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Torque Force applied at a distance causing a rotating effect

Torque Force applied at a distance causing a rotating effect

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Page 1: Torque Force applied at a distance causing a rotating effect

TorqueForce applied at a distance

causing a rotating effect

Page 2: Torque Force applied at a distance causing a rotating effect

Center of Gravity

The point at whichall of the weightof the object canbe considered tobe concentrated

All measurements are made to the center of gravity

Page 3: Torque Force applied at a distance causing a rotating effect

Torques

Page 4: Torque Force applied at a distance causing a rotating effect

The “torque arm” must always be measured perpendicular to the direction of the force.We will only be studying torques appliedperpendicular to the bar.

Page 5: Torque Force applied at a distance causing a rotating effect

Translational Equilibrium• All forces are balanced

• There is no linear acceleration

• The way we use this with rotary motion is we say:

• “The Up Forces equal the Down Forces”

• These forces are “coupled”: they do not need to act on the same point, just on the same plane

Page 6: Torque Force applied at a distance causing a rotating effect

Translational Equilibrium

• If the up forces = the down forces, then

• Fa = Fb and the bar will not have a tendency to change its linear motion

Page 7: Torque Force applied at a distance causing a rotating effect

Rotational Equilibrium

• Clockwise Torques = Counterclockwise Torques• Must be true about any pivot point• Therefore, in doing torque problems, choose a

pivot point that eases calculation

Page 8: Torque Force applied at a distance causing a rotating effect

Summarizing Problem Solving Strategy:

Σ CW = Σ CCWAlways used

Σ Up F = Σ Down FNot always necessary to use this

Page 9: Torque Force applied at a distance causing a rotating effect

Example 1A nonuniform bar is 4.5 m long and weighs 640 N. It is balanced when a 270 N weight is hung 0.80 from the light end of the bar and the bar is pivoted at the center. Where is the center of gravity of the bar? ANS: 1.6 m from heavy end

Page 10: Torque Force applied at a distance causing a rotating effect

Example 2Two workers carry a nonuniform beam weighing 730 N. The beam is 2.6 m long and its center of gravity is 1.1 m from one end. If the workers hold the beam at its ends, how much does each worker lift? ANS: 310 N and 420 N

Page 11: Torque Force applied at a distance causing a rotating effect

Practice Problems:

A nonuniform bar is 3.8 m long and has a weight of 560 N. The bar is balanced in a a horizontal position when it is supported at its geometric center and a 340 N weight is hung 0.70 m from the bar’s light end. Find the bar’s center of gravity. ANS: 1.2 m from heavy end

A large wooden beam weighs 820 N and is 3.2 m long. The beam’s center of gravity is 1.4 m from one end. Two workers begin carrying the beam away. If they lift the beam at its ends, what part of its weight does each worker lift? ANS: 460 N and 360 N.