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Slender Wall Behavior & Modeling
John WallaceUniversity of California, Los Angeles
with contributions fromDr. Kutay OrakcalUniversity of California, Los Angeles
2
Presentation OverviewFEMA 356 Requirements
! General requirements! Modeling approaches
" Beam-column, fiber, general
! Stiffness, strength
Experimental Results! Model Assessment
" Rectangular, T-shaped cross sections
! FEMA backbone relations" Flexure dominant walls
3
FEMA 356 –Nonlinear Modeling for Buildings with Slender RC Walls
4
FEMA 356 – RC WallsGeneral Considerations – 6.8.2.1! Represent stiffness, strength, and
deformation capacity! Model all potential failure modes anywhere
along the wall (member) height! Interaction with other structural and
nonstructural elements shall be considered
! So, we must consider any and everything
5
Wall Modeling ApproachesEquivalent beam-column model ! hw/lw ! 3Modified equivalent beam-column! Rectangular walls (hw/lw " 2.5)! Flanged walls (hw/lw " 3.5)
Multiple-line-element and Fiber models! Concrete and rebar material models
General wall model
6
Equivalent Beam-Column Modelhw/lw ! 3:! Use of equivalent beam-
column permitted! Neutral axis migration not
considered! Interaction with in- and out-
of-plane elements not properly considered
! Axial load Impacts" Stiffness (EI)" Strength (P-M)
! L- or T-shaped walls" Where to locate the
element? " Elastic centroid?
3112
column w w
column cracking w w
A t l
I t l#
$
% &$ ' () *
Beams
Wall
Rigid end zones for beam
Column at wall centroid
Hinges
7
Modified Beam - Column ModelRectangular walls (hw/lw " 2.5)& Flanged walls (hw/lw " 3.5):
Use of modified beam-column elementwith added shear spring
Nonlinear flexure/shearare uncoupled using thisapproach
Beams
Wall
Shear spring
Column at wall centroid
Hinges
8
Modified Beam - Column ModelShear force – deformation properties
A
B
C
D
E
+/h
V Vn
1.0
0.2
CPLSIO
Deformation-controlled componenta b - a
c
, -
0.4
1 and 0.21 2
yy
c c
c c
Vh
G E A
G E ..
/ 0+ $ 1 21 2$3 4
/ 0$ 51 263 4
+y/h
9
Fiber Section Model
! Typically use a more refined mesh where yielding is anticipated;however,
! Nonlinear strains tend to concentrate in a single element, thus, typically use an element length that is approximately equal to the plastic hinge length (e.g., 0.5lw). Might need to calibrate them first (this is essential).
! Calibration of fiber model with test results, or at least a plastic hinge model, is needed to impose a “reality” check on the element size and integration points used.
Actual cross section
Concrete Fibers
Steel Fibers
10
MaterialsUnconfined Concrete
Maximum permissible compressive strain for unconfined concrete (FEMA 356 S6.4.3.1)
7 = 0.002 or 0.005
Limit state associated with crack
width
Str
ess
(ksi
)
Strain
, - , -
2' '
0 0
' '0 85
2
Linear descending branch defined by:
0.002; and 0.0038; 0.85
c cc c c
c c c
f f f
f f
7 77 7
7 7
% &/ 0' ($ 8 91 2' (3 4) *
$ $
In the absence of cylinder stress-strain tests, Saatcioglu & Razvi (ASCE, JSE, 1992) recommend relation based on work by Hognestad.
11
Materials
Confined Concrete (FEMA 356 6.4.3.1)! Use appropriate model, e.g.:
" Saatcioglu & Razvi (ASCE JSE, 1992, 1995)"Mander (ASCE JSE, 1988)"Modified Kent & Park (ASCE JSE, 1982)
! For reference
! FEMA 356 Qualifications: "Maximum usable compression strain based on
experimental evidence and consider limitations posed by hoop fracture and longitudinal bar buckling.
