Structural Design for Low Rise Building

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    Supervised by : Dr. Khaled El-Sawy

    ID#Name200303838Saeed Mohammad Al Kaabi

    200304178Ahmed Obaid Al Dhaheri

    200303853Mohammad Owais AL Daraei

    200303840Ahmed Abdullah Al Braiki

    United Arab Emirates University

    College of Engineering

    Department of Civil and Environmental Engineering

    Industrial Training & Graduation Projects

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    -Introduction

    -Structural design of :

    o Slabs

    o Beams

    o Stairs

    o Columns

    o Tie-beams

    o Footing

    -Environmental, Financial, and Social Impact

    -Conclusion

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    .fc` Compressive strength of concrete = 28MPa

    .fy Yielding strength of steel = 420 MPa

    .Ig Moment of inertia

    .Ag Area gross

    .Ie Effective moment of inertia

    .wu Ultimate weight

    .Vu Ultimate shear

    .Mu Ultimate bending moment

    .Mcr Cracking moment .Icr Cracking moment of inertia

    .K Effective length factor

    .Ec Elasticity of concrete

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    The considered low-rise building consists of three blocks

    The Majles and Kitchen were designed in GP-I

    The Villa is designed in GP-II

    The slabs, beams, columns, tie- beams, stairs and footings arestructurally designed.

    This structural design in project followed the ACI-318-02M code.

    Prokon, AutoCAD and Excel sheets are used in the design.

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    Project area = 903 m2

    Each floor area of villa

    Ground floor = 338 m2

    First floor = 261 m2

    Each floor consist of several bedrooms, sitting rooms,family hall

    Kitchen in ground floor

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    What is structural design?

    It is finding concrete dimensions and reinforcing steel areas of eachstructural element with insurance of safety and serviceability of themember.

    Before designing :

    Type of the structural element (i.e., beam, column etc)

    The loads carried by the member

    The architectural limitations on the member dimensions

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    Figure 2:

    Architectural plan for first floor.

    Figure 1:

    Architectural plan for ground floor.

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    Figure 3:Typical structural elements

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    it is one way

    blocks and solid part for R1:

    5.3m

    5.2m2

    short

    long

    L

    L

    0.3m

    0.43m

    nb=22

    nr=7

    Width of Rib 0.2m

    Width of Block 0.38m

    No. of Ribs nr 7

    No. of Blocks along Ls nb 22

    Width of Solid part S1 0.43m

    Width of Solid part along Ls (S2) 0.3m

    L 5.3m

    Ls 5.2m

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    m

    kN

    8.1040.58)1.7(21.4(4.28)1.7(L.L)1.4(D.L)w u

    Load Calculation160 160 160420 420

    380200380200

    Block

    Rib

    30060

    Dimensions in mm

    cover)(floorblock)of(weightrib)of(weightslab)topof(weightD.L

    m

    kN4.380.58)(20.2)(525)10.3

    2

    0.20.16(25)10.58(0.06D.L

    Figure 4: Drawing for ribbed slab (R1)

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    Figure 5: Binding moment diagram for R1

    Bending Moment for Simply Supported Rib R1

    Length (m)

    Bending moment

    (kN.mm)

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    Figure 6: Required steel area for R1

    Area of steel is 252mm2 (2#13)

    Steel Area R1

    Length (m)

    Steel Area

    (mm2

    )

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    Shear design for R1

    Length (m)

    Shear Force

    (kN.mm)Figure 7: Shear diagram for R1

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    From PROKON software (Vu = 21.1 kn)

    stirrupsneed2

    VV

    20.24KN,2

    0.85x47.6

    2

    V

    c

    u

    c

    22.78kN0.85

    0.85(47.6)21.1

    VVV cus

    mmV

    dfAS

    s

    yv450434

    22780

    3004205.78

    Swcs VkNdbfV 4.190300180283

    2

    3

    2max,

    kN6.74300180286

    1dbf

    6

    1V wcc

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    From PROKON software (Vu = 21.1 kN)

