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  • B GIO DC V O TO

    I HC NNG

    MAI TH THY DNG

    NGHIN CU NG DNG KT HP

    BM BIN TN V TRM KH P TRONG

    CP NC CHO NH CAO TNG

    Chuyn ngnh: Cng ngh mi trng

    M s: 60.85.06

    TM TT LUN VN THC S K THUT

    Nng, Nm 2013

  • Cng trnh c hon thnh ti

    I HC NNG

    Ngi hng dn khoa hc: PGS.TS. NGUYN VN TN

    Phn bin 1: PGS.TS. TRN C H

    Phn bin 2: PGS.TS.TRN CT

    Lun vn c bo v trc Hi ng chm Lun vn tt

    nghip thc s K thut hp ti i hc Nng vo ngy 27

    thng 01 nm 2013.

    C th tm hiu ti:

    - Trung tm Thng tin - Hc liu, i hc Nng

    - Trung tm Hc liu, i hc Nng

  • 1

    M U

    1. S cp thit ca ti

    Vi s pht trin ngy cng mnh m ca cc loi nh cao tng l

    mt thch thc rt ln i vi cng tc cp thot nc, trong yu

    cu v thit k HTCN m bo ng tiu chun quy nh, kp thi l

    yu cu bt buc v ht sc cn thit m bo hiu qu trong cc

    hot ng ca nh cao tng.

    Vic thit k HTCN cn gp mt s vn phc tp v nhng s c

    lin quan n vn cp nc thng xuyn xy ra nh p lc nc

    khng m bo cng nh cc cng trnh lin quan n HTCN thng

    nh hng ln n kt cu, m quan kin trc cng trnh (kt nc, b

    cha), ng thi chi ph in nng cho HTCN hin ti thng kh

    cao

    Hin nay cha c tiu chun v cp nc cho nh cao tng, cc ti

    liu lin quan n thit k HTCN cho nh cao tng cn t. Vic thit k

    HTCN cho nh cao tng hin ang da trn tiu chun Vit Nam, kt

    hp vi kinh nghim ca ngi thit k, ng thi tham kho thm mt

    s tiu chun ca nc ngoi.

    Nhm mc ch gii quyt nhng vn cn tn ti trong HTCN

    cho nh cao tng, ti xut ti Nghin cu s dng kt hp bm

    bin tn v trm kh p trong cp nc cho nh cao tng.

    2. Mc tiu v ni dung nghin cu

    - Phn tch, nh gi hin trng ca HTCN thit k cho nh cao

    tng ti TP Nng.

    - xut cc gii php tnh ton thit k HTCN p dng cho nh

    cao tng trong iu kin c th ti TP Nng.

    3. i tng v phm vi nghin cu

    i tng: Bm bin tn v trm kh p trong lnh vc cp nc.

  • 2

    Phm vi nghin cu: HTCN cho cc nh cao tng vi iu kin c

    th ti TP Nng.

    4. Phng php nghin cu

    Cc phng php nghin cu:

    - Phng php thu thp s liu

    - Phng php kho st, nh gi

    - Phng php nghin cu l thuyt

    - Phng php k tha

    5. B cc ti:

    M u

    Chng 1: Tng quan HTCN cho nh cao tng

    Chng 2: Gii php cp nc cho nh cao tng

    Chng 3: L thuyt v my bin tn v trm kh p trong iu

    khin my bm

    Chng 4: xut phng n s dng my bin tn kt hp

    trm kh p trong HTCN nh cao tng.

    Kt lun v kin ngh

    6. Tng quan ti liu nghin cu

    Ti liu nghin cu c 8 ti liu ting Vit v 3 ti liu ting Anh.

    Cc ti liu c s dng trong ti gm cc ti liu v tiu chun

    cp nc ca Vit Nam, cc gio trnh v cp nc v my bm, trm

    bm.

    CHNG 1: TNG QUAN HTCN NH CAO TNG

    1.1. KHI NIM V PHN LOI NH CAO TNG

    Nh cao tng l nh v cc cng trnh cng cng c chiu cao t

    25m n 100m (tng ng 10 n 30 tng).

