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1CCB 3024
PROCESS PLANT DESIGN
Lecturer : Dr Abrar Inayat
Conceptual Process Design
Synthesis of Reaction System (2)
21. Select appropriate reactor system according to the reaction system
2. Specify suitable range for the design/operating parameter of reactors
3. To know about the mathematical approaches for reactor network
At the end of this lecture, student should be able to ;
HEURISTICPolymerisation reaction ......
Polymers are characterised by the distribution of molecular weight.
2 broad types of reaction
1. Reactions with Termination steps
eg.polymerisation of Vinyl Chloride
R + CH2 = CHCl ------> RCH2 - CHCl
initiator
CH3 or
OH
vinyl chloride vinyl chloride free radical
propagates
RCH2 - CHCl + CH2 = CHCl ------> RCH2 - CHCl - CH2 - CHCl
leading to
R - (CH2 - CHCl)n - CH2 - CHCl
Reaction terminated by
the joining of these molecules
Polymers
Question ?
How do we
select suitable
type of reactor
for such
reaction ?
3The active polymer life is short as compared to
the average residence time in reactor.
Important note for the reaction :
RCH2 - CHCl + CH2 = CHCl ------> RCH2 - CHCl - CH2 - CHCl
leading to
R - (CH2 - CHCl)n - CH2 - CHCl PolymersReaction terminated bythe joining of these molecules
The length of the chain depends on
concentration of free radical available
in the reactor. The concentration of the
free radical decreases as reaction proceed
with time. Therefore, at beginning due to
presence of high concentration of free radical,
polymer chain tend to be shorter. As reaction time
proceeds, lesser free radical concentration thus
harder for termination steps to take place resulting
in longer chain molecule.
Best to choose CSTR.
CSTR
HEURISTIC
HEURISTIC
2. Reactions without Termination Step.
eg.polycondensation
HO - (CH2)n - COOH + HO - (CH2)n - COOH
--------> HO - (CH2)n - COO - (CH2)n - COOH + H2O
In this reaction, the polymer grows by successive esterification with
elimination of water and no termination step.
How do we select suitable type of reactor for such reaction
Question ?
The active polymer life is long compared to the average residence
time in reactor. It is highly desirable for all the molecules to have
almost similar residence time to produce polymer of similar chain
length. Therefore, control of residence time is important.
Best to choose PLUG FLOW
PLUG FLOW
4Example on Reactor Selection
Given the following reaction systems to produce product C, select a suitable reactor for the system.
A + B C rC = k1 CA0.5 CB
2
A + B D rD = k3 CA CB
C D rD = k2 CC2 Mixture of series parallel reactions
Analysing the parallel reaction
A + B C rC = k1 CA0.5 CB
2
A + B D rD = k3 CA CB
r3
r1=
k3
k1CA
1-0.5
CB1-2
r3
r1=
k3
k1CA
0.5
CB-1
What reactor configuration should be selected?
r3
r1=
k3
k1CA
1-0.5
CB1-2
r3
r1=
k3
k1CA
0.5
CB-1
Semi CSTR
B
A
OR
SEMI PLUG FLOW
REACTANT A
REACTANT B
Analysing the series reaction
A + B C rC = k1 CA0.5 CB
2
C D rD = k2 CC2
Control of residence time is important.
Therefore choose plug flow.
5Reactor Operating Parameter
In the preceding lecture, the choice of the reactor is made based on the most appropriate
concentration profile as the reaction progressed. However, there are still important effects that need
to be considered i.e., the reactor operating parameter.
Besides looking at the reaction system, the other aspects governing chemical reaction which have
to be considered are;
1. Reaction Equilibrium for reversible reaction.
Pressure Effect
aA + bB cC + dD
The extent of reaction which can be calculated using Gibbs Free Energy =
0 = ln where
=
.
.
.
.
For gaseous reaction
=
.
.
.
.
For liquid reaction
Eg : Given reaction below at 1 bar, 300 K to produce Ammonia NH3. Feed is according to the stoichiometric ratio.
