Upload
makosantoniou
View
28
Download
0
Tags:
Embed Size (px)
DESCRIPTION
We initiate a solution procedure to the Painlevé PII equation. The method used is the Riccati equation method with variable expansion coefficients. The solutions are expressed in terms of the Airy functions.
Citation preview
Some General Solutions to the
Painlevé – PII Equation
Solomon M. Antoniou
SKEMSYS Scientific Knowledge Engineering
and Management Systems
Corinthos 20100, Greece [email protected]
Revised Version: 11/07/2014
Abstract
We initiate a solution procedure to the Painlevé PII equation. The method used is
the Riccati equation method with variable expansion coefficients. The solutions
are expressed in terms of the Airy functions.
Keywords: Painlevé equations, Painlevé PII equation,the extended Riccati
equation method, nonlinear equations, exact solutions, Airy functions.
2
1. Introduction.
The Painlevé equations (numbered as PI-PVI) is a special class of second order
nonlinear ODEs which have no movable critical points (branch points or essential
singularities). These equations were discovered under a number of assumptions at
the end of nineteenth century/beginning of twentieth century by Painlevé and
Gambier. They also appear in many physical applications. Some reviews and
further developments the reader can consult, are the classical book by E. L. Ince
(Ince [10], Chapter XIV) and the articles by A. S. Fokas and M. J. Ablowitz
(Fokas and Ablowitz [9]) and P. A. Clarkson (Clarkson [7]). Closely related to
Painlevé equations is the so-called ARS conjecture (after Ablowitz, Ramani and
Segur [1], [2] and [11]) which is an integrability test for ordinary differential
equations. The ARS conjecture was extended to PDEs by J. Weiss, M. Tabor and
G. Carnevale (Weiss, Tabor and Carnevale [13]) who introduced the so-called
singular manifold method (for a review and further examples see Ramani,
Grammaticos and Bountis [12]). This method (also named as Painlevé truncation
method) serves also as a solution method (Weiss [14], [15] and [16]) in the sense
that it can determine the Lax pairs and the Bäcklund transformations.
No explicit solutions of the Painlevé equations have been found so far. In some
cases only rational solutions are available (Airlaut [4] and Wenjum and Yezhou
[17]). Some relations have also been established between solutions (Fokas and
Ablowitz [9], Clarkson [7]).
In this paper we introduce a solution method and find some closed-form solutions
to the Painlevé PII equation using the extended Riccati equation method with
variable expansion coefficients. The solutions are expressed in terms of the Airy
functions. The paper is organized as follows: In Section 2 we describe the
extended Riccati equation method with variable expansion coefficients. This
method was introduced in Antoniou ([5] and [6]) and applied successfully in two
cases of nonlinear PDEs, the Burgers and KdV equations. In Section 3 we solve
3
the Painleve PII equation wzw2dz
wd 32
2⋅+= . We find two families of solutions,
expressed in terms of the Airy functions. In Section 4 we consider the
−′ )G/G( expansion method with variable expansion coefficients. We obtain two
third order differential equations which, when solved, can in principle determine
the unknown function G.
2. The Method.
We suppose that a nonlinear ordinary differential equation
0),u,u,u,x(F xxx =L (2.1)
with unknown function )x(u admits a solution expressed in the form
∑∑==
+=n
1kkk
n
0k
kk
Y
bYa)x(u (2.2)
where all the expansion coefficients depend on the variable x,
)x(aa kk ≡ , )x(bb kk ≡ for every n,,2,1,0k L=
The function )x(YY ≡ satisfies Riccati’s equation
2YBA)x(Y ⋅+=′ (2.3)
where the coefficients A and B depend on the variable x as well.
In solving the nonlinear ODE (2.1), we consider the expansion (2.2) and then we
balance the nonlinear term with the highest derivative term of the function )x(u
which determines n (the number of the expansion terms). Equating the
coefficients of the different powers of the function )x(Y to zero, we can
determine the various expansion coefficients )x(ak , )x(bk and the functions
)x(A , )x(B . We finally solve Riccati's equation and then find the solutions of the
equation considered.
