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DESIGN
OF
WEIR AND BARRAGES
HYDROLOGY
3
Hydrology Cycle
HYDROLOGY
4
Hydrology
Hydraulic Structure
5
Thiessen Polygon Method
PRECIPITATION AND ITS MEASUREMENT
Procedure
Join the adjacent rain gauge stations A,B,C,D,E etc. of the area
dividing the entire area in a series of triangles as sown in figure.
Draw the perpendicular bisector of each of these lines, as shown
by firm lines in figure.
The area enclosed by these perpendicular bisectors is served by
respective rain gauges. Thus these perpendicular bisectors form
a series of polygons around the Rain-gauge stations and
containing one and only one Rain-gauge station in each polygon.
The entire area within any polygon is nearer to the Rain-gauge
station contained there in than any other.
Find the area of each polygon and multiply it with the rainfall of
the respective Rain-gauge.
Continued….
6
Thiessen Polygon Method
PRECIPITATION AND ITS MEASUREMENT
The Calculations
If P1, P2, P3, P4, P5, and P6 are the rainfalls in station and
A1,A2,A3,A4,A5 and A6 are the areas respectively then average
rainfall of the catchment is;
Pav = (P1A1+P2A2+P3A3+P4A4+P5A5+P6A6+…+PnAn)
A1+A2+A3+A4+A5+A6 +…+An
P = (∑n
i=lPiA1 )/ A
7
Thiessen Polygon Method
PRECIPITATION MEASUREMENT
8
The Calculation
Let the isohyets represent the rainfall P1, P2,…… Pn and areas
between the successive isohyets A1, A2,…… Pn-1 Average
precipitation is then calculated as;
Pav = A1[P1+P2/2]+A2[P2+P3/2]+….+An-1[Pn-1+Pn/2]
A1+A2+A3+A4+….+An-1
P = A1[P1+P2/2]+A2[P2+P3/2]+….+An-1[Pn-1+Pn/2]
A Continued….
PRECIPITATION AND ITS MEASUREMENT
Procedure
From the rain fall data prepare the isohyetal map as shown infigure.
Measure the areas between two successive isohyets with the helpof a planmeter.
Multiply each area by the mean rainfall between the isohyets.
Calculate the average rainfall by the following equation
9
Isohyetal Method
PRECIPITATION MEASUREMENT
10
STREAM FLOW MEASUREMENT
Mean Section Method
In the mean section method, averages of the mean velocities
in the verticals and of the depths at the boundaries of a
section sub-division are taken and multiplied by the width of
the sub-division, or segment.
Q = ∑qi = ∑V.a = ∑ni=1 (Vi-1 + Vi)/2 (di-1 + di)/2
(bi – bi-1)
11
STREAM FLOW MEASUREMENT
Mid Section Method
In the mid section method, the mean velocity and depth
measurement at a sun-division point are multiplied by the
segment width measured between the mid points of
neighboring segments.
Q = ∑qi = ∑V.a = ∑ni=1 Vi.di (bi + 1– bi-1)/2
Empirical Formulae
S. N.
Author Formula in inch units
Formula in Centimeter Unit
1. Ingles formula for Ghat Area R=0.85 P-12 R=0.85 P-30.5
2. Ingles formula for non-Ghat Area
R= (P-7) x P100
R= (P-17.8) x P254
3. Lacey’s formula R = P(1+120F)/PS
R = P(1+304.8F)/PS
4. Khosla’s formula R= P – (T-32)9.5
R= P – (T-32)3.74
5. Parker’s formula for British Isles R = 0.94 P – 14 R = 0.94 P – 35.6
6. Parker’s formula for Germany R = 0.94 P – 16 R = 0.94 P – 40.6
RUN-OFF MEASUREMENT
HYDROGRAPH ANALYSIS
Estimation of Maximum Discharge
i) Physical Indication of past floods
ii) Flood Discharge Formula
iii) Rational Formula
iv) Unit Hydrograph
Flood Discharge Formula
Q = CAn
Q = Flood Discharge
A = Catchments Area
C = Flood Coefficient
n = Flood index
Both ‘C’ and ‘n’ depends upon; (i) catchments characteristics,
(ii) intensity and duration of rainfall and its distribution pattern of
storm over the basin.