3 H2 + N2 2 NH3
Given the data for Std. Free Energy of Formation 3000(
)
H2 0
N2 0
NH3 -16.223
ln =(2 16,223 0 0 )
8.314 300= 13.008
ln =0
= 4.4597 105
=3
2
23 .2
= 3
2
23 .2
2
a. Determine Ka equilibrium constant
H2 N2 NH3
Initial moles
Equilibrium moles
Total moles at equillibrium = 4 2X
Mole Fraction
3 1 0
3-3X 1-X 2X
3-3X 1-X 2X
4-2X 4-2X 4-2X
Assume ideal gas law
6Eg : Given reaction below at 1 bar, 300 K to produce Ammonia NH3. Feed is according to the stoichiometric ratio.
3 H2 + N2 2 NH3 H2 N2 NH3
Mole Fraction3-3X 1-X 2X
4-2X 4-2X 4-2X =3
2
23 .2
= 3
2
23 .2
2
b. Composition of the reaction products at equilibrium
=3
2
23 . 2
2 =162 2 2
27 1 4for P = 1 bar
X = 0.97 bar
Therefore the composition at equilibrium is ;
H2 [3 3 (0.97)] / [4 2 (0.97)] = 0.0437
N2 [1 (0.97)] / [4 2 (0.97)] = 0.0146
NH3 [2 (0.97) / [4 2 (0.97)] = 0.9418
Besides looking at the reaction system, the other aspects governing chemical reaction which have
to be considered are;
2. Reaction Equilibrium for reversible reaction.
Temperature Effect (Endothermic & Exothermic Reaction)
aA + bB cC + dD
Integrate the above relation ;
21
= 0
1
2
1
1The effect of temperature on reaction equilibrium could be determined since the std. heat of reaction is available
in thermodynamics data.
0 = 0 +
0 0
0
For exothermic reaction the DH0 is < 0 while for endothermic reaction the DH0 is > 0
For exothermic reaction, higher temperature will shift the equilibrium to reactant side while
For endothermic reaction, higher temperature will shift equilibrium to product side.
0
= 0
2=
ln
The extent of a reaction is influenced by temperature can be calculated using enthalpy of formation through the
relation developed from Gibbs Free Energy
0 = lnfrom
7Besides looking at the reaction system, the other aspects governing chemical reaction which
have to be considered are;
3. Rate of Reaction - Temperature Effect. aA + bB cC + dD
The effect of temperature on rate of reaction can be computed from the Arhennius equation.
= 0
Expanding the equation
21
=
1
1
1
2E is the activation energy
Generally, the higher the temperature, the higher is the reaction rate.
3. Decide on the Reaction Condition - operational parameter.
Let's consider concentration of reactants in the reactor
HEURISTIC
Some possibilities to consider
EXCESS OF ONE REACTANTS
This can force the reaction of a selected
component to completion due to certain
reason.
ADDITION OF INERTS
This can favour reaction to proceed
towards favorable direction.
eg. Feed Prod1 + Prod2
Rxn. cause an increase in no. of moles. Adding
inert cause reduction in no. of moles/vol.
Therefore rxn. proceed to produce more products.
eg. C2H4 + Cl2 ---> C2H4Cl2
Cl2 is difficult to separate. Add excess of C2H4 to
force complete reaction of Cl2
DESIGN PROCEDURE FOR REACTOR OPERATING PARAMETER.
8HEURISTIC
RECYCLE UNWANTED BYPRODUCTS
This can surpress the formation
of more unwanted by-products.
Let's consider concentration of reactants in the reactor (cont...)
REMOVAL OF PRODUCT
This can get the reaction to proceed to
the favorable direction.
eg. 2SO2 + O2 2SO3
Intermediate removal of Sulfur trioxide will
make the reaction towards producing more
products. But how?
R A R A
H2O
absorption absorption
H2O
Some possibilities to consider
eg. Feed1 + Feed2 Product
Feed1 + Feed2 Byproduct Rxn 2
Recycling byproduct will suppress
reaction 2 thus avoiding waste of feed material
HEURISTIC
Consider more complex reaction !
ratio of secondary
to primary reaction
r2
r1=
k2
k1Cfeed1 Cfeed2
a2 -a1 b2 -b1
Even after reactor selection was made, there are still opportunities for maximising selectivity !
1. If (a2-a1) > (b2-b1), use excess Feed2 and if (a2-a1) < (b2-b1), use excess Feed1
2. If reaction 2 is reversible, increasing inerts concentration will decrease byproduct formation.
3. Recycling the byproducts to the reactor will suppress the formation of more byproducts
if the reaction is reversible.
Let's consider concentration of reactants in the reactor (cont...)
