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Relative Charity (a 1 (p) = 1 a 1 (p) = 0)? Fabien Schang [email protected] [email protected] National Research University, HSE Seminar “Formal Philosophy” 24 February 2015

Relative Charity a1 p) = 1 a1 p) = 0)? - hse.ru · Relative Charity (a1 (p) = 1 a1 ( p) = 0)? Fabien Schang [email protected] [email protected] National Research University, HSE

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Page 1: Relative Charity a1 p) = 1 a1 p) = 0)? - hse.ru · Relative Charity (a1 (p) = 1 a1 ( p) = 0)? Fabien Schang schang.fabien@voila.fr fschang@hse.ru National Research University, HSE

Relative Charity (a1(p) = 1 a1(p) = 0)?

Fabien Schang

[email protected]

[email protected]

National Research University, HSE

Seminar “Formal Philosophy”

24 February 2015

Page 2: Relative Charity a1 p) = 1 a1 p) = 0)? - hse.ru · Relative Charity (a1 (p) = 1 a1 ( p) = 0)? Fabien Schang schang.fabien@voila.fr fschang@hse.ru National Research University, HSE

Content 1 The Background: Logic in Translation 2 An Alternative Referential Semantics 3 A Logic of Acceptance and Rejection 4 Coherence beyond Consistency 5 Truths in Meaning 6 Conclusion: The Answer is in the Question 7 Appendix: On Conditional

Page 3: Relative Charity a1 p) = 1 a1 p) = 0)? - hse.ru · Relative Charity (a1 (p) = 1 a1 ( p) = 0)? Fabien Schang schang.fabien@voila.fr fschang@hse.ru National Research University, HSE

1 The Background:

Logic in Translation

Page 4: Relative Charity a1 p) = 1 a1 p) = 0)? - hse.ru · Relative Charity (a1 (p) = 1 a1 ( p) = 0)? Fabien Schang schang.fabien@voila.fr fschang@hse.ru National Research University, HSE

by reference to assent and dissent we can state semantic criteria for truth-functions; i.e., criteria for determining whether a given native idiom is to be constructed as expressing the truth-function in question. The semantic criterion of negation is that it turns any short sentence to which one will assent into a sentence from which one will dissent, and vice versa. That of conjunction is that it produces compounds to which (so long as the component sentences are short) one is prepared to assent always only when one is prepared to assent to each component. That of alternation is similar with assent changed twice to dissent.

Quine (1960): 57-8

Page 5: Relative Charity a1 p) = 1 a1 p) = 0)? - hse.ru · Relative Charity (a1 (p) = 1 a1 ( p) = 0)? Fabien Schang schang.fabien@voila.fr fschang@hse.ru National Research University, HSE

For every proposition p: Assent v(p) = T Dissent v(p) = F

Page 6: Relative Charity a1 p) = 1 a1 p) = 0)? - hse.ru · Relative Charity (a1 (p) = 1 a1 ( p) = 0)? Fabien Schang schang.fabien@voila.fr fschang@hse.ru National Research University, HSE

by reference to assent and dissent we can state semantic criteria for truth-functions; i.e., criteria for determining whether a given native idiom is to be constructed as expressing the truth-function in question. The semantic criterion of negation is that it turns any short sentence to which one will assent into a sentence from which one will dissent, and vice versa. That of conjunction is that it produces compounds to which (so long as the component sentences are short) one is prepared to assent always only when one is prepared to assent to each component. That of alternation is similar with assent changed twice to dissent.

Quine (1960): 57-8

Page 7: Relative Charity a1 p) = 1 a1 p) = 0)? - hse.ru · Relative Charity (a1 (p) = 1 a1 ( p) = 0)? Fabien Schang schang.fabien@voila.fr fschang@hse.ru National Research University, HSE

Negation v(p) = T iff v(p) = F Conjunction v(p q) = T iff v(p) = v(q) = T Disjunction v(p q) = F iff v(p) = v(q) = F … Conditional?

Page 8: Relative Charity a1 p) = 1 a1 p) = 0)? - hse.ru · Relative Charity (a1 (p) = 1 a1 ( p) = 0)? Fabien Schang schang.fabien@voila.fr fschang@hse.ru National Research University, HSE

by reference to assent and dissent we can state semantic criteria for truth-functions; i.e., criteria for determining whether a given native idiom is to be constructed as expressing the truth-function in question. The semantic criterion of negation is that it turns any short sentence to which one will assent into a sentence from which one will dissent, and vice versa. That of conjunction is that it produces compounds to which (so long as the component sentences are short) one is prepared to assent always only when one is prepared to assent to each component. That of alternation is similar with assent changed twice to dissent.

Quine (1960): 57-8

Page 9: Relative Charity a1 p) = 1 a1 p) = 0)? - hse.ru · Relative Charity (a1 (p) = 1 a1 ( p) = 0)? Fabien Schang schang.fabien@voila.fr fschang@hse.ru National Research University, HSE

Negation v(p) = T iff v(p) = F Conjunction v(pq) = T iff v(p) = v(q) = T Disjunction v(p q) = F iff v(p) = v(q) = F … Conditional?

Page 10: Relative Charity a1 p) = 1 a1 p) = 0)? - hse.ru · Relative Charity (a1 (p) = 1 a1 ( p) = 0)? Fabien Schang schang.fabien@voila.fr fschang@hse.ru National Research University, HSE

by reference to assent and dissent we can state semantic criteria for truth-functions; i.e., criteria for determining whether a given native idiom is to be constructed as expressing the truth-function in question. The semantic criterion of negation is that it turns any short sentence to which one will assent into a sentence from which one will dissent, and vice versa. That of conjunction is that it produces compounds to which (so long as the component sentences are short) one is prepared to assent always only when one is prepared to assent to each component. That of alternation is similar with assent changed twice to dissent.

Quine (1960): 57-8

Page 11: Relative Charity a1 p) = 1 a1 p) = 0)? - hse.ru · Relative Charity (a1 (p) = 1 a1 ( p) = 0)? Fabien Schang schang.fabien@voila.fr fschang@hse.ru National Research University, HSE

Negation v(p) = T iff v(p) = F Conjunction v(pq) = T iff v(p) = v(q) = T Disjunction v(pq) = F iff v(p) = v(q) = F

Page 12: Relative Charity a1 p) = 1 a1 p) = 0)? - hse.ru · Relative Charity (a1 (p) = 1 a1 ( p) = 0)? Fabien Schang schang.fabien@voila.fr fschang@hse.ru National Research University, HSE

Negation v(p) = T iff v(p) = F Conjunction v(pq) = T iff v(p) = v(q) = T Disjunction v(pq) = F iff v(p) = v(q) = F … Conditional?

Page 13: Relative Charity a1 p) = 1 a1 p) = 0)? - hse.ru · Relative Charity (a1 (p) = 1 a1 ( p) = 0)? Fabien Schang schang.fabien@voila.fr fschang@hse.ru National Research University, HSE

The methodological advice to interpret in a way that optimizes agreement should not be conceived as resting on a charitable assumption about human intelligence that might turn out to be false. If we cannot find a way to interpret the utterances and other behavior of a creature as revealing a set of beliefs largely consistent and true by our own standards, we have no reason to count that creature as rational, as having beliefs, or as saying anything. Davidson (1973): 324

Page 14: Relative Charity a1 p) = 1 a1 p) = 0)? - hse.ru · Relative Charity (a1 (p) = 1 a1 ( p) = 0)? Fabien Schang schang.fabien@voila.fr fschang@hse.ru National Research University, HSE

2 An Alternative

Referential Semantics

Page 15: Relative Charity a1 p) = 1 a1 p) = 0)? - hse.ru · Relative Charity (a1 (p) = 1 a1 ( p) = 0)? Fabien Schang schang.fabien@voila.fr fschang@hse.ru National Research University, HSE

(1) Logical Absolutism A common rationality standard includes only one correct logic; there is only one rational standard; therefore, there is only one correct logic. (If A then B; A; therefore B) (2) Logical Relativism A common rationality standard includes only one correct logic; there are several correct logics; therefore, there are several rational standards. (If A then B; not-B; therefore A) (3) Relative charity A common rationality standard includes several correct logics not-(if A then B) = A and not-B

Page 16: Relative Charity a1 p) = 1 a1 p) = 0)? - hse.ru · Relative Charity (a1 (p) = 1 a1 ( p) = 0)? Fabien Schang schang.fabien@voila.fr fschang@hse.ru National Research University, HSE

(1) Logical Absolutism A common rationality standard includes only one correct logic; there is only one rational standard; therefore, there is only one correct logic. (If A then B; A; therefore B) (2) Logical Relativism A common rationality standard includes only one correct logic; there are several correct logics; therefore, there are several rational standards. (If A then B; not-B; therefore not-A) (3) Relative charity A common rationality standard includes several correct logics not-(if A then B) = A and not-B

Page 17: Relative Charity a1 p) = 1 a1 p) = 0)? - hse.ru · Relative Charity (a1 (p) = 1 a1 ( p) = 0)? Fabien Schang schang.fabien@voila.fr fschang@hse.ru National Research University, HSE

(1) Logical Absolutism A common rationality standard includes only one correct logic; there is only one rational standard; therefore, there is only one correct logic. (If A then B; A; therefore B) (2) Logical Relativism A common rationality standard includes only one correct logic; there are several correct logics; therefore, there are several rational standards. (If A then B; not-B; therefore not-A) (3) Relative charity A common rationality standard includes several correct logics not-(if A then B) = A and not-B

Page 18: Relative Charity a1 p) = 1 a1 p) = 0)? - hse.ru · Relative Charity (a1 (p) = 1 a1 ( p) = 0)? Fabien Schang schang.fabien@voila.fr fschang@hse.ru National Research University, HSE

Cultural anthropologists usually maintain that there is no evidence that there exist cultures which adhere to different logics than we do. But I find this a strange claim. For one thing, even in my own country there is a subculture of people who try to adhere to intuitionistic logic rather than classical logic. Lokhorst (1998): 57

Page 19: Relative Charity a1 p) = 1 a1 p) = 0)? - hse.ru · Relative Charity (a1 (p) = 1 a1 ( p) = 0)? Fabien Schang schang.fabien@voila.fr fschang@hse.ru National Research University, HSE

