Step 4 include ONE crossover event
Recombination Modeling
When yoursquore confident on the process show Mr Jones
bull When yoursquore confident on the process show Mr Jones
bull In your notebookFigure 1510 Recombination p295At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid crossing over recombinant chromosome independent assortment Meiosis I Meiosis II
Recombination Modeling
Analysis
1 How does recombination increase the variety of gametes formed
2 Which types of gametes were more likely Gametes with recombinant chromosomes or ones without
3 Recombination is a random process How might it benefithurt the survival of an individualspecies
Recombination Modeling
Warm-UP
1 How could you calculate recombination frequency2 What would the recombination frequency tell you about the relative position of
genes on a chromosome3 Genes A B and C are on the same chromosome Testcrosses show that the
recombination frequency between A and B is 28 and between A and C is 12 Can you determine the linear order of these genes
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP What can we learn about inheritance from looking at a pedigree (use example of the Royal Family of Europe from the early 1900s)
Warm-UP In the following human pedigree squares represent males circles represent females and shaded symbols indicate individuals affected with a disorder One of the affected males from the third generation has a child with a female who is a carrier For the pedigree shown which of the following best expresses the probability that the couplersquos first son will be affected with the disorder
(A) 25 (B) 50 (C) 75 (D) 100
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Is a widowrsquos peak a dominant or recessive trait
Is a widowrsquos peak a dominant or recessive trait
Fig 14-UN5
George
Sandra Tom Sam
Arlene
Wilma Ann Michael
Carla
Daniel Alan Tina
Christopher
A heterozygous tall and a homozygous purple flowered plant is crossed with a short and white flowered plant Predict the offspring Assume independent assortment
1
P=purplep=whiteT=tallt=short
For a plant with the genotype WwXxYyZz what is the probability that the plant will produce a gamete with a haploid genotype of Wxyz Give your answer as a fraction or as a value between 0 and 1 to four decimal places
2
A completely-plated stickleback from a marine population was mated to a low-plated stickleback from a freshwater population The resulting F1 hybrids all displayed a completely plated phenotype When the F1 hybrids were allowed to interbreed the resulting F2 generation included completely plated offspring and low-plated offspring in an approximate 31 ratio Which of the following conclusions is best supported by the results of the breeding experiments
a Phenotypic variation in the F2 generation suggests that armor morphology is controlled by many alleles of a single gene
b The completely-plated phenotype is controlled by a dominant allele of a single gene
c Armor loss is an acquired characteristic that is affected by one or more environmental factors
d Patterns of armor plating in stickleback populations are regulated by sex-specific signals
3
If a man with type AB blood marries a woman with type O what blood types would you expect in their children What fraction would you expect of each type
4
IA= Type AIB= Type Bi= Type O
If a King marries a Queen that is a carrier of hemophilia (sex-linked recessive disease that is historically fatal before adulthood) what is the chance of the Kingdom having an heir to the kingrsquos throne assuming only one child is born
5
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
7 Gregor Mendelrsquos pioneering genetic experiments with pea plants occurred before the discovery of the structure and function of chromosomes Which of the following observations about inheritance in pea plants could be explained only after the discovery that genes may be linked on a chromosome
a Pea color and pea shape display independent inheritance patterns b Offspring of a given cross show all possible combinations of traits in
equal proportions c Most offspring of a given cross have a combination of traits that is
identical to that of either one parent or the other d Recessive phenotypes can skip a generation showing up only in the
parental and F 2 generations
8
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Based on the data in Table I which of the following best explains why there are no individuals with constricted pods in the F 1 generation a Inflated pod shape is dominant to constricted pod shape b The inflated-pod offspring in the F sub one generation are
homozygous c Constricted pod shape typically arises from a new mutation in the F 1
generation d The constricted-pod offspring are carriers for the inflated pod shape
allele
9
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table I the ratio of phenotypes in the offspring from the testcross with F 1 plants that had purple flowers and inflated pods suggests that the genes for flower color and pod shape are located a close together on the same autosome b on the X chromosome c on different chromosomes d on a mitochondrial chromosome
10
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Which of the following provides the best justification for an assumption that might have been used in the computer simulation (Table II) a The broad allele is recessive to the narrow allele because broad
leaves appear in every generation b The purple allele is dominant to the white allele because all the
offspring from the cross of purple-flowered and white-flowered plants had purple flowers
c The narrow allele is codominant with the purple allele because the purple-flower trait and the narrow-leaf trait segregate together
d The white allele is dominant to both the broad and narrow alleles because plants with either type of leaf shape can have white flowers
11
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table II the F 1 offspring of the cross between broad-leaved white-flowered plants with narrow-leaved purple-flowered plants have a phenotype that differs from that of either parent However many testcross offspring have the same phenotype as one of the two plants in the parental cross but relatively few testcross offspring have the same phenotype as the F 1 offspring Which of the following best explains the observation a Recombination between the leaf-shape and flower-color genes resulted in
chromosomes carrying a dominant allele of both genes b Recombination between the broad and narrow alleles of the leaf-shape gene resulted in
chromosomes carrying three different alleles at the same genetic locus c Independent assortment of homologous chromosomes resulted in the combinations of
alleles present in the parental generation d The computer model cannot capture the possible assortments of gametes when
multiple genes are considered
Warm-UP Watch the video What is happening Why does this happen How does this increase variation
AP Test Money DUE TOMORROW 36Remember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Tomorrow
UNIT 78 TEST March 19th
Inheritance and Regulation
Fig 13-9a
MITOSIS MEIOSIS
MEIOSIS I
Prophase I
Chiasma
Chromosomereplication
Homologouschromosomepair
Chromosomereplication
2n = 6
Parent cell
Prophase
Replicated chromosome
Metaphase Metaphase I
Anaphase ITelophase I
Haploid n = 3
Daughter cells ofmeiosis I
MEIOSIS II
Daughter cells of meiosis II
nnnn
2n2n
Daughter cellsof mitosis
AnaphaseTelophase
Compare
Contrast
Independent Assortment
Crossing-over Sexual Fertilization Mutation
Types of Changes to Cells Think About what where when how how much variation created
Warm-UP Now we need to keep track of the genes on the chromosomes that are inherited Notice the letters on the chromosomes They represent different alleles for Huntingtons Barbie has Huntingtons What is the chance her child will get Huntingtons
AP Test Money DUE 36 TOMORROWRemember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Tomorrow 141 5 Key Ideas AND Concept Check 1-3
H=dominant (remember Huntingtonrsquos is dominant)
h=recessive (no Huntingtonrsquos)
Homework DUE Monday Test Corrections for 10 Make-UP
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
AP Test Money DUE 36 TODAYRemember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
DUE next Thursday Monohybrid Crosses
Homework DUE Monday Test Corrections for 10 Make-UP
Warm-UP Now we need to keep track of TWO UNLINKED genes on the chromosomes that are inherited Notice the letters on the chromosomes They represent different alleles for Huntingtons and red hair color Barbie has Huntingtons and is a blond (but a carrier) Ken does not have Huntingtonrsquos and is also a carrier for red hair What is the chance their child will get Huntingtons and red hair
Homework DUE Tomorrow 142 5 Key Ideas AND Concept Check 1-3
H= Huntingtonrsquosh=no HuntingtonrsquosR= no red hairr= red hair
DUE Now Test Corrections for 10 Make-UP
UNIT 78 TEST March 19th
Inheritance and Regulation
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
Homework DUE Tomorrow 143 5 Key Ideas AND Concept Check 1-3
DUE Now 142DUE Thursday Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
UNIT 78 TEST March 19th
Inheritance and Regulation
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoods
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with RrYy
1 Chance of baby with Rr 052 Chance of baby with Yy 053 Chance of baby with RrYy 025
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with both dominant phenotypes
1 Chance of baby with at least one R 0752 Chance of baby with at least one Y 0753 Chance of baby with RrYy 05625 (916)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with both dominant phenotypes
1 Chance of baby with at least one R 10
2 Chance of baby with at least one Y 10
3 Chance of baby with both dominant phenotypes 10
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
Homework DUE Tomorrow Linked vs Unlinked Genes AND Monohybrid Crosses to tunritincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with
vestigial wings and cinnabar eyes Predict the phenotypic ratio of the F2 individuals
Homework DUE Tomorrow 153 5 Key Ideas and Concept Check 1-3DUE Thursday Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with vestigial wings and cinnabar eyes Predict the
phenotypic ratio of the F2 individuals
3 The results of the cross from 2 show the following outcome Individuals of each phenotype are shown in the table Which of the following is the most likely explanation of the results a The two genes are located on two different chromosomes b The two genes are sex-linked c The two genes are located on mitochondrial DNA d The two genes are linked on an autosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
1 Build your diploid cell (an homologous pair for each chromosome)a Draw a big cell with a nucleus insideb DRAW homologous pairs of chromosomes
bull 1 big blue 1 big redbull 1 small blue 1 small red
ndash Add genes to your chromosomebull Write an H and an R on big blue and an h and an r on big redbull Write a T on small blue and a t on small red
2 Clone each chromosome (DNA Replication) (making sister chromatids)3 Nucleus breaks down (erase it)4 Homologous pairs form a tetrad crossing over may occur (note do not model
crossing over for now)5 Finish meiosis (see notes for help)6 Nucleus grows around chromosomes 4 cells made (gametes which have half
the number of chromosomes (haploids)7 Repeat Steps 1-6 this time at Step 4 include ONE crossover event
Recombination Modeling
When yoursquore confident on the process show Mr Jones
bull When yoursquore confident on the process show Mr Jones
bull In your notebookFigure 1510 Recombination p295At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid crossing over recombinant chromosome independent assortment Meiosis I Meiosis II
Recombination Modeling
Analysis
1 How does recombination increase the variety of gametes formed
2 Which types of gametes were more likely Gametes with recombinant chromosomes or ones without
3 Recombination is a random process How might it benefithurt the survival of an individualspecies
Recombination Modeling
Warm-UP
1 How could you calculate recombination frequency2 What would the recombination frequency tell you about the relative position of
genes on a chromosome3 Genes A B and C are on the same chromosome Testcrosses show that the
recombination frequency between A and B is 28 and between A and C is 12 Can you determine the linear order of these genes
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP What can we learn about inheritance from looking at a pedigree (use example of the Royal Family of Europe from the early 1900s)
Warm-UP In the following human pedigree squares represent males circles represent females and shaded symbols indicate individuals affected with a disorder One of the affected males from the third generation has a child with a female who is a carrier For the pedigree shown which of the following best expresses the probability that the couplersquos first son will be affected with the disorder
(A) 25 (B) 50 (C) 75 (D) 100
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Is a widowrsquos peak a dominant or recessive trait
Is a widowrsquos peak a dominant or recessive trait
Fig 14-UN5
George
Sandra Tom Sam
Arlene
Wilma Ann Michael
Carla
Daniel Alan Tina
Christopher
A heterozygous tall and a homozygous purple flowered plant is crossed with a short and white flowered plant Predict the offspring Assume independent assortment
1
P=purplep=whiteT=tallt=short
For a plant with the genotype WwXxYyZz what is the probability that the plant will produce a gamete with a haploid genotype of Wxyz Give your answer as a fraction or as a value between 0 and 1 to four decimal places
2
A completely-plated stickleback from a marine population was mated to a low-plated stickleback from a freshwater population The resulting F1 hybrids all displayed a completely plated phenotype When the F1 hybrids were allowed to interbreed the resulting F2 generation included completely plated offspring and low-plated offspring in an approximate 31 ratio Which of the following conclusions is best supported by the results of the breeding experiments
a Phenotypic variation in the F2 generation suggests that armor morphology is controlled by many alleles of a single gene
b The completely-plated phenotype is controlled by a dominant allele of a single gene
c Armor loss is an acquired characteristic that is affected by one or more environmental factors
d Patterns of armor plating in stickleback populations are regulated by sex-specific signals
3
If a man with type AB blood marries a woman with type O what blood types would you expect in their children What fraction would you expect of each type
4
IA= Type AIB= Type Bi= Type O
If a King marries a Queen that is a carrier of hemophilia (sex-linked recessive disease that is historically fatal before adulthood) what is the chance of the Kingdom having an heir to the kingrsquos throne assuming only one child is born
5
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
7 Gregor Mendelrsquos pioneering genetic experiments with pea plants occurred before the discovery of the structure and function of chromosomes Which of the following observations about inheritance in pea plants could be explained only after the discovery that genes may be linked on a chromosome
a Pea color and pea shape display independent inheritance patterns b Offspring of a given cross show all possible combinations of traits in
equal proportions c Most offspring of a given cross have a combination of traits that is
identical to that of either one parent or the other d Recessive phenotypes can skip a generation showing up only in the
parental and F 2 generations
8
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Based on the data in Table I which of the following best explains why there are no individuals with constricted pods in the F 1 generation a Inflated pod shape is dominant to constricted pod shape b The inflated-pod offspring in the F sub one generation are
homozygous c Constricted pod shape typically arises from a new mutation in the F 1
generation d The constricted-pod offspring are carriers for the inflated pod shape
allele
9
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table I the ratio of phenotypes in the offspring from the testcross with F 1 plants that had purple flowers and inflated pods suggests that the genes for flower color and pod shape are located a close together on the same autosome b on the X chromosome c on different chromosomes d on a mitochondrial chromosome
10
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Which of the following provides the best justification for an assumption that might have been used in the computer simulation (Table II) a The broad allele is recessive to the narrow allele because broad
leaves appear in every generation b The purple allele is dominant to the white allele because all the
offspring from the cross of purple-flowered and white-flowered plants had purple flowers
c The narrow allele is codominant with the purple allele because the purple-flower trait and the narrow-leaf trait segregate together
d The white allele is dominant to both the broad and narrow alleles because plants with either type of leaf shape can have white flowers
11
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table II the F 1 offspring of the cross between broad-leaved white-flowered plants with narrow-leaved purple-flowered plants have a phenotype that differs from that of either parent However many testcross offspring have the same phenotype as one of the two plants in the parental cross but relatively few testcross offspring have the same phenotype as the F 1 offspring Which of the following best explains the observation a Recombination between the leaf-shape and flower-color genes resulted in
chromosomes carrying a dominant allele of both genes b Recombination between the broad and narrow alleles of the leaf-shape gene resulted in
chromosomes carrying three different alleles at the same genetic locus c Independent assortment of homologous chromosomes resulted in the combinations of
alleles present in the parental generation d The computer model cannot capture the possible assortments of gametes when
multiple genes are considered
Fig 13-9a
MITOSIS MEIOSIS
MEIOSIS I
Prophase I
Chiasma
Chromosomereplication
Homologouschromosomepair
Chromosomereplication
2n = 6
Parent cell
Prophase
Replicated chromosome
Metaphase Metaphase I
Anaphase ITelophase I
Haploid n = 3
Daughter cells ofmeiosis I
MEIOSIS II
Daughter cells of meiosis II
nnnn
2n2n
Daughter cellsof mitosis
AnaphaseTelophase
Compare
Contrast
Independent Assortment
Crossing-over Sexual Fertilization Mutation
Types of Changes to Cells Think About what where when how how much variation created
Warm-UP Now we need to keep track of the genes on the chromosomes that are inherited Notice the letters on the chromosomes They represent different alleles for Huntingtons Barbie has Huntingtons What is the chance her child will get Huntingtons
AP Test Money DUE 36 TOMORROWRemember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Tomorrow 141 5 Key Ideas AND Concept Check 1-3
H=dominant (remember Huntingtonrsquos is dominant)
h=recessive (no Huntingtonrsquos)
Homework DUE Monday Test Corrections for 10 Make-UP
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
AP Test Money DUE 36 TODAYRemember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
DUE next Thursday Monohybrid Crosses
Homework DUE Monday Test Corrections for 10 Make-UP
Warm-UP Now we need to keep track of TWO UNLINKED genes on the chromosomes that are inherited Notice the letters on the chromosomes They represent different alleles for Huntingtons and red hair color Barbie has Huntingtons and is a blond (but a carrier) Ken does not have Huntingtonrsquos and is also a carrier for red hair What is the chance their child will get Huntingtons and red hair
Homework DUE Tomorrow 142 5 Key Ideas AND Concept Check 1-3
H= Huntingtonrsquosh=no HuntingtonrsquosR= no red hairr= red hair
DUE Now Test Corrections for 10 Make-UP
UNIT 78 TEST March 19th
Inheritance and Regulation
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
Homework DUE Tomorrow 143 5 Key Ideas AND Concept Check 1-3
DUE Now 142DUE Thursday Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
UNIT 78 TEST March 19th
Inheritance and Regulation
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoods
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with RrYy
1 Chance of baby with Rr 052 Chance of baby with Yy 053 Chance of baby with RrYy 025
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with both dominant phenotypes
1 Chance of baby with at least one R 0752 Chance of baby with at least one Y 0753 Chance of baby with RrYy 05625 (916)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with both dominant phenotypes
1 Chance of baby with at least one R 10
2 Chance of baby with at least one Y 10
3 Chance of baby with both dominant phenotypes 10
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
Homework DUE Tomorrow Linked vs Unlinked Genes AND Monohybrid Crosses to tunritincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with
vestigial wings and cinnabar eyes Predict the phenotypic ratio of the F2 individuals
Homework DUE Tomorrow 153 5 Key Ideas and Concept Check 1-3DUE Thursday Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with vestigial wings and cinnabar eyes Predict the
phenotypic ratio of the F2 individuals
3 The results of the cross from 2 show the following outcome Individuals of each phenotype are shown in the table Which of the following is the most likely explanation of the results a The two genes are located on two different chromosomes b The two genes are sex-linked c The two genes are located on mitochondrial DNA d The two genes are linked on an autosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
1 Build your diploid cell (an homologous pair for each chromosome)a Draw a big cell with a nucleus insideb DRAW homologous pairs of chromosomes
bull 1 big blue 1 big redbull 1 small blue 1 small red
ndash Add genes to your chromosomebull Write an H and an R on big blue and an h and an r on big redbull Write a T on small blue and a t on small red
2 Clone each chromosome (DNA Replication) (making sister chromatids)3 Nucleus breaks down (erase it)4 Homologous pairs form a tetrad crossing over may occur (note do not model
crossing over for now)5 Finish meiosis (see notes for help)6 Nucleus grows around chromosomes 4 cells made (gametes which have half
the number of chromosomes (haploids)7 Repeat Steps 1-6 this time at Step 4 include ONE crossover event
Recombination Modeling
When yoursquore confident on the process show Mr Jones
bull When yoursquore confident on the process show Mr Jones
bull In your notebookFigure 1510 Recombination p295At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid crossing over recombinant chromosome independent assortment Meiosis I Meiosis II
Recombination Modeling
Analysis
1 How does recombination increase the variety of gametes formed
2 Which types of gametes were more likely Gametes with recombinant chromosomes or ones without
3 Recombination is a random process How might it benefithurt the survival of an individualspecies
Recombination Modeling
Warm-UP
1 How could you calculate recombination frequency2 What would the recombination frequency tell you about the relative position of
genes on a chromosome3 Genes A B and C are on the same chromosome Testcrosses show that the
recombination frequency between A and B is 28 and between A and C is 12 Can you determine the linear order of these genes
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP What can we learn about inheritance from looking at a pedigree (use example of the Royal Family of Europe from the early 1900s)
Warm-UP In the following human pedigree squares represent males circles represent females and shaded symbols indicate individuals affected with a disorder One of the affected males from the third generation has a child with a female who is a carrier For the pedigree shown which of the following best expresses the probability that the couplersquos first son will be affected with the disorder
(A) 25 (B) 50 (C) 75 (D) 100
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Is a widowrsquos peak a dominant or recessive trait
Is a widowrsquos peak a dominant or recessive trait
Fig 14-UN5
George
Sandra Tom Sam
Arlene
Wilma Ann Michael
Carla
Daniel Alan Tina
Christopher
A heterozygous tall and a homozygous purple flowered plant is crossed with a short and white flowered plant Predict the offspring Assume independent assortment
1
P=purplep=whiteT=tallt=short
For a plant with the genotype WwXxYyZz what is the probability that the plant will produce a gamete with a haploid genotype of Wxyz Give your answer as a fraction or as a value between 0 and 1 to four decimal places
2
A completely-plated stickleback from a marine population was mated to a low-plated stickleback from a freshwater population The resulting F1 hybrids all displayed a completely plated phenotype When the F1 hybrids were allowed to interbreed the resulting F2 generation included completely plated offspring and low-plated offspring in an approximate 31 ratio Which of the following conclusions is best supported by the results of the breeding experiments
a Phenotypic variation in the F2 generation suggests that armor morphology is controlled by many alleles of a single gene
b The completely-plated phenotype is controlled by a dominant allele of a single gene
c Armor loss is an acquired characteristic that is affected by one or more environmental factors
d Patterns of armor plating in stickleback populations are regulated by sex-specific signals
3
If a man with type AB blood marries a woman with type O what blood types would you expect in their children What fraction would you expect of each type
4
IA= Type AIB= Type Bi= Type O
If a King marries a Queen that is a carrier of hemophilia (sex-linked recessive disease that is historically fatal before adulthood) what is the chance of the Kingdom having an heir to the kingrsquos throne assuming only one child is born
5
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
7 Gregor Mendelrsquos pioneering genetic experiments with pea plants occurred before the discovery of the structure and function of chromosomes Which of the following observations about inheritance in pea plants could be explained only after the discovery that genes may be linked on a chromosome
a Pea color and pea shape display independent inheritance patterns b Offspring of a given cross show all possible combinations of traits in
equal proportions c Most offspring of a given cross have a combination of traits that is
identical to that of either one parent or the other d Recessive phenotypes can skip a generation showing up only in the
parental and F 2 generations
8
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Based on the data in Table I which of the following best explains why there are no individuals with constricted pods in the F 1 generation a Inflated pod shape is dominant to constricted pod shape b The inflated-pod offspring in the F sub one generation are
homozygous c Constricted pod shape typically arises from a new mutation in the F 1
generation d The constricted-pod offspring are carriers for the inflated pod shape
allele
9
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table I the ratio of phenotypes in the offspring from the testcross with F 1 plants that had purple flowers and inflated pods suggests that the genes for flower color and pod shape are located a close together on the same autosome b on the X chromosome c on different chromosomes d on a mitochondrial chromosome
10
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Which of the following provides the best justification for an assumption that might have been used in the computer simulation (Table II) a The broad allele is recessive to the narrow allele because broad
leaves appear in every generation b The purple allele is dominant to the white allele because all the
offspring from the cross of purple-flowered and white-flowered plants had purple flowers
c The narrow allele is codominant with the purple allele because the purple-flower trait and the narrow-leaf trait segregate together
d The white allele is dominant to both the broad and narrow alleles because plants with either type of leaf shape can have white flowers
11
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table II the F 1 offspring of the cross between broad-leaved white-flowered plants with narrow-leaved purple-flowered plants have a phenotype that differs from that of either parent However many testcross offspring have the same phenotype as one of the two plants in the parental cross but relatively few testcross offspring have the same phenotype as the F 1 offspring Which of the following best explains the observation a Recombination between the leaf-shape and flower-color genes resulted in
chromosomes carrying a dominant allele of both genes b Recombination between the broad and narrow alleles of the leaf-shape gene resulted in
chromosomes carrying three different alleles at the same genetic locus c Independent assortment of homologous chromosomes resulted in the combinations of
alleles present in the parental generation d The computer model cannot capture the possible assortments of gametes when
multiple genes are considered
Compare
Contrast
Independent Assortment
Crossing-over Sexual Fertilization Mutation
Types of Changes to Cells Think About what where when how how much variation created
Warm-UP Now we need to keep track of the genes on the chromosomes that are inherited Notice the letters on the chromosomes They represent different alleles for Huntingtons Barbie has Huntingtons What is the chance her child will get Huntingtons
AP Test Money DUE 36 TOMORROWRemember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Tomorrow 141 5 Key Ideas AND Concept Check 1-3
H=dominant (remember Huntingtonrsquos is dominant)
h=recessive (no Huntingtonrsquos)
Homework DUE Monday Test Corrections for 10 Make-UP
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
AP Test Money DUE 36 TODAYRemember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
DUE next Thursday Monohybrid Crosses
Homework DUE Monday Test Corrections for 10 Make-UP
Warm-UP Now we need to keep track of TWO UNLINKED genes on the chromosomes that are inherited Notice the letters on the chromosomes They represent different alleles for Huntingtons and red hair color Barbie has Huntingtons and is a blond (but a carrier) Ken does not have Huntingtonrsquos and is also a carrier for red hair What is the chance their child will get Huntingtons and red hair
Homework DUE Tomorrow 142 5 Key Ideas AND Concept Check 1-3
H= Huntingtonrsquosh=no HuntingtonrsquosR= no red hairr= red hair
DUE Now Test Corrections for 10 Make-UP
UNIT 78 TEST March 19th
Inheritance and Regulation
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
Homework DUE Tomorrow 143 5 Key Ideas AND Concept Check 1-3
DUE Now 142DUE Thursday Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
UNIT 78 TEST March 19th
Inheritance and Regulation
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoods
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with RrYy
1 Chance of baby with Rr 052 Chance of baby with Yy 053 Chance of baby with RrYy 025
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with both dominant phenotypes
1 Chance of baby with at least one R 0752 Chance of baby with at least one Y 0753 Chance of baby with RrYy 05625 (916)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with both dominant phenotypes
1 Chance of baby with at least one R 10
2 Chance of baby with at least one Y 10
3 Chance of baby with both dominant phenotypes 10
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
Homework DUE Tomorrow Linked vs Unlinked Genes AND Monohybrid Crosses to tunritincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with
vestigial wings and cinnabar eyes Predict the phenotypic ratio of the F2 individuals
Homework DUE Tomorrow 153 5 Key Ideas and Concept Check 1-3DUE Thursday Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with vestigial wings and cinnabar eyes Predict the
phenotypic ratio of the F2 individuals
3 The results of the cross from 2 show the following outcome Individuals of each phenotype are shown in the table Which of the following is the most likely explanation of the results a The two genes are located on two different chromosomes b The two genes are sex-linked c The two genes are located on mitochondrial DNA d The two genes are linked on an autosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
1 Build your diploid cell (an homologous pair for each chromosome)a Draw a big cell with a nucleus insideb DRAW homologous pairs of chromosomes
bull 1 big blue 1 big redbull 1 small blue 1 small red
ndash Add genes to your chromosomebull Write an H and an R on big blue and an h and an r on big redbull Write a T on small blue and a t on small red
2 Clone each chromosome (DNA Replication) (making sister chromatids)3 Nucleus breaks down (erase it)4 Homologous pairs form a tetrad crossing over may occur (note do not model
crossing over for now)5 Finish meiosis (see notes for help)6 Nucleus grows around chromosomes 4 cells made (gametes which have half
the number of chromosomes (haploids)7 Repeat Steps 1-6 this time at Step 4 include ONE crossover event
Recombination Modeling
When yoursquore confident on the process show Mr Jones
bull When yoursquore confident on the process show Mr Jones
bull In your notebookFigure 1510 Recombination p295At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid crossing over recombinant chromosome independent assortment Meiosis I Meiosis II
Recombination Modeling
Analysis
1 How does recombination increase the variety of gametes formed
2 Which types of gametes were more likely Gametes with recombinant chromosomes or ones without
3 Recombination is a random process How might it benefithurt the survival of an individualspecies
Recombination Modeling
Warm-UP
1 How could you calculate recombination frequency2 What would the recombination frequency tell you about the relative position of
genes on a chromosome3 Genes A B and C are on the same chromosome Testcrosses show that the
recombination frequency between A and B is 28 and between A and C is 12 Can you determine the linear order of these genes
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP What can we learn about inheritance from looking at a pedigree (use example of the Royal Family of Europe from the early 1900s)
Warm-UP In the following human pedigree squares represent males circles represent females and shaded symbols indicate individuals affected with a disorder One of the affected males from the third generation has a child with a female who is a carrier For the pedigree shown which of the following best expresses the probability that the couplersquos first son will be affected with the disorder
(A) 25 (B) 50 (C) 75 (D) 100
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Is a widowrsquos peak a dominant or recessive trait
Is a widowrsquos peak a dominant or recessive trait
Fig 14-UN5
George
Sandra Tom Sam
Arlene
Wilma Ann Michael
Carla
Daniel Alan Tina
Christopher
A heterozygous tall and a homozygous purple flowered plant is crossed with a short and white flowered plant Predict the offspring Assume independent assortment
1
P=purplep=whiteT=tallt=short
For a plant with the genotype WwXxYyZz what is the probability that the plant will produce a gamete with a haploid genotype of Wxyz Give your answer as a fraction or as a value between 0 and 1 to four decimal places
2
A completely-plated stickleback from a marine population was mated to a low-plated stickleback from a freshwater population The resulting F1 hybrids all displayed a completely plated phenotype When the F1 hybrids were allowed to interbreed the resulting F2 generation included completely plated offspring and low-plated offspring in an approximate 31 ratio Which of the following conclusions is best supported by the results of the breeding experiments
a Phenotypic variation in the F2 generation suggests that armor morphology is controlled by many alleles of a single gene
b The completely-plated phenotype is controlled by a dominant allele of a single gene
c Armor loss is an acquired characteristic that is affected by one or more environmental factors
d Patterns of armor plating in stickleback populations are regulated by sex-specific signals
3
If a man with type AB blood marries a woman with type O what blood types would you expect in their children What fraction would you expect of each type
4
IA= Type AIB= Type Bi= Type O
If a King marries a Queen that is a carrier of hemophilia (sex-linked recessive disease that is historically fatal before adulthood) what is the chance of the Kingdom having an heir to the kingrsquos throne assuming only one child is born
5
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
7 Gregor Mendelrsquos pioneering genetic experiments with pea plants occurred before the discovery of the structure and function of chromosomes Which of the following observations about inheritance in pea plants could be explained only after the discovery that genes may be linked on a chromosome
a Pea color and pea shape display independent inheritance patterns b Offspring of a given cross show all possible combinations of traits in
equal proportions c Most offspring of a given cross have a combination of traits that is
identical to that of either one parent or the other d Recessive phenotypes can skip a generation showing up only in the
parental and F 2 generations
8
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Based on the data in Table I which of the following best explains why there are no individuals with constricted pods in the F 1 generation a Inflated pod shape is dominant to constricted pod shape b The inflated-pod offspring in the F sub one generation are
homozygous c Constricted pod shape typically arises from a new mutation in the F 1
generation d The constricted-pod offspring are carriers for the inflated pod shape
allele
9
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table I the ratio of phenotypes in the offspring from the testcross with F 1 plants that had purple flowers and inflated pods suggests that the genes for flower color and pod shape are located a close together on the same autosome b on the X chromosome c on different chromosomes d on a mitochondrial chromosome
10
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Which of the following provides the best justification for an assumption that might have been used in the computer simulation (Table II) a The broad allele is recessive to the narrow allele because broad
leaves appear in every generation b The purple allele is dominant to the white allele because all the
offspring from the cross of purple-flowered and white-flowered plants had purple flowers
c The narrow allele is codominant with the purple allele because the purple-flower trait and the narrow-leaf trait segregate together
d The white allele is dominant to both the broad and narrow alleles because plants with either type of leaf shape can have white flowers
11
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table II the F 1 offspring of the cross between broad-leaved white-flowered plants with narrow-leaved purple-flowered plants have a phenotype that differs from that of either parent However many testcross offspring have the same phenotype as one of the two plants in the parental cross but relatively few testcross offspring have the same phenotype as the F 1 offspring Which of the following best explains the observation a Recombination between the leaf-shape and flower-color genes resulted in
chromosomes carrying a dominant allele of both genes b Recombination between the broad and narrow alleles of the leaf-shape gene resulted in
chromosomes carrying three different alleles at the same genetic locus c Independent assortment of homologous chromosomes resulted in the combinations of
alleles present in the parental generation d The computer model cannot capture the possible assortments of gametes when
multiple genes are considered
Warm-UP Now we need to keep track of the genes on the chromosomes that are inherited Notice the letters on the chromosomes They represent different alleles for Huntingtons Barbie has Huntingtons What is the chance her child will get Huntingtons
AP Test Money DUE 36 TOMORROWRemember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
Homework DUE Tomorrow 141 5 Key Ideas AND Concept Check 1-3
H=dominant (remember Huntingtonrsquos is dominant)
h=recessive (no Huntingtonrsquos)
Homework DUE Monday Test Corrections for 10 Make-UP
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
AP Test Money DUE 36 TODAYRemember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
DUE next Thursday Monohybrid Crosses
Homework DUE Monday Test Corrections for 10 Make-UP
Warm-UP Now we need to keep track of TWO UNLINKED genes on the chromosomes that are inherited Notice the letters on the chromosomes They represent different alleles for Huntingtons and red hair color Barbie has Huntingtons and is a blond (but a carrier) Ken does not have Huntingtonrsquos and is also a carrier for red hair What is the chance their child will get Huntingtons and red hair
Homework DUE Tomorrow 142 5 Key Ideas AND Concept Check 1-3
H= Huntingtonrsquosh=no HuntingtonrsquosR= no red hairr= red hair
DUE Now Test Corrections for 10 Make-UP
UNIT 78 TEST March 19th
Inheritance and Regulation
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
Homework DUE Tomorrow 143 5 Key Ideas AND Concept Check 1-3
DUE Now 142DUE Thursday Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
UNIT 78 TEST March 19th
Inheritance and Regulation
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoods
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with RrYy
1 Chance of baby with Rr 052 Chance of baby with Yy 053 Chance of baby with RrYy 025
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with both dominant phenotypes
1 Chance of baby with at least one R 0752 Chance of baby with at least one Y 0753 Chance of baby with RrYy 05625 (916)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with both dominant phenotypes
1 Chance of baby with at least one R 10
2 Chance of baby with at least one Y 10
3 Chance of baby with both dominant phenotypes 10
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
Homework DUE Tomorrow Linked vs Unlinked Genes AND Monohybrid Crosses to tunritincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with
vestigial wings and cinnabar eyes Predict the phenotypic ratio of the F2 individuals
Homework DUE Tomorrow 153 5 Key Ideas and Concept Check 1-3DUE Thursday Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with vestigial wings and cinnabar eyes Predict the
phenotypic ratio of the F2 individuals
3 The results of the cross from 2 show the following outcome Individuals of each phenotype are shown in the table Which of the following is the most likely explanation of the results a The two genes are located on two different chromosomes b The two genes are sex-linked c The two genes are located on mitochondrial DNA d The two genes are linked on an autosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
1 Build your diploid cell (an homologous pair for each chromosome)a Draw a big cell with a nucleus insideb DRAW homologous pairs of chromosomes
bull 1 big blue 1 big redbull 1 small blue 1 small red
ndash Add genes to your chromosomebull Write an H and an R on big blue and an h and an r on big redbull Write a T on small blue and a t on small red
2 Clone each chromosome (DNA Replication) (making sister chromatids)3 Nucleus breaks down (erase it)4 Homologous pairs form a tetrad crossing over may occur (note do not model
crossing over for now)5 Finish meiosis (see notes for help)6 Nucleus grows around chromosomes 4 cells made (gametes which have half
the number of chromosomes (haploids)7 Repeat Steps 1-6 this time at Step 4 include ONE crossover event
Recombination Modeling
When yoursquore confident on the process show Mr Jones
bull When yoursquore confident on the process show Mr Jones
bull In your notebookFigure 1510 Recombination p295At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid crossing over recombinant chromosome independent assortment Meiosis I Meiosis II
Recombination Modeling
Analysis
1 How does recombination increase the variety of gametes formed
2 Which types of gametes were more likely Gametes with recombinant chromosomes or ones without
3 Recombination is a random process How might it benefithurt the survival of an individualspecies
Recombination Modeling
Warm-UP
1 How could you calculate recombination frequency2 What would the recombination frequency tell you about the relative position of
genes on a chromosome3 Genes A B and C are on the same chromosome Testcrosses show that the
recombination frequency between A and B is 28 and between A and C is 12 Can you determine the linear order of these genes
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP What can we learn about inheritance from looking at a pedigree (use example of the Royal Family of Europe from the early 1900s)
Warm-UP In the following human pedigree squares represent males circles represent females and shaded symbols indicate individuals affected with a disorder One of the affected males from the third generation has a child with a female who is a carrier For the pedigree shown which of the following best expresses the probability that the couplersquos first son will be affected with the disorder
(A) 25 (B) 50 (C) 75 (D) 100
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Is a widowrsquos peak a dominant or recessive trait
Is a widowrsquos peak a dominant or recessive trait
Fig 14-UN5
George
Sandra Tom Sam
Arlene
Wilma Ann Michael
Carla
Daniel Alan Tina
Christopher
A heterozygous tall and a homozygous purple flowered plant is crossed with a short and white flowered plant Predict the offspring Assume independent assortment
1
P=purplep=whiteT=tallt=short
For a plant with the genotype WwXxYyZz what is the probability that the plant will produce a gamete with a haploid genotype of Wxyz Give your answer as a fraction or as a value between 0 and 1 to four decimal places
2
A completely-plated stickleback from a marine population was mated to a low-plated stickleback from a freshwater population The resulting F1 hybrids all displayed a completely plated phenotype When the F1 hybrids were allowed to interbreed the resulting F2 generation included completely plated offspring and low-plated offspring in an approximate 31 ratio Which of the following conclusions is best supported by the results of the breeding experiments
a Phenotypic variation in the F2 generation suggests that armor morphology is controlled by many alleles of a single gene
b The completely-plated phenotype is controlled by a dominant allele of a single gene
c Armor loss is an acquired characteristic that is affected by one or more environmental factors
d Patterns of armor plating in stickleback populations are regulated by sex-specific signals
3
If a man with type AB blood marries a woman with type O what blood types would you expect in their children What fraction would you expect of each type
4
IA= Type AIB= Type Bi= Type O
If a King marries a Queen that is a carrier of hemophilia (sex-linked recessive disease that is historically fatal before adulthood) what is the chance of the Kingdom having an heir to the kingrsquos throne assuming only one child is born
5
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
7 Gregor Mendelrsquos pioneering genetic experiments with pea plants occurred before the discovery of the structure and function of chromosomes Which of the following observations about inheritance in pea plants could be explained only after the discovery that genes may be linked on a chromosome
a Pea color and pea shape display independent inheritance patterns b Offspring of a given cross show all possible combinations of traits in
equal proportions c Most offspring of a given cross have a combination of traits that is
identical to that of either one parent or the other d Recessive phenotypes can skip a generation showing up only in the
parental and F 2 generations
8
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Based on the data in Table I which of the following best explains why there are no individuals with constricted pods in the F 1 generation a Inflated pod shape is dominant to constricted pod shape b The inflated-pod offspring in the F sub one generation are
homozygous c Constricted pod shape typically arises from a new mutation in the F 1
generation d The constricted-pod offspring are carriers for the inflated pod shape
allele
9
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table I the ratio of phenotypes in the offspring from the testcross with F 1 plants that had purple flowers and inflated pods suggests that the genes for flower color and pod shape are located a close together on the same autosome b on the X chromosome c on different chromosomes d on a mitochondrial chromosome
10
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Which of the following provides the best justification for an assumption that might have been used in the computer simulation (Table II) a The broad allele is recessive to the narrow allele because broad
leaves appear in every generation b The purple allele is dominant to the white allele because all the
offspring from the cross of purple-flowered and white-flowered plants had purple flowers
c The narrow allele is codominant with the purple allele because the purple-flower trait and the narrow-leaf trait segregate together
d The white allele is dominant to both the broad and narrow alleles because plants with either type of leaf shape can have white flowers
11
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table II the F 1 offspring of the cross between broad-leaved white-flowered plants with narrow-leaved purple-flowered plants have a phenotype that differs from that of either parent However many testcross offspring have the same phenotype as one of the two plants in the parental cross but relatively few testcross offspring have the same phenotype as the F 1 offspring Which of the following best explains the observation a Recombination between the leaf-shape and flower-color genes resulted in
chromosomes carrying a dominant allele of both genes b Recombination between the broad and narrow alleles of the leaf-shape gene resulted in
chromosomes carrying three different alleles at the same genetic locus c Independent assortment of homologous chromosomes resulted in the combinations of
alleles present in the parental generation d The computer model cannot capture the possible assortments of gametes when
multiple genes are considered
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
AP Test Money DUE 36 TODAYRemember the 2nd semester Final Exam will be an AP test (the week before the official AP test) you might as well take the official test too
DUE next Thursday Monohybrid Crosses
Homework DUE Monday Test Corrections for 10 Make-UP
Warm-UP Now we need to keep track of TWO UNLINKED genes on the chromosomes that are inherited Notice the letters on the chromosomes They represent different alleles for Huntingtons and red hair color Barbie has Huntingtons and is a blond (but a carrier) Ken does not have Huntingtonrsquos and is also a carrier for red hair What is the chance their child will get Huntingtons and red hair
Homework DUE Tomorrow 142 5 Key Ideas AND Concept Check 1-3
