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1
CHAPTER-7 TRANSISTOR AT LOW
FREQUENCY
2
7.1 Transistor Amplifier Circuit:-Transistor equivalent ckt are divided in two
types (i) D.C. equivalent ckt. (ii) A.C. equivalent ckt.
Fig.7.1(a) Transistor Amplifier using Self Bias
3
4
Fig.7.1(b) D.C. Equivalent Ckt.
Fig.7.1(c) A.C. Equivalent ckt.
5
The capacitors CC1 & CC2 are called the coupling capacitors. Capacitors CC1 is used to couple the a.c. input signal to the base of the transistor. A coupling capacitor is also called a blocking capacitor because it blocks d.c.
Another capacitor CE is called bypass capacitor because it bypasses the all a.c. current from the emitter to ground.
6
7.2 Hybrid Parameter (h-Parameter):- h-parameter is widely used because they gives
accurate results & can be measured very easily. The transistor is a three terminal device but if one
terminal is grounded, then transistor can be used as a two port network.
The h-parameters are
V1=h11I1+h12V2
I2=h21I1+h22V2
The parameter h11, h12, h21 & h22 are called h-parameters.
7
Fig.7.2 (a) General h-parameter Equivalent Circuit
Fig.2.2(b) Transistor Two Port Network
8o22
1-
2
222
r12
2
112
f21
1
221
i11
1
111
hh as, drepresente also isit
mho.or ohm isunit & ckt.open I/P with admittance O/Ph
hh as, drepresente also isit
unit. no has & circuitedopen I/Pgain with voltageReverseV
Vh
hh as drepresente also isit
none. isunit & shorted O/Pgain with current forwardI
Ih
hh as, drepresente also isit
ohm isunit & shorted O/P with impedance I/PI
Vh
as, summarized isparameter -h the
V
I
9
7.3 h-Parameter Representation for Transistor:-Sr. No.
h-Parameter Common Emitter
Common Base
Common Collector
1. h11 hie hib hic
2. h21 hfe hfb hfc
3. h12 hre hrb hrc
4. h22 hoe hob hoc
10
7.4 Analysis of Transistor Amplifier by h-Parameter:-
Fig 7.4(a) General Amplifier Circuit with Source & Load Resistance
Fig 7.4(b) h-Parameter Equivalent Circuit of above General Amplifier
11
1. The Current Gain (Ai):- The current gain for the transistor amplifier is defined as the ratio of O/P current to the I/P current. Mathematically,
Ih)hR1(I
h.RI-IhI
get, weeq.(4)in V of value theputting Now
...eq.(4) VhIhI
...eq.(3) VhIhV
are, equations Parameters-h theNow
...eq.(2) .R-I.RIV
,V is minaloutput ter theacross voltage thefigure above from
...eq.(1) I
I-
I
IA
1foL2
oL21f2
2
2o1f2
2r1i1
L2LL2
2
1
2
1
Li
12
hR1
h-
I
I
I
I- A
hR1
h
I
I So
oL
f
1
L
1
2i
oL
f
1
2
13
2. The Input Resistance (Ri):- The I/P resistance Ri is defined as the resistance we see looking into the amplifier I/P terminals (1-1’). Mathematically,