    * Phn loi nh cao tng:

  • 3

    - Theo kt cu xy dng: Nh cao tng kt cu b tng ct thp v

    nh kt cu thp.

    - Theo mc ch s dng: khch sn, vn phng, tr s c quan,

    1.2. MT S C IM NH CAO TNG LIN QUAN N

    CNG TC CP NC

    1.2.1. c im v kin trc

    - Nh cao tng thng l cng trnh a nng nn vic thit k, qun

    l, vn hnh h thng cp thot nc rt phc tp.

    - Cn phn chia ra nhiu vng cp nc s dng bm tng p,

    linh kin, ng phi chu p lc cao.

    - Khu v sinh cng t c b tr cng mt trc thng ng, kh

    trong vic b tr hp k thut cho m bo kin trc ca ta nh.

    - m bo cp nc cho cng trnh th vic b tr kt nc trn

    mi l yu cu gn nh bt buc.

    1.2.2. c im v kt cu

    - Nhng cng trnh nh cao tng, phi tnh n tc ng ngang do

    hot ng ca gi v ng t gy ra.

    - Nh cao tng c nhiu khi thng c cc khe ln rt a dng.

    Vic hn ch cc tuyn k thut qua cc khe ln, nn cc khi kin trc

    cng c cc vng cp thot nc ring.

    1.2.3. c im trang thit b nh cao tng

    Trang thit b ca nh cao tng gm nhiu loi a dng

    1.3. NHNG TN TI CA HTCN CHO NH CAO TNG

    THIT K NNG

    1.3.1. Hin trng cp nc nh cao tng

    p lc nc ti cc im cui mng li nh.

  • 4

    Ti TP Nng: Vo cc gi cao im trong ngy, c nhng khu vc

    p lc nc trung bnh rt thp (Hnh 1.3). HTCN phi c b cha, bm

    v kt nc.

    Hnh 1.3: p lc nc mt s im ti TP Nng nm 2012

    (Ngun: Cng ty TNHH MTV cp nc Nng)

    Khch sn Novotel Sng Hn, cng vin phn mm Softtech,

    ton nh Indochina Riverside, cn h cao c 34 tng Azura... c s

    cp nc gm b cha, trm bm tng p v kt nc.

  • 5

    Hnh 1.4. S HTCN in hnh nh cao tng Nng

    Phn ln cc cng trnh cao tng ti TP Nng u s dng s

    cp nc nh hnh 1.4. HTCN ca cc cng trnh cao tng Nng:

    HTCN cho khch sn Novotel sng Hn:

    HTCN cng trnh Vnh Trung plaza

    HTCN khch sn Mecure o Xanh Nng.

    1.3.2. Nhng tn ti ca HTCN cho nh cao tng ti Nng

    - Chi ph in nng cho my bm ln.

    - Km hiu qu do cc tng pha di phi s dng van gim p.

    - Th tch kt nc rt ln, nh hng n kt cu ca cng trnh.

    CHNG 2: GII PHP CP NC NH CAO TNG

    2.1. CC S HTCN NH CAO TNG.

    2.1.1 C s l thuyt ca vn phn phi nc u trong nh

    cao tng

    Quan h gia lu lng nc chy qua vi v p lc (Hnh 2.1)

  • 6

    Hnh 2.1. Quan h qia Q v Htd ca mt loi thit b dng nc.

    Lu lng nc t l thun vi p lc nc.

    2.1.2.Cc bin php phn phi nc u trong cng trnh.

    Bin php kh p lc d phn phi nc u:

    - Lp t van gim p thng xuyn ti cc ng nhnh

    - Lp t cc rng en gim p trong cc rc co u nhnh.

    - Lp t van iu chnh ti cc u ng nhnh ca mi tng.

    - Dng cc loi ng, cc loi thit b c ng knh khc nhau.

    2.1.3. Cc s cp nc cho nh cao tng

    a. S cp nc phn vng song song.

    Hnh 2.2. L s HTCN phn vng song song cho nh 12 tng.