4
3. The Painleve PII equation and its solutions.
We consider the Painleve PII equation
wzw2dz
wd 32
2⋅+= (3.1)
where )z(ww ≡ is the unknown function and z the independent variable,
considered complex in general.
We shall use the extended Riccati equation method in solving equation (3.1). In
this case we consider the expansion
∑∑==
+=n
1kkk
n
0k
kk
Y
bYa)z(w (3.2)
and balance the second order derivative term with the second order nonlinear term
of (3.1). We then find 1n = and thus
Y
bYaa)z(w 1
10 ++= (3.3)
where all the coefficients 0a , 1a and 1b depend on z, and Y satisfies Riccati’s
equation
)z(Y)z(B)z(A)z(Y 2+=′ (3.4)
The prime will always denote derivative with respect to the variable z. From
equation (3.3) we obtain, taking into account 2BYAY +=′
2
2112
110Y
)BYA(b
Y
b)BYA(aYaa)z(w
+−′
+++′+′=′ (3.5)
)BYA(YB2YBA(a)BYA(a2Yaa)z(w 221
2110 ++′+′++′+′′+′′=′′
2
21
21
211
Y
)BYA(BYb2)YBA(b)BYA(b2
Y
b ++′+′++′−
′′+
3
221
Y
)BYA(b2 ++ (3.6)
Therefore equation (3.1), under the substitutions (3.3) and (3.6), becomes
5
)BYA(YB2YBA(a)BYA(a2Yaa 221
2110 ++′+′++′+′′+′′
2
21
21
211
Y
)BYA(BYb2)YBA(b)BYA(b2
Y
b ++′+′++′−
′′+
++⋅+
++=++Y
bYaaz
Y
bYaa2
Y
)BYA(b2 110
31
103
221 (3.7)
Upon expanding and equating the coefficients of Y to zero, we obtain from the
above equation a system of seven ordinary differential equations from which we
can determine the various expansion coefficients. We obtain
coefficient of 3Y :
0a2Ba2 31
21 =− (3.8)
coefficient of 2Y :
0Ba2Baaa6 11210 =′+′+− (3.9)
coefficient of Y:
0aaa6ba6azBAa2 11201
2111 =′′+−−− (3.10)
coefficient of 0Y :
0Aa2BbAaBb2baa12a2aza 11111103000 =′+′−′+′−−−−′′ (3.11)
coefficient of 1Y − :
0ABb2ba6ba6bzb 12111
2011 =+−−−′′ (3.12)
coefficient of 2Y − :
0Abba6Ab2 12101 =′−−′− (3.13)
coefficient of 3Y − :
0b2Ab2 31
21 =− (3.14)
We are to solve the system of equations (3.8)-(3.14), supplemented by Riccati's
equation 2BYAY +=′ .
6
From equations (3.8) and (3.14), ignoring the trivial solutions, we obtain
Ba1 ±= and Ab1 ±= (3.15)
respectively. We examine four cases separately. Two of them, leading to
inconsistent results are examined in Appendix B.
3.I. Case I. The First Solution.
We first consider the case
Ba1 = and Ab1 = (3.16)
We then obtain from (3.9) and (3.13)
BB
21
a0′
= and AA
21
a0′
−= (3.17)
respectively. Equating the two different expressions of 0a , we obtain 0BB
AA =
′+
′
and by integration, we find that
pBA = (3.18)
where p is a constant to be determined.
