Simple Frame

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    Chapter 3Section 2: Columns in Simple

    Construction

    Columns in Simple Construction Connections are assumed not to develop significant

    moments adversely affecting either the members or

    the structure as a whole.

    The beams may be designed as simply supported.

    The columns are designed to carry axial loads as well

    as nominal moments from the reaction shear of the

    beam, applied at the appropriate eccentricity.

    Columns must be fully continuous.

    It is assumed that sidesway due to horizontal loading

    is prevented by inserting bracing or by utilising shear

    walls, lift or staircase closures, acting together with

    shear resistance of the floor slab.

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    Joints in Simple

    Construction

    (a) Web Cleats (b) End Plate (c) Fin Plates

    100 mm

    Simple Construction

    Lift Shaft

    or stair well

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    Simple Braced Frame

    Simple Construction

    No need to consider pattern loading

    Assume all beams at any one level to

    be fully loaded

    Must consider eccentricity of loading

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    No need to consider pattern loading

    as shown below

    Buckling Capacity

    1++yy

    y

    bs

    x

    c

    c

    Zp

    M

    M

    M

    P

    F

    Based on min. (Pcx or Pcy) LT= 0.5L/ry

    mLT= 1.0 my = 1.0

    Local capacity check is not required

    Nominal moments

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    Nominal moments

    Moment = R x (D/2 + 100mm)

    R

    100mm

    D

    t/2

    Moment = R x (t/2 + 100mm)

    R

    100mm

    t

    D/2

    D is the depth of the column t is the thickness of the web

    R1

    R3

    R2

    Mx=R2(D/2+100)

    My=R1(t/2+100)

    R3(t/2+100)

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    Column Moments

    The applied moment is divided between the

    column lengths above and below in

    proportion to the stiffness (I/L)

    If the stiffness ratio 1.5, the moment may be

    divided equally

    m=1

    The moments have no effects at levels above

    and below

    Upper column stiffness = I/4

    Lower column stif fness = 2I/5

    Stiffness ratio =

    Example4m

    5m

    A

    2I

    I

    A M

    M

    M

    u

    l

    beam

    beam

    beam 5.16.14/I

    5/I2>=

    M385.0M

    5/I24/I

    4/IMu =

    +

    =

    M615.0M5/I24/I

    5/I2M l =

    +=

    *Note: If column stiffness ratio is less than 1.5, then

    Ml = Mu = 0.5M

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    Buckling Resistance

    Where LTB does not need

    to be considered Mbs = Mc

    In other cases Mbs is

    calculated according to

    clause 4.3.6.4 using

    LT = 0.5 L / ry

    1++yy

    y

    bs

    x

    c

    c

    Zp

    M

    M

    M

    P

    F

    Design Procedure

    Calculate beam reactions

    Calculate moment due to eccentricity

    Divide moment between column lengths

    Check1++

    yy

    y

    bs

    x

    c

    c

    Zp

    M

    M

    M

    P

    F

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    Braced Core to provide lateral stability

    UE SQUARE18 Storey office buildi

    Steel weight = 1800 to

    Castellated beams

    Composite slab

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    CUPPAGE CENTRE(STARHUB CENTRE)

    Completed in 1998

    Rebuilt 10-Storey

    building

    Steel weight = 3000 tons

    Composite beam

    Encased composite

    column Composite slab

    Simple construction

    Core wall with addition

    steel braces for lateral

    stability

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    Cuppage Centre

    Simple connection

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    Floor

    Diaphragm

    Rigid Floor Diaphragm

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    EXAMPLE