    Vi: - Qb = Q1 = Q2 = Q3

    - Hb1 H1 ; Hb2 2H1 ; Hb3 3H1

  • 7

    Hnh 2.2. S cp nc phn vng song song cho nh 12 tng.

    b. S cp nc phn vng ni tip.

    Hnh 2.3. L s HTCN phn vng ni tip cho nh 12 tng. Vi:

    - Qb1 3Q1 ; Qb2 2Q1 ; Qb3 Q1

    - H1 H2 H3

    Hnh 2.3. S HTCN phn vng ni tip nh 12 tng

  • 8

    c. S cp nc khng phn vng

    Hnh 2.4 l s cp nc khng phn vng cho nh 12 tng.

    Vi Qb = 3Q1 v Hb = 3H1.

    Hnh 2.4. S cp nc khng phn vng

    2.2. PHN TCH U V NHC IM CA CC S CP

    NC

    2.2.1. S cp nc phn vng song song

    Khi cng sut in ca my bm vng 1 l:

    N1 =

    b

    HQ

    *102

    ** 11 (kW) (2.10)

    Trong :

    - : T trng ring ca cht lng bm; (kG/m3)

    - b: Hiu xut my bm;

    Khi cng sut in ca my bm vng 2 v 3:

    N2 =

    b

    HQ

    *102

    2** 11 = 2N1 (2.12)

    N3 =

    b

    HQ

    *102

    3** 11 = 3N1 (2.13)

    Tng cng sut in ca cc my bm cho cc vng l :

  • 9

    Nb = N1 + N2 + N3 = N1 + 2N1 + 3N1 = 6 N1 (2.14)

    2.2.2. S cp nc phn vng ni tip

    - My bm vng 3:

    N3b =

    b

    HQ

    *102

    ** 11 = N1 (2.15)

    - My bm vng 2 v 1:

    N2b =

    b

    HQ

    *102

    *2* 11 = 2N1 (2.17)

    N1b =

    b

    HQ

    *102

    *3* 11 = 3K*Q1*H1 = 3N1 (2.18)

    Tng cng sut in cho c 3 my bm ca 3 vng l :

    N3b + N2

    b + N1

    b = N1 + 2N1 + 3N1 = 6 N1 (2.19)

    So snh hai trng hp phn vng song song v ni tip , ta thy chi

    ph in nng cho c hai trng hp l tng ng nhau.

    2.2.3. S cp nc khng phn vng

    Khng phn vng th cng sut in cho trm bm chung l:

    Nb = b

    HQ

    *102

    3*3* 11 = 9K*Q1*H1 = 9N1 (2.20)

    So vi HTCN phn vng, th khng phn vng c nhiu bt li:

    - Phn phi nc khng u gia cc tng nh

    - ng knh ng cp nc v cc thit b ln.

    - Chi ph in nng cao.

    => Vic phn chia mi vng cp nc t 4 n 5 tng l hp l.

    CHNG 3: L THUYT V MY BIN TN TRONG

    IU KHIN MY BM V TRM KH P

    3.1. MY BIN TN P DNG TRONG LNH VC CP NC

  • 10

    Hnh 3.4. im lm vic ca bm vi hiu sut cao nht

    C 2 cch iu chnh bm: thay i ng c tnh ng dn v thay

    i ng c tnh my bm.

    iu chnh lu lng nc bm thng c thc hin bng cc

    phng php truyn thng sau :

    - iu chnh bng cch khp van trn ng y ca bm

    - iu chnh bng ng m cc my bm hot ng ng thi

    - iu chnh thay i tc quay ca my bm

    - Thay i ng knh bnh xe cng tc ( gt bnh xe cng tc)

    Hn ch:

    - Khng tit kim c nng lng in.

    - Gim tui th, hng hc thit b v ng ng

    - My bm cung cp khng bm st c ch tiu th.

    Gii php:

    Thay i i tc vng quay bm bng thit b bin tn.

    a. Phm vi p dng

    Dng cho trm bm cp nc t quy m cng sut nh n quy m

    cng sut ln.