    #10@150mmchoose

    150mmS

    994mm180

    3x2x71x420

    b

    f3A

    150mm0.5(300)0.5d

    600mm

    ofsmallestSmax

    w

    yv

    max

    95.25kN30018028

    3

    1dbf

    3

    1V

    wcs

    22.78kNVs

    mmS 450

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    2#13

    2#10

    #10@150mm

    Check Deflection for R1 Simply supported beam

    Minimum thickness of R1 = L/16 = 5.2/16=0.325 m

    The actual thickness of R1= 0.36 m > 0.325

    It is acceptable

    Steel Arrangement

    Figure 6:

    Final drawing for ribbed slab (R1)

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    77.112kN/m8.261.745.051.41.7W1.4WW

    8.26kN/mW

    45.05kN/m10.53328.55

    WWO.Wreaction)(fromWW

    kN/m.10.53.53h3kN/mW

    3kN/m250.3(0.2x2)W

    kN/m.30.20.625bh O.W

    8.26kN/m0.58

    2.722.07

    0.58

    Rreaction)rib(fromW

    28.55kN/m0.58

    7.159.41

    0.58

    Rreaction)rib(fromW

    LDu

    L.L

    D(wall)partsolidbeamDD.Total

    2

    D.L(Wall)

    partSoild

    beam

    L.L

    L.L

    D.LD.L

    Beam : DB5

    20cm

    350cm

    Solidpart Solidpart

    20cm

    20cm

    20cm

    Beam 30cm

    30cm

    Wall

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    Steel arrangement

    Figure 7: Drawing of DB5

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    Figure 8: The stair design.

    Slope of the stairs

    1

    28.98380

    210tan

    Length of the stair

    Thickness to control deflection

    4.342m=1.23.8=L 22

    mmmmL

    h 300272

    20

    11004342

    20

    min

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    Load calculation for the stair

    2.8kN/m1.42w

    /1.165.108.28.2w

    /8.24.12w

    /8.22508.04.1w

    /5.10253.04.1o.w

    Liveload

    LD.

    coverfloor

    step

    slab

    total

    mkN

    mkN

    mkNhb

    mkNhb

    stair

    beam

    mkNLLw

    mkNLDw

    /8.2.

    /4.18cos

    1.16.

    2

    1

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    Length (m)

    Bending moment

    (kN.mm)

    Length (m)

    Area of steel (mm2)

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    From Prokon As=1270mm2 should be between As, min and As,max

    Asmin = 0.0033*1400*230=1062.6 mm2

    As,max = 0.02125*1400*230=6842.5 mm2 , Asmin < As< Asmax so we will use 7 bars diameter 16

    0.02125420600

    600

    420

    280.850.850.75

    f600

    600

    f

    `f`0.85(0.75)

    0.0033

    0.00315

    4204

    28

    0.0033420

    1.4

    4f

    f

    f

    1.4

    ofgreater

    yy

    c

    max

    y

    c

    y

    min

    1

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    Length (m)

    V (kN)

    Length (m)

    As (mm2/mm)

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    Shear design

    stirrupsforneednosokNVV

    kNdbf

    V

    KNV

    c

    u

    w

    c

    c

    u

    ,7.1202

    4.2411023014006

    2885.0

    6

    '

    82.70

    3

    stirrupsforneednosokNV

    V

    kNdbf

    V

    kNV

    cu

    w

    c

    c

    u

    ,4.157

    2

    8.3141030014006

    2885.0

    6

    '

    86

    3

    mmhS

    Sthanlessbeshouldmmspacing

    90030033

    2007

    1400

    max

    max

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    Figure 9

    The drawing for the stair.