From equation (3.10) we get
0)zp4(B
B
2
3
B
B 2
=+−
′−
′′ (3.19)
From equation (3.12) we get
0)zp4(A
A
2
3
A
A 2
=+−
′−
′′ (3.20)
From equation (3.11) we get
0BB
)zp8(BB
21
BB 3
=
′+−
′−
″
′ (3.21)
We first solve equation (3.19). Under the substitution
BB
F′
= (3.22)
equation (3.19) transforms into
7
)zp4(F21
F 2 ++=′ (3.23)
which is a Riccati differential equation. Under the standard substitution
uu
2F′
−= (3.24)
Riccati's equation (3.23) becomes
0)z(u2
zp4)z(u =⋅++′′ (3.25)
The previous equation can be transformed into the Airy equation. In fact, under
the substitution µ+λ= yz , equation (3.25) takes on the form
0)y(u2
)p4(y
2dy
)y(ud 23
2
2=
+µλ+λ+ (3.26)
The choices 23 −=λ and p4−=µ transforms (3.26) into
0)y(uydy
)y(ud2
2=− (3.27)
which is the Airy differential equation with general equation
)y(BiC)y(AiC)y(u 21 += (3.28)
where )y(Ai and )y(Bi are Airy's functions of the first and second kind
respectively (see for example Abramowitz and Stegun [3]). Going back to the
original variable (taking into account y)2(p4z 3/1−=+ ) we obtain the general
solution of equation (3.25)
−++
−+=
3/123/11)2(
p4zBiC
)2(
p4zAiC)z(u (3.29)
We now have to determine the function Y which satisfies Riccati's equation
2BYAY +=′ . Under the substitution
vv
B1
Y′
⋅−= (3.30)
Riccati's equation 2BYAY +=′ becomes
8
0v)AB(vBB
v =+′
′−′′ (3.31)
Since uu
2BB ′
−=′
and pBA = , equation (3.31) becomes 0uvp2vu2vu =+′′+′′
which can be written as
0v)uup2()vu( =′′−+′′⋅ (3.32)
The substitution
vu ⋅=Ψ (3.33)
transforms (3.32) into
0uu
p2 =Ψ
′′−+Ψ ′′ (3.34)
Since z21
p2uu −−=
′′ (because of (3.25)), equation (3.34) takes on the form
0z21
p4 =Ψ
++Ψ ′′ (3.35)
The above equation can be transformed into the Airy's equation (the same way
(3.25) was transformed into (3.27)) and admits the general solution
−++
−+=Ψ
3/123/11)2(
p8zBiC
~
)2(
p8zAiC
~ (3.36)
Integrating uu
2BB ′
−=′
we obtain
)z(u
KB
2= (3.37)
where K is a constant. Since uu
vv ′
−ΨΨ′
=′
(this equation comes from u/v Ψ=
by differentiation) we obtain from (3.30), using also (3.37)
′−
ΨΨ′
−=u
u
K
uY
2 (3.38)
where Ψ and u are given by (3.36) and (3.29) respectively.
9
So far we have not taken into account equations (3.20) and (3.21). It is obvious
that not every solution of (3.19) satisfies both (3.20) and (3.21). We thus have to
find the range of values the parameters and the constants should attain in order to
have compatible equations. The coefficients A and B of Riccati's equations are
connected through the relation 0BB
AA =
′+
′ and satisfy equations (3.19) and (3.20)
respectively. We thus have to examine the compatibility condition between (3.19)
and (3.20) first, taking into account 0BB
AA =
′+
′. We state and prove the following
Lemma. If 0BB
AA =
′+
′ then
2
B
B2
B
B
A
A
′=
′′+
′′.
Proof. We let AA
H′
= . Since 0FH =+ , we also have FH ′−=′ and then
22
BB
FAA
HAA
′+′−=
′+′=
′′ and
2
BB
FBB
′+′=
′′. Adding the last two
equations, we obtain 2
BB
2BB
AA
′=
′′+
′′ and the Lemma is proved. ■
Adding now equations (3.19) and (3.20) and taking into account the previous
Lemma, we obtain the equation 0)zp4(2BB 2
=+−
′− from which we obtain
further, in view of uu
2BB ′
−=′
, that
02z
p2uu 2
=
++
′ (3.39)
The above equation is the compatibility condition between (3.19) and (3.20) and
should be satisfied for every z.
We finally consider equation (3.21). This equation takes the form
F)p8z(F21
F 3 +=−′′ (3.40)
10
where F is defined in (3.22). This equation should be combined with (3.23).