    Q (m3/s)

    C D

    H

    (m) E

    Q-H

    A HA

    Q

    A

    Q-

    1

    3

    2

  • 11

    b. Nguyn l lm vic

    Mi quan h gia cc thng s lm vic ca my bm v s vng

    quay trn trc tun theo cng thc sau:

    2

    2

    1

    2

    1

    n

    n

    H

    H ;

    2

    1

    2

    1

    n

    n

    Q

    Q (3.1); (3.2)

    - H1; Q1: ct p v lu lng khi bm lm vic vi s vng quay n1.

    - H2; Q2: ct p v lu lng khi bm lm vic vi s vng quay n2.

    Hnh 3.5. ng c tnh cng tc my bm v ng dn khi iu

    chnh lu lng my bm bng cch thay i s vng quay.

    Hnh 3.6. S nguyn l h thng bin tn t ng iu chnh lu

    lng my bm.

    Q (m3/s)

    C D

    H (m)

    E

    Q-H(n1)

    1

    H2

    Q2

    2

    Q1

    H1 Q-H(n2)

  • 12

    - Khi nhu cu s dng nc thp hn hoc bng kh nng cung cp

    ca mt bm th bm c lp bin tn hot ng.

    - Khi nhu cu dng nc tng ln th mt bm s chy ti a, cn

    bm bin tn b sung thm lu lng yu cu.

    - Khi lu lng yu cu tng ln hn na hoc gim i th vic iu

    chnh cng din ra tng t.

    C ba phng thc iu khin cc my bm:

    - iu khin theo mc nc

    - iu khin theo hnh thc ch ng/ th ng

    - iu khin theo hnh thc bin tn iu khin mt bm

    c. Nhng u im khi iu khin tc bm bng thit b bin tn

    - Cung cp va lu lng yu cu.

    - Hn ch c dng in khi ng cao.

    - Tit kim nng lng.

    - iu khin linh hot cc my bm.

    - Cng sut my bm cao.

    - T ng ngng khi t ti im ci t.

    - Tng tc nhanh gip bin tn bt kp tc ca ng c.

    - Trnh qu ti hoc qa in p khi khi ng.

    - Bo v c ng c khi.

    - Kt ni vi my tnh chy trn h iu hnh Windows.

    - Kch thc nh gn khng chim din tch trong nh trm.

    - M men khi ng cao vi ch tit kim nng lng.

    - D dng lp t vn hnh.

    - Hin th cc thng s ca ng c v bin tn.

    3.2. TRM KH P: NGUYN L V IU KIN P DNG

    a. Cu to

    Bnh kh p cn gi l bnh iu p, t trn ng y ca bm.

  • 13

    - Bnh iu p ln gm hai thng bng thp: Mt thng cha nc

    v mt thng cha khng kh. ng dn nc t trm bm ti c ni

    vi thng cha nc, khi nc tha th nc s dn khng kh sang

    thng khng kh v p cht li.

    - Bnh iu p nh: (dung tch 100l - 200l - 500l - 1000l) ch c mt

    thng va cha nc v khng kh, nc di khng kh trn.

    Trm nn kh phi b tr thm my nn kh b sung

    Hnh 3.2. Trm kh p c dung tch ln

    Hnh 3.3 Bnh kh p c dung tch nh

    b. Nguyn tc hot ng

    - Khi lng nc trong mng li tiu th t nc vo bnh iu p

    v dn khng kh li, p lc khng kh ln nht Pmax (Pmax < 6 at).

    - Khi mng li tiu th nc, nc bnh iu p ra lm cho khng

    kh dn ra, khi nc ra ht th p lc khng kh thp nht, Pmin Hctnh

    Dung tch nc Wn , dung tch thng khng kh Wkk . Ta c:

  • 14

    (Pmin + 1) ( Wkk + Wn ) = (pmax + 1 ) Wkk (3.3)

    3.3. KT HP GIA MY BIN TN V TRM KH P

    Trnh kt nc, gim th tch ca bnh kh p, gim chi ph in

    nng, ko di tui th cho bm, tng hiu qu kinh t cho HTCN th

    phng php s dng kt hp bm bin tn v trm kh p s gii quyt

    c cc vn trn.

