Spring Mass

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    A mass is hooked on a flexible spring suspended vertically from a rigidsupport. Suppose the amount of elongation on the spring until it attain

    equilibrium is s. Then at this point, the weight of the mass will have the same

    magnitude as the restoring force. Once we pull the spring from the point of

    equilibrium and release it, then a restoring force will be applied on it.rovided that there is no other external force acting on the system ! i.e.

    retarding force", then we can equate the force acting on the spring and therestoring force. #esides, without damping ! retarding force" the spring$ mass

    system will continue to oscillate continuously.

    Since , so

    So we will obtain the following expression for the force acting on the spring%

    .

    The usual case for the spring mass system is%

    &" 'e pull the mass downwards ! the spring and release.

    (" 'e push the mass upwards !the spring compresses"

    mg ks= -mx ks= -&&

    kx mg- +

    mx kx= -&&

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    Solving the second order O)* !",

    #y using

    & & ( (x c y c y= +

    mx kx= -&&

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    +irst try%

    #y substituting the expression into the equation , we obtain%

    Thus the two roots of a is%

    (a m k= -

    aty e=

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    , but let

    So our solution is for the (nd order O)* is%

    onsider case &"

    - -

    & (

    i t i

    x c e c e-

    = +

    - k

    m=

    ka im

    = \

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    f the initial condition is such that , then , so

    .

    #esides, if we start the whole spring mass oscillation system such that .

    !/" /x =( ) ( & &cos- sin - cos - sin - c t i t c t i = + - -

    & (c c= -

    !/" /x =max0!/"x v=

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    Since , .

    Thus.

    max&

    (-

    vc

    i=

    &0! " (-cos-x t c i =

    &( sin-x c i t=

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    So the solution is% .

    onsider case ("

    f the initial condition is such that , then

    max! " sin--

    vx t =

    & (c A c= -!/"x A=

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    t is clear that when its position is at its amplitude then the velocity of the

    block is /.

    Since , we get%

    So

    0!/" /x =

    & (c c=

    - -

    & (0- i t i tx ic e ic e-= -

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    An alternative method can be used%

    #ut in real life situations, we usually do not have free motion ! i.e. retarding force isalways present". 1et2s only consider the first order resistive force which is .

    So the force

    ( ) ( cos- sin - cos- sin -( (cos-

    A A t i t t i

    A t

    = + + -

    =

    retardingF Cx= -

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    ( ) ( )

    ( ) ( )

    ( )

    ( ) ( )

    - -

    & (

    & (

    & ( & (

    & (

    ( ( & & (

    (

    &

    (

    ((( (

    & ( & ( & ( & (

    cos- sin - cos- sin -

    cos- sin -

    cos- sin -

    sin- 3

    ,

    )sin3

    cos3

    n3

    4 (

    i t i t

    c e c ec t i t c t i t

    c c t i t c c

    A t A t

    D tA

    c A c ci

    D

    A

    A

    A A c c i c c c c i

    -= +

    + - -

    - + +

    +

    +

    - = + =

    =

    =

    =

    = + = - + + = - =

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    & (

    &

    &

    (

    (

    & (

    ( 5( (

    & (

    5( (

    ( 5( (

    & (

    /

    5 - /

    5 - /

    5 5 4-

    (! "

    4- 5 4- /, , ! "

    (

    4- /, ! "

    5 4- 4- /, , ! "

    (

    a t a t

    a t

    t

    a t a

    x Cx kx

    x x

    a

    t c e c e

    ia x t e c e c e

    x t ce

    a x t e c e c e

    -

    -

    -

    + + =

    + + =

    + + =

    - -=

    = +

    -- < = = +

    - = =

    - - > = = +

    && &

    &