Special Inventory Mgmt Models

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    Special InventoryManagement & ControlModels

    Non-instantaneous replacement

    Quantity discount (Price break model)

    One period decision (Single period model)

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    NoninstantaneousReplenishment

    Maximum cycle inventory to be decided!Item used or sold as it is completedUsually production rate, p, exceeds the demandrate, d , so there is a buildup of ( p d ) units per time periodBoth p and d expressed in same time intervalBuildup continues for Q / p days to reach themaxm cycle inventory

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    NoninstantaneousReplenishment

    Product ion quant i ty Q

    Maximum inventory

    I max

    Productionand demand

    Demand or Consumption

    onlyTBO

    p d

    Demand duringproduction interval

    O n - h a n d

    i n v e n

    t o r y

    Time

    Lot Sizing with Noninstantaneous Replenishment

    p

    d

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    NoninstantaneousReplenishmentMaximum cycle inventory is:

    Cycle inventory is no longer Q / 2, it is I max / 2

    wherep = production rated = demand rate

    Q = lot size

    p

    d p Q d p

    p

    Q I max

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    NoninstantaneousReplenishment

    Total annual cost = Annual holding cost+ Annual ordering or setup cost

    D is annual demand and Q is lot sized is daily demand; p is daily production rate

    S Q

    D H

    p

    d p Q S

    Q

    D H

    I C

    22max

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    NoninstantaneousReplenishment

    Economic Production Lot Size (ELS): optimal lot size Derived by calculus Because the second term is greater than 1,

    the ELS results in a larger lot size than theEOQ

    d p

    p

    H

    DS EL S

    2

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    Finding the Economic Production LotSizeEXAMPLE D.1

    A plant manager of a chemical plant must determine the lotsize for a particular chemical that has a steady demand of 30 barrels per day. The production rate is 190 barrels per day, annual demand is 10,500 barrels, setup cost is $200,annual holding cost is $0.21 per barrel, and the plantoperates 350 days per year.

    a. Determine the economic production lot size (ELS)b. Determine the total annual setup and inventory

    holding cost for this item

    c. Determine the time between orders (TBO), or cyclelength, for the ELSd. Determine the production time per lot

    What are the advantages of reducing the setup time by 10percent?

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    Finding the Economic ProductionLot Size

    SOLUTIONa. Solving first for the ELS, we get

    d p

    p

    H

    DS 2ELS barrels4,873.430190

    190210

    200500102.$

    $,

    b. The total annual cost with the ELS is

    S Q

    D H

    p

    d p Q C

    2

    20048734

    50010210190

    301902

    48734$

    .,,

    .$.,

    828619143091430 .$.$.$

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    Finding the Economic ProductionLot Sizec. Applying the TBO formula to the ELS, we get

    days/year 350ELSTBO ELS D

    days162 or 162.4

    d. The production time during each cycle is the lot size dividedby the production rate:

    p

    ELS

    35050010

    48734,

    .,

    days26 or 25.6190

    48734 .,

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    Application D.1 A domestic automobile manufacturer schedules 12 two-person teams to assemble 4.6 liter DOHC V-8 engines per work day. Each team can assemble 5 engines per day. Theautomobile final assembly line creates an annual demand for the DOHC engine at 10,080 units per year. The engine andautomobile assembly plants operate 6 days per week, 48weeks per year. The engine assembly line also producesSOHC V-8 engines. The cost to switch the production linefrom one type of engine to the other is $100,000. It costs$2,000 to store one DOHC V-8 for one year.

    a. What is the economic lot size?b. How long is the production run?c. What is the average quantity in inventory?d. What is the total annual cost?

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    Application D.1SOLUTIONa. Demand per day = d = 10,080/[(48)(6)] = 35

    d p

    p

    H

    DS 2ELS 3855513560

    600002

    000100080102.,

    ,,,

    or 1,555 engines

    b. The production run

    p

    Q days production 26 or 25.91

    605551,

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    Application D.1

    c. Average inventory

    d. Total annual cost

    engines32460

    35602

    5551,

    S Q

    D H

    p

    d p Q S

    Q

    D H

    I C

    22max

    0001005551080100002

    603560

    25551 ,$

    ,,,$,

    1482961231648917647

    ,,$

    ,$,$

    p

    d p Q I

    22max

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    Quantity Discounts

    Price incentives to purchase large quantities createpressure to maintain a large inventory

    Items price is no longer fixed If the order quantity is increased enough, then the priceper unit is discounted

    A new approach is needed to find the best lot size thatbalances:

    Adv antages o f low er p r i ces fo r pu rchased m ate ri al s and fewer orders Disadvan tages o f th e inc reased c os t o f h o ld ing m ore inven to ry