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    Column (C1)

    212

    d

    gc

    LD

    Dd

    4933

    g

    u

    cu

    3

    N.mm8.33x10

    1

    /2.5IEEI

    0.88P

    P

    bucklingCheck

    19.58kNx4.350.3x0.6x25WeightOwn

    mm1.35x1012

    600x300

    12

    bhI

    968kNP

    0.09m0.3x0.30.3hr

    29000MPaE4.35m,l,kN/m25

    600mmx300mmissectioncrosscolumnAssume

    frameunbraced1.5,KAssume

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    Column (C1)

    1.51K:figure(9)Using

    2.78EI/l

    EI/l

    1.08EI/l

    EI/l

    beamn

    columnu

    B

    beamn

    columnu

    A

    72.02kN.mhPh

    e

    M

    0.080.030.3

    0.015

    h

    e

    3.1P/0.75P1

    1

    N1019.06)(Kl

    EIP

    usu

    cu

    s

    5

    2

    u

    2

    c

    Figure 10

    Effective length factor K

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    Column (C1)

    300mmspacingtieThen

    300mm

    456mm

    300mm

    305.6mm

    ofsmallesttiesofSpacing

    #10issizetieThen

    19)#7(choose

    1800mm6003000.01AA

    0.01use

    0.78Ksi895.38MPa/6.

    0.60.3

    968

    A

    P

    0.2Ksi891.33MPa/6.30.3x0.6x0.

    72.02

    hA

    M

    2

    gs

    min

    g

    u

    g

    u

    Figure 11

    Interaction Diagram

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    Figure 12:

    The drawing for the column C1.

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    Tie-beam (TB1)

    The longest tie beam is TB1 which has a length of 7m

    which was designed as the critical case. Then, comparedwith the minimum steel area and take the biggest area of

    steel:-

    In practice, As,min should be greater than the area of steel in

    a column that can enough to resist at least 10% of theheavily loaded column load (maximum load is 968 kn)

    In practice As,min > 0.5 % Aconcrete of tie beam x-sec

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    Length (m)

    M (kN.mm)

    Length (m)

    V (kN)

    Figure 13: Moment diagram and shear diagram for TB1.

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    For TB1 , As=573 mm2 which is (3 # 16) and compare it with:

    10% of the column load (maximum load is 968 kN)

    1- As,min =(10% Pu) / (0.9 Fy) =0.1 968 1000 / 0.9 420 = 256 mm2 (2 # 13)

    All the tie beams have a cross-section 20cm x 60cm

    2- As,min = 0.5 % Aconcrete = 0.005 200 600 = 600mm2 (3 # 16)So, the biggest area is 3 # 16.

    For shear (stirrups):

    maxs,s

    wcmaxs,

    svs

    sv

    VV395.1kN

    560200283

    2dbf

    3

    2V

    1Check

    kN38.57280.164420560

    AfydVFind,

    957mm0.164

    78.52SSo,

    S

    Asn

    fyd

    Vs0.164A

    #10@280mmchoose

    SS

    280mmS

    989.1mmb

    f3A

    280mm0.5d

    600mm

    ofsmallestS

    197.6kN560200283

    1dbf

    3

    1V

    2Check

    max

    max

    w

    yv

    max

    wcs

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    Footing (F1)

    94.8kN20.22648.6TB1)(fromPP

    291kN40251B11)(fromPP

    253.5kN35.5218HB10)(fromPP

    LD

    LD

    LD

    2.2m2.2mChoose4.69m150

    63.93639.3A

    63.93kN)P(P0.1PAssume

    AcapacitybearingPPP639.3kN394.8291253.5PP

    150kN/m1.5Kg/cmcapacityBearing

    F1

    2

    footing

    LDextra

    footingextraLD

    LD

    22

    0.95m

    0.3m

    0.6m

    2.2m

    2.2m

    0.8m

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    180.76kN.m)2

    0.95(0.952.2227.44)

