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STOICHIOMETRY REVIEW ANSWERS

STOICHIOMETRY REVIEW ANSWERS. 1. The calculation of quantities in chemical equations is called Stoichiometry 2. The first step in most stoichiometry problems

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Page 1: STOICHIOMETRY REVIEW ANSWERS. 1. The calculation of quantities in chemical equations is called Stoichiometry 2. The first step in most stoichiometry problems

STOICHIOMETRY REVIEW ANSWERS

Page 2: STOICHIOMETRY REVIEW ANSWERS. 1. The calculation of quantities in chemical equations is called Stoichiometry 2. The first step in most stoichiometry problems

• 1. The calculation of quantities in chemical equations is called

• Stoichiometry

• 2. The first step in most stoichiometry problems is to convert given quantities to

• Moles

• 3. When two substances react to form products, the reactant which is used up is called the

• Limiting Reagent

Page 3: STOICHIOMETRY REVIEW ANSWERS. 1. The calculation of quantities in chemical equations is called Stoichiometry 2. The first step in most stoichiometry problems

• 4. The amount of product that forms when a reaction is carried out in the laboratory is the

• Actual Yield

• 5. The maximum amount of products that could be formed from given amounts of reactants is the

• Theoretical Yield

• 6. When an equation is used to calculate the amount of product that will form during a reaction, then the value obtained is called the

• Theoretical Yield

Page 4: STOICHIOMETRY REVIEW ANSWERS. 1. The calculation of quantities in chemical equations is called Stoichiometry 2. The first step in most stoichiometry problems

• 7.

2Al(s) + 3Pb(NO3)2(aq) 2Al(NO3)3(aq) + 3Pb(s) • A.) 2 moles Al + 3 molecules Pb(NO3)2 2 molecules Al(NO3)3 + 3 moles Pb

• F

• B.) 2 grams Al + 3 grams Pb(NO3)2 2 grams Al(NO3)3 + 3 grams Pb

• F

• C.) 2 moles Al + 3 moles Pb(NO3)2 2 moles Al(NO3)3 + 3 moles Pb

• T

• 8. In every chemical reaction ___________ stay the same.• The Mass

• 9. In the reaction 2CO + O2 2CO2, what is the ratio of moles of oxygen used to moles of CO2 produced?

• 1:2

Page 5: STOICHIOMETRY REVIEW ANSWERS. 1. The calculation of quantities in chemical equations is called Stoichiometry 2. The first step in most stoichiometry problems

• 10. For C5H12 + 8O2 5CO2 + 6H2O

• ______ moles of reactants chemically change into ______ moles of product.

• 9 moles of reactant to 11 moles of product

Page 6: STOICHIOMETRY REVIEW ANSWERS. 1. The calculation of quantities in chemical equations is called Stoichiometry 2. The first step in most stoichiometry problems

11. How many moles of oxygen are required to react completely with

14.8 mol Al when given 4Al + 3O2 2Al2O3?

14.8 mol Al x -----------------4 mol Al

3 mol O2

= 11.1 mol O2

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Page 7: STOICHIOMETRY REVIEW ANSWERS. 1. The calculation of quantities in chemical equations is called Stoichiometry 2. The first step in most stoichiometry problems

12. Given the balanced equation 16HCl + 2KMnO4 2KCl + 2MnCl2 + 5Cl2 + 8H2O

if 2.0 mol of KMnO4 reacts, how many moles of H2O are produced?

8.0 mol H2O

Page 8: STOICHIOMETRY REVIEW ANSWERS. 1. The calculation of quantities in chemical equations is called Stoichiometry 2. The first step in most stoichiometry problems

13. Based on…16HCl + 2KMnO4 2KCl + 2MnCl2 + 5Cl2 + 8H2O

…how many grams of KCl are produced when 3.0 mol of KmnO4 reacts?

3.0 mol KMnO4 x ----------------2 mol KMnO4

2 mol KClX ---------------------

1 mol KCl

74.5 g KCl= 220 g KCl

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---------

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Page 9: STOICHIOMETRY REVIEW ANSWERS. 1. The calculation of quantities in chemical equations is called Stoichiometry 2. The first step in most stoichiometry problems

14. If CuO + H2 Cu + H2O, how many moles of H2O are produced

when 240 grams of CuO react?

