Signals and Systems 06

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  • 7/29/2019 Signals and Systems 06

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    2. Filtering

    Idealfrequencyselectivefiltersarefiltersthatletfrequencycomponentsoveragivenfrequencybandpassthrough

    undistorted,whilecomponentsatotherfrequenciesarecompletelycutoff.

    Filteringisneededwhennoiseisaddedtoasignalbutthenoisehasmostofitsenergyatfrequenciesoutsideofthe

    bandwidthofthesignal.Wewanttorecoverthesignalfromitsnoisymeasurement.

    Ideallowpassfilter

    Theoutput ( )y t ofthesystemforaninput ( )x t is

    givenby,. .

    ( ) ( ) ( ) ( ) ( )F T

    y t x t h t H j X j = .

    The step responseof the ideal lowpass filter is the

    running

    integral

    of

    the

    sinc

    function.

    Its

    plot

    indicates

    that there are potentially undesirable oscillations

    beforeandafterthediscontinuity.

    Theimpulseresponseofanideallowpassfilterisnot

    realizable as it is noncausal. Approximation of the

    ideal lowpass filtercanberealizedbythecausalLTI

    filters. Butterworth filter is one of them. The

    magnituderesponseofanNthorderB>W>filterwith

    cutofffrequency c isgivenby,

    TheplotofthemagnituderesponseofBWfilterforN=2isshownbelow.

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    3. Sampling

    Samplingistheacquisitionofacontinuoussignalatdiscretetimeintervals.TheprocessisshowninFigurebelow.

    Inthefrequencydomain,

    Samplingtheorem:Abandlimitedsignal ( )x t with ( ) 0X = for M > isuniquelydeterminedfrom itssamples

    ( )x nT if 2s M > where2

    sT

    = isthesamplingfrequency.

    Giventhesignalsamples,wecanrecover ( )x t byfiltering ( )px t usinganideallowpassfilterwithdcgainTandcut

    offfrequencybetween s and s M .

    Theoriginalspectrumcenteredat 0 = canbe recoveredundistorted if itdoesnotoverlapwith itsneighboringreplicas.

    SamplingusingZOH:Thezeroorderhold(ZOH)retainsthevalueofthesignalsampleupuntilthefollowingsample

    instant.Itbasicallyproducesstaircasesignalsfromthesamples.WecanviewZOHasafilterwithimpulseresponse

    0 ( )h t asshowninFigurebelow.

    ThefrequencyresponseofaZOHwithimpulseresponse 0 ( )h t isgivenby,

    20( ) sinc

    2

    Tj T

    H Te

    =

    2

    2sin

    2

    Tj T

    e

    =

    .

    Theinverseof 0 ( )H is,2

    1

    1( )

    2 sin( / 2)

    Tj

    H eT

    = .

    Thereconstructionfilteristhecascadeoftheinversefilterandthelowpassfilter.

    1( ) ( ) ( )r lpH TH H =

    ThemagnitudeandthephaseplotofthereconstructionfilterisshowninFigurebelow.

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    This

    frequency

    response

    can

    not

    be

    realized

    exactly

    in

    practice.

    But

    it

    can

    be

    approximated

    with

    a

    causal

    filter.

    ThewholeprocessisshowninFigurebelow.

    Example

    1. Aperiodicsignal ( )x t isgivenasan inputofa2ndorderButterworthfilterasshownbelow.Whatshouldbethe

    output

    of

    the

    filter?

    Given,

    1 / 4T T=

    ,

    0.001 sT=

    ,

    500

    2R =

    ,

    2

    1

    H4L =

    and

    6

    10 FC

    =.

    Thedifferentialequationrelatingtheoutputandinputofthefilteris,2

    2( ) ( )

    d y L dyLC y t x t

    dt R dt + + = .

    Thefrequencyresponseofthefilterisgivenby,

    2

    ( ) 1( )( )

    ( ) 1

    YHLX

    LC j jR

    = =+ +

    1sinc

    2 2k

    ka

    =

    2. FindtheinverseF.T. ( )x t of ( )X whosemagnitudeandphaseareshownbelow.

    Ifthephasefunctionwere0,then ( )x t wouldbeastandardsincfunction 0 ( )x t .

    0( ) 5 sin

    W Wtx t c

    =

    .

    Here,theslopeofthephaseplotisW

    .Hence, 0( ) ( )x t x tW

    = = 5 sinW W

    c tW

    =

    .

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    3. ConsiderthecausalLTIsystemshowninFigurebelow.Findthefrequencyresponseoftheoverallsystem.

    1 2 2

    1( ) ( ) ( ) ( 1)

    ( ) 2 1H H H j

    j j

    = = +

    + +

    2

    4

    1( )

    1H

    +=+

    and,1 1

    2

    2( ) tan tan1

    H

    = + + .

    4. PlottheFouriertransformofthesignal ( ) sin1000 cos1200x t t t = + .Whatshouldbethesamplingperiodthat

    wouldensurenoaliasing?

    Noaliasingwilloccurifthesamplingfrequencyis, 2400s > i.e.,2

    2400T

    < 1

    1200= s [Ans]