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    Quantity Discounts

    Total annual cost = Annual holding cost+ Annual ordering or setup cost+ Annual cost of materials

    where P = price per unit, and

    D = annual demand (consumption)

    PDS Q D H QC 2

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    Quantity Discounts

    Unit holding cost ( H ) is usual ly expressed as apercentage of unit priceThe lower the unit price ( P ) is, the lower the unitholding cost ( H ) is

    The total cost equation yields U-shape total costcurves

    There are cost curves for each price levelThe feasible total cost begins with the top curve, thendrops down, curve by curve, at the price breaksEOQs do not necessarily produce the best lot size

    The EOQ at a particular price level may not be feasibleThe EOQ at a particular price level may be feasible but

    may not be the best lot size

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    Two-Step Solution Procedure

    Step 1. Beginning with lowest price, calculate the EOQfor each price level until a feasible EOQ isfound. It is feasible if it lies in the rangecorresponding to its price. Each subsequentEOQ is smaller than the previous one,because P , and thus H , gets larger andbecause the larger H is in the denominator of the EOQ formula.Step 2. If the first feasible EOQ found is for thelowest price level, this quantity is the bestlot size. Otherwise, calculate the total costfor the first feasible EOQ and for the larger price break quantity at each lower pricelevel. The quantity with the lowest total costis optimal.

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    Quantity Discounts

    (a) Total cost curves with purchasedmaterials added

    (b) EOQs and price break quantities

    PD for P = $4.00 PD for

    P = $3.50 PD for P = $3.00

    EOQ 4.00

    EOQ 3.50 EOQ 3.00

    T o

    t a l c o s

    t ( d o

    l l a r s

    )

    Purchase quantity ( Q )0 100 200 300

    Firstprice

    break

    Secondprice

    break

    T o

    t a l c o s

    t ( d o

    l l a r s

    )

    Purchase quantity ( Q )0 100 200 300

    Firstpricebreak

    Secondpricebreak

    C for P = $4.00

    C for P = $3.50C for P = $3.00

    Total Cost Curves with Quantity Discounts

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    Find Q with QuantityDiscounts

    EXAMPLE D.2 A supplier for St. LeRoy Hospital has introduced quantitydiscounts to encourage larger order quantities of aspecial catheter. The price schedule is

    Order Quantity Price per Unit

    0 to 299 $60.00

    300 to 499 $58.80

    500 or more $57.00

    The hospital estimates that its annual demand for this item is936 units, its ordering cost is $45.00 per order, and its annualholding cost is 25 percent of the catheters unit price. Whatquantity of this catheter should the hospital order to minimizetotal costs? Suppose the price for quantities between 300 and499 is reduced to $58.00. Should the order quantity change?

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    Find Q with QuantityDiscounts

    SOLUTIONStep 1: Find the first feasible EOQ, starting with the lowest price

    level:

    H

    DS 2EOQ 0057 . units77005725000459362

    .$..$

    A 77-unit order actually costs $60.00 per unit, instead of the$57.00 per unit used in the EOQ calculation, so this EOQ isinfeasible. Now try the $58.80 level:

    H DS 2EOQ 8058 . units768058250 00459362 .$.

    .$

    This quantity also is infeasible because a 76-unit order is toosmall to qualify for the $58.80 price. Try the highest price level:

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    Find Q with QuantityDiscounts

    This quantity is feasible because it lies in the rangecorresponding to its price, P = $60.00

    H

    DS 2EOQ 0060 . units75006025000459362

    .$..$

    Step 2: The first feasible EOQ of 75 does not correspond tothe lowest price level. Hence, we must compare itstotal cost with the price break quantities (300 and 500units) at the lower price levels ($58.80 and $57.00):

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    Find Q with Quantity Discounts

    PD S Q D H Q C

    2

    284579360060004575

    93600602502

    7575 ,$.$.$.$.C

    38257936805800453009368058250

    2300

    300 ,$.$.$.$.C

    9995693600570045500

    93600572502

    500500 ,$.$.$.$.C

    The best purchase quantity is 500 units, which qualifies for thedeepest discount

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    Application D.2

    A suppliers price schedule is: Order Quantity Price per Unit

    0 99 $50

    100 or more $45

    If ordering cost is $16 per order, annual holding cost is 20percent of the purchase price, and annual demand is 1,800items, what is the best order quantity?

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    Application D.2

    SOLUTIONStep 1:

    H

    DS 2EOQ 0045 . e)(infeasiblunits8020451680012

    .,

    H DS 2EOQ 0050 . (feasible)units762050

    1680012.

    ,

    Step 2:

    76C 759908001501676

    800120502

    76,$,

    ,.

    100C 738818001451610080012045

    2100

    ,$,,

    .