From (3.23) multiplying by F we obtain F)zp4(FFF21 3 ++′−=− and because
of that, equation (3.40) takes on the form Fp4FFF =′−′′ . Differentiating (3.23)
we get 1FFF =′−′′ . We thus obtain the equation 1Fp4 = . Since uu
2F′
−= , we
derive the compatibility condition p8
1uu −=
′, i.e.
0uup8 =+′ (3.41)
This last equation should hold for every z.
Equations (3.39) and (3.41) should also be compatible each other. Equations
(3.39) and (3.41) are considered in Appendix A. In that Appendix, expanding the
function )z(u given by (3.29) we find the conditions between the parameters and
the various constants in order equations (3.39) and (3.41) should be true for every
z. According to the results of Appendix A, the compatibility equations (3.39) and
(3.41) lead to the same conditions
0);C,C(X 21 =ω and 0);C,C(Z 21 =ω (3.42)
where );C,C(X 21 ω and );C,C(Z 21 ω are defined by
)(BiC)(AiC);C,C(X 2121 ω+ω=ω (3.43)
)(iBC)(iAC);C,C(Z 2121 ω′+ω′=ω (3.44)
p)3i1(2 3/2 −=ω (3.45)
and the prime denotes the usual derivative
ω==ω′z
)z(Aidzd
)(iA and ω==ω′z
)z(Bidzd
)(iB
The two equations (3.42) hold simultaneously, in view of (3.43) and (3.44), if
)(Ai)(Bi
C
C
2
1
ωω−= and
)(iA)(iB
C
C
2
1
ω′ω′
−= (3.46)
11
Equating the two different expressions of the ratio 21 C/C , we arrive at the
condition
0)(Bi)(iA)(iB)(Ai =ω⋅ω′−ω′⋅ω (3.47)
The above condition determines the constant p.
Equation (3.29) has to be written, in view of (3.46), into the form
−+ω−
−+ω=
3/13/1 )2(
p4zAi)(Bi
)2(
p4zBi)(AiC)z(u (3.48)
where we have set )(Ai
CC 2
ω= .
Conclusion. The solution of the Painleve PII equation wzw2dz
wd 32
2⋅+= is
given by Y
bYaa)z(w 1
10 ++= where BB
21
a0′
= , Ba1 = , Ab1 = with pBA = ,
)z(u
K)z(B
2= and
′−
ΨΨ′
−=u
u
K
uY
2, where Ψ and u are given by (3.36) and
(3.48) respectively. Therefore )z(w is given by
1
uu
p)z(w−
ΨΨ′
−′
+ΨΨ′
−= (3.49)
where p is determined by (3.47) and Ψ , u are given by (3.36) and (3.48)
respectively.
3.II. Case II. The Second Solution.
We next consider the case
Ba1 −= and Ab1 −= (3.50)
We then obtain from (3.9) and (3.13)
BB
21
a0′
−= and AA
21
a0′
= (3.51)
respectively. Equating the two different expressions of 0a , we find that
pAB = (3.52)
12
where p is a constant.
From equation (3.10) we get
0)zp4(B
B
2
3
B
B 2
=+−
′−
′′ (3.53)
From equation (3.12) we get
0)zp4(A
A
2
3
A
A 2
=+−
′−
′′ (3.54)
From equation (3.11) we get
0BB
)zp8(BB
21
BB 3
=
′+−
′−
″
′ (3.55)
Using the same reasoning as in Case I, we obtain the following
Conclusion. The solution of the Painleve PII equation wz)z(w2dz
wd 32
2⋅+= is
given by Y
bYaa)z(w 1
10 ++= where BB
21
a0′
−= , Ba1 −= , Ab1 −= with
pBA = , )z(u
K)z(B
2= and
′−
ΨΨ′
−=uu
Ku
Y2
, where Ψ and u are given by
(3.36) and (3.48) respectively. Therefore )z(w is given by
1
uu
p)z(w−
ΨΨ′
−′
+ΨΨ′
= (3.56)
where p is determined by (3.47) and Ψ , u are given by (3.36) and (3.48)
respectively.
