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32. The SEPIC circuit of Fig. 6-14a has Vs = 5 V, VO = 12 V, C1 = C2 = 50 μF, L1 = 10 µH, and L2 = 20 µH. The load resistor is 4Ω. Sketch the currents in L1 and L2, indicating average, maximum, and minimum values. The switching frequency is 100 kHz. Solution: 12= 5 ( D 1D ) D=0.71 ∆il 1 = 5 ( 0.71) 10 × 10 6 ( 100 KHz) ∆il 1 =3.55 A ∆il 2 = 5 ( 0.71) 20 × 10 6 ( 100 KHz) ∆il 2 =1.78 A I o = 12 4 =3 A Il 1 = 12 ( 3) 5 =7.2 A Il 1 Max =7.2 + 3.55 2 =9 A Il 1 Min =7.23.55 2 =5.43 A Il 2 Max =3 + 3.55 2 =4.78 A Il 2 Min =33.55 2 =1.23 A

Sepic no. 32

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Sepic no. 32

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Page 1: Sepic no. 32

32. The SEPIC circuit of Fig. 6-14a has Vs = 5 V, VO = 12 V, C1 = C2 = 50 μF, L1 = 10 µH, and L2 = 20 µH. The load resistor is 4Ω. Sketch the currents in L1 and L2, indicating average, maximum, and minimum values. The switching frequency is 100 kHz.

Solution:

12=5 ( D1−D )

D=0.71

∆ i l1=5 (0.71)

10×10−6(100KHz )

∆ i l1=3.55 A

∆ i l2=5 (0.71)

20×10−6(100KHz)

∆ i l2=1.78 A

I o=124

=3 A

I l1=12(3)5

=7.2 A

Il1Max=7.2+3.552

=9 A

Il1Min=7.2−3.552

=5.43 A

Il2Max=3+3.552

=4.78 A

Il2Min=3−3.552

=1.23 A

Page 2: Sepic no. 32

IL1

Category 1 Category 2 Category 3 Category 40

1

2

3

4

5

6

7

8

9

10

Series 1Series 2Series 3

IL2

Category 1 Category 2 Category 3 Category 40

1

2

3

4

5

6

Series 1Series 2Series 3

Page 3: Sepic no. 32