The proper “Conceptual Scheme”: A Logic of Statements - each lexicographer has to do with statements, rather than sentences - statements: speech-acts performed with sentential content Reference: Searle (1965) p: sentence with truth-conditions (truth, false) F(p): statement with satisfaction-conditions F: assertion, order, declaration, … (speech-act theory) In the following, 2 basic “transcendental” speech-acts: - assertion (the speaker says “yes”, commits himself, accepts p) - rejection (the speaker says “no”, does not commit himself, rejects p)

Page 20: Relative Charity a1 p) = 1 a1 p) = 0)? - hse.ru · Relative Charity (a1 (p) = 1 a1 ( p) = 0)? Fabien Schang schang.fabien@voila.fr fschang@hse.ru National Research University, HSE

The proper “Conceptual Scheme”: A Logic of Statements - each lexicographer has to do with statements, rather than sentences - statements: speech-acts performed with sentential content Reference: Searle (1965) p: sentence with truth-conditions (truth, false) F(p): statement with satisfaction-conditions F: assertion, order, declaration, … (speech-act theory) In the following, 2 basic “transcendental” speech-acts: - assertion (the speaker says “yes”, commits himself, accepts p) - rejection (the speaker says “no”, does not commit himself, rejects p)

Page 21: Relative Charity a1 p) = 1 a1 p) = 0)? - hse.ru · Relative Charity (a1 (p) = 1 a1 ( p) = 0)? Fabien Schang schang.fabien@voila.fr fschang@hse.ru National Research University, HSE

The proper “Conceptual Scheme”: A Logic of Statements - each lexicographer has to do with statements, rather than sentences - statements: speech-acts performed with sentential content Reference: Searle (1965) p: sentence with truth-conditions (truth, false) F(p): statement with satisfaction-conditions F: assertion, order, declaration, … (speech-act theory) In the following, 2 basic “transcendental” speech-acts: - assertion (the speaker says “yes”, commits himself, accepts p) - rejection (the speaker says “no”, does not commit himself, rejects p)

Page 22: Relative Charity a1 p) = 1 a1 p) = 0)? - hse.ru · Relative Charity (a1 (p) = 1 a1 ( p) = 0)? Fabien Schang schang.fabien@voila.fr fschang@hse.ru National Research University, HSE

3 A Logic of

Acceptance and Rejection

Page 23: Relative Charity a1 p) = 1 a1 p) = 0)? - hse.ru · Relative Charity (a1 (p) = 1 a1 ( p) = 0)? Fabien Schang schang.fabien@voila.fr fschang@hse.ru National Research University, HSE

Meaning corresponds to a logical value: a 3-dimensional object

answers = statements

A() = a11(), … ,aij() questions = sentences parameters = quantifiers/modalities

Page 24: Relative Charity a1 p) = 1 a1 p) = 0)? - hse.ru · Relative Charity (a1 (p) = 1 a1 ( p) = 0)? Fabien Schang schang.fabien@voila.fr fschang@hse.ru National Research University, HSE

AR4: Logic of Acceptance and Rejection (theory of normative answers) 2 main components: Question Q: statement-forming operator upon a given sentence p

Q(p) = q1(p), …, qn(p) The number of required questions about p is not predetermined Answer A: set of ordered answers to a given question Q

A(p) = a1(p), …, am(p) In AR4: n = 2 relevant questions, m = 2 possible sorts of answer Card(V) = mn = 22 = 4 Note: n and m are independent from each other (rejectivism!)

Page 25: Relative Charity a1 p) = 1 a1 p) = 0)? - hse.ru · Relative Charity (a1 (p) = 1 a1 ( p) = 0)? Fabien Schang schang.fabien@voila.fr fschang@hse.ru National Research University, HSE

AR4: Logic of Acceptance and Rejection (theory of normative answers) 2 main components: Question Q: statement-forming operator upon a given sentence p

Q(p) = q1(p), …, qn(p) The number of required questions about p is not predetermined Answer A: set of ordered answers to a given question Q

A(p) = a1(p), …, am(p) In AR4: n = 2 relevant questions, m = 2 possible sorts of answer Card(V) = mn = 22 = 4 Note: n and m are independent from each other (rejectivism!)

Page 26: Relative Charity a1 p) = 1 a1 p) = 0)? - hse.ru · Relative Charity (a1 (p) = 1 a1 ( p) = 0)? Fabien Schang schang.fabien@voila.fr fschang@hse.ru National Research University, HSE

AR4: Logic of Acceptance and Rejection (theory of normative answers) 2 main components: Question Q: statement-forming operator upon a given sentence p

Q(p) = q1(p), …, qn(p) The number of required questions about p is not predetermined Answer A: set of ordered answers to a given question Q

A(p) = a1(p), …, am(p) In AR4: n = 2 relevant questions, m = 2 possible sorts of answers Card(V) = mn = 22 = 4 Note: n and m are independent from each other (rejectivism!)

Page 27: Relative Charity a1 p) = 1 a1 p) = 0)? - hse.ru · Relative Charity (a1 (p) = 1 a1 ( p) = 0)? Fabien Schang schang.fabien@voila.fr fschang@hse.ru National Research University, HSE

AR4: Logic of Acceptance and Rejection (theory of normative answers) 2 main components: Question Q: statement-forming operator upon a given sentence p

Q(p) = q1(p), …, qn(p) The number of required questions about p is not predetermined Answer A: set of ordered answers to a given question Q

A(p) = a1(p), …, am(p) In AR4: n = 2 relevant questions, m = 2 possible sorts of answer Card(V) = mn = 22 = 4 Note: n and m are independent from each other (rejectivism!)

Page 28: Relative Charity a1 p) = 1 a1 p) = 0)? - hse.ru · Relative Charity (a1 (p) = 1 a1 ( p) = 0)? Fabien Schang schang.fabien@voila.fr fschang@hse.ru National Research University, HSE

Affirmation vs Negation (Question), Assertion vs Rejection (Answer) Affirmation: expresses the sentence that p Question: “Is it the case that p?” q1(p) Negation: expresses the sentence opposed to p Question: “Is it not the case that p?” = “Is it the case that not-p?”

q2(p) = q1(p) Assertion: If I assert p, then I take p to be true (truth-claim) Answer: “Yes, it is the case that p (is true)”

a1(p) = 1 Rejection: If I reject p, then I do not take p to be true (non-truth-claim) Answer: “No, it is not the case that p (is true)”

a1(p) = 0

Page 29: Relative Charity a1 p) = 1 a1 p) = 0)? - hse.ru · Relative Charity (a1 (p) = 1 a1 ( p) = 0)? Fabien Schang schang.fabien@voila.fr fschang@hse.ru National Research University, HSE

Affirmation vs Negation (Question), Assertion vs Rejection (Answer) Affirmation: expresses the sentence that p Question: “Is it the case that p?” q1(p) Negation: expresses the sentence opposed to p Question: “Is it not the case that p?” = “Is it the case that not-p?”

q2(p) = q1(p) Assertion: If I assert p, then I take p to be true (truth-claim) Answer: “Yes, it is the case that p (is true)”

a1(p) = 1 Rejection: If I reject p, then I do not take p to be true (non-truth-claim) Answer: “No, it is not the case that p (is true)”

a1(p) = 0

Page 30: Relative Charity a1 p) = 1 a1 p) = 0)? - hse.ru · Relative Charity (a1 (p) = 1 a1 ( p) = 0)? Fabien Schang schang.fabien@voila.fr fschang@hse.ru National Research University, HSE

Affirmation vs Negation (Question), Assertion vs Rejection (Answer) Affirmation: expresses the sentence that p Question: “Is it the case that p?” q1(p) Negation: expresses the sentence opposed to p Question: “Is it not the case that p?” = “Is it the case that not-p?”

q2(p) = q1(p) Assertion: If I assert p, then I take p to be true (truth-claim) Answer: “Yes, it is the case that p (is true)”

a1(p) = 1 Rejection: If I reject p, then I do not take p to be true (non-truth-claim) Answer: “No, it is not the case that p (is true)”

a1(p) = 0

Page 31: Relative Charity a1 p) = 1 a1 p) = 0)? - hse.ru · Relative Charity (a1 (p) = 1 a1 ( p) = 0)? Fabien Schang schang.fabien@voila.fr fschang@hse.ru National Research University, HSE

Affirmation vs Negation (Question), Assertion vs Rejection (Answer) Affirmation: expresses the sentence that p Question: “Is it the case that p?” q1(p) Negation: expresses the sentence opposed to p Question: “Is it not the case that p?” = “Is it the case that not-p?”

q2(p) = q1(p) Assertion: If I assert p, then I take p to be true (truth-claim) Answer: “Yes, it is the case that p (is true)”

a1(p) = 1 Rejection: If I reject p, then I do not take p to be true (non-truth-claim) Answer: “No, it is not the case that p (is true)”

a1(p) = 0

Page 32: Relative Charity a1 p) = 1 a1 p) = 0)? - hse.ru · Relative Charity (a1 (p) = 1 a1 ( p) = 0)? Fabien Schang schang.fabien@voila.fr fschang@hse.ru National Research University, HSE

Affirmation vs Negation (Question), Assertion vs Rejection (Answer) Affirmation: expresses the sentence that p Question: “Is it the case that p?” q1(p) Negation: expresses the sentence opposed to p Question: “Is it not the case that p?” = “Is it the case that not-p?”

q2(p) = q1(p) Assertion: If I assert p, then I take p to be true (truth-claim) Answer: “Yes, it is the case that p (is true)”

a1(p) = 1 Rejection: If I reject p, then I do not take p to be true (non-truth-claim) Answer: “No, it is not the case that p (is true)”

a1(p) = 0

Page 33: Relative Charity a1 p) = 1 a1 p) = 0)? - hse.ru · Relative Charity (a1 (p) = 1 a1 ( p) = 0)? Fabien Schang schang.fabien@voila.fr fschang@hse.ru National Research University, HSE

Unilateralism Equivalence Thesis (Frege, 1919): there is no difference between “No, it is not the case that p is true” and “Yes, it is the case that p is false”

a1(p) = 0 a2(p) = 1 Logical theory: a theory of truth-preservation, only Denial is a by-product of assertion: a negative assertion