14
Rational Formula
Qp = CIA (FPS)
Qp = 1 CIA (MKS)
3.6
Qp = Peak Discharge (m3/sec),
‘I’ = Intensity of Rainfall (mm/hr) for duration more than time of
concentration
‘A’ = Area of drainage basin (km2)
‘C’ = constant (0.3 – 0.8)
RUN-OFF MEASUREMENT
15
Hydrograph Segment
HYDROGRAPH ANALYSIS
Unit Hydrograph
Unit Hydrograph (UH) is “defined as the Hydrograph of surface
runoff of a catchment area resulting from unit depth
(usually 1 cm) of rainfall excess or net rainfall occurring uniformly
over the basin and at uniform rate for a specified duration”.
Unit Hydrograph is a linear model of the catchment which is used
to find out the volume of DSR due to 1 cm of direct surface runoff
or 1 cm of rainfall excess. This is always constant for the
catchment since area of the catchment is constant.
If rainfall comes to the catchment producing 2 cm of rainfall
excess, “the ordinates of the DSR will be twice as great of the
Unit Hydrograph (UH) ordinates and volume of DSR will be two
time the volume of DSR of unit hydrograph”.
HYDROGRAPH ANALYSIS
Derivation of UH from a simple Flood Hydrograph –
(Isolated Storm)
Step 1 From the given flood Hydrograph, “separate the base flow” by
any one of the methods. Most commonly used method to
draw a straight line without much error for simplicity (Figure
enclosed)
Step 2 Determine the volume of DSR Hydrograph by the formula;
“Volume of DSR = ∑QΔt”
A
Step 3 Divide this volume by “known Area of Catchment” to get DSR
volume (depth in cm) i.e., “net rainfall or rainfall excess”.
Step 4 Divide the ordinates of DSR by the depth of DSR Hydrograph
to obtain ordinates of UH.
Step 5 Plot the ordinates of UH of the catchment as per enclosed
figure.
HYDROGRAPH ANALYSIS
Unit Hydrograph Derivation
HYDROGRAPH ANALYSIS
S-Hydrograph (S-Curve)
S-Hydrograph or S-Curve is a Hydrograph which is produced by a
“continuous effective rainfall at a constant rate for indefinite
period”.
It is a “continuous rising curve”, in the form of letter ‘S’, till
equilibrium is reached. At the time of equilibrium, “it will
represent a constant rate of continuous effective rainfall, say Ro
cm per hour”.
At the time of equilibrium, “the S-Curve will represent a runoff
discharge as under”;
Qo = (A x 100 x 100) Ro
100 x 3600
= A Ro cumec
36
(Where A is the catchment area in hectares)
HYDROGRAPH ANALYSIS
Contd…
If the catchment area ‘A’ is in “square kilometers”, the discharge
represented by S-Curve, at the time of equilibrium is given by;
Qo = (A x 1000 x 1000) Ro
100 x 3600
=(AR0) x 100 (cms)
36
= 2.778 A Ro (cms)
(‘A’ = Area of catchment in km2 and Ro = Constant rate of
continues effective Rainfall.)
The S-Hydrograph or S-Curve is constructed by “adding together
number of Unit Hydrographs of unit time duration (T0) spaced at a
unit time duration (T0) (i.e., duration of effective rainfall).
“This is illustrated in the enclosed example were in S-Curve has
been drawn for 6 hours Unit Hydrograph. Area of basin is 311
km2”.
HYDROGRAPH ANALYSIS
HYDROGRAPH ANALYSIS
Computation of S-Hydrograph from Successive Unit Hydrograph
Contd…
HYDROGRAPH ANALYSIS
This discharge of 144 cumecs will be achieved in the above table at 36
hours (which is equal to base period – T0 hours.)
HYDROGRAPH ANALYSIS
Derivation of S-Hydrograph from Series of Unit Hydrograph