Note. Considering the equation
α+⋅+= wz)z(w2dz
wd 32
2
we find that the solution does not depend on the constant α , a feature for which
we cannot provide an explanation.
13
4. The −
′GG expansion method with variable expansion
coefficients.
We consider that equation (3.1) admits a solution of the form
′+=
)z(G)z(G
)z(a)z(a)z(w 10 (4.1)
Upon substituting (4.1) into (3.3) we obtain an equation, which when arranged in
powers of G, can take the form
]Gaa6Ga2GaGazGa[)x(G
1)a2aza( 2
0111113000 ′−′′′+′′′+′−′′′+−−′′
])G(aa6GGa3)G(a2[)x(G
1 20
211
212
′−′′′−′′−+
0])G(a2)G(a2[)x(G
1 31
3313
=′+′−+ (4.2)
Equating to zero all the coefficients of )x(G in the above equation, we obtain the
following system of ordinary differential equations
0a2aza 3000 =−−′′ (4.3)
0Gaa6Ga2GaGazGa 2011111 =′−′′′+′′′+′−′′′ (4.4)
0)G(aa6GGa3)G(a2 20
211
21 =′−′′′−′′− (4.5)
0)G(a2)G(a2 31
331 =′+′− (4.6)
Equation (4.3) is essentially equation (3.3) and thus admits all the solutions found
in Section 3. From equation (4.6), ignoring the trivial solution, we obtain that
1a1 ±= (4.7)
From equation (4.4), taking into account the above values of 1a , we derive the
equation
za6GG 2
0 +=′′′′
(4.8)
14
From equation (4.5), we obtain
0a2GG −=
′′′
for 1a1 = and 0a2GG =
′′′
for 1a1 −= (4.9)
We thus derive the following equations, dividing (4.8) by (4.9):
Solution I. For 1a1 = , the function )x(G is determined as solution of the
equation 0
20
a2
za6
GG +−=
′′′′′
where 0a is any solution of equation (4.3).
Solution II. For 1a1 −= , the function )x(G is determined as solution of the
equation 0
20
a2
za6
GG +=
′′′′′
where 0a is any solution of equation (4.3).
In both the above equations, 0a is given by (3.47) and (3.54) (simply substitute
)z(w by 0a ). Because of the complexity of the expressions for 0a , the integration
of the differential equations might require supercomputing facilities with symbolic
capabilities. A remarkable feature of the −′ )G/G( expansion with variable
expansion coefficients is that a repeated use of the method in determining 0a
leads to a proliferation of solutions, a rather unique feature of the Riccati –
−′ )G/G( expansion.
Appendix A. In this Appendix we find the conditions the various parameters
and the constants should satisfy so as equations (3.39) and (3.41) should be true
for every value of the parameter z.
We first consider equation (3.39) which can be written as a couple of equations
0u2
zp2iu =++′ (A.1)
and
0u2
zp2iu =+−′ (A.2)
where )z(u is given by (3.29).