Page 34: Relative Charity a1 p) = 1 a1 p) = 0)? - hse.ru · Relative Charity (a1 (p) = 1 a1 ( p) = 0)? Fabien Schang schang.fabien@voila.fr fschang@hse.ru National Research University, HSE

Unilateralism Equivalence Thesis (Frege, 1919): there is no difference between “No, it is not the case that p is true” and “Yes, it is the case that p is false”

a1(p) = 0 a2(p) = 1 Logical theory: a theory of truth-preservation, only Denial is a by-product of assertion: a negative assertion

Page 35: Relative Charity a1 p) = 1 a1 p) = 0)? - hse.ru · Relative Charity (a1 (p) = 1 a1 ( p) = 0)? Fabien Schang schang.fabien@voila.fr fschang@hse.ru National Research University, HSE

Unilateralism Equivalence Thesis (Frege, 1919): there is no difference between “No, it is not the case that p is true” and “Yes, it is the case that p is false”

a1(p) = 0 a2(p) = 1 Logical theory: a theory of truth-preservation, only Denial is a by-product of assertion: a negative assertion

Page 36: Relative Charity a1 p) = 1 a1 p) = 0)? - hse.ru · Relative Charity (a1 (p) = 1 a1 ( p) = 0)? Fabien Schang schang.fabien@voila.fr fschang@hse.ru National Research University, HSE

Correctness Under what conditions can a sentence be correctly said to be “true”? Correctness: assertibility-conditions 3 grades of “modal” involvement (3 modes of “being” true) (1) strong correctness: true as impossibly false (truth “by default”) (2) mild correctness: true as not false (truth “by default”) (3) weak correctness: being true as being possibly not false Frege assumed a mild view of truth: Bivalentism (Equivalence Thesis) AR4: no involvement about what truth means (abstract logic)!

Page 37: Relative Charity a1 p) = 1 a1 p) = 0)? - hse.ru · Relative Charity (a1 (p) = 1 a1 ( p) = 0)? Fabien Schang schang.fabien@voila.fr fschang@hse.ru National Research University, HSE

Correctness Under what conditions can a sentence be correctly said to be “true”? Correctness: assertibility-conditions 3 grades of “modal” involvement (3 modes of “being” true) (1) strong correctness: true as impossibly false (truth “by default”) (2) mild correctness: true as not false (truth “by default”) (3) weak correctness: being true as being possibly not false Frege assumed a mild view of truth: Bivalentism (Equivalence Thesis) AR4: no involvement about what truth means (abstract logic)!

Page 38: Relative Charity a1 p) = 1 a1 p) = 0)? - hse.ru · Relative Charity (a1 (p) = 1 a1 ( p) = 0)? Fabien Schang schang.fabien@voila.fr fschang@hse.ru National Research University, HSE

Correctness Under what conditions can a sentence be correctly said to be “true”? Correctness: assertibility-conditions 3 grades of “modal” involvement (3 modes of “being” true) (1) strong correctness: true as impossibly false (2) mild correctness: true as not false (truth “by default”) (3) weak correctness: being true as being possibly not false Frege assumed a mild view of truth: Bivalentism (Equivalence Thesis) AR4: no involvement about what truth means (abstract logic)!

Page 39: Relative Charity a1 p) = 1 a1 p) = 0)? - hse.ru · Relative Charity (a1 (p) = 1 a1 ( p) = 0)? Fabien Schang schang.fabien@voila.fr fschang@hse.ru National Research University, HSE

Correctness Under what conditions can a sentence be correctly said to be “true”? Correctness: assertibility-conditions 3 grades of “modal” involvement (3 modes of “being” true) (1) strong correctness: true as impossibly false (2) mild correctness: true as not false (truth “by default”) (3) weak correctness: being true as being possibly not false Frege assumed a mild view of truth: Bivalentism (Equivalence Thesis) AR4: no involvement about what truth means (abstract logic)!

Page 40: Relative Charity a1 p) = 1 a1 p) = 0)? - hse.ru · Relative Charity (a1 (p) = 1 a1 ( p) = 0)? Fabien Schang schang.fabien@voila.fr fschang@hse.ru National Research University, HSE

Correctness Under what conditions can a sentence be correctly said to be “true”? Correctness: assertibility-conditions 3 grades of “modal” involvement (3 modes of “being” true) (1) strong correctness: true as impossibly false (2) mild correctness: true as not false (truth “by default”) (3) weak correctness: being true as being possibly not false Frege assumed a mild view of truth: Bivalentism (Equivalence Thesis) AR4: no involvement about what truth means (abstract logic)!

Page 41: Relative Charity a1 p) = 1 a1 p) = 0)? - hse.ru · Relative Charity (a1 (p) = 1 a1 ( p) = 0)? Fabien Schang schang.fabien@voila.fr fschang@hse.ru National Research University, HSE

Correctness Under what conditions can a sentence be correctly said to be “true”? Correctness: assertibility-conditions 3 grades of “modal” involvement (3 modes of “being” true) (1) strong correctness: true as impossibly false (2) mild correctness: true as not false (truth “by default”) (3) weak correctness: being true as being possibly not false Frege assumed a mild view of truth: Bivalentism (Equivalence Thesis) AR4: no involvement about what truth means (abstract logic)!

Page 42: Relative Charity a1 p) = 1 a1 p) = 0)? - hse.ru · Relative Charity (a1 (p) = 1 a1 ( p) = 0)? Fabien Schang schang.fabien@voila.fr fschang@hse.ru National Research University, HSE

Logical constants: for every sentence p such that A(p) = a1(p),a2(p) Negation A(p) = a2(p),a1(p) Conjunction A(pq) = a1(p)a2(q),a2(p)a2(q) Disjunction A(pq) = a1(p)a2(q),a2(p)a2(q)

Page 43: Relative Charity a1 p) = 1 a1 p) = 0)? - hse.ru · Relative Charity (a1 (p) = 1 a1 ( p) = 0)? Fabien Schang schang.fabien@voila.fr fschang@hse.ru National Research University, HSE

p p

11 11 10 01 01 10 00 00

Page 44: Relative Charity a1 p) = 1 a1 p) = 0)? - hse.ru · Relative Charity (a1 (p) = 1 a1 ( p) = 0)? Fabien Schang schang.fabien@voila.fr fschang@hse.ru National Research University, HSE

Logical constants Negation A(p) = a2(p),a1(p) Conjunction A(pq) = a1(p)a1(q),a2(p)a2(q) Disjunction A(pq) = a1(p)a2(q),a2(p)a2(q)

Page 45: Relative Charity a1 p) = 1 a1 p) = 0)? - hse.ru · Relative Charity (a1 (p) = 1 a1 ( p) = 0)? Fabien Schang schang.fabien@voila.fr fschang@hse.ru National Research University, HSE

p q pq pq

11 11 11 11 11 10 11 10 11 01 01 11 11 00 01 10 10 11 11 10 10 10 10 10 10 01 01 10 10 00 00 10 01 11 01 11 01 10 01 10 01 01 01 01 01 00 01 00 00 11 01 10 00 10 00 10 00 01 01 00 00 00 00 00

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Logical constants Negation A(p) = a2(p),a1(p) Conjunction A(pq) = a1(p)a1(q),a2(p)a2(q) Disjunction A(pq) = a1(p)a1(q),a2(p)a2(q)

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p q pq pq 11 11 11 11 11 10 11 10 11 01 01 11 11 00 01 10 10 11 11 10 10 10 10 10 10 01 01 10 10 00 00 10 01 11 01 11 01 10 01 10 01 01 01 01 01 00 01 00 00 11 01 10 00 10 00 10 00 01 01 00 00 00 00 00

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A Boolean translation of (non-)classical truth-values in AR4 v(p) = T p is true only

A(p) = 1,0 v(p) = F p is false only

A(p) = 0,1 v(p) = B p is both true and false

A(p) = 1,1 v(p) = N p is neither true nor false

A(p) = 0,0

Page 49: Relative Charity a1 p) = 1 a1 p) = 0)? - hse.ru · Relative Charity (a1 (p) = 1 a1 ( p) = 0)? Fabien Schang schang.fabien@voila.fr fschang@hse.ru National Research University, HSE

A Boolean translation of (non-)classical truth-values in AR4 v(p) = T p is true only

A(p) = 1,0 v(p) = F p is false only

A(p) = 0,1 v(p) = B p is both true and false

A(p) = 1,1 v(p) = N p is neither true nor false

A(p) = 0,0

Page 50: Relative Charity a1 p) = 1 a1 p) = 0)? - hse.ru · Relative Charity (a1 (p) = 1 a1 ( p) = 0)? Fabien Schang schang.fabien@voila.fr fschang@hse.ru National Research University, HSE

A Boolean translation of (non-)classical truth-values in AR4 v(p) = T p is true only

A(p) = 1,0 v(p) = F p is false only

A(p) = 0,1 v(p) = B p is both true and false

A(p) = 1,1 v(p) = N p is neither true nor false

A(p) = 0,0

Page 51: Relative Charity a1 p) = 1 a1 p) = 0)? - hse.ru · Relative Charity (a1 (p) = 1 a1 ( p) = 0)? Fabien Schang schang.fabien@voila.fr fschang@hse.ru National Research University, HSE

A Boolean translation of (non-)classical truth-values in AR4 v(p) = T p is true only

A(p) = 1,0 v(p) = F p is false only

A(p) = 0,1 v(p) = B p is both true and false

A(p) = 1,1 v(p) = N p is neither true nor false

A(p) = 0,0

Page 52: Relative Charity a1 p) = 1 a1 p) = 0)? - hse.ru · Relative Charity (a1 (p) = 1 a1 ( p) = 0)? Fabien Schang schang.fabien@voila.fr fschang@hse.ru National Research University, HSE

A Boolean translation of (non-)classical truth-values in AR4 v(p) = T p is true only

A(p) = 1,0 v(p) = F p is false only

A(p) = 0,1 v(p) = B p is both true and false

A(p) = 1,1 v(p) = N p is neither true nor false

A(p) = 0,0

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4

Coherence beyond Consistency

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3 grades of belief inconsistency (a) Bxp Bxp (b) Bxp Bxp (c) Bx(p Bxp) 2 norms of rationality

(CON) a1(p) = 1 a2(p) = 0 (COH) ai(p) = 1 ai(p) 0 What can “Yes and No” mean?

