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The evolution of populations & Hardy-Weinberg Equilibrium FRIDAY, SEPTEMBER 5, 2014

The evolution of populations & Hardy- Weinberg Equilibrium FRIDAY, SEPTEMBER 5, 2014

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Page 1: The evolution of populations & Hardy- Weinberg Equilibrium FRIDAY, SEPTEMBER 5, 2014

The evolution of populations & Hardy-Weinberg EquilibriumFRIDAY, SEPTEMBER 5, 2014

Page 2: The evolution of populations & Hardy- Weinberg Equilibrium FRIDAY, SEPTEMBER 5, 2014

Warm-up What do you think is the most important component in order for evolution to occur? (Hint: think about the definition of evolution).

Page 3: The evolution of populations & Hardy- Weinberg Equilibrium FRIDAY, SEPTEMBER 5, 2014

Homework Be a leader assignment… due Monday, September 8!◦Directions: Solve your problem on a separate sheet of paper and staple it to your given worksheet slip. Hand it in on Monday.

◦Be prepared to show your group how you solved the problem!

Page 4: The evolution of populations & Hardy- Weinberg Equilibrium FRIDAY, SEPTEMBER 5, 2014

Lamarck vs. Darwin

Inheritance of acquired characteristics Natural selection

Page 5: The evolution of populations & Hardy- Weinberg Equilibrium FRIDAY, SEPTEMBER 5, 2014
Page 6: The evolution of populations & Hardy- Weinberg Equilibrium FRIDAY, SEPTEMBER 5, 2014

Evolution is change in the genetic composition of a population from generation to generation

Page 7: The evolution of populations & Hardy- Weinberg Equilibrium FRIDAY, SEPTEMBER 5, 2014

But what is a more concise definition for evolution that will help us determine quantitatively if evolution is occurring??

Evolution is the change in allele frequencies over time

How can we measure allele frequencies?

How can we track changes in allele frequencies over time?

Page 8: The evolution of populations & Hardy- Weinberg Equilibrium FRIDAY, SEPTEMBER 5, 2014

Genetic variation exists in the population (this is key for evolution to occur!)

Certain alleles produce traits that are more adaptive, i.e., promote greater survival and reproduction

These alleles get passed on to the next generation

Page 9: The evolution of populations & Hardy- Weinberg Equilibrium FRIDAY, SEPTEMBER 5, 2014

Evolution is the change in allele frequencies in a population over generations Population: group of individuals of the same species that live in the same area and interbreed, producing fertile offspring. Gene pool: genetic makeup of a population

Page 10: The evolution of populations & Hardy- Weinberg Equilibrium FRIDAY, SEPTEMBER 5, 2014

Evolution is the change in allele frequencies in a population over generations

Mechanisms that cause allele frequency change:◦ Natural selection◦ Genetic drift◦ Gene flow◦ Mutation◦ Non-random mating

Only natural selection causes adaptive evolution

Page 11: The evolution of populations & Hardy- Weinberg Equilibrium FRIDAY, SEPTEMBER 5, 2014

Mini genetics review

Alleles are different versions of that geneExample:

Page 12: The evolution of populations & Hardy- Weinberg Equilibrium FRIDAY, SEPTEMBER 5, 2014

Combinations of alleles

Example for a population in which alleles for a gene are ‘R’ or ‘r’ Homozygous recessive: rr Homozygous dominant: RR Heterozygous: Rr

Skittles gene pool

Page 13: The evolution of populations & Hardy- Weinberg Equilibrium FRIDAY, SEPTEMBER 5, 2014

Now, how do we measure changes in allele frequencies in populations over time?

Page 14: The evolution of populations & Hardy- Weinberg Equilibrium FRIDAY, SEPTEMBER 5, 2014

First, we must know the starting point

What are the allele frequencies in the population right now? We cannot measure change unless we know the initial state.