15
Upon expanding )z(u in power series, we find that (A.1) can be written as
);C,C(Z)3i1(4
2);C,C(Xp2i 21
3/2
21 ω−+ω
z)};C,C(Z)i1(p24);C,C(X)p162i({p8
121
6/121
2/3 ω+⋅+ω−+
)3i()p2[(8);C,C(X)p2128ip322i({p128
1 6/121
32/32/3
++ω++−+
221
3/22/5 z)};C,C(Z]2p)13i(4 ω−+
+ω−++ );C,C(X)pi2640i23p2048({p3072
121
32/92/5
)i3(p2512)13i(2p128[ 46/13/22/5 +⋅−−+
321
6/1 z)};C,C(Z]p)3i(212 ω+⋅−
)z(O 4+ (A.3)
where we have introduced the notation
)(BiC)(AiC);C,C(X 2121 ω+ω=ω (A.4)
)(iBC)(iAC);C,C(Z 2121 ω′+ω′=ω (A.5)
p)3i1(2 3/2 −=ω (A.6)
and the prime denotes the usual derivative
ω==ω′z
)z(Aidzd
)(iA and ω==ω′z
)z(Bidzd
)(iB
Similarly expanding )z(u in power series, we find that (A.2) can be written as
);C,C(Z)3i1(4
2);C,C(Xp2i 21
3/2
21 ω−+ω−
z)};C,C(Z)i1(p24);C,C(X)p162i({p8
121
6/121
2/3 ω+⋅+ω+−
)3i()p2([8);C,C(X)p2128ip322i({p128
1 6/121
32/32/3
+−+ω+−+
16
221
3/22/5 z)};C,C(Z]2p)13i(4 ω−+
+ω+−+ );C,C(X)pi2640i23p2048({p3072
121
32/92/5
)i3(p2512)13i(2p128[ 46/13/22/5 +⋅+−+
321
6/1 z)};C,C(Z]p)3i(212 ω+⋅+
)z(O 4+ (A.7)
Expanding (3.41) we obtain similarly
+ω−⋅+ω });C,C(Z)3i1(p22);C,C(X{ 213/2
21
+
ω⋅−+ω⋅−+ z);C,C(Z)3i1(4
2);C,C(Xp16 21
3/2
212
+ω⋅−⋅+ω⋅−+ 221
23/221 z});C,C(Z)13i(p22);C,C(Xp3{
+
ω⋅−⋅−ω⋅
−+ 3
21
3/2
21
3z);C,C(Z)3i1(p
1225
);C,C(X121
3p16
0)z(O 4 =+ (A.8)
In all the higher order expansion terms, there appears the same linear combination
of the quantities );C,C(X 21 ω and );C,C(Z 21 ω . Therefore the compatibility
conditions (3.39) and (3.41) are true for every z , if and only if
0);C,C(X 21 =ω and 0);C,C(Z 21 =ω (A.9)
The two equations (A.9) hold simultaneously if
)(Ai)(Bi
C
C
2
1
ωω−= and
)(iA)(iB
C
C
2
1
ω′ω′
−= (A.10)
Equating the two different expressions of the ratio 21 C/C , we arrive at the
condition
0)(Bi)(iA)(iB)(Ai =ω⋅ω′−ω′⋅ω (A.11)
The above condition determines the constant p.
17
Appendix B.
In this Appendix we consider the cases ( Ba1 = , Ab1 −= ) and ( Ba1 −= ,
Ab1 = ). We show that in these two cases we obtain incompatible equations.
Case III. We consider the case
Ba1 = and Ab1 −= (B.1)
We then obtain from (3.9) and (3.13)
BB
21
a0′
= and AA
21
a0′
= (B.2)
respectively. Equating the two different expressions of 0a , and integrating, we
find that
BsA 2−= (B.3)
where s is a real constant. We can equally well consider the case BsA 2= .
From equation (3.10), we get
0zBs8B
B
2
3
B
B 222
=−−
′−
′′ (B.4)
From equation (3.12) we get
0zBs8AA
23
AA 22
2
=−−
′−
′′ (B.5)
From equation (3.11) we get
0)B(s12BB
zBB
21
BB 22
3
=′−
′−
′−
″
′ (B.6)
Equation (B.4) under the substitution
)z(u
1B
2= (B.7)
takes on the form
)z(u
s4)z(u
2z
)z(u3
2−=+′′ (B.8)
18
which is Ermakov's equation (Ermakov [8]). The equation 0)z(u2z
)z(u =+′′
admits two linearly independent solutions,
− 3/1)2(
zAi and
− 3/1)2(
zBi .