    Phm vi p dng:

    S dng cho mng cp nc nh, cc cn h, khch sn, chung c

    cao tng hoc cc nhu cu s dng nc khng iu ha khc

    Cu to:

    Hnh 3.8. Cu to bm bin tn v trm kh p

    Chc nng bnh iu p: n nh ct p v lu lng bm v ct p,

    lu lng tiu th

  • 15

    Nguyn tc hot ng:

    - Lu lng my bm : Qbm = Qtiu th max (3.4)

    - p lc my bm : Hb = Hhh + H + Htd (3.5)

    Trong :

    H : Tng tn tht

    Htd : p lc t do cn thit ti thit b dng nc.

    Lng nc trong bnh iu p vi Vnc c nn di p lc Pmax =

    P1, qu p lc ny bm t ng tt. Khi trn mng c dng nc, nc

    trong bnh di p lc ca kh nn chy vo mng cp nc thay cho

    bm, kh nn trong bnh cha dn ra, p lc trong bnh gim Pmin = P2,

    Bm chy li cp nc cho mng v tch nc vo bnh.

    CHNG 4: XUT PHNG N S DNG MY BIN

    TN KT HP TRM KH P TRONG H THNG CP

    NC NH CAO TNG

    4.1. S DNG MY BM IU KHIN BNG BIN TN KT

    HP VI TRM KH P TRONG HTCN NH CAO TNG.

    4.1.1. i vi my bm khng s dng b bin tn

    a. Tnh ton th tch nc cn thit iu ho lu lng

    - Th tch bnh Vn, p lc n P1 bm ngng hot ng, lc ny trn

    mng li tiu th mt lng nc l x (m3/h).

    - Thi gian lm cn bnh: t1 = x

    Vn (4.1)

    - Khi bnh ht nc p lc gim xung c gi tr P2 bm t ng chy, bm nc vo bnh v mng c lu lng Qb(m

    3/h).

    - Thi gian tch y bnh:

    xQ

    Vt

    b

    n

    2 (4.2)

    - Tng thi gian ca mt chu k ng m my bm :

    t = t1 + t2 = xQ

    V

    x

    V

    b

    nn n

    n

    Q

    xx

    t

    V 2 (4.3); (4.4)

  • 16

    Tm gi tr ca x cho thi gian t l ln nht hay t

    Vn l nh nht.

    Mun vy o hm phng trnh trn theo x v cho bng 0 ta c:

    2

    02

    1 b

    b

    n

    Qx

    Q

    x

    dx

    t

    Vd

    (4.5)

    Ly o hm bc 2 : 0

    22

    2

    b

    n

    Qdx

    t

    Vd

    (4.6)

    Phng trnh c im t cc i ti : x =2

    bQ (4.7)

    Thay gi tr x vo phng trnh ta c :

    t =

    b

    n

    Q

    V4 hay Vn =

    4

    btQ (4.8)

    Trong : t l thi gian cho php ca mt chu k ng m my,

    Vn = Z

    Qb

    4 (4.9)

    Vi Z l s ln ng m my cho php trong mt gi.

    b. Tnh ton th tch cha kh cn thit iu ho p lc v th

    tch bnh.

    p lc ti thiu P2 , kh chon c bnh : Vbnh = V2k (4.10)

    V1k : Th tch kh khi b nc nn n p lc ti a P1.

    V2k - V1k = Vn (4.11)

    Theo nh lut kh nn Boyle-Marood ta c : P1V1k = P2V2k hay

    k

    n

    k

    kk

    k

    k

    V

    V

    V

    VVf

    P

    PP

    V

    V

    P

    P

    22

    12

    1

    21

    2

    1

    1

    2 (4.12)

    Trong :

    V2k = Vbnh : Th tch bnh iu p; vi V2k = f

    Vn (4.13)

    Vbnh = Zf

    Qb

    4

    vi f =

    1

    21

    P

    PP (4.14)

  • 17

    Hnh 4.1. S HTCN c trm kh p

    Trm kh p thng dng trong HTCN mng kn bao gm my bm

    p lc, bnh p lc, thit b iu p v thit b to p

    4.1.2. i vi bm c gn b bin tn

    Thay i tn s lm cho s vng quay ca my bm thay i ko

    theo vic iu chnh ct p v lu lng v im lm vic yu cu.