i1
1rL
1
2i
1
1
1
rL21i1
2r1i1
L22
1
1i
RI
V But h.R
I
I-h
I
V
have, we.Iby sideboth on eq. above thedividing Now
h.RI-IhV
VhIhV
parameter -h of eq.in .R-IV of value theputting Now
I
VR So
14
Admittance Load R
1Y where
Yh
hhh
R1h
hhhR
Rh1
hRhhh.R
Rh1
h-hR so
Rh1
hA that know weh.RAh R
AI
I-but h.R
I
I-h R thereforeSo
LL
o
rfi
Lo
rfii
Lo
rLfirL
Lo
fii
Lo
firLiii
i1
2rL
1
2ii
L
15
3. The Voltage gain (Av):- The voltage gain is defined as the ratio of the O/P voltage V2 to I/P voltage V1.
Mathematically,
oL
frii
Lo
fi
i
Livi
1
1
1
1Li
1
L1iv
1i21
2i
1
L2
1
2v
hR1
hhhR &
Rh1
hA that,know Again we
..eq.(2) R
RAA So, R
I
V But
V
IRA
V
RIAA Therefore
IAIor I
IA that,Know weSince
eq.(1) ... V
RI
V
VA
16
hh-hhΔh where
R.Δhh
RhA
R.Δhh
Rh
Rhh-hhh
RhA
hR1
hhh
Rh1Rh-
A
have, then weeq.(2)in value theseputting now
froi
Li
Lfv
Li
Lf
Lfroii
Lfv
oL
fri
Lo
Lf
v
17
4. Output Resistance (Ro) :- The O/P resistance may be calculated by reducing the source voltage Vs to source & load resistance RL to infinity & driving the O/P terminals by a voltage generator V2. as shown below,
Fig.7.4(c) h-equivalent ckt. to calculate the O/P resistance
O/P resistance Ro is the ratio of the voltage V2 & the current drawn from the voltage source I2
So Ro=V2/I2
18
2ois
2rf
2
2ois
2rf
2o
1
is
2r1
2r1is
2r1i1s
2o1f
2o
2o1f2
VhhRVhhV
VhhR
Vhh
VR
get, weeq.(1)in I of value theputting Now
...eq.(2) hR
VhI
VhIhR or
0VhIhIR
fig.7.4(c)in shown as ckt. theof side I/P the toKVL Applying
...eq.(1) VhIh
VR hence
VhIhI eq.parameter -h from
19
Δh
hR
be, willresistance O/P then 0R resistance source if
hhhhΔh where ΔhRh
hRR ,
hhhhRh
hR
hhhRh
hRR
get, wearrangingRe
io
s
rfioso
iso
rfioso
is
rfiso
iso
So
20
5. The Overall Voltage Gain (Avs):- The overall voltage gain of the transistor amplifier is the ratio of O/P voltage V2 to the source voltage Vs . It is denoted by Avs.
Fig 7.4(d) Equivalent I/P ckt.
...eq.(1) .AA fore thereV
VA but,
V
V
V
VA gain, voltageoverallally Mathematic
1vvs
1
2v
1
1
2
s
2vs
s
s
V
V
V
V
21
0)(R source
voltageidealan gain with voltage theis A therefore
AAen th0R if
RZ
ZA.AA
get, weeq.(1)in /VV of value theputting
RZ
Z
V
Vor
RZ
.ZVV
have, wefigure from resistance I/P
amplifier therepresents Zhere ckt. equivalent from now
s
v
vvss
si
iv
1vvs
s1
si
i
s
1
si
is1
i
sV
V
22
6. Overall Current Gain (Ais):- overall current gain of the transistor amplifier is the ratio of the O/P current (IL) to the current delivered by the source (Is)
Fig 7.4(e) Modified I/P Equivalent ckt.
1
2i
s
1
1
2is
s
2
s
Lis
I
IAbut ...eq.(1)
