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The Calculus of Juggling. Ashley Bennett Stephen Bent. 3-Ball Cascade. 5-ball Cascade. We knew that the formula for an accelerating body is:. Distance = (startingvelocity)(time) +(1/2)(acceleration)(time)(time) d = (v o )(t)+(1/2)(a)(t 2 ). - PowerPoint PPT Presentation
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The Calculus of Juggling
Ashley Bennett
Stephen Bent
3-Ball CascadeTrial Time (seconds)
1 0.47
2 0.49
3 0.52
4 0.49
5 0.51
Average 0.496
5-ball CascadeTrial Time (seconds)
1 0.63
2 0.68
3 0.67
4 0.64
5 0.64
Average 0.658
We knew that the formula for an accelerating body is:
Distance = (startingvelocity)(time)
+(1/2)(acceleration)(time)(time)
d = (vo)(t)+(1/2)(a)(t2)
Second Degree Taylor Polynomial
General Formula:
P2(x) = f(a) + f’(a)(x-a) + ½f’’(a)(x - a)2
Specifically:
d = (first derivative) (change in time) + (½) (second derivative)*(change in time)* (change in time)
Hand 1q1 Hand
He
igh
t
Three Ball Cascade:t/2 = .496/2 = .248 seconds
Five Ball Cascade:t/2 = .658/2 = .329 seconds
• Three Ball Cascade:
d = (0)(.248) + (1/2)(9.8)(.2482) = .30317 meters
• Five Ball Cascade:
d = (0)(.329) + (1/2) (9.8) (.3292) = .53038 meters
3 Ball CascadeTrial Height (meters)
1 0.30
2 0.30
3 0.31
4 0.31
5 0.30
Average 0.304
5 Ball CascadeTrial Height (meters)
1 0.53
2 0.53
3 0.53
4 0.53
5 0.53
Average 0.53
V = V0 + a*t
• Three Balls:V = (0) + (9.8) (.248) = 2.4304 meters/second
• Five BallsV = (0) + (9.8) (.329) = 3.2242 meters/second
Three Balls:V = V0 + (a) (t)
V = 2.4304 – (9.8*t)
t
V
Five Balls:V = V0 + (a) (t)
V = 3.2242 – (9.8*t)
t
V
Assumptions
• 1: Juggling is consistent
• 2: Gravity is the only force
• 3: Stephen’s juggling height and speed is law!!!