    Dung tch bnh iu p khi kt hp vi bm bin tn:

    V= K

    TQ (Lt) (4.15)

    Trong :

    - V: Dung tch bnh p lc (L)

    - Q: Lu lng ca 1 bm (L/ph)

    - T : Thi gian chy ti thiu ca bm (Pht). 5-10 giy.

    - K: h s s dng ca bnh, K=0.9

    4.2. CHN MY BM, MY BIN TN V TNH TON

    TRM KH P.

    4.2.1. Cch la chn my bm, my bin tn v trm kh p.

    Cc bc tnh ton thy lc v la chn bm:

  • 18

    - Xc nh thy lc tng tuyn ng.

    - Xc nh tn tht p lc

    - Tnh p lc cn thit ca ngi nh (Hnhct

    )

    * Xc nh lu lng my bm

    q = 0,2 N . (4.16)

    N- Tng s ng lng ca cc TBVS trong on ng tnh ton

    ca vng m my bm phc v.

    - H s ph thuc chc nng ca ngi nh.

    * Xc nh ct p

    H = Hct = Hhh + Ht + Htd (m). (4.17)

    Trong :

    - Hhh: Chnh hnh hc tnh t y b cha nc ln TBVS bt li.

    - Htd : p lc t do ca vi phun. Ly nh nht l 1m.

    - Ht: Tn tht p lc trn ng ng; Ht = Hcb + Hl;

    La chn kch thc bnh iu p:

    - Khng s dng bin tn th tnh my bm ng m ti a l 4 ln/h.

    - C s dng b bin tn th thi gian chy ti thiu my bm, t 5-10s

    4.2.2. Vn dng cho HTCN cho khch sn Mercure o Xanh.

    a. Thit k hin ti

    S cp nc gm c 1 b cha, trm bm v kt nc :

    - S gm c 6 ng ng ni thng t mi xung.

    - Th tch b cha nc l 400 m3.

    - Trm bm cc c 2 vi 3 bm mc song song, 2 bm hot ng v

    1 bm d phng. Lu lng mi bm l 40m3/h v ct p 120m.

    - Th tch kt nc 120 m3

    b. Tnh ton theo phng n xut mi

    S dng s phn vng, mi vng s dng mt bm bin tn kt

    hp bnh kh p ring.

  • 19

    - Vng I: ng ng 1 cp nc cho tng hm v tng 1-4, tng 5 l

    tng k thut.

    - Vng II: ng ng 2 cp nc cho tng 6 9.

    - Vng III: ng ng 3 cp nc cho tng 10 13.

    - Vng IV: ng ng 4 cp nc cho tng 14 - 17.

    - Vng V: ng ng 5 cp nc cho tng 18 21.

    Lu lng nc tnh ton cho tng on ng :

    q = 0,2 N

    Trong :

    - q: Lu lng nc tnh ton trong 1 giy cho tng on ng.

    - N: Tng ng lng ca cc TBVS trong on ng tnh ton.

    - : H s ph thuc chc nng ca ngi nh ( khch sn = 2,5)

    Chn bm cho tng vng, ct p ca bm:

    Hb = Hct = Hhh + Ht + Htd (m).

    Th tch bnh iu p:

    V = K

    TQ (Lt)

    Bng 4.2: Cc thng s tnh ton ca bm

    STT Bm Lu lng cn

    thit (m3/h)

    Ct p cn

    thit (m)

    Th tch bnh iu

    p cn thit (lt)

    1 Bm 1 11.30 33 17.44

    2 Bm 2 21.78 52 33.61

    3 Bm 3 21.78 67 33.61

    4 Bm 4 21.78 83 33.61

    5 Bm 5 18.22 100 28.12

    Chn 5 bm Grundfos cho 5 vng:

  • 20

    Bng 4.3: Loi bm la chn

    STT on ng Loi bm Lu lng

    (m3/h)

    Ct p

    (m)

    Th tch

    bnh (lt)

    1 ng ng 1 CM 10-3 11.30 33 33

    2 ng ng 2 CR 20-5 21.78 52 33

    3 ng ng 3 CR 20-7 21.78 67 33

    4 ng ng 4 CR 20-8 21.78 83 33

    5 ng ng 5 CR 15-10 18.22 100 33

    c. Khi ton kinh t

    Tnh gi tr kinh t 2 phng n thi gian s dng l 30 nm.

