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Section 5.1 1
Section 5.1: Areas and Distances
Section 5.1 2
Section 5.1: Area and Distances
• Objective– Understand the basic properties of area– Understand the area of basic shapes– Understand rudimentary area approximations– Be able to calculate the area under a curve
Section 5.1 3
Properties of Area
Section 5.1 4
Properties of Area: Typed
1. The area of a plane region is a nonnegative real number
2. Area is measured in square units
3. Congruent regions have equal areas
4. The area of the union of two regions that overlap only in a line segment equals the sum of the areas of the two regions
5. If one region is contained in a second, then the area of the first is less than or equal to that of the second
Section 5.1 5
Basic Area Formulas
A=A1+A2+A3+A4+…+An
Polygon
A=Triangle
A=bhParallellogram
A=lwRectangle
l
w
12
bh
h
b
b
h
A1A2
A3
A4A5
Section 5.1 6
Sigma Notation
Section 5.1 7
Sigma Notation: Typed
The sum of n terms is written as:1 2, 3,, ..., na a a a
1 2 31
...,n
i ni
a a a a a=
= + + +∑
where i is the index of summation, is the i’th term of the sum ia
1 = lower bound of the sum, and n is the upper bound
Section 5.1 8
Sigma Notation: Examples
8 times
Section 5.1 9
Sigma Notation: Example: Typed6
1
62
2
1
8
1
1 2 3
.
.
. ( )
. 7
. , , ,...,
ii
j
n
ii
i
n
a a
b j
c f x x
d
e Average of n numbers a a a a
=
=
=
=
∆
∑
∑
∑
∑
Section 5.1 10
Summation Formulas
1 1
n n
i ii i
ka k a= =
=∑ ∑
( )1 1 1
n n n
i i i ii i i
a b a b= = =
+ = +∑ ∑ ∑
( )1 1 1
n n n
i i i ii i i
a b a b= = =
− = −∑ ∑ ∑
Section 5.1 11
Area
We already know how to find the area of rectangles, triangles, polygons, circles, etc. How do we find the area of a region S that lies under the curve y = f(x)
from a to b?
Strategy:
1) Divide the interval [a,b] into n intervals of equal width
2) Construct n rectangles from these intervals in such a way that the width of each rectangle will be the width of the interval and such that the height of each rectangle will be f evaluated the right or left endpoint of the interval used to construct the rectangle.
3) Sum the areas of the n rectangles
4) This gives an approximation to the area of the rectangle
5) Take Limits
Section 5.1 12
Example 1: y = 3x+1Estimate the area under f(x) = 3x + 1 over the interval [1 , 3].Divide the interval [1 , 3] into 4 equal subintervals and calculate the area of the corresponding circumscribed polygon.
Solution:
1 2 3
1
2
3
4
5
6
7
8
9
10
Section 5.1 13
Example 1: Divide The Interval [1,3]Divide the interval [1 , 3] into 4 equal subintervals
Solution:
1 2 3
1
2
3
4
5
6
7
8
9
10
f(x) =3x + 1
Section 5.1 14
4 Subintervals
1 33/2
2 5/2
3 3 5 51, , , 2 , 2, , ,32 2 2 2
⎡ ⎤ ⎡ ⎤ ⎡ ⎤ ⎡ ⎤⎢ ⎥ ⎢ ⎥ ⎢ ⎥ ⎢ ⎥⎣ ⎦ ⎣ ⎦ ⎣ ⎦ ⎣ ⎦
intLet width of each sub erval∆ =
3 1 14 2
Then −∆ = =
Section 5.1 15
Calculate the AreaCalculate the area of the corresponding circumscribed polygon. Called this approximation an Upper Sum.
1 2 3
123456789
103 1 1
4 2x −∆ = =
The sum of the reas of the 4 rectangles is:A
1 11 14 17 20 312 2 2 2 2 2
A ⎛ ⎞= + + + =⎜ ⎟⎝ ⎠
4Let R = approximated area using right endpoints
( )1 3 1 1 5 12 (3)2 2 2 2 2 2
A f f f f⎛ ⎞ ⎛ ⎞= + + +⎜ ⎟ ⎜ ⎟⎝ ⎠ ⎝ ⎠
( ) 3 1f x x= +
Section 5.1 16
ExampleFind an Upper Sum the area under y= x+1, between 0 and 2, when n=8
Solution:
1 2
1
2
3
y = x +
11Since 8, 4
n x= ∆ =
1The area of each rectangle is ( )4
f x
41 1 2 3 4 5 6 7 84 4 4 4 4 4 4 4 4
R f f f f f f f f⎡ ⎤⎛ ⎞ ⎛ ⎞ ⎛ ⎞ ⎛ ⎞ ⎛ ⎞ ⎛ ⎞ ⎛ ⎞ ⎛ ⎞= + + + + + + +⎜ ⎟ ⎜ ⎟ ⎜ ⎟ ⎜ ⎟ ⎜ ⎟ ⎜ ⎟ ⎜ ⎟ ⎜ ⎟⎢ ⎥⎝ ⎠ ⎝ ⎠ ⎝ ⎠ ⎝ ⎠ ⎝ ⎠ ⎝ ⎠ ⎝ ⎠ ⎝ ⎠⎣ ⎦1 5 6 7 8 9 10 11 12 174 4 4 4 4 4 4 4 4 4⎛ ⎞= + + + + + + + =⎜ ⎟⎝ ⎠
0
Section 5.1 17
Summary: Definition of Area
The area A of the region S that lies under the graph of a continuous function f is the limit of the sum of the areas of approximatingrectangles. In symbols:
[ ]1lim lim ( ) ( 2) ... ( )n nn nA R f x x f x x f x x→∞ →∞= = ∆ + ∆ + + ∆
1
lim ( )n
in i
A f x x→∞
=
= ∆∑
OR[ ]0 1lim lim ( ) ( 2) ... ( )n nn nA L f x x f x x f x x−→∞ →∞= = ∆ + ∆ + + ∆
11
lim ( )n
in i
A f x x−→∞=
= ∆∑
intnR right endpo s=
intnL right endpo s=
Section 5.1 18
Example 2:Find the area of the region under the curve over the interval [0,1].21 1
2y x= +
-1 1 2
-1
1
2
21 12
y x= +
To Be Continued