Today – Monday, December 17, 2012

Q & A from Friday’s Warm up PG. 292: 1-13

Questions from HW #1

Learning Target: Use the Perpendicular Bisector to solve problems

Independent practice/Check HW #1

CHECK YOUR ANSWERS from Friday’s WARM UP Pg. 292: 1-13

1. No: is not perpendicular to 2. 3. 4. 5. 6. 7. 8. 9. 10. 11. 12. 13.

PERPENDICULAR BISECTOR THEOREM:If a point is on the perpendicular bisector of a segment, then it is equidistant from the endpoints of the segment.

𝐴 𝐵

𝐶

𝑃

If is the bisector of

then

CONVERSE OF THE PERPENDICULAR BISECTOR THEOREM: If a point is equidistant from the endpoints of a segment, then it is on the perpendicular bisector of the segment.

𝐴 𝐵

𝐶

𝑃

If , then lies on the

bisector of

𝐷

is the perpendicular bisector of . Find .

𝐴

𝐵

𝐶

𝐷

13 Since is the perpendicular bisector of , then

and

so

13

is the perpendicular bisector of . Find .

𝐴

𝐵

𝐶

𝐷

𝑥+8

2 𝑥−4

Since is the perpendicular bisector of , then

and

Congruent segments Substitute values

Subtract

Add

is the perpendicular bisector of .Find .

𝐿

𝑀

𝑁

𝐾

6 𝑦−5

4 𝑦+1𝑥

8𝐴

To find x: Congruent Seg. Substitute values

To find y: Congruent Seg. Substitute values Subtract

Add

Divide

When 3 or more lines intersect in a common point it is called concurrent. The point of intersection is called the point of concurrency.

Point of concurrency

CIRCUMCENTER: CONCURRENCY OF THE PERPENDICULAR BISECTORThe perpendicular bisectors of a triangle intersect at a point that is equidistant from the vertices of the triangle.

𝐴 𝐶

𝐵

𝐸𝐷

𝐹

𝑃

If are perpendicular bisectors,

then

HOMEWORK #2:

Page 306: 3-5, 9-17Page 309: 34-41

If finished, work on other assignments:

HW #1: Pg. 298: 3-28 all except 20