12
MaterialsSteel Material:
Str
ess
(ksi
)
Strain
Maximum usable strain limits perFEMA 356 S6.4.3.1
7 = 0.02 7 = 0.05
13
General Wall Models/FE Modelse.g., RAM-PERFORM:! Flexure - fiber model (2-directions)! Shear - Trilinear backbone relation! Flexibility to model complex wall
geometry! Mesh refinement issues
Flexure/Axial Shear
Concentration of nonlinear Deformations in one element
14
Stiffness ModelingFEMA 356 Section 6.8.2.2 – Use Table 6.5! Uncracked: EIeffective = 0.8EIg
! Cracked: EIeffective = 0.5EIg
30 x 2 ft Wall Section16 - #14 Boundary#6@12" Web
CURVATURE
MO
MEN
T
P=0.30Agf'cP=0.20Agf'cP=0.10Agf'c1.0, 0.75, 0.5, 0.4EcIg
0.75EcIg 0.5EcIg
Wallace, et al., 4NCEE, Vol. 2, pp 359-368, 1990.
15
Response Correlation Studies! Ten Story Building in San Jose, California! Instrumented: Base, 6th Floor, and Roof! Moderate Intensity Ground Motions – Loma Prieta
4.53 m (14.88 ft)
1.68 m(5.5 ft)
PLAN VIEW: CSMIP BUILDING 57356
8.84 m (29 ft)
8.84 m (29 ft)
5 @ 10.97 m (36 ft)
16
Response Correlation Studies! Ten Story Building in San Jose, California! Instrumented: Base, 6th Floor, and Roof! Moderate Intensity Ground Motions – Loma Prieta
0 10 20 30Time (sec)
-1.5
0
1.5
Dis
plac
emen
t (in
.)
Analysis - 0.5Ig
Measured
17
Strength RequirementsACI 318 Provisions! Pn- Mn
" For extreme fiber compression strain of 7c =0.003.
! Vn" ACI 318-99,02,05 Equation 21-7
'
3.0 for / 1.52.0 for / 2.0
n cv c c t y
c w w
c w w
V A f f
h lh l
# :
##
% &$ 6) *$ "$ !
Linear interpolationallowed for intermediatevalues
18
Definition of Wall Cross Section
Flexural strength! Consider all vertical reinforcement within web
and within the effective flange width
Consider the influence of openings on the strength and detailing requirements ! ACI 318-02, 05 Appendix A – Strut & Tie Approach
Cross-Section Definition
beff
0.25hw
' ', ,
', ,
s bound s flange s
s bound s flange s
A A A
A A A
6
6
19
Behavior of Flanged WallsFlange Compression versus Tension
7t
7c
sAbeff
Flange CompressionLow compressive strainLarge curvature capacityMn & Vu similar rectangle
beff
Flange TensionLarge compressive strainLess curvature capacityMn ; Vu ;
7t
7c
, ,s bound s flangeA A6
20
Experimental ResultsRW2 & TW1: ~ ¼ scale tests
Thomsen & Wallace, ASCE JSE, April 2004.
Uncoupled designDisplacement-based design
21
Experimental Results
P = 0.09Agf'cvu,max = 4.85<f'c
-4.0 -2.0 0.0 2.0 4.0Top Displacement (in.)
-80
-40
0
40
80
Lat
eral
Loa
d (k
ips)
-2.8 -1.4 0.0 1.4 2.8Lateral Drift (%)
TW1RW2
P = 0.07Agf'cvu,max = 2.32<f'c
Abrupt Lateral Strength lossDue to buckling; Axial load Maintained
RW2
TW1
22
Experimental ResultsRW2 & TW2: ~ ¼ scale tests
Thomsen & Wallace, ASCE JSE, April 2004.
Displacement-based design of T-shape
23
Experimental Results
P = 0.075Agf'cvu,max = 5.5<f'c
-4.0 -2.0 0.0 2.0 4.0Top Displacement (in.)
-80
-40
0
40
80
Lat
eral
Loa
d (k
ips)
-2.8 -1.4 0.0 1.4 2.8Lateral Drift (%)
TW2RW2
P = 0.07Agf'cvu,max = 2.32<f'c
TW2
RW2Lateral strength loss due to lateralInstability due to spalling; Axial load maintained
24
Model Assessment –Comparison of Analytical and Experimental results
25
MVLE (Fiber) Model
h
(1-c)h
ch
12
3
45
6 Rigid Beam
Rigid Beam
k 1 k 2 knkH. . . . . . .
m
RC WALL WALL MODEL
1
2
. . . . .
Basic assumptions: • Plane sections (rigid rotation of top/bottom beams• Uniaxial material relations (vertical spring elements)
MVLE Model versus Fiber Model:• Similar to a fiber model except with constant curvature
over the element height (vs linear for fiber model)
Orakcal, Wallace, Conte; ACI SJ, Sept-Oct 2004.