Multiple reactions in parallel producing byproducts
Rxn 1 : r1 = k1 Cfeed1 Cfeed2a1
Feed1 + Feed2 ------> Product (s)
Feed1 + Feed2 ------> Byproduct (s)
b1
Rxn 2 : r2 = k2 Cfeed1 Cfeed2a2 b2
9HEURISTIC
Multiple reaction in series producing byproducts.
Feed(s) -------> Product
Product -------> Byproduct(s)
Rxn 1 : r1 = k1 Cfeeda1
Rxn 2 : r2 = k2 Cproducta2
Formation of byproducts is minimise by keeping the product composition low in the reactor.
Option that can be considered :
Use of 3rd component which does not participate in the reaction to produce byproducts
Intermittent/intermediate removal of products as reaction takes place.
eg. C6H5CH3 + H2 -------> C6H6 + CH4
2C6H6 C12H10 + H2 The use of excess Hydrogen
helps to minimise formation
of diphenyl.
HEURISTIC
Mixed parallel and series reactions producing byproducts
Feed(s) -------> Product
Feed(s) -------> Byproduct(s)
Product -------> Byproduct(s)
Feed(s) ------> Product(s)
Feed(s) ------> Byproduct(s)
Product ------> Byproduct(s)
Options that can be considered ;
The use of excess 3rd component which does not involve in reaction to produce byproduct
can suppress the byproduct formation by keeping product composition low.
Recycling of byproducts if the reaction is reversible can assist in minimising byproduct
formation.
Rxn 1 : r1 = k1 Cfeeda1
Rxn 3 : r3 = k3 Cproducta3
Rxn 2 : r2 = k2 Cfeeda2
10
3. Decide on the Reaction Condition - operational parameter.
SUGGESTED PROCEDURE (cont...)
Let's now consider temperature for the operation of the reactor.
HEURISTIC
Generally, there are several critical temperature limits that apply to chemical processes. At elevated temperatures, common construction materials (primarily carbon steel), suffer a significant drop in physical strength and must be replaced by a more costly material.
Turton et al., Analysis, Synthesis and Design of Chemical Processes 1998
Temperature Ambient 400 C 550 C
Tensile Strength of Material (bar)
Carbon Steel (grade 70) 1190 970 170
Stainless Steel (Type 302) 1290 1290 430
A decision to operate above 400 C must be justified in view of the material limitation.
From utility perspective, a decision to operate outside the range of 40 C to 260 C requiring special heating/cooling media, has to be justified. Within this range, normal steam and cooling water could be utilised easily.
Turton et al., Analysis, Synthesis and Design of Chemical Processes 1998
3. Decide on the Reaction Condition - operational parameter.
SUGGESTED PROCEDURE (cont...)
Let's now consider temperature for the operation of the reactor.
HEURISTIC
How do we decide ?
SINGLE REACTION
Endothermic Rxn
Set T as high as possible
Good for rate of reaction
So what is the limit ?
Exothermic Rxn
Set T low to take advantage on
conversion in a reversible reaction.
Not good for rate of reaction
So what is the compromise ?
Need to compromise !
MULTIPLE REACTIONS
For Parallel/Series Reaction
A ---> B ---> Ck1 k2
B product
if k1 increase more than k2 w.r.t. T, then go for as
highest T as possible.
if k2 increase more than k1 w.r.t. T, then go for as
lowest T as possible. Careful, as need to compromise.
The main issue is how to control T effectively.
Can you suggest a number of ways to do that.
11
HEURISTIC
Let's now consider pressure for the operation of the reactor.
3. Decide on the Reaction Condition - operational parameter.
SUGGESTED PROCEDURE (cont...)
There are economic advantages associated with operating equipment at higher pressure when gases are present i.e., decrease in gas volume. This tend to reduce the size of equipment to give the required residence time. Most chemical processing equipment can withstand pressures up to 10 bar without additional capital investment. Beyond 10 bar, thicker walls for the equipment vessel is required thus contributing to higher cost.
Likewise operating below ambient pressure causes equipment size to be larger and thus increased in capital cost.
A decision to operate outside the pressure range of 1 to 10 bar must be justified.
Turton et al., Analysis, Synthesis and Design of Chemical Processes 1998
HEURISTIC
Let's now consider pressure for the operation of the reactor. For liquid phase reaction,
pressure is known to have
little effect. Why?For vapour phase reaction....
