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Aptitude (http://mrunal.org/category/aptitude) / 3 years Ago /110 Comments (http://mrunal.org/2012/05/aptitude-time-n-work-4-men-and-6-women.html#comments)

This is merely a subtype of Time n Work problems. and can be solved using our good ol STDtable Method.

1. Case 1: Women finish entire job2. Case 2: Women to finish remaining job3. Case: Child labour

Case 1: Women nish entire job

4 men and 6 women can complete a work in 8 days, while 3men and 7 women can complete it in 10 days. In how manydays will 10 women complete it?

Suppose 1 man can pour 1 bucketful of water in the tank in 1 minute.If 6 men work together, they pour 6 buckets in a tank in 1 minute.In short, you multiply the speed with number of person.

Our usual table

1 Man 1 Woman 4 men & 6 women 3 men & 7 women

Speed m w 4m+6w 3m+7w

Time 8 10

[Aptitude] Time n Work: 4 men and 6 women can complete a work in 8Days then

English: SP Bakshi(http://www.flipkart.com/objective-general-

english-2012/p/itmdyuqqgafhtehp?pid=9788183480000&affid=mrunalrugm)

Mrunal (http://mrunal.org/)

distance

Distance covered in each column is same.So compare last two columnsDistance = distanceSpeed x time = speed x time(4m+6w)*8=(3m+7w)*10

Solve this equation and you get m=11wReplace this value of w in last column


Speed m w 4m+6w 3(11w)+7w

Time 8 10

distance

3(11w)+7w=33w+7w=40w


Speed m w 4m+6w 40w

Time 8 10

distance 40w x 10= 400w

So the total work isSpeed x time = distance40w x 10= 400w

If 10 women work together, theyve to cover 400w kms. Make a new column, run STD formula

1 Man 1 Woman 4 men & 6 women 3 men & 7 women 10 women

Speed m w 4m+6w 40w 10w

Time 8 10 ??

distance 40w x 10= 400w 400w

10w x time =400wTime =400w/ 10w=40days.

Answer: If 10 women work together, itll take 40 days to finish the job.

Case 2: Women to nish remaining job

12 men can complete a piece of work in 4 days, while 15women can complete the same work in 4 days. 6 men startworking on the job and after working for 2 days, all of themstopped working. How many women should be put on thejob to complete the remaining work, if it is to be completedin 3 days?

12 Man 15 Woman

Speed 12m 15w

Time 4 4

distance

Distance covered in both column is same so compare them

Speed x time = speed x time12m x 4= 15w x 44m=5wM=(5/4)w

The question is asking about number of women in the end, so better convert everything interms of women.Given: 6 men start working on the job and after working for 2 days, all of them stoppedworkingMake a new column.

12 Man 15 Woman 6men

Speed 12m 15w 6x (5/4)w

Time 4 4 2

distance 60w 6x (5/4)w x2=15w

As you can see, Ive applied STD formula in last two columns to find distance simultaneously.Remaining work=60w minus 15w=45wRequired: we want to finish this work in 3 days.Asked: How many women should be put on the job to complete the remaining work, if it is tobe completed in 3 days?

Make a new column. Suppose we need F number of women so speed = f x w = Fw.

12 Man 15 Woman 6men Find women

Speed 12m 15w 6x (5/4)w Fw

Time 4 4 2 3

Distance 60w 15w 45w

Time limit is given to us: complete remaining work in three days. So t=3 for last column.Run STD on last columnFw x 3 =45wF=45w /3wF=15Answer : 15 women required.

Important: Remaining work is to be completed in 3 days. So t=3If they had asked total work is to be completed in 3 days, well need to take t=1, because thosemen already worked for 2 days to only 1 day left to complete the job (2+1=3 days)

Case: Child labour

Twelve children take sixteen days to complete a work whichcan be completed by eight adults in twelve days. Sixteenadults started working and after three days ten adults leftand four children joined them. How many days will theytake to complete the remaining work?