    * Phng n hin ti

    3 bm trc ngang Grundfos NGB 65-40-315:

    - Lu lng: Q = 40m3/h - Ct p: H = 120 m

    - Cng sut: N = 45 kW

    S ln m bm trong mt ngy l 4, thi gian hot ng trong mt

    ln l 1.25h. Nng lng in tiu th trong mt ngy ca 2 bm:

    G = N x 4 x 1.25 = 45 x 4 x 1.25 x 2 = 450 (kWh/ngy) (4.19)

    Bng 4.4. Khi ton kinh ph theo phng n hin ti

    STT Hng mc n gi

    (1000 ng) n v S lng

    Thnh tin

    (1000 ng)

    1 Bm trc ngang NGB

    65-40-315 198 816 Ci 3 596 448

    2 T iu khin bm 65 347 Ci 1 65 347

    3 Chi ph xy kt nc 5 800 m2 166 962 800

    4 n gi in 4 kWh/ngy 450365 30 19 710 000

    TNG CHI PH 21 334 592

    * Phng n xut

    Cng sut trn trc ca my bm cho phng n xut:

  • 21

    Bng 4.5. Cng sut trn trc ca cc bm bin tn

    STT Loi bm Lu lng Q

    (m3/h)

    Ct p H

    (m)

    Cng sut N

    (kW)

    1 CM 10-3 11.30 33 2.2

    2 CR 20-5 21.78 52 5.5

    3 CR 20-7 21.78 67 7.5

    4 CR 20-8 21.78 83 11

    5 CR 15-10 18.22 100 11

    H s khng iu ha ca khch sn l Kh = 2.4, tc l:

    Kh = hTB

    h

    Q

    Q max = 2.4 (4.20)

    Trong :

    - Qhmax : lu lng vo gi dng nc ln nht trong ngy.

    - QhTB: lu lng vo gi dng nc trung bnh trong ngy.(m3/h)

    => QhTB = 41.7% Qhmax

    Vy nng lng in cc my bm tiu th trong 1 ngy:

    G = 41.7% N 24 (kWh/ngy) (4.21)

    Bng 4.6. Bng nng lng tiu th trong ngy ca cc bm bin tn

    STT Hng mc Qhmax

    (m3/h)

    N

    (kW)

    G

    (kWh)

    1 CM 10-3 v b bin tn iu khin 11.30 2.2 22

    2 CR 20-5 v b bin tn iu khin 21.78 5.5 55

    3 CR 20-7 v b bin tn iu khin 21.78 7.5 75

    4 CR 20-8 v b bin tn iu khin 21.78 11 110

    5 CR 15-10 v b bin tn iu khin 18.22 11 110

    TNG CNG 372

  • 22

    Bng 4.7. Khi ton kinh ph theo phng n xut

    STT Hng mc n gi

    (1000 ) n v S lng

    Thnh tin

    (1000 )

    1 CM 10-3 v b bin tn 72 523 Ci 1 72 523

    2 CR 20-5 v b bin tn 142 584 Ci 1 142 584

    3 CR 20-7 v b bin tn 160 952 Ci 1 160 952

    4 CR 20-8 v b bin tn 189 623 Ci 1 189 623

    5 CR 15-10 v b bin tn 90 930 Ci 1 90 930

    6 n gi in 4 kWh 372 x 365

    x 30 16 293 600

    TNG CHI PH 16 950 212

    Nhn xt:

    - Gim chi ph cho xy dng kt, gim nh phng n mng ct.

    - Gim c chi ph in nng.