SINGLE REACTION
Decrease in number of moles
Pressure decreases as reactant/s
were converted to products
Increase pressure to take advantage.
Increase in number of moles
Decrease pressure to take advantage
Pressure increases as reactant/s
were converted to products
MULTIPLE REACTIONS
The same general guideline can be used but
consideration has to be given when having
competing reaction producing byproducts.
Selectivity has to be taken into account !
3. Decide on the Reaction Condition - operational parameter.
SUGGESTED PROCEDURE (cont...)
12
HEURISTIC
4. What about reactor phase?
Given the fact that the temperature and pressure
has been decided normaly, the phase can be
determined directly !
The preferences if possible ---> liquid phase reactor !
Smaller Reactor Volume
Higher density thus higher concentration
per volume size
However, depends on other matters
- Rate of mass/Heat transfer
- Safety consideration
Gas phase might have
better transfer of heat & mass
Not so much of an important criteria !
SUGGESTED PROCEDURE (cont...)
HEURISTIC
5. Catalyst Selection.
Function of Catalyst :
increase rate of reaction without changes in quantity and composition
at the end of reaction.
Homogenous Catalyst
may modify reaction mechanism by
participating in the reaction but regenerated
back in the subsequent step.
eg. production of ketene from acetic acid.
CH3COOH ----> CH2=C=O + H2O
use triethyl phospate as a
catalyst.
problem : possible loss of catalyst due
to imperfect separation to recover
catalyst.
Heterogenous Catalyst
- Catalyst differ in phase from reacting species
- Most oftenly solid
- Reacting species diffuse to surface of catalyst and
are adsorped. Reaction takes place and products
then desorb and diffuse back to bulk gas/liquid.
- Effective surface area on catalyst which depends
on catalyst porosity is an important consideration.
SUGGESTED PROCEDURE (cont...)
13
Example (Text by Smith R. pg. 80)
Given the reaction below for the production of monoethanolamine;
Ethylene oxide + ammonia monoethanolamine
Monoethanolamine + ethylene oxide diethanolamine
Diethanolamine + ethylene oxide triethanolamine
Side reaction
Side reaction
Select a reactor that will maximise the production of monoethanolamine.
Suggest option for the operational condition which could further maximise the production.
Plug Flow to control residence time.
Excess AmmoniaIntermediate removal of Monoethanolamine.
Example.
tert-Butyl hydrogen sulfate is produced from the reaction below;
Iso-butylene + sulfuric acid tert-butyl hydrogen sulfate
tert-butyl hydrogen sulfate + water tert-butyl alcohol + sulfuric acid
The primary reaction is rapid and exothermic. Laboratory studies indicate that the reactor yield is a maximum when the concentration of sulfuric acid is maintained at 63 percent. The temperature should be maintained around 0 oC to avoid excessive formation of byproducts.
Make the choice of the reactor.
Sulfuric acid
14
During the conceptual design of a chemical process, among the related decisions that
have to be made concerning reactor ;
SELECTION OF REACTOR
Reactor Type and/or Network Operating Conditions
CSTR
PLUG FLOW
RECYCLE REACTOR
CSTR OR BATCH
PLUG FLOW RECYCLE REACTOR
PLUG FLOW
RECYCLE REACTORCSTR
TEMPERATURE
PRESSURE
CONCENTRATION
INERT
CATALYST
?
REACTOR VOLUME
AND ORIENTATION
HOW DO WE
DECIDE ?
Recall the following slide again.....
we have look at tackling this using heuristic approach !
We have seen a number of guidelines developed to conceptually design reactor.
Limitations will appear when having to deal with complex reactor configuration/network.
The method that can deliver this will need extensive mathematics and programming
- Mathematical Programming Approach.
Simple reaction
straight forward thus
simple guideline will do.
A B
B C
simple plug flow reactor
Highly Complex reaction
complicated with conflicting in guideline.
require complex reactor - network of reactor !
A + B C D
A + C E
exotherm. rxn
endotherm. rxn
B + D F endotherm. rxn
D is the product !
Could be ;
How can we derive such configuration
or network just from the heuristic guideline ?
Synthesis of Reactor Network Mathematical Programming Approach
Flow Pattern
Mixing Location
Heating & Cooling
15
MATHEMATICALBut how do we go about doing this ?
