BAB 3030.15 Diket: E = 7,7 kV/m, B = 0,14 T Dit: v? Jwb : 30.17
Diket: v = 1,0 x 107 m/det,r = 1,55 m,B = 0,134 Wb/m2,q= 1,6 x
10-19 Dit: m? Jwb: 30.19 Diket: v = 5,0 x 106 m/det, = 20o, r =
1,55 m, B = 20 mT = 2 x 10-3 T me = 9,1 x 10-31 kg, q = 1,6 x 10-19
C Ditanyakan: r? x?Jawab : Gaya ini tegak lurus terhadap sehingga
membelokkan elektron. Mengikuti lintasan melingkar.sin 20o = 0,3420
cos 20o = 0,9397vI= sin 20o. v = (0,3420)(5,0x106 m/det) =
1,7101x106 CvII= cos 20o. v= (0,9397)(5,0x106 m/det) = 4,6985x106
m/det = 0,49 cm = 1,799x10-8 det (4,6985x106 m/det)(1,799x10-8 det)
= 8,5 cm30.21 Diket: L = 0,15 m, I = 6 A, r = 1,55 m, B = 0,40 T
Dit: a. Fm (90o)? b. Fm (30o)?Jwb : a. Fm = ILB sin 90o =
(6)(0,15)(1) = 0,36 N b. Fm = ILB sin 30o = (6) (0,15)(0,5) = 0,18
N30.23 Diket : LAB = LDE = L, LBC = 0,16 m, LCD = 0,2 m, I = 5A,
AB= DE= 180o, BC= 90o, CD= 55o, B = 0,15 T Dit: FAB? FBC? FCD?Jwb:
FAB = ILB sin 180o = (5)(L)(0) = 0 NFBC = ILB sin 90o =
(5)(0,16)(1) = 0,12 N FCD = ILB sin 55o = (5)(0,2)(0,82) = 0,12
N