12 kids 8 men

Speed 12k 8m

Time 16 12

Distance

Since work done in both columns is sameSpeed x time = speed x time12k x 16= 8m x 12K=(1/2)m

Concentrate on middle column (8 men) run STD table on it. You get distance = 8m x 12 =96mSo total distance to be covered is 48m

Given: Sixteen adults started working and after three days .Means 16 men worked for 3 days.

12 kids 8 men 16 men

Speed 12k 8m 16m

Time 16 12 3

Distance 8m x 12=96m 16m x 3=48m

Weve run STD on last column and got that 16 men covered 48m kms.So remaining work is 96m minus 48m=48m

Given: after three days ten adults left and four children joined themSo now men left =16 minus 10 =6 men and 4 kids joins them so speed is 6m+4kMake a new column

12 kids 8 men 16 men Men & kids

Speed 12k 8m 16m 6m+4k

Time 16 12 3 ??

Distance 96m 48m 48m

Run STD on last column(6m+4k) x time =48mBut We already calculated that K=(1/2)mApply it in above equation{6m+4(1/2)m} x time =48m{6m+2m} x time = 48m8m x time = 48mTime =48m /8mTime=6 days.

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R E P L Y ( / 2 0 1 2 / 0 5 / A P T I T U D E - T I M E - N - W O R K - 4 - M E N - A N D - 6 - W O M E N . H T M L ?R E P L Y T O C O M = 2 1 7 8 6 7 # R E S P O N D )

sunny kumarkindly help with below question-my answer- 48.actual answer-24

twenty four men can complete a work in 16 days.thirty two women can complete the same work in 24 days.sixteen men & sixteen women started working and worked for twelve

dayshow many more men are to be added to complete the remaining work in2 days?

thanks.


diptanshu gaurhey sunny 24 is the correct answer actually i use a differentmethod for time & work questions acc. to my method 24 menfinish the job in 16 days and 32 women did it in 24 days first takelcm of 16 and 24 as their respective speed to do the work ie: 48 (let48 as total work that needs to be done) if we divide 48 by 16 then itis 3 thats the speed of 24 men in a day n same for women 2 is thespeed now what will be the speed of 16 men that will be 2 because24 and 16 divisible by 8 so speed of 8 men will be 1 16=2 & 24=3same for women speed will be 16=1. the work has to be finishedwithin 14 days if 16 men work for 14 days the total work done bythem will be 28 becoz speed is 2 & women will do 14 work becozspeed is 1 now total work done=42 remaining 6 that is to be doneso if 24 men can do 3 work in one day they will do 6 in two days sothe remaining 6 they will contribute after 6 days. question is askinghow main additional men required as well as other will also workfor 2 days thankyou.


SANDHYAhii Sunny,

in the last sentence of ur qn is how many men more to be added tocomplete the work. It means 24 men is already working, how manymore men should be added

So, its (24M+X) men has to do 96M work in 2 daysso 24M+X = 96M/224M+X=48MX=48M-24Mi.e, x=24 men more needed to work


AanyaCorrect ans 24.1 mans 1 day work =1/16*24, for woman its 1/32*2416 men 12 day work=16*12/16*24=1/216 women 12days work=16*12/32*24=1/4Total completed work in 12 days=3/4Rest work=1/416 men+ 16 women 1 day work= 16/16*24 + 16/32*24= 1/24+1/48=1/16Their 2 days work=1/8Extra men needed to complete the work=1/4-1/8= 1/8 in 2 days means1/16 in one day24 men can complete a work in 16 days means their 1 day work 1/16, sowe need 24 men.

In writing it seems long but very quick when we actually solve!


24*16=32*24i.e.1M=2F

so,16M+16F=24Mfind remaining worki.e 1- (12/16)=1/4th work remainsnowwork- 1/4men- 24days- 2

use relation WMT


Ans is 24 men


sunny kumarThanks Sankalp!But could you plz help me with my solution given below-

after M=2F OR F=M/2So, 8M + 16M24M *12 = 288M- Work done by 16M + 16FWork left to be done= (16*24M)- 288M= 96M

Here on wards am facing the problem-as if 1M can do M work per daythan to complete in two days why shouldnt it be 48M?


