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Unit 6Unit 6Chemical ReactionsChemical Reactions
General ChemistrySpring 2010
NOMENCLATURE NOMENCLATURE REVIEWREVIEW
Section 1
IonicIonicBasic Rules
◦These have a cation (+) and an anion (-)◦Usually a metal and a nonmetal◦Sometimes contain polyatomic ion(s)
(back of PT)
◦Pay attention to charges Overall charge on ENTIRE formula has to be
ZERO Use subscripts to add charge to make zero Criss-cross is a shortcut but be careful!
◦Practice this on the next slide
Basic Ionic FormulaBasic Ionic Formula Give the formulas for the following
compounds w/o PAI
◦ Potassium sulfide
◦ Magnesium oxide Give the formulas w/ PAI
◦ (DON’T CHANGE THE FORMULA)
◦ Aluminum nitrate
◦ Calcium phosphate
Transition MetalsTransition MetalsIn the name, charge on TM is in ()
◦Ex) Iron (III) chloride
◦Ex) Tin (II) fluoride Use that charge to do criss-cross
To figure out the TM charge do reverse criss-cross. The charge is on ONE TM!
◦Ex) CuO
◦Ex) Cu2O
Covalent NomenclatureCovalent Nomenclature NO CRISS CROSS!!! NO REDUCE!!! The subscript after the symbol = the prefix in
the name The prefix in the name = the subscript in the
formula (what are these rules?)
1. Ex) NO2
2. Ex) N2O
3. Ex) Sulfur hexafluoride
4. Ex) Triphosphorus pentachloride
Diatomic molecules
AcidsAcidsEvery acid formula begins with hydrogenThe other half is either a halogen or a
polyatomic ion◦ Halogen? Use “hydro” in name
Ex) HCl
Ex) HF
◦ Polyatomic? Change ending to “-ic” (for this class)
Ex) H3PO4
Ex) H2SO4
# of H’s is the charge on the PAI
Section 2Section 2Counting Atoms Review
SubscriptSubscriptIndicates the number present Only applies to the element it’s
withAlCl3
◦One aluminum and three chlorines
SubscriptsSubscriptsWhen an element has no
subscript◦The implied subscript is ONE
◦Ag1 = Ag
CoefficientCoefficientAffects anything behind itMultiply everything by the
coefficient3 AlCl3
◦Three aluminums and nine chlorines
Section 3Section 3Reaction Basics
Chemical EquationsChemical EquationsThe “sentences” of chemistryShow how elements react with each other
and what compounds they will form
So that’s what happens when
sodium and water mix!!!!
Parts of a chemical Parts of a chemical EquationEquationReactants
◦Always on the left of the equation◦What the reaction STARTS with
Products◦Always on the right of the equation◦What is produced from the reaction
(made)Yield
◦Arrow◦Where the reaction actually occurs
Can you show me what you just said???
Mg + O2 MgO
Reactants Products
Yield Sign
Symbols in Equations (Table Symbols in Equations (Table 11.1)11.1)
Symbol Explanation
+ Used to separate 2 reactions or 2 products
“Yields,” separates reactions from products
Used in place of for reversible rxns
(s) Designates a R or P in the solid state; placed after the formula
(l) A R or P in the liquid state; placed after formula
(g) “ ” in the gas state; “ ”
(aq) Designates an aqueous solution; the substance is dissolved in water; placed after formula
heat Indicates that head is supplied to the rxn
PtA formula written above the yield sign indicates its use as a catalyst (in this example, platinum)
Section 4Section 4Inventory Reactions
Law of Conservation of Law of Conservation of MassMassThe reason we balance reactionsMatter is neither created nor
destroyed◦Must account for all elements
Before and after reaction
Antoine-Laurent de Lavoisier
was the first to state this law.
Reaction AnatomyReaction Anatomy
KClO3 KCl + O2
K 1
Cl 1
O 3
K 1
Cl 1
O 2
Reactant(s) Products
InventoryInventoryCompare the number of each atom in the
reactants to the products◦ If equal = “balanced reaction”
Abides by the law of conservation of mass◦ If not equal = “not balanced”
Does not abide by the law of conservation of mass; MUST BALANCE
KClO3 KCl + O2
K 1
Cl 1
O 3
K 1
Cl 1
O 2
“Not balanced”
Reactant(s) Products
Section 5Section 5Balancing Reactions
BalanceBalance
1. Inventory first2. Locate one element that does not balance3. Add a coefficient to make it balance
◦ NEVER TOUCH A SUBSCRIPT◦ Look to make odd numbers even
4. Re inventory5. Repeat until balanced
KClO3 KCl + O2
K 1
Cl 1
O 3
K 1
Cl 1
O 2
2
2
2
6
32
2
2
6
balanced
It’s best to leave H and O for the end
BalancingBalancingWhen balancing a chemical
equation you may only change the coefficient (big number in front of the substance)
Balancing example #1:◦ Mg(s) + O2(g) MgO(s)
1 Mg 12 O 1
2 2
2 / / 2 / 2
Balance Combustion = 2 Balance Combustion = 2 CHORCHOR
Combustion is any reaction with CO2 + H2O for products2…coefficient of 2 in front of big hydrocarbonC…balance carbonsH…balance hydrogenO…balance oxygenR…reduce if possible (divide by a common factor, like 2)
C7H16 + O2 CO2 + H2O 2 14 16 22 1 11 7 8
H C
Balancing (cont.)Balancing (cont.)
