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Electromagnetic radiation spectrum

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Page 1: ssr sir nmr class

Electromagnetic radiation spectrum

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NUCLEAR MAGNETIC RESONANCE SPECTROSCOPY

PRINCIPLE AND APPLICATION IN STRUCTURE ELUCIDATION

Professor S. SANKARARAMAN

Department of Chemistry

Indian Institute of Technology Madras

Chennai – 600 036

[email protected]

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HISTORICAL PERSPECTIVE

Discovery of NMR phenomenon in 1945

Purcell, Torrey and Pound – Harvard University USA

Bloch, Hansen and Packard – Stanford University USA

When ethanol was placed between pole pieces of an

electromagnet and irradiated with electromagnetic

radiation it absorbed radiation in the radio frequency

region. When the magnetic field was turned off no

absorption was observed.

Purcell and Bloch – Nobel prize in Physics – 1952

For the discovery of NMR.

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The first published high resolution NMR spectrum of ethanol at 30 MHz

F. Bloch, W. W. Hansen, M. E. Packard, Phys. Rev. 1946, 69, 127

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NMR – magnetic properties of atomic nuclei

Atomic nucleus has mass and it spins on its own axis

Due to the spin, it possesses angular momentum (P)

Due to the charge and the spin it possesses magnetic momentum (m)

Only certain nuclei have non-zero magnetic moment. In others the

“Net magnetic momentum” can be zero

Only nuclei with non-zero magnetic moment are “magnetically active”

Both (P) and (m) are vector quantities and also quantized

The ratio of magnetic momentum to angular momentum is called

“Gyromagnetic ratio”. It is very characteristic of a given nuclei.

Gyromagnetic ration = [g] = (m)/(P)

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Basic theory of NMR Spectroscopy

Nucleus should be magnetically active –

non-zero magnetic momentum

According to quantum mechanics angular momentum

can have only certain fixed values (eigen states)

P = (m)(h/2p) where m is the magnetic quantum number of the

nucleus

In the presence of an external magnetic field(m) can have

(2I+1) values, namely (+I), (I-1), (I-2)……..(-I) where (I) is the spin quantum number of the nucleus

For I = ½, two states are possible (+½) and (-½)

For I = 1, three states are possible (+1, 0, -1)

For I = 3/2 , four states are possible (3/2, +1/2, -1/2, -3/2)

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Nuclear Spin (I):

A simple way to find out nuclear spin

Atomic mass Atomic number Spin

Even Even zero

Even Odd multiple of 1

Odd Even or Odd multiple of ½

Examples:

I = 0 12C6, 16O8

I = integer 14N7 (1), 10B5 (3), 2H1 (1)

I = half integer 1H1 (1/2), 13C6 (1/2), 15N7 (1/2)

17O8 (5/2) 33S16 (3/2)

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Properties of some common NMR nuclei:

Nucleus Spin g Natural

(rad T-1 s-1) abundance (%)

1H ½ 26.7 99.9

2H1 1 4.107 0.015

13C6 ½ 6.72 1.10

19F9 ½ 25.18 100

31P15 ½ 10.84 100

29Si14 ½ -5.32 4.67

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NMR of spin ½ nuclei, namely proton and carbon-13

In the absence of external magnetic field the magnetic moment

vectors will be randomly oriented

In the presence of applied external magnetic field (Bo) two

orientations are possible, namely (+1/2) and (-1/2)

The two orientations, one aligning with external field (-1/2)

and another opposing the external field (+1/2),

differ in energy.

