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Charles’ Law Jacques Charles 1746 – – 1823
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REVIEW HOMEWORK ??REVIEW HOMEWORK ??
What is the formula for Avogadro’s Law?
What happens to volume when the number of moles increases?
Avogadro’s Law Questions 1-4
REVIEW HOMEWORK ??REVIEW HOMEWORK ??
What is the formula for Boyles Law?
What happens to volume when pressure increases?
Boyle’s Law Questions 1-8
Charles’ LawCharles’ Law Jacques CharlesJacques Charles 1746 – 18231746 – 1823
Charles’ LawCharles’ Law
At constant pressure, the volume of a gas varies directly with its Kelvin temperature
Equation: V1
V2= T1
T2
Volume = L Temperature = K
Charles’ LawCharles’ Law
Cross multiply the equation:
V2
= T1
T2
V1
Resulting Equation: V1T2 = V2T1
At Constant Pressure, V At Constant Pressure, V T T
means proportional
When volume , temp
When volume , temp
Temp. scale K not °C
What error exists on this graph?
Solving Charles’ Law ProblemsSolving Charles’ Law Problems
– Write the given information– Determine an equation to use– Isolate the missing variable – Convert to Kelvin temp. scale– Plug-in the given values and solve
Write Given Info.Write Given Info.
A volume of 20.0m3 of argon gas is kept under constant pressure. The gas is heated from 22ºC to 283 ºC. What is the new volume of the gas?
V1 = 20.0 m3
T1 = 22ºC
T2 = 283 º C
V2 = ?
Determine an Equation & Isolate VDetermine an Equation & Isolate V22
V1T2 = V2T1
V1T2 = V2T1
T1T1
V1T2
T1= V2
Temperature Conversion EquationsTemperature Conversion Equations
Celsius to KelvinK = ºC + 273
Fahrenheit to CelsiusºC = 5/9 (º F – 32)
Convert Convert ººC to KC to K
Given Info.
V1 = 20.0 m3
T1 = 22ºC
T2 = 283 º C
V2 = ?
K = ºC + 273K = 22 + 273K = 295
K = ºC + 273
K = 283 + 273
K = 556
Plug-in Given Values and SolvePlug-in Given Values and Solve
Given Info.
V1 = 20.0 m3
T1 = 295K
T2 = 556K
V2 = ?
V1T2
T1= V2
(20.0 m3)(556K) = V2295K
37.7 m3 = V2
Turn to a person next to you…Turn to a person next to you…
“I’m here to help whenever I can”
OutstandingOutstanding Teamwork!Teamwork!
Let’s try a few more Charles’ Law problems.
EXERCISEEXERCISE