H= Huntingtonrsquosh=no HuntingtonrsquosR= no red hairr= red hair
DUE Now Test Corrections for 10 Make-UP
UNIT 78 TEST March 19th
Inheritance and Regulation
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
Homework DUE Tomorrow 143 5 Key Ideas AND Concept Check 1-3
DUE Now 142DUE Thursday Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
UNIT 78 TEST March 19th
Inheritance and Regulation
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoods
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with RrYy
1 Chance of baby with Rr 052 Chance of baby with Yy 053 Chance of baby with RrYy 025
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with both dominant phenotypes
1 Chance of baby with at least one R 0752 Chance of baby with at least one Y 0753 Chance of baby with RrYy 05625 (916)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with both dominant phenotypes
1 Chance of baby with at least one R 10
2 Chance of baby with at least one Y 10
3 Chance of baby with both dominant phenotypes 10
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
Homework DUE Tomorrow Linked vs Unlinked Genes AND Monohybrid Crosses to tunritincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with
vestigial wings and cinnabar eyes Predict the phenotypic ratio of the F2 individuals
Homework DUE Tomorrow 153 5 Key Ideas and Concept Check 1-3DUE Thursday Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with vestigial wings and cinnabar eyes Predict the
phenotypic ratio of the F2 individuals
3 The results of the cross from 2 show the following outcome Individuals of each phenotype are shown in the table Which of the following is the most likely explanation of the results a The two genes are located on two different chromosomes b The two genes are sex-linked c The two genes are located on mitochondrial DNA d The two genes are linked on an autosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
1 Build your diploid cell (an homologous pair for each chromosome)a Draw a big cell with a nucleus insideb DRAW homologous pairs of chromosomes
bull 1 big blue 1 big redbull 1 small blue 1 small red
ndash Add genes to your chromosomebull Write an H and an R on big blue and an h and an r on big redbull Write a T on small blue and a t on small red
2 Clone each chromosome (DNA Replication) (making sister chromatids)3 Nucleus breaks down (erase it)4 Homologous pairs form a tetrad crossing over may occur (note do not model
crossing over for now)5 Finish meiosis (see notes for help)6 Nucleus grows around chromosomes 4 cells made (gametes which have half
the number of chromosomes (haploids)7 Repeat Steps 1-6 this time at Step 4 include ONE crossover event
Recombination Modeling
When yoursquore confident on the process show Mr Jones
bull When yoursquore confident on the process show Mr Jones
bull In your notebookFigure 1510 Recombination p295At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid crossing over recombinant chromosome independent assortment Meiosis I Meiosis II
Recombination Modeling
Analysis
1 How does recombination increase the variety of gametes formed
2 Which types of gametes were more likely Gametes with recombinant chromosomes or ones without
3 Recombination is a random process How might it benefithurt the survival of an individualspecies
Recombination Modeling
Warm-UP
1 How could you calculate recombination frequency2 What would the recombination frequency tell you about the relative position of
genes on a chromosome3 Genes A B and C are on the same chromosome Testcrosses show that the
recombination frequency between A and B is 28 and between A and C is 12 Can you determine the linear order of these genes
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP What can we learn about inheritance from looking at a pedigree (use example of the Royal Family of Europe from the early 1900s)
Warm-UP In the following human pedigree squares represent males circles represent females and shaded symbols indicate individuals affected with a disorder One of the affected males from the third generation has a child with a female who is a carrier For the pedigree shown which of the following best expresses the probability that the couplersquos first son will be affected with the disorder
(A) 25 (B) 50 (C) 75 (D) 100
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Is a widowrsquos peak a dominant or recessive trait
Is a widowrsquos peak a dominant or recessive trait
Fig 14-UN5
George
Sandra Tom Sam
Arlene
Wilma Ann Michael
Carla
Daniel Alan Tina
Christopher
A heterozygous tall and a homozygous purple flowered plant is crossed with a short and white flowered plant Predict the offspring Assume independent assortment
1
P=purplep=whiteT=tallt=short
For a plant with the genotype WwXxYyZz what is the probability that the plant will produce a gamete with a haploid genotype of Wxyz Give your answer as a fraction or as a value between 0 and 1 to four decimal places
2
A completely-plated stickleback from a marine population was mated to a low-plated stickleback from a freshwater population The resulting F1 hybrids all displayed a completely plated phenotype When the F1 hybrids were allowed to interbreed the resulting F2 generation included completely plated offspring and low-plated offspring in an approximate 31 ratio Which of the following conclusions is best supported by the results of the breeding experiments
a Phenotypic variation in the F2 generation suggests that armor morphology is controlled by many alleles of a single gene
b The completely-plated phenotype is controlled by a dominant allele of a single gene
c Armor loss is an acquired characteristic that is affected by one or more environmental factors
d Patterns of armor plating in stickleback populations are regulated by sex-specific signals
3
If a man with type AB blood marries a woman with type O what blood types would you expect in their children What fraction would you expect of each type
4
IA= Type AIB= Type Bi= Type O
If a King marries a Queen that is a carrier of hemophilia (sex-linked recessive disease that is historically fatal before adulthood) what is the chance of the Kingdom having an heir to the kingrsquos throne assuming only one child is born
5
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
7 Gregor Mendelrsquos pioneering genetic experiments with pea plants occurred before the discovery of the structure and function of chromosomes Which of the following observations about inheritance in pea plants could be explained only after the discovery that genes may be linked on a chromosome
a Pea color and pea shape display independent inheritance patterns b Offspring of a given cross show all possible combinations of traits in
equal proportions c Most offspring of a given cross have a combination of traits that is
identical to that of either one parent or the other d Recessive phenotypes can skip a generation showing up only in the
parental and F 2 generations
8
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Based on the data in Table I which of the following best explains why there are no individuals with constricted pods in the F 1 generation a Inflated pod shape is dominant to constricted pod shape b The inflated-pod offspring in the F sub one generation are
homozygous c Constricted pod shape typically arises from a new mutation in the F 1
generation d The constricted-pod offspring are carriers for the inflated pod shape
allele
9
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table I the ratio of phenotypes in the offspring from the testcross with F 1 plants that had purple flowers and inflated pods suggests that the genes for flower color and pod shape are located a close together on the same autosome b on the X chromosome c on different chromosomes d on a mitochondrial chromosome
10
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Which of the following provides the best justification for an assumption that might have been used in the computer simulation (Table II) a The broad allele is recessive to the narrow allele because broad
leaves appear in every generation b The purple allele is dominant to the white allele because all the
offspring from the cross of purple-flowered and white-flowered plants had purple flowers
c The narrow allele is codominant with the purple allele because the purple-flower trait and the narrow-leaf trait segregate together
d The white allele is dominant to both the broad and narrow alleles because plants with either type of leaf shape can have white flowers
11
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table II the F 1 offspring of the cross between broad-leaved white-flowered plants with narrow-leaved purple-flowered plants have a phenotype that differs from that of either parent However many testcross offspring have the same phenotype as one of the two plants in the parental cross but relatively few testcross offspring have the same phenotype as the F 1 offspring Which of the following best explains the observation a Recombination between the leaf-shape and flower-color genes resulted in
chromosomes carrying a dominant allele of both genes b Recombination between the broad and narrow alleles of the leaf-shape gene resulted in
chromosomes carrying three different alleles at the same genetic locus c Independent assortment of homologous chromosomes resulted in the combinations of
alleles present in the parental generation d The computer model cannot capture the possible assortments of gametes when
multiple genes are considered
Warm-UP Now we need to keep track of TWO UNLINKED genes on the chromosomes that are inherited Notice the letters on the chromosomes They represent different alleles for Huntingtons and red hair color Barbie has Huntingtons and is a blond (but a carrier) Ken does not have Huntingtonrsquos and is also a carrier for red hair What is the chance their child will get Huntingtons and red hair
Homework DUE Tomorrow 142 5 Key Ideas AND Concept Check 1-3
H= Huntingtonrsquosh=no HuntingtonrsquosR= no red hairr= red hair
DUE Now Test Corrections for 10 Make-UP
UNIT 78 TEST March 19th
Inheritance and Regulation
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
Homework DUE Tomorrow 143 5 Key Ideas AND Concept Check 1-3
DUE Now 142DUE Thursday Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
UNIT 78 TEST March 19th
Inheritance and Regulation
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoods
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with RrYy
1 Chance of baby with Rr 052 Chance of baby with Yy 053 Chance of baby with RrYy 025
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with both dominant phenotypes
1 Chance of baby with at least one R 0752 Chance of baby with at least one Y 0753 Chance of baby with RrYy 05625 (916)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with both dominant phenotypes
1 Chance of baby with at least one R 10
2 Chance of baby with at least one Y 10
3 Chance of baby with both dominant phenotypes 10
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
Homework DUE Tomorrow Linked vs Unlinked Genes AND Monohybrid Crosses to tunritincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with
vestigial wings and cinnabar eyes Predict the phenotypic ratio of the F2 individuals
Homework DUE Tomorrow 153 5 Key Ideas and Concept Check 1-3DUE Thursday Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with vestigial wings and cinnabar eyes Predict the
phenotypic ratio of the F2 individuals
3 The results of the cross from 2 show the following outcome Individuals of each phenotype are shown in the table Which of the following is the most likely explanation of the results a The two genes are located on two different chromosomes b The two genes are sex-linked c The two genes are located on mitochondrial DNA d The two genes are linked on an autosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
1 Build your diploid cell (an homologous pair for each chromosome)a Draw a big cell with a nucleus insideb DRAW homologous pairs of chromosomes
bull 1 big blue 1 big redbull 1 small blue 1 small red
ndash Add genes to your chromosomebull Write an H and an R on big blue and an h and an r on big redbull Write a T on small blue and a t on small red
2 Clone each chromosome (DNA Replication) (making sister chromatids)3 Nucleus breaks down (erase it)4 Homologous pairs form a tetrad crossing over may occur (note do not model
crossing over for now)5 Finish meiosis (see notes for help)6 Nucleus grows around chromosomes 4 cells made (gametes which have half
the number of chromosomes (haploids)7 Repeat Steps 1-6 this time at Step 4 include ONE crossover event
Recombination Modeling
When yoursquore confident on the process show Mr Jones
bull When yoursquore confident on the process show Mr Jones
bull In your notebookFigure 1510 Recombination p295At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid crossing over recombinant chromosome independent assortment Meiosis I Meiosis II
Recombination Modeling
Analysis
1 How does recombination increase the variety of gametes formed
2 Which types of gametes were more likely Gametes with recombinant chromosomes or ones without
3 Recombination is a random process How might it benefithurt the survival of an individualspecies
Recombination Modeling
Warm-UP
1 How could you calculate recombination frequency2 What would the recombination frequency tell you about the relative position of
genes on a chromosome3 Genes A B and C are on the same chromosome Testcrosses show that the
recombination frequency between A and B is 28 and between A and C is 12 Can you determine the linear order of these genes
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP What can we learn about inheritance from looking at a pedigree (use example of the Royal Family of Europe from the early 1900s)
Warm-UP In the following human pedigree squares represent males circles represent females and shaded symbols indicate individuals affected with a disorder One of the affected males from the third generation has a child with a female who is a carrier For the pedigree shown which of the following best expresses the probability that the couplersquos first son will be affected with the disorder
(A) 25 (B) 50 (C) 75 (D) 100
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Is a widowrsquos peak a dominant or recessive trait
Is a widowrsquos peak a dominant or recessive trait
Fig 14-UN5
George
Sandra Tom Sam
Arlene
Wilma Ann Michael
Carla
Daniel Alan Tina
Christopher
A heterozygous tall and a homozygous purple flowered plant is crossed with a short and white flowered plant Predict the offspring Assume independent assortment
1
P=purplep=whiteT=tallt=short
For a plant with the genotype WwXxYyZz what is the probability that the plant will produce a gamete with a haploid genotype of Wxyz Give your answer as a fraction or as a value between 0 and 1 to four decimal places
2
A completely-plated stickleback from a marine population was mated to a low-plated stickleback from a freshwater population The resulting F1 hybrids all displayed a completely plated phenotype When the F1 hybrids were allowed to interbreed the resulting F2 generation included completely plated offspring and low-plated offspring in an approximate 31 ratio Which of the following conclusions is best supported by the results of the breeding experiments
a Phenotypic variation in the F2 generation suggests that armor morphology is controlled by many alleles of a single gene
b The completely-plated phenotype is controlled by a dominant allele of a single gene
c Armor loss is an acquired characteristic that is affected by one or more environmental factors
d Patterns of armor plating in stickleback populations are regulated by sex-specific signals
3
If a man with type AB blood marries a woman with type O what blood types would you expect in their children What fraction would you expect of each type
4
IA= Type AIB= Type Bi= Type O
If a King marries a Queen that is a carrier of hemophilia (sex-linked recessive disease that is historically fatal before adulthood) what is the chance of the Kingdom having an heir to the kingrsquos throne assuming only one child is born
5
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
7 Gregor Mendelrsquos pioneering genetic experiments with pea plants occurred before the discovery of the structure and function of chromosomes Which of the following observations about inheritance in pea plants could be explained only after the discovery that genes may be linked on a chromosome
a Pea color and pea shape display independent inheritance patterns b Offspring of a given cross show all possible combinations of traits in
equal proportions c Most offspring of a given cross have a combination of traits that is
identical to that of either one parent or the other d Recessive phenotypes can skip a generation showing up only in the
parental and F 2 generations
8
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Based on the data in Table I which of the following best explains why there are no individuals with constricted pods in the F 1 generation a Inflated pod shape is dominant to constricted pod shape b The inflated-pod offspring in the F sub one generation are
homozygous c Constricted pod shape typically arises from a new mutation in the F 1
generation d The constricted-pod offspring are carriers for the inflated pod shape
allele
9
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table I the ratio of phenotypes in the offspring from the testcross with F 1 plants that had purple flowers and inflated pods suggests that the genes for flower color and pod shape are located a close together on the same autosome b on the X chromosome c on different chromosomes d on a mitochondrial chromosome
10
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Which of the following provides the best justification for an assumption that might have been used in the computer simulation (Table II) a The broad allele is recessive to the narrow allele because broad
leaves appear in every generation b The purple allele is dominant to the white allele because all the
offspring from the cross of purple-flowered and white-flowered plants had purple flowers
c The narrow allele is codominant with the purple allele because the purple-flower trait and the narrow-leaf trait segregate together
d The white allele is dominant to both the broad and narrow alleles because plants with either type of leaf shape can have white flowers
11
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table II the F 1 offspring of the cross between broad-leaved white-flowered plants with narrow-leaved purple-flowered plants have a phenotype that differs from that of either parent However many testcross offspring have the same phenotype as one of the two plants in the parental cross but relatively few testcross offspring have the same phenotype as the F 1 offspring Which of the following best explains the observation a Recombination between the leaf-shape and flower-color genes resulted in
chromosomes carrying a dominant allele of both genes b Recombination between the broad and narrow alleles of the leaf-shape gene resulted in
chromosomes carrying three different alleles at the same genetic locus c Independent assortment of homologous chromosomes resulted in the combinations of
alleles present in the parental generation d The computer model cannot capture the possible assortments of gametes when
multiple genes are considered
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
Homework DUE Tomorrow 143 5 Key Ideas AND Concept Check 1-3
DUE Now 142DUE Thursday Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
UNIT 78 TEST March 19th
Inheritance and Regulation
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoods
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with RrYy
1 Chance of baby with Rr 052 Chance of baby with Yy 053 Chance of baby with RrYy 025
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with both dominant phenotypes
1 Chance of baby with at least one R 0752 Chance of baby with at least one Y 0753 Chance of baby with RrYy 05625 (916)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with both dominant phenotypes
1 Chance of baby with at least one R 10
2 Chance of baby with at least one Y 10
3 Chance of baby with both dominant phenotypes 10
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
Homework DUE Tomorrow Linked vs Unlinked Genes AND Monohybrid Crosses to tunritincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with
vestigial wings and cinnabar eyes Predict the phenotypic ratio of the F2 individuals
Homework DUE Tomorrow 153 5 Key Ideas and Concept Check 1-3DUE Thursday Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with vestigial wings and cinnabar eyes Predict the
phenotypic ratio of the F2 individuals
3 The results of the cross from 2 show the following outcome Individuals of each phenotype are shown in the table Which of the following is the most likely explanation of the results a The two genes are located on two different chromosomes b The two genes are sex-linked c The two genes are located on mitochondrial DNA d The two genes are linked on an autosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
1 Build your diploid cell (an homologous pair for each chromosome)a Draw a big cell with a nucleus insideb DRAW homologous pairs of chromosomes
bull 1 big blue 1 big redbull 1 small blue 1 small red
ndash Add genes to your chromosomebull Write an H and an R on big blue and an h and an r on big redbull Write a T on small blue and a t on small red
2 Clone each chromosome (DNA Replication) (making sister chromatids)3 Nucleus breaks down (erase it)4 Homologous pairs form a tetrad crossing over may occur (note do not model
crossing over for now)5 Finish meiosis (see notes for help)6 Nucleus grows around chromosomes 4 cells made (gametes which have half
the number of chromosomes (haploids)7 Repeat Steps 1-6 this time at Step 4 include ONE crossover event
Recombination Modeling
When yoursquore confident on the process show Mr Jones
bull When yoursquore confident on the process show Mr Jones
bull In your notebookFigure 1510 Recombination p295At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid crossing over recombinant chromosome independent assortment Meiosis I Meiosis II
Recombination Modeling
Analysis
1 How does recombination increase the variety of gametes formed
2 Which types of gametes were more likely Gametes with recombinant chromosomes or ones without
3 Recombination is a random process How might it benefithurt the survival of an individualspecies
Recombination Modeling
Warm-UP
1 How could you calculate recombination frequency2 What would the recombination frequency tell you about the relative position of
genes on a chromosome3 Genes A B and C are on the same chromosome Testcrosses show that the
recombination frequency between A and B is 28 and between A and C is 12 Can you determine the linear order of these genes
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP What can we learn about inheritance from looking at a pedigree (use example of the Royal Family of Europe from the early 1900s)
Warm-UP In the following human pedigree squares represent males circles represent females and shaded symbols indicate individuals affected with a disorder One of the affected males from the third generation has a child with a female who is a carrier For the pedigree shown which of the following best expresses the probability that the couplersquos first son will be affected with the disorder
(A) 25 (B) 50 (C) 75 (D) 100
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Is a widowrsquos peak a dominant or recessive trait
Is a widowrsquos peak a dominant or recessive trait
Fig 14-UN5
George
Sandra Tom Sam
Arlene
Wilma Ann Michael
Carla
Daniel Alan Tina
Christopher
A heterozygous tall and a homozygous purple flowered plant is crossed with a short and white flowered plant Predict the offspring Assume independent assortment
1
P=purplep=whiteT=tallt=short
For a plant with the genotype WwXxYyZz what is the probability that the plant will produce a gamete with a haploid genotype of Wxyz Give your answer as a fraction or as a value between 0 and 1 to four decimal places
2
A completely-plated stickleback from a marine population was mated to a low-plated stickleback from a freshwater population The resulting F1 hybrids all displayed a completely plated phenotype When the F1 hybrids were allowed to interbreed the resulting F2 generation included completely plated offspring and low-plated offspring in an approximate 31 ratio Which of the following conclusions is best supported by the results of the breeding experiments
a Phenotypic variation in the F2 generation suggests that armor morphology is controlled by many alleles of a single gene
b The completely-plated phenotype is controlled by a dominant allele of a single gene
c Armor loss is an acquired characteristic that is affected by one or more environmental factors
d Patterns of armor plating in stickleback populations are regulated by sex-specific signals
3
If a man with type AB blood marries a woman with type O what blood types would you expect in their children What fraction would you expect of each type
4
IA= Type AIB= Type Bi= Type O
If a King marries a Queen that is a carrier of hemophilia (sex-linked recessive disease that is historically fatal before adulthood) what is the chance of the Kingdom having an heir to the kingrsquos throne assuming only one child is born
5
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
7 Gregor Mendelrsquos pioneering genetic experiments with pea plants occurred before the discovery of the structure and function of chromosomes Which of the following observations about inheritance in pea plants could be explained only after the discovery that genes may be linked on a chromosome
a Pea color and pea shape display independent inheritance patterns b Offspring of a given cross show all possible combinations of traits in
equal proportions c Most offspring of a given cross have a combination of traits that is
identical to that of either one parent or the other d Recessive phenotypes can skip a generation showing up only in the
parental and F 2 generations
8
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Based on the data in Table I which of the following best explains why there are no individuals with constricted pods in the F 1 generation a Inflated pod shape is dominant to constricted pod shape b The inflated-pod offspring in the F sub one generation are
homozygous c Constricted pod shape typically arises from a new mutation in the F 1
generation d The constricted-pod offspring are carriers for the inflated pod shape
allele
9
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table I the ratio of phenotypes in the offspring from the testcross with F 1 plants that had purple flowers and inflated pods suggests that the genes for flower color and pod shape are located a close together on the same autosome b on the X chromosome c on different chromosomes d on a mitochondrial chromosome
10
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Which of the following provides the best justification for an assumption that might have been used in the computer simulation (Table II) a The broad allele is recessive to the narrow allele because broad
leaves appear in every generation b The purple allele is dominant to the white allele because all the
offspring from the cross of purple-flowered and white-flowered plants had purple flowers
c The narrow allele is codominant with the purple allele because the purple-flower trait and the narrow-leaf trait segregate together
d The white allele is dominant to both the broad and narrow alleles because plants with either type of leaf shape can have white flowers
11
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table II the F 1 offspring of the cross between broad-leaved white-flowered plants with narrow-leaved purple-flowered plants have a phenotype that differs from that of either parent However many testcross offspring have the same phenotype as one of the two plants in the parental cross but relatively few testcross offspring have the same phenotype as the F 1 offspring Which of the following best explains the observation a Recombination between the leaf-shape and flower-color genes resulted in
chromosomes carrying a dominant allele of both genes b Recombination between the broad and narrow alleles of the leaf-shape gene resulted in
chromosomes carrying three different alleles at the same genetic locus c Independent assortment of homologous chromosomes resulted in the combinations of
alleles present in the parental generation d The computer model cannot capture the possible assortments of gametes when
multiple genes are considered
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
Homework DUE Tomorrow 143 5 Key Ideas AND Concept Check 1-3
DUE Now 142DUE Thursday Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
UNIT 78 TEST March 19th
Inheritance and Regulation
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoods
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with RrYy
1 Chance of baby with Rr 052 Chance of baby with Yy 053 Chance of baby with RrYy 025
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with both dominant phenotypes
1 Chance of baby with at least one R 0752 Chance of baby with at least one Y 0753 Chance of baby with RrYy 05625 (916)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with both dominant phenotypes
1 Chance of baby with at least one R 10
2 Chance of baby with at least one Y 10
3 Chance of baby with both dominant phenotypes 10
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
Homework DUE Tomorrow Linked vs Unlinked Genes AND Monohybrid Crosses to tunritincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with
vestigial wings and cinnabar eyes Predict the phenotypic ratio of the F2 individuals
Homework DUE Tomorrow 153 5 Key Ideas and Concept Check 1-3DUE Thursday Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with vestigial wings and cinnabar eyes Predict the
phenotypic ratio of the F2 individuals
3 The results of the cross from 2 show the following outcome Individuals of each phenotype are shown in the table Which of the following is the most likely explanation of the results a The two genes are located on two different chromosomes b The two genes are sex-linked c The two genes are located on mitochondrial DNA d The two genes are linked on an autosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
1 Build your diploid cell (an homologous pair for each chromosome)a Draw a big cell with a nucleus insideb DRAW homologous pairs of chromosomes
bull 1 big blue 1 big redbull 1 small blue 1 small red
ndash Add genes to your chromosomebull Write an H and an R on big blue and an h and an r on big redbull Write a T on small blue and a t on small red
2 Clone each chromosome (DNA Replication) (making sister chromatids)3 Nucleus breaks down (erase it)4 Homologous pairs form a tetrad crossing over may occur (note do not model
crossing over for now)5 Finish meiosis (see notes for help)6 Nucleus grows around chromosomes 4 cells made (gametes which have half
the number of chromosomes (haploids)7 Repeat Steps 1-6 this time at Step 4 include ONE crossover event
Recombination Modeling
When yoursquore confident on the process show Mr Jones
bull When yoursquore confident on the process show Mr Jones
bull In your notebookFigure 1510 Recombination p295At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid crossing over recombinant chromosome independent assortment Meiosis I Meiosis II
Recombination Modeling
Analysis
1 How does recombination increase the variety of gametes formed
2 Which types of gametes were more likely Gametes with recombinant chromosomes or ones without
3 Recombination is a random process How might it benefithurt the survival of an individualspecies
Recombination Modeling
Warm-UP
1 How could you calculate recombination frequency2 What would the recombination frequency tell you about the relative position of
genes on a chromosome3 Genes A B and C are on the same chromosome Testcrosses show that the
recombination frequency between A and B is 28 and between A and C is 12 Can you determine the linear order of these genes
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP What can we learn about inheritance from looking at a pedigree (use example of the Royal Family of Europe from the early 1900s)
Warm-UP In the following human pedigree squares represent males circles represent females and shaded symbols indicate individuals affected with a disorder One of the affected males from the third generation has a child with a female who is a carrier For the pedigree shown which of the following best expresses the probability that the couplersquos first son will be affected with the disorder
(A) 25 (B) 50 (C) 75 (D) 100
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Is a widowrsquos peak a dominant or recessive trait
Is a widowrsquos peak a dominant or recessive trait
Fig 14-UN5
George
Sandra Tom Sam
Arlene
Wilma Ann Michael
Carla
Daniel Alan Tina
Christopher
A heterozygous tall and a homozygous purple flowered plant is crossed with a short and white flowered plant Predict the offspring Assume independent assortment
1
P=purplep=whiteT=tallt=short
For a plant with the genotype WwXxYyZz what is the probability that the plant will produce a gamete with a haploid genotype of Wxyz Give your answer as a fraction or as a value between 0 and 1 to four decimal places
2
A completely-plated stickleback from a marine population was mated to a low-plated stickleback from a freshwater population The resulting F1 hybrids all displayed a completely plated phenotype When the F1 hybrids were allowed to interbreed the resulting F2 generation included completely plated offspring and low-plated offspring in an approximate 31 ratio Which of the following conclusions is best supported by the results of the breeding experiments
a Phenotypic variation in the F2 generation suggests that armor morphology is controlled by many alleles of a single gene
b The completely-plated phenotype is controlled by a dominant allele of a single gene
c Armor loss is an acquired characteristic that is affected by one or more environmental factors
d Patterns of armor plating in stickleback populations are regulated by sex-specific signals
3
If a man with type AB blood marries a woman with type O what blood types would you expect in their children What fraction would you expect of each type
4
IA= Type AIB= Type Bi= Type O
If a King marries a Queen that is a carrier of hemophilia (sex-linked recessive disease that is historically fatal before adulthood) what is the chance of the Kingdom having an heir to the kingrsquos throne assuming only one child is born
5
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
7 Gregor Mendelrsquos pioneering genetic experiments with pea plants occurred before the discovery of the structure and function of chromosomes Which of the following observations about inheritance in pea plants could be explained only after the discovery that genes may be linked on a chromosome
a Pea color and pea shape display independent inheritance patterns b Offspring of a given cross show all possible combinations of traits in
equal proportions c Most offspring of a given cross have a combination of traits that is
identical to that of either one parent or the other d Recessive phenotypes can skip a generation showing up only in the
parental and F 2 generations
8
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Based on the data in Table I which of the following best explains why there are no individuals with constricted pods in the F 1 generation a Inflated pod shape is dominant to constricted pod shape b The inflated-pod offspring in the F sub one generation are
homozygous c Constricted pod shape typically arises from a new mutation in the F 1
generation d The constricted-pod offspring are carriers for the inflated pod shape
allele
9
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table I the ratio of phenotypes in the offspring from the testcross with F 1 plants that had purple flowers and inflated pods suggests that the genes for flower color and pod shape are located a close together on the same autosome b on the X chromosome c on different chromosomes d on a mitochondrial chromosome
10
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Which of the following provides the best justification for an assumption that might have been used in the computer simulation (Table II) a The broad allele is recessive to the narrow allele because broad
leaves appear in every generation b The purple allele is dominant to the white allele because all the
offspring from the cross of purple-flowered and white-flowered plants had purple flowers
c The narrow allele is codominant with the purple allele because the purple-flower trait and the narrow-leaf trait segregate together
d The white allele is dominant to both the broad and narrow alleles because plants with either type of leaf shape can have white flowers
11
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table II the F 1 offspring of the cross between broad-leaved white-flowered plants with narrow-leaved purple-flowered plants have a phenotype that differs from that of either parent However many testcross offspring have the same phenotype as one of the two plants in the parental cross but relatively few testcross offspring have the same phenotype as the F 1 offspring Which of the following best explains the observation a Recombination between the leaf-shape and flower-color genes resulted in
chromosomes carrying a dominant allele of both genes b Recombination between the broad and narrow alleles of the leaf-shape gene resulted in
chromosomes carrying three different alleles at the same genetic locus c Independent assortment of homologous chromosomes resulted in the combinations of
alleles present in the parental generation d The computer model cannot capture the possible assortments of gametes when
multiple genes are considered
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Mendel 1857bull P Crossed purebredsbull F1 all one phenotypebull F2 31 ratio
Conclusion1 ldquoAllelesrdquo segregate (in meiosis)
independently2 Some alleles (dominant) hide the
expression of others (recessive)3 Recessive alleles can appear again
IF the dominant are no longer present
Termsbull allele variety of a genebull homozygous both alleles are the
same (purebred)bull heterozygous alleles are different
(carriers) (hybrids)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
Homework DUE Tomorrow 143 5 Key Ideas AND Concept Check 1-3
DUE Now 142DUE Thursday Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
UNIT 78 TEST March 19th
Inheritance and Regulation
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoods
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with RrYy
1 Chance of baby with Rr 052 Chance of baby with Yy 053 Chance of baby with RrYy 025
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with both dominant phenotypes
1 Chance of baby with at least one R 0752 Chance of baby with at least one Y 0753 Chance of baby with RrYy 05625 (916)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with both dominant phenotypes
1 Chance of baby with at least one R 10
2 Chance of baby with at least one Y 10
3 Chance of baby with both dominant phenotypes 10
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
Homework DUE Tomorrow Linked vs Unlinked Genes AND Monohybrid Crosses to tunritincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with
vestigial wings and cinnabar eyes Predict the phenotypic ratio of the F2 individuals
Homework DUE Tomorrow 153 5 Key Ideas and Concept Check 1-3DUE Thursday Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with vestigial wings and cinnabar eyes Predict the
phenotypic ratio of the F2 individuals
3 The results of the cross from 2 show the following outcome Individuals of each phenotype are shown in the table Which of the following is the most likely explanation of the results a The two genes are located on two different chromosomes b The two genes are sex-linked c The two genes are located on mitochondrial DNA d The two genes are linked on an autosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
1 Build your diploid cell (an homologous pair for each chromosome)a Draw a big cell with a nucleus insideb DRAW homologous pairs of chromosomes
bull 1 big blue 1 big redbull 1 small blue 1 small red
ndash Add genes to your chromosomebull Write an H and an R on big blue and an h and an r on big redbull Write a T on small blue and a t on small red
2 Clone each chromosome (DNA Replication) (making sister chromatids)3 Nucleus breaks down (erase it)4 Homologous pairs form a tetrad crossing over may occur (note do not model
crossing over for now)5 Finish meiosis (see notes for help)6 Nucleus grows around chromosomes 4 cells made (gametes which have half
the number of chromosomes (haploids)7 Repeat Steps 1-6 this time at Step 4 include ONE crossover event
Recombination Modeling
When yoursquore confident on the process show Mr Jones
bull When yoursquore confident on the process show Mr Jones
bull In your notebookFigure 1510 Recombination p295At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid crossing over recombinant chromosome independent assortment Meiosis I Meiosis II
Recombination Modeling
Analysis
1 How does recombination increase the variety of gametes formed
2 Which types of gametes were more likely Gametes with recombinant chromosomes or ones without
3 Recombination is a random process How might it benefithurt the survival of an individualspecies
Recombination Modeling
Warm-UP
1 How could you calculate recombination frequency2 What would the recombination frequency tell you about the relative position of
genes on a chromosome3 Genes A B and C are on the same chromosome Testcrosses show that the
recombination frequency between A and B is 28 and between A and C is 12 Can you determine the linear order of these genes
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP What can we learn about inheritance from looking at a pedigree (use example of the Royal Family of Europe from the early 1900s)
Warm-UP In the following human pedigree squares represent males circles represent females and shaded symbols indicate individuals affected with a disorder One of the affected males from the third generation has a child with a female who is a carrier For the pedigree shown which of the following best expresses the probability that the couplersquos first son will be affected with the disorder
(A) 25 (B) 50 (C) 75 (D) 100
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Is a widowrsquos peak a dominant or recessive trait
Is a widowrsquos peak a dominant or recessive trait
Fig 14-UN5
George
Sandra Tom Sam
Arlene
Wilma Ann Michael
Carla
Daniel Alan Tina
Christopher
A heterozygous tall and a homozygous purple flowered plant is crossed with a short and white flowered plant Predict the offspring Assume independent assortment
1
P=purplep=whiteT=tallt=short
For a plant with the genotype WwXxYyZz what is the probability that the plant will produce a gamete with a haploid genotype of Wxyz Give your answer as a fraction or as a value between 0 and 1 to four decimal places
2
A completely-plated stickleback from a marine population was mated to a low-plated stickleback from a freshwater population The resulting F1 hybrids all displayed a completely plated phenotype When the F1 hybrids were allowed to interbreed the resulting F2 generation included completely plated offspring and low-plated offspring in an approximate 31 ratio Which of the following conclusions is best supported by the results of the breeding experiments
a Phenotypic variation in the F2 generation suggests that armor morphology is controlled by many alleles of a single gene
b The completely-plated phenotype is controlled by a dominant allele of a single gene
c Armor loss is an acquired characteristic that is affected by one or more environmental factors
d Patterns of armor plating in stickleback populations are regulated by sex-specific signals
3
If a man with type AB blood marries a woman with type O what blood types would you expect in their children What fraction would you expect of each type
4
IA= Type AIB= Type Bi= Type O
If a King marries a Queen that is a carrier of hemophilia (sex-linked recessive disease that is historically fatal before adulthood) what is the chance of the Kingdom having an heir to the kingrsquos throne assuming only one child is born
5
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
7 Gregor Mendelrsquos pioneering genetic experiments with pea plants occurred before the discovery of the structure and function of chromosomes Which of the following observations about inheritance in pea plants could be explained only after the discovery that genes may be linked on a chromosome
a Pea color and pea shape display independent inheritance patterns b Offspring of a given cross show all possible combinations of traits in
equal proportions c Most offspring of a given cross have a combination of traits that is
identical to that of either one parent or the other d Recessive phenotypes can skip a generation showing up only in the
parental and F 2 generations
8
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Based on the data in Table I which of the following best explains why there are no individuals with constricted pods in the F 1 generation a Inflated pod shape is dominant to constricted pod shape b The inflated-pod offspring in the F sub one generation are
homozygous c Constricted pod shape typically arises from a new mutation in the F 1
generation d The constricted-pod offspring are carriers for the inflated pod shape
allele
9
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table I the ratio of phenotypes in the offspring from the testcross with F 1 plants that had purple flowers and inflated pods suggests that the genes for flower color and pod shape are located a close together on the same autosome b on the X chromosome c on different chromosomes d on a mitochondrial chromosome
10
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Which of the following provides the best justification for an assumption that might have been used in the computer simulation (Table II) a The broad allele is recessive to the narrow allele because broad
leaves appear in every generation b The purple allele is dominant to the white allele because all the
offspring from the cross of purple-flowered and white-flowered plants had purple flowers
c The narrow allele is codominant with the purple allele because the purple-flower trait and the narrow-leaf trait segregate together
d The white allele is dominant to both the broad and narrow alleles because plants with either type of leaf shape can have white flowers
11
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table II the F 1 offspring of the cross between broad-leaved white-flowered plants with narrow-leaved purple-flowered plants have a phenotype that differs from that of either parent However many testcross offspring have the same phenotype as one of the two plants in the parental cross but relatively few testcross offspring have the same phenotype as the F 1 offspring Which of the following best explains the observation a Recombination between the leaf-shape and flower-color genes resulted in
chromosomes carrying a dominant allele of both genes b Recombination between the broad and narrow alleles of the leaf-shape gene resulted in
chromosomes carrying three different alleles at the same genetic locus c Independent assortment of homologous chromosomes resulted in the combinations of
alleles present in the parental generation d The computer model cannot capture the possible assortments of gametes when
multiple genes are considered
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
Homework DUE Tomorrow 143 5 Key Ideas AND Concept Check 1-3
DUE Now 142DUE Thursday Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
UNIT 78 TEST March 19th
Inheritance and Regulation
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoods
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with RrYy
1 Chance of baby with Rr 052 Chance of baby with Yy 053 Chance of baby with RrYy 025
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with both dominant phenotypes
1 Chance of baby with at least one R 0752 Chance of baby with at least one Y 0753 Chance of baby with RrYy 05625 (916)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with both dominant phenotypes
1 Chance of baby with at least one R 10
2 Chance of baby with at least one Y 10
3 Chance of baby with both dominant phenotypes 10
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
Homework DUE Tomorrow Linked vs Unlinked Genes AND Monohybrid Crosses to tunritincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with
vestigial wings and cinnabar eyes Predict the phenotypic ratio of the F2 individuals
Homework DUE Tomorrow 153 5 Key Ideas and Concept Check 1-3DUE Thursday Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with vestigial wings and cinnabar eyes Predict the
phenotypic ratio of the F2 individuals
3 The results of the cross from 2 show the following outcome Individuals of each phenotype are shown in the table Which of the following is the most likely explanation of the results a The two genes are located on two different chromosomes b The two genes are sex-linked c The two genes are located on mitochondrial DNA d The two genes are linked on an autosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
1 Build your diploid cell (an homologous pair for each chromosome)a Draw a big cell with a nucleus insideb DRAW homologous pairs of chromosomes
bull 1 big blue 1 big redbull 1 small blue 1 small red
ndash Add genes to your chromosomebull Write an H and an R on big blue and an h and an r on big redbull Write a T on small blue and a t on small red
2 Clone each chromosome (DNA Replication) (making sister chromatids)3 Nucleus breaks down (erase it)4 Homologous pairs form a tetrad crossing over may occur (note do not model
crossing over for now)5 Finish meiosis (see notes for help)6 Nucleus grows around chromosomes 4 cells made (gametes which have half
the number of chromosomes (haploids)7 Repeat Steps 1-6 this time at Step 4 include ONE crossover event
Recombination Modeling
When yoursquore confident on the process show Mr Jones
bull When yoursquore confident on the process show Mr Jones
bull In your notebookFigure 1510 Recombination p295At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid crossing over recombinant chromosome independent assortment Meiosis I Meiosis II
Recombination Modeling
Analysis
1 How does recombination increase the variety of gametes formed
2 Which types of gametes were more likely Gametes with recombinant chromosomes or ones without
3 Recombination is a random process How might it benefithurt the survival of an individualspecies
Recombination Modeling
Warm-UP
1 How could you calculate recombination frequency2 What would the recombination frequency tell you about the relative position of
genes on a chromosome3 Genes A B and C are on the same chromosome Testcrosses show that the
recombination frequency between A and B is 28 and between A and C is 12 Can you determine the linear order of these genes
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP What can we learn about inheritance from looking at a pedigree (use example of the Royal Family of Europe from the early 1900s)