The energy difference depends on the strength of applied

magnetic field

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E = hn = (h/2p)Bog n = (Bog)/2p

no field

increasing filed strength Bo

E = hn

Nuclear spins in an external magnetic field for I = 1/2

- 1/2

+ 1/2 b

a Bo

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Distribution of nuclear spins:

Na / Nb = exp(-DE/kT)

Bo (T) n (MHz) DE (J) Na / Nb T oC

2.35 100 6.7 x 10-26 17 ppm 17

4.70 200 22.5 x 10-26 57 ppm 17

7.0 300 33.5 x 10-26 85 ppm 17

2.35 100 6.7 x 10-26 28

13

-100

+100

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Higher the magnetic field strength –

higher the sensitivity and resolution

Lower the temperature –

higher the sensitivity

A 400 MHz NMR instrument is more sensitive

as well as more resolving than a 60 MHz NMR

instrument

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The energy gap between the spin states corresponds

to radio frequency region

Application of radio frequency causes the absorption

of the same due to excitation of nuclear spins from

lower energy level to upper energy level when the two

energies match (resonance condition)

The spins in the excited state return back to ground

State by (a) spin lattice relaxation and (b) spin-spin

relaxation

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Concept of chemical shift:

n = (Bo g)/ 2p

Nucleus is surrounded by electrons

Electrons have charge as well as spin

The magnetic field due to the spinning electron

shields the nucleus from the external magnetic

field. This is diamagnetic shielding.

The nucleus does not feel Bo, but Beff = Bo(1-s)

Beff is the effective magnetic field felt by nucleus

s is the shielding constant

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s - the shielding constant

Characteristic of the chemical environment

of the proton

Depends on the electron density around the protons

n = (Beff g) / 2p = [Bo(1-s) g / 2p]

Since s is different for chemically different protons

the resonance frequency of chemically different

protons will be different – chemical shift

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Definition of chemical shift – d:

It is inconvenient to refer to proton frequency as

398.432 MHz

Instead of actual frequencies of resonances, a reference

is taken and the frequencies are calibrated with

respect to the reference

d (in Hz) = n sample – n reference (Spectrometer dependent)

d = (n sample – n reference) x 106 (in ppm)

spectrometer frequency

Chemical shift expressed in d is a dimensionless quantity and

also does not depend on the spectrometer frequency

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Reference for 1H-NMR spectroscopy:

Tetramethylsilane (TMS) is used as a reference

The chemical shift of TMS is lower than most protons in

organic molecules, so it is taken as zero

All the protons in TMS are equivalent and hence only one

signal for all the 12 protons – high signal intensity

TMS is a liquid and miscible with most solvents

It is also volatile and hence easy to remove

It is inert and does not react with the samples

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0 10 ppm

60 MHz spectrometer

0 10 ppm

400 MHz spectrometer 0 4000 Hz

0 600 Hz

d 2 ppm in a 60 MHz spectrometer is 120 Hz

d 2 ppm in a 400 MHz spectrometer is 800 Hz

Chemical shifts and scan widths

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Factors affecting chemical shift:

1. Electronegativity, inductive and resonance effects

TMS = 0.0 CH4 = 0.23 (all in ppm)

MeI 2.2 MeOH 3.4

MeBr 2.6 MeF 4.3

MeCl 3.1 MeNO2 4.3

MeF 4.3

MeCl 3.1

CH2Cl2 5.3

CHCl3 7.2

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2. Anisotropic effects:

Spherical electron density – induced magnetic field

will be uniform in space – isotropic effect

For example s –electron – spherical

Non-spherical electron density – induced magnetic

field will be non-uniform in space – anisotropic

Example: p electron cloud of aromatic ring, C=C

and C=O type – most common feature of organic

molecules

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H

+

+

shielding

--deshielding

Bo

+

+

H

shielding

-deshielding

-

Bo

d 5.28

d 1.80

Diamagnetic anisotropy in ethylene and acetylene

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HH

Bo

HH

+

+

-deshielding

-

Bo

d 7.28

shielding

Diamagnetic anisotropy in aromatic ring

Ring current effect

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OH

+

+

shielding

--deshielding

Bo

d 9.5

Diamagnetic anisotropy in carbonyl group

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Examples of effect of anisotropy on chemical shift