Page 15: The evolution of populations & Hardy- Weinberg Equilibrium FRIDAY, SEPTEMBER 5, 2014

Use Hardy-Weinberg Principle to quantify evolution

Godfrey Harold "G. H." Hardy Wilhelm Weinberg

Page 16: The evolution of populations & Hardy- Weinberg Equilibrium FRIDAY, SEPTEMBER 5, 2014

The idea is to track allele frequencies

AA

AA

AA

AA AA

Aa

Aa

Aa

aa

aa

What is the frequency of allele A?What is the frequency of allele a?

Page 17: The evolution of populations & Hardy- Weinberg Equilibrium FRIDAY, SEPTEMBER 5, 2014

The idea is to track allele frequencies

AA

AA

AA

AA AA

Aa

Aa

Aa

aa

aa

The frequency for allele A = 13/20 or 0.65The frequency for allele a = 7/20 or 0.35

Page 18: The evolution of populations & Hardy- Weinberg Equilibrium FRIDAY, SEPTEMBER 5, 2014

AA

AA

AA

AA AA

Aa

Aa

Aa

aa

aa

Generation 1

?

Generation 2

Page 19: The evolution of populations & Hardy- Weinberg Equilibrium FRIDAY, SEPTEMBER 5, 2014

Hardy-Weinberg Principle Allele frequencies of alleles and genotypes in a population will remain constant from generation to generation if all assumptions are met

A gene pool that remains constant is said to be in Hardy-Weinberg equilibrium

Page 20: The evolution of populations & Hardy- Weinberg Equilibrium FRIDAY, SEPTEMBER 5, 2014

AA

AA

AA

AA AA

Aa

Aa

Aa

aa

aa

Generation 1

?

Generation 2

Page 21: The evolution of populations & Hardy- Weinberg Equilibrium FRIDAY, SEPTEMBER 5, 2014

AA

AA

AA

AA AA

Aa

Aa

Aa

aa

aa

Generation 1

A0.65

a0.35

A0.65

AA0.42

Aa0.23

a0.35

Aa0.23

aa0.12

Generation 2

Page 22: The evolution of populations & Hardy- Weinberg Equilibrium FRIDAY, SEPTEMBER 5, 2014

AA

AA

AA

AA AA

Aa

Aa

Aa

aa

aa

f(A) = 0.65f(a) = 0.35

A0.65

a0.35

A0.65

AA0.42

Aa0.23

a0.35

Aa0.23

aa0.12

f(A) = ?f(a) = ?

Page 23: The evolution of populations & Hardy- Weinberg Equilibrium FRIDAY, SEPTEMBER 5, 2014

AA

AA

AA

AA AA

Aa

Aa

Aa

aa

aa

f(A) = 0.65f(a) = 0.35

A0.65

a0.35

A0.65

AA0.42

Aa0.23

a0.35

Aa0.23

aa0.12

f(A) = 0.65f(a) = 0.35

Allele frequencies did not change, thus no evolution.

Page 24: The evolution of populations & Hardy- Weinberg Equilibrium FRIDAY, SEPTEMBER 5, 2014

The Hardy-Weinberg Principle

Allele frequencies in a population will remain constant if ALL of the following conditions are met:

1. The population is infinitely large2. Individuals mate randomly3. No gene flow4. No natural selection5. No mutations

If all conditions are met, then NO evolution. Allele frequencies will remain constant. This is the null hypothesis.

Page 25: The evolution of populations & Hardy- Weinberg Equilibrium FRIDAY, SEPTEMBER 5, 2014

The Hardy-Weinberg equation: p2 + 2pq + q2 = 1A

0.65a

0.35

A0.65

AA0.42

Aa0.23

a0.35

Aa0.23

aa0.12

Page 26: The evolution of populations & Hardy- Weinberg Equilibrium FRIDAY, SEPTEMBER 5, 2014

Understanding the equation

AA

AA

AA

AA AA

Aa

Aa

Aa

aa

aa

p2 + 2pq + q2 = 1p is the frequency of the dominant allele (A) = 0.65q is the frequency of the recessive allele (a) = 0.35