A bivalentist answerhood from a non-bivalentist perspective “Yes” to p from one standpoint w1, “Yes” to p from another standpoint w2 (inconsistency) “Yes” to p from w1, “No” to p to w1

(incoherence)

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3 grades of belief inconsistency (a) Bxp Bxp (b) Bxp Bxp (c) Bx(p Bxp) 2 norms of rationality

(CON) a1(p) = 1 a2(p) = 0 (COH) ai(p) = 1 ai(p) 0 What can “Yes and No” mean?

A bivalentist answerhood from a non-bivalentist perspective “Yes” to p from one standpoint w1, “Yes” to p from another standpoint w2 (inconsistency) “Yes” to p from w1, “No” to p to w1

(incoherence)

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3 grades of belief inconsistency (a) Bxp Bxp (b) Bxp Bxp (c) Bx(p Bxp) 2 norms of rationality

(CON) a1(p) = 1 a2(p) = 0 (COH) ai(p) = 1 ai(p) 0 What can “Yes and No” mean?

A bivalentist answerhood from a non-bivalentist perspective “Yes” to p from one standpoint w1, “Yes” to p from another standpoint w2 (inconsistency) “Yes” to p from w1, “No” to p to w1

(incoherence)

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3 grades of belief inconsistency (a) Bxp Bxp (b) Bxp Bxp (c) Bx(p p) 2 norms of rationality

(CON) a1(p) = 1 a2(p) = 0 (COH) ai(p) = 1 ai(p) 0 What can “Yes and No” mean?

A bivalentist answerhood from a non-bivalentist perspective “Yes” to p from one standpoint w1, “Yes” to p from another standpoint w2 (inconsistency) “Yes” to p from w1, “No” to p to w1

(incoherence)

Page 58: Relative Charity a1 p) = 1 a1 p) = 0)? - hse.ru · Relative Charity (a1 (p) = 1 a1 ( p) = 0)? Fabien Schang schang.fabien@voila.fr fschang@hse.ru National Research University, HSE

3 grades of belief inconsistency (a) Bxp Bxp (b) Bxp Bxp (c) Bx(p p) 2 norms of rationality

(CON) a1(p) = 1 a2(p) = 0 (COH) ai(p) = 1 ai(p) 0 What can “Yes and No” mean?

A bivalentist answerhood from a non-bivalentist perspective “Yes” to p from one standpoint w1, “Yes” to p from another standpoint w2 (inconsistency) “Yes” to p from w1, “No” to p to w1

(incoherence)

Page 59: Relative Charity a1 p) = 1 a1 p) = 0)? - hse.ru · Relative Charity (a1 (p) = 1 a1 ( p) = 0)? Fabien Schang schang.fabien@voila.fr fschang@hse.ru National Research University, HSE

3 grades of belief inconsistency (a) Bxp Bxp (b) Bxp Bxp (c) Bx(p p) 2 norms of rationality

(CON) a1(p) = 1 a2(p) = 0 (COH) ai(p) = 1 ai(p) 0 What can “Yes and No” mean?

A bivalentist answerhood from a non-bivalentist perspective “Yes” to p from one standpoint w1, “Yes” to p from another standpoint w2 (inconsistency) “Yes” to p from w1, “No” to p to w1

(incoherence)

Page 60: Relative Charity a1 p) = 1 a1 p) = 0)? - hse.ru · Relative Charity (a1 (p) = 1 a1 ( p) = 0)? Fabien Schang schang.fabien@voila.fr fschang@hse.ru National Research University, HSE

3 grades of belief inconsistency (a) Bxp Bxp (b) Bxp Bxp (c) Bx(p p) 2 norms of rationality

(CON) a1(p) = 1 a2(p) = 0 (COH) ai(p) = 1 ai(p) 0 What can “Yes and No” mean?

A bivalentist answerhood from a non-bivalentist perspective “Yes” to p from one standpoint w1, “Yes” to p from another standpoint w2 (inconsistency) “Yes” to p from w1, “No” to p to w1

(incoherence)

Page 61: Relative Charity a1 p) = 1 a1 p) = 0)? - hse.ru · Relative Charity (a1 (p) = 1 a1 ( p) = 0)? Fabien Schang schang.fabien@voila.fr fschang@hse.ru National Research University, HSE

3 grades of belief inconsistency (a) Bxp Bxp (b) Bxp Bxp (c) Bx(p p) 2 norms of rationality

(CON) a1(p) = 1 a2(p) = 0 (COH) ai(p) = 1 ai(p) 0 What can “Yes and No” mean?

Non-bivalentist answers to a (single) bivalentist question “Yes” to p from one standpoint w1, “Yes” to p from another standpoint w2 (inconsistency) “Yes” to p from w1, “No” to p from w1

(incoherence)

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(At least) 3 sorts of ensuing propositional attitudes Bivalentism, Paracompletism Quine, Davidson, Lokhorst: (CON) (COH) Paraconsistentism Da Costa: (CON) (COH), but not (COH) (CON) Dialethism Priest: (COH) does not hold (dialetheism) Does paracoherence make sense? ai(p) = {1,0}

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(At least) 3 sorts of ensuing propositional attitudes Bivalentism, Paracompletism Quine, Davidson, Lokhorst: (CON) (COH) Paraconsistentism Da Costa: (CON) (COH), but not (COH) (CON) Dialethism Priest: (COH) does not hold (dialetheism) Does paracoherence make sense? ai(p) = {1,0}

Page 64: Relative Charity a1 p) = 1 a1 p) = 0)? - hse.ru · Relative Charity (a1 (p) = 1 a1 ( p) = 0)? Fabien Schang schang.fabien@voila.fr fschang@hse.ru National Research University, HSE

(At least) 3 sorts of ensuing propositional attitudes Bivalentism, Paracompletism Quine, Davidson, Lokhorst: (CON) (COH) Paraconsistentism Da Costa: (CON) (COH), but not (COH) (CON) Dialethism Priest: (COH) does not hold (dialetheism) Does paracoherence make sense? ai(p) = {1,0}

Page 65: Relative Charity a1 p) = 1 a1 p) = 0)? - hse.ru · Relative Charity (a1 (p) = 1 a1 ( p) = 0)? Fabien Schang schang.fabien@voila.fr fschang@hse.ru National Research University, HSE

(At least) 3 sorts of ensuing propositional attitudes Bivalentism, Paracompletism Quine, Davidson, Lokhorst: (CON) (COH) Paraconsistentism Da Costa: (CON) (COH), but not (COH) (CON) Dialetheism Priest: (COH) does not hold (dialetheism) Does paracoherence make sense? ai(p) = {1,0}

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5 Truths in Meaning

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3 sublogics in AR4: 3 subvaluations in V Bivalentism (“classical” logic) V\{11,00} = {10,01} Paracompletism (intuitionistic logic) V\{10,11,01} = {10,00,01} Paraconsistentism V\{10,11,01} = {10,11,01}

Page 68: Relative Charity a1 p) = 1 a1 p) = 0)? - hse.ru · Relative Charity (a1 (p) = 1 a1 ( p) = 0)? Fabien Schang schang.fabien@voila.fr fschang@hse.ru National Research University, HSE

3 sublogics in AR4: 3 subvaluations in V Bivalentism (“classical” logic) V\{11,00} = {10,01} Paracompletism (intuitionistic logic) V\{10,11,01} = {10,00,01} Paraconsistentism V\{10,11,01} = {10,11,01}

Page 69: Relative Charity a1 p) = 1 a1 p) = 0)? - hse.ru · Relative Charity (a1 (p) = 1 a1 ( p) = 0)? Fabien Schang schang.fabien@voila.fr fschang@hse.ru National Research University, HSE

3 sublogics in AR4: 3 subvaluations in V Bivalentism (“classical” logic) V\{11,00} = {10,01} Paracompletism (gappy logics) V\{10,11,01} = {10,00,01} Paraconsistentism V\{10,11,01} = {10,11,01}

Page 70: Relative Charity a1 p) = 1 a1 p) = 0)? - hse.ru · Relative Charity (a1 (p) = 1 a1 ( p) = 0)? Fabien Schang schang.fabien@voila.fr fschang@hse.ru National Research University, HSE

3 sublogics in AR4: 3 subvaluations in V Bivalentism (“classical” logic) V\{11,00} = {10,01} Paracompletism (gappy logics) V\{10,11,01} = {10,00,01} Paraconsistentism (glutty logics) V\{10,00,01} = {10,11,01}

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6 Conclusion:

The Answer is in the Question

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Absolutists: (+) are right to claim that a general theory of meaning requires a universal standard for understanding (–) miss the point in focusing the problem upon truth and only truth Relativists: (+) are right to claim that alternative reasonings may prevail in different contexts of reasoning (-) lose track of common rationality by equating plurality with relativity

Page 73: Relative Charity a1 p) = 1 a1 p) = 0)? - hse.ru · Relative Charity (a1 (p) = 1 a1 ( p) = 0)? Fabien Schang schang.fabien@voila.fr fschang@hse.ru National Research University, HSE

Absolutists: (+) are right to claim that a general theory of meaning requires a universal standard for understanding (–) miss the point in focusing the problem upon truth and only truth Relativists: (+) are right to claim that alternative reasonings may prevail in different contexts of reasoning (–) lose track of common rationality by equating plurality with relativity

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QAS: (+) reconciles opposite standpoints within a common framework where the classical truth-functions v are replaced by verdict-functions A (+) the real bearer of meaning is not a sentence, but its statement (+) an answer to the problem of logical charity is in the question, viz. the statement-forming operator Q that is attached to any sentence

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References da Costa, Newton C.A. & French, S. (1989): “On the logic of belief”, Philosophy and

Phenomenological Research, Vol. 49, pp. 431-46 Davidson, D. (1973): “On radical interpretation”, Dialectica, Vol. 27, pp. 313-28 Frege, G. (1919): “Die Verneinung”, published in M. Black and P. T. Geach (eds.),

Translations from the Philosophical Writings of Gottlob Frege, Blackwell, Oxford (1960) Lokhorst, G.J. (1998): “The Logic of Logical Relativism”, Logique et Analyse, 161-162-

163, pp. 57-65 Priest, G. (1979): “The Logic of Paradox”, Journal of Philosophical Logic, Vol. 8, pp.

