41
Velocity The velocity of the wave is the measurement of how fast a crest is moving from a fixed point. The speed of sound is about 1000 feet/second. The speed of light is 186,000 miles/second. Velocity = Wavelength x Frequency

Velocity

  • Upload
    gen

  • View
    39

  • Download
    0

Embed Size (px)

DESCRIPTION

Velocity. The velocity of the wave is the measurement of how fast a crest is moving from a fixed point. The speed of sound is about 1000 feet/second. The speed of light is 186,000 miles/second. Velocity = Wavelength x Frequency. Velocity = frequency x wavelength. v = גּ f - PowerPoint PPT Presentation

Citation preview

Page 1: Velocity

Velocity The velocity of the wave is the measurement

of how fast a crest is moving from a fixed point.

The speed of sound is about 1000 feet/second. The speed of light is 186,000 miles/second.

Velocity = Wavelength x Frequency

Page 2: Velocity

Velocity = frequency x wavelength

v = ּג f

m/s m Hz (1/s) “distance” “time”

m•Hz = m•1/s = m/s

Page 3: Velocity

Frequency Frequency: The number of times the

wavelength occurs in one second. Measured in kilohertz (Khz), or cycles per second. The faster the sound source vibrates, the higher the frequency.

Higher frequencies are interpreted as a higher pitch. For example, when you sing in a high-pitched voice you are forcing your vocal chords to vibrate quickly.

measured in Hertz (Hz)1 Hz = 1/secondThe shorter the wavelength, the higher the

frequency

Page 4: Velocity

Simple Harmonic Motion

period, T:

frequency, f:

time to complete one cycle

# of cycles per second (Hz)

f1 T

T1

f

(s)

Page 5: Velocity

wall equilibrium position

frictionless floor

x = 0 Felas = 0

xmax

–xmax

v = 0 x = max

Felas = max

period of a mass-spring system:

km

2 T m = mass (kg) k = spring constant (N/m)

Page 6: Velocity

A 5.5 kg cat is attached to a fixedhorizontal spring of stiffness 22.8 N/mand is set in motion on a frictionlesssurface. Find the period of motion of…

…the cat.

…a 240 g mouse, with the same spring and surface.

Page 7: Velocity

What stiffness must a spring have so that the periodof the mouse’s motion is the same as that of the cat?

Ballpark answer: Need a “less stiff” spring; k < 22.8 N/m.

Page 8: Velocity

A 1275 kg car carries two passengerswith a combined mass of 153 kg. Thecar has four shock absorbers, each witha spring constant of 2.0 x 104 N/m. Findthe frequency of the vehicle’s motionafter it hits a pothole.

Page 9: Velocity

restoring force:

simple harmonic motion (SHM):

For a mass-spring system,Hooke’s law applies:

acts to move an objectback to equilibrium

Frestore x

Frestore = Felas = k x

As displacement increases, so does Frestore.

And when x = 0… Frestore = 0.

Page 10: Velocity

KE = ½ m v2

energy:

kinetic energy, KE: energy of mass m having velocity v

m (kg); v (m/s)

the ability to do work

KE = max. at eq. pos.; KE = 0 at xmax.

Page 11: Velocity

PEelas = ½ k (x)2

potential energy, PE: stored energy

For a spring with spring constant k and “stretch” x:

k (N/m); x (m)

For a mass m at a height h above a reference line:

m (kg); h (m);g = 9.81 m/s2

For m-s sys., PEelas is max at xmax and 0 at eq. pos.

PEg = m g h

For pend., PEg is max atxmax and min. at eq. pos.

Page 12: Velocity

amplitude, A: maximum displacement from equilibrium

Energy of a Mass-Spring System

frictionless

A A

Period T is not affected by amplitude A.

Energy (J)

total energy

PEelas

KE PEg

km

2T

Page 13: Velocity

The Pendulum

For < 15o, asimple pendulum

approximates SHM. mass mof bob

length Lamplitude

Energy of a Simple Pendulum

Energy (J)

total energy

PEg

KE PEelas

Page 14: Velocity

period of a simple pendulum:

The period of a pendulum is 5.2 s. Find…

A. …its length

B. …the mass of the bob

g L

2 T

Period T is independent of mass and amplitude.

Page 15: Velocity

Waves

vibrations moving through space and time

medium: the matter through which the energy of mechanical waves moves

Waves transmit energy, not matter.

Page 16: Velocity

transverse waves: particles of medium move to direction of wave travel

For a transverse wave:

amplitude A crest

wavelength

trough

Energy Amplitude2

Page 17: Velocity

longitudinal(compressional) wave:

particles of mediummove // to directionof wave travel

rarefaction compression

pulse wave:

periodic wave:

a single vibration

rhythmic, repeated vibrations

Page 18: Velocity

Wave Reflection

fixed boundary free boundary

v

v

v

v

A A

waves are reflectedand inverted

waves are reflectedand upright

Page 19: Velocity

http://www.acs.psu.edu/drussell/Demos/reflect/reflect.html

Page 20: Velocity

Wave Interference

Two waves (unlike two objects) can occupythe same place at the same time. This

condition is called interference.

constructive interference: destructive interference: displacements arein same direction

displacements arein opposite directions

A1 A2

A1 + A2

A1 A2

A2

A1

A1 – A2

A2

A1

Page 21: Velocity

Standing Waves

incident and reflected waves interfere so thatantinodes have a max. amplitude, while nodeshave zero amplitude

On a string, nodes remain motionless; antinodesgo from max. (+) to max. (–) displacement.