26
Strain, 7
O
TensionNot to scale
Compression
( =7c ' , = f c
' )
(70, 0)
(70+ 7t , ft)
Material (Uni-axial) Models
Strain, 7
7y
E0
E1= bE0>y
OR
Concrete :• Chang and Mander (1994)
# Generalized (can be updated)# Allows refined calibration# Gap and tension stiffening
Reinforcing Steel :• Menegotto and Pinto (1973)• Filippou et al. (1984)
# Simple but effective# Degradation of
cyclic curvature
r
Stre
ss, >
27
Model Assessment$ Approximately 1/4 scale$ Aspect ratio = 3$ Displacement – based
evaluation for detailing provided at the wall boundaries
$ 12 ft tall, 4 ft long, 4 inches thick
$ #3 vertical steel, 3/16” hoops/ties
$ #2 deformed web steel$ Constant axial load$ Cyclic lateral
displacements applied at the top of the walls
28
Instrumentation
Wire Potentiometers(horizontal displacement)
Wire Potentiometers (X configuration)
Steel Strain Gage Levels
Wire Potentiometers(vertical displacement)
LVDT's
Concrete Strain Gages
Linear Potentiometers (Pedestal Movement)
Rigid Reference Frame
RW2
• Extensive instrumentation provided to measure wall response at various locations
Massone & Wallace; ACI SJ, Jan-Feb 2004.
29
Applied Lateral Displacement
-80
-40
0
40
80
-2
-1
0
1
2RW2
0 100 200 300 400 500 600 700 800Data Point Number
-80
-40
0
40
80
Top
Dis
plac
emen
t (m
m)
-2
-1
0
1
2
Drif
t Rat
io (%
)
Applied displacementPedestal movement excludedPedestal movement and shear deformations excluded
TW2
30
Model Details – RW2 1219 mm
19 mm 19 mm3 @ 51 mm 153 mm 3 @ 191 mm 153 mm 3 @ 51 mm
64 mm
19 mm
19 mm
102 mm
#2 bars (db=6.35 mm) Hoops (db=4.76 mm)8 - #3 bars
1 2 3 4 5 6 7 8uniaxial element # :
(db=9.53 mm) @ 191 mm @ 76 mm
m=16
1
2
. . . . .h
(1-c)h
ch
k 1 k2 knkH . . . . . . .
31
Model Details – TW2
19 mm 19 mm
3 @ 51 mm153 mm 3 @ 191 mm 153 mm
3 @ 51 mm
64 mm
19 mm
19 mm
1219 mm
3 @ 140 mm
102 mm
4 @ 102 mm
19 mm
102 mm
19 mm
3 @ 51 mm
102 mm
1219 mm
uniaxial element # : 1
2
345
6
7
8
9
10
12-19
118 - #3 bars(db=9.53 mm)
#2 bars (db=6.35 mm) @ 191 mm
Hoops (db=4.76 mm)@ 76 mm
#2 bars (db=6.35 mm) @ 140 mm
2 - #2 bars (db=6.35 mm)
Hoops and cross-ties (db=4.76 mm)@ 38 mm
8 - #3 bars(db=9.53 mm)
Hoops (db=4.76 mm)@ 32 mm
+
-
32
Concrete Model - Unconfined
0 0.001 0.002 0.003 0.004
Strain
0
10
20
30
40
50
Stre
ss (M
Pa)
Test Results1st Story2nd Story3rd Story4th Story
Analytical (Unconfined)
33
Concrete Model - Confined
0 0.005 0.01 0.015 0.02 0.025
Strain
0
10
20
30
40
50
60
70
Stre
ss (M
Pa)
Unconfined ModelMander et al. (1988)Saatcioglu and Razvi (1992)
RW2
TW2 Flange
TW2 Web
34
Concrete Model - Tension
0 0.0005 0.001 0.0015 0.002 0.0025
Strain
0
0.5
1
1.5
2
2.5
Stre
ss (M
Pa)
Chang and Mander (1994)Belarbi and Hsu (1994)
0 0.005 0.01 0.015 0.02 0.025 0.03
0
0.5
1
1.5
2
2.5(7t ,ft )
r
35
Reinforcement Material Model