Therefore, using the standard procedure, the general solution of (B.8) is given by
−
++−×
−= ∫
2
2
3/1
122
2
3/12
1
)2(
zAi
dzCCs4
)2(
zAi)z(uC (B.9)
and
−
++−×
−= ∫
2
2
3/1
122
2
3/12
1
)2(
zBi
dzCCs4
)2(
zBi)z(uC (B.10)
Every solution of the equation (B.4) found previously has to be substituted in
(B.6) and thus to obtain a compatibility condition. Despite the fact that (B.4)
admits closed-form solution, equations (B.4) and (B.6) are incompatible. The
proof goes as follows: Equations (B.4) and (B.6) can be written in terms of
BB
G′
≡ as
zBs8G21
G 222 +=−′ (B.11)
and
0)B(s12GzG21
G 223 =′−−−′′ (B.12)
respectively. Multiplying equation (B.11) by G we derive the equation
19
GzBGs8GGG21 223 ++′−=− (B.13)
Combining (B.12) with (B.13) we get
0)B(s12BGs8GGG 2222 =′−+′−′′ (B.14)
Differentiating (B.11) with respect to z we obtain
1)B(s8GGG 22 +′=′−′′ (B.15)
Equations (B.14) and (B.15) give
0)B(s12BGs81)B(s8 222222 =′−++′
which is equivalent to the quite remarkable result 01= . We have thus proved that
equations (B.4) and (B.6) are incompatible. The case BsA 2= leads again to
incompatible equations.
Case IV. We consider next the case
Ba1 −= and Ab1 = (B.16)
Using the same reasoning as before, we obtain again incompatible equations.
20
References
[1] M. J. Ablowitz, A. Ramani and H. Segur: "A connection between
nonlinear evolution equations and ordinary differential equations of
P-type. I" J. Math. Phys. 21 (1980) 715-721
[2] M. J. Ablowitz, A. Ramani and H. Segur: "A connection between
nonlinear evolution equations and ordinary differential equations of
P-type. II" J. Math. Phys. 21 (1980) 1006-1015
[3] M. Abramowitz and I. A. Stegun: "Handbook of Mathematical
Functions". Dover 1972
[4] H. Airault: "Rational solutions of Painlevé equations"
Stud. Appl. Math. 61 (1979) 31-53
[5] S. Antoniou: “The Riccati equation method with variable expansion
coefficients. I. Solving the Burgers equation”. submitted for publication
[6] S. Antoniou: “The Riccati equation method with variable expansion
coefficients. II. Solving the KdV equation”. submitted for publication
[7] P. A. Clarkson: "Painlevé equations-nonlinear special functions"
J. Comp. Appl. Math. 153 (2003) 127-140
[8] V. P. Ermakov: “Second-Order Differential Equations: Conditions of
Complete Integrability”. Appl. Anal. Discr. Math. 2 (2008) 123-145
Translation from the original Russian article:
Universitetskiye Izvestiya Kiev No. 9 (1880) 1-25
[9] A. S. Fokas and M. J. Ablowitz: "On a unified approach to
transformations and elementary solutions of Painlevé equations"
J. Math. Phys. 23 (1982) 2033-2042
[10] E. L. Ince: "Ordinary Differential Equations". Dover 1956
[11] A. Ramani, B. Dorizzi and B. Grammaticos: "Painlevé conjecture
revisited". J. Math. Phys. 21 (1980) 715-721
21
[12] A. Ramani, B. Grammaticos and T. Bountis: "The Painleve Property and
Singularity Analysis of Integrable and Non-Integrable Systems".
Phys. Rep. 180 (1989) 159-245
[13] J. Weiss, M. Tabor and G. Carnevale: "The Painlevé property for partial
differential equations". J. Math. Phys. 24 (1983) 522-526
[14] J. Weiss: "The Painlevé property for partial differential equations. II:
Bäcklund transformation, Lax pairs, and the Schwarzian derivative"
J. Math. Phys. 24 (1983) 1405-1413
[15] J. Weiss: "On classes of integrable systems and the Painlevé property "
J. Math. Phys. 25 (1984) 13-24
[16] J. Weiss: "The Painlevé property and Bäcklund transformations for the
sequence of Boussinesq equations".
J. Math. Phys. 26 (1985) 258-269
[17] Y. Wenjum and Li Yezhou: "Rational Solutions of Painlevé Equations"
Canadian J. Math. 54 (2002) 648-670