Warm-UP In the following human pedigree squares represent males circles represent females and shaded symbols indicate individuals affected with a disorder One of the affected males from the third generation has a child with a female who is a carrier For the pedigree shown which of the following best expresses the probability that the couplersquos first son will be affected with the disorder
(A) 25 (B) 50 (C) 75 (D) 100
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Is a widowrsquos peak a dominant or recessive trait
Is a widowrsquos peak a dominant or recessive trait
Fig 14-UN5
George
Sandra Tom Sam
Arlene
Wilma Ann Michael
Carla
Daniel Alan Tina
Christopher
A heterozygous tall and a homozygous purple flowered plant is crossed with a short and white flowered plant Predict the offspring Assume independent assortment
1
P=purplep=whiteT=tallt=short
For a plant with the genotype WwXxYyZz what is the probability that the plant will produce a gamete with a haploid genotype of Wxyz Give your answer as a fraction or as a value between 0 and 1 to four decimal places
2
A completely-plated stickleback from a marine population was mated to a low-plated stickleback from a freshwater population The resulting F1 hybrids all displayed a completely plated phenotype When the F1 hybrids were allowed to interbreed the resulting F2 generation included completely plated offspring and low-plated offspring in an approximate 31 ratio Which of the following conclusions is best supported by the results of the breeding experiments
a Phenotypic variation in the F2 generation suggests that armor morphology is controlled by many alleles of a single gene
b The completely-plated phenotype is controlled by a dominant allele of a single gene
c Armor loss is an acquired characteristic that is affected by one or more environmental factors
d Patterns of armor plating in stickleback populations are regulated by sex-specific signals
3
If a man with type AB blood marries a woman with type O what blood types would you expect in their children What fraction would you expect of each type
4
IA= Type AIB= Type Bi= Type O
If a King marries a Queen that is a carrier of hemophilia (sex-linked recessive disease that is historically fatal before adulthood) what is the chance of the Kingdom having an heir to the kingrsquos throne assuming only one child is born
5
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
7 Gregor Mendelrsquos pioneering genetic experiments with pea plants occurred before the discovery of the structure and function of chromosomes Which of the following observations about inheritance in pea plants could be explained only after the discovery that genes may be linked on a chromosome
a Pea color and pea shape display independent inheritance patterns b Offspring of a given cross show all possible combinations of traits in
equal proportions c Most offspring of a given cross have a combination of traits that is
identical to that of either one parent or the other d Recessive phenotypes can skip a generation showing up only in the
parental and F 2 generations
8
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Based on the data in Table I which of the following best explains why there are no individuals with constricted pods in the F 1 generation a Inflated pod shape is dominant to constricted pod shape b The inflated-pod offspring in the F sub one generation are
homozygous c Constricted pod shape typically arises from a new mutation in the F 1
generation d The constricted-pod offspring are carriers for the inflated pod shape
allele
9
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table I the ratio of phenotypes in the offspring from the testcross with F 1 plants that had purple flowers and inflated pods suggests that the genes for flower color and pod shape are located a close together on the same autosome b on the X chromosome c on different chromosomes d on a mitochondrial chromosome
10
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Which of the following provides the best justification for an assumption that might have been used in the computer simulation (Table II) a The broad allele is recessive to the narrow allele because broad
leaves appear in every generation b The purple allele is dominant to the white allele because all the
offspring from the cross of purple-flowered and white-flowered plants had purple flowers
c The narrow allele is codominant with the purple allele because the purple-flower trait and the narrow-leaf trait segregate together
d The white allele is dominant to both the broad and narrow alleles because plants with either type of leaf shape can have white flowers
11
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table II the F 1 offspring of the cross between broad-leaved white-flowered plants with narrow-leaved purple-flowered plants have a phenotype that differs from that of either parent However many testcross offspring have the same phenotype as one of the two plants in the parental cross but relatively few testcross offspring have the same phenotype as the F 1 offspring Which of the following best explains the observation a Recombination between the leaf-shape and flower-color genes resulted in
chromosomes carrying a dominant allele of both genes b Recombination between the broad and narrow alleles of the leaf-shape gene resulted in
chromosomes carrying three different alleles at the same genetic locus c Independent assortment of homologous chromosomes resulted in the combinations of
alleles present in the parental generation d The computer model cannot capture the possible assortments of gametes when
multiple genes are considered
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
Homework DUE Tomorrow 143 5 Key Ideas AND Concept Check 1-3
DUE Now 142DUE Thursday Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
UNIT 78 TEST March 19th
Inheritance and Regulation
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoods
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with RrYy
1 Chance of baby with Rr 052 Chance of baby with Yy 053 Chance of baby with RrYy 025
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with both dominant phenotypes
1 Chance of baby with at least one R 0752 Chance of baby with at least one Y 0753 Chance of baby with RrYy 05625 (916)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with both dominant phenotypes
1 Chance of baby with at least one R 10
2 Chance of baby with at least one Y 10
3 Chance of baby with both dominant phenotypes 10
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
Homework DUE Tomorrow Linked vs Unlinked Genes AND Monohybrid Crosses to tunritincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with
vestigial wings and cinnabar eyes Predict the phenotypic ratio of the F2 individuals
Homework DUE Tomorrow 153 5 Key Ideas and Concept Check 1-3DUE Thursday Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with vestigial wings and cinnabar eyes Predict the
phenotypic ratio of the F2 individuals
3 The results of the cross from 2 show the following outcome Individuals of each phenotype are shown in the table Which of the following is the most likely explanation of the results a The two genes are located on two different chromosomes b The two genes are sex-linked c The two genes are located on mitochondrial DNA d The two genes are linked on an autosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
1 Build your diploid cell (an homologous pair for each chromosome)a Draw a big cell with a nucleus insideb DRAW homologous pairs of chromosomes
bull 1 big blue 1 big redbull 1 small blue 1 small red
ndash Add genes to your chromosomebull Write an H and an R on big blue and an h and an r on big redbull Write a T on small blue and a t on small red
2 Clone each chromosome (DNA Replication) (making sister chromatids)3 Nucleus breaks down (erase it)4 Homologous pairs form a tetrad crossing over may occur (note do not model
crossing over for now)5 Finish meiosis (see notes for help)6 Nucleus grows around chromosomes 4 cells made (gametes which have half
the number of chromosomes (haploids)7 Repeat Steps 1-6 this time at Step 4 include ONE crossover event
Recombination Modeling
When yoursquore confident on the process show Mr Jones
bull When yoursquore confident on the process show Mr Jones
bull In your notebookFigure 1510 Recombination p295At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid crossing over recombinant chromosome independent assortment Meiosis I Meiosis II
Recombination Modeling
Analysis
1 How does recombination increase the variety of gametes formed
2 Which types of gametes were more likely Gametes with recombinant chromosomes or ones without
3 Recombination is a random process How might it benefithurt the survival of an individualspecies
Recombination Modeling
Warm-UP
1 How could you calculate recombination frequency2 What would the recombination frequency tell you about the relative position of
genes on a chromosome3 Genes A B and C are on the same chromosome Testcrosses show that the
recombination frequency between A and B is 28 and between A and C is 12 Can you determine the linear order of these genes
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP What can we learn about inheritance from looking at a pedigree (use example of the Royal Family of Europe from the early 1900s)
Warm-UP In the following human pedigree squares represent males circles represent females and shaded symbols indicate individuals affected with a disorder One of the affected males from the third generation has a child with a female who is a carrier For the pedigree shown which of the following best expresses the probability that the couplersquos first son will be affected with the disorder
(A) 25 (B) 50 (C) 75 (D) 100
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Is a widowrsquos peak a dominant or recessive trait
Is a widowrsquos peak a dominant or recessive trait
Fig 14-UN5
George
Sandra Tom Sam
Arlene
Wilma Ann Michael
Carla
Daniel Alan Tina
Christopher
A heterozygous tall and a homozygous purple flowered plant is crossed with a short and white flowered plant Predict the offspring Assume independent assortment
1
P=purplep=whiteT=tallt=short
For a plant with the genotype WwXxYyZz what is the probability that the plant will produce a gamete with a haploid genotype of Wxyz Give your answer as a fraction or as a value between 0 and 1 to four decimal places
2
A completely-plated stickleback from a marine population was mated to a low-plated stickleback from a freshwater population The resulting F1 hybrids all displayed a completely plated phenotype When the F1 hybrids were allowed to interbreed the resulting F2 generation included completely plated offspring and low-plated offspring in an approximate 31 ratio Which of the following conclusions is best supported by the results of the breeding experiments
a Phenotypic variation in the F2 generation suggests that armor morphology is controlled by many alleles of a single gene
b The completely-plated phenotype is controlled by a dominant allele of a single gene
c Armor loss is an acquired characteristic that is affected by one or more environmental factors
d Patterns of armor plating in stickleback populations are regulated by sex-specific signals
3
If a man with type AB blood marries a woman with type O what blood types would you expect in their children What fraction would you expect of each type
4
IA= Type AIB= Type Bi= Type O
If a King marries a Queen that is a carrier of hemophilia (sex-linked recessive disease that is historically fatal before adulthood) what is the chance of the Kingdom having an heir to the kingrsquos throne assuming only one child is born
5
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
7 Gregor Mendelrsquos pioneering genetic experiments with pea plants occurred before the discovery of the structure and function of chromosomes Which of the following observations about inheritance in pea plants could be explained only after the discovery that genes may be linked on a chromosome
a Pea color and pea shape display independent inheritance patterns b Offspring of a given cross show all possible combinations of traits in
equal proportions c Most offspring of a given cross have a combination of traits that is
identical to that of either one parent or the other d Recessive phenotypes can skip a generation showing up only in the
parental and F 2 generations
8
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Based on the data in Table I which of the following best explains why there are no individuals with constricted pods in the F 1 generation a Inflated pod shape is dominant to constricted pod shape b The inflated-pod offspring in the F sub one generation are
homozygous c Constricted pod shape typically arises from a new mutation in the F 1
generation d The constricted-pod offspring are carriers for the inflated pod shape
allele
9
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table I the ratio of phenotypes in the offspring from the testcross with F 1 plants that had purple flowers and inflated pods suggests that the genes for flower color and pod shape are located a close together on the same autosome b on the X chromosome c on different chromosomes d on a mitochondrial chromosome
10
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Which of the following provides the best justification for an assumption that might have been used in the computer simulation (Table II) a The broad allele is recessive to the narrow allele because broad
leaves appear in every generation b The purple allele is dominant to the white allele because all the
offspring from the cross of purple-flowered and white-flowered plants had purple flowers
c The narrow allele is codominant with the purple allele because the purple-flower trait and the narrow-leaf trait segregate together
d The white allele is dominant to both the broad and narrow alleles because plants with either type of leaf shape can have white flowers
11
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table II the F 1 offspring of the cross between broad-leaved white-flowered plants with narrow-leaved purple-flowered plants have a phenotype that differs from that of either parent However many testcross offspring have the same phenotype as one of the two plants in the parental cross but relatively few testcross offspring have the same phenotype as the F 1 offspring Which of the following best explains the observation a Recombination between the leaf-shape and flower-color genes resulted in
chromosomes carrying a dominant allele of both genes b Recombination between the broad and narrow alleles of the leaf-shape gene resulted in
chromosomes carrying three different alleles at the same genetic locus c Independent assortment of homologous chromosomes resulted in the combinations of
alleles present in the parental generation d The computer model cannot capture the possible assortments of gametes when
multiple genes are considered
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
Homework DUE Tomorrow 143 5 Key Ideas AND Concept Check 1-3
DUE Now 142DUE Thursday Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
UNIT 78 TEST March 19th
Inheritance and Regulation
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoods
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with RrYy
1 Chance of baby with Rr 052 Chance of baby with Yy 053 Chance of baby with RrYy 025
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with both dominant phenotypes
1 Chance of baby with at least one R 0752 Chance of baby with at least one Y 0753 Chance of baby with RrYy 05625 (916)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with both dominant phenotypes
1 Chance of baby with at least one R 10
2 Chance of baby with at least one Y 10
3 Chance of baby with both dominant phenotypes 10
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
Homework DUE Tomorrow Linked vs Unlinked Genes AND Monohybrid Crosses to tunritincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with
vestigial wings and cinnabar eyes Predict the phenotypic ratio of the F2 individuals
Homework DUE Tomorrow 153 5 Key Ideas and Concept Check 1-3DUE Thursday Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with vestigial wings and cinnabar eyes Predict the
phenotypic ratio of the F2 individuals
3 The results of the cross from 2 show the following outcome Individuals of each phenotype are shown in the table Which of the following is the most likely explanation of the results a The two genes are located on two different chromosomes b The two genes are sex-linked c The two genes are located on mitochondrial DNA d The two genes are linked on an autosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
1 Build your diploid cell (an homologous pair for each chromosome)a Draw a big cell with a nucleus insideb DRAW homologous pairs of chromosomes
bull 1 big blue 1 big redbull 1 small blue 1 small red
ndash Add genes to your chromosomebull Write an H and an R on big blue and an h and an r on big redbull Write a T on small blue and a t on small red
2 Clone each chromosome (DNA Replication) (making sister chromatids)3 Nucleus breaks down (erase it)4 Homologous pairs form a tetrad crossing over may occur (note do not model
crossing over for now)5 Finish meiosis (see notes for help)6 Nucleus grows around chromosomes 4 cells made (gametes which have half
the number of chromosomes (haploids)7 Repeat Steps 1-6 this time at Step 4 include ONE crossover event
Recombination Modeling
When yoursquore confident on the process show Mr Jones
bull When yoursquore confident on the process show Mr Jones
bull In your notebookFigure 1510 Recombination p295At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid crossing over recombinant chromosome independent assortment Meiosis I Meiosis II
Recombination Modeling
Analysis
1 How does recombination increase the variety of gametes formed
2 Which types of gametes were more likely Gametes with recombinant chromosomes or ones without
3 Recombination is a random process How might it benefithurt the survival of an individualspecies
Recombination Modeling
Warm-UP
1 How could you calculate recombination frequency2 What would the recombination frequency tell you about the relative position of
genes on a chromosome3 Genes A B and C are on the same chromosome Testcrosses show that the
recombination frequency between A and B is 28 and between A and C is 12 Can you determine the linear order of these genes
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP What can we learn about inheritance from looking at a pedigree (use example of the Royal Family of Europe from the early 1900s)
Warm-UP In the following human pedigree squares represent males circles represent females and shaded symbols indicate individuals affected with a disorder One of the affected males from the third generation has a child with a female who is a carrier For the pedigree shown which of the following best expresses the probability that the couplersquos first son will be affected with the disorder
(A) 25 (B) 50 (C) 75 (D) 100
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Is a widowrsquos peak a dominant or recessive trait
Is a widowrsquos peak a dominant or recessive trait
Fig 14-UN5
George
Sandra Tom Sam
Arlene
Wilma Ann Michael
Carla
Daniel Alan Tina
Christopher
A heterozygous tall and a homozygous purple flowered plant is crossed with a short and white flowered plant Predict the offspring Assume independent assortment
1
P=purplep=whiteT=tallt=short
For a plant with the genotype WwXxYyZz what is the probability that the plant will produce a gamete with a haploid genotype of Wxyz Give your answer as a fraction or as a value between 0 and 1 to four decimal places
2
A completely-plated stickleback from a marine population was mated to a low-plated stickleback from a freshwater population The resulting F1 hybrids all displayed a completely plated phenotype When the F1 hybrids were allowed to interbreed the resulting F2 generation included completely plated offspring and low-plated offspring in an approximate 31 ratio Which of the following conclusions is best supported by the results of the breeding experiments
a Phenotypic variation in the F2 generation suggests that armor morphology is controlled by many alleles of a single gene
b The completely-plated phenotype is controlled by a dominant allele of a single gene
c Armor loss is an acquired characteristic that is affected by one or more environmental factors
d Patterns of armor plating in stickleback populations are regulated by sex-specific signals
3
If a man with type AB blood marries a woman with type O what blood types would you expect in their children What fraction would you expect of each type
4
IA= Type AIB= Type Bi= Type O
If a King marries a Queen that is a carrier of hemophilia (sex-linked recessive disease that is historically fatal before adulthood) what is the chance of the Kingdom having an heir to the kingrsquos throne assuming only one child is born
5
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
7 Gregor Mendelrsquos pioneering genetic experiments with pea plants occurred before the discovery of the structure and function of chromosomes Which of the following observations about inheritance in pea plants could be explained only after the discovery that genes may be linked on a chromosome
a Pea color and pea shape display independent inheritance patterns b Offspring of a given cross show all possible combinations of traits in
equal proportions c Most offspring of a given cross have a combination of traits that is
identical to that of either one parent or the other d Recessive phenotypes can skip a generation showing up only in the
parental and F 2 generations
8
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Based on the data in Table I which of the following best explains why there are no individuals with constricted pods in the F 1 generation a Inflated pod shape is dominant to constricted pod shape b The inflated-pod offspring in the F sub one generation are
homozygous c Constricted pod shape typically arises from a new mutation in the F 1
generation d The constricted-pod offspring are carriers for the inflated pod shape
allele
9
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table I the ratio of phenotypes in the offspring from the testcross with F 1 plants that had purple flowers and inflated pods suggests that the genes for flower color and pod shape are located a close together on the same autosome b on the X chromosome c on different chromosomes d on a mitochondrial chromosome
10
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Which of the following provides the best justification for an assumption that might have been used in the computer simulation (Table II) a The broad allele is recessive to the narrow allele because broad
leaves appear in every generation b The purple allele is dominant to the white allele because all the
offspring from the cross of purple-flowered and white-flowered plants had purple flowers
c The narrow allele is codominant with the purple allele because the purple-flower trait and the narrow-leaf trait segregate together
d The white allele is dominant to both the broad and narrow alleles because plants with either type of leaf shape can have white flowers
11
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table II the F 1 offspring of the cross between broad-leaved white-flowered plants with narrow-leaved purple-flowered plants have a phenotype that differs from that of either parent However many testcross offspring have the same phenotype as one of the two plants in the parental cross but relatively few testcross offspring have the same phenotype as the F 1 offspring Which of the following best explains the observation a Recombination between the leaf-shape and flower-color genes resulted in
chromosomes carrying a dominant allele of both genes b Recombination between the broad and narrow alleles of the leaf-shape gene resulted in
chromosomes carrying three different alleles at the same genetic locus c Independent assortment of homologous chromosomes resulted in the combinations of
alleles present in the parental generation d The computer model cannot capture the possible assortments of gametes when
multiple genes are considered
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
Homework DUE Tomorrow 143 5 Key Ideas AND Concept Check 1-3
DUE Now 142DUE Thursday Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
UNIT 78 TEST March 19th
Inheritance and Regulation
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoods
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with RrYy
1 Chance of baby with Rr 052 Chance of baby with Yy 053 Chance of baby with RrYy 025
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with both dominant phenotypes
1 Chance of baby with at least one R 0752 Chance of baby with at least one Y 0753 Chance of baby with RrYy 05625 (916)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with both dominant phenotypes
1 Chance of baby with at least one R 10
2 Chance of baby with at least one Y 10
3 Chance of baby with both dominant phenotypes 10
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
Homework DUE Tomorrow Linked vs Unlinked Genes AND Monohybrid Crosses to tunritincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with
vestigial wings and cinnabar eyes Predict the phenotypic ratio of the F2 individuals
Homework DUE Tomorrow 153 5 Key Ideas and Concept Check 1-3DUE Thursday Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with vestigial wings and cinnabar eyes Predict the
phenotypic ratio of the F2 individuals
3 The results of the cross from 2 show the following outcome Individuals of each phenotype are shown in the table Which of the following is the most likely explanation of the results a The two genes are located on two different chromosomes b The two genes are sex-linked c The two genes are located on mitochondrial DNA d The two genes are linked on an autosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
1 Build your diploid cell (an homologous pair for each chromosome)a Draw a big cell with a nucleus insideb DRAW homologous pairs of chromosomes
bull 1 big blue 1 big redbull 1 small blue 1 small red
ndash Add genes to your chromosomebull Write an H and an R on big blue and an h and an r on big redbull Write a T on small blue and a t on small red
2 Clone each chromosome (DNA Replication) (making sister chromatids)3 Nucleus breaks down (erase it)4 Homologous pairs form a tetrad crossing over may occur (note do not model
crossing over for now)5 Finish meiosis (see notes for help)6 Nucleus grows around chromosomes 4 cells made (gametes which have half
the number of chromosomes (haploids)7 Repeat Steps 1-6 this time at Step 4 include ONE crossover event
Recombination Modeling
When yoursquore confident on the process show Mr Jones
bull When yoursquore confident on the process show Mr Jones
bull In your notebookFigure 1510 Recombination p295At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid crossing over recombinant chromosome independent assortment Meiosis I Meiosis II
Recombination Modeling
Analysis
1 How does recombination increase the variety of gametes formed
2 Which types of gametes were more likely Gametes with recombinant chromosomes or ones without
3 Recombination is a random process How might it benefithurt the survival of an individualspecies
Recombination Modeling
Warm-UP
1 How could you calculate recombination frequency2 What would the recombination frequency tell you about the relative position of
genes on a chromosome3 Genes A B and C are on the same chromosome Testcrosses show that the
recombination frequency between A and B is 28 and between A and C is 12 Can you determine the linear order of these genes
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP What can we learn about inheritance from looking at a pedigree (use example of the Royal Family of Europe from the early 1900s)
Warm-UP In the following human pedigree squares represent males circles represent females and shaded symbols indicate individuals affected with a disorder One of the affected males from the third generation has a child with a female who is a carrier For the pedigree shown which of the following best expresses the probability that the couplersquos first son will be affected with the disorder
(A) 25 (B) 50 (C) 75 (D) 100
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Is a widowrsquos peak a dominant or recessive trait
Is a widowrsquos peak a dominant or recessive trait
Fig 14-UN5
George
Sandra Tom Sam
Arlene
Wilma Ann Michael
Carla
Daniel Alan Tina
Christopher
A heterozygous tall and a homozygous purple flowered plant is crossed with a short and white flowered plant Predict the offspring Assume independent assortment
1
P=purplep=whiteT=tallt=short
For a plant with the genotype WwXxYyZz what is the probability that the plant will produce a gamete with a haploid genotype of Wxyz Give your answer as a fraction or as a value between 0 and 1 to four decimal places
2
A completely-plated stickleback from a marine population was mated to a low-plated stickleback from a freshwater population The resulting F1 hybrids all displayed a completely plated phenotype When the F1 hybrids were allowed to interbreed the resulting F2 generation included completely plated offspring and low-plated offspring in an approximate 31 ratio Which of the following conclusions is best supported by the results of the breeding experiments
a Phenotypic variation in the F2 generation suggests that armor morphology is controlled by many alleles of a single gene
b The completely-plated phenotype is controlled by a dominant allele of a single gene
c Armor loss is an acquired characteristic that is affected by one or more environmental factors
d Patterns of armor plating in stickleback populations are regulated by sex-specific signals
3
If a man with type AB blood marries a woman with type O what blood types would you expect in their children What fraction would you expect of each type
4
IA= Type AIB= Type Bi= Type O
If a King marries a Queen that is a carrier of hemophilia (sex-linked recessive disease that is historically fatal before adulthood) what is the chance of the Kingdom having an heir to the kingrsquos throne assuming only one child is born
5
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
7 Gregor Mendelrsquos pioneering genetic experiments with pea plants occurred before the discovery of the structure and function of chromosomes Which of the following observations about inheritance in pea plants could be explained only after the discovery that genes may be linked on a chromosome
a Pea color and pea shape display independent inheritance patterns b Offspring of a given cross show all possible combinations of traits in
equal proportions c Most offspring of a given cross have a combination of traits that is
identical to that of either one parent or the other d Recessive phenotypes can skip a generation showing up only in the
parental and F 2 generations
8
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Based on the data in Table I which of the following best explains why there are no individuals with constricted pods in the F 1 generation a Inflated pod shape is dominant to constricted pod shape b The inflated-pod offspring in the F sub one generation are
homozygous c Constricted pod shape typically arises from a new mutation in the F 1
generation d The constricted-pod offspring are carriers for the inflated pod shape
allele
9
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table I the ratio of phenotypes in the offspring from the testcross with F 1 plants that had purple flowers and inflated pods suggests that the genes for flower color and pod shape are located a close together on the same autosome b on the X chromosome c on different chromosomes d on a mitochondrial chromosome
10
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Which of the following provides the best justification for an assumption that might have been used in the computer simulation (Table II) a The broad allele is recessive to the narrow allele because broad
leaves appear in every generation b The purple allele is dominant to the white allele because all the
offspring from the cross of purple-flowered and white-flowered plants had purple flowers
c The narrow allele is codominant with the purple allele because the purple-flower trait and the narrow-leaf trait segregate together
d The white allele is dominant to both the broad and narrow alleles because plants with either type of leaf shape can have white flowers
11
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table II the F 1 offspring of the cross between broad-leaved white-flowered plants with narrow-leaved purple-flowered plants have a phenotype that differs from that of either parent However many testcross offspring have the same phenotype as one of the two plants in the parental cross but relatively few testcross offspring have the same phenotype as the F 1 offspring Which of the following best explains the observation a Recombination between the leaf-shape and flower-color genes resulted in
chromosomes carrying a dominant allele of both genes b Recombination between the broad and narrow alleles of the leaf-shape gene resulted in
chromosomes carrying three different alleles at the same genetic locus c Independent assortment of homologous chromosomes resulted in the combinations of
alleles present in the parental generation d The computer model cannot capture the possible assortments of gametes when
multiple genes are considered
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
Homework DUE Tomorrow 143 5 Key Ideas AND Concept Check 1-3
DUE Now 142DUE Thursday Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
UNIT 78 TEST March 19th
Inheritance and Regulation
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoods
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with RrYy
1 Chance of baby with Rr 052 Chance of baby with Yy 053 Chance of baby with RrYy 025
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with both dominant phenotypes
1 Chance of baby with at least one R 0752 Chance of baby with at least one Y 0753 Chance of baby with RrYy 05625 (916)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with both dominant phenotypes
1 Chance of baby with at least one R 10
2 Chance of baby with at least one Y 10
3 Chance of baby with both dominant phenotypes 10
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
Homework DUE Tomorrow Linked vs Unlinked Genes AND Monohybrid Crosses to tunritincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with
vestigial wings and cinnabar eyes Predict the phenotypic ratio of the F2 individuals
Homework DUE Tomorrow 153 5 Key Ideas and Concept Check 1-3DUE Thursday Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with vestigial wings and cinnabar eyes Predict the
phenotypic ratio of the F2 individuals
3 The results of the cross from 2 show the following outcome Individuals of each phenotype are shown in the table Which of the following is the most likely explanation of the results a The two genes are located on two different chromosomes b The two genes are sex-linked c The two genes are located on mitochondrial DNA d The two genes are linked on an autosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
1 Build your diploid cell (an homologous pair for each chromosome)a Draw a big cell with a nucleus insideb DRAW homologous pairs of chromosomes
bull 1 big blue 1 big redbull 1 small blue 1 small red
ndash Add genes to your chromosomebull Write an H and an R on big blue and an h and an r on big redbull Write a T on small blue and a t on small red
2 Clone each chromosome (DNA Replication) (making sister chromatids)3 Nucleus breaks down (erase it)4 Homologous pairs form a tetrad crossing over may occur (note do not model
crossing over for now)5 Finish meiosis (see notes for help)6 Nucleus grows around chromosomes 4 cells made (gametes which have half
the number of chromosomes (haploids)7 Repeat Steps 1-6 this time at Step 4 include ONE crossover event
Recombination Modeling
When yoursquore confident on the process show Mr Jones
bull When yoursquore confident on the process show Mr Jones
bull In your notebookFigure 1510 Recombination p295At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid crossing over recombinant chromosome independent assortment Meiosis I Meiosis II
Recombination Modeling
Analysis
1 How does recombination increase the variety of gametes formed
2 Which types of gametes were more likely Gametes with recombinant chromosomes or ones without
3 Recombination is a random process How might it benefithurt the survival of an individualspecies
Recombination Modeling
Warm-UP
1 How could you calculate recombination frequency2 What would the recombination frequency tell you about the relative position of
genes on a chromosome3 Genes A B and C are on the same chromosome Testcrosses show that the
recombination frequency between A and B is 28 and between A and C is 12 Can you determine the linear order of these genes
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP What can we learn about inheritance from looking at a pedigree (use example of the Royal Family of Europe from the early 1900s)
Warm-UP In the following human pedigree squares represent males circles represent females and shaded symbols indicate individuals affected with a disorder One of the affected males from the third generation has a child with a female who is a carrier For the pedigree shown which of the following best expresses the probability that the couplersquos first son will be affected with the disorder
(A) 25 (B) 50 (C) 75 (D) 100
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Is a widowrsquos peak a dominant or recessive trait
Is a widowrsquos peak a dominant or recessive trait
Fig 14-UN5
George
Sandra Tom Sam
Arlene
Wilma Ann Michael
Carla
Daniel Alan Tina
Christopher
A heterozygous tall and a homozygous purple flowered plant is crossed with a short and white flowered plant Predict the offspring Assume independent assortment
1
P=purplep=whiteT=tallt=short
For a plant with the genotype WwXxYyZz what is the probability that the plant will produce a gamete with a haploid genotype of Wxyz Give your answer as a fraction or as a value between 0 and 1 to four decimal places
2
A completely-plated stickleback from a marine population was mated to a low-plated stickleback from a freshwater population The resulting F1 hybrids all displayed a completely plated phenotype When the F1 hybrids were allowed to interbreed the resulting F2 generation included completely plated offspring and low-plated offspring in an approximate 31 ratio Which of the following conclusions is best supported by the results of the breeding experiments
a Phenotypic variation in the F2 generation suggests that armor morphology is controlled by many alleles of a single gene
b The completely-plated phenotype is controlled by a dominant allele of a single gene
c Armor loss is an acquired characteristic that is affected by one or more environmental factors
d Patterns of armor plating in stickleback populations are regulated by sex-specific signals
3
If a man with type AB blood marries a woman with type O what blood types would you expect in their children What fraction would you expect of each type
4
IA= Type AIB= Type Bi= Type O
If a King marries a Queen that is a carrier of hemophilia (sex-linked recessive disease that is historically fatal before adulthood) what is the chance of the Kingdom having an heir to the kingrsquos throne assuming only one child is born
5
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
7 Gregor Mendelrsquos pioneering genetic experiments with pea plants occurred before the discovery of the structure and function of chromosomes Which of the following observations about inheritance in pea plants could be explained only after the discovery that genes may be linked on a chromosome
a Pea color and pea shape display independent inheritance patterns b Offspring of a given cross show all possible combinations of traits in
equal proportions c Most offspring of a given cross have a combination of traits that is
identical to that of either one parent or the other d Recessive phenotypes can skip a generation showing up only in the
parental and F 2 generations
8
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Based on the data in Table I which of the following best explains why there are no individuals with constricted pods in the F 1 generation a Inflated pod shape is dominant to constricted pod shape b The inflated-pod offspring in the F sub one generation are
homozygous c Constricted pod shape typically arises from a new mutation in the F 1
generation d The constricted-pod offspring are carriers for the inflated pod shape
allele
9
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table I the ratio of phenotypes in the offspring from the testcross with F 1 plants that had purple flowers and inflated pods suggests that the genes for flower color and pod shape are located a close together on the same autosome b on the X chromosome c on different chromosomes d on a mitochondrial chromosome
10
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Which of the following provides the best justification for an assumption that might have been used in the computer simulation (Table II) a The broad allele is recessive to the narrow allele because broad
leaves appear in every generation b The purple allele is dominant to the white allele because all the
offspring from the cross of purple-flowered and white-flowered plants had purple flowers
c The narrow allele is codominant with the purple allele because the purple-flower trait and the narrow-leaf trait segregate together
d The white allele is dominant to both the broad and narrow alleles because plants with either type of leaf shape can have white flowers
11
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table II the F 1 offspring of the cross between broad-leaved white-flowered plants with narrow-leaved purple-flowered plants have a phenotype that differs from that of either parent However many testcross offspring have the same phenotype as one of the two plants in the parental cross but relatively few testcross offspring have the same phenotype as the F 1 offspring Which of the following best explains the observation a Recombination between the leaf-shape and flower-color genes resulted in
chromosomes carrying a dominant allele of both genes b Recombination between the broad and narrow alleles of the leaf-shape gene resulted in
chromosomes carrying three different alleles at the same genetic locus c Independent assortment of homologous chromosomes resulted in the combinations of
alleles present in the parental generation d The computer model cannot capture the possible assortments of gametes when
multiple genes are considered
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
Homework DUE Tomorrow 143 5 Key Ideas AND Concept Check 1-3
DUE Now 142DUE Thursday Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
UNIT 78 TEST March 19th
Inheritance and Regulation
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoods
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with RrYy
1 Chance of baby with Rr 052 Chance of baby with Yy 053 Chance of baby with RrYy 025
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with both dominant phenotypes
1 Chance of baby with at least one R 0752 Chance of baby with at least one Y 0753 Chance of baby with RrYy 05625 (916)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with both dominant phenotypes
1 Chance of baby with at least one R 10
2 Chance of baby with at least one Y 10
3 Chance of baby with both dominant phenotypes 10
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
Homework DUE Tomorrow Linked vs Unlinked Genes AND Monohybrid Crosses to tunritincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with
vestigial wings and cinnabar eyes Predict the phenotypic ratio of the F2 individuals
Homework DUE Tomorrow 153 5 Key Ideas and Concept Check 1-3DUE Thursday Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with vestigial wings and cinnabar eyes Predict the
phenotypic ratio of the F2 individuals
3 The results of the cross from 2 show the following outcome Individuals of each phenotype are shown in the table Which of the following is the most likely explanation of the results a The two genes are located on two different chromosomes b The two genes are sex-linked c The two genes are located on mitochondrial DNA d The two genes are linked on an autosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
1 Build your diploid cell (an homologous pair for each chromosome)a Draw a big cell with a nucleus insideb DRAW homologous pairs of chromosomes
bull 1 big blue 1 big redbull 1 small blue 1 small red
ndash Add genes to your chromosomebull Write an H and an R on big blue and an h and an r on big redbull Write a T on small blue and a t on small red
2 Clone each chromosome (DNA Replication) (making sister chromatids)3 Nucleus breaks down (erase it)4 Homologous pairs form a tetrad crossing over may occur (note do not model
crossing over for now)5 Finish meiosis (see notes for help)6 Nucleus grows around chromosomes 4 cells made (gametes which have half
the number of chromosomes (haploids)7 Repeat Steps 1-6 this time at Step 4 include ONE crossover event
Recombination Modeling
When yoursquore confident on the process show Mr Jones
bull When yoursquore confident on the process show Mr Jones
bull In your notebookFigure 1510 Recombination p295At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid crossing over recombinant chromosome independent assortment Meiosis I Meiosis II
Recombination Modeling
Analysis
1 How does recombination increase the variety of gametes formed
2 Which types of gametes were more likely Gametes with recombinant chromosomes or ones without
3 Recombination is a random process How might it benefithurt the survival of an individualspecies
Recombination Modeling
Warm-UP
1 How could you calculate recombination frequency2 What would the recombination frequency tell you about the relative position of
genes on a chromosome3 Genes A B and C are on the same chromosome Testcrosses show that the
recombination frequency between A and B is 28 and between A and C is 12 Can you determine the linear order of these genes
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP What can we learn about inheritance from looking at a pedigree (use example of the Royal Family of Europe from the early 1900s)
Warm-UP In the following human pedigree squares represent males circles represent females and shaded symbols indicate individuals affected with a disorder One of the affected males from the third generation has a child with a female who is a carrier For the pedigree shown which of the following best expresses the probability that the couplersquos first son will be affected with the disorder
(A) 25 (B) 50 (C) 75 (D) 100
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Is a widowrsquos peak a dominant or recessive trait
Is a widowrsquos peak a dominant or recessive trait
Fig 14-UN5
George
Sandra Tom Sam
Arlene
Wilma Ann Michael
Carla
Daniel Alan Tina
Christopher
A heterozygous tall and a homozygous purple flowered plant is crossed with a short and white flowered plant Predict the offspring Assume independent assortment
1
P=purplep=whiteT=tallt=short
For a plant with the genotype WwXxYyZz what is the probability that the plant will produce a gamete with a haploid genotype of Wxyz Give your answer as a fraction or as a value between 0 and 1 to four decimal places
2
A completely-plated stickleback from a marine population was mated to a low-plated stickleback from a freshwater population The resulting F1 hybrids all displayed a completely plated phenotype When the F1 hybrids were allowed to interbreed the resulting F2 generation included completely plated offspring and low-plated offspring in an approximate 31 ratio Which of the following conclusions is best supported by the results of the breeding experiments
a Phenotypic variation in the F2 generation suggests that armor morphology is controlled by many alleles of a single gene
b The completely-plated phenotype is controlled by a dominant allele of a single gene
c Armor loss is an acquired characteristic that is affected by one or more environmental factors
d Patterns of armor plating in stickleback populations are regulated by sex-specific signals
3
If a man with type AB blood marries a woman with type O what blood types would you expect in their children What fraction would you expect of each type
4
IA= Type AIB= Type Bi= Type O
If a King marries a Queen that is a carrier of hemophilia (sex-linked recessive disease that is historically fatal before adulthood) what is the chance of the Kingdom having an heir to the kingrsquos throne assuming only one child is born
5
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
7 Gregor Mendelrsquos pioneering genetic experiments with pea plants occurred before the discovery of the structure and function of chromosomes Which of the following observations about inheritance in pea plants could be explained only after the discovery that genes may be linked on a chromosome
a Pea color and pea shape display independent inheritance patterns b Offspring of a given cross show all possible combinations of traits in
equal proportions c Most offspring of a given cross have a combination of traits that is
identical to that of either one parent or the other d Recessive phenotypes can skip a generation showing up only in the
parental and F 2 generations
8
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Based on the data in Table I which of the following best explains why there are no individuals with constricted pods in the F 1 generation a Inflated pod shape is dominant to constricted pod shape b The inflated-pod offspring in the F sub one generation are
homozygous c Constricted pod shape typically arises from a new mutation in the F 1
generation d The constricted-pod offspring are carriers for the inflated pod shape
allele
9
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table I the ratio of phenotypes in the offspring from the testcross with F 1 plants that had purple flowers and inflated pods suggests that the genes for flower color and pod shape are located a close together on the same autosome b on the X chromosome c on different chromosomes d on a mitochondrial chromosome
10
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Which of the following provides the best justification for an assumption that might have been used in the computer simulation (Table II) a The broad allele is recessive to the narrow allele because broad
leaves appear in every generation b The purple allele is dominant to the white allele because all the
offspring from the cross of purple-flowered and white-flowered plants had purple flowers
c The narrow allele is codominant with the purple allele because the purple-flower trait and the narrow-leaf trait segregate together
d The white allele is dominant to both the broad and narrow alleles because plants with either type of leaf shape can have white flowers
11
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table II the F 1 offspring of the cross between broad-leaved white-flowered plants with narrow-leaved purple-flowered plants have a phenotype that differs from that of either parent However many testcross offspring have the same phenotype as one of the two plants in the parental cross but relatively few testcross offspring have the same phenotype as the F 1 offspring Which of the following best explains the observation a Recombination between the leaf-shape and flower-color genes resulted in
chromosomes carrying a dominant allele of both genes b Recombination between the broad and narrow alleles of the leaf-shape gene resulted in