240 g CuO x ----------------80 g CuO

1 mol CuOX ---------------------

1 mol CuO

1 mol H2O= 3.0 mol H2O---------

---------

------------------

Page 10: STOICHIOMETRY REVIEW ANSWERS. 1. The calculation of quantities in chemical equations is called Stoichiometry 2. The first step in most stoichiometry problems

15. In the reaction Zn + H2SO4 ZnSO4 + H2

how many grams of H2SO4 are required to produce

2.3 gram of H2?

2.3 g H2 x -----------------

2 g H2

1 mol H2

x ------------------- x -------------------

1 mol H2

1 mol H2SO4

1 mol H2SO4

98 g H2SO4

113 g H2SO4

=-----------------

----------------

-----------

-----------

-------

-------

Page 11: STOICHIOMETRY REVIEW ANSWERS. 1. The calculation of quantities in chemical equations is called Stoichiometry 2. The first step in most stoichiometry problems

16. LiOH + HBr LiBr + H2OIf you start with 15.0 grams of

lithium hydroxide, how many grams of lithium bromide will be produced?

54.4 g LiBr

Page 12: STOICHIOMETRY REVIEW ANSWERS. 1. The calculation of quantities in chemical equations is called Stoichiometry 2. The first step in most stoichiometry problems

17. How many molecules of oxygen are required to react completely with 2.96 X 1023 molecules Al when given 4Al + 3O2 2Al2O3?

2.96 x 1023 molecules Al x -----------------4 molecules Al

3 molecules O2

=

2.22 x 1023 molecules O2

----------------------

----------------------

Page 13: STOICHIOMETRY REVIEW ANSWERS. 1. The calculation of quantities in chemical equations is called Stoichiometry 2. The first step in most stoichiometry problems

18. How many molecules of oxygen are produced by the

decomposition of 6.54 g of potassium chlorate (KClO3)?

2KClO3 2KCl + 3O2

6.54 g KClO3 x --------------- x --------------- x ------------------ =122.5 g KClO3

1 mol KClO3

2 mol KClO3

3 mol O2

1 mol O2

6.02 x 1023 molecules O2

---------

---------

------------

------------

------------

------------

4.82 x 1022 molecules O2

Page 14: STOICHIOMETRY REVIEW ANSWERS. 1. The calculation of quantities in chemical equations is called Stoichiometry 2. The first step in most stoichiometry problems

• 19. LiOH + KCl LiCl + KOH

• A) I began this reaction with 20 grams of lithium hydroxide.

What is my theoretical yield of lithium chloride?

Convert 20 grams of LiOH Grams of LiCl

35 g LiCl• B) I actually produced 6 grams of lithium

chloride. What is my percent yield?

Actual_________

Theoretical X 100 = 17%

Page 15: STOICHIOMETRY REVIEW ANSWERS. 1. The calculation of quantities in chemical equations is called Stoichiometry 2. The first step in most stoichiometry problems

• 20. C3H8 + 5 O2 3 CO2 + 4 H2O

• A) If I start with 5 grams of C3H8, what is my theoretical yield of water?

Convert 5 grams C3H8 Grams of H2O

8.2 g H2O• B) I made 6.1 g of water. What was my percent

yield?

Actual_________

Theoretical X 100 = 74%

Page 16: STOICHIOMETRY REVIEW ANSWERS. 1. The calculation of quantities in chemical equations is called Stoichiometry 2. The first step in most stoichiometry problems

21. Be + 2 HCl BeCl2 + H2

My theoretical yield of beryllium chloride was 10.7 grams. If my

actual yield was 4.5 grams, what was my percent yield?

Actual___Theoretical

= 42%X 100

Page 17: STOICHIOMETRY REVIEW ANSWERS. 1. The calculation of quantities in chemical equations is called Stoichiometry 2. The first step in most stoichiometry problems

22. CaSO4 + NaI CaI2 + Na2SO4

If 34.7 g of calcium sulfate and 58.3 g of sodium iodide are placed in a reaction vessel, what will be the

limiting reagent?

NaINote: Refer to Limiting Reagent Notes to see how to work it out.