219-41 Quine, W.V.O. (1960): Word and Object, MIT Press Quine, W.V.O. (1973): The Roots of Reference, Open Court Publishing, La Salle (Illinois) Quine, W.V.O. (2004): Philosophy of Logic, Harvard University Press (2nd edition) Searle, J. (1969): Speech Acts, Cambridge University Press Searle, J. Vanderveken, D. (1985): Foundations of Illocutionary Logic, N.-Y.,

Cambridge University Press Suszko, R. (1977): “The Fregean axiom and Polish mathematical logic in the 1920’s”,

Studia Logica, Vol. 36, pp. 377-80 Williams, J.N. (1981): “Inconsistency and contradiction”, Mind, Vol. 90, pp. 600-2

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7 Appendix:

On Conditional

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A difference between conditional and the other logical constants: , , are committal upon their components: to give an answer to p, pq, pq is to give answers about p and q is not committal upon its components: An answer can be given to pq without giving any one about p and q Frege-Geach’s (Embedding) Problem, aka Frege’s Point:

Force-indicators operate only on complete sentences, and never occur significantly within the scope of a logical or sentential connective. Frege’s Point: ‘├(p q)’ is a correct operation, whereas ‘├p ├q’ is not Logical constants do not connect statements but, rather, sentences Statements: sentences marked with force-indicators

Page 78: Relative Charity a1 p) = 1 a1 p) = 0)? - hse.ru · Relative Charity (a1 (p) = 1 a1 ( p) = 0)? Fabien Schang schang.fabien@voila.fr fschang@hse.ru National Research University, HSE

A difference between conditional and the other logical constants: , , are committal upon their components: to give an answer to p, pq, pq is to give answers about p and q is not committal upon its components: An answer can be given to pq without giving any one about p and q Frege-Geach’s (Embedding) Problem, aka Frege’s Point:

Force-indicators operate only on complete sentences, and never occur significantly within the scope of a logical or sentential connective. Frege’s Point: ‘├(p q)’ is a correct operation, whereas ‘├p ├q’ is not Logical constants do not connect statements but, rather, sentences Statements: sentences marked with force-indicators

Page 79: Relative Charity a1 p) = 1 a1 p) = 0)? - hse.ru · Relative Charity (a1 (p) = 1 a1 ( p) = 0)? Fabien Schang schang.fabien@voila.fr fschang@hse.ru National Research University, HSE

A difference between conditional and the other logical constants: , , are committal upon their components: to give an answer to p, pq, pq is to give answers about p and q is not committal upon its components: An answer can be given to pq without giving any one about p and q Frege-Geach’s (Embedding) Problem, aka Frege’s Point:

Force-indicators operate only on complete sentences, and never occur significantly within the scope of a logical or sentential connective. Frege’s Point: ‘├(p q)’ is a correct operation, whereas ‘├p ├q’ is not Logical constants do not connect statements but, rather, sentences Statements: sentences marked with force-indicat

Page 80: Relative Charity a1 p) = 1 a1 p) = 0)? - hse.ru · Relative Charity (a1 (p) = 1 a1 ( p) = 0)? Fabien Schang schang.fabien@voila.fr fschang@hse.ru National Research University, HSE

A difference between conditional and the other logical constants: , , are committal upon their components: to give an answer to p, pq, pq is to give answers about p and q is not committal upon its components: An answer can be given to pq without giving any one about p and q Frege-Geach’s (Embedding) Problem, aka Frege’s Point:

Force-indicators operate only on complete sentences, and never occur significantly within the scope of a logical or sentential connective. Frege’s Point: ‘├(p q)’ is a correct operation, whereas ‘├p ├q’ is not Logical constants do not connect statements but, rather, sentences Statements: sentences marked with force-indicators ors

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A difference between conditional and the other logical constants: , , are committal upon their components: to give an answer to p, pq, pq is to give answers about p and q is not committal upon its components: An answer can be given to pq without giving any one about p and q Frege-Geach’s (Embedding) Problem, aka Frege’s Point:

Force-indicators operate only on complete sentences, and never occur significantly within the scope of a logical or sentential connective Frege’s Point: ‘├(p q)’ is a correct operation, whereas ‘├p ├q’ is not Logical constants do not connect statements but, rather, sentences Statements: sentences marked with force-indicators

Page 82: Relative Charity a1 p) = 1 a1 p) = 0)? - hse.ru · Relative Charity (a1 (p) = 1 a1 ( p) = 0)? Fabien Schang schang.fabien@voila.fr fschang@hse.ru National Research University, HSE

A difference between conditional and the other logical constants: , , are committal upon their components: to give an answer to p, pq, pq is to give answers about p and q is not committal upon its components: An answer can be given to pq without giving any one about p and q Frege-Geach’s (Embedding) Problem, aka Frege’s Point:

Force-indicators operate only on complete sentences, and never occur significantly within the scope of a logical or sentential connective Frege’s Point: ‘├(p q)’ is a wff, whereas ‘├p ├q’ is not Logical constants do not connect statements but, rather, sentences

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Frege (1919): (a) “If the accused was in Rome at the time of the deed, he did not commit the murder. He was in Rome at this time. Therefore he did not commit the crime.” p: the accused was in Rome at the time of the deed q: he (the accused) did committ the murder An inference the form: ├(p q), ├p, ├q (Modus Ponens) (b) “If the accused was in Rome at the time of the deed, he did not commit the murder. He did commit the murder. Therefore he was not in Rome at this time.” An inference the form: ├ (p q), ├q, ├p (Modus Tollens)

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Frege (1919): (a) “If the accused was in Rome at the time of the deed, he did not commit the murder. He was in Rome at this time. Therefore he did not commit the crime.” p: the accused was in Rome at the time of the deed q: he did commit the murder An inference the form: ├(p q), ├p, ├q (Modus Ponens) (b) “If the accused was in Rome at the time of the deed, he did not commit the murder. He did commit the murder. Therefore he was not in Rome at this time.” An inference the form: ├ (p q), ├q, ├p (Modus Tollens)

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Frege (1919): (a) “If the accused was in Rome at the time of the deed, he did not commit the murder. He was in Rome at this time. Therefore he did not commit the crime.” p: the accused was in Rome at the time of the deed q: he did commit the murder An inference the form: ├(p q), ├p, ├q (Modus Ponens) (b) “If the accused was in Rome at the time of the deed, he did not commit the murder. He did commit the murder. Therefore he was not in Rome at this time.” An inference the form: ├ (p q), ├q, ├p (Modus Tollens)

Page 86: Relative Charity a1 p) = 1 a1 p) = 0)? - hse.ru · Relative Charity (a1 (p) = 1 a1 ( p) = 0)? Fabien Schang schang.fabien@voila.fr fschang@hse.ru National Research University, HSE

Frege (1919): (a) “If the accused was in Rome at the time of the deed, he did not commit the murder. He was in Rome at this time. Therefore he did not commit the crime.” p: the accused was in Rome at the time of the deed q: he did commit the murder An inference the form: ├(p q), ├p, ├q (Modus Ponens) (b) “If the accused was in Rome at the time of the deed, he did not commit the murder. He did commit the murder. Therefore he was not in Rome at this time.” An inference the form: ├ (p q), ├q, ├p (Modus Tollens)

Page 87: Relative Charity a1 p) = 1 a1 p) = 0)? - hse.ru · Relative Charity (a1 (p) = 1 a1 ( p) = 0)? Fabien Schang schang.fabien@voila.fr fschang@hse.ru National Research University, HSE

What of (c) “If the accused was in Rome at the time of the deed, he did not commit the murder. The accused was not in Rome at the time of the deed. (…)” An inference the form: ├ (p q), ├p, … therefore ├ q ? (d) “If the accused was in Rome at the time of the deed, he did not commit the murder. I do not say that he was in Rome at the time of the deed. (…)” An inference the form: ├ (p q), ┤q, … therefore ├ p ? 2 paradoxical side-effects of the “classical” (mainstream) conditional: (c) entails everything if p is asserted, in classical (bivalent) logics (d) is reducible to (c), according to Frege’s thesis of equivalence

Page 88: Relative Charity a1 p) = 1 a1 p) = 0)? - hse.ru · Relative Charity (a1 (p) = 1 a1 ( p) = 0)? Fabien Schang schang.fabien@voila.fr fschang@hse.ru National Research University, HSE

What of (c) “If the accused was in Rome at the time of the deed, he did not commit the murder. The accused was not in Rome at the time of the deed. (…)” An inference the form: ├ (p q), ├p, … therefore ├ q ? (d) “If the accused was in Rome at the time of the deed, he did not commit the murder. I do not say that he was in Rome at the time of the deed. (…)” An inference the form: ├ (p q), ┤q, … therefore ├ p ? 2 paradoxical side-effects of the “classical” (mainstream) conditional: (c) entails everything if p is asserted, in classical (bivalent) logics (d) is reducible to (c), according to Frege’s thesis of equivalence

Page 89: Relative Charity a1 p) = 1 a1 p) = 0)? - hse.ru · Relative Charity (a1 (p) = 1 a1 ( p) = 0)? Fabien Schang schang.fabien@voila.fr fschang@hse.ru National Research University, HSE

What of (c) “If the accused was in Rome at the time of the deed, he did not commit the murder. The accused was not in Rome at the time of the deed. (…)” An inference the form: ├ (p q), ├p, … therefore ├ q ? (d) “If the accused was in Rome at the time of the deed, he did not commit the murder. I do not say that he did commit the murder. (…)” An inference the form: ├ (p q), ┤q, … therefore ├ p ? 2 paradoxical side-effects of the “classical” (mainstream) conditional: (c) entails everything if p is asserted, in classical (bivalent) logics (d) is reducible to (c), according to Frege’s thesis of equivalence

Page 90: Relative Charity a1 p) = 1 a1 p) = 0)? - hse.ru · Relative Charity (a1 (p) = 1 a1 ( p) = 0)? Fabien Schang schang.fabien@voila.fr fschang@hse.ru National Research University, HSE