Recall the key info. required when designing reactor
Reaction Chemistry Reaction Kinetics
For simple reaction chemistry, selection of
reactor can be done using the heuristic guideline
even without the reaction kinetics.
But for complex reaction chemistry, since
mathematical programming approach is
to be adopted, detailed reaction kinetics now
become important.
Still the important parameters that decide the reactor network are ;Conversion
Selectivity
Selectivity normally becomes the more dominant one.
Recall the mathematical programming approach that was introduced earlier.
Generate a super structure containing all alternatives and optimised it
in order to produce the optimal solution.
MATHEMATICAL
Formulate/Generate a super structure which contains all possible candidates for the
solution of the optimal reactor. Then solved it mathematically.
The superstructure is created mathematically.
How do we identify all the possible candidates for the solution ?
One Option : Use the method of Geometric Concepts for Attainable Region
Biegler, Grossman & Westerberg,
Synthesis Methods of Chemical Process Design pp 438 - 447
For chemical reactor networks, the attainable region concept was first presented
by Horn (1964) who noted that ;
...variable such as recycle flowrate and composition of the product form a space which in
general can be divided into an attainable region and a non-attainable region. The attainable
region corresponds to the totality of physically possible reactors ... Once the border is known
the optimum reactor corresponding to a certain environment can be found by simple geometric
considerations.Horn F., (1964). Attainable Regions in Chemical Reaction Technique. In the
3 rd European Symposium on Chemical Reaction Engg. London: Pergamon.
SUGGESTED PROCEDURE
16
MATHEMATICALTo briefly understand how it works,
Consider a reaction A B C
C
Time
A B
C
MATHEMATICAL
A B C
CB
CA
H
E
GF
For a PFR with variable residence time and fixed feed CA0 and CB0, one can solve
the ordinary differential equations from the feed point :
dCA / dt = rA
dCB / dt = rBdCB / dCA = rB / rA
From this differential eqn.,
we can plot the trajectory for
HEGF
CSTR
PLUG FLOW
17
MATHEMATICAL
Consider a reaction A --> B ---> C
CB
CA
H
E
GF
For a CSTR, the path from the feed can be generated using the equations:
From this eqn., we can plot the
trajectory for GH
CA - CA 0 = t rA
CB - CB 0 = t rB
CA - CA 0CA - CA 0
CB - CB 0= rA / rB
PLUG FLOW
CSTR
Note that in the two cases above, we assume a fixed feed, an initial temperature and trajectories
that are determined entirely by the state eqns. derived for concentration as shown above. This is
true unsteady state for isothermal or adiabatic systems.
MATHEMATICAL
How do we plot the attainable region ?
Plot the attainable region using reaction/rate
vectors. The eqn. for the vectors are obtained
from the plug flow and/or CSTR trajectory
as shown earlier.
dCB / dCA = rB / rA
CA - CA 0CA - CA 0
CB - CB 0= rA / rB
plug flow
CSTR
Example 13.3 page 443 : Systematic Methods of Chemical Process Design
Biegler, Grossman & Westerberg.
illustrates the application of the method !
CB
CA
H
E
GF
PLUG
FLOW
CSTR
18
MATHEMATICAL
The attainable region will assist in setting the super structure for the mathematical
programming approach in the sense that it can provide engineer with the family of solutions for
the problem related to reactor network. This will significantly reduces the number of options
that have to be dealt by the mathematical programming during optimisation.
During the conceptual design of a chemical process, among the related decisions that
have to be made concerning reactor ;
SELECTION OF REACTOR
Reactor Type and/or Network Operating Conditions
CSTR
PLUG FLOW
RECYCLE REACTOR
CSTR OR BATCH
PLUG FLOW RECYCLE REACTOR
PLUG FLOW
RECYCLE REACTORCSTR
TEMPERATURE
PRESSURE
CONCENTRATION
INERT
CATALYST
?REACTOR VOLUME
AND ORIENTATION
HOW DO WE
DECIDE ?
Hence the task of determining this,
is made simpler !
Conclusions
We have looked at the followings;
Selection of Suitable Reactor for a Specified Reaction System : Plug flow, CSTR,Hybrid of Plug Flow and CSTR.
Determination of Suitable Reactor Operating Parameter : Temperature, Pressure,Reactant Concentration etc.
Mathematical approach for reactor synthesis
19