    The best order quantity is 100 units

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    One-Period Decisions

    Seasonal goods are a dilemma facing manyretailers.Newsboy problem

    Step 1: List different demand levels and

    probabilities.Step 2: Develop a payoff table that shows the profit

    for each purchase quantity, Q , at eachassumed demand level, D .Each row represents a different order quantity and each column represents adifferent demand.The payoff depends on whether all units aresold at the regular profit margin whichresults in two possible cases.

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    One-Period Decisions

    If demand is high enough ( Q D), then all of the casesare sold at the full profit margin, p, during the regular season

    If the purchase quantity exceeds the eventual demand(Q > D ), only D units are sold at the full profit margin,and the remaining units purchased must be disposedof at a loss, l , after the season

    Payoff = (Profit per unit)(Purchase quantity) = pQ

    Payoff = (Demand)Lossper unit

    Profit per unit sold

    duringseason

    Amountdisposedof after season

    = p X D l X (Q D)

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    One-Period Decisions

    Step 3: Calculate the expected payoff of each Q byusing the expected value decision rule. For a specific Q, first multiply each payoff by itsdemand probability, and then add theproducts.

    Step 4: Choose the order quantity Q with thehighest expected payoff.

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    Finding Q for One-PeriodDecisions

    EXAMPLE D.3One of many items sold at a museum of natural history is aChristmas ornament carved from wood. The gift shop makes a$10 profit per unit sold during the season, but it takes a $5loss per unit after the season is over. The following discreteprobability distribution for the seasons demand has beenidentified:

    Demand 10 20 30 40 50

    Demand Probability 0.2 0.3 0.3 0.1 0.1

    How many ornaments should the museums buyer order?

    Fi di f O P i d

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    Finding Q for One-PeriodDecisions

    SOLUTIONEach demand level is a candidate for best order quantity,so the payoff table should have five rows. For the firstrow, where Q = 10, demand is at least as great as thepurchase quantity. Thus, all five payoffs in this row are

    This formula can be used in other rows but only for thosequantity demand combinations where all units are soldduring the season. These combinations lie in the upper-right portion of the payoff table, where Q D . For example,the payoff when Q = 40 and D = 50 is

    Payoff = pQ = ($10)(10) = $100

    Payoff = pQ = ($10)(40) = $400

    d f d

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    Finding Q for One-PeriodDecisions

    The payoffs in the lower-left portion of the table representquantity demand combinations where some units must bedisposed of after the season ( Q > D). For this case, the payoff must be calculated with the second formula. For example,when Q = 40 and D = 30,

    Using OM Explorer, we obtain the payoff table in Figure D.5

    Payoff = pD l (Q D ) = ($10)(30) ($5)(40 30) = $250

    Now we calculate the expected payoff for each Q by multiplying

    the payoff for each demand quantity by the probability of thatdemand and then adding the results. For example, for Q = 30,

    Payoff = 0.2($0) + 0.3($150) + 0.3($300) + 0.1($300) + 0.1($300)= $195

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    Application D.3

    For one item, p = $10 and l = $5. The probability distribution for theseasons demand is:

    Demand Demand(D) Probability10 0.220 0.330 0.340 0.150 0.1

    Complete the following payoff matrix, as well as the column onthe right showing expected payoff. What is the best choice for Q ?

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    Application D.3D

    ExpectedPayoff Q 10 20 30 40 5010 $100 $100 $100 $100 $100 $10020 50 200 200 200 200 17030 0 300 30040 50 100 250 400 400 175

    50 100 50 200 350 500 140

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    Application D.3

    Payoff if Q = 30 and D = 20:

    pD l (Q D ) = 10(20) 5(30 20) = $150

    Payoff if Q = 30 and D = 40:

    Expected payoff if Q = 30:

    pD = 10(30) = $300

    0(0.2) + 150(0.3) + 300(0.3 + 0.1 + 0.1) = $195

    Q = 30 has the highest payoff at $195.00

    D

    ExpectedPayoff Q 10 20 30 40 5010 $100 $100 $100 $100 $100 $10020 50 200 200 200 200 17030 0 300 30040 50 100 250 400 400 175

    50 100 50 200 350 500 140

    150 300 195

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    Solved Problem 1

    Peachy Keen, Inc., makes mohair sweaters, blouses withPeter Pan collars, pedal pushers, poodle skirts, and other popular clothing styles of the 1950s. The average demandfor mohair sweaters is 100 per week. Peachys productionfacility has the capacity to sew 400 sweaters per week.

    Setup cost is $351. The value of finished goods inventoryis $40 per sweater. The annual per-unit inventory holdingcost is 20 percent of the items value.

    a. What is the economic production lot size (ELS)?b. What is the average time between orders (TBO)?c. What is the total of the annual holding cost and setup cost?