What of (c) “If the accused was in Rome at the time of the deed, he did not commit the murder. The accused was not in Rome at the time of the deed. (…)” An inference the form: ├ (p q), ├p, … therefore ├ q ? (d) “If the accused was in Rome at the time of the deed, he did not commit the murder. I do not say that he did commit the murder. (…)” An inference the form: ├ (p q), ┤q, … therefore ├ p ? 2 paradoxical side-effects of the “classical” (mainstream) conditional: (c) entails everything if p is asserted, in classical (bivalent) logics (d) is reducible to (c), according to Frege’s thesis of equivalence

Page 91: Relative Charity a1 p) = 1 a1 p) = 0)? - hse.ru · Relative Charity (a1 (p) = 1 a1 ( p) = 0)? Fabien Schang schang.fabien@voila.fr fschang@hse.ru National Research University, HSE

What of (c) “If the accused was in Rome at the time of the deed, he did not commit the murder. The accused was not in Rome at the time of the deed. (…)” An inference the form: ├ (p q), ├p, … therefore ├ q ? (d) “If the accused was in Rome at the time of the deed, he did not commit the murder. I do not say that he did commit the murder. (…)” An inference the form: ├ (p q), ┤q, … therefore ├ p ? 2 paradoxical side-effects of the “classical” (mainstream) conditional: (c) entails everything if p is asserted, in classical (bivalent) logics (d) is reducible to (c), according to Frege’s thesis of equivalence

Page 92: Relative Charity a1 p) = 1 a1 p) = 0)? - hse.ru · Relative Charity (a1 (p) = 1 a1 ( p) = 0)? Fabien Schang schang.fabien@voila.fr fschang@hse.ru National Research University, HSE

What of (c) “If the accused was in Rome at the time of the deed, he did not commit the murder. The accused was not in Rome at the time of the deed. (…)” An inference the form: ├ (p q), ├p, … therefore ├ q ? (d) “If the accused was in Rome at the time of the deed, he did not commit the murder. I do not say that he did commit the murder. (…)” An inference the form: ├ (p q), ┤q, … therefore ├ p ? 2 paradoxical side-effects of the “classical” (mainstream) conditional: (c) entails everything if p is asserted, in classical (bivalent) logics (d) is reducible to (c), according to Frege’s thesis of equivalence

Page 93: Relative Charity a1 p) = 1 a1 p) = 0)? - hse.ru · Relative Charity (a1 (p) = 1 a1 ( p) = 0)? Fabien Schang schang.fabien@voila.fr fschang@hse.ru National Research University, HSE

What of (c) “If the accused was in Rome at the time of the deed, he did not commit the murder. The accused was not in Rome at the time of the deed. (…)” An inference the form: ├ (p q), ├p, … therefore ├ q ? (d) “If the accused was in Rome at the time of the deed, he did not commit the murder. I do not say that he did commit the murder. (…)” An inference the form: ├ (p q), ┤q, … therefore ├ p ? 2 paradoxical side-effects of the “classical” (mainstream) conditional: (c) entails everything if p is asserted, in classical (bivalent) logics (d) is reducible to (c), according to Frege’s Equivalence Thesis

Page 94: Relative Charity a1 p) = 1 a1 p) = 0)? - hse.ru · Relative Charity (a1 (p) = 1 a1 ( p) = 0)? Fabien Schang schang.fabien@voila.fr fschang@hse.ru National Research University, HSE

An alternative definition of conditional: commitment as a bet QAS is a question-answer game upon components: - this game relies upon behavioral rules, i.e. answerhood-conditions - whoever does not reply correctly does not even play the game A strengthened set of rules for the conditional p q: - the answerer must assert the antecedent to use conditional meaningfully - whoever does not assert p is compelled to reject any commitment about the whole pq If the speaker does not assert p in pq, then: - (s)he is not committed at all about q - (s)he does not assert pq and, therefore, rejects it(s being true) - to reject (p q) is not tantamount to assert its negation!

Page 95: Relative Charity a1 p) = 1 a1 p) = 0)? - hse.ru · Relative Charity (a1 (p) = 1 a1 ( p) = 0)? Fabien Schang schang.fabien@voila.fr fschang@hse.ru National Research University, HSE

An alternative definition of conditional: commitment as a bet QAS is a question-answer game upon components: - this game relies upon behavioral rules, i.e. answerhood-conditions - whoever does not reply correctly does not even play the game A strengthened set of rules for the conditional p q: - the answerer must assert the antecedent to use conditional meaningfully - whoever does not assert p is compelled to reject any commitment about the whole pq If the speaker does not assert p in pq, then: - (s)he is not committed at all about q - (s)he does not assert pq and, therefore, rejects it(s being true) - to reject (p q) is not tantamount to assert its negation!

Page 96: Relative Charity a1 p) = 1 a1 p) = 0)? - hse.ru · Relative Charity (a1 (p) = 1 a1 ( p) = 0)? Fabien Schang schang.fabien@voila.fr fschang@hse.ru National Research University, HSE

An alternative definition of conditional: commitment as a bet QAS is a question-answer game upon components: - this game relies upon behavioral rules, i.e. answerhood-conditions - whoever does not reply correctly does not even play the game A strengthened set of rules for the conditional p q: - the answerer must assert the antecedent to use conditional meaningfully - whoever does not assert p is compelled to reject any commitment about the whole pq If the speaker does not assert p in pq, then: - (s)he is not committed at all about q - (s)he does not assert pq and, therefore, rejects it(s being true) - to reject (p q) is not tantamount to assert its negation!

Page 97: Relative Charity a1 p) = 1 a1 p) = 0)? - hse.ru · Relative Charity (a1 (p) = 1 a1 ( p) = 0)? Fabien Schang schang.fabien@voila.fr fschang@hse.ru National Research University, HSE

An alternative definition of conditional: commitment as a bet QAS is a question-answer game upon components: - this game relies upon behavioral rules, i.e. answerhood-conditions - whoever does not reply correctly does not even play the game A strengthened set of rules for the conditional p q: - the answerer must assert the antecedent to use conditional meaningfully - whoever does not assert p is compelled to reject any commitment about the whole pq If the speaker does not assert p in pq, then: - (s)he is not committed at all about q - (s)he does not assert pq and, therefore, rejects it(s being true) - to reject (p q) is not tantamount to asserting its negation!

Page 98: Relative Charity a1 p) = 1 a1 p) = 0)? - hse.ru · Relative Charity (a1 (p) = 1 a1 ( p) = 0)? Fabien Schang schang.fabien@voila.fr fschang@hse.ru National Research University, HSE

Yes: if p, then q p q -------------- If (yes: p), then (yes: q) p q Yes: not-(If p, then q) (p q) --------------- If (yes: p), then (yes: p) p q

Page 99: Relative Charity a1 p) = 1 a1 p) = 0)? - hse.ru · Relative Charity (a1 (p) = 1 a1 ( p) = 0)? Fabien Schang schang.fabien@voila.fr fschang@hse.ru National Research University, HSE

a1(p q) = 1 p q -------------- a1(p) = 1 a1(q) = 1 p q a2(p q) = 1 (p q) --------------- a1(p) = 1 a2(q) = 1 p q

Page 100: Relative Charity a1 p) = 1 a1 p) = 0)? - hse.ru · Relative Charity (a1 (p) = 1 a1 ( p) = 0)? Fabien Schang schang.fabien@voila.fr fschang@hse.ru National Research University, HSE

a1(p q) = 1 p q -------------- a1(p) = 1 a1(q) = 1 p q Yes: not-(if p, then q) (p q) --------------- If (yes: p), then (yes: p) p q

Page 101: Relative Charity a1 p) = 1 a1 p) = 0)? - hse.ru · Relative Charity (a1 (p) = 1 a1 ( p) = 0)? Fabien Schang schang.fabien@voila.fr fschang@hse.ru National Research University, HSE

a1(p q) = 1 p q -------------- a1(p) = 1 a1(q) = 1 p q a2(p q) = 1 (p q) --------------- a1(p) = 1 a2(q) = 1 p q

Page 102: Relative Charity a1 p) = 1 a1 p) = 0)? - hse.ru · Relative Charity (a1 (p) = 1 a1 ( p) = 0)? Fabien Schang schang.fabien@voila.fr fschang@hse.ru National Research University, HSE

Logical constants Negation A(p) = a2(p),a1(p) Conjunction A(pq) = a1(p)a1(q),a2(p)a2(q) Disjunction A(pq) = a1(p)a1(q),a2(p)a2(q) … Conditional A(pq) = a1(p)a1(q),a1(p)a2(q)

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p q pq pq

11 11 11 11 11 10 10 10 11 01 01 11 11 00 00 10 10 11 11 10 10 10 10 10 10 01 01 10 10 00 00 10 01 11 00 11 01 10 00 10 01 01 00 01 01 00 00 00 00 11 00 10 00 10 00 10 00 01 00 00 00 00 00 00

Page 104: Relative Charity a1 p) = 1 a1 p) = 0)? - hse.ru · Relative Charity (a1 (p) = 1 a1 ( p) = 0)? Fabien Schang schang.fabien@voila.fr fschang@hse.ru National Research University, HSE

AR4 p q pq pq pq qp pq V = {11,10,01,00} D = {10,11} 11 11 11 11 11 11 10 10 10 10 11 01 01 11 01 11 00 00 10 00 10 11 11 10 11 10 10 10 10 10 10 10 10 01 01 10 01 00 00 10 00 00 10 00 00 00 01 11 01 11 00 01 10 01 10 00 01 00 01 01 01 01 00 00 00 01 00 01 00 00 00 00 00 11 01 10 00 00 10 00 10 00 00 00 00 01 01 00 00 00 00 00 00 00 00 00 00 00

Page 105: Relative Charity a1 p) = 1 a1 p) = 0)? - hse.ru · Relative Charity (a1 (p) = 1 a1 ( p) = 0)? Fabien Schang schang.fabien@voila.fr fschang@hse.ru National Research University, HSE

p q pq pq 11 11 11 11 11 10 11 10 11 01 01 11 11 00 01 10 ? 10 11 11 10 10 10 10 10 10 01 01 10 10 00 00 10 01 11 01 11 01 10 01 10 01 01 01 01 01 00 01 00 00 11 01 10 ? 00 10 00 10 00 01 01 00 00 00 00 00

Page 106: Relative Charity a1 p) = 1 a1 p) = 0)? - hse.ru · Relative Charity (a1 (p) = 1 a1 ( p) = 0)? Fabien Schang schang.fabien@voila.fr fschang@hse.ru National Research University, HSE

