View
75
Download
0
Tags:
Embed Size (px)
Citation preview
1
SOIL MECHANICS SOIL MECHANICS
BASIC CONCEPTSBASIC CONCEPTS
1.1. PhysicalPhysical and index and index propertiesproperties of of soilssoils . . SoilSoil classificationsclassifications
2.2. Stresses in Stresses in soilssoils , , geostaticgeostatic stresses, stresses due to surface stresses, stresses due to surface loadsloads
3.3. Constitutive Constitutive lawslaws of of materialsmaterials
4.4. Water in Water in soilssoils
5.5. SoilSoil deformabilitydeformability and and soilsoil strengthstrength1.1. Consolidation and Consolidation and settlementsettlement of of soilssoils2.2. ShearShear strengthstrength . . BehaviourBehaviour of of sandysandy and and clayeyclayey soilssoils ..
Application to the case of the plane Application to the case of the plane failurefailure
SoilSoil mechanicsmechanics –– Basic conceptsBasic concepts
2
1.1. PhysicalPhysical and index and index propertiespropertiesof of soilssoils . .
SoilSoil classificationsclassifications
Physical properties of soils
• Definitions– Volumes
• V or Vt : Total volume of soil• Vs : Volume of solid grains• Vw : Volume of soil water • Va : Volume of soil air• Vv : Volume of voids (partly or totally filled with water)
– Weights• W ou Wt : Total weight of soil• Ws : Weight of solid grains• Ww : Weight of soil water• Wa : Weight of soil air (Wa = 0)
3
Schematic representation of soil, as a tree-phase med ium
Solid grains
air
water
WeightsVolumes
Wa = 0
Ww
Ws
Va
Vw
Vs
Phase diagram illustration of a soil that exhibits a total volume V and total weight WV = Vs + Vw + Va ; W = Ws + Ww + Wa
• Unit weights– Unit weight of grains: γs = Ws / Vs
– Unit weight of water: γw = Ww / Vw
– Unit weight of natural soil: γ = W / V– Unit weight of dry soil: γd = Ws / V– Unit weight of saturated soil: γsat = Wsat / Vsat
• Void ratio, porosity– Void ratio: e = Vv / Vs
– Relative density: Dr = (emax – e)/(emax – emin)– Porosity: n = Vv / Vt
– Effective porosity of saturated soil: ne = Vfree water / Vt
• Water content, saturation degree– Water content: w = Ww / Ws
– Water content of saturated soil: wsat = γw . Vv / Ws
– Saturation degree: S = Vw / Vv
4
Relationships between physical parameters
Solid grains
air
water
WeightsVolumes
Wa = 0
Ww = w. γs
Ws = γs
Va = (1 – S).e
Vw = S.e
Vs = 1
Vv = e
Phase diagram illustration with the hypothesis of Vs = 1 that allowseasily establishing relationships between physical parameters
Relationships between parameters(γs et γw being given)
� n = e / (1 + e)
� e = n / (1 - n)� γd = γs / (1 + e) = γs . (1 – n) � γ = γs . (1 + w) / (1 + e)
� w . γs = γw . S . e In case of a saturated soil, then: e ~ 2.7 . w
• Dry soil (w = 0, S = 0): one parameter among (γ = γd, γsat, e, n) is used to calculate the other parameters;
• Saturated soil (S = 1): one parameter among (γd, γ = γsat, e, n, w) is used to calculate the other parameters;
• Unsaturated soil: two independant parameters among (γd, γsat, e, n) and (γ, w, S) are used to calculate the other parameters.
5
Minerals and unit weights (kN.m -3)
23.0Attapulgite
27.5 – 27.8Montmorillonite
26.0 – 28.6Illite
25.5Halloysite (2H 2O)
25.5Kaolinite
26.2 – 26.6Serpentine
28.4Pyrophyllite
26.0 – 29.0Chlorite
28.0 – 32.0Biotite
27.0 – 31.0Muscovite
28.5Dolomite
27.2Calcite
26.2 – 27.6Na-Ca-Feldspath
25.4 – 25.7K-Feldspath
26.5Quartz
23.714.612460.140.85Silty sand and gravel
19.312.329550.401.20Micaceoussand
22.513.917490.200.95Fine to coarsesand
20.814.223470.300.90Silty sand
19.312.929520.401,10Uniform inorganic silt
19.313.529500.401.00Uniform clean sand
18.015.033440.500.80Ottawa standard sand
20.014.12647.60.350.92Uniform spheres
γdmaxγdminnminnmaxeminemax
Dry unit weightsPorosityVoid ratioDescription
Void ratios, porosities and dry unit weights of soils
7
Cranularity – Granulometry – sedimentometryGrain size distribution curves
• Definition : Granularity is given by the distribution of grain weights as a function of size (width or equivalent diameter)
• Granulometry uses a sieve column for particle sizes more than 40µm or 80µm.