Sorry friend my typing mistakesAns is 48..If u see my processUr ans is right.

Ashitha48 is required for remaining work is right. So menadded is 48-24 = 24. Bcoz 24 are already working


josegood job


sunny kumaram also getting 48 as answer but the book m reffering, says 24.one more problem-

25 men & 15 women can complete a work in 12 days.all of them start working together and after working for 8 days thewomen stops working.25 men completed the remaining work in 6 dayshow many days will it take for completing the entire job if only 15 womenare put on the job?

kindly help with this aswell


Virender Batra36 days


Ans- 36 days (completing whole work by 15 female)How? Letsee..

Find remaining work that by both (25M+15F) i.e.12 8/12 = 1/3NdThis work done by 25M in 6 days,Find whole work done by 25MNdThats18 days (i think u knows, how it is?)NdFind 1D work of (25M+15F) as wel as 25M separatelyNd then find their differenceluklike.1/12 1/18 = 1/36

So whole work done by 15F in 36D..

Coss-check for examination1/36 + 1/18 = 1/12..12 days


ABCD36 Days


GarimaKindly help How to solve this type of Ques.8 Men complete the work in 12 days. 4 Women can complete the samework in 48 days while 10 children can complete same work in 24 days. Inhow many days 10 Men,4 Women & 10 Children complete the work?


ANZ6 days

Am i correct.??


ABCD

1 1/11 Days Or 12/11 Days


ashithaits 48 required for the remaining work but 24 men already working so 24more required


Kanwaljeet Singh24 is the correct answer.16 men are already working so 40-16= 24ans


shakti1. 12 men take 18 days to complete a job where as 12 women in 18 dayscan com. 3/4th of the same job. how many days will 10m and 8 wtogether take to complete the same job?


ABCD13 1/2 or 27/2 Days

R E P L Y ( / 2 0 1 2 / 0 5 / A P T I T U D E - T I M E - N - W O R K - 4 - M E N - A N D - 6 - W O M E N . H T M L ?

R E P L Y T O C O M = 2 5 1 3 6 7 # R E S P O N D )

shivagihi sankalpi want to ask how do u find work in the question asked by sunny kumar?i mean, i was doing it by very long multiplication 24men*16 days= 384mn u did sumthing like 1- 12/16 = 1/4so where does this 12/16 came from.how did u find the remaining work in jus 2 simple steps?


SRamancan anyone solve this problem in STD method..

6Men can complete apiece of work in 12 days. 8women can complete thesame piece of work in 18 days, whereas 18 children can complete thepiece of work in 10 days. 4men, 12 women and 20 children worktogether for 2 days. if only men were to complete the remaining work in1 day. how many men would be required totally ?


SanjuAns 24 men a???


ABCD

36 Days


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plzz solve thism confused?


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Raaz

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ABCD9 Days


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Anas MYou are the best teacher..


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var12 days-1work-7men8days-2work-let x more man

X/7=12/8*2/1

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saurabh6 men and 11 women can complete a work in 30 days. 4 men and 6women can complete the same work in 50 days.find in how many days10 men, 5 woman and 10 children can do the same work of each womenI twice as efficient as a child?


siddharthIf 6 men and 8 boys can do a piece of work in 10 days while 26 men and48 boys can do the same in 2 days, the time taken by 15 men and 20boys in doing the same type of work will beA. 4 days B. 5 daysC. 6 days D. 7 days


siddharth

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If 6 men and 8 boys can do a piece of work in 10 days while 26 men and48 boys can do the same in 2 days, the time taken by 15 men and 20boys in doing the same type of work will beA. 4 days B. 5 daysC. 6 days D. 7 days by std method please explain me i have made thetable but the problem is i did not getting the concept to get the totaldistance covered in the end column casem=2b by putting all in the equations we get 50b in 15m+20b case, 18b in 6m+8b case and 52b in 26m+48b case what to tonext always struck in getting the total distance for last column


Vaibhav12 men nd 8 women can do a price of work in 16 days, while 13 men nd1 woman can do it in 18 days.How long will 13 men nd 12 women take to finish the work?