Page 23: Velocity

Standing Waves in Open Tubes

wavelength of nth

harmonic of an open tube:

n = 1

L

1 = 2 L n = 2 2 = L

n = 3 3 = 2/3 L

nL 2

n (n = 1,2,3,…)

Page 24: Velocity

wavelength of nth

harmonic on a string:

n = 1; 1st harmonic (fundamental)

n = 2; 2nd harmonic(1st overtone)

n = 3; 3rd harmonic(2nd overtone)

n = 4; 4th harmonic(3rd overtone)

nL 2

n (n = 1,2,3,…)

1 = 2 L

2 = L

3 = 2/3 L

4 = ½ L

L

Page 25: Velocity

Waves travel along a 96.1 cmguitar string at 492 m/s. Find thefundamental frequency of the string.

Find the frequency ofthe 5th harmonic.

frequency of the nth harmonic:

nL 2

n

Page 26: Velocity

Find the fundamental frequencyfor an open tube of length 1.24 m and a velocity of 343m/s

1.24 m

nL 2

n

Page 27: Velocity

Closed Tubes

wavelength of nth

harmonic of a closed tube:

n = 1

L

1 = 4 L n = 2

2 = 2 Ln = 3

3 = 4/3 L

nL 4

n (n = 1,3,5,…)

(even harmonicsare not present)

Page 28: Velocity

Find fundamental frequency for a Closed tube in the third harmonic of length 1.24m and a Velocity of 350m/s .

nL 4

n

Page 29: Velocity

Sound

compression:

rarefaction:

20 Hz 20,000 Hz

high pressure / high density

low pressure / low density

audiblefrequencies

(humanhearing)infrasonic ultrasonic

Page 30: Velocity

Fundamental frequency determines pitch.

high pitch high f =

low f =

= short

low pitch = long

Page 31: Velocity

Number and intensity of an instrument’s harmonicsgive it its unique sound quality, or ________.timbre

f1 f2 f3 f4 f1 f2 f3 f4

f1 f2 f3 f4 f1 f2 f3 f4

Page 32: Velocity

The Doppler Effect Relative motion between wave source and observercauses a change in the ____________ frequency. observed

fobserved

fobserved

(higher)

(lower)

femitted femitted

femitted

v = 0

Page 33: Velocity

Other examples of Doppler effect:

police radar

race cars

expansion of universe dolphins (echolocation)

R O Y G B V

Sun

most stars (“red-shifted”)

Page 34: Velocity

Traveling Very Fast

vbug = 0 vbug < vwave

vbug = vwave vbug > vwave

bow wavewave barrier

Page 35: Velocity

supersonic: “faster than sound” (vs. subsonic)

sonic boom:

shock wave: a 3-D bow wave

caused by high-pressureair, not roaring engine

cracking bulletslion tamer’s whip

The Matrix

Page 36: Velocity

Sound Intensity

If a piano’s power output is 0.302 W,find the sound intensity at a distance of…

A. …1.0 m

B. …2.0 m

r 4

P I 2

Page 37: Velocity

Intensity is related to volume (or relative intensity):

--

-- measured in decibels (dB)

A difference of 10 dB changesthe sound intensity

by a factor of 10 andthe volume by a factor of 2.

50 dB 40 dB 60 dB 90 dB

how loud we perceive a sound to be

half as loud 1/10 as intense

8X louder

1000X more intense

Page 38: Velocity

Beats

alternating loud-and-soft sounds resultingfrom interference between two slightly-different frequencies

Equation: f - f f 21beat

1 second elapses 1 second elapses

f 1 =

16

Hz

f 2 =

18

Hzf 1 =

16

Hz

f 2 =

17

Hz

fbeat = 1 Hz fbeat = 2 Hz

Page 39: Velocity

Forced Vibrations and Resonance

natural frequency:

forced vibration:

resonance:

-- result of resonance =

the frequency at which anobject most easily vibrates

a vibration due toan applied force

occurs when a force is repeatedlyapplied to an object AT the object’s natural frequency

large amplitude

Page 40: Velocity

Examples:

swing

shattering crystal wine glasses

Tacoma Narrows Bridge (1940)

British regiment (Manchester, 1831)

aeolian harps

“The wind in the wires made a tattletale sound,as a wave broke over the railing…”

Page 41: Velocity

f1 T

T1

f

km

2 T

Frestore = Felas = k x

KE = ½ m v2

PEelas = ½ k (x)2

PEg = m g h

g L

2 T

f

T v

vsound = 331 + 0.6Ta

nL 2

n

fn = n f1

nL 4

n

r 4

P I 2

f - f f 21beat