• Sedimentometry uses an hydrometer or a sedimentometer for particle sizes less than< 40µm or 80µm.
Granulometric curve
% in
wei
ghto
f tot
al s
oil
Particle diameters decreasing (logarithmic scale)
100%
0%
50%
(100 – y)% = retained on D y diameter sieve
y% = passing through the D y diameter sieve
y%
Dy
8
% in
wei
ghto
f tot
al s
oil
Particle diameters decreasing (logarithmic scale)
100%
0%
50%
y%
Dy
y’%
Dy’
This soil contains (y – y’) % in weight of total soil,made up of particles with diameters between Dy and Dy’ .
Well sorted soils or poorly graded soils
% in
wei
ghto
f tot
al s
oil
Particle diameters decreasing (logarithmic scale)
100%
0%
50%
y%
Dy
y’%
Dy’
This soil is well sorted or poorly graded. The grain size distribution curve is uniform.
This may be a sediment that has undergone a grain sorting:
� in the marine environment�Example: Fontainebleau sand, with Dy’ = 100µm and Dy = 300µm
� in the continental environment�Example: aeolian silt or loess, with Dy’ = 10µm and Dy = 50µm
9
Poorly sorted soils or well graded soils%
in w
eigh
tof t
otal
soi
l
Particle diameters decreasing (logarithmic scale)
100%
0%
y%
Dy
y’%
Dy’
This soil is poorly sorted or well graded. The soil exhibits a large range of particle diameters.
This may be a sediment that has undergone gravitational or fluvial transport, such as mountain screes or alluvial sands and gravels.
� Example: Screes, with Dy’ = 1mm and Dy = 50cm
� Example: Alluvium, with Dy’ = 100µm and Dy = 10cm
10
Granulometric indices
Fractiles: D25, D75, D50 = median value
Deciles: D10, D90
Uniformity coefficient: Cu = D60/D10Example: Cu<2: well sorted sands, uniform grain size curve
Sorting coefficient: S0 = D75/D25Example: S0<2.5: well sorted sediment (marine or aeolian sediment)
S0>4.5: poorly sorted sediment (gravitational, torrential, glacial sediment)
Coefficient of curvature: Cc = D302/(D60.D10)
Some of these indices are used for soil classifications
11
Sol 1: Gb, grave propre bien graduée, Cu = 30, Cc = 1,15Sol 2: Gm, grave propre mal graduée, Cu = 50, Cc = 0,25Sol 3: GL, grave limoneuse, WL = 45%, IP = 12%Sol 4: GA, grave argileuse, WL = 70%, IP = 40%
Sol 5: Sb, sable propre bien gradué, Cu=7,2, Cc= 1,14Sol 6: Sm, Sable propre mal gradué, Cu=2, Cc=1,0Sol 7: SL: sable limoneux, WL = 55%, IP = 22%Sol 8: SA, sable argileux, WL = 66%, IP = 37%
Soil 1: GW, clean well graded gravels, Cu = 30, Cc = 1,15Soil 2: GP, clean poorly graded gravels, Cu = 50, Cc = 0,25Soil 3: GM, silty gravels, WL = 45%, IP = 12%Soil 4: GC, clayey gravels, WL = 70%, IP = 40%
Soil 5: SW, clean well graded sands, Cu=7,2, Cc= 1,14Soil 6: SP, clean poorly graded sands, Cu=2, Cc=1,0Soil 7: SM: silty sands, WL = 55%, IP = 22%Soil 8: SC, clayey sands, WL = 66%, IP = 37%
13
Caracterization of fine particles
Fine particles (<2µm) exhibit surface properties when in contact with water.These properties are named « activity » and can be described as cohesion, plasticity, shrinkage, swelling.
These properties result from:� the small size of clayey particles (<2µm, such as kaolinite, illite, smectite) and the corresponding
high external specific surface;� the crystal structure of phyllosilicates and the corresponding high internal specific structure,
especially for smectite, sepiolite, attapulgite;� the adsorption complex of clayey minerals with a general deficit of electric charges
and the possibility to adsorb dipolar water molecules and cations.