chromosomes carrying three different alleles at the same genetic locus c Independent assortment of homologous chromosomes resulted in the combinations of
alleles present in the parental generation d The computer model cannot capture the possible assortments of gametes when
multiple genes are considered
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Inheritance Patterns
bull Simple DominanceRecessive Mendelbull monohybrid cross one traitbull di or tri hybrid cross two or three traits
assuming independent assortmentbull laws of probability vs punnett squares
bull incomplete dominance phenotype of hybrids is between the phenotypes of the purebreds
bull codominance two dominant alleles affect the phenotype in separate distinguishable ways
bull polygenic inheritance an additive effect of two or more genes on a single phenotype
bull x-linked genes genes on the x chromosome are expressed by boys more often than girls bc boys only have one x chromosome (they cannot ldquomaskrdquo recessive alleles)
bull linked genes when 2 alleles are on the same chromosome they show up together more often
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
Homework DUE Tomorrow 143 5 Key Ideas AND Concept Check 1-3
DUE Now 142DUE Thursday Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
UNIT 78 TEST March 19th
Inheritance and Regulation
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoods
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with RrYy
1 Chance of baby with Rr 052 Chance of baby with Yy 053 Chance of baby with RrYy 025
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with both dominant phenotypes
1 Chance of baby with at least one R 0752 Chance of baby with at least one Y 0753 Chance of baby with RrYy 05625 (916)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with both dominant phenotypes
1 Chance of baby with at least one R 10
2 Chance of baby with at least one Y 10
3 Chance of baby with both dominant phenotypes 10
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
Homework DUE Tomorrow Linked vs Unlinked Genes AND Monohybrid Crosses to tunritincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with
vestigial wings and cinnabar eyes Predict the phenotypic ratio of the F2 individuals
Homework DUE Tomorrow 153 5 Key Ideas and Concept Check 1-3DUE Thursday Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with vestigial wings and cinnabar eyes Predict the
phenotypic ratio of the F2 individuals
3 The results of the cross from 2 show the following outcome Individuals of each phenotype are shown in the table Which of the following is the most likely explanation of the results a The two genes are located on two different chromosomes b The two genes are sex-linked c The two genes are located on mitochondrial DNA d The two genes are linked on an autosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
1 Build your diploid cell (an homologous pair for each chromosome)a Draw a big cell with a nucleus insideb DRAW homologous pairs of chromosomes
bull 1 big blue 1 big redbull 1 small blue 1 small red
ndash Add genes to your chromosomebull Write an H and an R on big blue and an h and an r on big redbull Write a T on small blue and a t on small red
2 Clone each chromosome (DNA Replication) (making sister chromatids)3 Nucleus breaks down (erase it)4 Homologous pairs form a tetrad crossing over may occur (note do not model
crossing over for now)5 Finish meiosis (see notes for help)6 Nucleus grows around chromosomes 4 cells made (gametes which have half
the number of chromosomes (haploids)7 Repeat Steps 1-6 this time at Step 4 include ONE crossover event
Recombination Modeling
When yoursquore confident on the process show Mr Jones
bull When yoursquore confident on the process show Mr Jones
bull In your notebookFigure 1510 Recombination p295At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid crossing over recombinant chromosome independent assortment Meiosis I Meiosis II
Recombination Modeling
Analysis
1 How does recombination increase the variety of gametes formed
2 Which types of gametes were more likely Gametes with recombinant chromosomes or ones without
3 Recombination is a random process How might it benefithurt the survival of an individualspecies
Recombination Modeling
Warm-UP
1 How could you calculate recombination frequency2 What would the recombination frequency tell you about the relative position of
genes on a chromosome3 Genes A B and C are on the same chromosome Testcrosses show that the
recombination frequency between A and B is 28 and between A and C is 12 Can you determine the linear order of these genes
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP What can we learn about inheritance from looking at a pedigree (use example of the Royal Family of Europe from the early 1900s)
Warm-UP In the following human pedigree squares represent males circles represent females and shaded symbols indicate individuals affected with a disorder One of the affected males from the third generation has a child with a female who is a carrier For the pedigree shown which of the following best expresses the probability that the couplersquos first son will be affected with the disorder
(A) 25 (B) 50 (C) 75 (D) 100
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Is a widowrsquos peak a dominant or recessive trait
Is a widowrsquos peak a dominant or recessive trait
Fig 14-UN5
George
Sandra Tom Sam
Arlene
Wilma Ann Michael
Carla
Daniel Alan Tina
Christopher
A heterozygous tall and a homozygous purple flowered plant is crossed with a short and white flowered plant Predict the offspring Assume independent assortment
1
P=purplep=whiteT=tallt=short
For a plant with the genotype WwXxYyZz what is the probability that the plant will produce a gamete with a haploid genotype of Wxyz Give your answer as a fraction or as a value between 0 and 1 to four decimal places
2
A completely-plated stickleback from a marine population was mated to a low-plated stickleback from a freshwater population The resulting F1 hybrids all displayed a completely plated phenotype When the F1 hybrids were allowed to interbreed the resulting F2 generation included completely plated offspring and low-plated offspring in an approximate 31 ratio Which of the following conclusions is best supported by the results of the breeding experiments
a Phenotypic variation in the F2 generation suggests that armor morphology is controlled by many alleles of a single gene
b The completely-plated phenotype is controlled by a dominant allele of a single gene
c Armor loss is an acquired characteristic that is affected by one or more environmental factors
d Patterns of armor plating in stickleback populations are regulated by sex-specific signals
3
If a man with type AB blood marries a woman with type O what blood types would you expect in their children What fraction would you expect of each type
4
IA= Type AIB= Type Bi= Type O
If a King marries a Queen that is a carrier of hemophilia (sex-linked recessive disease that is historically fatal before adulthood) what is the chance of the Kingdom having an heir to the kingrsquos throne assuming only one child is born
5
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
7 Gregor Mendelrsquos pioneering genetic experiments with pea plants occurred before the discovery of the structure and function of chromosomes Which of the following observations about inheritance in pea plants could be explained only after the discovery that genes may be linked on a chromosome
a Pea color and pea shape display independent inheritance patterns b Offspring of a given cross show all possible combinations of traits in
equal proportions c Most offspring of a given cross have a combination of traits that is
identical to that of either one parent or the other d Recessive phenotypes can skip a generation showing up only in the
parental and F 2 generations
8
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Based on the data in Table I which of the following best explains why there are no individuals with constricted pods in the F 1 generation a Inflated pod shape is dominant to constricted pod shape b The inflated-pod offspring in the F sub one generation are
homozygous c Constricted pod shape typically arises from a new mutation in the F 1
generation d The constricted-pod offspring are carriers for the inflated pod shape
allele
9
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table I the ratio of phenotypes in the offspring from the testcross with F 1 plants that had purple flowers and inflated pods suggests that the genes for flower color and pod shape are located a close together on the same autosome b on the X chromosome c on different chromosomes d on a mitochondrial chromosome
10
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Which of the following provides the best justification for an assumption that might have been used in the computer simulation (Table II) a The broad allele is recessive to the narrow allele because broad
leaves appear in every generation b The purple allele is dominant to the white allele because all the
offspring from the cross of purple-flowered and white-flowered plants had purple flowers
c The narrow allele is codominant with the purple allele because the purple-flower trait and the narrow-leaf trait segregate together
d The white allele is dominant to both the broad and narrow alleles because plants with either type of leaf shape can have white flowers
11
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table II the F 1 offspring of the cross between broad-leaved white-flowered plants with narrow-leaved purple-flowered plants have a phenotype that differs from that of either parent However many testcross offspring have the same phenotype as one of the two plants in the parental cross but relatively few testcross offspring have the same phenotype as the F 1 offspring Which of the following best explains the observation a Recombination between the leaf-shape and flower-color genes resulted in
chromosomes carrying a dominant allele of both genes b Recombination between the broad and narrow alleles of the leaf-shape gene resulted in
chromosomes carrying three different alleles at the same genetic locus c Independent assortment of homologous chromosomes resulted in the combinations of
alleles present in the parental generation d The computer model cannot capture the possible assortments of gametes when
multiple genes are considered
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
Homework DUE Tomorrow 143 5 Key Ideas AND Concept Check 1-3
DUE Now 142DUE Thursday Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
UNIT 78 TEST March 19th
Inheritance and Regulation
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoods
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with RrYy
1 Chance of baby with Rr 052 Chance of baby with Yy 053 Chance of baby with RrYy 025
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with both dominant phenotypes
1 Chance of baby with at least one R 0752 Chance of baby with at least one Y 0753 Chance of baby with RrYy 05625 (916)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with both dominant phenotypes
1 Chance of baby with at least one R 10
2 Chance of baby with at least one Y 10
3 Chance of baby with both dominant phenotypes 10
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
Homework DUE Tomorrow Linked vs Unlinked Genes AND Monohybrid Crosses to tunritincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with
vestigial wings and cinnabar eyes Predict the phenotypic ratio of the F2 individuals
Homework DUE Tomorrow 153 5 Key Ideas and Concept Check 1-3DUE Thursday Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with vestigial wings and cinnabar eyes Predict the
phenotypic ratio of the F2 individuals
3 The results of the cross from 2 show the following outcome Individuals of each phenotype are shown in the table Which of the following is the most likely explanation of the results a The two genes are located on two different chromosomes b The two genes are sex-linked c The two genes are located on mitochondrial DNA d The two genes are linked on an autosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
1 Build your diploid cell (an homologous pair for each chromosome)a Draw a big cell with a nucleus insideb DRAW homologous pairs of chromosomes
bull 1 big blue 1 big redbull 1 small blue 1 small red
ndash Add genes to your chromosomebull Write an H and an R on big blue and an h and an r on big redbull Write a T on small blue and a t on small red
2 Clone each chromosome (DNA Replication) (making sister chromatids)3 Nucleus breaks down (erase it)4 Homologous pairs form a tetrad crossing over may occur (note do not model
crossing over for now)5 Finish meiosis (see notes for help)6 Nucleus grows around chromosomes 4 cells made (gametes which have half
the number of chromosomes (haploids)7 Repeat Steps 1-6 this time at Step 4 include ONE crossover event
Recombination Modeling
When yoursquore confident on the process show Mr Jones
bull When yoursquore confident on the process show Mr Jones
bull In your notebookFigure 1510 Recombination p295At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid crossing over recombinant chromosome independent assortment Meiosis I Meiosis II
Recombination Modeling
Analysis
1 How does recombination increase the variety of gametes formed
2 Which types of gametes were more likely Gametes with recombinant chromosomes or ones without
3 Recombination is a random process How might it benefithurt the survival of an individualspecies
Recombination Modeling
Warm-UP
1 How could you calculate recombination frequency2 What would the recombination frequency tell you about the relative position of
genes on a chromosome3 Genes A B and C are on the same chromosome Testcrosses show that the
recombination frequency between A and B is 28 and between A and C is 12 Can you determine the linear order of these genes
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP What can we learn about inheritance from looking at a pedigree (use example of the Royal Family of Europe from the early 1900s)
Warm-UP In the following human pedigree squares represent males circles represent females and shaded symbols indicate individuals affected with a disorder One of the affected males from the third generation has a child with a female who is a carrier For the pedigree shown which of the following best expresses the probability that the couplersquos first son will be affected with the disorder
(A) 25 (B) 50 (C) 75 (D) 100
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Is a widowrsquos peak a dominant or recessive trait
Is a widowrsquos peak a dominant or recessive trait
Fig 14-UN5
George
Sandra Tom Sam
Arlene
Wilma Ann Michael
Carla
Daniel Alan Tina
Christopher
A heterozygous tall and a homozygous purple flowered plant is crossed with a short and white flowered plant Predict the offspring Assume independent assortment
1
P=purplep=whiteT=tallt=short
For a plant with the genotype WwXxYyZz what is the probability that the plant will produce a gamete with a haploid genotype of Wxyz Give your answer as a fraction or as a value between 0 and 1 to four decimal places
2
A completely-plated stickleback from a marine population was mated to a low-plated stickleback from a freshwater population The resulting F1 hybrids all displayed a completely plated phenotype When the F1 hybrids were allowed to interbreed the resulting F2 generation included completely plated offspring and low-plated offspring in an approximate 31 ratio Which of the following conclusions is best supported by the results of the breeding experiments
a Phenotypic variation in the F2 generation suggests that armor morphology is controlled by many alleles of a single gene
b The completely-plated phenotype is controlled by a dominant allele of a single gene
c Armor loss is an acquired characteristic that is affected by one or more environmental factors
d Patterns of armor plating in stickleback populations are regulated by sex-specific signals
3
If a man with type AB blood marries a woman with type O what blood types would you expect in their children What fraction would you expect of each type
4
IA= Type AIB= Type Bi= Type O
If a King marries a Queen that is a carrier of hemophilia (sex-linked recessive disease that is historically fatal before adulthood) what is the chance of the Kingdom having an heir to the kingrsquos throne assuming only one child is born
5
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
7 Gregor Mendelrsquos pioneering genetic experiments with pea plants occurred before the discovery of the structure and function of chromosomes Which of the following observations about inheritance in pea plants could be explained only after the discovery that genes may be linked on a chromosome
a Pea color and pea shape display independent inheritance patterns b Offspring of a given cross show all possible combinations of traits in
equal proportions c Most offspring of a given cross have a combination of traits that is
identical to that of either one parent or the other d Recessive phenotypes can skip a generation showing up only in the
parental and F 2 generations
8
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Based on the data in Table I which of the following best explains why there are no individuals with constricted pods in the F 1 generation a Inflated pod shape is dominant to constricted pod shape b The inflated-pod offspring in the F sub one generation are
homozygous c Constricted pod shape typically arises from a new mutation in the F 1
generation d The constricted-pod offspring are carriers for the inflated pod shape
allele
9
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table I the ratio of phenotypes in the offspring from the testcross with F 1 plants that had purple flowers and inflated pods suggests that the genes for flower color and pod shape are located a close together on the same autosome b on the X chromosome c on different chromosomes d on a mitochondrial chromosome
10
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Which of the following provides the best justification for an assumption that might have been used in the computer simulation (Table II) a The broad allele is recessive to the narrow allele because broad
leaves appear in every generation b The purple allele is dominant to the white allele because all the
offspring from the cross of purple-flowered and white-flowered plants had purple flowers
c The narrow allele is codominant with the purple allele because the purple-flower trait and the narrow-leaf trait segregate together
d The white allele is dominant to both the broad and narrow alleles because plants with either type of leaf shape can have white flowers
11
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table II the F 1 offspring of the cross between broad-leaved white-flowered plants with narrow-leaved purple-flowered plants have a phenotype that differs from that of either parent However many testcross offspring have the same phenotype as one of the two plants in the parental cross but relatively few testcross offspring have the same phenotype as the F 1 offspring Which of the following best explains the observation a Recombination between the leaf-shape and flower-color genes resulted in
chromosomes carrying a dominant allele of both genes b Recombination between the broad and narrow alleles of the leaf-shape gene resulted in
chromosomes carrying three different alleles at the same genetic locus c Independent assortment of homologous chromosomes resulted in the combinations of
alleles present in the parental generation d The computer model cannot capture the possible assortments of gametes when
multiple genes are considered
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoods
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with RrYy
1 Chance of baby with Rr 052 Chance of baby with Yy 053 Chance of baby with RrYy 025
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with both dominant phenotypes
1 Chance of baby with at least one R 0752 Chance of baby with at least one Y 0753 Chance of baby with RrYy 05625 (916)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with both dominant phenotypes
1 Chance of baby with at least one R 10
2 Chance of baby with at least one Y 10
3 Chance of baby with both dominant phenotypes 10
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
Homework DUE Tomorrow Linked vs Unlinked Genes AND Monohybrid Crosses to tunritincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with
vestigial wings and cinnabar eyes Predict the phenotypic ratio of the F2 individuals
Homework DUE Tomorrow 153 5 Key Ideas and Concept Check 1-3DUE Thursday Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with vestigial wings and cinnabar eyes Predict the
phenotypic ratio of the F2 individuals
3 The results of the cross from 2 show the following outcome Individuals of each phenotype are shown in the table Which of the following is the most likely explanation of the results a The two genes are located on two different chromosomes b The two genes are sex-linked c The two genes are located on mitochondrial DNA d The two genes are linked on an autosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
1 Build your diploid cell (an homologous pair for each chromosome)a Draw a big cell with a nucleus insideb DRAW homologous pairs of chromosomes
bull 1 big blue 1 big redbull 1 small blue 1 small red
ndash Add genes to your chromosomebull Write an H and an R on big blue and an h and an r on big redbull Write a T on small blue and a t on small red
2 Clone each chromosome (DNA Replication) (making sister chromatids)3 Nucleus breaks down (erase it)4 Homologous pairs form a tetrad crossing over may occur (note do not model
crossing over for now)5 Finish meiosis (see notes for help)6 Nucleus grows around chromosomes 4 cells made (gametes which have half
the number of chromosomes (haploids)7 Repeat Steps 1-6 this time at Step 4 include ONE crossover event
Recombination Modeling
When yoursquore confident on the process show Mr Jones
bull When yoursquore confident on the process show Mr Jones
bull In your notebookFigure 1510 Recombination p295At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid crossing over recombinant chromosome independent assortment Meiosis I Meiosis II
Recombination Modeling
Analysis
1 How does recombination increase the variety of gametes formed
2 Which types of gametes were more likely Gametes with recombinant chromosomes or ones without
3 Recombination is a random process How might it benefithurt the survival of an individualspecies
Recombination Modeling
Warm-UP
1 How could you calculate recombination frequency2 What would the recombination frequency tell you about the relative position of
genes on a chromosome3 Genes A B and C are on the same chromosome Testcrosses show that the
recombination frequency between A and B is 28 and between A and C is 12 Can you determine the linear order of these genes
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP What can we learn about inheritance from looking at a pedigree (use example of the Royal Family of Europe from the early 1900s)
Warm-UP In the following human pedigree squares represent males circles represent females and shaded symbols indicate individuals affected with a disorder One of the affected males from the third generation has a child with a female who is a carrier For the pedigree shown which of the following best expresses the probability that the couplersquos first son will be affected with the disorder
(A) 25 (B) 50 (C) 75 (D) 100
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Is a widowrsquos peak a dominant or recessive trait
Is a widowrsquos peak a dominant or recessive trait
Fig 14-UN5
George
Sandra Tom Sam
Arlene
Wilma Ann Michael
Carla
Daniel Alan Tina
Christopher
A heterozygous tall and a homozygous purple flowered plant is crossed with a short and white flowered plant Predict the offspring Assume independent assortment
1
P=purplep=whiteT=tallt=short
For a plant with the genotype WwXxYyZz what is the probability that the plant will produce a gamete with a haploid genotype of Wxyz Give your answer as a fraction or as a value between 0 and 1 to four decimal places
2
A completely-plated stickleback from a marine population was mated to a low-plated stickleback from a freshwater population The resulting F1 hybrids all displayed a completely plated phenotype When the F1 hybrids were allowed to interbreed the resulting F2 generation included completely plated offspring and low-plated offspring in an approximate 31 ratio Which of the following conclusions is best supported by the results of the breeding experiments
a Phenotypic variation in the F2 generation suggests that armor morphology is controlled by many alleles of a single gene
b The completely-plated phenotype is controlled by a dominant allele of a single gene
c Armor loss is an acquired characteristic that is affected by one or more environmental factors
d Patterns of armor plating in stickleback populations are regulated by sex-specific signals
3
If a man with type AB blood marries a woman with type O what blood types would you expect in their children What fraction would you expect of each type
4
IA= Type AIB= Type Bi= Type O
If a King marries a Queen that is a carrier of hemophilia (sex-linked recessive disease that is historically fatal before adulthood) what is the chance of the Kingdom having an heir to the kingrsquos throne assuming only one child is born
5
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
7 Gregor Mendelrsquos pioneering genetic experiments with pea plants occurred before the discovery of the structure and function of chromosomes Which of the following observations about inheritance in pea plants could be explained only after the discovery that genes may be linked on a chromosome
a Pea color and pea shape display independent inheritance patterns b Offspring of a given cross show all possible combinations of traits in
equal proportions c Most offspring of a given cross have a combination of traits that is
identical to that of either one parent or the other d Recessive phenotypes can skip a generation showing up only in the
parental and F 2 generations
8
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Based on the data in Table I which of the following best explains why there are no individuals with constricted pods in the F 1 generation a Inflated pod shape is dominant to constricted pod shape b The inflated-pod offspring in the F sub one generation are
homozygous c Constricted pod shape typically arises from a new mutation in the F 1
generation d The constricted-pod offspring are carriers for the inflated pod shape
allele
9
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table I the ratio of phenotypes in the offspring from the testcross with F 1 plants that had purple flowers and inflated pods suggests that the genes for flower color and pod shape are located a close together on the same autosome b on the X chromosome c on different chromosomes d on a mitochondrial chromosome
10
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Which of the following provides the best justification for an assumption that might have been used in the computer simulation (Table II) a The broad allele is recessive to the narrow allele because broad
leaves appear in every generation b The purple allele is dominant to the white allele because all the
offspring from the cross of purple-flowered and white-flowered plants had purple flowers
c The narrow allele is codominant with the purple allele because the purple-flower trait and the narrow-leaf trait segregate together
d The white allele is dominant to both the broad and narrow alleles because plants with either type of leaf shape can have white flowers
11
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table II the F 1 offspring of the cross between broad-leaved white-flowered plants with narrow-leaved purple-flowered plants have a phenotype that differs from that of either parent However many testcross offspring have the same phenotype as one of the two plants in the parental cross but relatively few testcross offspring have the same phenotype as the F 1 offspring Which of the following best explains the observation a Recombination between the leaf-shape and flower-color genes resulted in
chromosomes carrying a dominant allele of both genes b Recombination between the broad and narrow alleles of the leaf-shape gene resulted in
chromosomes carrying three different alleles at the same genetic locus c Independent assortment of homologous chromosomes resulted in the combinations of
alleles present in the parental generation d The computer model cannot capture the possible assortments of gametes when
multiple genes are considered
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with RrYy
1 Chance of baby with Rr 052 Chance of baby with Yy 053 Chance of baby with RrYy 025
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with both dominant phenotypes
1 Chance of baby with at least one R 0752 Chance of baby with at least one Y 0753 Chance of baby with RrYy 05625 (916)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with both dominant phenotypes
1 Chance of baby with at least one R 10
2 Chance of baby with at least one Y 10
3 Chance of baby with both dominant phenotypes 10
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
Homework DUE Tomorrow Linked vs Unlinked Genes AND Monohybrid Crosses to tunritincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with
vestigial wings and cinnabar eyes Predict the phenotypic ratio of the F2 individuals
Homework DUE Tomorrow 153 5 Key Ideas and Concept Check 1-3DUE Thursday Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with vestigial wings and cinnabar eyes Predict the
phenotypic ratio of the F2 individuals
3 The results of the cross from 2 show the following outcome Individuals of each phenotype are shown in the table Which of the following is the most likely explanation of the results a The two genes are located on two different chromosomes b The two genes are sex-linked c The two genes are located on mitochondrial DNA d The two genes are linked on an autosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
1 Build your diploid cell (an homologous pair for each chromosome)a Draw a big cell with a nucleus insideb DRAW homologous pairs of chromosomes
bull 1 big blue 1 big redbull 1 small blue 1 small red
ndash Add genes to your chromosomebull Write an H and an R on big blue and an h and an r on big redbull Write a T on small blue and a t on small red
2 Clone each chromosome (DNA Replication) (making sister chromatids)3 Nucleus breaks down (erase it)4 Homologous pairs form a tetrad crossing over may occur (note do not model
crossing over for now)5 Finish meiosis (see notes for help)6 Nucleus grows around chromosomes 4 cells made (gametes which have half
the number of chromosomes (haploids)7 Repeat Steps 1-6 this time at Step 4 include ONE crossover event
Recombination Modeling
When yoursquore confident on the process show Mr Jones
bull When yoursquore confident on the process show Mr Jones
bull In your notebookFigure 1510 Recombination p295At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid crossing over recombinant chromosome independent assortment Meiosis I Meiosis II
Recombination Modeling
Analysis
1 How does recombination increase the variety of gametes formed
2 Which types of gametes were more likely Gametes with recombinant chromosomes or ones without
3 Recombination is a random process How might it benefithurt the survival of an individualspecies
Recombination Modeling
Warm-UP
1 How could you calculate recombination frequency2 What would the recombination frequency tell you about the relative position of
genes on a chromosome3 Genes A B and C are on the same chromosome Testcrosses show that the
recombination frequency between A and B is 28 and between A and C is 12 Can you determine the linear order of these genes
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP What can we learn about inheritance from looking at a pedigree (use example of the Royal Family of Europe from the early 1900s)
Warm-UP In the following human pedigree squares represent males circles represent females and shaded symbols indicate individuals affected with a disorder One of the affected males from the third generation has a child with a female who is a carrier For the pedigree shown which of the following best expresses the probability that the couplersquos first son will be affected with the disorder
(A) 25 (B) 50 (C) 75 (D) 100
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Is a widowrsquos peak a dominant or recessive trait
Is a widowrsquos peak a dominant or recessive trait
Fig 14-UN5
George
Sandra Tom Sam
Arlene
Wilma Ann Michael
Carla
Daniel Alan Tina
Christopher
A heterozygous tall and a homozygous purple flowered plant is crossed with a short and white flowered plant Predict the offspring Assume independent assortment
1
P=purplep=whiteT=tallt=short
For a plant with the genotype WwXxYyZz what is the probability that the plant will produce a gamete with a haploid genotype of Wxyz Give your answer as a fraction or as a value between 0 and 1 to four decimal places
2
A completely-plated stickleback from a marine population was mated to a low-plated stickleback from a freshwater population The resulting F1 hybrids all displayed a completely plated phenotype When the F1 hybrids were allowed to interbreed the resulting F2 generation included completely plated offspring and low-plated offspring in an approximate 31 ratio Which of the following conclusions is best supported by the results of the breeding experiments
a Phenotypic variation in the F2 generation suggests that armor morphology is controlled by many alleles of a single gene
b The completely-plated phenotype is controlled by a dominant allele of a single gene
c Armor loss is an acquired characteristic that is affected by one or more environmental factors
d Patterns of armor plating in stickleback populations are regulated by sex-specific signals
3
If a man with type AB blood marries a woman with type O what blood types would you expect in their children What fraction would you expect of each type
4
IA= Type AIB= Type Bi= Type O
If a King marries a Queen that is a carrier of hemophilia (sex-linked recessive disease that is historically fatal before adulthood) what is the chance of the Kingdom having an heir to the kingrsquos throne assuming only one child is born
5
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
7 Gregor Mendelrsquos pioneering genetic experiments with pea plants occurred before the discovery of the structure and function of chromosomes Which of the following observations about inheritance in pea plants could be explained only after the discovery that genes may be linked on a chromosome
a Pea color and pea shape display independent inheritance patterns b Offspring of a given cross show all possible combinations of traits in
equal proportions c Most offspring of a given cross have a combination of traits that is
identical to that of either one parent or the other d Recessive phenotypes can skip a generation showing up only in the
parental and F 2 generations
8
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Based on the data in Table I which of the following best explains why there are no individuals with constricted pods in the F 1 generation a Inflated pod shape is dominant to constricted pod shape b The inflated-pod offspring in the F sub one generation are
homozygous c Constricted pod shape typically arises from a new mutation in the F 1
generation d The constricted-pod offspring are carriers for the inflated pod shape
allele
9
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table I the ratio of phenotypes in the offspring from the testcross with F 1 plants that had purple flowers and inflated pods suggests that the genes for flower color and pod shape are located a close together on the same autosome b on the X chromosome c on different chromosomes d on a mitochondrial chromosome
10
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Which of the following provides the best justification for an assumption that might have been used in the computer simulation (Table II) a The broad allele is recessive to the narrow allele because broad
leaves appear in every generation b The purple allele is dominant to the white allele because all the
offspring from the cross of purple-flowered and white-flowered plants had purple flowers
c The narrow allele is codominant with the purple allele because the purple-flower trait and the narrow-leaf trait segregate together
d The white allele is dominant to both the broad and narrow alleles because plants with either type of leaf shape can have white flowers
11
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table II the F 1 offspring of the cross between broad-leaved white-flowered plants with narrow-leaved purple-flowered plants have a phenotype that differs from that of either parent However many testcross offspring have the same phenotype as one of the two plants in the parental cross but relatively few testcross offspring have the same phenotype as the F 1 offspring Which of the following best explains the observation a Recombination between the leaf-shape and flower-color genes resulted in
chromosomes carrying a dominant allele of both genes b Recombination between the broad and narrow alleles of the leaf-shape gene resulted in
chromosomes carrying three different alleles at the same genetic locus c Independent assortment of homologous chromosomes resulted in the combinations of
alleles present in the parental generation d The computer model cannot capture the possible assortments of gametes when
multiple genes are considered
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with both dominant phenotypes
1 Chance of baby with at least one R 0752 Chance of baby with at least one Y 0753 Chance of baby with RrYy 05625 (916)
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with both dominant phenotypes
1 Chance of baby with at least one R 10
2 Chance of baby with at least one Y 10
3 Chance of baby with both dominant phenotypes 10
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
Homework DUE Tomorrow Linked vs Unlinked Genes AND Monohybrid Crosses to tunritincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with
vestigial wings and cinnabar eyes Predict the phenotypic ratio of the F2 individuals
Homework DUE Tomorrow 153 5 Key Ideas and Concept Check 1-3DUE Thursday Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with vestigial wings and cinnabar eyes Predict the
phenotypic ratio of the F2 individuals
3 The results of the cross from 2 show the following outcome Individuals of each phenotype are shown in the table Which of the following is the most likely explanation of the results a The two genes are located on two different chromosomes b The two genes are sex-linked c The two genes are located on mitochondrial DNA d The two genes are linked on an autosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
1 Build your diploid cell (an homologous pair for each chromosome)a Draw a big cell with a nucleus insideb DRAW homologous pairs of chromosomes
bull 1 big blue 1 big redbull 1 small blue 1 small red
ndash Add genes to your chromosomebull Write an H and an R on big blue and an h and an r on big redbull Write a T on small blue and a t on small red
2 Clone each chromosome (DNA Replication) (making sister chromatids)3 Nucleus breaks down (erase it)4 Homologous pairs form a tetrad crossing over may occur (note do not model
crossing over for now)5 Finish meiosis (see notes for help)6 Nucleus grows around chromosomes 4 cells made (gametes which have half
the number of chromosomes (haploids)7 Repeat Steps 1-6 this time at Step 4 include ONE crossover event
Recombination Modeling
When yoursquore confident on the process show Mr Jones
bull When yoursquore confident on the process show Mr Jones
bull In your notebookFigure 1510 Recombination p295At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid crossing over recombinant chromosome independent assortment Meiosis I Meiosis II
Recombination Modeling
Analysis
1 How does recombination increase the variety of gametes formed
2 Which types of gametes were more likely Gametes with recombinant chromosomes or ones without
3 Recombination is a random process How might it benefithurt the survival of an individualspecies
Recombination Modeling
Warm-UP
1 How could you calculate recombination frequency2 What would the recombination frequency tell you about the relative position of
genes on a chromosome3 Genes A B and C are on the same chromosome Testcrosses show that the
recombination frequency between A and B is 28 and between A and C is 12 Can you determine the linear order of these genes
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP What can we learn about inheritance from looking at a pedigree (use example of the Royal Family of Europe from the early 1900s)
Warm-UP In the following human pedigree squares represent males circles represent females and shaded symbols indicate individuals affected with a disorder One of the affected males from the third generation has a child with a female who is a carrier For the pedigree shown which of the following best expresses the probability that the couplersquos first son will be affected with the disorder
(A) 25 (B) 50 (C) 75 (D) 100
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Is a widowrsquos peak a dominant or recessive trait
Is a widowrsquos peak a dominant or recessive trait
Fig 14-UN5
George
Sandra Tom Sam
Arlene
Wilma Ann Michael
Carla
Daniel Alan Tina
Christopher
A heterozygous tall and a homozygous purple flowered plant is crossed with a short and white flowered plant Predict the offspring Assume independent assortment
1
P=purplep=whiteT=tallt=short
For a plant with the genotype WwXxYyZz what is the probability that the plant will produce a gamete with a haploid genotype of Wxyz Give your answer as a fraction or as a value between 0 and 1 to four decimal places
2
A completely-plated stickleback from a marine population was mated to a low-plated stickleback from a freshwater population The resulting F1 hybrids all displayed a completely plated phenotype When the F1 hybrids were allowed to interbreed the resulting F2 generation included completely plated offspring and low-plated offspring in an approximate 31 ratio Which of the following conclusions is best supported by the results of the breeding experiments
a Phenotypic variation in the F2 generation suggests that armor morphology is controlled by many alleles of a single gene
b The completely-plated phenotype is controlled by a dominant allele of a single gene
c Armor loss is an acquired characteristic that is affected by one or more environmental factors
d Patterns of armor plating in stickleback populations are regulated by sex-specific signals
3
If a man with type AB blood marries a woman with type O what blood types would you expect in their children What fraction would you expect of each type
4
IA= Type AIB= Type Bi= Type O
If a King marries a Queen that is a carrier of hemophilia (sex-linked recessive disease that is historically fatal before adulthood) what is the chance of the Kingdom having an heir to the kingrsquos throne assuming only one child is born
5
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
7 Gregor Mendelrsquos pioneering genetic experiments with pea plants occurred before the discovery of the structure and function of chromosomes Which of the following observations about inheritance in pea plants could be explained only after the discovery that genes may be linked on a chromosome
a Pea color and pea shape display independent inheritance patterns b Offspring of a given cross show all possible combinations of traits in
equal proportions c Most offspring of a given cross have a combination of traits that is
identical to that of either one parent or the other d Recessive phenotypes can skip a generation showing up only in the
parental and F 2 generations
8
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Based on the data in Table I which of the following best explains why there are no individuals with constricted pods in the F 1 generation a Inflated pod shape is dominant to constricted pod shape b The inflated-pod offspring in the F sub one generation are
homozygous c Constricted pod shape typically arises from a new mutation in the F 1
generation d The constricted-pod offspring are carriers for the inflated pod shape
allele
9
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table I the ratio of phenotypes in the offspring from the testcross with F 1 plants that had purple flowers and inflated pods suggests that the genes for flower color and pod shape are located a close together on the same autosome b on the X chromosome c on different chromosomes d on a mitochondrial chromosome
10
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Which of the following provides the best justification for an assumption that might have been used in the computer simulation (Table II) a The broad allele is recessive to the narrow allele because broad
leaves appear in every generation b The purple allele is dominant to the white allele because all the
offspring from the cross of purple-flowered and white-flowered plants had purple flowers
c The narrow allele is codominant with the purple allele because the purple-flower trait and the narrow-leaf trait segregate together
d The white allele is dominant to both the broad and narrow alleles because plants with either type of leaf shape can have white flowers
11
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table II the F 1 offspring of the cross between broad-leaved white-flowered plants with narrow-leaved purple-flowered plants have a phenotype that differs from that of either parent However many testcross offspring have the same phenotype as one of the two plants in the parental cross but relatively few testcross offspring have the same phenotype as the F 1 offspring Which of the following best explains the observation a Recombination between the leaf-shape and flower-color genes resulted in
chromosomes carrying a dominant allele of both genes b Recombination between the broad and narrow alleles of the leaf-shape gene resulted in
chromosomes carrying three different alleles at the same genetic locus c Independent assortment of homologous chromosomes resulted in the combinations of
alleles present in the parental generation d The computer model cannot capture the possible assortments of gametes when
multiple genes are considered
The inheritance pattern of many traits cannot be explained by simple Mendelian genetics
Laws of Probabilitybull skip Punnett squaresbull instead multiply likelyhoodsbull ex
Chance of baby with both dominant phenotypes
1 Chance of baby with at least one R 10
2 Chance of baby with at least one Y 10
3 Chance of baby with both dominant phenotypes 10
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
Homework DUE Tomorrow Linked vs Unlinked Genes AND Monohybrid Crosses to tunritincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with
vestigial wings and cinnabar eyes Predict the phenotypic ratio of the F2 individuals
Homework DUE Tomorrow 153 5 Key Ideas and Concept Check 1-3DUE Thursday Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with vestigial wings and cinnabar eyes Predict the
phenotypic ratio of the F2 individuals
3 The results of the cross from 2 show the following outcome Individuals of each phenotype are shown in the table Which of the following is the most likely explanation of the results a The two genes are located on two different chromosomes b The two genes are sex-linked c The two genes are located on mitochondrial DNA d The two genes are linked on an autosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
1 Build your diploid cell (an homologous pair for each chromosome)a Draw a big cell with a nucleus insideb DRAW homologous pairs of chromosomes
bull 1 big blue 1 big redbull 1 small blue 1 small red
ndash Add genes to your chromosomebull Write an H and an R on big blue and an h and an r on big redbull Write a T on small blue and a t on small red
2 Clone each chromosome (DNA Replication) (making sister chromatids)3 Nucleus breaks down (erase it)4 Homologous pairs form a tetrad crossing over may occur (note do not model
crossing over for now)5 Finish meiosis (see notes for help)6 Nucleus grows around chromosomes 4 cells made (gametes which have half
the number of chromosomes (haploids)7 Repeat Steps 1-6 this time at Step 4 include ONE crossover event
Recombination Modeling
When yoursquore confident on the process show Mr Jones
bull When yoursquore confident on the process show Mr Jones
bull In your notebookFigure 1510 Recombination p295At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid crossing over recombinant chromosome independent assortment Meiosis I Meiosis II
Recombination Modeling
Analysis
1 How does recombination increase the variety of gametes formed
2 Which types of gametes were more likely Gametes with recombinant chromosomes or ones without
3 Recombination is a random process How might it benefithurt the survival of an individualspecies
Recombination Modeling
Warm-UP
1 How could you calculate recombination frequency2 What would the recombination frequency tell you about the relative position of
genes on a chromosome3 Genes A B and C are on the same chromosome Testcrosses show that the
recombination frequency between A and B is 28 and between A and C is 12 Can you determine the linear order of these genes
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP What can we learn about inheritance from looking at a pedigree (use example of the Royal Family of Europe from the early 1900s)
Warm-UP In the following human pedigree squares represent males circles represent females and shaded symbols indicate individuals affected with a disorder One of the affected males from the third generation has a child with a female who is a carrier For the pedigree shown which of the following best expresses the probability that the couplersquos first son will be affected with the disorder
(A) 25 (B) 50 (C) 75 (D) 100
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Is a widowrsquos peak a dominant or recessive trait
Is a widowrsquos peak a dominant or recessive trait
Fig 14-UN5
George
Sandra Tom Sam
Arlene
Wilma Ann Michael
Carla
Daniel Alan Tina
Christopher
A heterozygous tall and a homozygous purple flowered plant is crossed with a short and white flowered plant Predict the offspring Assume independent assortment
1
P=purplep=whiteT=tallt=short
For a plant with the genotype WwXxYyZz what is the probability that the plant will produce a gamete with a haploid genotype of Wxyz Give your answer as a fraction or as a value between 0 and 1 to four decimal places
2
A completely-plated stickleback from a marine population was mated to a low-plated stickleback from a freshwater population The resulting F1 hybrids all displayed a completely plated phenotype When the F1 hybrids were allowed to interbreed the resulting F2 generation included completely plated offspring and low-plated offspring in an approximate 31 ratio Which of the following conclusions is best supported by the results of the breeding experiments
a Phenotypic variation in the F2 generation suggests that armor morphology is controlled by many alleles of a single gene
b The completely-plated phenotype is controlled by a dominant allele of a single gene
c Armor loss is an acquired characteristic that is affected by one or more environmental factors