-0.03 -0.02 -0.01 0 0.01 0.02 0.03
Strain
-600-500-400-300-200-100
0100200300400500600
Stre
ss (M
Pa)
#3 (RW2 & TW2 Flange)#3 (TW2 Web)#2 (TW2 Web)#2 (RW2 & TW2 Flange)
#3#2
0 0.02 0.04 0.06 0.08 0.1
0100200300400500600700
#3 rebar#2 rebar4.76 mm wire
Tension
Compression Test Results
36
Model Assessment – RW2
-80 -60 -40 -20 0 20 40 60 80
Top Flexural Displacement, +top (mm)
-200
-150
-100
-50
0
50
100
150
200
Late
ral L
oad,
Pla
t (k
N)
-2 -1.5 -1 -0.5 0 0.5 1 1.5 2
Lateral Flexural Drift (%)
TestAnalysis
5Pax 0.07Ag=f c'
Plat , +top
0100200300400500
P ax
(kN
)
RW2
37
Model Assessment – RW2
-80 -60 -40 -20 0 20 40 60 80
Lateral Flexural Displacement (mm)
0
1
2
3
4
5
Stor
y N
umbe
r
-2 -1.5 -1 -0.5 0 0.5 1 1.5 2
Lateral Flexural Drift (%)
TestAnalysis
1.5%2.0%2.5%
0.75%1.0 %
RW2
Applied LateralDrift Levels:
Top
38
Model Assessment – RW2
-0.01
0
0.01
0.02
Rot
atio
n
( r
ad)
0 100 200 300 400 500 600 700-15-10
-505
1015
Dis
plac
emen
t
(
mm
)
TestAnalysis
RW2 (First Story)
Results based on recommended values for material parameters; however, results could vary, maybe significantly, for different element lengths and material parameters (particularly if no strain hardening)
1.5%2.0%
Data Point
0.008 FEMA 356 CP limit
39
Model Assessment – RW2
RW2Boundary Zone
100 150 200 250 300 350 400 450 500 550 600
Data Point
-0.01
-0.005
0
0.005
0.01
0.015
0.02
0.025
0.03
0.035
Con
cret
e St
rain
Concrete Strain GageLVDTAnalysis
0.25% 0.5%0.75%
1.0%
1.5%
1.0%
2.0%
1.5%
Orakcal & Wallace; ACI SJ, in-press for publication in 2006 (see 13WCEE).
40
Model Assessment – RW2
RW2Boundary Zone
100 150 200 250 300 350 400 450 500 550 600
Data Point
-0.01
-0.005
0
0.005
0.01
0.015
0.02
0.025
0.03
0.035
Con
cret
e St
rain
Concrete Strain GageLVDTAnalysis
0.25% 0.5%0.75%
1.0%
1.5%
1.0%
2.0%
1.5%
Orakcal & Wallace; ACI SJ, in-press for publication in 2006 (see 13WCEE).
41
Model Assessment – TW2
-80 -60 -40 -20 0 20 40 60 80
Top Flexural Displacement, +top (mm)
-400
-300
-200
-100
0
100
200
300
400
Late
ral L
oad,
Pla
t (k
N)
-2 -1.5 -1 -0.5 0 0.5 1 1.5 2
Lateral Flexural Drift (%)
TestAnalysis
5Pax 0.075Ag=f c'
Plat , +top
0250500750
P ax
(kN
)
TW2
C
T
T
C
42
Model Assessment – TW2
-80 -60 -40 -20 0 20 40 60 80
Lateral Flexural Displacement (mm)
0
1
2
3
4
5
Stor
y N
umbe
r
-2 -1.5 -1 -0.5 0 0.5 1 1.5 2
Lateral Flexural Drift (%)
TestAnalysis
1.5%2.0%2.5%
0.75%1.0 %
TW2
Applied LateralDrift Levels:
Top
C
T
T
C
43
Model Assessment – TW2
-600 -400 -200 0 200 400 600
Distance along Flange from Web (mm)
-0.005
0
0.005
0.01
0.015
0.02
0.025
Flan
ge C
oncr
ete
Stra
in (
LVD
Ts)
TestAnalysis
0.5%1.0%2.0%2.5%
TW2
C
T
T
C
y7
2.0%
2.5%
2.5%
2.0%
44
Model Assessment – Stability
P = 0.09Agf'cvu,max = 4.85<f'c
-4.0 -2.0 0.0 2.0 4.0Top Displacement (in.)
