Stoichiometry

Kathleen

ThorrKF+O

How many grams of Potassium Oxide are

needed to produce 4.18g of Oxygen??

Write a complete and balanced chemical equation

K2O +2F -----> 2K F+ O2

2K2O +4F ----> 4KF + O2

Draw a column after each chemical

4F + 2K2O O2 + 4KF

Write the amount given in the correct column

4F + 2K2O O2

4.18g

+ 4KF

Convert the amount given into moles

4F + 2K2O O2

4.18g 1/31.998

4.18g x 1mole 1 31.998.131 moles

+ 4KF

Do the math and label as moles

4F +.131x 4/1.524mol

2K2O .131 x 2/1 =

.262mol

O2

4.18g 1/31.998

4.18g x 1mole 1 31.998.131 moles

+ 4KF.131 x 4/1=

.524

Convert all moles into grams

4F +.131x 4/1.524 x 19.00=9.96g

2K2O .131 x 2/1 =

.262 x 94.199=-

24.7g

O2

4.18g 1/31.998

4.18g x 1mole 1 31.998.131 moles

+ 4KF.131 x 4/1=

.524 x 58.1=

30.4

Verify the Law of Conservation

4F +.131x 4/1.524 x 19.00=9.96g

9.96 + 24.7 =

34.7g

2K2O .131 x 2/1 =

.262 x 94.199=-

24.7g

O2

4.18g 1/31.998

4.18g x 1mole 1 31.998.131 moles

4.18 + 30.4 =34.6g

+ 4KF.131 x 4/1=

.524 x 58.1=

30.4

Answer

4F +.131x 4/1.524 x 19.00=9.96g

9.96 + 24.7 =

34.7g

2K2O .131 x 2/1 =

.262 x 94.199=-

24.7g

O2

4.18g 1/31.998

4.18g x 1mole 1 31.998.131 moles

4.18 + 30.4 =34.6g

+ 4KF.131 x 4/1=

.524 x 58.1=

30.4