I
I
I
IA but,
have, weexpression above themodifying
I
I
I
IA gain,Current overallally Mathematic
23)(R sourcecurrent idealan gain with current
theis A thereforeAA then R if Now
ZR
RA
I
I.AA
get, weeq.(1)in I
I of value theputting now
...eq.(2) ZR
R
I
I then
ZR
RII
have wefig.7.4(e) from ,resistance I/Pamplifier is Zhere
ckt., equivalent I/P modified use weA determine To
...eq.(1) I
I.AA So
s
iiiss
is
si
s
1iis
s
1
is
s
s
1
is
ss1
i
is
s
1iis
24
7.5 h-Parameter Expression for CE amplifier:-
Fig. 7.5 h-parameter equivalent circuit for CE amplifier
E
CB
EE
25
1. Current gain (Ai):-
hR1
h- A
Amplifier,Emitter Common for Gain Current
)Expression (General hR1
h- A
oeL
fei
oL
fi
R then Zresistance biasing
nofor & RR Zckt. bias fixed for the
R1h
hhhR
Amplifier, E-Cfor resistance I/P The
)Expression (General
R1h
hhhR
ii
Bii
Loe
refeiei
Lo
rfii
2. Input Resistance (Ri):-
26
hh-hhΔh where
R.Δhh
RhA amplifier, CEfor gain Voltage
)Expression (General R.Δhh
RhA
fereoeie
Lie
Lfev
Li
Lfv
3. Voltage Gain (Av):-
Loo
srefeieoe
soe
ieso
so
iso
RR Z
be willstageamplifier theof resistance O/P The
resistance source theis R & hhhhΔh where
amplifier) CE(for ΔhRh
hRR
)Expression (General ΔhRh
hRR
4. Output Resistance (Ro):-
27
fereoeie
si
i
Lie
Lfe
si
ivvs
si
iv
1vvs
hhhhΔh here
amplifier) CE(for RZ
Z
ΔhRh
Rh-
RZ
ZAA
)expression (general RZ
ZA.AA
sV
V
amplifier) CE(For ZR
R
Rh1
hA
)expression (General ZR
R
Rh1
h
ZR
RAA
is
s
Loe
feis
is
s
Lo
f
is
siis
5. Overall Voltage Gain (Avs):-
6. Overall Current Gain (Ais):-
28
Properties of Common Emitter Amplifier:-
1. Large current gain (Ai=100).
2. Large voltage gain (Av=500).
3. Large power gain (Ap=Av.Ai)
4. Moderate I/P impedance (50KΩ).
5. Moderate O/P impedance (10KΩ).
6. Phase shift is 180º bet I/P & O/P voltage.
29
1. Current gain (Ai):-
hR1
h- A
Amplifier, BaseCommon for Gain Current
obL
fbi
R Z
then,biasing no is theret.ifarrangemen biasing
upon the depends stageamplifier theof resistance i/p The
R1h
hhhR
Amplifier, B-Cfor resistance I/P The
ii
Lob
rbfbibi
2. Input Resistance (Ri):-
7.6 h-Parameter Expression for CB amplifier:-
30
hh-hhΔh where
R.Δhh
RhA amplifier, CBfor gain Voltage
fbrbobib
Lib
Lfbv
3. Voltage Gain (Av):-
Loo
srbfbibob
sob
ibso
RR Z
be willstageamplifier theof resistance O/P The
resistance source theis R & hhhhΔh where
ΔhRh
hRR
4. Output Resistance (Ro):-
31
rbfbibob
si
i
Lib
Lfb
si
ivvs
hhhhΔh here
RZ
Z
ΔhRh
Rh-
RZ
ZAA
ZR
R
Rh1
hA
is
s
Lob
fbis
5. Overall Voltage Gain (Avs):-
6. Overall Current Gain (Ais):-
The overall current gain for the CB amplifier is,
32
Properties of Common base Amplifier:-
1. current gain is less than 1(Ai<1).
2. Large voltage gain (Av=150).
3. Power gain is less than CE configuration (Ap=Av.Ai)4. Small I/P impedance (40Ω).5. Large O/P impedance (1MΩ).6. No voltage & current Phase shift.
33
1. Current gain (Ai):-
hR1
h- A
Amplifier,collector Common for Gain Current
ocL
fci
R Z
then,biasing no is theret.ifarrangemen biasing
upon the depends stageamplifier theof resistance i/p The
R1h
hhhR
Amplifier, C-Cfor resistance I/P The
ii
Loc
rcfcici
2. Input Resistance (Ri):-
7.7 h-Parameter Expression for CC amplifier:-
34
hh-hhΔh where
R.Δhh
RhA amplifier, CCfor gain Voltage
fcrcocic
Lic
Lfcv
3. Voltage Gain (Av):-
resistance source theis R
hhhhΔh where
ΔhRh
hRR
is,amplifier CC theof resistance O/P The
s
rcfcicoc
soc
icso
4. Output Resistance (Ro):-
35
rcfcicoc
si
i
Lic
Lfc
si
ivvs
hhhhΔh here
RZ
Z
ΔhRh
Rh-
RZ
ZAA
ZR
R
Rh1
hA
is
s
Loc
fcis
5. Overall Voltage Gain (Avs):-
6. Overall Current Gain (Ais):-
The overall current gain for the CC amplifier is,
36
Properties of Common Collector Amplifier:-
1. current gain is Very high (Ai=100).
