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Topic: Enthalpy and Table I Do Now: packet p.1

Topic: Enthalpy and Table I Do Now: packet p.1. Chemistry is the study of matter and energy. So far we have learned about the types of matter and how

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Page 1: Topic: Enthalpy and Table I Do Now: packet p.1. Chemistry is the study of matter and energy. So far we have learned about the types of matter and how

Topic: Enthalpy and Table I

Do Now: packet p.1

Page 2: Topic: Enthalpy and Table I Do Now: packet p.1. Chemistry is the study of matter and energy. So far we have learned about the types of matter and how

Chemistry is the study of matter and energy. So far we have learned about the types of matter and how they can physically combined to make mixutures or

chemically combine in chemical reactions to from new compounds.Every physical or chemical change is accompanied by energy change

Energy released = _________________

Energy absorbed = _______________

exothermic

endothermic

G

L

S

exot

herm

ic

endothermic

The universe wouldn’t exist without energy. It provides all our work, our heat, can be stored to use

later and it never goes away (conservation of energy) The total amount of energy a substance contains depends on many factors, some of which are not

totally understood…it’s impossible to know the total heat content of a substance.

So scientists measure scientists can measure the amount of heat lost or gain by a system

Page 3: Topic: Enthalpy and Table I Do Now: packet p.1. Chemistry is the study of matter and energy. So far we have learned about the types of matter and how

H = Enthalpy = heatΔH = Heat of Reaction

The heat gained or lost by the system (at constant pressure)

ΔH = Hproducts – Hreactants

ΔH=Q

Energy is stored in chemical bonds

Page 4: Topic: Enthalpy and Table I Do Now: packet p.1. Chemistry is the study of matter and energy. So far we have learned about the types of matter and how

For any reaction occurring at constant pressure ΔH = Q

• Q = mCT– Q = Energy change

– m = mass of water

– C = specific heat of water

– T = temperature change = Tf – Ti

4Fe(s) + 3O2(g) 2Fe2O3(s) + 1625 kJOR

4Fe(s) + 3O2(g) 2Fe2O3(s) H = -1625 kJ (heat is lost)

NH4NO3(s) + 27 kJ NH4+(aq) + NO3

-(aq)OR

NH4NO3(s) NH4+(aq) + NO3

-(aq) H = 27 kJ (heat is gained)

Page 5: Topic: Enthalpy and Table I Do Now: packet p.1. Chemistry is the study of matter and energy. So far we have learned about the types of matter and how

If ΔH is negative…- ΔH = exothermic – heat is lost

- Hproducts < Hreactants

- PE of Products < PE of Reactant- Example: 4Fe(s) + 3O2(g) 2Fe2O3(s) + 1625 kJ

- ΔH = -1625kJ

Page 6: Topic: Enthalpy and Table I Do Now: packet p.1. Chemistry is the study of matter and energy. So far we have learned about the types of matter and how

If ΔH is positive…+ ΔH = endothermic – heat is gained

- Hproducts > Hreactants

- PE of Products > PE of Reactant

Example: NH4NO3(s) + 27 kJ NH4+(aq) + NO3

-(aq)- ΔH = +27kJ

Page 7: Topic: Enthalpy and Table I Do Now: packet p.1. Chemistry is the study of matter and energy. So far we have learned about the types of matter and how

Universe

Environment

System A

B

Since energy is conversed…the system changes in one direction and the surrounding have to change in the opposite direction

A. Reaction is Exothermic, environment gets _________________

B. Reaction is Endothermic, environment gets _________________

warmer

colder

Page 8: Topic: Enthalpy and Table I Do Now: packet p.1. Chemistry is the study of matter and energy. So far we have learned about the types of matter and how

Since there are different types of reactions, you have various ΔH’s

• ΔHcomb = enthalpy (heat) of combustion – the enthalpy change for the complete bunring of one mole of the substance

• ΔHformation = enthalpy (heat) of formation – the enthalpy change for the formation of a compound from its constituent elements

• ΔHsolution = enthalpy (heat) of solution – the enthalpy change when 1 mole of an ionic substance is dissolved in water.