d Patterns of armor plating in stickleback populations are regulated by sex-specific signals
3
If a man with type AB blood marries a woman with type O what blood types would you expect in their children What fraction would you expect of each type
4
IA= Type AIB= Type Bi= Type O
If a King marries a Queen that is a carrier of hemophilia (sex-linked recessive disease that is historically fatal before adulthood) what is the chance of the Kingdom having an heir to the kingrsquos throne assuming only one child is born
5
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
7 Gregor Mendelrsquos pioneering genetic experiments with pea plants occurred before the discovery of the structure and function of chromosomes Which of the following observations about inheritance in pea plants could be explained only after the discovery that genes may be linked on a chromosome
a Pea color and pea shape display independent inheritance patterns b Offspring of a given cross show all possible combinations of traits in
equal proportions c Most offspring of a given cross have a combination of traits that is
identical to that of either one parent or the other d Recessive phenotypes can skip a generation showing up only in the
parental and F 2 generations
8
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Based on the data in Table I which of the following best explains why there are no individuals with constricted pods in the F 1 generation a Inflated pod shape is dominant to constricted pod shape b The inflated-pod offspring in the F sub one generation are
homozygous c Constricted pod shape typically arises from a new mutation in the F 1
generation d The constricted-pod offspring are carriers for the inflated pod shape
allele
9
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table I the ratio of phenotypes in the offspring from the testcross with F 1 plants that had purple flowers and inflated pods suggests that the genes for flower color and pod shape are located a close together on the same autosome b on the X chromosome c on different chromosomes d on a mitochondrial chromosome
10
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Which of the following provides the best justification for an assumption that might have been used in the computer simulation (Table II) a The broad allele is recessive to the narrow allele because broad
leaves appear in every generation b The purple allele is dominant to the white allele because all the
offspring from the cross of purple-flowered and white-flowered plants had purple flowers
c The narrow allele is codominant with the purple allele because the purple-flower trait and the narrow-leaf trait segregate together
d The white allele is dominant to both the broad and narrow alleles because plants with either type of leaf shape can have white flowers
11
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table II the F 1 offspring of the cross between broad-leaved white-flowered plants with narrow-leaved purple-flowered plants have a phenotype that differs from that of either parent However many testcross offspring have the same phenotype as one of the two plants in the parental cross but relatively few testcross offspring have the same phenotype as the F 1 offspring Which of the following best explains the observation a Recombination between the leaf-shape and flower-color genes resulted in
chromosomes carrying a dominant allele of both genes b Recombination between the broad and narrow alleles of the leaf-shape gene resulted in
chromosomes carrying three different alleles at the same genetic locus c Independent assortment of homologous chromosomes resulted in the combinations of
alleles present in the parental generation d The computer model cannot capture the possible assortments of gametes when
multiple genes are considered
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
Homework DUE Tomorrow Linked vs Unlinked Genes AND Monohybrid Crosses to tunritincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with
vestigial wings and cinnabar eyes Predict the phenotypic ratio of the F2 individuals
Homework DUE Tomorrow 153 5 Key Ideas and Concept Check 1-3DUE Thursday Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with vestigial wings and cinnabar eyes Predict the
phenotypic ratio of the F2 individuals
3 The results of the cross from 2 show the following outcome Individuals of each phenotype are shown in the table Which of the following is the most likely explanation of the results a The two genes are located on two different chromosomes b The two genes are sex-linked c The two genes are located on mitochondrial DNA d The two genes are linked on an autosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
1 Build your diploid cell (an homologous pair for each chromosome)a Draw a big cell with a nucleus insideb DRAW homologous pairs of chromosomes
bull 1 big blue 1 big redbull 1 small blue 1 small red
ndash Add genes to your chromosomebull Write an H and an R on big blue and an h and an r on big redbull Write a T on small blue and a t on small red
2 Clone each chromosome (DNA Replication) (making sister chromatids)3 Nucleus breaks down (erase it)4 Homologous pairs form a tetrad crossing over may occur (note do not model
crossing over for now)5 Finish meiosis (see notes for help)6 Nucleus grows around chromosomes 4 cells made (gametes which have half
the number of chromosomes (haploids)7 Repeat Steps 1-6 this time at Step 4 include ONE crossover event
Recombination Modeling
When yoursquore confident on the process show Mr Jones
bull When yoursquore confident on the process show Mr Jones
bull In your notebookFigure 1510 Recombination p295At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid crossing over recombinant chromosome independent assortment Meiosis I Meiosis II
Recombination Modeling
Analysis
1 How does recombination increase the variety of gametes formed
2 Which types of gametes were more likely Gametes with recombinant chromosomes or ones without
3 Recombination is a random process How might it benefithurt the survival of an individualspecies
Recombination Modeling
Warm-UP
1 How could you calculate recombination frequency2 What would the recombination frequency tell you about the relative position of
genes on a chromosome3 Genes A B and C are on the same chromosome Testcrosses show that the
recombination frequency between A and B is 28 and between A and C is 12 Can you determine the linear order of these genes
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP What can we learn about inheritance from looking at a pedigree (use example of the Royal Family of Europe from the early 1900s)
Warm-UP In the following human pedigree squares represent males circles represent females and shaded symbols indicate individuals affected with a disorder One of the affected males from the third generation has a child with a female who is a carrier For the pedigree shown which of the following best expresses the probability that the couplersquos first son will be affected with the disorder
(A) 25 (B) 50 (C) 75 (D) 100
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Is a widowrsquos peak a dominant or recessive trait
Is a widowrsquos peak a dominant or recessive trait
Fig 14-UN5
George
Sandra Tom Sam
Arlene
Wilma Ann Michael
Carla
Daniel Alan Tina
Christopher
A heterozygous tall and a homozygous purple flowered plant is crossed with a short and white flowered plant Predict the offspring Assume independent assortment
1
P=purplep=whiteT=tallt=short
For a plant with the genotype WwXxYyZz what is the probability that the plant will produce a gamete with a haploid genotype of Wxyz Give your answer as a fraction or as a value between 0 and 1 to four decimal places
2
A completely-plated stickleback from a marine population was mated to a low-plated stickleback from a freshwater population The resulting F1 hybrids all displayed a completely plated phenotype When the F1 hybrids were allowed to interbreed the resulting F2 generation included completely plated offspring and low-plated offspring in an approximate 31 ratio Which of the following conclusions is best supported by the results of the breeding experiments
a Phenotypic variation in the F2 generation suggests that armor morphology is controlled by many alleles of a single gene
b The completely-plated phenotype is controlled by a dominant allele of a single gene
c Armor loss is an acquired characteristic that is affected by one or more environmental factors
d Patterns of armor plating in stickleback populations are regulated by sex-specific signals
3
If a man with type AB blood marries a woman with type O what blood types would you expect in their children What fraction would you expect of each type
4
IA= Type AIB= Type Bi= Type O
If a King marries a Queen that is a carrier of hemophilia (sex-linked recessive disease that is historically fatal before adulthood) what is the chance of the Kingdom having an heir to the kingrsquos throne assuming only one child is born
5
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
7 Gregor Mendelrsquos pioneering genetic experiments with pea plants occurred before the discovery of the structure and function of chromosomes Which of the following observations about inheritance in pea plants could be explained only after the discovery that genes may be linked on a chromosome
a Pea color and pea shape display independent inheritance patterns b Offspring of a given cross show all possible combinations of traits in
equal proportions c Most offspring of a given cross have a combination of traits that is
identical to that of either one parent or the other d Recessive phenotypes can skip a generation showing up only in the
parental and F 2 generations
8
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Based on the data in Table I which of the following best explains why there are no individuals with constricted pods in the F 1 generation a Inflated pod shape is dominant to constricted pod shape b The inflated-pod offspring in the F sub one generation are
homozygous c Constricted pod shape typically arises from a new mutation in the F 1
generation d The constricted-pod offspring are carriers for the inflated pod shape
allele
9
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table I the ratio of phenotypes in the offspring from the testcross with F 1 plants that had purple flowers and inflated pods suggests that the genes for flower color and pod shape are located a close together on the same autosome b on the X chromosome c on different chromosomes d on a mitochondrial chromosome
10
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Which of the following provides the best justification for an assumption that might have been used in the computer simulation (Table II) a The broad allele is recessive to the narrow allele because broad
leaves appear in every generation b The purple allele is dominant to the white allele because all the
offspring from the cross of purple-flowered and white-flowered plants had purple flowers
c The narrow allele is codominant with the purple allele because the purple-flower trait and the narrow-leaf trait segregate together
d The white allele is dominant to both the broad and narrow alleles because plants with either type of leaf shape can have white flowers
11
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table II the F 1 offspring of the cross between broad-leaved white-flowered plants with narrow-leaved purple-flowered plants have a phenotype that differs from that of either parent However many testcross offspring have the same phenotype as one of the two plants in the parental cross but relatively few testcross offspring have the same phenotype as the F 1 offspring Which of the following best explains the observation a Recombination between the leaf-shape and flower-color genes resulted in
chromosomes carrying a dominant allele of both genes b Recombination between the broad and narrow alleles of the leaf-shape gene resulted in
chromosomes carrying three different alleles at the same genetic locus c Independent assortment of homologous chromosomes resulted in the combinations of
alleles present in the parental generation d The computer model cannot capture the possible assortments of gametes when
multiple genes are considered
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with
vestigial wings and cinnabar eyes Predict the phenotypic ratio of the F2 individuals
Homework DUE Tomorrow 153 5 Key Ideas and Concept Check 1-3DUE Thursday Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 143
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with vestigial wings and cinnabar eyes Predict the
phenotypic ratio of the F2 individuals
3 The results of the cross from 2 show the following outcome Individuals of each phenotype are shown in the table Which of the following is the most likely explanation of the results a The two genes are located on two different chromosomes b The two genes are sex-linked c The two genes are located on mitochondrial DNA d The two genes are linked on an autosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
1 Build your diploid cell (an homologous pair for each chromosome)a Draw a big cell with a nucleus insideb DRAW homologous pairs of chromosomes
bull 1 big blue 1 big redbull 1 small blue 1 small red
ndash Add genes to your chromosomebull Write an H and an R on big blue and an h and an r on big redbull Write a T on small blue and a t on small red
2 Clone each chromosome (DNA Replication) (making sister chromatids)3 Nucleus breaks down (erase it)4 Homologous pairs form a tetrad crossing over may occur (note do not model
crossing over for now)5 Finish meiosis (see notes for help)6 Nucleus grows around chromosomes 4 cells made (gametes which have half
the number of chromosomes (haploids)7 Repeat Steps 1-6 this time at Step 4 include ONE crossover event
Recombination Modeling
When yoursquore confident on the process show Mr Jones
bull When yoursquore confident on the process show Mr Jones
bull In your notebookFigure 1510 Recombination p295At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid crossing over recombinant chromosome independent assortment Meiosis I Meiosis II
Recombination Modeling
Analysis
1 How does recombination increase the variety of gametes formed
2 Which types of gametes were more likely Gametes with recombinant chromosomes or ones without
3 Recombination is a random process How might it benefithurt the survival of an individualspecies
Recombination Modeling
Warm-UP
1 How could you calculate recombination frequency2 What would the recombination frequency tell you about the relative position of
genes on a chromosome3 Genes A B and C are on the same chromosome Testcrosses show that the
recombination frequency between A and B is 28 and between A and C is 12 Can you determine the linear order of these genes
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP What can we learn about inheritance from looking at a pedigree (use example of the Royal Family of Europe from the early 1900s)
Warm-UP In the following human pedigree squares represent males circles represent females and shaded symbols indicate individuals affected with a disorder One of the affected males from the third generation has a child with a female who is a carrier For the pedigree shown which of the following best expresses the probability that the couplersquos first son will be affected with the disorder
(A) 25 (B) 50 (C) 75 (D) 100
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Is a widowrsquos peak a dominant or recessive trait
Is a widowrsquos peak a dominant or recessive trait
Fig 14-UN5
George
Sandra Tom Sam
Arlene
Wilma Ann Michael
Carla
Daniel Alan Tina
Christopher
A heterozygous tall and a homozygous purple flowered plant is crossed with a short and white flowered plant Predict the offspring Assume independent assortment
1
P=purplep=whiteT=tallt=short
For a plant with the genotype WwXxYyZz what is the probability that the plant will produce a gamete with a haploid genotype of Wxyz Give your answer as a fraction or as a value between 0 and 1 to four decimal places
2
A completely-plated stickleback from a marine population was mated to a low-plated stickleback from a freshwater population The resulting F1 hybrids all displayed a completely plated phenotype When the F1 hybrids were allowed to interbreed the resulting F2 generation included completely plated offspring and low-plated offspring in an approximate 31 ratio Which of the following conclusions is best supported by the results of the breeding experiments
a Phenotypic variation in the F2 generation suggests that armor morphology is controlled by many alleles of a single gene
b The completely-plated phenotype is controlled by a dominant allele of a single gene
c Armor loss is an acquired characteristic that is affected by one or more environmental factors
d Patterns of armor plating in stickleback populations are regulated by sex-specific signals
3
If a man with type AB blood marries a woman with type O what blood types would you expect in their children What fraction would you expect of each type
4
IA= Type AIB= Type Bi= Type O
If a King marries a Queen that is a carrier of hemophilia (sex-linked recessive disease that is historically fatal before adulthood) what is the chance of the Kingdom having an heir to the kingrsquos throne assuming only one child is born
5
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
7 Gregor Mendelrsquos pioneering genetic experiments with pea plants occurred before the discovery of the structure and function of chromosomes Which of the following observations about inheritance in pea plants could be explained only after the discovery that genes may be linked on a chromosome
a Pea color and pea shape display independent inheritance patterns b Offspring of a given cross show all possible combinations of traits in
equal proportions c Most offspring of a given cross have a combination of traits that is
identical to that of either one parent or the other d Recessive phenotypes can skip a generation showing up only in the
parental and F 2 generations
8
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Based on the data in Table I which of the following best explains why there are no individuals with constricted pods in the F 1 generation a Inflated pod shape is dominant to constricted pod shape b The inflated-pod offspring in the F sub one generation are
homozygous c Constricted pod shape typically arises from a new mutation in the F 1
generation d The constricted-pod offspring are carriers for the inflated pod shape
allele
9
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table I the ratio of phenotypes in the offspring from the testcross with F 1 plants that had purple flowers and inflated pods suggests that the genes for flower color and pod shape are located a close together on the same autosome b on the X chromosome c on different chromosomes d on a mitochondrial chromosome
10
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Which of the following provides the best justification for an assumption that might have been used in the computer simulation (Table II) a The broad allele is recessive to the narrow allele because broad
leaves appear in every generation b The purple allele is dominant to the white allele because all the
offspring from the cross of purple-flowered and white-flowered plants had purple flowers
c The narrow allele is codominant with the purple allele because the purple-flower trait and the narrow-leaf trait segregate together
d The white allele is dominant to both the broad and narrow alleles because plants with either type of leaf shape can have white flowers
11
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table II the F 1 offspring of the cross between broad-leaved white-flowered plants with narrow-leaved purple-flowered plants have a phenotype that differs from that of either parent However many testcross offspring have the same phenotype as one of the two plants in the parental cross but relatively few testcross offspring have the same phenotype as the F 1 offspring Which of the following best explains the observation a Recombination between the leaf-shape and flower-color genes resulted in
chromosomes carrying a dominant allele of both genes b Recombination between the broad and narrow alleles of the leaf-shape gene resulted in
chromosomes carrying three different alleles at the same genetic locus c Independent assortment of homologous chromosomes resulted in the combinations of
alleles present in the parental generation d The computer model cannot capture the possible assortments of gametes when
multiple genes are considered
Warm-UP
A series of crosses is performed with fruit flies (Drosophila melanogaster) to examine inheritance of the genes vestigial (vg) and cinnabar (cn) The recessive vg allele causes small malformed wings called vestigial wings The recessive cn allele causes bright-red eyes called cinnabar eyes In the first cross a purebred female with wild-type wings and red eyes is mated with a purebred male with vestigial wings and cinnabar eyes 1 Predict the phenotypic ratio of the F1 individuals 2 In the second cross female F1 flies are mated with males with vestigial wings and cinnabar eyes Predict the
phenotypic ratio of the F2 individuals
3 The results of the cross from 2 show the following outcome Individuals of each phenotype are shown in the table Which of the following is the most likely explanation of the results a The two genes are located on two different chromosomes b The two genes are sex-linked c The two genes are located on mitochondrial DNA d The two genes are linked on an autosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
1 Build your diploid cell (an homologous pair for each chromosome)a Draw a big cell with a nucleus insideb DRAW homologous pairs of chromosomes
bull 1 big blue 1 big redbull 1 small blue 1 small red
ndash Add genes to your chromosomebull Write an H and an R on big blue and an h and an r on big redbull Write a T on small blue and a t on small red
2 Clone each chromosome (DNA Replication) (making sister chromatids)3 Nucleus breaks down (erase it)4 Homologous pairs form a tetrad crossing over may occur (note do not model
crossing over for now)5 Finish meiosis (see notes for help)6 Nucleus grows around chromosomes 4 cells made (gametes which have half
the number of chromosomes (haploids)7 Repeat Steps 1-6 this time at Step 4 include ONE crossover event
Recombination Modeling
When yoursquore confident on the process show Mr Jones
bull When yoursquore confident on the process show Mr Jones
bull In your notebookFigure 1510 Recombination p295At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid crossing over recombinant chromosome independent assortment Meiosis I Meiosis II
Recombination Modeling
Analysis
1 How does recombination increase the variety of gametes formed
2 Which types of gametes were more likely Gametes with recombinant chromosomes or ones without
3 Recombination is a random process How might it benefithurt the survival of an individualspecies
Recombination Modeling
Warm-UP
1 How could you calculate recombination frequency2 What would the recombination frequency tell you about the relative position of
genes on a chromosome3 Genes A B and C are on the same chromosome Testcrosses show that the
recombination frequency between A and B is 28 and between A and C is 12 Can you determine the linear order of these genes
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP What can we learn about inheritance from looking at a pedigree (use example of the Royal Family of Europe from the early 1900s)
Warm-UP In the following human pedigree squares represent males circles represent females and shaded symbols indicate individuals affected with a disorder One of the affected males from the third generation has a child with a female who is a carrier For the pedigree shown which of the following best expresses the probability that the couplersquos first son will be affected with the disorder
(A) 25 (B) 50 (C) 75 (D) 100
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Is a widowrsquos peak a dominant or recessive trait
Is a widowrsquos peak a dominant or recessive trait
Fig 14-UN5
George
Sandra Tom Sam
Arlene
Wilma Ann Michael
Carla
Daniel Alan Tina
Christopher
A heterozygous tall and a homozygous purple flowered plant is crossed with a short and white flowered plant Predict the offspring Assume independent assortment
1
P=purplep=whiteT=tallt=short
For a plant with the genotype WwXxYyZz what is the probability that the plant will produce a gamete with a haploid genotype of Wxyz Give your answer as a fraction or as a value between 0 and 1 to four decimal places
2
A completely-plated stickleback from a marine population was mated to a low-plated stickleback from a freshwater population The resulting F1 hybrids all displayed a completely plated phenotype When the F1 hybrids were allowed to interbreed the resulting F2 generation included completely plated offspring and low-plated offspring in an approximate 31 ratio Which of the following conclusions is best supported by the results of the breeding experiments
a Phenotypic variation in the F2 generation suggests that armor morphology is controlled by many alleles of a single gene
b The completely-plated phenotype is controlled by a dominant allele of a single gene
c Armor loss is an acquired characteristic that is affected by one or more environmental factors
d Patterns of armor plating in stickleback populations are regulated by sex-specific signals
3
If a man with type AB blood marries a woman with type O what blood types would you expect in their children What fraction would you expect of each type
4
IA= Type AIB= Type Bi= Type O
If a King marries a Queen that is a carrier of hemophilia (sex-linked recessive disease that is historically fatal before adulthood) what is the chance of the Kingdom having an heir to the kingrsquos throne assuming only one child is born
5
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
7 Gregor Mendelrsquos pioneering genetic experiments with pea plants occurred before the discovery of the structure and function of chromosomes Which of the following observations about inheritance in pea plants could be explained only after the discovery that genes may be linked on a chromosome
a Pea color and pea shape display independent inheritance patterns b Offspring of a given cross show all possible combinations of traits in
equal proportions c Most offspring of a given cross have a combination of traits that is
identical to that of either one parent or the other d Recessive phenotypes can skip a generation showing up only in the
parental and F 2 generations
8
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Based on the data in Table I which of the following best explains why there are no individuals with constricted pods in the F 1 generation a Inflated pod shape is dominant to constricted pod shape b The inflated-pod offspring in the F sub one generation are
homozygous c Constricted pod shape typically arises from a new mutation in the F 1
generation d The constricted-pod offspring are carriers for the inflated pod shape
allele
9
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table I the ratio of phenotypes in the offspring from the testcross with F 1 plants that had purple flowers and inflated pods suggests that the genes for flower color and pod shape are located a close together on the same autosome b on the X chromosome c on different chromosomes d on a mitochondrial chromosome
10
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Which of the following provides the best justification for an assumption that might have been used in the computer simulation (Table II) a The broad allele is recessive to the narrow allele because broad
leaves appear in every generation b The purple allele is dominant to the white allele because all the
offspring from the cross of purple-flowered and white-flowered plants had purple flowers
c The narrow allele is codominant with the purple allele because the purple-flower trait and the narrow-leaf trait segregate together
d The white allele is dominant to both the broad and narrow alleles because plants with either type of leaf shape can have white flowers
11
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table II the F 1 offspring of the cross between broad-leaved white-flowered plants with narrow-leaved purple-flowered plants have a phenotype that differs from that of either parent However many testcross offspring have the same phenotype as one of the two plants in the parental cross but relatively few testcross offspring have the same phenotype as the F 1 offspring Which of the following best explains the observation a Recombination between the leaf-shape and flower-color genes resulted in
chromosomes carrying a dominant allele of both genes b Recombination between the broad and narrow alleles of the leaf-shape gene resulted in
chromosomes carrying three different alleles at the same genetic locus c Independent assortment of homologous chromosomes resulted in the combinations of
alleles present in the parental generation d The computer model cannot capture the possible assortments of gametes when
multiple genes are considered
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
1 Build your diploid cell (an homologous pair for each chromosome)a Draw a big cell with a nucleus insideb DRAW homologous pairs of chromosomes
bull 1 big blue 1 big redbull 1 small blue 1 small red
ndash Add genes to your chromosomebull Write an H and an R on big blue and an h and an r on big redbull Write a T on small blue and a t on small red
2 Clone each chromosome (DNA Replication) (making sister chromatids)3 Nucleus breaks down (erase it)4 Homologous pairs form a tetrad crossing over may occur (note do not model
crossing over for now)5 Finish meiosis (see notes for help)6 Nucleus grows around chromosomes 4 cells made (gametes which have half
the number of chromosomes (haploids)7 Repeat Steps 1-6 this time at Step 4 include ONE crossover event
Recombination Modeling
When yoursquore confident on the process show Mr Jones
bull When yoursquore confident on the process show Mr Jones
bull In your notebookFigure 1510 Recombination p295At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid crossing over recombinant chromosome independent assortment Meiosis I Meiosis II
Recombination Modeling
Analysis
1 How does recombination increase the variety of gametes formed
2 Which types of gametes were more likely Gametes with recombinant chromosomes or ones without
3 Recombination is a random process How might it benefithurt the survival of an individualspecies
Recombination Modeling
Warm-UP
1 How could you calculate recombination frequency2 What would the recombination frequency tell you about the relative position of
genes on a chromosome3 Genes A B and C are on the same chromosome Testcrosses show that the
recombination frequency between A and B is 28 and between A and C is 12 Can you determine the linear order of these genes
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP What can we learn about inheritance from looking at a pedigree (use example of the Royal Family of Europe from the early 1900s)
Warm-UP In the following human pedigree squares represent males circles represent females and shaded symbols indicate individuals affected with a disorder One of the affected males from the third generation has a child with a female who is a carrier For the pedigree shown which of the following best expresses the probability that the couplersquos first son will be affected with the disorder
(A) 25 (B) 50 (C) 75 (D) 100
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Is a widowrsquos peak a dominant or recessive trait
Is a widowrsquos peak a dominant or recessive trait
Fig 14-UN5
George
Sandra Tom Sam
Arlene
Wilma Ann Michael
Carla
Daniel Alan Tina
Christopher
A heterozygous tall and a homozygous purple flowered plant is crossed with a short and white flowered plant Predict the offspring Assume independent assortment
1
P=purplep=whiteT=tallt=short
For a plant with the genotype WwXxYyZz what is the probability that the plant will produce a gamete with a haploid genotype of Wxyz Give your answer as a fraction or as a value between 0 and 1 to four decimal places
2
A completely-plated stickleback from a marine population was mated to a low-plated stickleback from a freshwater population The resulting F1 hybrids all displayed a completely plated phenotype When the F1 hybrids were allowed to interbreed the resulting F2 generation included completely plated offspring and low-plated offspring in an approximate 31 ratio Which of the following conclusions is best supported by the results of the breeding experiments
a Phenotypic variation in the F2 generation suggests that armor morphology is controlled by many alleles of a single gene
b The completely-plated phenotype is controlled by a dominant allele of a single gene
c Armor loss is an acquired characteristic that is affected by one or more environmental factors
d Patterns of armor plating in stickleback populations are regulated by sex-specific signals
3
If a man with type AB blood marries a woman with type O what blood types would you expect in their children What fraction would you expect of each type
4
IA= Type AIB= Type Bi= Type O
If a King marries a Queen that is a carrier of hemophilia (sex-linked recessive disease that is historically fatal before adulthood) what is the chance of the Kingdom having an heir to the kingrsquos throne assuming only one child is born
5
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
7 Gregor Mendelrsquos pioneering genetic experiments with pea plants occurred before the discovery of the structure and function of chromosomes Which of the following observations about inheritance in pea plants could be explained only after the discovery that genes may be linked on a chromosome
a Pea color and pea shape display independent inheritance patterns b Offspring of a given cross show all possible combinations of traits in
equal proportions c Most offspring of a given cross have a combination of traits that is
identical to that of either one parent or the other d Recessive phenotypes can skip a generation showing up only in the
parental and F 2 generations
8
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Based on the data in Table I which of the following best explains why there are no individuals with constricted pods in the F 1 generation a Inflated pod shape is dominant to constricted pod shape b The inflated-pod offspring in the F sub one generation are
homozygous c Constricted pod shape typically arises from a new mutation in the F 1
generation d The constricted-pod offspring are carriers for the inflated pod shape
allele
9
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table I the ratio of phenotypes in the offspring from the testcross with F 1 plants that had purple flowers and inflated pods suggests that the genes for flower color and pod shape are located a close together on the same autosome b on the X chromosome c on different chromosomes d on a mitochondrial chromosome
10
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Which of the following provides the best justification for an assumption that might have been used in the computer simulation (Table II) a The broad allele is recessive to the narrow allele because broad
leaves appear in every generation b The purple allele is dominant to the white allele because all the
offspring from the cross of purple-flowered and white-flowered plants had purple flowers
c The narrow allele is codominant with the purple allele because the purple-flower trait and the narrow-leaf trait segregate together
d The white allele is dominant to both the broad and narrow alleles because plants with either type of leaf shape can have white flowers
11
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table II the F 1 offspring of the cross between broad-leaved white-flowered plants with narrow-leaved purple-flowered plants have a phenotype that differs from that of either parent However many testcross offspring have the same phenotype as one of the two plants in the parental cross but relatively few testcross offspring have the same phenotype as the F 1 offspring Which of the following best explains the observation a Recombination between the leaf-shape and flower-color genes resulted in
chromosomes carrying a dominant allele of both genes b Recombination between the broad and narrow alleles of the leaf-shape gene resulted in
chromosomes carrying three different alleles at the same genetic locus c Independent assortment of homologous chromosomes resulted in the combinations of
alleles present in the parental generation d The computer model cannot capture the possible assortments of gametes when
multiple genes are considered
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
1 Build your diploid cell (an homologous pair for each chromosome)a Draw a big cell with a nucleus insideb DRAW homologous pairs of chromosomes
bull 1 big blue 1 big redbull 1 small blue 1 small red
ndash Add genes to your chromosomebull Write an H and an R on big blue and an h and an r on big redbull Write a T on small blue and a t on small red
2 Clone each chromosome (DNA Replication) (making sister chromatids)3 Nucleus breaks down (erase it)4 Homologous pairs form a tetrad crossing over may occur (note do not model
crossing over for now)5 Finish meiosis (see notes for help)6 Nucleus grows around chromosomes 4 cells made (gametes which have half
the number of chromosomes (haploids)7 Repeat Steps 1-6 this time at Step 4 include ONE crossover event
Recombination Modeling
When yoursquore confident on the process show Mr Jones
bull When yoursquore confident on the process show Mr Jones
bull In your notebookFigure 1510 Recombination p295At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid crossing over recombinant chromosome independent assortment Meiosis I Meiosis II
Recombination Modeling
Analysis
1 How does recombination increase the variety of gametes formed
2 Which types of gametes were more likely Gametes with recombinant chromosomes or ones without
3 Recombination is a random process How might it benefithurt the survival of an individualspecies
Recombination Modeling
Warm-UP
1 How could you calculate recombination frequency2 What would the recombination frequency tell you about the relative position of
genes on a chromosome3 Genes A B and C are on the same chromosome Testcrosses show that the
recombination frequency between A and B is 28 and between A and C is 12 Can you determine the linear order of these genes
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP What can we learn about inheritance from looking at a pedigree (use example of the Royal Family of Europe from the early 1900s)
Warm-UP In the following human pedigree squares represent males circles represent females and shaded symbols indicate individuals affected with a disorder One of the affected males from the third generation has a child with a female who is a carrier For the pedigree shown which of the following best expresses the probability that the couplersquos first son will be affected with the disorder
(A) 25 (B) 50 (C) 75 (D) 100
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Is a widowrsquos peak a dominant or recessive trait
Is a widowrsquos peak a dominant or recessive trait
Fig 14-UN5
George
Sandra Tom Sam
Arlene
Wilma Ann Michael
Carla
Daniel Alan Tina
Christopher
A heterozygous tall and a homozygous purple flowered plant is crossed with a short and white flowered plant Predict the offspring Assume independent assortment
1
P=purplep=whiteT=tallt=short
For a plant with the genotype WwXxYyZz what is the probability that the plant will produce a gamete with a haploid genotype of Wxyz Give your answer as a fraction or as a value between 0 and 1 to four decimal places
2
A completely-plated stickleback from a marine population was mated to a low-plated stickleback from a freshwater population The resulting F1 hybrids all displayed a completely plated phenotype When the F1 hybrids were allowed to interbreed the resulting F2 generation included completely plated offspring and low-plated offspring in an approximate 31 ratio Which of the following conclusions is best supported by the results of the breeding experiments
a Phenotypic variation in the F2 generation suggests that armor morphology is controlled by many alleles of a single gene
b The completely-plated phenotype is controlled by a dominant allele of a single gene
c Armor loss is an acquired characteristic that is affected by one or more environmental factors
d Patterns of armor plating in stickleback populations are regulated by sex-specific signals
3
If a man with type AB blood marries a woman with type O what blood types would you expect in their children What fraction would you expect of each type
4
IA= Type AIB= Type Bi= Type O
If a King marries a Queen that is a carrier of hemophilia (sex-linked recessive disease that is historically fatal before adulthood) what is the chance of the Kingdom having an heir to the kingrsquos throne assuming only one child is born
5
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
7 Gregor Mendelrsquos pioneering genetic experiments with pea plants occurred before the discovery of the structure and function of chromosomes Which of the following observations about inheritance in pea plants could be explained only after the discovery that genes may be linked on a chromosome
a Pea color and pea shape display independent inheritance patterns b Offspring of a given cross show all possible combinations of traits in
equal proportions c Most offspring of a given cross have a combination of traits that is
identical to that of either one parent or the other d Recessive phenotypes can skip a generation showing up only in the
parental and F 2 generations
8
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Based on the data in Table I which of the following best explains why there are no individuals with constricted pods in the F 1 generation a Inflated pod shape is dominant to constricted pod shape b The inflated-pod offspring in the F sub one generation are
homozygous c Constricted pod shape typically arises from a new mutation in the F 1
generation d The constricted-pod offspring are carriers for the inflated pod shape
allele
9
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table I the ratio of phenotypes in the offspring from the testcross with F 1 plants that had purple flowers and inflated pods suggests that the genes for flower color and pod shape are located a close together on the same autosome b on the X chromosome c on different chromosomes d on a mitochondrial chromosome
10
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Which of the following provides the best justification for an assumption that might have been used in the computer simulation (Table II) a The broad allele is recessive to the narrow allele because broad
leaves appear in every generation b The purple allele is dominant to the white allele because all the
offspring from the cross of purple-flowered and white-flowered plants had purple flowers
c The narrow allele is codominant with the purple allele because the purple-flower trait and the narrow-leaf trait segregate together
d The white allele is dominant to both the broad and narrow alleles because plants with either type of leaf shape can have white flowers
11
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table II the F 1 offspring of the cross between broad-leaved white-flowered plants with narrow-leaved purple-flowered plants have a phenotype that differs from that of either parent However many testcross offspring have the same phenotype as one of the two plants in the parental cross but relatively few testcross offspring have the same phenotype as the F 1 offspring Which of the following best explains the observation a Recombination between the leaf-shape and flower-color genes resulted in
chromosomes carrying a dominant allele of both genes b Recombination between the broad and narrow alleles of the leaf-shape gene resulted in
chromosomes carrying three different alleles at the same genetic locus c Independent assortment of homologous chromosomes resulted in the combinations of
alleles present in the parental generation d The computer model cannot capture the possible assortments of gametes when
multiple genes are considered
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
1 Build your diploid cell (an homologous pair for each chromosome)a Draw a big cell with a nucleus insideb DRAW homologous pairs of chromosomes
bull 1 big blue 1 big redbull 1 small blue 1 small red
ndash Add genes to your chromosomebull Write an H and an R on big blue and an h and an r on big redbull Write a T on small blue and a t on small red
2 Clone each chromosome (DNA Replication) (making sister chromatids)3 Nucleus breaks down (erase it)4 Homologous pairs form a tetrad crossing over may occur (note do not model
crossing over for now)5 Finish meiosis (see notes for help)6 Nucleus grows around chromosomes 4 cells made (gametes which have half
the number of chromosomes (haploids)7 Repeat Steps 1-6 this time at Step 4 include ONE crossover event
Recombination Modeling
When yoursquore confident on the process show Mr Jones
bull When yoursquore confident on the process show Mr Jones
bull In your notebookFigure 1510 Recombination p295At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid crossing over recombinant chromosome independent assortment Meiosis I Meiosis II
Recombination Modeling
Analysis
1 How does recombination increase the variety of gametes formed
2 Which types of gametes were more likely Gametes with recombinant chromosomes or ones without
3 Recombination is a random process How might it benefithurt the survival of an individualspecies
Recombination Modeling
Warm-UP
1 How could you calculate recombination frequency2 What would the recombination frequency tell you about the relative position of
genes on a chromosome3 Genes A B and C are on the same chromosome Testcrosses show that the
recombination frequency between A and B is 28 and between A and C is 12 Can you determine the linear order of these genes
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP What can we learn about inheritance from looking at a pedigree (use example of the Royal Family of Europe from the early 1900s)
Warm-UP In the following human pedigree squares represent males circles represent females and shaded symbols indicate individuals affected with a disorder One of the affected males from the third generation has a child with a female who is a carrier For the pedigree shown which of the following best expresses the probability that the couplersquos first son will be affected with the disorder
(A) 25 (B) 50 (C) 75 (D) 100
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Is a widowrsquos peak a dominant or recessive trait
Is a widowrsquos peak a dominant or recessive trait
Fig 14-UN5
George
Sandra Tom Sam
Arlene
Wilma Ann Michael
Carla
Daniel Alan Tina
Christopher
A heterozygous tall and a homozygous purple flowered plant is crossed with a short and white flowered plant Predict the offspring Assume independent assortment
1
P=purplep=whiteT=tallt=short
For a plant with the genotype WwXxYyZz what is the probability that the plant will produce a gamete with a haploid genotype of Wxyz Give your answer as a fraction or as a value between 0 and 1 to four decimal places
2
A completely-plated stickleback from a marine population was mated to a low-plated stickleback from a freshwater population The resulting F1 hybrids all displayed a completely plated phenotype When the F1 hybrids were allowed to interbreed the resulting F2 generation included completely plated offspring and low-plated offspring in an approximate 31 ratio Which of the following conclusions is best supported by the results of the breeding experiments
a Phenotypic variation in the F2 generation suggests that armor morphology is controlled by many alleles of a single gene
b The completely-plated phenotype is controlled by a dominant allele of a single gene
c Armor loss is an acquired characteristic that is affected by one or more environmental factors
d Patterns of armor plating in stickleback populations are regulated by sex-specific signals
3
If a man with type AB blood marries a woman with type O what blood types would you expect in their children What fraction would you expect of each type
4
IA= Type AIB= Type Bi= Type O
If a King marries a Queen that is a carrier of hemophilia (sex-linked recessive disease that is historically fatal before adulthood) what is the chance of the Kingdom having an heir to the kingrsquos throne assuming only one child is born
5
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
7 Gregor Mendelrsquos pioneering genetic experiments with pea plants occurred before the discovery of the structure and function of chromosomes Which of the following observations about inheritance in pea plants could be explained only after the discovery that genes may be linked on a chromosome
a Pea color and pea shape display independent inheritance patterns b Offspring of a given cross show all possible combinations of traits in
equal proportions c Most offspring of a given cross have a combination of traits that is
identical to that of either one parent or the other d Recessive phenotypes can skip a generation showing up only in the
parental and F 2 generations
8
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Based on the data in Table I which of the following best explains why there are no individuals with constricted pods in the F 1 generation a Inflated pod shape is dominant to constricted pod shape b The inflated-pod offspring in the F sub one generation are
homozygous c Constricted pod shape typically arises from a new mutation in the F 1
generation d The constricted-pod offspring are carriers for the inflated pod shape
allele
9
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table I the ratio of phenotypes in the offspring from the testcross with F 1 plants that had purple flowers and inflated pods suggests that the genes for flower color and pod shape are located a close together on the same autosome b on the X chromosome c on different chromosomes d on a mitochondrial chromosome
10
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Which of the following provides the best justification for an assumption that might have been used in the computer simulation (Table II) a The broad allele is recessive to the narrow allele because broad
leaves appear in every generation b The purple allele is dominant to the white allele because all the
offspring from the cross of purple-flowered and white-flowered plants had purple flowers
c The narrow allele is codominant with the purple allele because the purple-flower trait and the narrow-leaf trait segregate together
d The white allele is dominant to both the broad and narrow alleles because plants with either type of leaf shape can have white flowers
11
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table II the F 1 offspring of the cross between broad-leaved white-flowered plants with narrow-leaved purple-flowered plants have a phenotype that differs from that of either parent However many testcross offspring have the same phenotype as one of the two plants in the parental cross but relatively few testcross offspring have the same phenotype as the F 1 offspring Which of the following best explains the observation a Recombination between the leaf-shape and flower-color genes resulted in
