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Warm-up for Section 3.2:
0(5). 1x
75
2(3).
x
xx
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1( x
x
2 3 5(1). xx x 5 13 5(2). ( ) xx
23 6
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x
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x x
3.1B Homework Answers
1. 28 = 256 2. (-7)3 = -343 3. 1/47 =
1/16384
4. 1/54 = 1/625 5. 1/44 = 1/256 6. 1/86 = 1/262,144
7. 1.342 1012 8. 3.38 10-5 9. 2.025 109
10. 3.73248 10-7 11. 6.6 101 12. 3.5 10-15
13. x4 14. y11 15. 531,441x18
16. 17. 18.
10
1
w 3z
y3
716
n
m
3.1B Homework Answers Continued…
19. 20. 21.
22. 4q3r 23. 24.
25. 26. 27. 1.032
1011
44
3x 632
3x
41449
1
dc 12
9
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7
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Operations on Functions
Section 3.2B
Standard: MM2A5d
Essential Question: How do I perform operations with functions?
Vocabulary
Power function: a function of the form y = axb,where a is a real number and b is a rational number
Composition: h(x) = g(f(x)) is the composition of a function g with a function f. • The domain of h is the set of all x-values such that
x is in the domain of f and f(x) is the domain of g.
Investigation 1: New functions can be created from established functions through the operations of addition, subtraction, multiplication, and division. Consider the linear function f(x) = 2x + 1 and the quadratic function g(x) = x2 – 3. Complete the table below for the selected values of the domain. The first column has been done for you.
Table 1: x -2 -1 0 3y = f(x) -3y = g(x) 1
Table 1: x -2 -1 0 3y = f(x) -3y = g(x) 1
Now, keeping the domain fixed, add the range values for f and g to create a new function. Complete the table below to identify the y values for this new function. The first column has been done for you.
Table 2: x -2 -1 0 3y = f(x) + g(x) -2
-1 1 7-2 -3 6
-3 -2 13
This new function is denoted y = f(x) + g(x) or y = (f + g)(x). To find the rule for the new function, simply add the expressions for y = f(x) and y = g(x).
This new function is: y = (2x + 1) + (x2 – 3).In simple form, we have y = x2 + 2x – 2. Let’s call this function h. So, h(x) = x2 + 2x – 2. Evaluate the function for each domain element to check the values in Table 2.
Let’s call this function h. So, h(x) = x2 + 2x – 2. Evaluate the function for each domain element to check the values in Table 2. h(-2) = (-2)2 + 2(-2) – 2 = _______h(-1) = (-1)2 + 2(-1) – 2 = _______h(0) = (0)2 + 2(0) – 2 = _______h(3) = (3)2 + 2(3) – 2 = _______
Did you get the same values in Table 2? ________
-2-3-213
YES
Let’s use f(x) = 2x + 1 and g(x) = x2 – 3 and the operations of subtraction, multiplication, and division to create other new functions. Call the new functions s(x), m(x), and d(x), respectively.
(2). f(x) – g(x) or (f – g)(x)
= (2x + 1) – (x2 – 3) = 2x + 1 – x2 + 3 = -x2 + 2x + 4 s(x) = -x2 + 2x + 4
Let’s use f(x) = 2x + 1 and g(x) = x2 – 3 and the operations of subtraction, multiplication, and division to create other new functions. Call the new functions s(x), m(x), and d(x), respectively.
(3). f(x) ∙ g(x) or (f g)(x)
= (2x + 1)(x2 – 3) = 2x3 – 6x + x2 – 3 = 2x3 + x2 – 6x – 3 m(x) = 2x3 + x2 – 6x – 3
Let’s use f(x) = 2x + 1 and g(x) = x2 – 3 and the operations of subtraction, multiplication, and division to create other new functions. Call the new functions s(x), m(x), and d(x), respectively.
(4). or
)(
)(
xf
xg xf
g
12
32
x
x
12
3)(
2
x
xxd
The domain of the new function is the set of values common to original functions. In other words, it is the intersection of the domains of the original functions. The domain of f(x) = 2x + 1 is _____________ and the domain of g(x) = x2 – 3 is ___________.So, the domains for h, s, and m will all be ___________.
all realsall reals
all reals
But, the function d was created by division so we must check to see what values of the common domain will make the denominator zero. This value must be excluded. So, the domain of y = d(x) is all reals except __________.x = -½
2x + 1 = 0 2x = -1 x = -1/2
Check for Understanding: Let h(x) = 3x + 1 and p(x) = 2x – 5 Find the following and state the domain. (5). h(x) + p(x) or (h + p)(x) = ____________
Domain: _____________
(6). h(x) – p(x) or (h – p)(x) = ___________
Domain: _____________
5x – 4
all reals
x + 6
all reals
Check for Understanding: Let h(x) = 3x + 1 and p(x) = 2x – 5 Find the following and state the domain. (7). h(x) ∙ p(x) or (hp)(x) = ____________
Domain: _____________
(8). or = ___________
Domain: ______________________
6x2 – 13x – 5
all reals
all reals except x = 5/2
)(
)(
xp
xh xp
h
52
13
x
x
Another way of combining two functions is to form the composition of one with the other.
-234
-145
11625
Df
Dg
Rf
Rg
f(x) = x + 1 g(x) = x2
The composition of g with f can be pictured above.
The new function created maps the domain of f to the range of g.
-234
-145
11625
Df
Dg
Rf
Rg
f(x) = x + 1 g(x) = x2
If we call this new function h, then the rule for h is h(x) = (x + 1)2
The domain of h is the set of all x-values such That x is in the domain of g and g(x) is in the domain of f.
h(x) = f(g(x))
(9). Let f(x) = 6x and g(x) = 3x + 5 find each composition and its domain.
a. f(g(x)) =
Domain: _________
b. g(f(x)) =
Domain: _________
f(3x + 5)
= 6(3x + 5)
g(6x)
= 3(6x) + 5
h(x) = 18x + 5all reals
h(x) = 18x + 5all reals
(9). Let f(x) = 6x and g(x) = 3x + 5 find each composition and its domain.
c. f(f(x)) =
Domain: __________
d. g(g(x)) =
Domain: _________
g(3x + 5)
= 3(3x + 5) + 5
h(x) = 9x + 20
= 9x + 15 + 5
f(6x)
= 6(6x)
h(x) = 36x all reals
all reals
(10). Let f(x) = 2x and g(x) = x2 – 3 find each composition and its domain.
a. f(g(x)) =
Domain = __________
b. g(f(x) =
Domian = _________
f(x2 – 3 )
= 2(x2 – 3 )
h(x) = 2x2 – 6
g(2x )
= (2x)2 – 3
h(x) = 4x2 – 3
all reals
all reals
(10). Let f(x) = 2x and g(x) = x2 – 3 find each composition and its domain.
c. g(g(x)) =
Domian = _________
g(x2 – 3 )
= (x2 – 3)2 – 3
h(x) = x4 – 6x2 + 6
= (x2 – 3)(x2 – 3) – 3
= x4 – 3x2 – 3x2 + 9 – 3
all reals
Check for Understanding: Let p(x) = 3x + 1 and h(x) = x2 – 4, find each new functions and its domain. (11). (p + h)(x) = _____________________
Domain: ________________ (12). (h – p)(x) = _____________________
Domain: ________________ (13). (ph)(x) = _____________________
Domain: ________________
x2 + 3x – 3
x2 – 3x – 5
3x3 + x2 – 12x – 4
all reals
all reals
all reals