Page 27: The evolution of populations & Hardy- Weinberg Equilibrium FRIDAY, SEPTEMBER 5, 2014

p2 + 2pq + q2 = 1p is the frequency of the dominant allele (A) = 0.65q is the frequency of the recessive allele (a) = 0.35

p = f(AA) + ½ f(Aa)p = 0.5 + ½ 0.3 = 0.65

q = f(aa) + ½ f(Aa)q = 0.2 + ½ 0.3 = 0.35

Understanding the equation

AA

AA

AA

AA AA

Aa

Aa

Aa

aa

aa

Page 28: The evolution of populations & Hardy- Weinberg Equilibrium FRIDAY, SEPTEMBER 5, 2014

Using p and q from generation 1, solve for frequencies of predicted genotypes in generation 2 using HW

Page 29: The evolution of populations & Hardy- Weinberg Equilibrium FRIDAY, SEPTEMBER 5, 2014

Understanding the equation

A0.65

a0.35

A0.65

AA0.42

Aa0.23

a0.35

Aa0.23

aa0.12

p2 + 2pq + q2 = 1p is the frequency of the dominant allele (A) = 0.65q is the frequency of the recessive allele (a) = 0.35

p = f(AA) + ½ f(Aa)p = 0.5 + ½ 0.3 = 0.65

q = f(aa) + ½ f(Aa)q = 0.2 + ½ 0.3 = 0.35

Generation 2p = f(A) = 0.65q = f(a) = 0.35

Page 30: The evolution of populations & Hardy- Weinberg Equilibrium FRIDAY, SEPTEMBER 5, 2014

Understanding the equation

A0.65

a0.35

A0.65

AA0.42

Aa0.23

a0.35

Aa0.23

aa0.12

Generation 2p = f(A) = 0.65q = f(a) = 0.35

p2 + 2pq + q2 = 1p is the frequency of the dominant allele (A) = 0.65q is the frequency of the recessive allele (a) = 0.35

p = f(AA) + ½ f(Aa)p = 0.5 + ½ 0.3 = 0.65

q = f(aa) + ½ f(Aa)q = 0.2 + ½ 0.3 = 0.35

p2 = the predicted frequency of genotype AA = 0.422pq = the predicted frequency of genotype Aa = 0.46q2 = the predicted frequency of genotype aa = 0.12

Page 31: The evolution of populations & Hardy- Weinberg Equilibrium FRIDAY, SEPTEMBER 5, 2014
Page 32: The evolution of populations & Hardy- Weinberg Equilibrium FRIDAY, SEPTEMBER 5, 2014

The Hardy-Weinberg equation: p2 + 2pq + q2 = 1

What is the frequency of alleles B and b?

Page 33: The evolution of populations & Hardy- Weinberg Equilibrium FRIDAY, SEPTEMBER 5, 2014

Allele Frequencies

a) red = 0.36, white = 0.16

b) red = 0.6, white = 0.4

c) red = 0.5, white = 0.5

d) Allele frequencies cannot be determined unless the population is in equilibrium.

Red short-horned cattle are homozygous for the red allele, white cattle are homozygous for the white allele, and roan cattle are heterozygotes. Population A consists of 36% red, 16% white, and 48% roan cattle. What are the allele frequencies?

Page 34: The evolution of populations & Hardy- Weinberg Equilibrium FRIDAY, SEPTEMBER 5, 2014

Allele Frequencies

a) red = 0.36, white = 0.16

b) red = 0.6, white = 0.4

c) red = 0.5, white = 0.5

d) Allele frequencies cannot be determined unless the population is in equilibrium.

Red short-horned cattle are homozygous for the red allele, white cattle are homozygous for the white allele, and roan cattle are heterozygotes. Population A consists of 36% red, 16% white, and 48% roan cattle. What are the allele frequencies?

Page 35: The evolution of populations & Hardy- Weinberg Equilibrium FRIDAY, SEPTEMBER 5, 2014

Let’s see another example

We sampled 200 individuals from a population:

128 individuals have the AA genotype

53 individuals have the Aa genotype

19 individuals have the aa genotype

What are the genotype frequencies?

