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Solving Quadratics Equations. With Professor Owl Created by Robbie Smith. Solve by Graphing. Quadratic Term: ax² Linear Term: bx Constant Term: c. In order to have a solution, the line or parabola must touch the x-axis once or twice. If it doesn’t touch at all, there is no solution. - PowerPoint PPT Presentation
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SOLVING QUADRATICS EQUATIONS
With Professor OwlCreated by Robbie Smith
Solve by Graphing
Quadratic Term: ax²Linear Term: bxConstant Term: c
In order to have a solution, the line or
parabola must touch the x-axis once or twice. If it
doesn’t touch at all, there is no solution.
You must also find the vertex and axis
of symmetry
Solve by Graphing
To find the points, you can make a table!
X Y
-4 6
-3 5
-2 6
-1 9
0 14
Ex. x²+6x+14=y
Then graph the results.
This graph shows that there is no solution.
Vertex: (-3,5)Axis or Sym: -3Solution: None
Solve by Factoring
Remember: Most equations can be factored, but not all equations can be factored.
Here are some examples of factoring.
Ex. (x+5)(3x-2)=0X+5=0 3x-2=0 -5 -5 +2 +2X=-5 3x=2
3 3x=2 3
Unlike the last example which was already factored, you must factor
this one.Ex. 16x² -9=0
(4x+3)(4x-3)=04x+3=0 4x-3=0
-3 -3 +3 +34x=-3 4x=34 4 4 4X=-3 x=3 4 4
Solve by Factoring More Examples
Set the equation equal to zero
Ex. x²+16=8x -8x -8x x²-8x+16=0 (x-4)(x-4)=0
x-4=0 +4 +4
x=4
Write in Proper FormEx. 8x² -2=-2x +2x +2x
8x² -2=0x²-16=0
(8x+4)(8x-4) 8
(x+4)(8x-4)x=-4 x=1 2
Ex. 3x²+6x=0 3x(x+2)=0
x= 0 x= -2
Completing the Square
Examples of Perfect Squares
x²+4x+4 (x+2)(x+2)=(x+2)²x²-8+16 (x-4)(x-4)=(x-4)²x²+14x+49 (x+7)(x+7)=(x+7)²
To find the constant, do the following:Divide Linear by 2
Then square it.x²+4x+?
4/2=22²=4
x²+4x+4
Completing the Square
Examples
x²+4-10=0 +10 +10
x²+4x=104/2=2 2²=4
x²+4x+4=10+4(x+2)²=14
√(x+2)²=√14x+2=√14
x=-2+√14 x=-2-√14
3x²+6x-9=03 3 3 3x²+2x-3=0
x²+2x+1=3+1√(x+1)=√4
x+1=2x+1=-2
x=1x=-3
Solve by the Quadratic Formula When you get an equation, it looks like this:
ax²+bx+cWhen using the quadratic formula, use this
formula:x=-b±√b²-4ac
2a
Let’s see an example!
The Discriminant: b²-4ac (Very Important)
It tells you the numbers, root, and solutions. Sweet!
Solve by the Quadratic Formula
Discriminant:Negative-2 Imaginary SolutionsZero- 1 Real SolutionPositive-perfect Square- 2 Reals RationalPositive-Non-perfect square- 2 Reals Irrational
You must find the discriminant!
3x²+6x-9=06²-4(3)(-9)36+108=144144: Two Reals Rational
x=-6±122(3)
x=-6+12 6
x=-6-12 6
x=1 x=-3
And That’s It!