Kaolinite
Smectite7.2 Å
15 Å
General scheme of crystal structures of clayey mineral s
14
Activity of fine soils – Atterberg limits
Measurement of Liquid limit,using the Casagrande apparatus
15
Atterberg limits and indices
• Plasticity index: I P = wL - wP• 0 < IP < 5 Non-plastic soil• 5 < IP < 15 Moderately plastic soil• 15 < IP < 40 Plastic soil• IP > 40 Very plastic soil
• Consistency index: I c = (wL – w) / IP• Ic < 0 Soil with liquid consistence• 0 < Ic < 0,25 Soil with pasty or very soft consistence• 0,25 < Ic< 0,50 Soil with soft consistence• 0,50 < Ic< 0,75 Soil with firm consistence• 0,75 < Ic< 1 Soil with very firm consistence• Ic > 1 Soil with stiff consistence
• Skempton or activity index: A = I P / (%< 2µm)• A < 0,50 Soil with very low activity• 0,50 < A < 0,75 Soil with low activity• 0,75 < A < 1,25 Soil with medium activity• 1,25 < A < 2 Soil with high activity• A > 2 Soil with very high activity
Casagrande plasticity chart
A line
16
7.6120150270HAttapulgite
29.2223759Fe
28.7233154Mg
24.5112738Ca
25.3202949K
26.8213253NaKaolinite
15.36149110Fe
14.7494695Mg
16.85545100Ca
17.56060120K
15.46753120NaIllite
10.321575290Fe
14.735060410Mg
10.542981510Ca
9.356298660K
9.965654710NaMontmorillonite
ShrinkageLimit (%)
PlasticityIndex (%)
PlasticityLimit (%)
Liquid Limit(%)
Exchangeablecations
Mineral
Clayey minerals and Atterberg limits
17
N°200 sieve: 0.075 mmN°4 sieve: 4.75 mm
G: gravel, S: sand, M: silt, C: clay,O: organic soil, PT: peat, highly organic soilW: well graded, P: poorly gradedL: low plasticity, H: high plasticity
Soil classification
18
G: gravel, S: sand, M: silt, C: clay,O: organic soil, PT: peat, highly organic soilW: well graded, P: poorly gradedL: low plasticity, H: high plasticity
Engineering use chart
19
Approximate classification of cohesive soils and rocks
2. Stresses in 2. Stresses in soilssoils ,,
GeostaticGeostatic stresses,stresses,
Stresses due to surface Stresses due to surface loadsloads ,,
StrainsStrains in in soilssoils
25
Stress calculation for an hydrostatic situation
Geostatic stresses
Stresses in normally consolidated sediment. �, �e and u are respectively the total stress, effective stress and pore water pressure.
γb is the bulk unit weight.
26
Pore water pressure forces acting on a submerged cylinder
Stresses due to surface loads
Stresses on elements due to concentrated load Q.(a) Rectangular coordinate notation. (b) Polar coordinate notation
27
Induced loads
Boussinesq Formula
Distribution of vertical stresses �z induced by point load Q. Dashed lines represent the �z distribution for various �z values at depth z.
Solid lines connect points of equal stress.
Bulbs of induced stresses
28
Example of approximate �z avg calculation on plane at depth z, using a simplified model
Geostatic stresses,stress increments,Stress path
30
3. Constitutive 3. Constitutive lawslaws of of materialsmaterials
Three fundamentalmechanical specific test:
�Loading test,
�Creep test,
�Stress relaxation test.