When balancing a chemical equation you may only change the coefficient (big number in front of the substance)
Balancing example #3:◦ NaOH(aq) + H2SO4(aq) Na2SO4(aq) +
HOH(l)
1 Na 21 OH 12 H 11 SO4 1
22
/ 2 / 2
2 / 2 / Count
polyatomic ions as one
piece!
Practice Problem #1Practice Problem #1
Balance the following reactions:◦ P4(s) + O2(aq) P4O10
◦ Zn + HCl ZnCl2 + H2(g)
◦ Mg(s) + O2(g) MgO(s)
◦ KClO3 KCl + O2(g)
5
2
22
2 2 3
Section 6Section 6Reaction Types
Reaction TypesReaction TypesChemical reactions are classified
into 5 different types:◦This makes it easier to see what is
happening in a reaction◦This makes it easier to predict
products in a reaction
Sorting into piles makes it easier to
see the similarities and
differences
Reaction Types (cont.)Reaction Types (cont.)Five reaction types
◦1) Synthesis (Combination)◦2) Decomposition◦3) Single Replacement◦4) Double Replacement◦5) Combustion
Now let’s look at each type individually
Please NotePlease NoteThe following reactions are not
balancedThe examples are only used to
show the type of reaction
Synthesis = S Synthesis = S (Note: The book uses the term “combination;” it’s the (Note: The book uses the term “combination;” it’s the same thingsame thing))
Two or more substances react to form one new compound
Element + element new compoundcompound + compound new
compoundExamples
◦H2 + N2 NH3
◦Mg + O2 MgO (magnesium oxide)
Decomposition = DDecomposition = D
One compound breaks into two or more simpler products
Compound element/compound + element/compound
Examples◦Na2O Na + O2
◦NH4NO3 N2O + H2O Ammonium nitrate, when heated,
explosively breaks down!
Single Replacement = SRSingle Replacement = SRElement + compound new
element + new compoundExamples
◦AlCl3 + O2 Al2O3 + Cl2◦H2(SO4) + K K2(SO4) + H2
◦Br2 + NaI NaBr + I2◦Br2 + NaCl No Reaction
Halogen activity decreases as you go down group
Activity SeriesActivity SeriesWhether one metal
displaces another depends on upon the reactivities of the metals
A reactive metal will replace any metal listed below it on the activity series◦ Ex) iron will displace
copper from a copper compound, but iron does not similarly displace zinc or calcium
Double Replacement = DRDouble Replacement = DRCompound + compound new
compound + new compoundExamples
◦Na2O + MgBr2 NaBr + MgO
◦H(NO3) + Mg(OH)2 H(OH) + Mg(NO3)2
Which switch? Think about Paula Abdul when you rewrite the formulas!
Combustion = CCombustion = C
An element or a compound reacts with oxygen, usually producing heat and light
Always involves oxygen as a reactantReaction with CO2 + H2O for productsExamples
◦C6H12O6 + O2 CO2 + H2O
◦2 C8H18 + 25 O2 16 CO2 + 18 H2O
Visual Review of Types of Visual Review of Types of ReactionsReactions
Single Replacement
Double Replacement
Combustion
Decomposition Synthesis
Section 7Section 7Predicting Products(p.338-339)
Synthesis (cont.)Synthesis (cont.)
Steps to predict products:◦ 1. Combine the two
reactants in one product (switchy switchy
◦ 2. Balance
Steps in the Irish Countryside
Practice Problem #4Practice Problem #4
Predict the product and balance:◦ Mg(s) + O2(g)
◦ Be(s) + Br2(g)
◦ Cs(s) + S2(g)
MgO(s)
BeBr2(s)
Cs2S(s)
22
4 2
Decomposition (cont.)Decomposition (cont.)
Steps to predict products:◦ 1. Break the one
reactant into two products Don’t forget about
diatomic moleculesH, N, O, F, Cl, Br, I
◦ 2. Balance
Ancient Steps in Cancun, Mexico
Practice Problem #5Practice Problem #5
Predict the products and balance:◦ MgCl2(s)
◦ FeS(s)
◦ NaI(s)
Mg(s) + Cl2(g)
Fe(s) + S(s)
Na(s) + I2(s)2 2
Single Replacement (cont.)Single Replacement (cont.)
Steps to predict products:◦ 1. Figure out which metal is
going to replace which other metal
◦ 2. Write the products: One metal is now by itself One metal is now part of a
compound (Switchy Switchy)
◦ 3. Balance
Steps to the House of the Ñusta at Machu Picchu
Practice Problem #2Practice Problem #2
Predict the products and balance:◦ K(s) + MgS(aq)
◦ Ba(s) + Au(C2H3O2)3(aq)
◦ Zn(s) + HCl(aq)
Mg(s) + K2S(aq)
Au(s) + Ba(C2H3O2)2(aq)
H2(s) + ZnCl2(aq)
2
33 2 2
2
Double Replacement (cont.)Double Replacement (cont.)