Let A(p) = 11 and A(q) = 00. Then: A(pq) = 01 a1(p) = 1 and a1(q) = 0, hence a1(pq) = 0 a2(p) = 1 and a2(q) = 0, hence a2(pq) = 1 Therefore A(1100) = 01 A(pq) = 01 a1(p) = 1 and a1(q) = 0, hence a1(pq) = 1 a2(p) = 1 and a2(q) = 0, hence a2(pq) = 0 Therefore A(1100) = 10

Page 107: Relative Charity a1 p) = 1 a1 p) = 0)? - hse.ru · Relative Charity (a1 (p) = 1 a1 ( p) = 0)? Fabien Schang schang.fabien@voila.fr fschang@hse.ru National Research University, HSE

Ł3 p q pq pq pq qp pq V = {10,00,01} D = {10,11} 11 11 11 11 11 11 10 10 10 10 11 01 01 11 01 11 00 00 10 00 10 11 11 10 11 10 10 10 10 10 10 10 10 01 01 10 01 10 01 10 00 00 10 00 10 00 01 11 01 11 00 01 10 01 10 10 01 01 01 01 01 01 10 10 10 01 00 01 00 10 00 00 00 11 01 10 00 00 10 00 10 10 00 00 00 01 01 00 00 10 00 00 00 00 00 10 10 10

Page 108: Relative Charity a1 p) = 1 a1 p) = 0)? - hse.ru · Relative Charity (a1 (p) = 1 a1 ( p) = 0)? Fabien Schang schang.fabien@voila.fr fschang@hse.ru National Research University, HSE

AR4 p q pq pq pq qp pq V = {11,10,01,00} D = {10,11} 11 11 11 11 11 11 10 10 10 10 11 01 01 11 01 11 00 00 10 00 10 11 11 10 11 10 10 10 10 10 10 10 10 01 01 10 01 00 00 10 00 00 10 00 00 00 01 11 01 11 00 01 10 01 10 00 01 00 01 01 01 01 00 00 00 01 00 01 00 00 00 00 00 11 01 10 00 00 10 00 10 00 00 00 00 01 01 00 00 00 00 00 00 00 00 00 00 00

Page 109: Relative Charity a1 p) = 1 a1 p) = 0)? - hse.ru · Relative Charity (a1 (p) = 1 a1 ( p) = 0)? Fabien Schang schang.fabien@voila.fr fschang@hse.ru National Research University, HSE

Ks3 p q pq pq pq qp pq V = {10,00,01} D = {10} 11 11 11 11 11 11 10 10 10 10 11 01 01 11 01 11 00 00 10 00 10 11 11 10 11 10 10 10 10 10 10 10 10 01 01 10 01 10 01 10 00 00 10 00 10 00 01 11 01 11 00 01 10 01 10 00 01 00 01 01 01 01 10 10 10 01 00 01 00 00 00 00 00 11 01 10 00 00 10 00 10 10 00 00 00 01 01 00 10 10 10 00 00 00 00 10 00 00

Page 110: Relative Charity a1 p) = 1 a1 p) = 0)? - hse.ru · Relative Charity (a1 (p) = 1 a1 ( p) = 0)? Fabien Schang schang.fabien@voila.fr fschang@hse.ru National Research University, HSE

AR4 p q pq pq pq qp pq V = {11,10,01,00} D = {11,10} 11 11 11 11 11 11 10 10 10 10 11 01 01 11 01 11 00 00 10 00 10 11 11 10 11 10 10 10 10 10 10 10 10 01 01 10 01 00 00 10 00 00 10 00 00 00 01 11 01 11 00 01 10 01 10 00 01 00 01 01 01 01 00 00 00 01 00 01 00 00 00 00 00 11 01 10 00 00 10 00 10 00 00 00 00 01 01 00 00 00 00 00 00 00 00 00 00 00

Page 111: Relative Charity a1 p) = 1 a1 p) = 0)? - hse.ru · Relative Charity (a1 (p) = 1 a1 ( p) = 0)? Fabien Schang schang.fabien@voila.fr fschang@hse.ru National Research University, HSE

B3 p q pq pq pq qp pq V = {10,00,01} D = {10} 11 11 11 11 11 11 10 10 10 10 11 01 01 11 01 11 00 00 10 00 10 11 11 10 11 10 10 10 10 10 10 10 10 01 01 10 01 10 01 10 00 00 00 00 00 00 01 11 01 11 00 01 10 01 10 10 01 01 01 01 01 01 10 01 01 01 00 00 00 00 00 00 00 11 01 10 00 00 10 00 10 00 10 00 00 01 01 00 00 00 00 00 00 00 00 00 00 00

Page 112: Relative Charity a1 p) = 1 a1 p) = 0)? - hse.ru · Relative Charity (a1 (p) = 1 a1 ( p) = 0)? Fabien Schang schang.fabien@voila.fr fschang@hse.ru National Research University, HSE

AR4 p q pq pq pq qp pq V = {11,10,01,00} D = {11,10} 11 11 11 11 11 11 10 10 10 10 11 01 01 11 01 11 00 00 10 00 10 11 11 10 11 10 10 10 10 10 10 10 10 01 01 10 01 00 00 10 00 00 10 00 00 00 01 11 01 11 00 01 10 01 10 00 01 00 01 01 01 01 00 00 00 01 00 01 00 00 00 00 00 11 01 10 00 00 10 00 10 00 00 00 00 01 01 00 00 00 00 00 00 00 00 00 00 00

Page 113: Relative Charity a1 p) = 1 a1 p) = 0)? - hse.ru · Relative Charity (a1 (p) = 1 a1 ( p) = 0)? Fabien Schang schang.fabien@voila.fr fschang@hse.ru National Research University, HSE

P3 p q pq pq pq qp pq V = {10,11,01} D = {10,11} 11 11 11 11 11 11 11 11 10 11 10 10 11 11 11 01 01 11 01 10 01 11 00 00 10 00 10 11 11 10 11 10 11 10 10 10 10 10 10 10 10 01 01 10 01 10 01 10 00 00 10 00 01 11 01 11 10 11 11 01 10 01 10 10 01 01 01 01 01 01 10 10 10 01 00 01 00 00 00 11 01 10 00 00 10 00 10 00 00 0 00 00 00 00 00

Page 114: Relative Charity a1 p) = 1 a1 p) = 0)? - hse.ru · Relative Charity (a1 (p) = 1 a1 ( p) = 0)? Fabien Schang schang.fabien@voila.fr fschang@hse.ru National Research University, HSE

AR4 p q pq pq pq qp pq V = {11,10,01,00} D = {11,10} 11 11 11 11 11 11 11 11 10 11 10 10 11 11 11 01 01 11 01 00 01 11 00 00 10 00 10 11 11 10 11 10 11 10 10 10 10 10 10 10 10 01 01 10 01 00 01 10 00 00 10 00 01 11 01 11 00 01 00 01 10 01 10 00 01 00 01 01 01 01 00 00 00 01 00 01 00 00 00 11 01 10 00 00 10 00 10 00 00 0 00 00 00

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K3 Ł3 P3 AR4

q ╞ p q p ╞ p q (p q) r ╞ (p r) (q r) (p q) (r s) ╞ (p s) (r q) (p q) ╞ p p r ╞ (p q) r p q, q r ╞ p r p q ╞ q p ╞ p (q q) ╞ (p p) q

Page 116: Relative Charity a1 p) = 1 a1 p) = 0)? - hse.ru · Relative Charity (a1 (p) = 1 a1 ( p) = 0)? Fabien Schang schang.fabien@voila.fr fschang@hse.ru National Research University, HSE

Advantages of the strengthened : 1. It avoids the Paradoxes of Material Implication v( F q) = T (“Ex falso sequitur quodlibet”) a1(p q) 1 when a1(p) = 0 and a1(q) = 1 v(p T) = T (“Verum sequitur ex quodlibet”) a1(p q) 1 when a1(p) = 0 2. It requires rejectivism, by assigning an essential occurrence to denial Assertibility- and deniability-conditions are not the same for and : A(p q) A(p q) only in the light of QAS the difference holds only if denial and negative assertion differ

Page 117: Relative Charity a1 p) = 1 a1 p) = 0)? - hse.ru · Relative Charity (a1 (p) = 1 a1 ( p) = 0)? Fabien Schang schang.fabien@voila.fr fschang@hse.ru National Research University, HSE

Advantages of the strengthened : 1. It avoids the Paradoxes of Material Implication v(F q) = T (“Ex falso sequitur quodlibet”) a1(p q) 1 when a1(p) = 0 and a1(q) = 1 v(p T) = T (“Verum sequitur ex quodlibet”) a1(p q) 1 when a1(p) = 0 2. It requires rejectivism, by assigning an essential occurrence to denial Assertibility- and deniability-conditions are not the same for and : A(p q) A(p q) only in the light of QAS the difference holds only if denial and negative assertion differ

Page 118: Relative Charity a1 p) = 1 a1 p) = 0)? - hse.ru · Relative Charity (a1 (p) = 1 a1 ( p) = 0)? Fabien Schang schang.fabien@voila.fr fschang@hse.ru National Research University, HSE

Advantages of the strengthened : 1. It avoids the Paradoxes of Material Implication v(F q) = T (“Ex falso sequitur quodlibet”) a1(p q) 1 when a1(p) = 0 and a1(q) = 1 v(p T) = T (“Verum sequitur ex quodlibet”) a1(p q) 1 when a1(p) = 0 2. It requires rejectivism, by assigning an essential occurrence to denial Assertibility- and deniability-conditions are not the same for and : A(p q) A(p q) only in the light of QAS the difference holds only if denial and negative assertion differ

Page 119: Relative Charity a1 p) = 1 a1 p) = 0)? - hse.ru · Relative Charity (a1 (p) = 1 a1 ( p) = 0)? Fabien Schang schang.fabien@voila.fr fschang@hse.ru National Research University, HSE

AR4 p q pq pq pq qp pq V = {10,11,00,01} D = {10,11}

11 11 11 11 11 11 11 11 10 11 10 10 11 10 11 01 01 11 01 00 00 11 00 00 10 00 00 00 10 11 11 10 11 10 10 10 10 10 10 10 10 10 10 01 01 10 01 00 00 10 00 00 10 00 00 00 01 11 01 11 00 01 01 01 10 01 10 00 01 01 01 01 01 01 00 00 00 01 00 01 00 00 00 00 00 11 01 10 00 00 00 00 10 00 10 00 00 00