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30-Jun: NEIGRIHMS (http://neigrihms.gov.in)

30-Jun: Lucknow Law (http://rmlnlu.ac.in/recruitment-notification-process.html)

30-Jun: AIIMS Raipur (http://www.aiimsraipur.edu.in/Career.aspx)

28-Jun: Ranchi Agro (http://www.bauranchi.org/application-for-the-post-of-teachers-2/)

22-Jun: DIATPune (http://14.139.111.180/admin.html)

22-Jun: IGIT (http://www.igitsarang.ac.in/careers.php)

22-Jun: Himachal Central Univ. (http://www.cuhimachal.ac.in/job_emp.aspx)

Uniform

19-Jul: Navy Officers (http://www.irfc-nausena.nic.in/hindi/join_indiannavy.htm)

17-Jul: NDA Officers (http://upsconline.nic.in/mainmenu2.php)

15-Jul: Army Dental (23) (http://indianarmy.nic.in)

10-Jul: Army 10+2 (http://joinindianarmy.nic.in/)

30-Jun: BSF Constable (http://bsf.nic.in/en/recruitment.html)

15-Jun: Navy Sailers (SSR) (http://nausena-bharti.nic.in/forthcomingSailor.php)

15-Jun: Daman Diu Constables (http://daman.nic.in/jobs/2015/616-12-05-2015.PDF)

B.Com,CA,HR,MBA

20-Jul: Pawan Hans Audit (http://pawanhans.co.in/site/Careern.aspx)

06-Jul: GBPUAT Accountant (http://www.gbpuat.ac.in/)

01-Jul: NIELIT Accounts (http://www.nielit.gov.in/recruitments.aspx)

25-Jun: MP Electricity Accounts

(https://www.mponline.gov.in/Portal/Services/Recruit_MPKVV/Indore/notification.aspx)

21-Jun: Lucknow Metro Accounts

(https://www.digialm.com/EForms/html/form2399/index.html)

RESULT /MARKSHEET

SSC 2014 T2

NCLAT

(https://www.facebook.com/Mrunal.org)

(https://twitter.com/mrunal_patel)

(https://plus.google.com/109455346868280536907?

rel=author)

(http://www.youtube.com/user/TheMrunalPatel)

(http://feedburner.google.com/fb/a/mailverify?

uri=CivilServiceExam)HOME (HTTP://MRUNAL.ORG/) ECONOMY (HTTP://MRUNAL.ORG/ECONOMY)

DOWNLOAD (HTTP://MRUNAL.ORG/DOWNLOAD) CONTACT ME (HTTP://MRUNAL.ORG/CONTACT)

The work of Mrunal (http://mrunal.org/) is under the Creative Commons Attribution-Non Commercial-ShareAlike 4.0License (http://creativecommons.org/l icenses/by-nc-sa/4.0/deed.en_US).Permissions beyond the scope of this l icense

may be available at Mrunal.org/contact (http://mrunal.org/contact).

1. Online Form Part-I stops few days before deadline, so don't wait till last date. Dont forget

reg.id & roll no.Note'em in Google Drive (https://www.google.com/drive/)

2. I usually update vacancies every Monday.Purple link= newly added,Blue= existing.Last

updated Mon. Jun 22, at 9:04PM

Hotel Management

TENTATIVE NOTIFICATIONS

IAS-IPS-IFoS: 16 May

IES: 7 Feb

SSC CGL: 2 May

SSC 10+2: 6 June

SSC Sub insp: 28 Mar

CAT: Aug 2015

RBI Officer / Assistant: ??

IBPS PO / Clerk / RRB: ??

ACIO 2015: ??

// /

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Documents

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