31
Perfectly elastic solid
Isotropic linear elasticity 1/2
h
∆h
S = π.r2
F
�1 = F/S �2 = �3 = 0
ε1 = ∆h/h ε2 = ε3 = ∆r/r
33
Perfectly plastic solid and elasto-plastic solid
Elasto-plastic solid with hardening
ε
�
�1
�2
�3Failure
Plasticity thresholds
34
Examples of mechanical models of materials with different rheology:(a): ideal plastic (�0 = strength); (b): Bingham visco-plastic body;(c): Maxwell visco-elastic body; (d): Kelvin visco-elastic body
Examples of stress-strain diagramsfor different mechanical behaviours
Stress-strain diagram for an ideal plastic body
Stress plotted against rate of strain for a Bingham plastic body
35
Examples of strain-time diagramsfor different mechanical behaviours
Strain-time diagram for a Maxwell bodywhen the applied stress is held constant
Strain-time diagram for a Kelvin bodywhen the applied stress is held constant
Common types of stress-strain tests in laboratory
41
Seepage apparatus and test resultsillustrating Darcy’s law
Diagram of a typical setup for the field permeability test(after J.N. Cernica, 1995)
42
Example of calculation of the critical gradient
i = [(h + L + Z) – (L + Z)] / L = h/L
�’/L = γb – γw.h/L = γb – i.γw
�’ = 0 ↔ i = γb / γw
Example of pore water pressure calculation for an hydrodynamic case
44
Different top flow lines for various earth dam cross sections
5. 5. SoilSoil deformabilitydeformability and and soilsoilstrengthstrength
5.1 Consolidation and 5.1 Consolidation and settlementsettlement of of soilssoils
46
Unidimensional model of consolidation
0,1,2: the cell contains air = dry soil
3, 4: the cell contains water = saturated soil
1, 2, 3, 4, 5: the force F is applied
2, 4: the upper tap is open
5: the lower tap is open
(0)
Settlement curves:settlement w as a function of time t
Corresponding components used in the mechanical analogy model
47
Consolidation curve, for a given load �
The consolidation curve represents the void ratio as a function of timewhen a given load � is applied on the sample in the oedometer.
It allows to determine the amount of settlement for a given load �and the coefficient of consolidation Cv that accounts for the consolidation velocity
Oedometric curve
The oedometric curve results from the compilation of n (6 or 8) consolidation curves.
It allows to determine: the preconsolidation pressure Pc or �’c
and the compression index Cc.
48
Example of consolidation curves (arithmetic scale for time)
Determination of the theoretical 100% consolidation,the primary time effect and the secondary time effect
49
Determination of the coefficient Cα that accounts for the secondary compression
Schematic representation of the three usual components of settlement:1: immediate settlement
(different in the oedometer by comparaison to field conditions);2: primary consolidation (or Terzaghi consolidation);3: secondary compression (or secondary consolidation).
50
Example of experimental oedometric curves (pressure – void ratio curves)of an undisturbed precompressed clay soil.
(a): arithmetic scale; (b): logarithmic scale
Practical conditions for settlement calculations, usin g the oedometric curve
The amount of settlement
51
Principal causes of differential compaction or differential settlement
A: Difference in original thickness;
B: Difference in compactibility of mixed lithologies;
C: Differential compaction rates, in this caseproduced by a well, or well fieldlocated at the center of the illustration.
Original configuration is at left in each illustration, compacted configuration at right.
Compaction is to scale, with sand compacting from original porosity of 40 percent to a final 20 percent,clay from 80 percent to 20 percent.
C was assumed to be be precompacted, with initial sand porosity of 25 percent,initial clay porosity of 50 percent and final porosities as above.
52
Consolidation: Evolution of excess pore water pressures within a clayey layeras a function of time.Case of a compressible layer intercalated between two permeable layers
Consolidation ratio as a function of depth and time
The time dependent settlement
Average consolidation ratio: linear initial excess pore water pressure.(a) Graphical interpretation of average consolidation ratio U;(b) U versus T: time factor, U = F(T) = F(Tv) T = Tv = Cv t / H2
53
Average percent consolidation versus time factor U = F(T)
5. 5. SoilSoil deformabilitydeformability and and soilsoilstrengthstrength
5.2 5.2 ShearShear strengthstrength . . BehaviourBehaviour of of sandysandy and and clayeyclayey soilssoils ..
Application to the case of the plane Application to the case of the plane failurefailure
54
a) Ideal elasto-plastic materialb) Elasto-plastic material
Loose sand;Normally consolidated clay.
a) Elasto-plastic material with work softeningDense sand;Overconsolidated clay.
Examples of some elasto-plastic behaviours
56
Unconfined compression testDefinition of cohesion C and internal friction angle φ
Envelope or intrinsic curve at failure
58
Shearing of a loose sand,with negative dilatancy or contractancy
Shearing of a dense sand,with positive dilatancy
Results of direct shear test on claysPeak shear strength and residual shear strength
59
Triaxial test – CD test
CD test1) Consolidated while �3 is applied2) Drained while (�1 - �3) is increasing until failure
Triaxial test – UU test
UU test1) Uconsolidated while �3 is applied2) Undrained while (�1 - �3) is increasing until failure