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Review:1. Solve for a: 43 = 2a
2. What is the domain for y = 2e-x - 3?
3. What is the range for y = tan x?
Answers:3. Domain:(-∞, ∞) Range: (-2,∞)6. 163x = (24)3x = 212x
9. x-intercept:≈-2.322 y-intercept: -3.012. x-intercept: 2.0 y-intercept:≈1.58515. c18. f21. Use 500,000(1.0375)t = 1,000,000 t ≈ 18.828
23.a. A(t) = 6.6(.5)t/14
b. t ≈ 38.114524. Use 2300(1.06)t = 4150 t ≈ 10.129
25. Use 2A = A(1.0625)t
2 = 1.0625t
t ≈ 11.433
26. Use A(1 + .0625/12)12t
t ≈ 11.119
27. Use 2A = Ae.0625t
t ≈ 11.090
32a. Use C(t) = 10,000(.8)t
t ≈ 10.319
b. t ≈ 41.275
36. x y ratio 1 8.155 2.718 2 22.167 2.718 3 60.257 2.718 4 160.79440a.y = 24121.49(1.0178)t
b. 36, 194,000 exceeds actual by 710,000 c. 1.8%
Parametric EquationsIf x and y are given as the functions x = f(t) y = g(t)over an interval of t-values, then the set of points (x,y) = (f(t),g(t)) defined by these equations is a parametric curve.
The equations are giving the horizontal and vertical positions over time.
t as a variable
Aside from setting our domain and range, we also need to set the interval of time we are looking at the equations.
What value of t should be our starting point?
Why would we want to have a negative value for the initial t?
Ex 1: Let x = a cos t and y = a sin t.a) Let a = 1, 2, or 3 and graph the parametric equations in a square viewing window using a parameter interval of [0,2π]. How does changing a affect the graph?
b) Let a = 2 and graph the interval over the following parameter values:[0,π/2]0,π][0,3π/2][0,2π][2π,4π][0,4π]Describe the role of the length of the parameter values.
Ex 2: Find the Cartesian equation for the parametric equationsa) x = t, y = 2t t ≥ 0
b) x = √t , t = t2 , t ≥0
Ex 3: Find the Cartesian equation for the parametric equationsa) x = 3 cost t, y = 3 sin t, 0 ≤ t ≤ 2π
b) x = 4 cos t, y = 2 sin t, 0 ≤ t ≤2π