chromosomes carrying a dominant allele of both genes b Recombination between the broad and narrow alleles of the leaf-shape gene resulted in
chromosomes carrying three different alleles at the same genetic locus c Independent assortment of homologous chromosomes resulted in the combinations of
alleles present in the parental generation d The computer model cannot capture the possible assortments of gametes when
multiple genes are considered
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
1 Build your diploid cell (an homologous pair for each chromosome)a Draw a big cell with a nucleus insideb DRAW homologous pairs of chromosomes
bull 1 big blue 1 big redbull 1 small blue 1 small red
ndash Add genes to your chromosomebull Write an H and an R on big blue and an h and an r on big redbull Write a T on small blue and a t on small red
2 Clone each chromosome (DNA Replication) (making sister chromatids)3 Nucleus breaks down (erase it)4 Homologous pairs form a tetrad crossing over may occur (note do not model
crossing over for now)5 Finish meiosis (see notes for help)6 Nucleus grows around chromosomes 4 cells made (gametes which have half
the number of chromosomes (haploids)7 Repeat Steps 1-6 this time at Step 4 include ONE crossover event
Recombination Modeling
When yoursquore confident on the process show Mr Jones
bull When yoursquore confident on the process show Mr Jones
bull In your notebookFigure 1510 Recombination p295At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid crossing over recombinant chromosome independent assortment Meiosis I Meiosis II
Recombination Modeling
Analysis
1 How does recombination increase the variety of gametes formed
2 Which types of gametes were more likely Gametes with recombinant chromosomes or ones without
3 Recombination is a random process How might it benefithurt the survival of an individualspecies
Recombination Modeling
Warm-UP
1 How could you calculate recombination frequency2 What would the recombination frequency tell you about the relative position of
genes on a chromosome3 Genes A B and C are on the same chromosome Testcrosses show that the
recombination frequency between A and B is 28 and between A and C is 12 Can you determine the linear order of these genes
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP What can we learn about inheritance from looking at a pedigree (use example of the Royal Family of Europe from the early 1900s)
Warm-UP In the following human pedigree squares represent males circles represent females and shaded symbols indicate individuals affected with a disorder One of the affected males from the third generation has a child with a female who is a carrier For the pedigree shown which of the following best expresses the probability that the couplersquos first son will be affected with the disorder
(A) 25 (B) 50 (C) 75 (D) 100
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Is a widowrsquos peak a dominant or recessive trait
Is a widowrsquos peak a dominant or recessive trait
Fig 14-UN5
George
Sandra Tom Sam
Arlene
Wilma Ann Michael
Carla
Daniel Alan Tina
Christopher
A heterozygous tall and a homozygous purple flowered plant is crossed with a short and white flowered plant Predict the offspring Assume independent assortment
1
P=purplep=whiteT=tallt=short
For a plant with the genotype WwXxYyZz what is the probability that the plant will produce a gamete with a haploid genotype of Wxyz Give your answer as a fraction or as a value between 0 and 1 to four decimal places
2
A completely-plated stickleback from a marine population was mated to a low-plated stickleback from a freshwater population The resulting F1 hybrids all displayed a completely plated phenotype When the F1 hybrids were allowed to interbreed the resulting F2 generation included completely plated offspring and low-plated offspring in an approximate 31 ratio Which of the following conclusions is best supported by the results of the breeding experiments
a Phenotypic variation in the F2 generation suggests that armor morphology is controlled by many alleles of a single gene
b The completely-plated phenotype is controlled by a dominant allele of a single gene
c Armor loss is an acquired characteristic that is affected by one or more environmental factors
d Patterns of armor plating in stickleback populations are regulated by sex-specific signals
3
If a man with type AB blood marries a woman with type O what blood types would you expect in their children What fraction would you expect of each type
4
IA= Type AIB= Type Bi= Type O
If a King marries a Queen that is a carrier of hemophilia (sex-linked recessive disease that is historically fatal before adulthood) what is the chance of the Kingdom having an heir to the kingrsquos throne assuming only one child is born
5
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
7 Gregor Mendelrsquos pioneering genetic experiments with pea plants occurred before the discovery of the structure and function of chromosomes Which of the following observations about inheritance in pea plants could be explained only after the discovery that genes may be linked on a chromosome
a Pea color and pea shape display independent inheritance patterns b Offspring of a given cross show all possible combinations of traits in
equal proportions c Most offspring of a given cross have a combination of traits that is
identical to that of either one parent or the other d Recessive phenotypes can skip a generation showing up only in the
parental and F 2 generations
8
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Based on the data in Table I which of the following best explains why there are no individuals with constricted pods in the F 1 generation a Inflated pod shape is dominant to constricted pod shape b The inflated-pod offspring in the F sub one generation are
homozygous c Constricted pod shape typically arises from a new mutation in the F 1
generation d The constricted-pod offspring are carriers for the inflated pod shape
allele
9
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table I the ratio of phenotypes in the offspring from the testcross with F 1 plants that had purple flowers and inflated pods suggests that the genes for flower color and pod shape are located a close together on the same autosome b on the X chromosome c on different chromosomes d on a mitochondrial chromosome
10
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Which of the following provides the best justification for an assumption that might have been used in the computer simulation (Table II) a The broad allele is recessive to the narrow allele because broad
leaves appear in every generation b The purple allele is dominant to the white allele because all the
offspring from the cross of purple-flowered and white-flowered plants had purple flowers
c The narrow allele is codominant with the purple allele because the purple-flower trait and the narrow-leaf trait segregate together
d The white allele is dominant to both the broad and narrow alleles because plants with either type of leaf shape can have white flowers
11
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table II the F 1 offspring of the cross between broad-leaved white-flowered plants with narrow-leaved purple-flowered plants have a phenotype that differs from that of either parent However many testcross offspring have the same phenotype as one of the two plants in the parental cross but relatively few testcross offspring have the same phenotype as the F 1 offspring Which of the following best explains the observation a Recombination between the leaf-shape and flower-color genes resulted in
chromosomes carrying a dominant allele of both genes b Recombination between the broad and narrow alleles of the leaf-shape gene resulted in
chromosomes carrying three different alleles at the same genetic locus c Independent assortment of homologous chromosomes resulted in the combinations of
alleles present in the parental generation d The computer model cannot capture the possible assortments of gametes when
multiple genes are considered
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
1 Build your diploid cell (an homologous pair for each chromosome)a Draw a big cell with a nucleus insideb DRAW homologous pairs of chromosomes
bull 1 big blue 1 big redbull 1 small blue 1 small red
ndash Add genes to your chromosomebull Write an H and an R on big blue and an h and an r on big redbull Write a T on small blue and a t on small red
2 Clone each chromosome (DNA Replication) (making sister chromatids)3 Nucleus breaks down (erase it)4 Homologous pairs form a tetrad crossing over may occur (note do not model
crossing over for now)5 Finish meiosis (see notes for help)6 Nucleus grows around chromosomes 4 cells made (gametes which have half
the number of chromosomes (haploids)7 Repeat Steps 1-6 this time at Step 4 include ONE crossover event
Recombination Modeling
When yoursquore confident on the process show Mr Jones
bull When yoursquore confident on the process show Mr Jones
bull In your notebookFigure 1510 Recombination p295At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid crossing over recombinant chromosome independent assortment Meiosis I Meiosis II
Recombination Modeling
Analysis
1 How does recombination increase the variety of gametes formed
2 Which types of gametes were more likely Gametes with recombinant chromosomes or ones without
3 Recombination is a random process How might it benefithurt the survival of an individualspecies
Recombination Modeling
Warm-UP
1 How could you calculate recombination frequency2 What would the recombination frequency tell you about the relative position of
genes on a chromosome3 Genes A B and C are on the same chromosome Testcrosses show that the
recombination frequency between A and B is 28 and between A and C is 12 Can you determine the linear order of these genes
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP What can we learn about inheritance from looking at a pedigree (use example of the Royal Family of Europe from the early 1900s)
Warm-UP In the following human pedigree squares represent males circles represent females and shaded symbols indicate individuals affected with a disorder One of the affected males from the third generation has a child with a female who is a carrier For the pedigree shown which of the following best expresses the probability that the couplersquos first son will be affected with the disorder
(A) 25 (B) 50 (C) 75 (D) 100
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Is a widowrsquos peak a dominant or recessive trait
Is a widowrsquos peak a dominant or recessive trait
Fig 14-UN5
George
Sandra Tom Sam
Arlene
Wilma Ann Michael
Carla
Daniel Alan Tina
Christopher
A heterozygous tall and a homozygous purple flowered plant is crossed with a short and white flowered plant Predict the offspring Assume independent assortment
1
P=purplep=whiteT=tallt=short
For a plant with the genotype WwXxYyZz what is the probability that the plant will produce a gamete with a haploid genotype of Wxyz Give your answer as a fraction or as a value between 0 and 1 to four decimal places
2
A completely-plated stickleback from a marine population was mated to a low-plated stickleback from a freshwater population The resulting F1 hybrids all displayed a completely plated phenotype When the F1 hybrids were allowed to interbreed the resulting F2 generation included completely plated offspring and low-plated offspring in an approximate 31 ratio Which of the following conclusions is best supported by the results of the breeding experiments
a Phenotypic variation in the F2 generation suggests that armor morphology is controlled by many alleles of a single gene
b The completely-plated phenotype is controlled by a dominant allele of a single gene
c Armor loss is an acquired characteristic that is affected by one or more environmental factors
d Patterns of armor plating in stickleback populations are regulated by sex-specific signals
3
If a man with type AB blood marries a woman with type O what blood types would you expect in their children What fraction would you expect of each type
4
IA= Type AIB= Type Bi= Type O
If a King marries a Queen that is a carrier of hemophilia (sex-linked recessive disease that is historically fatal before adulthood) what is the chance of the Kingdom having an heir to the kingrsquos throne assuming only one child is born
5
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
7 Gregor Mendelrsquos pioneering genetic experiments with pea plants occurred before the discovery of the structure and function of chromosomes Which of the following observations about inheritance in pea plants could be explained only after the discovery that genes may be linked on a chromosome
a Pea color and pea shape display independent inheritance patterns b Offspring of a given cross show all possible combinations of traits in
equal proportions c Most offspring of a given cross have a combination of traits that is
identical to that of either one parent or the other d Recessive phenotypes can skip a generation showing up only in the
parental and F 2 generations
8
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Based on the data in Table I which of the following best explains why there are no individuals with constricted pods in the F 1 generation a Inflated pod shape is dominant to constricted pod shape b The inflated-pod offspring in the F sub one generation are
homozygous c Constricted pod shape typically arises from a new mutation in the F 1
generation d The constricted-pod offspring are carriers for the inflated pod shape
allele
9
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table I the ratio of phenotypes in the offspring from the testcross with F 1 plants that had purple flowers and inflated pods suggests that the genes for flower color and pod shape are located a close together on the same autosome b on the X chromosome c on different chromosomes d on a mitochondrial chromosome
10
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Which of the following provides the best justification for an assumption that might have been used in the computer simulation (Table II) a The broad allele is recessive to the narrow allele because broad
leaves appear in every generation b The purple allele is dominant to the white allele because all the
offspring from the cross of purple-flowered and white-flowered plants had purple flowers
c The narrow allele is codominant with the purple allele because the purple-flower trait and the narrow-leaf trait segregate together
d The white allele is dominant to both the broad and narrow alleles because plants with either type of leaf shape can have white flowers
11
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table II the F 1 offspring of the cross between broad-leaved white-flowered plants with narrow-leaved purple-flowered plants have a phenotype that differs from that of either parent However many testcross offspring have the same phenotype as one of the two plants in the parental cross but relatively few testcross offspring have the same phenotype as the F 1 offspring Which of the following best explains the observation a Recombination between the leaf-shape and flower-color genes resulted in
chromosomes carrying a dominant allele of both genes b Recombination between the broad and narrow alleles of the leaf-shape gene resulted in
chromosomes carrying three different alleles at the same genetic locus c Independent assortment of homologous chromosomes resulted in the combinations of
alleles present in the parental generation d The computer model cannot capture the possible assortments of gametes when
multiple genes are considered
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
1 Build your diploid cell (an homologous pair for each chromosome)a Draw a big cell with a nucleus insideb DRAW homologous pairs of chromosomes
bull 1 big blue 1 big redbull 1 small blue 1 small red
ndash Add genes to your chromosomebull Write an H and an R on big blue and an h and an r on big redbull Write a T on small blue and a t on small red
2 Clone each chromosome (DNA Replication) (making sister chromatids)3 Nucleus breaks down (erase it)4 Homologous pairs form a tetrad crossing over may occur (note do not model
crossing over for now)5 Finish meiosis (see notes for help)6 Nucleus grows around chromosomes 4 cells made (gametes which have half
the number of chromosomes (haploids)7 Repeat Steps 1-6 this time at Step 4 include ONE crossover event
Recombination Modeling
When yoursquore confident on the process show Mr Jones
bull When yoursquore confident on the process show Mr Jones
bull In your notebookFigure 1510 Recombination p295At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid crossing over recombinant chromosome independent assortment Meiosis I Meiosis II
Recombination Modeling
Analysis
1 How does recombination increase the variety of gametes formed
2 Which types of gametes were more likely Gametes with recombinant chromosomes or ones without
3 Recombination is a random process How might it benefithurt the survival of an individualspecies
Recombination Modeling
Warm-UP
1 How could you calculate recombination frequency2 What would the recombination frequency tell you about the relative position of
genes on a chromosome3 Genes A B and C are on the same chromosome Testcrosses show that the
recombination frequency between A and B is 28 and between A and C is 12 Can you determine the linear order of these genes
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP What can we learn about inheritance from looking at a pedigree (use example of the Royal Family of Europe from the early 1900s)
Warm-UP In the following human pedigree squares represent males circles represent females and shaded symbols indicate individuals affected with a disorder One of the affected males from the third generation has a child with a female who is a carrier For the pedigree shown which of the following best expresses the probability that the couplersquos first son will be affected with the disorder
(A) 25 (B) 50 (C) 75 (D) 100
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Is a widowrsquos peak a dominant or recessive trait
Is a widowrsquos peak a dominant or recessive trait
Fig 14-UN5
George
Sandra Tom Sam
Arlene
Wilma Ann Michael
Carla
Daniel Alan Tina
Christopher
A heterozygous tall and a homozygous purple flowered plant is crossed with a short and white flowered plant Predict the offspring Assume independent assortment
1
P=purplep=whiteT=tallt=short
For a plant with the genotype WwXxYyZz what is the probability that the plant will produce a gamete with a haploid genotype of Wxyz Give your answer as a fraction or as a value between 0 and 1 to four decimal places
2
A completely-plated stickleback from a marine population was mated to a low-plated stickleback from a freshwater population The resulting F1 hybrids all displayed a completely plated phenotype When the F1 hybrids were allowed to interbreed the resulting F2 generation included completely plated offspring and low-plated offspring in an approximate 31 ratio Which of the following conclusions is best supported by the results of the breeding experiments
a Phenotypic variation in the F2 generation suggests that armor morphology is controlled by many alleles of a single gene
b The completely-plated phenotype is controlled by a dominant allele of a single gene
c Armor loss is an acquired characteristic that is affected by one or more environmental factors
d Patterns of armor plating in stickleback populations are regulated by sex-specific signals
3
If a man with type AB blood marries a woman with type O what blood types would you expect in their children What fraction would you expect of each type
4
IA= Type AIB= Type Bi= Type O
If a King marries a Queen that is a carrier of hemophilia (sex-linked recessive disease that is historically fatal before adulthood) what is the chance of the Kingdom having an heir to the kingrsquos throne assuming only one child is born
5
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
7 Gregor Mendelrsquos pioneering genetic experiments with pea plants occurred before the discovery of the structure and function of chromosomes Which of the following observations about inheritance in pea plants could be explained only after the discovery that genes may be linked on a chromosome
a Pea color and pea shape display independent inheritance patterns b Offspring of a given cross show all possible combinations of traits in
equal proportions c Most offspring of a given cross have a combination of traits that is
identical to that of either one parent or the other d Recessive phenotypes can skip a generation showing up only in the
parental and F 2 generations
8
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Based on the data in Table I which of the following best explains why there are no individuals with constricted pods in the F 1 generation a Inflated pod shape is dominant to constricted pod shape b The inflated-pod offspring in the F sub one generation are
homozygous c Constricted pod shape typically arises from a new mutation in the F 1
generation d The constricted-pod offspring are carriers for the inflated pod shape
allele
9
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table I the ratio of phenotypes in the offspring from the testcross with F 1 plants that had purple flowers and inflated pods suggests that the genes for flower color and pod shape are located a close together on the same autosome b on the X chromosome c on different chromosomes d on a mitochondrial chromosome
10
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Which of the following provides the best justification for an assumption that might have been used in the computer simulation (Table II) a The broad allele is recessive to the narrow allele because broad
leaves appear in every generation b The purple allele is dominant to the white allele because all the
offspring from the cross of purple-flowered and white-flowered plants had purple flowers
c The narrow allele is codominant with the purple allele because the purple-flower trait and the narrow-leaf trait segregate together
d The white allele is dominant to both the broad and narrow alleles because plants with either type of leaf shape can have white flowers
11
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table II the F 1 offspring of the cross between broad-leaved white-flowered plants with narrow-leaved purple-flowered plants have a phenotype that differs from that of either parent However many testcross offspring have the same phenotype as one of the two plants in the parental cross but relatively few testcross offspring have the same phenotype as the F 1 offspring Which of the following best explains the observation a Recombination between the leaf-shape and flower-color genes resulted in
chromosomes carrying a dominant allele of both genes b Recombination between the broad and narrow alleles of the leaf-shape gene resulted in
chromosomes carrying three different alleles at the same genetic locus c Independent assortment of homologous chromosomes resulted in the combinations of
alleles present in the parental generation d The computer model cannot capture the possible assortments of gametes when
multiple genes are considered
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Morganbull experiments with fruit flies bull Interested in how linkage (when
characters are on the same chromosome) affects inheritance of two characters
bull crossed flies that differed in traits of body color and wing size
Conclusionsbull body color and wing size are usually
inherited together in specific combinations (parental phenotypes)
bull these genes sometimes assort independentlybull they must linked on the same
chromosomebull but the linkage is incomplete
cross-over sometimes creates recombinant chromosomes
1 Build your diploid cell (an homologous pair for each chromosome)a Draw a big cell with a nucleus insideb DRAW homologous pairs of chromosomes
bull 1 big blue 1 big redbull 1 small blue 1 small red
ndash Add genes to your chromosomebull Write an H and an R on big blue and an h and an r on big redbull Write a T on small blue and a t on small red
2 Clone each chromosome (DNA Replication) (making sister chromatids)3 Nucleus breaks down (erase it)4 Homologous pairs form a tetrad crossing over may occur (note do not model
crossing over for now)5 Finish meiosis (see notes for help)6 Nucleus grows around chromosomes 4 cells made (gametes which have half
the number of chromosomes (haploids)7 Repeat Steps 1-6 this time at Step 4 include ONE crossover event
Recombination Modeling
When yoursquore confident on the process show Mr Jones
bull When yoursquore confident on the process show Mr Jones
bull In your notebookFigure 1510 Recombination p295At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid crossing over recombinant chromosome independent assortment Meiosis I Meiosis II
Recombination Modeling
Analysis
1 How does recombination increase the variety of gametes formed
2 Which types of gametes were more likely Gametes with recombinant chromosomes or ones without
3 Recombination is a random process How might it benefithurt the survival of an individualspecies
Recombination Modeling
Warm-UP
1 How could you calculate recombination frequency2 What would the recombination frequency tell you about the relative position of
genes on a chromosome3 Genes A B and C are on the same chromosome Testcrosses show that the
recombination frequency between A and B is 28 and between A and C is 12 Can you determine the linear order of these genes
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP What can we learn about inheritance from looking at a pedigree (use example of the Royal Family of Europe from the early 1900s)
Warm-UP In the following human pedigree squares represent males circles represent females and shaded symbols indicate individuals affected with a disorder One of the affected males from the third generation has a child with a female who is a carrier For the pedigree shown which of the following best expresses the probability that the couplersquos first son will be affected with the disorder
(A) 25 (B) 50 (C) 75 (D) 100
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Is a widowrsquos peak a dominant or recessive trait
Is a widowrsquos peak a dominant or recessive trait
Fig 14-UN5
George
Sandra Tom Sam
Arlene
Wilma Ann Michael
Carla
Daniel Alan Tina
Christopher
A heterozygous tall and a homozygous purple flowered plant is crossed with a short and white flowered plant Predict the offspring Assume independent assortment
1
P=purplep=whiteT=tallt=short
For a plant with the genotype WwXxYyZz what is the probability that the plant will produce a gamete with a haploid genotype of Wxyz Give your answer as a fraction or as a value between 0 and 1 to four decimal places
2
A completely-plated stickleback from a marine population was mated to a low-plated stickleback from a freshwater population The resulting F1 hybrids all displayed a completely plated phenotype When the F1 hybrids were allowed to interbreed the resulting F2 generation included completely plated offspring and low-plated offspring in an approximate 31 ratio Which of the following conclusions is best supported by the results of the breeding experiments
a Phenotypic variation in the F2 generation suggests that armor morphology is controlled by many alleles of a single gene
b The completely-plated phenotype is controlled by a dominant allele of a single gene
c Armor loss is an acquired characteristic that is affected by one or more environmental factors
d Patterns of armor plating in stickleback populations are regulated by sex-specific signals
3
If a man with type AB blood marries a woman with type O what blood types would you expect in their children What fraction would you expect of each type
4
IA= Type AIB= Type Bi= Type O
If a King marries a Queen that is a carrier of hemophilia (sex-linked recessive disease that is historically fatal before adulthood) what is the chance of the Kingdom having an heir to the kingrsquos throne assuming only one child is born
5
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
7 Gregor Mendelrsquos pioneering genetic experiments with pea plants occurred before the discovery of the structure and function of chromosomes Which of the following observations about inheritance in pea plants could be explained only after the discovery that genes may be linked on a chromosome
a Pea color and pea shape display independent inheritance patterns b Offspring of a given cross show all possible combinations of traits in
equal proportions c Most offspring of a given cross have a combination of traits that is
identical to that of either one parent or the other d Recessive phenotypes can skip a generation showing up only in the
parental and F 2 generations
8
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Based on the data in Table I which of the following best explains why there are no individuals with constricted pods in the F 1 generation a Inflated pod shape is dominant to constricted pod shape b The inflated-pod offspring in the F sub one generation are
homozygous c Constricted pod shape typically arises from a new mutation in the F 1
generation d The constricted-pod offspring are carriers for the inflated pod shape
allele
9
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table I the ratio of phenotypes in the offspring from the testcross with F 1 plants that had purple flowers and inflated pods suggests that the genes for flower color and pod shape are located a close together on the same autosome b on the X chromosome c on different chromosomes d on a mitochondrial chromosome
10
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Which of the following provides the best justification for an assumption that might have been used in the computer simulation (Table II) a The broad allele is recessive to the narrow allele because broad
leaves appear in every generation b The purple allele is dominant to the white allele because all the
offspring from the cross of purple-flowered and white-flowered plants had purple flowers
c The narrow allele is codominant with the purple allele because the purple-flower trait and the narrow-leaf trait segregate together
d The white allele is dominant to both the broad and narrow alleles because plants with either type of leaf shape can have white flowers
11
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table II the F 1 offspring of the cross between broad-leaved white-flowered plants with narrow-leaved purple-flowered plants have a phenotype that differs from that of either parent However many testcross offspring have the same phenotype as one of the two plants in the parental cross but relatively few testcross offspring have the same phenotype as the F 1 offspring Which of the following best explains the observation a Recombination between the leaf-shape and flower-color genes resulted in
chromosomes carrying a dominant allele of both genes b Recombination between the broad and narrow alleles of the leaf-shape gene resulted in
chromosomes carrying three different alleles at the same genetic locus c Independent assortment of homologous chromosomes resulted in the combinations of
alleles present in the parental generation d The computer model cannot capture the possible assortments of gametes when
multiple genes are considered
1 Build your diploid cell (an homologous pair for each chromosome)a Draw a big cell with a nucleus insideb DRAW homologous pairs of chromosomes
bull 1 big blue 1 big redbull 1 small blue 1 small red
ndash Add genes to your chromosomebull Write an H and an R on big blue and an h and an r on big redbull Write a T on small blue and a t on small red
2 Clone each chromosome (DNA Replication) (making sister chromatids)3 Nucleus breaks down (erase it)4 Homologous pairs form a tetrad crossing over may occur (note do not model
crossing over for now)5 Finish meiosis (see notes for help)6 Nucleus grows around chromosomes 4 cells made (gametes which have half
the number of chromosomes (haploids)7 Repeat Steps 1-6 this time at Step 4 include ONE crossover event
Recombination Modeling
When yoursquore confident on the process show Mr Jones
bull When yoursquore confident on the process show Mr Jones
bull In your notebookFigure 1510 Recombination p295At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid crossing over recombinant chromosome independent assortment Meiosis I Meiosis II
Recombination Modeling
Analysis
1 How does recombination increase the variety of gametes formed
2 Which types of gametes were more likely Gametes with recombinant chromosomes or ones without
3 Recombination is a random process How might it benefithurt the survival of an individualspecies
Recombination Modeling
Warm-UP
1 How could you calculate recombination frequency2 What would the recombination frequency tell you about the relative position of
genes on a chromosome3 Genes A B and C are on the same chromosome Testcrosses show that the
recombination frequency between A and B is 28 and between A and C is 12 Can you determine the linear order of these genes
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP What can we learn about inheritance from looking at a pedigree (use example of the Royal Family of Europe from the early 1900s)
Warm-UP In the following human pedigree squares represent males circles represent females and shaded symbols indicate individuals affected with a disorder One of the affected males from the third generation has a child with a female who is a carrier For the pedigree shown which of the following best expresses the probability that the couplersquos first son will be affected with the disorder
(A) 25 (B) 50 (C) 75 (D) 100
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Is a widowrsquos peak a dominant or recessive trait
Is a widowrsquos peak a dominant or recessive trait
Fig 14-UN5
George
Sandra Tom Sam
Arlene
Wilma Ann Michael
Carla
Daniel Alan Tina
Christopher
A heterozygous tall and a homozygous purple flowered plant is crossed with a short and white flowered plant Predict the offspring Assume independent assortment
1
P=purplep=whiteT=tallt=short
For a plant with the genotype WwXxYyZz what is the probability that the plant will produce a gamete with a haploid genotype of Wxyz Give your answer as a fraction or as a value between 0 and 1 to four decimal places
2
A completely-plated stickleback from a marine population was mated to a low-plated stickleback from a freshwater population The resulting F1 hybrids all displayed a completely plated phenotype When the F1 hybrids were allowed to interbreed the resulting F2 generation included completely plated offspring and low-plated offspring in an approximate 31 ratio Which of the following conclusions is best supported by the results of the breeding experiments
a Phenotypic variation in the F2 generation suggests that armor morphology is controlled by many alleles of a single gene
b The completely-plated phenotype is controlled by a dominant allele of a single gene
c Armor loss is an acquired characteristic that is affected by one or more environmental factors
d Patterns of armor plating in stickleback populations are regulated by sex-specific signals
3
If a man with type AB blood marries a woman with type O what blood types would you expect in their children What fraction would you expect of each type
4
IA= Type AIB= Type Bi= Type O
If a King marries a Queen that is a carrier of hemophilia (sex-linked recessive disease that is historically fatal before adulthood) what is the chance of the Kingdom having an heir to the kingrsquos throne assuming only one child is born
5
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
7 Gregor Mendelrsquos pioneering genetic experiments with pea plants occurred before the discovery of the structure and function of chromosomes Which of the following observations about inheritance in pea plants could be explained only after the discovery that genes may be linked on a chromosome
a Pea color and pea shape display independent inheritance patterns b Offspring of a given cross show all possible combinations of traits in
equal proportions c Most offspring of a given cross have a combination of traits that is
identical to that of either one parent or the other d Recessive phenotypes can skip a generation showing up only in the
parental and F 2 generations
8
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Based on the data in Table I which of the following best explains why there are no individuals with constricted pods in the F 1 generation a Inflated pod shape is dominant to constricted pod shape b The inflated-pod offspring in the F sub one generation are
homozygous c Constricted pod shape typically arises from a new mutation in the F 1
generation d The constricted-pod offspring are carriers for the inflated pod shape
allele
9
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table I the ratio of phenotypes in the offspring from the testcross with F 1 plants that had purple flowers and inflated pods suggests that the genes for flower color and pod shape are located a close together on the same autosome b on the X chromosome c on different chromosomes d on a mitochondrial chromosome
10
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Which of the following provides the best justification for an assumption that might have been used in the computer simulation (Table II) a The broad allele is recessive to the narrow allele because broad
leaves appear in every generation b The purple allele is dominant to the white allele because all the
offspring from the cross of purple-flowered and white-flowered plants had purple flowers
c The narrow allele is codominant with the purple allele because the purple-flower trait and the narrow-leaf trait segregate together
d The white allele is dominant to both the broad and narrow alleles because plants with either type of leaf shape can have white flowers
11
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table II the F 1 offspring of the cross between broad-leaved white-flowered plants with narrow-leaved purple-flowered plants have a phenotype that differs from that of either parent However many testcross offspring have the same phenotype as one of the two plants in the parental cross but relatively few testcross offspring have the same phenotype as the F 1 offspring Which of the following best explains the observation a Recombination between the leaf-shape and flower-color genes resulted in
chromosomes carrying a dominant allele of both genes b Recombination between the broad and narrow alleles of the leaf-shape gene resulted in
chromosomes carrying three different alleles at the same genetic locus c Independent assortment of homologous chromosomes resulted in the combinations of
alleles present in the parental generation d The computer model cannot capture the possible assortments of gametes when
multiple genes are considered
bull When yoursquore confident on the process show Mr Jones
bull In your notebookFigure 1510 Recombination p295At each stage describe what is happening in 1-2 sentences DO NOT COPY
DRAW with LABELS cell membrane nucleus chromosome DNA replication cytokinesis sister chromatid crossing over recombinant chromosome independent assortment Meiosis I Meiosis II
Recombination Modeling
Analysis
1 How does recombination increase the variety of gametes formed
2 Which types of gametes were more likely Gametes with recombinant chromosomes or ones without
3 Recombination is a random process How might it benefithurt the survival of an individualspecies
Recombination Modeling
Warm-UP
1 How could you calculate recombination frequency2 What would the recombination frequency tell you about the relative position of
genes on a chromosome3 Genes A B and C are on the same chromosome Testcrosses show that the
recombination frequency between A and B is 28 and between A and C is 12 Can you determine the linear order of these genes
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP What can we learn about inheritance from looking at a pedigree (use example of the Royal Family of Europe from the early 1900s)
Warm-UP In the following human pedigree squares represent males circles represent females and shaded symbols indicate individuals affected with a disorder One of the affected males from the third generation has a child with a female who is a carrier For the pedigree shown which of the following best expresses the probability that the couplersquos first son will be affected with the disorder
(A) 25 (B) 50 (C) 75 (D) 100
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Is a widowrsquos peak a dominant or recessive trait
Is a widowrsquos peak a dominant or recessive trait
Fig 14-UN5
George
Sandra Tom Sam
Arlene
Wilma Ann Michael
Carla
Daniel Alan Tina
Christopher
A heterozygous tall and a homozygous purple flowered plant is crossed with a short and white flowered plant Predict the offspring Assume independent assortment
1
P=purplep=whiteT=tallt=short
For a plant with the genotype WwXxYyZz what is the probability that the plant will produce a gamete with a haploid genotype of Wxyz Give your answer as a fraction or as a value between 0 and 1 to four decimal places
2
A completely-plated stickleback from a marine population was mated to a low-plated stickleback from a freshwater population The resulting F1 hybrids all displayed a completely plated phenotype When the F1 hybrids were allowed to interbreed the resulting F2 generation included completely plated offspring and low-plated offspring in an approximate 31 ratio Which of the following conclusions is best supported by the results of the breeding experiments
a Phenotypic variation in the F2 generation suggests that armor morphology is controlled by many alleles of a single gene
b The completely-plated phenotype is controlled by a dominant allele of a single gene
c Armor loss is an acquired characteristic that is affected by one or more environmental factors
d Patterns of armor plating in stickleback populations are regulated by sex-specific signals
3
If a man with type AB blood marries a woman with type O what blood types would you expect in their children What fraction would you expect of each type
4
IA= Type AIB= Type Bi= Type O
If a King marries a Queen that is a carrier of hemophilia (sex-linked recessive disease that is historically fatal before adulthood) what is the chance of the Kingdom having an heir to the kingrsquos throne assuming only one child is born
5
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
7 Gregor Mendelrsquos pioneering genetic experiments with pea plants occurred before the discovery of the structure and function of chromosomes Which of the following observations about inheritance in pea plants could be explained only after the discovery that genes may be linked on a chromosome
a Pea color and pea shape display independent inheritance patterns b Offspring of a given cross show all possible combinations of traits in
equal proportions c Most offspring of a given cross have a combination of traits that is
identical to that of either one parent or the other d Recessive phenotypes can skip a generation showing up only in the
parental and F 2 generations
8
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Based on the data in Table I which of the following best explains why there are no individuals with constricted pods in the F 1 generation a Inflated pod shape is dominant to constricted pod shape b The inflated-pod offspring in the F sub one generation are
homozygous c Constricted pod shape typically arises from a new mutation in the F 1
generation d The constricted-pod offspring are carriers for the inflated pod shape
allele
9
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table I the ratio of phenotypes in the offspring from the testcross with F 1 plants that had purple flowers and inflated pods suggests that the genes for flower color and pod shape are located a close together on the same autosome b on the X chromosome c on different chromosomes d on a mitochondrial chromosome
10
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Which of the following provides the best justification for an assumption that might have been used in the computer simulation (Table II) a The broad allele is recessive to the narrow allele because broad
leaves appear in every generation b The purple allele is dominant to the white allele because all the
offspring from the cross of purple-flowered and white-flowered plants had purple flowers
c The narrow allele is codominant with the purple allele because the purple-flower trait and the narrow-leaf trait segregate together
d The white allele is dominant to both the broad and narrow alleles because plants with either type of leaf shape can have white flowers
11
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table II the F 1 offspring of the cross between broad-leaved white-flowered plants with narrow-leaved purple-flowered plants have a phenotype that differs from that of either parent However many testcross offspring have the same phenotype as one of the two plants in the parental cross but relatively few testcross offspring have the same phenotype as the F 1 offspring Which of the following best explains the observation a Recombination between the leaf-shape and flower-color genes resulted in
chromosomes carrying a dominant allele of both genes b Recombination between the broad and narrow alleles of the leaf-shape gene resulted in
chromosomes carrying three different alleles at the same genetic locus c Independent assortment of homologous chromosomes resulted in the combinations of
alleles present in the parental generation d The computer model cannot capture the possible assortments of gametes when
multiple genes are considered
Analysis
1 How does recombination increase the variety of gametes formed
2 Which types of gametes were more likely Gametes with recombinant chromosomes or ones without
3 Recombination is a random process How might it benefithurt the survival of an individualspecies
Recombination Modeling
Warm-UP
1 How could you calculate recombination frequency2 What would the recombination frequency tell you about the relative position of
genes on a chromosome3 Genes A B and C are on the same chromosome Testcrosses show that the
recombination frequency between A and B is 28 and between A and C is 12 Can you determine the linear order of these genes
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP What can we learn about inheritance from looking at a pedigree (use example of the Royal Family of Europe from the early 1900s)
Warm-UP In the following human pedigree squares represent males circles represent females and shaded symbols indicate individuals affected with a disorder One of the affected males from the third generation has a child with a female who is a carrier For the pedigree shown which of the following best expresses the probability that the couplersquos first son will be affected with the disorder
(A) 25 (B) 50 (C) 75 (D) 100
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Is a widowrsquos peak a dominant or recessive trait
Is a widowrsquos peak a dominant or recessive trait
Fig 14-UN5
George
Sandra Tom Sam
Arlene
Wilma Ann Michael
Carla
Daniel Alan Tina
Christopher
A heterozygous tall and a homozygous purple flowered plant is crossed with a short and white flowered plant Predict the offspring Assume independent assortment
1
P=purplep=whiteT=tallt=short
For a plant with the genotype WwXxYyZz what is the probability that the plant will produce a gamete with a haploid genotype of Wxyz Give your answer as a fraction or as a value between 0 and 1 to four decimal places
2
A completely-plated stickleback from a marine population was mated to a low-plated stickleback from a freshwater population The resulting F1 hybrids all displayed a completely plated phenotype When the F1 hybrids were allowed to interbreed the resulting F2 generation included completely plated offspring and low-plated offspring in an approximate 31 ratio Which of the following conclusions is best supported by the results of the breeding experiments
a Phenotypic variation in the F2 generation suggests that armor morphology is controlled by many alleles of a single gene
b The completely-plated phenotype is controlled by a dominant allele of a single gene
c Armor loss is an acquired characteristic that is affected by one or more environmental factors
d Patterns of armor plating in stickleback populations are regulated by sex-specific signals
3
If a man with type AB blood marries a woman with type O what blood types would you expect in their children What fraction would you expect of each type
4
IA= Type AIB= Type Bi= Type O
If a King marries a Queen that is a carrier of hemophilia (sex-linked recessive disease that is historically fatal before adulthood) what is the chance of the Kingdom having an heir to the kingrsquos throne assuming only one child is born
5
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
7 Gregor Mendelrsquos pioneering genetic experiments with pea plants occurred before the discovery of the structure and function of chromosomes Which of the following observations about inheritance in pea plants could be explained only after the discovery that genes may be linked on a chromosome
a Pea color and pea shape display independent inheritance patterns b Offspring of a given cross show all possible combinations of traits in
equal proportions c Most offspring of a given cross have a combination of traits that is
identical to that of either one parent or the other d Recessive phenotypes can skip a generation showing up only in the
parental and F 2 generations
8
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Based on the data in Table I which of the following best explains why there are no individuals with constricted pods in the F 1 generation a Inflated pod shape is dominant to constricted pod shape b The inflated-pod offspring in the F sub one generation are
homozygous c Constricted pod shape typically arises from a new mutation in the F 1
generation d The constricted-pod offspring are carriers for the inflated pod shape
allele
9
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table I the ratio of phenotypes in the offspring from the testcross with F 1 plants that had purple flowers and inflated pods suggests that the genes for flower color and pod shape are located a close together on the same autosome b on the X chromosome c on different chromosomes d on a mitochondrial chromosome
10
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Which of the following provides the best justification for an assumption that might have been used in the computer simulation (Table II) a The broad allele is recessive to the narrow allele because broad
leaves appear in every generation b The purple allele is dominant to the white allele because all the
offspring from the cross of purple-flowered and white-flowered plants had purple flowers
c The narrow allele is codominant with the purple allele because the purple-flower trait and the narrow-leaf trait segregate together
d The white allele is dominant to both the broad and narrow alleles because plants with either type of leaf shape can have white flowers
11
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table II the F 1 offspring of the cross between broad-leaved white-flowered plants with narrow-leaved purple-flowered plants have a phenotype that differs from that of either parent However many testcross offspring have the same phenotype as one of the two plants in the parental cross but relatively few testcross offspring have the same phenotype as the F 1 offspring Which of the following best explains the observation a Recombination between the leaf-shape and flower-color genes resulted in