    - m bo phn phi nc u gia cc tng nh, gim chi ph cho

    vic s dng cc bin php gim p.

    => xut mi em li hiu qu v kinh t cng nh v k thut.

    4.3. CHNG TRNH CHN MY BM CHO NH CAO

    TNG CA HNG GRUNDFOS

    4.3.1. Chc nng ca chng trnh

    Tnh ton, la chn bm cho lnh vc cp thot nc.

    4.3.2. Cc ni dung chnh ca chng trnh

    a. D liu

    - Heating (H thng nc nng, si)

    - Air-conditioning (H thng lnh, iu ha)

    - Pressure boosting (H thng tng p)

    - Groundwater supply (Cp nc ngm)

    - Domestic water supply (Cp nc dn dng)

  • 23

    - Wastewater (H thng nc thi)

    - Industrial applications (Cc ng dng cng nghip)

    - Dosing & Disinfection (H thng nh lng v tit trng)

    - All products (Tt c sn phm)

    - Accessories (Ph kin)

    b. Cch s dng chng trnh

    - Chn theo danh mc

    - Chn thng qua Product number

    c. Cch la chn sn phm

    - Xc nh thng s ct p v lu lng yu cu.

    - Chn loi bm trong ng dng .

    KT LUN V KIN NGH

    1. Kt lun

    Nh cao tng l mt cng trnh i hi trang b nhiu h thng k

    thut. Mi h thng k thut phi lm vic tht s c hiu qu v p

    ng mc tiu u t xy dng cng trnh. Trong qu trnh gii quyt

    vn cp nc trong nh cao tng, ngoi nhng yu cu k thut c

    bit, cn quan tm trit theo mi tiu chun ca cc quy phm hin

    hnh.

    Vic thit k v tnh ton thu lc HTCN cho nh cao tng ph

    thuc vo nhiu vn c c th ring. ti nu v la chn

    c gii php cp nc mang tnh kh thi cao cho cng trnh nh cao

    tng.

    Vn c quan tm nht trong cp nc l la chn s HTCN

    hp l cho nh cao tng:

    - Thng thng phn chia s tng nh thnh cc vng khc nhau

    mi vng t 4 n 5 tng. Phn vng cp nc c th thc hin bng

  • 24

    hai cch : Phn vng song song v phn vng ni tip . C hai cch

    phn vng u mang li nhng hiu qu cao v phng din k thut

    v kinh t :

    + Phng din k thut : Phn chia s tng nh ra cc vng khc

    nhau to ra p lc ng u gia cc vng. Khng cn kh p lc

    d. Dn ti vic phn phi nc u gia cc tng nh.

    + Hiu qu kinh t: Mi vng cp nc c mt my bm ring bit

    vi lu lng v ct p ph hp vi vng . Tng lu lng v ct p

    ca cc my bm phc v cho cc tng nh . Do chi ph cho nng

    lng in tiu th thp.

    - Chn s cp nc vi bm bin tn v trm kh p bn cnh

    vn v hiu qu k thut v kinh t nh phn tch trn th s

    xut phn no gii quyt c bi ton kt cu cho cc cng trnh

    cao tng do kt nc trn mi to ra, c bit l n kh hiu qu khu

    vc thng xuyn xy ra bo ln nh Nng.

    Vit Nam hin nay, cc tiu chun, quy phm xy lp v qun l

    h thng cp thot nc cho nh cao tng cn t. Tin tng rng trong

    mt thi gian khng xa, h thng tiu chun quy phm s y hn,

    nhm to iu kin cho cng tc thit k xy dng c c nhng c s

    php l khi nghin cu thit k v xy dng cng trnh.

    2. Kin ngh

    - Khi tnh ton thy lc mng li cp nc nh cao tng nn s

    dng s cp nc vi ng ng chnh phn phi t pha trn xung

    v chn vn tc nc trong cc on ng ln hn vn tc kinh t.

    - Nghin cu b sung tiu chun thit k HTCN cho nh cao tng.

    - Vic s dng cc loi thit b dng nc v cc loi ng ng c

    ng knh khc nhau c vai tr trong vic phn phi nc u.