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    Solved Problem 1

    SOLUTIONa. The production lot size that minimizes total cost is

    d p

    p

    H

    DS 2ELS100400

    40040200

    351521002$.

    $

    sweaters78034300456 ,

    b. The average time between orders is

    D ELSOTB ELS year 0.152005780,

    Converting to weeks, we get

    weeks7.8r weeks/yea52year 0.15TBO ELS

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    Solved Problem 1

    c. The minimum total of setup and holding costs is

    S Q

    D H

    p

    d p Q C

    2

    3517802005402004001004002780 $,$.

    r $4,680/year $2,340/year $2,340/yea

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    Solved Problem 2

    A hospital buys disposable surgical packages from Pfisher, Inc.Pfishers price schedule is $50.25 per package on orders of 1 to 199packages and $49.00 per package on orders of 200 or morepackages. Ordering cost is $64 per order, and annual holding cost is20 percent of the per unit purchase price. Annual demand is 490packages. What is the best purchase quantity?

    SOLUTIONWe first calculate the EOQ at the lowest price:

    H

    DS 2EOQ0049 .

    packages8040060049200

    00644902,

    .$.

    .$

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    Solved Problem 2

    This solution is infeasible because, according to the priceschedule, we cannot purchase 80 packages at a price of $49.00 each. Therefore, we calculate the EOQ at the nextlowest price ($50.25):

    H

    DS 2EOQ 2550 . packages7924162550200

    00644902,.$.

    .$

    This EOQ is feasible, but $50.25 per package is not the lowestprice. Hence, we have to determine whether total costs can be

    reduced by purchasing 200 units and thereby obtaining aquantity discount.

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    Solved Problem 2

    PD S Q D H Q C

    2

    4902550006479

    49025502002

    7979 .$.$.$.C

    490004900642004900049200

    2200

    200 .$.$.$.C

    /year $25,416.44$24,622.50ar $396.68/year $396.98/ye

    /year $25,146.80$24,010.00ar $156.80/year $980.00/ye

    Purchasing 200 units per order will save $269.64/year,compared to buying 79 units at a time.

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    Solved Problem 3

    Swell Productions is sponsoring an outdoor conclave for owners of collectible and classic Fords. The concession standin the T-Bird area will sell clothing such as T-shirts and officialThunderbird racing jerseys. Jerseys are purchased fromColumbia Products for $40 each and are sold during the eventfor $75 each. If any jerseys are left over, they can be returnedto Columbia for a refund of $30 each. Jersey sales depend onthe weather, attendance, and other variables. The followingtable shows the probability of various sales quantities. Howmany jerseys should Swell Productions order from Columbiafor this one-time event?Sales Quantity Probability Quantity Sales Probability

    100 0.05 400 0.34

    200 0.11 500 0.11

    300 0.34 600 0.05

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    Solved Problem 3

    SOLUTIONTable next slide is the payoff table that describes this one-period inventory decision. The upper right portion of the tableshows the payoffs when the demand, D , is greater than or equal to the order quantity, Q. The payoff is equal to the per-unit profit (the difference between price and cost) multiplied bythe order quantity. For example, when the order quantity is100 and the demand is 200,

    Payoff = ( p c )Q = ($75 - $40)100 = $3,500

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    Solved Problem 3

    PAYOFFS table

    Demand, D Expected

    Payoff Q 100 200 300 400 500 600100 $3,500 $3,500 $3,500 $3,500 $3,500 $3,500 $3,500

    200 $2,500 $7,000 $7,000 $7,000 $7,000 $7,000 $6,775

    300 $1,500 $6,000 $10,500 $10,500 $10,500 $10,500 $9,555

    400 $500 $5,000 $9,500 $14,000 $14,000 $14,000 $10,805

    500 ($500) $4,000 $8,500 $13,000 $17,500 $17,500 $10,525

    600 ($1,500) $3,000 $7,000 $12,000 $16,500 $21,000 $9,750

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    Solved Problem 3The lower-left portion of the payoff table shows the payoffswhen the order quantity exceeds the demand. Here thepayoff is the profit from sales, pD , minus the lossassociated with returning overstock, l (Q D), where l is thedifference between the cost and the amount refunded for each jersey returned and Q D is the number of jerseys

    returned. For example, when the order quantity is 500 andthe demand is 200,Payoff = pD l (Q D ) = ($75 - $40)200 ($40 $30)(500 200)

    = $4,000

    The highest expected payoff occurs when 400 jerseys are

    ordered:Expected payoff 400 = ($500 0.05) + ($5,000 0.11)

    + ($9,500 0.34) + ($14,000 0.34)+ ($14,000 0.11) + ($14,000 0.05)

    = $10,805