2. Voltage gain is less than unity (Av<1).
3. Power gain is less than CE configuration (Ap=Av.Ai)
4. Large I/P impedance (750KΩ).
5. Small O/P impedance (50Ω).
6. No voltage & current Phase shift.
37
7.8 Simplified or Approximate model:- ..Simplified model are used to reduce the ckt complexity.
…If the load resistance RL is small it is possible to neglect the parameter hre & hoe and obtain the approx. equivalent ckt. as shown in fig.7.8 below. By using hoe.RL<=0.1 the error in calculating Ai, Av, Ri & Ro is less than 10%
Fig.7.8 h-parameter Approximate CE model
38
Parameter Symbol CE Approx.
CB Approx.
CC Approx.
Current Gain
Ai -hfe hfb=1 hfc
I/P Resistance
Ri hie hib hic+hfcRL
Voltage Gain
Av 1
O/P Resistance
Ro
ie
Lfe
h
Rh
oeh
1
obh
1
ib
Lfb
h
Rh
fc
icS
h
hR
39
7.9 Typical h-Parameter values for Transistor:-Sr. No.
h-Parameter Common Emitter
Common Base
Common Collector
1. hi 1100Ω 1100Ω 22Ω
2. hr 1
3. hf 50 -51 -0.98
4. ho 25μA/V 25μA/V 0.49μA/V
-410 2.5 4103
40
7.10 Conversion Expression for h-parameter:-
Sr. No. Common Base Common Collector
1. hic=hie
2. hrc=(1-hre)≈1
3. hfc=-(1+hfe)
4. hoc=hoe
fe
ieib h1
hh
refe
oeierb h
h1
hhh
fe
fefb h1
h-h
fe
oeob h1
hh
41
re model of Transistor:- re model of transistor is an alternate approach which
employs transistor beta & resistance values is gaining importance.
Advantage of using these models are:-
(1) Required parameters are easily available.
(2) Simple & easy procedure.
(3) Results obtained have a fairly good accuracy for the study of amplifier circuit.
Note:- In CE re-model hie=βre & hfe=β
In CB re-model hib=re & hfb=-1
Rest of the analysis is very similar to approx. analysis.
42
7.11 Giacoletto or hybrid π-Model:-
Fig. 7.11(a) Giacoletto or hybrid-π Model of a CE transistor
43
Fig. 7.11(b) Diagram showing virtual base B’ & ohmic base spreading resistance rbb’
44
7.12 Hybrid-π Parameter Values:-The typical magnitude for the element of the hybrid π Parameter Values at room temperature & for IC=1.3mA are,
gm=50mA/V, rbb’=100Ω, rb’e=1K Ω
rb’c=4MΩ, rce=80K Ω Cb’c=3pF
Cb’e=100pF
45
7.13 Relationship bet low frequency h-parameter & high frequency or π- Parameters :-
cb'feoece
ce
re
eb'
cb'cb'
eb'iebb'
fe
meb'
m
feeb'
C
T
Cm
)gh(1hr
1g (V)
h
r
g
1r (IV)
r-hr (III)
h
ggor
g
hr (II)
26
)mAin (I
V
Ig (I)
46
unity. todropsgain current
ckt.short CE heat which trequency theis f
CCCC
f2
gC (VI)
T
DeTeDeeb'
T
meb'
47
7.14 Frequency Response of an Amplifier:-
Fig. 7.14(a) Typical R-C Coupled Amplifier Frequency Response
48
If the I/P voltage of an amplifier is kept constant but its frequency is varied, it is found that the amplifier gain,
remains practically constant over a sizable range of the mid frequency.
Decrease at low as well as high frequencies.
thus in frequency response curve three values of frequency are important,
(i) Mid frequency range.
(ii) Lower cutoff frequency, fL.
(iii) Upper cutoff frequency, fH
49
7.15 Frequency Response Parameter:- The β cut off frequency fβ is the CE short ckt small signal
forward current transfer ratio cut off frequency. It is given by,
fα is the cut off frequency at which the CB short ckt small signal forward current ratio drops 3dB from its value at low frequency.
b'eb'cb'eβ )rcCπf
(2
1
b'eb'e
fe
b'efbb'e rπC
h
)rhπCf
21(2
1
50
fT is the frequency at which the short ckt. Common emitter current gain attains unit magnitude.
cbeb
mT CC
gf
''2
51
7.16 Cascaded Amplifier:-
Fig. 7.16(a) Cascaded Amplifier
When the amplification of a single stage transistor is not sufficient for a particular purpose then two or more stages are connected in cascaded Then the required level of amplification is achieved.