-80
-40
0
40
80
Lat
eral
Loa
d (k
ips)
-2.8 -1.4 0.0 1.4 2.8Lateral Drift (%)
TW1TW2
P = 0.075Agf'cvu,max = 5.5<f'c
TW1 – Abrupt failure due to bucklingTW2 – Lateral instability due to spalling
and large compression
45
Model Assessment - Stability
Rebar Buckling at Wall Boundary Rebar Fracture Following Buckling at Wall Boundary
Instabilities, such as rebar buckling and lateral web buckling, and rebar fractureare typically not considered in models; therefore, engineering judgment is required. Loss of lateral-load capacity does not necessarily mean loss of axial load capacity
46
FEMA 356 Table 6-18
47
FEMA 356 Table 6-18
48
FEMA 356 – Modeling Parameters
' '
2
's
& 0.07 & Hoops @ 2" o.c.
2(0.027 in ) 0.09( )( 6" 3/ 8" 3 /16")(5 ksi / 63 ksi) 1.2" Non-confo
WALL RW2:
WALL TW2: Flange Compre
rming
8 - #3
ssio
A 10 - #
n
s s g c
c
s
A A P A f
s hs
A
$ $
$ $ 6 69
$ $
, - , -' 2
'
'
3 and 4 - #2 63 ksi & Hoops/Ties @ s=4"
No special detailing required: Conforming
0.42 in 63 ksi0.075(2) 0.127
4"(48")( 6 ksi)40 kips 2.7
4"(48") 6000 /1000
y
s s y
w w c
u
w w c
f
A A f Pt l f
Vt l f
5
% &8 6 8) *$ 6 $
$ $
!
49
FEMA 356 – Modeling Parameters
's
2
8 - #3 & 2 - #2 A 24 - #3 and 8 - #2 & 63 ksi
Hoops/Ties @ s=1.25" (5 legs and 2 legs)5(0.027 in ) 0.09( )( 16" 3/
WALL TW2: Flange
8" 3/16")(6 ksi / 63 ksi) 1.
Tension
"
(
0
2 0
s y
c
A f
s h s
$ $ 5
$ $ 6 6 9
, - ? @, -
2
'
'
'
.027 in ) 0.09( )( 2.5" 3/ 8" 3/16")(6 ksi / 63 ksi) 2.1" Conforming
16(0.11) 6(0.049) 63 ksi0.075(2) 0.26
4"(48")( 6 ksi)80 kips 5.4
4"(48") 6000 /1000
c
s s y
w w c
u
w w c
s h s
A A f Pt l f
Vt l f
$ $ 6 6 9
8 6 6$ 6 $
$ $
!
!
50
FEMA 356 – Modeling Parameters
Tables 6-18 (partial):
Model Parameters, Radians Walls Controlled by Flexure
'
')(
cww
yss
fltPfAA 68
Conf.
Bound. 'cww flt
V Plastic Hinge
a
Plastic Hinge
b
Residual Strength
c
" 0.1 Yes " 3 0.015 0.02 0.75
" 0.1 No " 3 0.008 0.015 0.60 ! 0.25 Yes ! 6 0.005 0.010 0.30
! 0.25 No ! 6 0.002 0.004 0.20
RW2TW2Flange Tension
TW2Flange Comp
51
FEMA Backbone Relation – RW2
, -, -
4
3
y
3
29.4 kips
3 0.5
29.4 (150") 0.41"3(4000 )(18,432 )0.008(144") 1.15"0.015(144") 2.16"
0.6(29.4 ) 17.6 kips
nlateral
w
lateral load
c g
k
ksi in
a
bk
residual
MPh
P h
E I
P
A
AA
$ $
% &' ($' () *
$ $
$ $$ $
$ $
52
FEMA Backbone Relations – TW2
, -, -
, -
4
3
y
3
4 48
40.2 kips
3 0.5
40.2 (150")3(4400 )(40,700 )0.25"
2.2 =34.5"
0.015(144") 2.16"0.020(144") 2.88"
0.75(40.2 ) 30.2 kips
nlateral
w
lateral load
c g
k
ksi in
g g x
a
bk
residual
MPh
P h
E I
I I y
P
A
AA
$ $
% &' ($' () *
$
$
$
$ $$ $
$ $
, -, -
, -
4
3
y
3
4 48
77.0 kips
3 0.5
77.0 (150")3(4400 )(40,700 )0.48"
2.2 =34.5"
0.005(144") 0.72"0.010(144") 1.44"
0.30(77.0 ) 23.1 kips
nlateral
w
lateral load
c g
k
ksi in
g g x
a
bk
residual
MPh
P h
E I
I I y
P
A
AA
$ $
% &' ($' () *
$
$
$
$ $$ $
$ $
Flange Compression Flange Tension
53
Backbone Curve – RW2
, -, -3/3n w w
yc cr
M h hE I
A $
P = 0.07Agf'cvu,max = 2.2<f'c psi
-4.0 -2.0 0.0 2.0 4.0Top Displacement (in.)