    2

    z(LzqM

    122.6kN.m)2

    0.8

    (0.82.2227.44)2

    z

    (BzqM

    227.44kN/m2.22.2

    1100.8

    A

    1.7L1.4Dq

    150kN/m136.05kN/m2.22.219.206639.3

    APPP

    63.93kN19.206kN15)0.4)(240.6(1.50.315)0.4(242.22.2

    )h)(lb(1.5)LBh(P

    :Check

    22ulongu,

    11ushortu,

    2

    chosen

    u

    22

    chosen

    extraLD

    soilconcretesoilconcreteextra

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    12#16)(choose2323.2mm32022000.0033bdA

    choose

    0.02125420600

    600

    420

    280.850.850.75

    f600

    600

    f

    `f`0.85(0.75)

    0.0033

    0.003154204

    28

    0.0033420

    1.4

    4f

    f

    f

    1.4

    ofgreater

    0.00216

    280.85

    0.89211

    420

    280.85

    `0.85f`

    2R11

    f

    `0.85f`

    0.89MPa891.52kN/m0.08)(0.42.20.9

    180.76

    bd

    MR

    entreinforcemLong

    2s

    minmin

    yy

    c

    max

    y

    c

    y

    min

    c

    n

    y

    c

    2

    22u

    long

    1

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    11#16)(choose2178mm30022000.0033A

    )choose0.00167(280.85

    0.692

    11420

    280.85

    0.69MPa688kN/m0.1)(0.42.20.9

    122.6

    bd

    MR

    entreinforcemShort

    2s

    minmin

    2

    22u

    short

    0.95m

    0.3m0.6m

    2.2m

    2.2m

    0.8m

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    OkVV

    1847.09kN

    4002320)(300320)(60012

    2840.852hd)(bd)(l

    12

    f4V

    750.552kN0.32)0.32)(0.3(0.62.22.2227.44d)d)(b(lBLqV

    shearwayTwo

    OkVV

    527.74kN32022006

    280.85Bd

    6

    f0.85V

    265.2kN0.32)(0.952.2227.44d)B(zqV

    entreinforcemLong

    OkVV

    527.74kN32022006

    280.85Bd

    6

    f0.85V

    190.14kN0.32)(0.82.2227.44d)B(zqV

    entreinforcemshortshearwayOne

    cu

    c

    c

    uu

    cu

    c

    c

    2uu

    cu

    c

    c

    1uu

    0.95m

    0.3m0.6m

    2.2m

    2.2m

    0.8m

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    C1(7#19)columnasentreinforcemsameUse

    Safe(Design)PP

    2728.8kN(Design)P15.16MPa2.2KsiAg

    Pu

    figurethisUsing

    OK0.010.011600300

    1985

    A

    A

    180000mm600300A1100.8kN,P

    ColumnNeck

    uu

    u

    g

    s

    4

    gu

    Figure 14: Interaction diagram

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    Figure 15:

    The drawing of the footing F1.

    12#162.2m

    0.4m

    0.85m

    12#16

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    The environmental aspects and impact of the project should be

    controlled by the involved parties to control the bad effects in both

    sides either by the environment on the building or on the other way.

    - here in UAE, the building usually consumes some of the countrys energy

    and water resources and this could be reduced by using green house

    technology where solar and wind energies can be used extensively.

    - Although the building material considered in this project (i.e., reinforced concrete) isrelatively cheap compared to the steel material, it is, unfortunately, not

    environmental friendly

    Impact

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    Each building in this world represents a unique and creativeidea that is made real by the cooperation of the involved design andconstruction parties.

    It is an event that starts by developing the owner ideas on the hands ofengineers to achieve safety, serviceability and creativity of project.

    For example, as a social aspects, here in UAE, traditions and thecultural background of the people is totally different from thewestern countries. Thats should be achieved by the architecturaldesign to represent the cultural identity in the scope of the projectdesign beside the modernity.

    Impact

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    Conclusion and recommendation

    The experience gained in the design process is invaluableand represents a major stone in building an efficientstructural designer engineer.

    Finally, it is recommended that the design work achievedin this project is originally performed by two groupsusing two different structural systems.

    This would provide information enough to compare thecost of each system and get experience with cheapersolutions.