Page 36: The evolution of populations & Hardy- Weinberg Equilibrium FRIDAY, SEPTEMBER 5, 2014

Let’s see another example

We sampled 200 individuals from a population:

128 individuals have the AA genotype (0.64)

53 individuals have the Aa genotype (0.26)

19 individuals have the aa genotype (0.10)

What are the allele frequencies?

Genotype frequencies

Page 37: The evolution of populations & Hardy- Weinberg Equilibrium FRIDAY, SEPTEMBER 5, 2014

Let’s see another example

We sampled 200 individuals from a population:

128 individuals have the AA genotype (0.64)

53 individuals have the Aa genotype (0.26)

19 individuals have the aa genotype (0.10)

p = AA + ½(Aa) = 0.64 + ½(0.26) = 0.77

q = aa + ½(Aa) = 0.10 + ½(0.26) = 0.23

Genotype frequencies

Allele frequencies

Page 38: The evolution of populations & Hardy- Weinberg Equilibrium FRIDAY, SEPTEMBER 5, 2014

Let’s see another example

We sampled 200 individuals from a population:

128 individuals have the AA genotype (0.64)

53 individuals have the Aa genotype (0.26)

19 individuals have the aa genotype (0.10)

p = AA + ½(Aa) = 0.64 + ½(0.26) = 0.77

q = aa + ½(Aa) = 0.10 + ½(0.26) = 0.23p + q = 0.77 + 0.23 = 1.0p2 + 2pq + q2 = (0.77)2 + 2(0.77)(0.23) + (0.23)2 = 1.0

Genotype frequencies

Allele frequencies

Page 39: The evolution of populations & Hardy- Weinberg Equilibrium FRIDAY, SEPTEMBER 5, 2014

Let’s work through another example

Albinism (aa) occurs on average 1 in 20,000 individuals in North America.

What is the frequency of the A and a allele in this population?

Page 40: The evolution of populations & Hardy- Weinberg Equilibrium FRIDAY, SEPTEMBER 5, 2014

Let’s work through another exampleAlbinism (aa) occurs on average 1 in 20,000 individuals in North America. What is the frequency of the A and a allele in this population?

The Hardy-Weinberg equation: p2 + 2pq + q2 = 1

q2 = f(aa) = 1/20,000 = 0.00005√ q2 = √ 0.00005q = 0.007 (frequency of a in the population)

p = 1 – qp = 1 – 0.007 p = 0.993 (frequency A in the population)

p2 + 2pq + q2 (0.993)2 + 2(0.993)(0.007) + (0.007)2 = 1.0

p2 = 98.6% (AA)2pq = 1.4% (Aa)q2 = 0.005% (aa)

Page 41: The evolution of populations & Hardy- Weinberg Equilibrium FRIDAY, SEPTEMBER 5, 2014

The Hardy-Weinberg Principle Allele frequencies in a population will remain constant if ALL of

the following conditions are met:1. The population is infinitely large2. Individuals mate randomly3. No genetic migration and mutation4. No natural selection5. No mutation

If ALL conditions are met, then there’s NO evolution. Allele frequencies will remain constant.

The Hardy-Weinberg equation: p2 + 2pq + q2 = 1

Page 42: The evolution of populations & Hardy- Weinberg Equilibrium FRIDAY, SEPTEMBER 5, 2014

AA

AA

AA

AA AA

Aa

Aa

Aa

aa

aa

f(A) = 0.65f(a) = 0.35

A0.65

a0.35

A0.65

AA0.42

Aa0.23

a0.35

Aa0.23

aa0.12

What will happen if these assumptions are not met?1. The population is infinitely large2. Individuals mate randomly3. No genetic migration and mutation4. No natural selection

f(A) = 0.65f(a) = 0.35

Page 43: The evolution of populations & Hardy- Weinberg Equilibrium FRIDAY, SEPTEMBER 5, 2014

Exit TicketWhat is the Hardy-Weinberg formula, and what does each component represent?

Page 44: The evolution of populations & Hardy- Weinberg Equilibrium FRIDAY, SEPTEMBER 5, 2014

Work on Clover Study