-40
-20
0
20
40
Late
ral L
oad
(kip
s)-2.8 -1.4 0.0 1.4 2.8
Lateral Drift (%)
Plat@Mn(7c=0.003)=29.4k-100
0
100
Late
ral L
oad
(kN
)
FEMA 356 NC/C
NC C
54
Backbone Curve – TW2
, -, -3/3n w w
yc cr
M h hE I
A $
P = 0.075Agf'c
-4.0 -2.0 0.0 2.0 4.0Top Displacement (in.)
-120
-80
-40
0
40
80
Late
ral L
oad
(kip
s)
-2.8 -1.4 0.0 1.4 2.8Lateral Drift (%)
Plat@Mn(7c=0.003)=77.0k
Plat@Mn(7c=0.003)=40.2k
-400
-200
0
200
Late
ral L
oad
(kN
)
FEMA 356 Conformingvu,max = 5.4<f'c psi
vu,max = 2.7<f'c psi
55
Cantilever Wall TestsPaulay, EERI, 2(4), 1986 [Goodsir, PhD 1985 NZ]
h = 3.3 m= 10.83 ft
(3.94”)
' 'g
3 3
y 3 '
& 0.163 A & Assume conforming
(70 )(130") 700.4" (10.0 ) 4.63 0.5 3(~
WALL Goodsir
3750 )(0.5)(4")(59") /12 (4")(59") 3750
0.01(33
, 1985:
00 ) 33
s s c
u
c g w w c
a
A A P f
VPL k kmmE I ksi psit l f
mm m
A
A
$ $
$ $ $ $ $
5 $ 0.015(3300 ) 50bm mm mmA 5 $
(59”)
ConformingP=10%, V=3
ConformingP=10%, V=6
56
Cantilever Wall TestsPaulay, EERI, 2(4), 1986 [Goodsir, PhD 1985 NZ]
h = 3.3 m= 10.83 ft
' 'g
3 3
y 3 '
& 0.12 A & Assume conforming
(70 )(130") 700.4" (10.0 ) 4.63 0.5 3(~ 3
WALL Goodsir,
750 )(0.5)(4")(59") /12 (4")(59") 3750
0.01(330
1
0
8
)
5
3
:
3
9
s s c
u
c g w w c
a
A A P f
VPL k kmmE I ksi psit l f
mm mm
A
A
$ $
$ $ $ $ $
5 $ 0.015(3300 ) 50b mm mmA 5 $
ConformingP=10%, V=3
ConformingP=10%, V=6
57
SummaryFEMA 356 Backbone Curves! In general, quite conservative! This appears to be especially true for cases where
moderate detailing is provided around boundary bars! Possible reformat
" Compute neutral axis depth" If s <12db over c/2, then modest ductility " If s < 8db and transverse steel ratio is ~1/2 of ACI 318-05,
then moderate ductility " If s < 8db and transverse steel ratio is > 3/4 of ACI 318-05,
then high ductility " Do not reduce deformation capacity for shear stress below 5
roots f’c
58
Shear DesignWall shear studies! Aktan & Bertero, ASCE, JSE, Aug. 1985! Paulay, EERI 1996; Wallace, ASCE, JSE, 1994.! Eberhard & Sozen, ASCE JSE, Feb. 1993
Design Recommendations! Based on Mpr at hinge region! Uniform lateral force distribution
, -, -, -lim
0.9 /10
0.3
prwall v u v
u
wall it m e
MV V n
M
V V D W weight A EPA
B B/ 0
$ $ 61 23 4
$ 6 $ $ $
Paulay, 1986
Eberhard, 1993
Slender Wall Behavior & Modeling
John WallaceUniversity of California, Los Angeles
With contributions fromDr. Kutay OrakcalUniversity of California, Los Angeles