H H Me Me

1.031.32 1.27 0.70

H H

1.44 2.82

HH

H

7.29

-0.51H8.14-8.67

-4.2

HH

H

HH

H

H 9.3

-3.0

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H

H

1.62

1.12

H

NO2

4.23

NO2

H

4.43

H

OH

3.37

OH

H

3.93

Anisotropic effect of sigma bond

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CH3 – CH2 - OH

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OSPh

OCH2Ph

PhCH2O

PhCH2O

PhCH2O

Solvent effect on chemical shift: (a) in CDCl3, (b) Benzene-d6

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Effect of neighboring protons – spin-spin coupling

a

b

d Absence of any interacting protons

No neighboring protons

No spin-spin coupling – only a single peak for each

chemically different proton

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Consider two protons Ha and Hb - neighbors

a a

a b

b a

b b

Ha Hb

no spin-spin interaction spin-spin interaction

only two transitionsone for Ha and onefor Hb

four transitions,two each for Ha andHb

Case 1 Case 2

da db

da db

Case 1

Case 2

Jab Jab

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http://www.cem.msu.edu/~reusch/VirtualText/Spectrpy/nmr/nmr1.htm

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http://www.cem.msu.edu/~reusch/VirtualText/Spectrpy/nmr/nmr1.htm

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J spin-spin coupling constant depends on

1. Distance between the coupling partners – intervening bonds

2. Dihedral angle between the coupling partners for vicinal protons

3. Coupling constant is largest when dihedral angle is 180o

and very small when dihedral angle is 90o

4. In freely rotating bonds (like in alkyl chains) average

J values are obtained

http://www.cem.msu.edu/~reusch/VirtualText/Spectrpy/nmr/nmr2.htm#pulse

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Spin – spin splitting patterns for I = ½ nucleus like 1H:

The no. of lines from coupling = (2nI+1) = (n+1) for I = ½

Where n is the number of equivalent protons that couple

C C HbHa Ha and Hb - each a doublet with Jab

C C HbHa

Hb

Ha - triplet and Hb - doublet with Jab

C C HbHa

HbHa

Ha and Hb - each triplet with Jab

CH3 - CH2 CH3 - triplet and CH2 - quartet

CH3-CH2-CH2 CH3 - triplet, CH2 - sextet, CH2 - triplet

CH3-CH-CH3 CH3 - doublet, CH-septet

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Line intensities of multiplets for spin ½ nucleus

Corresponds to the coefficients of binomial expansion

Can be obtained simply from Pascal’s triangle

1

1 1

1 2 1

1 3 3 1

1 4 6 4 1

1 5 10 10 5 1

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1H-NMR chemical shifts of various types of protons

http://www.cem.msu.edu/~reusch/VirtualText/Spectrpy/nmr/nmr1.htm

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Magnitude of some coupling constants J in Hz

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Chemically equivalent protons –

protons having same chemical environment

hence the same chemical shift (d)

Homo and enantiotopic hydrogens in organic

molecules

isochronous

Magnetically nonequivalent protons –

protons having different magnetic environment

different coupling constant with other protons

diastereotopic hydrogens in organic molecules

For two protons to show spin-spin coupling they have to be

magnetically non-equivalent. They may or may not be chemically

non-equivalent

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Parameters obtainable from a 1H-NMR spectrum:

1. Chemical shift values of various protons

2. Coupling constant values from multiplets

3. Relative ratio of signal intensities – area under the peaks

proportional to the number of protons responsible for

each signal

4. Relative mole ratios of components in a mixture

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CH3CH2Br

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CH3COOCH2C6H5

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HCOOCH2CH3

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A

C4H8O

B

C4H8O2 CH3COCH2CH3

CH3COOCH2CH3

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C5H7NO2 CH3CH2O CH2C

O

N

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CH3-CH2-CH(Br)-COOH

C4H7O2Br

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H3C CH3

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CH2CH3

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CH3

CH3

H3C

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H

CH3

CH3

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Ha and Hb are diastereotopic due to the adjacent chiral center

