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1 Structured Data Types A structure can be used to combine data of different types into a single (compound) data value. Like all data types, structures must be declared and defined. C has three different ways to define a structure variable structures tagged structures type-defined structures

Structured Data Types

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Structured Data Types. A structure can be used to combine data of different types into a single (compound) data value . A Java class is a generalization of a C struct . - PowerPoint PPT Presentation

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Page 1: Structured Data Types

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Structured Data Types• A structure can be used to combine data of

different types into a single (compound) data value.

• Like all data types, structures must be declared and defined.

• C has three different ways to define a structure– variable structures– tagged structures– type-defined structures

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Structured Data TypesA variable structure definition defines a struct variable. struct {

unsigned char red; unsigned char green; unsigned char blue; } pixel;

variable name DON’T FORGET THE SEMICOLON

Members

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Structured Data Types

A tagged structure definition defines a type. We can use the tag to define variables, parameters, and return types.

struct point_t structure tag {

double x; Member names double y; };

DON’T FORGET THE SEMICOLON

To Use: struct point_t point1, point2;

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Structured Data Types • Example 2 (tagged structure definition) struct pixel_t {

unsigned char red; unsigned char green; unsigned char blue;

};

DON’T FORGET THE SEMICOLON

To Use: struct pixel_t pixel;

Structure tag

Members

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Structured Data Types

• A typed-defined structure is the most powerful way to declare a structure. We can use the tag to define variables, parameters, and return types.

typedef struct pixel_type { unsigned char red;

unsigned char green; unsigned char blue; } pixel_t;

• To declare a variable of the new type, use:

pixel_t pixel;

New type name

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Structured Data Types Example 2 (typed-defined structure) typedef struct pointType { double x; double y;

} point_t;

To declare variables of the type, use: point_t point1;

point_t point2;

These structure variable definitions create member variables x and y associated with the structure.

New type name

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Structured data types

• Member variables of a struct are accessed using the dot operator. pixel1.red = 200; pixel1.green = 200;

pixel1.blue = 0; point1.x = 10.0; // type is double

point1.y = 5.5; // type is double

• These variables may be used exactly like any other variables.

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Example

typedef struct student_type{

int id; char grade;

} student_t;int main( ) { student_t student; student.id = 2201; student.grade = ‘A’; fprintf(stdout, “id: %d, grade: %c\n”, student.id, student.grade);

return 0;}

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Initializing Structures• At declaration time, members of a struct can be

initialized in a manner similar to initializing array elements.

pixel_t pixel = {255, 0, 100};• The sequence of values is used to initialize the

successive variables in the struct. The order is essential.• It is an error to have more initializers than variables. • If there are fewer initializers than variables, the

initializers provided are used to initialize the data members. The remainder are initialized to 0 for primitive types.

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Use of sizeof() with structures• The sizeof() operator should always be used in

dynamic allocation of storage for structured data types and in reading and writing structured data types. However, it is somewhat easy to do this incorrectly.

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Structures as parameters to functions• A struct, like an int, may be passed to a function. • The process works just like passing an int, in that:– The complete structure is copied to the stack– The function is unable to modify the caller's

copy of the variable

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Structures as parameters to functions#include <stdio.h>

typedef struct s_type{ int a; double b;} sample_t;

void funct(sample_t x){ fprintf(stdout, "x.a = %d\n", x.a); fprintf(stdout, "x.b= %lf\n", x.b); x.a = 1000; x.b = 55.5;}

int main() { sample_t y; y.a = 99; y.b = 11.5; funct(y); fprintf(stdout, "y.a = %d\n", y.a); fprintf(stdout, "y.b = %lf\n", y.b); return 0;}

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Structures as parameters to functionsSample Run:

[11:26:47] rlowe:~ [142] ./a.outx.a = 99x.b= 11.500000y.a = 99y.b = 11.500000

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Structures as parameters to functions• The disadvantages of passing structures by value

are that copying large structures onto the stack– is very inefficient and– may even cause program failure due to stack

overflow.typedef struct { int w[1024 * 1024];} sample_t;

/* passing a struct of type sampleType above will cause */

/* 4 Terabytes to be copied onto the stack. */

sample_t fourMB; for(i = 0; i < 1000000; i++) { slow_call(fourMB); }

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Passing the address of a struct• A more efficient way is to pass the address of the

struct.• Passing an address requires that only a single

word be pushed on the stack, regardless of how large the structure is.

• Furthermore, the called function can then modify the structure.