Look at Table I: Heats of ReactionLets label the various types from above

Page 9: Topic: Enthalpy and Table I Do Now: packet p.1. Chemistry is the study of matter and energy. So far we have learned about the types of matter and how

• Rxns 1-6: combustion rxns

-H = heat of combustion

• Rxns 7-18: formation (synthesis) rxns

– Substance is formed from its elements

– H = heat of formation

• Rxns 19-24: dissolving equations

– H = heat of solution

Table I

Page 10: Topic: Enthalpy and Table I Do Now: packet p.1. Chemistry is the study of matter and energy. So far we have learned about the types of matter and how

Many other processes other than chemical reactions absorb or release energy

like, Changes of state

Hvaporization = molar heat of vaporization

= amount of heat required to vaporize one mole of a liquid

Hfusion = molar heat of fusion

= amount of heat required to melt one moles of a solid

Page 11: Topic: Enthalpy and Table I Do Now: packet p.1. Chemistry is the study of matter and energy. So far we have learned about the types of matter and how

Energy depends on amount

• Remember – it takes more energy to heat up water in the ocean than to make a cup of tea

Page 12: Topic: Enthalpy and Table I Do Now: packet p.1. Chemistry is the study of matter and energy. So far we have learned about the types of matter and how

CH4(g) + 2O2(g) CO2(g) + 2H2O (l) H = -890.4 kJ

1 mole of methane + 2 mole of oxygen →

1 mole of carbon dioxide gas & 2 moles of liquid water

reaction is ____________ (negative sign for ΔH)

890.4 kJ energy released per mole of CH4(g) burned

exothermic

What would happen if we had 2 moles of methane?

Twice as much energy would be released

2 x 890.4 kJ = 1780.8 kJ will be released

Page 13: Topic: Enthalpy and Table I Do Now: packet p.1. Chemistry is the study of matter and energy. So far we have learned about the types of matter and how

Reactions: Energy depends on direction too!

• N2(g) + 3H2(g) 2NH3(g) H = -91.8 kJ

• 2NH3(g) N2(g) + 3H2(g) H = _______

If reverse equation, reverse sign of H

91.8 kJ

Page 14: Topic: Enthalpy and Table I Do Now: packet p.1. Chemistry is the study of matter and energy. So far we have learned about the types of matter and how

Table I

• Exothermic: ΔH = -

• Pay attention to number of moles, may need to divide or multiply ΔH

• Pay attention to direction, if in reverse direction, switch the sign

Page 15: Topic: Enthalpy and Table I Do Now: packet p.1. Chemistry is the study of matter and energy. So far we have learned about the types of matter and how

• Check POINT

• 1. According to Ref. Table I, the decomposition of which compound is exothermic?

• A) C2H6 B)NO

• C) CO2 D) NH3

• 2. According to Ref. table I, what is the heat of reaction for the formation 1 mole of H2O (l) from hydrogen and oxygen gas at STP?

• A) -571.6kJ B) -483.6 kJ

• C)-55.8kJ D) -285.8kJ

Page 16: Topic: Enthalpy and Table I Do Now: packet p.1. Chemistry is the study of matter and energy. So far we have learned about the types of matter and how

If we can’t calc. H for one individual substance how are we

able to calc. ΔH???!

Page 17: Topic: Enthalpy and Table I Do Now: packet p.1. Chemistry is the study of matter and energy. So far we have learned about the types of matter and how

FYI: Hess’s Law(not on regents)

Can add 2 or more equations by adding the H’s

Enables you to calculate H for # of rxns

Say you’re interested in

2S(s) + 3O2(g) 2SO3(g)

Page 18: Topic: Enthalpy and Table I Do Now: packet p.1. Chemistry is the study of matter and energy. So far we have learned about the types of matter and how

2S(s) + 3O2(g) 2SO3(g)Have H’s for the following:

a) S(s) + O2(g) SO2(g) H = -297 kJ

b) 2SO3(g) 2SO2(g) + O2(g) H = 198 kJ

2 2 2

2SO2(g) + O2(g) 2SO3(g) H = -198 kJ

H = -594KJ + (- 198kJ) H = -792 kJ

x (2)