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7/27/2019 s Plane Review
1/15
EE122, Stanford University, Ross Venook
S-plane Explained
Introduction
Motivation for s-plane analysis
When I say s-plane, what do I mean?
How to use the s-plane
Circuit analysis/design: the Integrator
Signal analysis/design: FM
A (P)REVIEW OF LAPLACE TRANFORMS AND
HOW TO USE THEM IN EE122
7/27/2019 s Plane Review
2/15
EE122, Stanford University, Ross Venook
Motivation for s-plane analysis
Understanding circuits in another
domain (the frequency domain) The more ways we can understand our
circuit, the better because...
The time domain is hard for some things
filtering = convolution (Doh!)
The s-plane (often) makes things easier
filtering = multiplication (Woohoo!)
7/27/2019 s Plane Review
3/15
EE122, Stanford University, Ross Venook
Math behind the s-plane
The actual Laplace Transform*:
h(t) could be a signal, or a system As a signal:
As a system:
H(s): Laplace Transform of h(t)
s = + j: Complex Frequency Variable
*: not necessary for EE122, but interesting (maybe)
=
0)()( dtethsH st
)16.015sin()( += tth
)(
)()(
tv
tvth
in
out=
The Laplace Transform of a time-domain function gives us
a function of the complex frequency variable s
7/27/2019 s Plane Review
4/15
EE122, Stanford University, Ross Venook
A note about transforms
They make life easier (or should)
If youve taken E40 (and/or Math 53),
you have already used transforms
E40 uses phasor analysis of linear circuits
Complex impedances are just a tricky way ofgetting around differential equations so that we
can take C as a resistor of value 1/ jC.
Indeed, they are simply Laplace (or Fourier)transforms in disguise--as you will see.
Math 53 uses Laplace Transforms to solve
differential equations
7/27/2019 s Plane Review
5/15
EE122, Stanford University, Ross Venook
What do I mean when I say s-plane?
Example:
Tent pole plot of the
magnitude of a
Chebychev filters
response to inputs ofcomplex frequency s
is what you usually
think of as radianfrequency (=2f)
is decay rate*
ANSWER: THE REAL () AND IMAGINARY () PARTS OF s
ARE THE x and y ON A GRAPH
*: Not important for EE122, but used in stability analysis
-axis axis s-plane
|H(s)|
7/27/2019 s Plane Review
6/15
EE122, Stanford University, Ross Venook
Why should I use the s-plane?
Turns differential equations (hard) into
algebraic equations (easy)
Turns convolution (hard) into multiplication
(easy)
THIS IS THE SAME QUESTION AS:WHY IS THE LAPLACE TRANSFORM USEFUL?
inoutinoutout CvvsBAtCvdtdvBtAv =+=+ )()()(
sBACsH
vv
in
out
+== )(
)()()()()()( sGsHsFtgthtf ==
7/27/2019 s Plane Review
7/15
EE122, Stanford University, Ross Venook
How to use s-plane analysis
Examples to follow:
Systems Simple RC circuit
Integrator
Signals
Multiplication by a sinusoid: Heterodyning
7/27/2019 s Plane Review
8/15
EE122, Stanford University, Ross Venook
RC circuit (simple)
Straight from EE122 lecture notes:
sRCsH
vv
vsRCv
TransformLaplaceMagictvdtdvRCtv
dtdvCi
iRtvtverivation
in
out
inout
inoutout
out
inout
+==
=+
=+
=
=
11)(
)1(
)("")()(
)()(:
7/27/2019 s Plane Review
9/15
EE122, Stanford University, Ross Venook
Integrator (slightly less simple)
121
2
2211
21
1
2
)(
)(
)//)(()(
/)(
/)()(
))()(()(
:
RCRsR
RsH
v
v
RvvCRsRR
RdtCdvRtvtv
dtCdvti
Rtvti
Rtititv
AnalysisC
in
out
inout
outinout
outC
inin
Cinout
+==
=+
+=
=
=
=
1
2
2
1
R
R
CR2
1
7/27/2019 s Plane Review
10/15
EE122, Stanford University, Ross Venook
A familiar slide
7/27/2019 s Plane Review
11/15
EE122, Stanford University, Ross Venook
Another familiar slide...
7/27/2019 s Plane Review
12/15
EE122, Stanford University, Ross Venook
A last familiar slide
7/27/2019 s Plane Review
13/15
EE122, Stanford University, Ross Venook
Heterodyning (for FM radio)
Motivation: Base-band txn is trouble Efficiency
/4 Antenna for kHz ~ length > kilometers Interference
All of the signals would muddle together
Hence, we need distinct carrierfrequencies (regulated by the FCC)
92.3 MHz (KSJO)
88.5 MHz (KQED)
1070 kHz (KNX)
710 kHz (KABC)
FM
AM
7/27/2019 s Plane Review
14/15
EE122, Stanford University, Ross Venook
The frequency domain
All base-band:
Heterodyned
7/27/2019 s Plane Review
15/15
EE122, Stanford University, Ross Venook
Back to heterodyning
Because convolution in the time domain is multiplicationin the frequency domain, when we multiply by a sinusoid
in the time domain, it convolves the frequency content of
our signal up to the frequency of the sinusoid.(Whew! That was a mouthful)
Base-band signal...
convolved with pure tone...
yields heterodyned signal!
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