OH

H

O

Hb

Ha

CH3O

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H

H3C H

O

O

CH3

CH3

CH3

H H

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H

H3C H

H

O

H

H

H

CH3

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O

O CH2CH3O

OCH3CH2

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O

OCH2CH3

O

O

CH2CH3

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C10H12O3

O H

O

O

CH3

H3C

5H

1H

3H

3H

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CH2CH2OH

5H 2H

2H 1H

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C9H11Br

5H

2H 2H

2H

CH2CH2CH2Br

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C6H5NBr2

2H

1H 2H

NH2

BrBr

H

H

H

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Second order spectra:

When the chemical shift values are very close and

the difference in chemical shifts are comparable to J values

one finds second order effects in the NMR spectra

Typically when (Dd)/J is less than 10, second order effects

are seen in the spectra

Unusual intensity of multiplets

More than expected number of lines in multiplets

are characteristic features of a second order spectrum

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Examples of spin systems that show second order effects:

Hm

Ha Hx

R

mutually coupled amx spin system

da, dm, dx, Jam, Jax, Jmx

Ha

Hb

X

Y

R

Rmutually coupled ab spin system

da, db, Jab

X

R

Ha

Hb

Y Z

Ha'

Hb'Hb

Ha

X

Y

X

YHa Ha'

Hb Hb'

mutually coupled aa'bb' spin system

da, db, six different coupling constants

Note: Ha and Ha' are chemicallyequivalent but magnetically non-equivalent protons. similarlyHb and Hb' are.

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NH3C NH2

C6H8N2

3H 2H

1H 1H 1H

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Dimethyl cyclopropanedicarboxylate

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Variable Temperature NMR Spectroscopy

Study of dynamic properties of molecules

Conformational changes

Restricted rotation around C-C and C-X bonds

Aggregation phenomena

Fluxional properties of molecules

Temperature range – typically -150 oC to +150 oC

provided solubility and solvent mp/bp permit

Processes with activation barrier typically in the range

of 8-25 Kcal/mole can be studied

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Restricted rotation around C-N bond

In amides

H

Me

N

O

Me

H

Me

N

O

MeH

Me

N

O

Me

Activation barrier = 22 Kcal / mole

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Conformational changes

Interconversion of chair

form of cyclohexane

H

H

Cyclohexane-d11

Activation barrier = 10 Kcal / mole

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H

NHD2

D2

HNH

H

H

D2

D2

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HH

H

HH

H

H H

H

H

H

H

HH

H

H

H

H

[18]annulene

Fluxional behaviour of

large annulenes

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Bullvalene – most fluxional molecule

Synthesis: Schröder – 1963

C10H10 isomer

C3v symmetry

Degenerate Cope rearrangement [3,3]-shifts

Activation barrier = 11.8 Kcal/mole

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HH

HH H

HH

H

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Me MeAl

Me

Al AlMe

Me

Me

Me

Me

Me

2

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13C-NMR spectroscopy

Carbon-13 nucleus is spin active wih I = ½

Hence C-13 NMR spectroscopy is possible and very useful

in organic structure elucidation

Abundance of Carbon-13 is very low, only about 1.1%

The gyromagnetic ratio of Carbon-13 is also low, it is about

1/4th of proton gyromagentic ratio

Both these factors are responsible for the poor sensitivity of

Carbon-13 NMR spectroscopy, it is about 1/(6400)th of

proton

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FT-NMR technique

Two types of NMR spectrometers

Continuous wave (CW)

Fourier Transform (FT)

In CW spectrometer either the magnetic field or the

radio frequency is swept, bringing each nuclei to

resonance one at a time – signals are recorded one at a

time – hence very time consuming because each SCAN

has to be accumulated and averaged

In FT technique a short pulse of radio frequency is

applied that bring all the nuclei to resonance. The nuclei

are allowed to relax to ground state and the resulting

free induction decay is FOURIER transformed

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FREE INDUCTION DECAY OF EXCITED NUCLEI - FID

Signal

intenisty

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The concept of time domain-frequency domain spectroscopy – FT method

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Effect of signal averaging on

S/N ratio

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Carbon-13 NMR is usually recorded under conditions

of proton decoupling

That is all the C13-H1 coupling are decoupled by

irradiation (saturation) of all the protons

Therefore only a single signal is observed for each of

the chemically different carbons

From the symmetry of the structure one can easily

predict the number of signals expected for a compound

Groups like acetylene carbon, CN, CO, quaternary carbon

(no protons) are easily detected by Carbon-13 NMR

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Broad band decoupling: Carbon-13 spectra are recorded with

simultanous saturation of the proton spins using a second radio

frequency corresponding to the protons. This results in complete

decoupling of the protons and only carbon peaks are seen in the spectrum.