chromosomes carrying a dominant allele of both genes b Recombination between the broad and narrow alleles of the leaf-shape gene resulted in
chromosomes carrying three different alleles at the same genetic locus c Independent assortment of homologous chromosomes resulted in the combinations of
alleles present in the parental generation d The computer model cannot capture the possible assortments of gametes when
multiple genes are considered
Warm-UP
1 How could you calculate recombination frequency2 What would the recombination frequency tell you about the relative position of
genes on a chromosome3 Genes A B and C are on the same chromosome Testcrosses show that the
recombination frequency between A and B is 28 and between A and C is 12 Can you determine the linear order of these genes
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP What can we learn about inheritance from looking at a pedigree (use example of the Royal Family of Europe from the early 1900s)
Warm-UP In the following human pedigree squares represent males circles represent females and shaded symbols indicate individuals affected with a disorder One of the affected males from the third generation has a child with a female who is a carrier For the pedigree shown which of the following best expresses the probability that the couplersquos first son will be affected with the disorder
(A) 25 (B) 50 (C) 75 (D) 100
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Is a widowrsquos peak a dominant or recessive trait
Is a widowrsquos peak a dominant or recessive trait
Fig 14-UN5
George
Sandra Tom Sam
Arlene
Wilma Ann Michael
Carla
Daniel Alan Tina
Christopher
A heterozygous tall and a homozygous purple flowered plant is crossed with a short and white flowered plant Predict the offspring Assume independent assortment
1
P=purplep=whiteT=tallt=short
For a plant with the genotype WwXxYyZz what is the probability that the plant will produce a gamete with a haploid genotype of Wxyz Give your answer as a fraction or as a value between 0 and 1 to four decimal places
2
A completely-plated stickleback from a marine population was mated to a low-plated stickleback from a freshwater population The resulting F1 hybrids all displayed a completely plated phenotype When the F1 hybrids were allowed to interbreed the resulting F2 generation included completely plated offspring and low-plated offspring in an approximate 31 ratio Which of the following conclusions is best supported by the results of the breeding experiments
a Phenotypic variation in the F2 generation suggests that armor morphology is controlled by many alleles of a single gene
b The completely-plated phenotype is controlled by a dominant allele of a single gene
c Armor loss is an acquired characteristic that is affected by one or more environmental factors
d Patterns of armor plating in stickleback populations are regulated by sex-specific signals
3
If a man with type AB blood marries a woman with type O what blood types would you expect in their children What fraction would you expect of each type
4
IA= Type AIB= Type Bi= Type O
If a King marries a Queen that is a carrier of hemophilia (sex-linked recessive disease that is historically fatal before adulthood) what is the chance of the Kingdom having an heir to the kingrsquos throne assuming only one child is born
5
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
7 Gregor Mendelrsquos pioneering genetic experiments with pea plants occurred before the discovery of the structure and function of chromosomes Which of the following observations about inheritance in pea plants could be explained only after the discovery that genes may be linked on a chromosome
a Pea color and pea shape display independent inheritance patterns b Offspring of a given cross show all possible combinations of traits in
equal proportions c Most offspring of a given cross have a combination of traits that is
identical to that of either one parent or the other d Recessive phenotypes can skip a generation showing up only in the
parental and F 2 generations
8
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Based on the data in Table I which of the following best explains why there are no individuals with constricted pods in the F 1 generation a Inflated pod shape is dominant to constricted pod shape b The inflated-pod offspring in the F sub one generation are
homozygous c Constricted pod shape typically arises from a new mutation in the F 1
generation d The constricted-pod offspring are carriers for the inflated pod shape
allele
9
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table I the ratio of phenotypes in the offspring from the testcross with F 1 plants that had purple flowers and inflated pods suggests that the genes for flower color and pod shape are located a close together on the same autosome b on the X chromosome c on different chromosomes d on a mitochondrial chromosome
10
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Which of the following provides the best justification for an assumption that might have been used in the computer simulation (Table II) a The broad allele is recessive to the narrow allele because broad
leaves appear in every generation b The purple allele is dominant to the white allele because all the
offspring from the cross of purple-flowered and white-flowered plants had purple flowers
c The narrow allele is codominant with the purple allele because the purple-flower trait and the narrow-leaf trait segregate together
d The white allele is dominant to both the broad and narrow alleles because plants with either type of leaf shape can have white flowers
11
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table II the F 1 offspring of the cross between broad-leaved white-flowered plants with narrow-leaved purple-flowered plants have a phenotype that differs from that of either parent However many testcross offspring have the same phenotype as one of the two plants in the parental cross but relatively few testcross offspring have the same phenotype as the F 1 offspring Which of the following best explains the observation a Recombination between the leaf-shape and flower-color genes resulted in
chromosomes carrying a dominant allele of both genes b Recombination between the broad and narrow alleles of the leaf-shape gene resulted in
chromosomes carrying three different alleles at the same genetic locus c Independent assortment of homologous chromosomes resulted in the combinations of
alleles present in the parental generation d The computer model cannot capture the possible assortments of gametes when
multiple genes are considered
Homework DUE Tomorrow Linked and Unlinked GenesDUE Tonight Monohybrid Crosses to turnitincomDUE Friday Dihybrid Crosses to turnitincom
DUE Now 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP Talk about your Concept Check with your table team Do you have agreement Do you have questions
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP What can we learn about inheritance from looking at a pedigree (use example of the Royal Family of Europe from the early 1900s)
Warm-UP In the following human pedigree squares represent males circles represent females and shaded symbols indicate individuals affected with a disorder One of the affected males from the third generation has a child with a female who is a carrier For the pedigree shown which of the following best expresses the probability that the couplersquos first son will be affected with the disorder
(A) 25 (B) 50 (C) 75 (D) 100
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Is a widowrsquos peak a dominant or recessive trait
Is a widowrsquos peak a dominant or recessive trait
Fig 14-UN5
George
Sandra Tom Sam
Arlene
Wilma Ann Michael
Carla
Daniel Alan Tina
Christopher
A heterozygous tall and a homozygous purple flowered plant is crossed with a short and white flowered plant Predict the offspring Assume independent assortment
1
P=purplep=whiteT=tallt=short
For a plant with the genotype WwXxYyZz what is the probability that the plant will produce a gamete with a haploid genotype of Wxyz Give your answer as a fraction or as a value between 0 and 1 to four decimal places
2
A completely-plated stickleback from a marine population was mated to a low-plated stickleback from a freshwater population The resulting F1 hybrids all displayed a completely plated phenotype When the F1 hybrids were allowed to interbreed the resulting F2 generation included completely plated offspring and low-plated offspring in an approximate 31 ratio Which of the following conclusions is best supported by the results of the breeding experiments
a Phenotypic variation in the F2 generation suggests that armor morphology is controlled by many alleles of a single gene
b The completely-plated phenotype is controlled by a dominant allele of a single gene
c Armor loss is an acquired characteristic that is affected by one or more environmental factors
d Patterns of armor plating in stickleback populations are regulated by sex-specific signals
3
If a man with type AB blood marries a woman with type O what blood types would you expect in their children What fraction would you expect of each type
4
IA= Type AIB= Type Bi= Type O
If a King marries a Queen that is a carrier of hemophilia (sex-linked recessive disease that is historically fatal before adulthood) what is the chance of the Kingdom having an heir to the kingrsquos throne assuming only one child is born
5
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
7 Gregor Mendelrsquos pioneering genetic experiments with pea plants occurred before the discovery of the structure and function of chromosomes Which of the following observations about inheritance in pea plants could be explained only after the discovery that genes may be linked on a chromosome
a Pea color and pea shape display independent inheritance patterns b Offspring of a given cross show all possible combinations of traits in
equal proportions c Most offspring of a given cross have a combination of traits that is
identical to that of either one parent or the other d Recessive phenotypes can skip a generation showing up only in the
parental and F 2 generations
8
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Based on the data in Table I which of the following best explains why there are no individuals with constricted pods in the F 1 generation a Inflated pod shape is dominant to constricted pod shape b The inflated-pod offspring in the F sub one generation are
homozygous c Constricted pod shape typically arises from a new mutation in the F 1
generation d The constricted-pod offspring are carriers for the inflated pod shape
allele
9
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table I the ratio of phenotypes in the offspring from the testcross with F 1 plants that had purple flowers and inflated pods suggests that the genes for flower color and pod shape are located a close together on the same autosome b on the X chromosome c on different chromosomes d on a mitochondrial chromosome
10
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Which of the following provides the best justification for an assumption that might have been used in the computer simulation (Table II) a The broad allele is recessive to the narrow allele because broad
leaves appear in every generation b The purple allele is dominant to the white allele because all the
offspring from the cross of purple-flowered and white-flowered plants had purple flowers
c The narrow allele is codominant with the purple allele because the purple-flower trait and the narrow-leaf trait segregate together
d The white allele is dominant to both the broad and narrow alleles because plants with either type of leaf shape can have white flowers
11
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table II the F 1 offspring of the cross between broad-leaved white-flowered plants with narrow-leaved purple-flowered plants have a phenotype that differs from that of either parent However many testcross offspring have the same phenotype as one of the two plants in the parental cross but relatively few testcross offspring have the same phenotype as the F 1 offspring Which of the following best explains the observation a Recombination between the leaf-shape and flower-color genes resulted in
chromosomes carrying a dominant allele of both genes b Recombination between the broad and narrow alleles of the leaf-shape gene resulted in
chromosomes carrying three different alleles at the same genetic locus c Independent assortment of homologous chromosomes resulted in the combinations of
alleles present in the parental generation d The computer model cannot capture the possible assortments of gametes when
multiple genes are considered
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP What can we learn about inheritance from looking at a pedigree (use example of the Royal Family of Europe from the early 1900s)
Warm-UP In the following human pedigree squares represent males circles represent females and shaded symbols indicate individuals affected with a disorder One of the affected males from the third generation has a child with a female who is a carrier For the pedigree shown which of the following best expresses the probability that the couplersquos first son will be affected with the disorder
(A) 25 (B) 50 (C) 75 (D) 100
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Is a widowrsquos peak a dominant or recessive trait
Is a widowrsquos peak a dominant or recessive trait
Fig 14-UN5
George
Sandra Tom Sam
Arlene
Wilma Ann Michael
Carla
Daniel Alan Tina
Christopher
A heterozygous tall and a homozygous purple flowered plant is crossed with a short and white flowered plant Predict the offspring Assume independent assortment
1
P=purplep=whiteT=tallt=short
For a plant with the genotype WwXxYyZz what is the probability that the plant will produce a gamete with a haploid genotype of Wxyz Give your answer as a fraction or as a value between 0 and 1 to four decimal places
2
A completely-plated stickleback from a marine population was mated to a low-plated stickleback from a freshwater population The resulting F1 hybrids all displayed a completely plated phenotype When the F1 hybrids were allowed to interbreed the resulting F2 generation included completely plated offspring and low-plated offspring in an approximate 31 ratio Which of the following conclusions is best supported by the results of the breeding experiments
a Phenotypic variation in the F2 generation suggests that armor morphology is controlled by many alleles of a single gene
b The completely-plated phenotype is controlled by a dominant allele of a single gene
c Armor loss is an acquired characteristic that is affected by one or more environmental factors
d Patterns of armor plating in stickleback populations are regulated by sex-specific signals
3
If a man with type AB blood marries a woman with type O what blood types would you expect in their children What fraction would you expect of each type
4
IA= Type AIB= Type Bi= Type O
If a King marries a Queen that is a carrier of hemophilia (sex-linked recessive disease that is historically fatal before adulthood) what is the chance of the Kingdom having an heir to the kingrsquos throne assuming only one child is born
5
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
7 Gregor Mendelrsquos pioneering genetic experiments with pea plants occurred before the discovery of the structure and function of chromosomes Which of the following observations about inheritance in pea plants could be explained only after the discovery that genes may be linked on a chromosome
a Pea color and pea shape display independent inheritance patterns b Offspring of a given cross show all possible combinations of traits in
equal proportions c Most offspring of a given cross have a combination of traits that is
identical to that of either one parent or the other d Recessive phenotypes can skip a generation showing up only in the
parental and F 2 generations
8
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Based on the data in Table I which of the following best explains why there are no individuals with constricted pods in the F 1 generation a Inflated pod shape is dominant to constricted pod shape b The inflated-pod offspring in the F sub one generation are
homozygous c Constricted pod shape typically arises from a new mutation in the F 1
generation d The constricted-pod offspring are carriers for the inflated pod shape
allele
9
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table I the ratio of phenotypes in the offspring from the testcross with F 1 plants that had purple flowers and inflated pods suggests that the genes for flower color and pod shape are located a close together on the same autosome b on the X chromosome c on different chromosomes d on a mitochondrial chromosome
10
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Which of the following provides the best justification for an assumption that might have been used in the computer simulation (Table II) a The broad allele is recessive to the narrow allele because broad
leaves appear in every generation b The purple allele is dominant to the white allele because all the
offspring from the cross of purple-flowered and white-flowered plants had purple flowers
c The narrow allele is codominant with the purple allele because the purple-flower trait and the narrow-leaf trait segregate together
d The white allele is dominant to both the broad and narrow alleles because plants with either type of leaf shape can have white flowers
11
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table II the F 1 offspring of the cross between broad-leaved white-flowered plants with narrow-leaved purple-flowered plants have a phenotype that differs from that of either parent However many testcross offspring have the same phenotype as one of the two plants in the parental cross but relatively few testcross offspring have the same phenotype as the F 1 offspring Which of the following best explains the observation a Recombination between the leaf-shape and flower-color genes resulted in
chromosomes carrying a dominant allele of both genes b Recombination between the broad and narrow alleles of the leaf-shape gene resulted in
chromosomes carrying three different alleles at the same genetic locus c Independent assortment of homologous chromosomes resulted in the combinations of
alleles present in the parental generation d The computer model cannot capture the possible assortments of gametes when
multiple genes are considered
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Sturtevant Genetic Mapping
bull linkage map an ordered list of the genetic loci along a particular chromosome based on recombination frequencies
bull map unitbull one map unit represents a 1
recombination frequencybull indicate relative distance and order
not precise locations of genesbull 50 frequency of recombination is
observed for any two genes on different chromosomes
bull the farther apart two genes are the higher the probability a crossover will occur between them and therefore the higher the recombination frequency
bull genes that are far apart on the same chromosome can have a recombination frequency near 50 Such genes are physically linked but genetically unlinked and behave as if found on different chromosomes
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP What can we learn about inheritance from looking at a pedigree (use example of the Royal Family of Europe from the early 1900s)
Warm-UP In the following human pedigree squares represent males circles represent females and shaded symbols indicate individuals affected with a disorder One of the affected males from the third generation has a child with a female who is a carrier For the pedigree shown which of the following best expresses the probability that the couplersquos first son will be affected with the disorder
(A) 25 (B) 50 (C) 75 (D) 100
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Is a widowrsquos peak a dominant or recessive trait
Is a widowrsquos peak a dominant or recessive trait
Fig 14-UN5
George
Sandra Tom Sam
Arlene
Wilma Ann Michael
Carla
Daniel Alan Tina
Christopher
A heterozygous tall and a homozygous purple flowered plant is crossed with a short and white flowered plant Predict the offspring Assume independent assortment
1
P=purplep=whiteT=tallt=short
For a plant with the genotype WwXxYyZz what is the probability that the plant will produce a gamete with a haploid genotype of Wxyz Give your answer as a fraction or as a value between 0 and 1 to four decimal places
2
A completely-plated stickleback from a marine population was mated to a low-plated stickleback from a freshwater population The resulting F1 hybrids all displayed a completely plated phenotype When the F1 hybrids were allowed to interbreed the resulting F2 generation included completely plated offspring and low-plated offspring in an approximate 31 ratio Which of the following conclusions is best supported by the results of the breeding experiments
a Phenotypic variation in the F2 generation suggests that armor morphology is controlled by many alleles of a single gene
b The completely-plated phenotype is controlled by a dominant allele of a single gene
c Armor loss is an acquired characteristic that is affected by one or more environmental factors
d Patterns of armor plating in stickleback populations are regulated by sex-specific signals
3
If a man with type AB blood marries a woman with type O what blood types would you expect in their children What fraction would you expect of each type
4
IA= Type AIB= Type Bi= Type O
If a King marries a Queen that is a carrier of hemophilia (sex-linked recessive disease that is historically fatal before adulthood) what is the chance of the Kingdom having an heir to the kingrsquos throne assuming only one child is born
5
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
7 Gregor Mendelrsquos pioneering genetic experiments with pea plants occurred before the discovery of the structure and function of chromosomes Which of the following observations about inheritance in pea plants could be explained only after the discovery that genes may be linked on a chromosome
a Pea color and pea shape display independent inheritance patterns b Offspring of a given cross show all possible combinations of traits in
equal proportions c Most offspring of a given cross have a combination of traits that is
identical to that of either one parent or the other d Recessive phenotypes can skip a generation showing up only in the
parental and F 2 generations
8
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Based on the data in Table I which of the following best explains why there are no individuals with constricted pods in the F 1 generation a Inflated pod shape is dominant to constricted pod shape b The inflated-pod offspring in the F sub one generation are
homozygous c Constricted pod shape typically arises from a new mutation in the F 1
generation d The constricted-pod offspring are carriers for the inflated pod shape
allele
9
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table I the ratio of phenotypes in the offspring from the testcross with F 1 plants that had purple flowers and inflated pods suggests that the genes for flower color and pod shape are located a close together on the same autosome b on the X chromosome c on different chromosomes d on a mitochondrial chromosome
10
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Which of the following provides the best justification for an assumption that might have been used in the computer simulation (Table II) a The broad allele is recessive to the narrow allele because broad
leaves appear in every generation b The purple allele is dominant to the white allele because all the
offspring from the cross of purple-flowered and white-flowered plants had purple flowers
c The narrow allele is codominant with the purple allele because the purple-flower trait and the narrow-leaf trait segregate together
d The white allele is dominant to both the broad and narrow alleles because plants with either type of leaf shape can have white flowers
11
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table II the F 1 offspring of the cross between broad-leaved white-flowered plants with narrow-leaved purple-flowered plants have a phenotype that differs from that of either parent However many testcross offspring have the same phenotype as one of the two plants in the parental cross but relatively few testcross offspring have the same phenotype as the F 1 offspring Which of the following best explains the observation a Recombination between the leaf-shape and flower-color genes resulted in
chromosomes carrying a dominant allele of both genes b Recombination between the broad and narrow alleles of the leaf-shape gene resulted in
chromosomes carrying three different alleles at the same genetic locus c Independent assortment of homologous chromosomes resulted in the combinations of
alleles present in the parental generation d The computer model cannot capture the possible assortments of gametes when
multiple genes are considered
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP What can we learn about inheritance from looking at a pedigree (use example of the Royal Family of Europe from the early 1900s)
Warm-UP In the following human pedigree squares represent males circles represent females and shaded symbols indicate individuals affected with a disorder One of the affected males from the third generation has a child with a female who is a carrier For the pedigree shown which of the following best expresses the probability that the couplersquos first son will be affected with the disorder
(A) 25 (B) 50 (C) 75 (D) 100
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Is a widowrsquos peak a dominant or recessive trait
Is a widowrsquos peak a dominant or recessive trait
Fig 14-UN5
George
Sandra Tom Sam
Arlene
Wilma Ann Michael
Carla
Daniel Alan Tina
Christopher
A heterozygous tall and a homozygous purple flowered plant is crossed with a short and white flowered plant Predict the offspring Assume independent assortment
1
P=purplep=whiteT=tallt=short
For a plant with the genotype WwXxYyZz what is the probability that the plant will produce a gamete with a haploid genotype of Wxyz Give your answer as a fraction or as a value between 0 and 1 to four decimal places
2
A completely-plated stickleback from a marine population was mated to a low-plated stickleback from a freshwater population The resulting F1 hybrids all displayed a completely plated phenotype When the F1 hybrids were allowed to interbreed the resulting F2 generation included completely plated offspring and low-plated offspring in an approximate 31 ratio Which of the following conclusions is best supported by the results of the breeding experiments
a Phenotypic variation in the F2 generation suggests that armor morphology is controlled by many alleles of a single gene
b The completely-plated phenotype is controlled by a dominant allele of a single gene
c Armor loss is an acquired characteristic that is affected by one or more environmental factors
d Patterns of armor plating in stickleback populations are regulated by sex-specific signals
3
If a man with type AB blood marries a woman with type O what blood types would you expect in their children What fraction would you expect of each type
4
IA= Type AIB= Type Bi= Type O
If a King marries a Queen that is a carrier of hemophilia (sex-linked recessive disease that is historically fatal before adulthood) what is the chance of the Kingdom having an heir to the kingrsquos throne assuming only one child is born
5
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
7 Gregor Mendelrsquos pioneering genetic experiments with pea plants occurred before the discovery of the structure and function of chromosomes Which of the following observations about inheritance in pea plants could be explained only after the discovery that genes may be linked on a chromosome
a Pea color and pea shape display independent inheritance patterns b Offspring of a given cross show all possible combinations of traits in
equal proportions c Most offspring of a given cross have a combination of traits that is
identical to that of either one parent or the other d Recessive phenotypes can skip a generation showing up only in the
parental and F 2 generations
8
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Based on the data in Table I which of the following best explains why there are no individuals with constricted pods in the F 1 generation a Inflated pod shape is dominant to constricted pod shape b The inflated-pod offspring in the F sub one generation are
homozygous c Constricted pod shape typically arises from a new mutation in the F 1
generation d The constricted-pod offspring are carriers for the inflated pod shape
allele
9
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table I the ratio of phenotypes in the offspring from the testcross with F 1 plants that had purple flowers and inflated pods suggests that the genes for flower color and pod shape are located a close together on the same autosome b on the X chromosome c on different chromosomes d on a mitochondrial chromosome
10
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Which of the following provides the best justification for an assumption that might have been used in the computer simulation (Table II) a The broad allele is recessive to the narrow allele because broad
leaves appear in every generation b The purple allele is dominant to the white allele because all the
offspring from the cross of purple-flowered and white-flowered plants had purple flowers
c The narrow allele is codominant with the purple allele because the purple-flower trait and the narrow-leaf trait segregate together
d The white allele is dominant to both the broad and narrow alleles because plants with either type of leaf shape can have white flowers
11
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table II the F 1 offspring of the cross between broad-leaved white-flowered plants with narrow-leaved purple-flowered plants have a phenotype that differs from that of either parent However many testcross offspring have the same phenotype as one of the two plants in the parental cross but relatively few testcross offspring have the same phenotype as the F 1 offspring Which of the following best explains the observation a Recombination between the leaf-shape and flower-color genes resulted in
chromosomes carrying a dominant allele of both genes b Recombination between the broad and narrow alleles of the leaf-shape gene resulted in
chromosomes carrying three different alleles at the same genetic locus c Independent assortment of homologous chromosomes resulted in the combinations of
alleles present in the parental generation d The computer model cannot capture the possible assortments of gametes when
multiple genes are considered
The chromosomal basis of inheritance provides an understanding of the pattern of transmission of genes from
parent to offspring Abnormal Chromosome Numberbull In nondisjunction pairs of homologous
chromosomes do not separate normally during meiosis
bull As a result one gamete receives two of the same type of chromosome and another gamete receives no copy
bull Aneuploidy results from the fertilization of gametes in which nondisjunction occurred
bull Offspring with this condition have an abnormal number of a particular chromosome
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP What can we learn about inheritance from looking at a pedigree (use example of the Royal Family of Europe from the early 1900s)
Warm-UP In the following human pedigree squares represent males circles represent females and shaded symbols indicate individuals affected with a disorder One of the affected males from the third generation has a child with a female who is a carrier For the pedigree shown which of the following best expresses the probability that the couplersquos first son will be affected with the disorder
(A) 25 (B) 50 (C) 75 (D) 100
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Is a widowrsquos peak a dominant or recessive trait
Is a widowrsquos peak a dominant or recessive trait
Fig 14-UN5
George
Sandra Tom Sam
Arlene
Wilma Ann Michael
Carla
Daniel Alan Tina
Christopher
A heterozygous tall and a homozygous purple flowered plant is crossed with a short and white flowered plant Predict the offspring Assume independent assortment
1
P=purplep=whiteT=tallt=short
For a plant with the genotype WwXxYyZz what is the probability that the plant will produce a gamete with a haploid genotype of Wxyz Give your answer as a fraction or as a value between 0 and 1 to four decimal places
2
A completely-plated stickleback from a marine population was mated to a low-plated stickleback from a freshwater population The resulting F1 hybrids all displayed a completely plated phenotype When the F1 hybrids were allowed to interbreed the resulting F2 generation included completely plated offspring and low-plated offspring in an approximate 31 ratio Which of the following conclusions is best supported by the results of the breeding experiments
a Phenotypic variation in the F2 generation suggests that armor morphology is controlled by many alleles of a single gene
b The completely-plated phenotype is controlled by a dominant allele of a single gene
c Armor loss is an acquired characteristic that is affected by one or more environmental factors
d Patterns of armor plating in stickleback populations are regulated by sex-specific signals
3
If a man with type AB blood marries a woman with type O what blood types would you expect in their children What fraction would you expect of each type
4
IA= Type AIB= Type Bi= Type O
If a King marries a Queen that is a carrier of hemophilia (sex-linked recessive disease that is historically fatal before adulthood) what is the chance of the Kingdom having an heir to the kingrsquos throne assuming only one child is born
5
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
7 Gregor Mendelrsquos pioneering genetic experiments with pea plants occurred before the discovery of the structure and function of chromosomes Which of the following observations about inheritance in pea plants could be explained only after the discovery that genes may be linked on a chromosome
a Pea color and pea shape display independent inheritance patterns b Offspring of a given cross show all possible combinations of traits in
equal proportions c Most offspring of a given cross have a combination of traits that is
identical to that of either one parent or the other d Recessive phenotypes can skip a generation showing up only in the
parental and F 2 generations
8
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Based on the data in Table I which of the following best explains why there are no individuals with constricted pods in the F 1 generation a Inflated pod shape is dominant to constricted pod shape b The inflated-pod offspring in the F sub one generation are
homozygous c Constricted pod shape typically arises from a new mutation in the F 1
generation d The constricted-pod offspring are carriers for the inflated pod shape
allele
9
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table I the ratio of phenotypes in the offspring from the testcross with F 1 plants that had purple flowers and inflated pods suggests that the genes for flower color and pod shape are located a close together on the same autosome b on the X chromosome c on different chromosomes d on a mitochondrial chromosome
10
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Which of the following provides the best justification for an assumption that might have been used in the computer simulation (Table II) a The broad allele is recessive to the narrow allele because broad
leaves appear in every generation b The purple allele is dominant to the white allele because all the
offspring from the cross of purple-flowered and white-flowered plants had purple flowers
c The narrow allele is codominant with the purple allele because the purple-flower trait and the narrow-leaf trait segregate together
d The white allele is dominant to both the broad and narrow alleles because plants with either type of leaf shape can have white flowers
11
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table II the F 1 offspring of the cross between broad-leaved white-flowered plants with narrow-leaved purple-flowered plants have a phenotype that differs from that of either parent However many testcross offspring have the same phenotype as one of the two plants in the parental cross but relatively few testcross offspring have the same phenotype as the F 1 offspring Which of the following best explains the observation a Recombination between the leaf-shape and flower-color genes resulted in
chromosomes carrying a dominant allele of both genes b Recombination between the broad and narrow alleles of the leaf-shape gene resulted in
chromosomes carrying three different alleles at the same genetic locus c Independent assortment of homologous chromosomes resulted in the combinations of
alleles present in the parental generation d The computer model cannot capture the possible assortments of gametes when
multiple genes are considered
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Warm-UP What can we learn about inheritance from looking at a pedigree (use example of the Royal Family of Europe from the early 1900s)
Warm-UP In the following human pedigree squares represent males circles represent females and shaded symbols indicate individuals affected with a disorder One of the affected males from the third generation has a child with a female who is a carrier For the pedigree shown which of the following best expresses the probability that the couplersquos first son will be affected with the disorder
(A) 25 (B) 50 (C) 75 (D) 100
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Is a widowrsquos peak a dominant or recessive trait
Is a widowrsquos peak a dominant or recessive trait
Fig 14-UN5
George
Sandra Tom Sam
Arlene
Wilma Ann Michael
Carla
Daniel Alan Tina
Christopher
A heterozygous tall and a homozygous purple flowered plant is crossed with a short and white flowered plant Predict the offspring Assume independent assortment
1
P=purplep=whiteT=tallt=short
For a plant with the genotype WwXxYyZz what is the probability that the plant will produce a gamete with a haploid genotype of Wxyz Give your answer as a fraction or as a value between 0 and 1 to four decimal places
2
A completely-plated stickleback from a marine population was mated to a low-plated stickleback from a freshwater population The resulting F1 hybrids all displayed a completely plated phenotype When the F1 hybrids were allowed to interbreed the resulting F2 generation included completely plated offspring and low-plated offspring in an approximate 31 ratio Which of the following conclusions is best supported by the results of the breeding experiments
a Phenotypic variation in the F2 generation suggests that armor morphology is controlled by many alleles of a single gene
b The completely-plated phenotype is controlled by a dominant allele of a single gene
c Armor loss is an acquired characteristic that is affected by one or more environmental factors
d Patterns of armor plating in stickleback populations are regulated by sex-specific signals
3
If a man with type AB blood marries a woman with type O what blood types would you expect in their children What fraction would you expect of each type
4
IA= Type AIB= Type Bi= Type O
If a King marries a Queen that is a carrier of hemophilia (sex-linked recessive disease that is historically fatal before adulthood) what is the chance of the Kingdom having an heir to the kingrsquos throne assuming only one child is born
5
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
7 Gregor Mendelrsquos pioneering genetic experiments with pea plants occurred before the discovery of the structure and function of chromosomes Which of the following observations about inheritance in pea plants could be explained only after the discovery that genes may be linked on a chromosome
a Pea color and pea shape display independent inheritance patterns b Offspring of a given cross show all possible combinations of traits in
equal proportions c Most offspring of a given cross have a combination of traits that is
identical to that of either one parent or the other d Recessive phenotypes can skip a generation showing up only in the
parental and F 2 generations
8
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Based on the data in Table I which of the following best explains why there are no individuals with constricted pods in the F 1 generation a Inflated pod shape is dominant to constricted pod shape b The inflated-pod offspring in the F sub one generation are
homozygous c Constricted pod shape typically arises from a new mutation in the F 1
generation d The constricted-pod offspring are carriers for the inflated pod shape
allele
9
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table I the ratio of phenotypes in the offspring from the testcross with F 1 plants that had purple flowers and inflated pods suggests that the genes for flower color and pod shape are located a close together on the same autosome b on the X chromosome c on different chromosomes d on a mitochondrial chromosome
10
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Which of the following provides the best justification for an assumption that might have been used in the computer simulation (Table II) a The broad allele is recessive to the narrow allele because broad
leaves appear in every generation b The purple allele is dominant to the white allele because all the
offspring from the cross of purple-flowered and white-flowered plants had purple flowers
c The narrow allele is codominant with the purple allele because the purple-flower trait and the narrow-leaf trait segregate together
d The white allele is dominant to both the broad and narrow alleles because plants with either type of leaf shape can have white flowers
11
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table II the F 1 offspring of the cross between broad-leaved white-flowered plants with narrow-leaved purple-flowered plants have a phenotype that differs from that of either parent However many testcross offspring have the same phenotype as one of the two plants in the parental cross but relatively few testcross offspring have the same phenotype as the F 1 offspring Which of the following best explains the observation a Recombination between the leaf-shape and flower-color genes resulted in
chromosomes carrying a dominant allele of both genes b Recombination between the broad and narrow alleles of the leaf-shape gene resulted in
chromosomes carrying three different alleles at the same genetic locus c Independent assortment of homologous chromosomes resulted in the combinations of
alleles present in the parental generation d The computer model cannot capture the possible assortments of gametes when
multiple genes are considered
Warm-UP In the following human pedigree squares represent males circles represent females and shaded symbols indicate individuals affected with a disorder One of the affected males from the third generation has a child with a female who is a carrier For the pedigree shown which of the following best expresses the probability that the couplersquos first son will be affected with the disorder
(A) 25 (B) 50 (C) 75 (D) 100
DUE Tonight Dihybrid Crosses to turnitincom
DUE Linked vs Unlinked Genes 153
UNIT 78 TEST March 19th
Inheritance and Regulation
Is a widowrsquos peak a dominant or recessive trait
Is a widowrsquos peak a dominant or recessive trait
Fig 14-UN5
George
Sandra Tom Sam
Arlene
Wilma Ann Michael
Carla
Daniel Alan Tina
Christopher
A heterozygous tall and a homozygous purple flowered plant is crossed with a short and white flowered plant Predict the offspring Assume independent assortment
1
P=purplep=whiteT=tallt=short
For a plant with the genotype WwXxYyZz what is the probability that the plant will produce a gamete with a haploid genotype of Wxyz Give your answer as a fraction or as a value between 0 and 1 to four decimal places
2
A completely-plated stickleback from a marine population was mated to a low-plated stickleback from a freshwater population The resulting F1 hybrids all displayed a completely plated phenotype When the F1 hybrids were allowed to interbreed the resulting F2 generation included completely plated offspring and low-plated offspring in an approximate 31 ratio Which of the following conclusions is best supported by the results of the breeding experiments
a Phenotypic variation in the F2 generation suggests that armor morphology is controlled by many alleles of a single gene
b The completely-plated phenotype is controlled by a dominant allele of a single gene
c Armor loss is an acquired characteristic that is affected by one or more environmental factors
d Patterns of armor plating in stickleback populations are regulated by sex-specific signals
3
If a man with type AB blood marries a woman with type O what blood types would you expect in their children What fraction would you expect of each type
4
IA= Type AIB= Type Bi= Type O
If a King marries a Queen that is a carrier of hemophilia (sex-linked recessive disease that is historically fatal before adulthood) what is the chance of the Kingdom having an heir to the kingrsquos throne assuming only one child is born
5
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
7 Gregor Mendelrsquos pioneering genetic experiments with pea plants occurred before the discovery of the structure and function of chromosomes Which of the following observations about inheritance in pea plants could be explained only after the discovery that genes may be linked on a chromosome
a Pea color and pea shape display independent inheritance patterns b Offspring of a given cross show all possible combinations of traits in
equal proportions c Most offspring of a given cross have a combination of traits that is
identical to that of either one parent or the other d Recessive phenotypes can skip a generation showing up only in the
parental and F 2 generations
8
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Based on the data in Table I which of the following best explains why there are no individuals with constricted pods in the F 1 generation a Inflated pod shape is dominant to constricted pod shape b The inflated-pod offspring in the F sub one generation are
homozygous c Constricted pod shape typically arises from a new mutation in the F 1
generation d The constricted-pod offspring are carriers for the inflated pod shape
allele
9
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table I the ratio of phenotypes in the offspring from the testcross with F 1 plants that had purple flowers and inflated pods suggests that the genes for flower color and pod shape are located a close together on the same autosome b on the X chromosome c on different chromosomes d on a mitochondrial chromosome
10
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Which of the following provides the best justification for an assumption that might have been used in the computer simulation (Table II) a The broad allele is recessive to the narrow allele because broad
leaves appear in every generation b The purple allele is dominant to the white allele because all the
offspring from the cross of purple-flowered and white-flowered plants had purple flowers
c The narrow allele is codominant with the purple allele because the purple-flower trait and the narrow-leaf trait segregate together
d The white allele is dominant to both the broad and narrow alleles because plants with either type of leaf shape can have white flowers
11
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table II the F 1 offspring of the cross between broad-leaved white-flowered plants with narrow-leaved purple-flowered plants have a phenotype that differs from that of either parent However many testcross offspring have the same phenotype as one of the two plants in the parental cross but relatively few testcross offspring have the same phenotype as the F 1 offspring Which of the following best explains the observation a Recombination between the leaf-shape and flower-color genes resulted in
chromosomes carrying a dominant allele of both genes b Recombination between the broad and narrow alleles of the leaf-shape gene resulted in
chromosomes carrying three different alleles at the same genetic locus c Independent assortment of homologous chromosomes resulted in the combinations of
alleles present in the parental generation d The computer model cannot capture the possible assortments of gametes when
multiple genes are considered
Is a widowrsquos peak a dominant or recessive trait
Is a widowrsquos peak a dominant or recessive trait
Fig 14-UN5
George
Sandra Tom Sam
Arlene
Wilma Ann Michael
Carla
Daniel Alan Tina
Christopher
A heterozygous tall and a homozygous purple flowered plant is crossed with a short and white flowered plant Predict the offspring Assume independent assortment
1
P=purplep=whiteT=tallt=short
For a plant with the genotype WwXxYyZz what is the probability that the plant will produce a gamete with a haploid genotype of Wxyz Give your answer as a fraction or as a value between 0 and 1 to four decimal places
2
A completely-plated stickleback from a marine population was mated to a low-plated stickleback from a freshwater population The resulting F1 hybrids all displayed a completely plated phenotype When the F1 hybrids were allowed to interbreed the resulting F2 generation included completely plated offspring and low-plated offspring in an approximate 31 ratio Which of the following conclusions is best supported by the results of the breeding experiments
a Phenotypic variation in the F2 generation suggests that armor morphology is controlled by many alleles of a single gene
b The completely-plated phenotype is controlled by a dominant allele of a single gene
c Armor loss is an acquired characteristic that is affected by one or more environmental factors
d Patterns of armor plating in stickleback populations are regulated by sex-specific signals
3
If a man with type AB blood marries a woman with type O what blood types would you expect in their children What fraction would you expect of each type
4
IA= Type AIB= Type Bi= Type O
If a King marries a Queen that is a carrier of hemophilia (sex-linked recessive disease that is historically fatal before adulthood) what is the chance of the Kingdom having an heir to the kingrsquos throne assuming only one child is born
5
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
7 Gregor Mendelrsquos pioneering genetic experiments with pea plants occurred before the discovery of the structure and function of chromosomes Which of the following observations about inheritance in pea plants could be explained only after the discovery that genes may be linked on a chromosome
a Pea color and pea shape display independent inheritance patterns b Offspring of a given cross show all possible combinations of traits in
equal proportions c Most offspring of a given cross have a combination of traits that is
identical to that of either one parent or the other d Recessive phenotypes can skip a generation showing up only in the
parental and F 2 generations
8
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Based on the data in Table I which of the following best explains why there are no individuals with constricted pods in the F 1 generation a Inflated pod shape is dominant to constricted pod shape b The inflated-pod offspring in the F sub one generation are
