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This is problem 49 page 219: - PowerPoint PPT Presentation
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This is problem 49 page 219:
A man is in a boat 2 miles from the nearest point on the coast. He is to go to a point Q, located 3 miles down the coast and 1 mile inland. If he can row at 2 miles per hour and walk at 4 miles per hour, toward what point on the coast should he row in order to reach point Q in the least amount of time.
Need a picture:
Q
1 mile
2 miles
3 miles
x
3 - x
Find x to minimize time
Use the Pythagorean theorem twice to find the distance to row and walk
To row: 42 x
To walk: 1)3( 2 x
The time to row is: milesxmiles
hour4
22
Notice I used unit analysis to find I had to divide by 2 and not multiply by 2
The time to walk is:
milesxmiles
hour1)3(
42
The primary equation is the total time:
1)3(4
14
2
1 22 xxT
We don’t need a “secondary equation”. Why?
The primary equation only has one variable, there is no need to substitute for a second variable.
1)3(4
14
2
1 22 xxT
To minimize, find the derivative = 0
This will be good chain rule practice
))1)(3(2(1)3(
2
14124
2
121' 2
122
12 xxxxT
Outside Inside Outside Inside
Do you see another chain rule here?
))1)(3(2(1)3(
2
14124
2
121' 2
122
12 xxxxT
We need to solve this mess = 0
First, let’s clean it up a bit by multiplying constants
)3(1)3(4
1421' 2
122
12 xxxxT
Wow, let’s cheat and use MathPert to graph this and find the solution
Click on this
Now this
Select “Type it in”
note the use of ( ) everywhere and the use of negative exponents now
click OK
Make sure this is the equation we want and it is. Click OK again
Here is our graph, we want where it equals 0, ie, the x-intercept
click this about 4 times to get a better view
This looks like the point
Use the Point and Slope Tool
click it and center the crosshairs on the intercept
y = 0 and x = 1
this is where the derivative is equal to 0!
We just use a ‘numerical” technique to solve the equation
Just to make sure, evaluate at x = 1:
)3(1)3(4
1421' 2
122
12 xxxxT
You should get:
054
2
52
1
The man should aim for a point 1 mile down the coast
)3(1)3(4
1421' 2
122
12 xxxxT
To review what I typed into MathPert:
1/2((x^2+4)^(-1/2)(x))-1/4((3-x)^2+1)(-1/2)(3-x))
“Count” the number of opening (( versus the number of closing )), they must match in any expression. I could also type, which is easier:
x/2sqrt(x^2+4)-(3-x)/4sqrt((3-x)^2+1)