Gated coupling: Decoupler is switched on only during the delay time

and it is off during the data acquisition.

NOE enhancement is retained and the Carbon-13 spectrum is

proton coupled

Off-resonance decoupling: Decoupling with the radio frequency

that is not exactly that of protons but few hundred hertz displaced.

Splitting only due to the protons directly attached to a carbon are seen.

CH3 – quartet, CH2 – triplet, CH – doublet, Quaternary C - singlet

Page 83: ssr sir nmr class

Unlike proton NMR the signal intensities of Carbon-13 spectrum is

usually not quantitative.

1. The relaxation times of Carbon-13 nuclei are much longer than that of

protons.

2. Nuclear Overhauser Effect (NOE).

Relaxation mechanisms:

Spin-Lattice or Longitudinal Relaxation: (T1)

Relaxation by dispersing energy to the surroundings (lattice).

Spin-Spin or Transverse Relaxation: (T2)

Relaxation by dispersing energy to other spin active nucleus.

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Nuclear Overhauser Effect:

Enhancement of signal intensities due to heteronuclear coupling

For example: Carbon-13 signal intensities are enhanced due to

irradiation (decoupling) of the protons.

The major relaxation route for Carbon-13 nucleus involves

dipolar transfer of its excitation energy to protons that are

directly attached to it (transverse relaxation).

NOE effect will be maximum for CH3, CH2, CH and none for

Quaternary carbon.

Therefore peak intensities of CH3 > CH2 > CH > C

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Relaxation agents:

Paramagnetic relaxation agents such as Cr(acac)3 reduces

the longitudinal relaxation

This allows faster signal averaging

10-100 mM relaxation agent is needed – the solution takes on

a slight pink-purple hue

Net result: Signal intensities of quaternary carbons are

enhanced

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O

(a) Spectrum of camphor without relaxation agent

(b) With relaxation agent, Cr(acac)3 added, under otherwise identical conditions

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Chemical shift range in 13C-NMR spectrosocpy

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O

O CH2CH3O

OCH3CH2

1

2

3

4 5

5 4

2,3

1

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CDCl3

O

OCH2CH3

O

O

CH2CH3

1

2 3

4

5 6

6

5

2

3

4

1

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NH3C NH2

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CH3CH2O CH2C

O

N

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Distorsionless enhancement by polarization transfer (DEPT)

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2D Correlation Spectroscopy (COSY)

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O

HO OH

N3

O

O

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H-H COSY of 2-chlorobutane

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O

AcO OAc

OHN

OO

O

OAcAcO

N3

A B

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N

N

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N

N

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HMQC NMR of menthol

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Het-2D-J resolved

2-chlorobutane

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a-Pinene

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References:

J. B. Lambert, H. F. Shurvell, L. Verbit, R. G. Cooks, G. H. Stout

Organic Structural Analysis

Macmillan, New York, 1976

W. Kemp

Organic Spectroscopy, 3rd Edition, Macmillan, New York, 1991

D. H. Williams, I. Fleming

Spectroscopic Methods in Organic Chemistry, 4th Edition

Tata McGraw Hill, New Delhi, 1988

R. M. Silverstein, G. C. Bassler, T. C. Morrill

Spectroscopic Identification of Organic Compounds, 5th Edition

John Wiley, New York, 1991

H. Günther

NMR Spectroscopy, 2nd Edition

John Wiley, New York, 1994

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Timothy D. W. Claridge, High-Resolution NMR Techniques in Chemistry, Pergamon, 1999

John Wiley, 1998