Steps to predict products:◦ 1. Figure out which
metal is going to trade partners with which other metal
◦ 2. Write the products: One metal is now in a
compound with the other anion (switchy switchy)
One metal is now in a compound with the other anion (switchy switchy)
◦ 3. BalanceSteps on a Sand Dune at the
edge of the Gobi Desert
Practice Problem #3Practice Problem #3
Predict the products and balance:◦ FeS(s) + HCl(aq)
◦ CaCl2(aq) + H2SO4(aq)
◦ NH4I(aq) + AgNO3(aq)
FeCl2(aq) + H2S(g)
HCl(aq) + CaSO4(s)
NH4NO3(aq) + AgI(s)
2
2
Combustion (cont.)Combustion (cont.)
Steps to predict products:◦ 1. Write CO2 and H2O as
the products◦ 2. Balance…2CHOR
1st balance C 2nd balance H 3rd balance O
Steps to the Lincoln Memorial
Practice Problem #6Practice Problem #6
Predict the products and balance:◦ C3H8 (g) + O2(g)
◦ C5H12O(s) + O2(g)
◦ C4H10(s) + O2(g)
CO2(g) + H2O(l)
CO2(g) + H2O(l)
CO2(g) + H2O(l)
5 3 4
2 15 10 12
2 13 8 10
Section 8Section 8Reaction Rates and Equilibrium
Energy BasicsEnergy BasicsFor a reaction to proceed…
◦Reactants’ bonds must break◦Bonds must reform to make products
Energy is required to break reactants apart (their bonds)
Reactions either gain or lose energy, they never stay the same
Activation EnergyActivation EnergyBonds must break in order to
reformEnergy required to break bonds
= ACTIVATION ENERGYAll reactions require thisThe activation energy is always
positive
Energy DiagramEnergy DiagramReactants Products
NaBr + Li(OH) LiBr + Na(OH)
Ene
rgy
in K
ilojo
ules
(kJ
)
Time
Ener
gy o
f rea
ctan
ts
Ene
rgy
of p
rodu
cts
Energy DiagramEnergy DiagramReactants Products
NaBr + Li(OH) LiBr + Na(OH)
Ene
rgy
in K
ilojo
ules
(kJ
)
Time
Reactants
Products
The difference between the energy of reactants and products =
The total heat or energy of the reaction
OR
ΔΔHH (change in heat) (change in heat)
Activation EnergyActivation Energy
Reactants
Products (bonds have reformed)
NaBr + Li(OH)
LiBr + Na(OH)
Na+1
Li+1Br-1
(OH) -1
Bonds are brokenBonds are broken
Take
s Ene
rgy
The energy required to break the reactants’ bonds =
ACTIVATION ENERGYACTIVATION ENERGY
Reactants Products
NaBr + Li(OH) LiBr + Na(OH)
Activated ComplexActivated ComplexE
nerg
y in
Kilo
joul
es (
kJ)
Time
Na+1
Li+1Br-1
(OH) -1
Bonds are brokenBonds are broken
Reactants Products
NaBr + Li(OH) LiBr + Na(OH)
Reactants
Products
The point at which all bonds have been broken and products begin to reform =
ACTIVATED COMPLEXACTIVATED COMPLEX
SummarySummaryE
nerg
y in
Kilo
joul
es (
kJ)
Time
Reactants Products
NaBr + Li(OH) LiBr + Na(OH)
Reactants
Products
Activated Complex
Activation Energy
Total heat of reaction or ΔH
Rates of ReactionRates of ReactionWays to make reactions happen
faster:◦Make chemicals at higher
concentration◦Increase the temperature◦Make the particles smaller◦Add a catalyst
Rates of Reactions (cont.)Rates of Reactions (cont.)Catalysts lower the activation energy
Heats of ReactionHeats of Reaction
Reactions can either…◦Give off heat
Exothermic The energy level at the end of the reaction is
lower than the energy level at the beginning of the reaction
Therefore, the change in heat (∆H) is negative◦Take in heat
Endothermic The energy level at the end of the reaction is
higher than the energy level at the beginning of the reaction
Therefore, the change in heat (∆H) is positive
Feels Hot
Feels Cold
Exothermic Reaction◦ Reaction loses heat◦ ΔH value is always
negative
Endothermic Reaction◦ Reaction gains heat◦ ΔH value is always
positive
energy
time
energy
time
Exo vs Endothermic Reactions
Bond Formation (cont.)Bond Formation (cont.)
Example #1◦ Endo or
exothermic?
◦ Energy of the Activated complex?
◦ ∆H?
Reactants (500 kJ)
Products (200 kJ)
Act. Energy (150 kJ) Exothermic
650 kJ
-300 kJ
Bond Formation (cont.)Bond Formation (cont.)
Example #2◦ Endo or exothermic?
◦ Activation energy?
◦ Energy of products?
Endothermic
750 kJ
600 kJ
Reactants (200 kJ)
∆H (400 kJ)
Activated Complex (950 kJ)