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Passing the address of a struct#include <stdio.h>typedef struct { int a; double b;} sample_t;

/* Use the * operator. funct modifies the struct */void funct (sample_t *x) { fprintf(stdout, "x->a = %d\n", x->a); // note the

use of -> operator fprintf(stdout, "x->b = %lf\n", x->b); x->a = 1000; x->b = 55.5;}int main() { sample_t y; y.a = 99; y.b = 11.5; /* use the address operator, &, in the call */ funct(&y); fprintf(stdout, "y.a = %d\n", y.a); fprintf(stdout, "y.b = %lf\n", y.b); return 0;}

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Passing the address of a structSample run:

[11:39:29] rlowe:~ [169] ./a.outx->a = 99x->b = 11.500000y.a = 1000y.b = 55.500000

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Passing the address of a struct• What if you do not want the recipient to be

able to modify the structure?• In the prototype and function header, use the *

operator.– Use the const modifier

void funct(const sample_t *x) ;

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Using the const modifier#include <stdio.h>

typedef struct s_type{ int a; double b;} sample_t;

void funct(const sample_t *x) { fprintf(stdout, "x.a = %d\n", x->a); fprintf(stdout, "x.b = %d\n", x->a); x->a = 1000; x->b = 55.5;}

int main( ) { sample_t y; y.a = 99; y.b = 11.5; /* to pass the address use the & operator */ funct(&y); fprintf(stdout, "y.a = %d\n", y.a); fprintf(stdout, "y.b = %d\n", y.b); return 0;}

– The above code will generate a compile-time error.

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Using the const modifier

• [11:34:04] rlowe:~ [147] gcc struc5.c• struc5.c: In function 'funct':• struc5.c:12: error: assignment of read-only

location• struc5.c:13: error: assignment of read-only

location

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Arrays within structuresAn element of a structure may be an array

typedef struct { char name[25]; double payRate; int hoursWorked[7];} timeCard_type;

timeCard_type myTime;Elements of the array are accessed in the usual

way: myTime.hoursWorked[5] = 6;

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Arrays of structures• We can also create an array of structure types:

pixel_t pixelMap[400 * 300];student_t roster[125];

• To access an individual element of the array, pixelMap[20].red = 250; roster[50].gpa = 3.75;

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Arrays of structures containing arrays• We can also create an array of structures that

contain arraystimeCard_type employees[50];

• To access an individual element employees[10].hoursWorked[3] = 10;

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Structures containing structures• It is common for structures to contain elements

which are themselves structures or arrays of structures. In these cases, the structure definitions should apear in "inside-out" order.

• This is done to comply with te usual rule of not referencing a name before it is defined.

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Structures containing structurestypedef struct { unsigned char red; unsigned char green; unsigned char blue;} pixel_t;

typedef struct { int numRows; int numCols; pixel_t pixelData[400 * 300];} image_t;

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Structures as return values from functions• Scalar values (int, float, etc) are efficiently

returned in CPU registers.• Historically, the structure assignments and the

return of structures was not supported in C.• But, the return of pointers (addresses), including

pointers to structures, has always been supported.

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Structures as return values from functionstypedef struct { int a; double b;} sampleType;sample_t *funct ( ) { sample_t s; s->a = 1000; s->b = 55.5; return (&s);}int main() { sample_t *y; y = funct( ); fprintf(stdout, "y->a = %d\n", y->a); return 0;}rlowe@hornet7 [160] ./a.outreturnParam.c: In function 'funct':returnParam.c:8: warning: function returns address of local

variable

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Structures as return values from functions• The reason for the warning is that the

function is returning a pointer to a variable that was allocated on the stack during execution of the function.

• Such variables are subject to being wiped out by subsequent function calls.

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Structures as return values from functions• It is possible for a function to return a

structure.• This facility depends upon the structure

assignment mechanisms which copies one complete structure to another.– This avoids the unsafe condition associated

with returning a pointer, but– incurs the possibly extreme penalty of

copying a very large structure

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Structures as return values from functions#include <stdio.h>

typedef struct s_type { int a; double b;} sample_t;

sample_t funct ( ) { sample_t s; s.a = 1000; s.b = 55.5; return s;}

int main() { sample_t y; sample_t z; y = funct(); z = y; printf("%d %d\n", y.a, z.a); return 0;}

[11:51:51] lowerm@spider3:~ [184] ./a.out1000 1000

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Summary• Passing/returning instances of structures

potentially incurs big overhead.• Passing/returning addresses incurs almost no

overhead• Accidental modifications can be prevented with

const– Therefore, it is recommended that, in general,

you never pass nor return an instance of a structure unless you have a very good reason for doing so.

• This problem does not arise with arrays.– The only way to pass an array by value in the

C language is to embed it in a structure– The only way to return an array is to embed it

in a structure.