homozygous c Constricted pod shape typically arises from a new mutation in the F 1
generation d The constricted-pod offspring are carriers for the inflated pod shape
allele
9
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table I the ratio of phenotypes in the offspring from the testcross with F 1 plants that had purple flowers and inflated pods suggests that the genes for flower color and pod shape are located a close together on the same autosome b on the X chromosome c on different chromosomes d on a mitochondrial chromosome
10
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Which of the following provides the best justification for an assumption that might have been used in the computer simulation (Table II) a The broad allele is recessive to the narrow allele because broad
leaves appear in every generation b The purple allele is dominant to the white allele because all the
offspring from the cross of purple-flowered and white-flowered plants had purple flowers
c The narrow allele is codominant with the purple allele because the purple-flower trait and the narrow-leaf trait segregate together
d The white allele is dominant to both the broad and narrow alleles because plants with either type of leaf shape can have white flowers
11
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table II the F 1 offspring of the cross between broad-leaved white-flowered plants with narrow-leaved purple-flowered plants have a phenotype that differs from that of either parent However many testcross offspring have the same phenotype as one of the two plants in the parental cross but relatively few testcross offspring have the same phenotype as the F 1 offspring Which of the following best explains the observation a Recombination between the leaf-shape and flower-color genes resulted in
chromosomes carrying a dominant allele of both genes b Recombination between the broad and narrow alleles of the leaf-shape gene resulted in
chromosomes carrying three different alleles at the same genetic locus c Independent assortment of homologous chromosomes resulted in the combinations of
alleles present in the parental generation d The computer model cannot capture the possible assortments of gametes when
multiple genes are considered
Is a widowrsquos peak a dominant or recessive trait
Fig 14-UN5
George
Sandra Tom Sam
Arlene
Wilma Ann Michael
Carla
Daniel Alan Tina
Christopher
A heterozygous tall and a homozygous purple flowered plant is crossed with a short and white flowered plant Predict the offspring Assume independent assortment
1
P=purplep=whiteT=tallt=short
For a plant with the genotype WwXxYyZz what is the probability that the plant will produce a gamete with a haploid genotype of Wxyz Give your answer as a fraction or as a value between 0 and 1 to four decimal places
2
A completely-plated stickleback from a marine population was mated to a low-plated stickleback from a freshwater population The resulting F1 hybrids all displayed a completely plated phenotype When the F1 hybrids were allowed to interbreed the resulting F2 generation included completely plated offspring and low-plated offspring in an approximate 31 ratio Which of the following conclusions is best supported by the results of the breeding experiments
a Phenotypic variation in the F2 generation suggests that armor morphology is controlled by many alleles of a single gene
b The completely-plated phenotype is controlled by a dominant allele of a single gene
c Armor loss is an acquired characteristic that is affected by one or more environmental factors
d Patterns of armor plating in stickleback populations are regulated by sex-specific signals
3
If a man with type AB blood marries a woman with type O what blood types would you expect in their children What fraction would you expect of each type
4
IA= Type AIB= Type Bi= Type O
If a King marries a Queen that is a carrier of hemophilia (sex-linked recessive disease that is historically fatal before adulthood) what is the chance of the Kingdom having an heir to the kingrsquos throne assuming only one child is born
5
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
7 Gregor Mendelrsquos pioneering genetic experiments with pea plants occurred before the discovery of the structure and function of chromosomes Which of the following observations about inheritance in pea plants could be explained only after the discovery that genes may be linked on a chromosome
a Pea color and pea shape display independent inheritance patterns b Offspring of a given cross show all possible combinations of traits in
equal proportions c Most offspring of a given cross have a combination of traits that is
identical to that of either one parent or the other d Recessive phenotypes can skip a generation showing up only in the
parental and F 2 generations
8
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Based on the data in Table I which of the following best explains why there are no individuals with constricted pods in the F 1 generation a Inflated pod shape is dominant to constricted pod shape b The inflated-pod offspring in the F sub one generation are
homozygous c Constricted pod shape typically arises from a new mutation in the F 1
generation d The constricted-pod offspring are carriers for the inflated pod shape
allele
9
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table I the ratio of phenotypes in the offspring from the testcross with F 1 plants that had purple flowers and inflated pods suggests that the genes for flower color and pod shape are located a close together on the same autosome b on the X chromosome c on different chromosomes d on a mitochondrial chromosome
10
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Which of the following provides the best justification for an assumption that might have been used in the computer simulation (Table II) a The broad allele is recessive to the narrow allele because broad
leaves appear in every generation b The purple allele is dominant to the white allele because all the
offspring from the cross of purple-flowered and white-flowered plants had purple flowers
c The narrow allele is codominant with the purple allele because the purple-flower trait and the narrow-leaf trait segregate together
d The white allele is dominant to both the broad and narrow alleles because plants with either type of leaf shape can have white flowers
11
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table II the F 1 offspring of the cross between broad-leaved white-flowered plants with narrow-leaved purple-flowered plants have a phenotype that differs from that of either parent However many testcross offspring have the same phenotype as one of the two plants in the parental cross but relatively few testcross offspring have the same phenotype as the F 1 offspring Which of the following best explains the observation a Recombination between the leaf-shape and flower-color genes resulted in
chromosomes carrying a dominant allele of both genes b Recombination between the broad and narrow alleles of the leaf-shape gene resulted in
chromosomes carrying three different alleles at the same genetic locus c Independent assortment of homologous chromosomes resulted in the combinations of
alleles present in the parental generation d The computer model cannot capture the possible assortments of gametes when
multiple genes are considered
Fig 14-UN5
George
Sandra Tom Sam
Arlene
Wilma Ann Michael
Carla
Daniel Alan Tina
Christopher
A heterozygous tall and a homozygous purple flowered plant is crossed with a short and white flowered plant Predict the offspring Assume independent assortment
1
P=purplep=whiteT=tallt=short
For a plant with the genotype WwXxYyZz what is the probability that the plant will produce a gamete with a haploid genotype of Wxyz Give your answer as a fraction or as a value between 0 and 1 to four decimal places
2
A completely-plated stickleback from a marine population was mated to a low-plated stickleback from a freshwater population The resulting F1 hybrids all displayed a completely plated phenotype When the F1 hybrids were allowed to interbreed the resulting F2 generation included completely plated offspring and low-plated offspring in an approximate 31 ratio Which of the following conclusions is best supported by the results of the breeding experiments
a Phenotypic variation in the F2 generation suggests that armor morphology is controlled by many alleles of a single gene
b The completely-plated phenotype is controlled by a dominant allele of a single gene
c Armor loss is an acquired characteristic that is affected by one or more environmental factors
d Patterns of armor plating in stickleback populations are regulated by sex-specific signals
3
If a man with type AB blood marries a woman with type O what blood types would you expect in their children What fraction would you expect of each type
4
IA= Type AIB= Type Bi= Type O
If a King marries a Queen that is a carrier of hemophilia (sex-linked recessive disease that is historically fatal before adulthood) what is the chance of the Kingdom having an heir to the kingrsquos throne assuming only one child is born
5
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
7 Gregor Mendelrsquos pioneering genetic experiments with pea plants occurred before the discovery of the structure and function of chromosomes Which of the following observations about inheritance in pea plants could be explained only after the discovery that genes may be linked on a chromosome
a Pea color and pea shape display independent inheritance patterns b Offspring of a given cross show all possible combinations of traits in
equal proportions c Most offspring of a given cross have a combination of traits that is
identical to that of either one parent or the other d Recessive phenotypes can skip a generation showing up only in the
parental and F 2 generations
8
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Based on the data in Table I which of the following best explains why there are no individuals with constricted pods in the F 1 generation a Inflated pod shape is dominant to constricted pod shape b The inflated-pod offspring in the F sub one generation are
homozygous c Constricted pod shape typically arises from a new mutation in the F 1
generation d The constricted-pod offspring are carriers for the inflated pod shape
allele
9
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table I the ratio of phenotypes in the offspring from the testcross with F 1 plants that had purple flowers and inflated pods suggests that the genes for flower color and pod shape are located a close together on the same autosome b on the X chromosome c on different chromosomes d on a mitochondrial chromosome
10
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Which of the following provides the best justification for an assumption that might have been used in the computer simulation (Table II) a The broad allele is recessive to the narrow allele because broad
leaves appear in every generation b The purple allele is dominant to the white allele because all the
offspring from the cross of purple-flowered and white-flowered plants had purple flowers
c The narrow allele is codominant with the purple allele because the purple-flower trait and the narrow-leaf trait segregate together
d The white allele is dominant to both the broad and narrow alleles because plants with either type of leaf shape can have white flowers
11
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table II the F 1 offspring of the cross between broad-leaved white-flowered plants with narrow-leaved purple-flowered plants have a phenotype that differs from that of either parent However many testcross offspring have the same phenotype as one of the two plants in the parental cross but relatively few testcross offspring have the same phenotype as the F 1 offspring Which of the following best explains the observation a Recombination between the leaf-shape and flower-color genes resulted in
chromosomes carrying a dominant allele of both genes b Recombination between the broad and narrow alleles of the leaf-shape gene resulted in
chromosomes carrying three different alleles at the same genetic locus c Independent assortment of homologous chromosomes resulted in the combinations of
alleles present in the parental generation d The computer model cannot capture the possible assortments of gametes when
multiple genes are considered
A heterozygous tall and a homozygous purple flowered plant is crossed with a short and white flowered plant Predict the offspring Assume independent assortment
1
P=purplep=whiteT=tallt=short
For a plant with the genotype WwXxYyZz what is the probability that the plant will produce a gamete with a haploid genotype of Wxyz Give your answer as a fraction or as a value between 0 and 1 to four decimal places
2
A completely-plated stickleback from a marine population was mated to a low-plated stickleback from a freshwater population The resulting F1 hybrids all displayed a completely plated phenotype When the F1 hybrids were allowed to interbreed the resulting F2 generation included completely plated offspring and low-plated offspring in an approximate 31 ratio Which of the following conclusions is best supported by the results of the breeding experiments
a Phenotypic variation in the F2 generation suggests that armor morphology is controlled by many alleles of a single gene
b The completely-plated phenotype is controlled by a dominant allele of a single gene
c Armor loss is an acquired characteristic that is affected by one or more environmental factors
d Patterns of armor plating in stickleback populations are regulated by sex-specific signals
3
If a man with type AB blood marries a woman with type O what blood types would you expect in their children What fraction would you expect of each type
4
IA= Type AIB= Type Bi= Type O
If a King marries a Queen that is a carrier of hemophilia (sex-linked recessive disease that is historically fatal before adulthood) what is the chance of the Kingdom having an heir to the kingrsquos throne assuming only one child is born
5
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
7 Gregor Mendelrsquos pioneering genetic experiments with pea plants occurred before the discovery of the structure and function of chromosomes Which of the following observations about inheritance in pea plants could be explained only after the discovery that genes may be linked on a chromosome
a Pea color and pea shape display independent inheritance patterns b Offspring of a given cross show all possible combinations of traits in
equal proportions c Most offspring of a given cross have a combination of traits that is
identical to that of either one parent or the other d Recessive phenotypes can skip a generation showing up only in the
parental and F 2 generations
8
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Based on the data in Table I which of the following best explains why there are no individuals with constricted pods in the F 1 generation a Inflated pod shape is dominant to constricted pod shape b The inflated-pod offspring in the F sub one generation are
homozygous c Constricted pod shape typically arises from a new mutation in the F 1
generation d The constricted-pod offspring are carriers for the inflated pod shape
allele
9
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table I the ratio of phenotypes in the offspring from the testcross with F 1 plants that had purple flowers and inflated pods suggests that the genes for flower color and pod shape are located a close together on the same autosome b on the X chromosome c on different chromosomes d on a mitochondrial chromosome
10
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Which of the following provides the best justification for an assumption that might have been used in the computer simulation (Table II) a The broad allele is recessive to the narrow allele because broad
leaves appear in every generation b The purple allele is dominant to the white allele because all the
offspring from the cross of purple-flowered and white-flowered plants had purple flowers
c The narrow allele is codominant with the purple allele because the purple-flower trait and the narrow-leaf trait segregate together
d The white allele is dominant to both the broad and narrow alleles because plants with either type of leaf shape can have white flowers
11
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table II the F 1 offspring of the cross between broad-leaved white-flowered plants with narrow-leaved purple-flowered plants have a phenotype that differs from that of either parent However many testcross offspring have the same phenotype as one of the two plants in the parental cross but relatively few testcross offspring have the same phenotype as the F 1 offspring Which of the following best explains the observation a Recombination between the leaf-shape and flower-color genes resulted in
chromosomes carrying a dominant allele of both genes b Recombination between the broad and narrow alleles of the leaf-shape gene resulted in
chromosomes carrying three different alleles at the same genetic locus c Independent assortment of homologous chromosomes resulted in the combinations of
alleles present in the parental generation d The computer model cannot capture the possible assortments of gametes when
multiple genes are considered
For a plant with the genotype WwXxYyZz what is the probability that the plant will produce a gamete with a haploid genotype of Wxyz Give your answer as a fraction or as a value between 0 and 1 to four decimal places
2
A completely-plated stickleback from a marine population was mated to a low-plated stickleback from a freshwater population The resulting F1 hybrids all displayed a completely plated phenotype When the F1 hybrids were allowed to interbreed the resulting F2 generation included completely plated offspring and low-plated offspring in an approximate 31 ratio Which of the following conclusions is best supported by the results of the breeding experiments
a Phenotypic variation in the F2 generation suggests that armor morphology is controlled by many alleles of a single gene
b The completely-plated phenotype is controlled by a dominant allele of a single gene
c Armor loss is an acquired characteristic that is affected by one or more environmental factors
d Patterns of armor plating in stickleback populations are regulated by sex-specific signals
3
If a man with type AB blood marries a woman with type O what blood types would you expect in their children What fraction would you expect of each type
4
IA= Type AIB= Type Bi= Type O
If a King marries a Queen that is a carrier of hemophilia (sex-linked recessive disease that is historically fatal before adulthood) what is the chance of the Kingdom having an heir to the kingrsquos throne assuming only one child is born
5
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
7 Gregor Mendelrsquos pioneering genetic experiments with pea plants occurred before the discovery of the structure and function of chromosomes Which of the following observations about inheritance in pea plants could be explained only after the discovery that genes may be linked on a chromosome
a Pea color and pea shape display independent inheritance patterns b Offspring of a given cross show all possible combinations of traits in
equal proportions c Most offspring of a given cross have a combination of traits that is
identical to that of either one parent or the other d Recessive phenotypes can skip a generation showing up only in the
parental and F 2 generations
8
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Based on the data in Table I which of the following best explains why there are no individuals with constricted pods in the F 1 generation a Inflated pod shape is dominant to constricted pod shape b The inflated-pod offspring in the F sub one generation are
homozygous c Constricted pod shape typically arises from a new mutation in the F 1
generation d The constricted-pod offspring are carriers for the inflated pod shape
allele
9
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table I the ratio of phenotypes in the offspring from the testcross with F 1 plants that had purple flowers and inflated pods suggests that the genes for flower color and pod shape are located a close together on the same autosome b on the X chromosome c on different chromosomes d on a mitochondrial chromosome
10
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Which of the following provides the best justification for an assumption that might have been used in the computer simulation (Table II) a The broad allele is recessive to the narrow allele because broad
leaves appear in every generation b The purple allele is dominant to the white allele because all the
offspring from the cross of purple-flowered and white-flowered plants had purple flowers
c The narrow allele is codominant with the purple allele because the purple-flower trait and the narrow-leaf trait segregate together
d The white allele is dominant to both the broad and narrow alleles because plants with either type of leaf shape can have white flowers
11
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table II the F 1 offspring of the cross between broad-leaved white-flowered plants with narrow-leaved purple-flowered plants have a phenotype that differs from that of either parent However many testcross offspring have the same phenotype as one of the two plants in the parental cross but relatively few testcross offspring have the same phenotype as the F 1 offspring Which of the following best explains the observation a Recombination between the leaf-shape and flower-color genes resulted in
chromosomes carrying a dominant allele of both genes b Recombination between the broad and narrow alleles of the leaf-shape gene resulted in
chromosomes carrying three different alleles at the same genetic locus c Independent assortment of homologous chromosomes resulted in the combinations of
alleles present in the parental generation d The computer model cannot capture the possible assortments of gametes when
multiple genes are considered
A completely-plated stickleback from a marine population was mated to a low-plated stickleback from a freshwater population The resulting F1 hybrids all displayed a completely plated phenotype When the F1 hybrids were allowed to interbreed the resulting F2 generation included completely plated offspring and low-plated offspring in an approximate 31 ratio Which of the following conclusions is best supported by the results of the breeding experiments
a Phenotypic variation in the F2 generation suggests that armor morphology is controlled by many alleles of a single gene
b The completely-plated phenotype is controlled by a dominant allele of a single gene
c Armor loss is an acquired characteristic that is affected by one or more environmental factors
d Patterns of armor plating in stickleback populations are regulated by sex-specific signals
3
If a man with type AB blood marries a woman with type O what blood types would you expect in their children What fraction would you expect of each type
4
IA= Type AIB= Type Bi= Type O
If a King marries a Queen that is a carrier of hemophilia (sex-linked recessive disease that is historically fatal before adulthood) what is the chance of the Kingdom having an heir to the kingrsquos throne assuming only one child is born
5
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
7 Gregor Mendelrsquos pioneering genetic experiments with pea plants occurred before the discovery of the structure and function of chromosomes Which of the following observations about inheritance in pea plants could be explained only after the discovery that genes may be linked on a chromosome
a Pea color and pea shape display independent inheritance patterns b Offspring of a given cross show all possible combinations of traits in
equal proportions c Most offspring of a given cross have a combination of traits that is
identical to that of either one parent or the other d Recessive phenotypes can skip a generation showing up only in the
parental and F 2 generations
8
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Based on the data in Table I which of the following best explains why there are no individuals with constricted pods in the F 1 generation a Inflated pod shape is dominant to constricted pod shape b The inflated-pod offspring in the F sub one generation are
homozygous c Constricted pod shape typically arises from a new mutation in the F 1
generation d The constricted-pod offspring are carriers for the inflated pod shape
allele
9
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table I the ratio of phenotypes in the offspring from the testcross with F 1 plants that had purple flowers and inflated pods suggests that the genes for flower color and pod shape are located a close together on the same autosome b on the X chromosome c on different chromosomes d on a mitochondrial chromosome
10
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Which of the following provides the best justification for an assumption that might have been used in the computer simulation (Table II) a The broad allele is recessive to the narrow allele because broad
leaves appear in every generation b The purple allele is dominant to the white allele because all the
offspring from the cross of purple-flowered and white-flowered plants had purple flowers
c The narrow allele is codominant with the purple allele because the purple-flower trait and the narrow-leaf trait segregate together
d The white allele is dominant to both the broad and narrow alleles because plants with either type of leaf shape can have white flowers
11
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table II the F 1 offspring of the cross between broad-leaved white-flowered plants with narrow-leaved purple-flowered plants have a phenotype that differs from that of either parent However many testcross offspring have the same phenotype as one of the two plants in the parental cross but relatively few testcross offspring have the same phenotype as the F 1 offspring Which of the following best explains the observation a Recombination between the leaf-shape and flower-color genes resulted in
chromosomes carrying a dominant allele of both genes b Recombination between the broad and narrow alleles of the leaf-shape gene resulted in
chromosomes carrying three different alleles at the same genetic locus c Independent assortment of homologous chromosomes resulted in the combinations of
alleles present in the parental generation d The computer model cannot capture the possible assortments of gametes when
multiple genes are considered
If a man with type AB blood marries a woman with type O what blood types would you expect in their children What fraction would you expect of each type
4
IA= Type AIB= Type Bi= Type O
If a King marries a Queen that is a carrier of hemophilia (sex-linked recessive disease that is historically fatal before adulthood) what is the chance of the Kingdom having an heir to the kingrsquos throne assuming only one child is born
5
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
7 Gregor Mendelrsquos pioneering genetic experiments with pea plants occurred before the discovery of the structure and function of chromosomes Which of the following observations about inheritance in pea plants could be explained only after the discovery that genes may be linked on a chromosome
a Pea color and pea shape display independent inheritance patterns b Offspring of a given cross show all possible combinations of traits in
equal proportions c Most offspring of a given cross have a combination of traits that is
identical to that of either one parent or the other d Recessive phenotypes can skip a generation showing up only in the
parental and F 2 generations
8
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Based on the data in Table I which of the following best explains why there are no individuals with constricted pods in the F 1 generation a Inflated pod shape is dominant to constricted pod shape b The inflated-pod offspring in the F sub one generation are
homozygous c Constricted pod shape typically arises from a new mutation in the F 1
generation d The constricted-pod offspring are carriers for the inflated pod shape
allele
9
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table I the ratio of phenotypes in the offspring from the testcross with F 1 plants that had purple flowers and inflated pods suggests that the genes for flower color and pod shape are located a close together on the same autosome b on the X chromosome c on different chromosomes d on a mitochondrial chromosome
10
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Which of the following provides the best justification for an assumption that might have been used in the computer simulation (Table II) a The broad allele is recessive to the narrow allele because broad
leaves appear in every generation b The purple allele is dominant to the white allele because all the
offspring from the cross of purple-flowered and white-flowered plants had purple flowers
c The narrow allele is codominant with the purple allele because the purple-flower trait and the narrow-leaf trait segregate together
d The white allele is dominant to both the broad and narrow alleles because plants with either type of leaf shape can have white flowers
11
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table II the F 1 offspring of the cross between broad-leaved white-flowered plants with narrow-leaved purple-flowered plants have a phenotype that differs from that of either parent However many testcross offspring have the same phenotype as one of the two plants in the parental cross but relatively few testcross offspring have the same phenotype as the F 1 offspring Which of the following best explains the observation a Recombination between the leaf-shape and flower-color genes resulted in
chromosomes carrying a dominant allele of both genes b Recombination between the broad and narrow alleles of the leaf-shape gene resulted in
chromosomes carrying three different alleles at the same genetic locus c Independent assortment of homologous chromosomes resulted in the combinations of
alleles present in the parental generation d The computer model cannot capture the possible assortments of gametes when
multiple genes are considered
If a King marries a Queen that is a carrier of hemophilia (sex-linked recessive disease that is historically fatal before adulthood) what is the chance of the Kingdom having an heir to the kingrsquos throne assuming only one child is born
5
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
7 Gregor Mendelrsquos pioneering genetic experiments with pea plants occurred before the discovery of the structure and function of chromosomes Which of the following observations about inheritance in pea plants could be explained only after the discovery that genes may be linked on a chromosome
a Pea color and pea shape display independent inheritance patterns b Offspring of a given cross show all possible combinations of traits in
equal proportions c Most offspring of a given cross have a combination of traits that is
identical to that of either one parent or the other d Recessive phenotypes can skip a generation showing up only in the
parental and F 2 generations
8
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Based on the data in Table I which of the following best explains why there are no individuals with constricted pods in the F 1 generation a Inflated pod shape is dominant to constricted pod shape b The inflated-pod offspring in the F sub one generation are
homozygous c Constricted pod shape typically arises from a new mutation in the F 1
generation d The constricted-pod offspring are carriers for the inflated pod shape
allele
9
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table I the ratio of phenotypes in the offspring from the testcross with F 1 plants that had purple flowers and inflated pods suggests that the genes for flower color and pod shape are located a close together on the same autosome b on the X chromosome c on different chromosomes d on a mitochondrial chromosome
10
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Which of the following provides the best justification for an assumption that might have been used in the computer simulation (Table II) a The broad allele is recessive to the narrow allele because broad
leaves appear in every generation b The purple allele is dominant to the white allele because all the
offspring from the cross of purple-flowered and white-flowered plants had purple flowers
c The narrow allele is codominant with the purple allele because the purple-flower trait and the narrow-leaf trait segregate together
d The white allele is dominant to both the broad and narrow alleles because plants with either type of leaf shape can have white flowers
11
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table II the F 1 offspring of the cross between broad-leaved white-flowered plants with narrow-leaved purple-flowered plants have a phenotype that differs from that of either parent However many testcross offspring have the same phenotype as one of the two plants in the parental cross but relatively few testcross offspring have the same phenotype as the F 1 offspring Which of the following best explains the observation a Recombination between the leaf-shape and flower-color genes resulted in
chromosomes carrying a dominant allele of both genes b Recombination between the broad and narrow alleles of the leaf-shape gene resulted in
chromosomes carrying three different alleles at the same genetic locus c Independent assortment of homologous chromosomes resulted in the combinations of
alleles present in the parental generation d The computer model cannot capture the possible assortments of gametes when
multiple genes are considered
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
7 Gregor Mendelrsquos pioneering genetic experiments with pea plants occurred before the discovery of the structure and function of chromosomes Which of the following observations about inheritance in pea plants could be explained only after the discovery that genes may be linked on a chromosome
a Pea color and pea shape display independent inheritance patterns b Offspring of a given cross show all possible combinations of traits in
equal proportions c Most offspring of a given cross have a combination of traits that is
identical to that of either one parent or the other d Recessive phenotypes can skip a generation showing up only in the
parental and F 2 generations
8
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Based on the data in Table I which of the following best explains why there are no individuals with constricted pods in the F 1 generation a Inflated pod shape is dominant to constricted pod shape b The inflated-pod offspring in the F sub one generation are
homozygous c Constricted pod shape typically arises from a new mutation in the F 1
generation d The constricted-pod offspring are carriers for the inflated pod shape
allele
9
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table I the ratio of phenotypes in the offspring from the testcross with F 1 plants that had purple flowers and inflated pods suggests that the genes for flower color and pod shape are located a close together on the same autosome b on the X chromosome c on different chromosomes d on a mitochondrial chromosome
10
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Which of the following provides the best justification for an assumption that might have been used in the computer simulation (Table II) a The broad allele is recessive to the narrow allele because broad
leaves appear in every generation b The purple allele is dominant to the white allele because all the
offspring from the cross of purple-flowered and white-flowered plants had purple flowers
c The narrow allele is codominant with the purple allele because the purple-flower trait and the narrow-leaf trait segregate together
d The white allele is dominant to both the broad and narrow alleles because plants with either type of leaf shape can have white flowers
11
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table II the F 1 offspring of the cross between broad-leaved white-flowered plants with narrow-leaved purple-flowered plants have a phenotype that differs from that of either parent However many testcross offspring have the same phenotype as one of the two plants in the parental cross but relatively few testcross offspring have the same phenotype as the F 1 offspring Which of the following best explains the observation a Recombination between the leaf-shape and flower-color genes resulted in
chromosomes carrying a dominant allele of both genes b Recombination between the broad and narrow alleles of the leaf-shape gene resulted in
chromosomes carrying three different alleles at the same genetic locus c Independent assortment of homologous chromosomes resulted in the combinations of
alleles present in the parental generation d The computer model cannot capture the possible assortments of gametes when
multiple genes are considered
6Is an attached earlobe a dominant or recessive trait Draw the pedigree and fill in the genotypes for each offspring
7 Gregor Mendelrsquos pioneering genetic experiments with pea plants occurred before the discovery of the structure and function of chromosomes Which of the following observations about inheritance in pea plants could be explained only after the discovery that genes may be linked on a chromosome
a Pea color and pea shape display independent inheritance patterns b Offspring of a given cross show all possible combinations of traits in
equal proportions c Most offspring of a given cross have a combination of traits that is
identical to that of either one parent or the other d Recessive phenotypes can skip a generation showing up only in the
parental and F 2 generations
8
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Based on the data in Table I which of the following best explains why there are no individuals with constricted pods in the F 1 generation a Inflated pod shape is dominant to constricted pod shape b The inflated-pod offspring in the F sub one generation are
homozygous c Constricted pod shape typically arises from a new mutation in the F 1
generation d The constricted-pod offspring are carriers for the inflated pod shape
allele
9
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table I the ratio of phenotypes in the offspring from the testcross with F 1 plants that had purple flowers and inflated pods suggests that the genes for flower color and pod shape are located a close together on the same autosome b on the X chromosome c on different chromosomes d on a mitochondrial chromosome
10
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Which of the following provides the best justification for an assumption that might have been used in the computer simulation (Table II) a The broad allele is recessive to the narrow allele because broad
leaves appear in every generation b The purple allele is dominant to the white allele because all the
offspring from the cross of purple-flowered and white-flowered plants had purple flowers
c The narrow allele is codominant with the purple allele because the purple-flower trait and the narrow-leaf trait segregate together
d The white allele is dominant to both the broad and narrow alleles because plants with either type of leaf shape can have white flowers
11
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table II the F 1 offspring of the cross between broad-leaved white-flowered plants with narrow-leaved purple-flowered plants have a phenotype that differs from that of either parent However many testcross offspring have the same phenotype as one of the two plants in the parental cross but relatively few testcross offspring have the same phenotype as the F 1 offspring Which of the following best explains the observation a Recombination between the leaf-shape and flower-color genes resulted in
chromosomes carrying a dominant allele of both genes b Recombination between the broad and narrow alleles of the leaf-shape gene resulted in
chromosomes carrying three different alleles at the same genetic locus c Independent assortment of homologous chromosomes resulted in the combinations of
alleles present in the parental generation d The computer model cannot capture the possible assortments of gametes when
multiple genes are considered
7 Gregor Mendelrsquos pioneering genetic experiments with pea plants occurred before the discovery of the structure and function of chromosomes Which of the following observations about inheritance in pea plants could be explained only after the discovery that genes may be linked on a chromosome
a Pea color and pea shape display independent inheritance patterns b Offspring of a given cross show all possible combinations of traits in
equal proportions c Most offspring of a given cross have a combination of traits that is
identical to that of either one parent or the other d Recessive phenotypes can skip a generation showing up only in the
parental and F 2 generations
8
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Based on the data in Table I which of the following best explains why there are no individuals with constricted pods in the F 1 generation a Inflated pod shape is dominant to constricted pod shape b The inflated-pod offspring in the F sub one generation are
homozygous c Constricted pod shape typically arises from a new mutation in the F 1
generation d The constricted-pod offspring are carriers for the inflated pod shape
allele
9
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table I the ratio of phenotypes in the offspring from the testcross with F 1 plants that had purple flowers and inflated pods suggests that the genes for flower color and pod shape are located a close together on the same autosome b on the X chromosome c on different chromosomes d on a mitochondrial chromosome
10
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Which of the following provides the best justification for an assumption that might have been used in the computer simulation (Table II) a The broad allele is recessive to the narrow allele because broad
leaves appear in every generation b The purple allele is dominant to the white allele because all the
offspring from the cross of purple-flowered and white-flowered plants had purple flowers
c The narrow allele is codominant with the purple allele because the purple-flower trait and the narrow-leaf trait segregate together
d The white allele is dominant to both the broad and narrow alleles because plants with either type of leaf shape can have white flowers
11
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table II the F 1 offspring of the cross between broad-leaved white-flowered plants with narrow-leaved purple-flowered plants have a phenotype that differs from that of either parent However many testcross offspring have the same phenotype as one of the two plants in the parental cross but relatively few testcross offspring have the same phenotype as the F 1 offspring Which of the following best explains the observation a Recombination between the leaf-shape and flower-color genes resulted in
chromosomes carrying a dominant allele of both genes b Recombination between the broad and narrow alleles of the leaf-shape gene resulted in
chromosomes carrying three different alleles at the same genetic locus c Independent assortment of homologous chromosomes resulted in the combinations of
alleles present in the parental generation d The computer model cannot capture the possible assortments of gametes when
multiple genes are considered
8
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Based on the data in Table I which of the following best explains why there are no individuals with constricted pods in the F 1 generation a Inflated pod shape is dominant to constricted pod shape b The inflated-pod offspring in the F sub one generation are
homozygous c Constricted pod shape typically arises from a new mutation in the F 1
generation d The constricted-pod offspring are carriers for the inflated pod shape
allele
9
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table I the ratio of phenotypes in the offspring from the testcross with F 1 plants that had purple flowers and inflated pods suggests that the genes for flower color and pod shape are located a close together on the same autosome b on the X chromosome c on different chromosomes d on a mitochondrial chromosome
10
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Which of the following provides the best justification for an assumption that might have been used in the computer simulation (Table II) a The broad allele is recessive to the narrow allele because broad
leaves appear in every generation b The purple allele is dominant to the white allele because all the
offspring from the cross of purple-flowered and white-flowered plants had purple flowers
c The narrow allele is codominant with the purple allele because the purple-flower trait and the narrow-leaf trait segregate together
d The white allele is dominant to both the broad and narrow alleles because plants with either type of leaf shape can have white flowers
11
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table II the F 1 offspring of the cross between broad-leaved white-flowered plants with narrow-leaved purple-flowered plants have a phenotype that differs from that of either parent However many testcross offspring have the same phenotype as one of the two plants in the parental cross but relatively few testcross offspring have the same phenotype as the F 1 offspring Which of the following best explains the observation a Recombination between the leaf-shape and flower-color genes resulted in
chromosomes carrying a dominant allele of both genes b Recombination between the broad and narrow alleles of the leaf-shape gene resulted in
chromosomes carrying three different alleles at the same genetic locus c Independent assortment of homologous chromosomes resulted in the combinations of
alleles present in the parental generation d The computer model cannot capture the possible assortments of gametes when
multiple genes are considered
9
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table I the ratio of phenotypes in the offspring from the testcross with F 1 plants that had purple flowers and inflated pods suggests that the genes for flower color and pod shape are located a close together on the same autosome b on the X chromosome c on different chromosomes d on a mitochondrial chromosome
10
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Which of the following provides the best justification for an assumption that might have been used in the computer simulation (Table II) a The broad allele is recessive to the narrow allele because broad
leaves appear in every generation b The purple allele is dominant to the white allele because all the
offspring from the cross of purple-flowered and white-flowered plants had purple flowers
c The narrow allele is codominant with the purple allele because the purple-flower trait and the narrow-leaf trait segregate together
d The white allele is dominant to both the broad and narrow alleles because plants with either type of leaf shape can have white flowers
11
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table II the F 1 offspring of the cross between broad-leaved white-flowered plants with narrow-leaved purple-flowered plants have a phenotype that differs from that of either parent However many testcross offspring have the same phenotype as one of the two plants in the parental cross but relatively few testcross offspring have the same phenotype as the F 1 offspring Which of the following best explains the observation a Recombination between the leaf-shape and flower-color genes resulted in
chromosomes carrying a dominant allele of both genes b Recombination between the broad and narrow alleles of the leaf-shape gene resulted in
chromosomes carrying three different alleles at the same genetic locus c Independent assortment of homologous chromosomes resulted in the combinations of
alleles present in the parental generation d The computer model cannot capture the possible assortments of gametes when
multiple genes are considered
10
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
Which of the following provides the best justification for an assumption that might have been used in the computer simulation (Table II) a The broad allele is recessive to the narrow allele because broad
leaves appear in every generation b The purple allele is dominant to the white allele because all the
offspring from the cross of purple-flowered and white-flowered plants had purple flowers
c The narrow allele is codominant with the purple allele because the purple-flower trait and the narrow-leaf trait segregate together
d The white allele is dominant to both the broad and narrow alleles because plants with either type of leaf shape can have white flowers
11
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table II the F 1 offspring of the cross between broad-leaved white-flowered plants with narrow-leaved purple-flowered plants have a phenotype that differs from that of either parent However many testcross offspring have the same phenotype as one of the two plants in the parental cross but relatively few testcross offspring have the same phenotype as the F 1 offspring Which of the following best explains the observation a Recombination between the leaf-shape and flower-color genes resulted in
chromosomes carrying a dominant allele of both genes b Recombination between the broad and narrow alleles of the leaf-shape gene resulted in
chromosomes carrying three different alleles at the same genetic locus c Independent assortment of homologous chromosomes resulted in the combinations of
alleles present in the parental generation d The computer model cannot capture the possible assortments of gametes when
multiple genes are considered
11
Table I shows the results of breeding experiments to examine the inheritance of flower color (purple versus white) and pod shape (inflated versus constricted) For the crosses recorded in Table I true-breeding parents were crossed to produce F1 offspring which were then testcrossed to homozygous recessive individuals Table II shows the results of computer-simulated crosses to model the inheritance of leaf shape (broad versus narrow) and flower color (purple versus white)
In Table II the F 1 offspring of the cross between broad-leaved white-flowered plants with narrow-leaved purple-flowered plants have a phenotype that differs from that of either parent However many testcross offspring have the same phenotype as one of the two plants in the parental cross but relatively few testcross offspring have the same phenotype as the F 1 offspring Which of the following best explains the observation a Recombination between the leaf-shape and flower-color genes resulted in
chromosomes carrying a dominant allele of both genes b Recombination between the broad and narrow alleles of the leaf-shape gene resulted in
chromosomes carrying three different alleles at the same genetic locus c Independent assortment of homologous chromosomes resulted in the combinations of
alleles present in the parental generation d The computer model cannot capture the possible assortments of gametes when
multiple genes are considered