Page 120: Relative Charity a1 p) = 1 a1 p) = 0)? - hse.ru · Relative Charity (a1 (p) = 1 a1 ( p) = 0)? Fabien Schang schang.fabien@voila.fr fschang@hse.ru National Research University, HSE

AR4 p q pq pq pq qp pq V = {10,11,00,01} D = {10,11}

11 11 11 11 11 11 11 11 10 11 10 10 11 10 11 01 01 11 01 00 00 11 00 00 10 00 00 00 10 11 11 10 11 10 10 10 10 10 10 10 10 10 10 01 01 10 01 00 00 10 00 00 10 00 00 00 01 11 01 11 00 01 01 01 10 01 10 00 01 01 01 01 01 01 00 00 00 01 00 01 00 00 00 00 00 11 01 10 00 00 00 00 10 00 10 00 00 00

Page 121: Relative Charity a1 p) = 1 a1 p) = 0)? - hse.ru · Relative Charity (a1 (p) = 1 a1 ( p) = 0)? Fabien Schang schang.fabien@voila.fr fschang@hse.ru National Research University, HSE

Inconvenients of the strengthened : 1. The difference is irrelevant, according to Suszko’s Thesis There is no substantial difference between 01 and 00 Both logical values belong to the same class of undesignated values play the same role in logic as a theory of consequence 2. Accordingly, it conflates conditional and biconditional a1(p q) = 1 iff a1(q p) = 1, therefore a1(p q) = 1 iff a1(p q) = 1

Page 122: Relative Charity a1 p) = 1 a1 p) = 0)? - hse.ru · Relative Charity (a1 (p) = 1 a1 ( p) = 0)? Fabien Schang schang.fabien@voila.fr fschang@hse.ru National Research University, HSE

Inconvenients of the strengthened : 1. The difference is irrelevant, according to Suszko’s Thesis There is no substantial difference between 01 and 00 Both logical values belong to the same class of undesignated values play the same role in any theory of consequence 2. Accordingly, it conflates conditional and biconditional a1(p q) = 1 iff a1(q p) = 1, therefore a1(p q) = 1 iff a1(p q) = 1

Page 123: Relative Charity a1 p) = 1 a1 p) = 0)? - hse.ru · Relative Charity (a1 (p) = 1 a1 ( p) = 0)? Fabien Schang schang.fabien@voila.fr fschang@hse.ru National Research University, HSE

Inconvenients of the strengthened : 1. The difference is irrelevant, according to Suszko’s Thesis There is no substantial difference between 01 and 00 Both logical values belong to the same class of undesignated values play the same role in any theory of consequence 2. Accordingly, it conflates conditional and biconditional a1(p q) = 1 iff a1(q p) = 1, therefore a1(p q) = 1 iff a1(p q) = 1

Page 124: Relative Charity a1 p) = 1 a1 p) = 0)? - hse.ru · Relative Charity (a1 (p) = 1 a1 ( p) = 0)? Fabien Schang schang.fabien@voila.fr fschang@hse.ru National Research University, HSE

AR4 p q pq pq pq qp pq V = {10,11,00,01} D = {10,11}

11 11 11 11 11 11 11 11 10 11 10 10 11 10 11 01 01 11 01 00 00 11 00 00 10 00 00 00 10 11 11 10 11 10 10 10 10 10 10 10 10 10 10 01 01 10 01 00 00 10 00 00 10 00 00 00 01 11 01 11 00 01 01 01 10 01 10 00 01 01 01 01 01 01 00 00 00 01 00 01 00 00 00 00 00 11 01 10 00 00 00 00 10 00 10 00 00 00

Page 125: Relative Charity a1 p) = 1 a1 p) = 0)? - hse.ru · Relative Charity (a1 (p) = 1 a1 ( p) = 0)? Fabien Schang schang.fabien@voila.fr fschang@hse.ru National Research University, HSE

A way out: rejectivism against Suszko’s Thesis There is an essential difference between denial and assertion 01 and 00 are not only designated values, but also: A(pq) = 01 is the value of a negative assertion: an anti-designated value (pq) D– A(pq) = 00 is not the value of an assertion at all: a non-designated value (pq) D If A(pq) = 01, then ╞AR4 p q and p ╞AR4 q I cannot assert p without rejecting q If A(pq) = 00, then ╡AR4 p q but not p ╡AR4 q I can reject p without rejecting q

Page 126: Relative Charity a1 p) = 1 a1 p) = 0)? - hse.ru · Relative Charity (a1 (p) = 1 a1 ( p) = 0)? Fabien Schang schang.fabien@voila.fr fschang@hse.ru National Research University, HSE

A way out: rejectivism against Suszko’s Thesis There is an essential difference between denial and assertion 01 and 00 are not only designated values, but also: A(pq) = 01 is the value of a negative assertion: an anti-designated value (pq) D– A(pq) = 00 is not the value of an assertion at all: a non-designated value (pq) D If A(pq) = 01, then ╞AR4 p q and p ╞AR4 q I cannot assert p without rejecting q If A(pq) = 00, then ╡AR4 p q but not p ╡AR4 q I can reject p without rejecting q

Page 127: Relative Charity a1 p) = 1 a1 p) = 0)? - hse.ru · Relative Charity (a1 (p) = 1 a1 ( p) = 0)? Fabien Schang schang.fabien@voila.fr fschang@hse.ru National Research University, HSE

A way out: rejectivism against Suszko’s Thesis There is an essential difference between denial and assertion 01 and 00 are not only designated values, but also: A(pq) = 01 is the value of a negative assertion: an anti-designated value (pq) D– A(pq) = 00 is not the value of an assertion at all: a non-designated value (pq) D If A(pq) = 01, then ╞AR4 p q and p ╞AR4 q I cannot assert p without rejecting q If A(pq) = 00, then ╡AR4 p q but not p ╡AR4 q I can reject p without rejecting q

Page 128: Relative Charity a1 p) = 1 a1 p) = 0)? - hse.ru · Relative Charity (a1 (p) = 1 a1 ( p) = 0)? Fabien Schang schang.fabien@voila.fr fschang@hse.ru National Research University, HSE

A way out: rejectivism against Suszko’s Thesis There is an essential difference between denial and assertion 01 and 00 are not only designated values, but also: A(pq) = 01 is the value of a negative assertion: an anti-designated value (pq) D– A(pq) = 00 is not the value of an assertion at all: a non-designated value (pq) D If A(pq) = 01, then ╞AR4 p q and p ╞AR4 q I cannot assert p without rejecting q If A(pq) = 00, then ╡AR4 p q but not p ╡AR4 q I can reject p without rejecting q

Page 129: Relative Charity a1 p) = 1 a1 p) = 0)? - hse.ru · Relative Charity (a1 (p) = 1 a1 ( p) = 0)? Fabien Schang schang.fabien@voila.fr fschang@hse.ru National Research University, HSE

Prospects A revision (not a mere extension) of classical logic, within QAS

2 basic relations in logic:

- consequence (truth- and falsity-preservation) - rejection (non-truth and non-falsity preservation) 1 universal relation, upstream of consequence and rejection:

Partition, as a structuration of universe: - formal ontology (predicative dimension of a logical value) - formal logic (answerhood dimension of a logical value) A universal theory of negation: - opposite-forming operators (predicative dimension) - iterated answerhood (beyond Pavlov’s Logic of Truth and Falsehood)

Page 130: Relative Charity a1 p) = 1 a1 p) = 0)? - hse.ru · Relative Charity (a1 (p) = 1 a1 ( p) = 0)? Fabien Schang schang.fabien@voila.fr fschang@hse.ru National Research University, HSE

Prospects A revision (not a mere extension) of classical logic, within QAS:

- conditional (or implication) and sharing principle (in formal ontology) - co-implication (dual of implication) 2 basic relations in logic:

- consequence (truth- and falsity-preservation) - rejection (non-truth and non-falsity preservation) 1 universal relation, upstream of consequence and rejection

Partition, as a structuration of meaning: - formal ontology (predicative dimension of a logical value) - formal logic (answerhood dimension of a logical value) A universal theory of negation: - opposite-forming operators (predicative dimension) - iterated answerhood (beyond Pavlov’s Logic of Truth and Falsehood)

Page 131: Relative Charity a1 p) = 1 a1 p) = 0)? - hse.ru · Relative Charity (a1 (p) = 1 a1 ( p) = 0)? Fabien Schang schang.fabien@voila.fr fschang@hse.ru National Research University, HSE

Prospects A revision (not a mere extension) of classical logic, within QAS:

- conditional (or implication) and sharing principle (in formal ontology) - co-implication (dual of implication) 2 basic relations in logic:

- consequence (truth- and falsity-preservation) - rejection (non-truth and non-falsity preservation) 1 universal relation, upstream of consequence and rejection

Partition, as a structuration of meaning: - formal ontology (predicative dimension of a logical value) - formal logic (answerhood dimension of a logical value) A universal theory of negation: - opposite-forming operators (predicative dimension) - iterated answerhood (beyond Pavlov’s Logic of Truth and Falsehood)

Page 132: Relative Charity a1 p) = 1 a1 p) = 0)? - hse.ru · Relative Charity (a1 (p) = 1 a1 ( p) = 0)? Fabien Schang schang.fabien@voila.fr fschang@hse.ru National Research University, HSE

Prospects A revision (not a mere extension) of classical logic, within QAS:

- conditional (or implication) and sharing principle (in formal ontology) - co-implication (dual of implication) 2 basic relations in logic:

- consequence (truth- and falsity-preservation) - rejection (non-truth and non-falsity preservation) 1 universal relation, upstream of consequence and rejection

Partition, as a structuration of meaning: - formal ontology (predicative dimension of a logical value) - formal logic (answerhood dimension of a logical value) A universal theory of negation: - opposite-forming operators (predicative dimension) - iterated answerhood (beyond Pavlov’s Logic of Truth and Falsehood)

Page 133: Relative Charity a1 p) = 1 a1 p) = 0)? - hse.ru · Relative Charity (a1 (p) = 1 a1 ( p) = 0)? Fabien Schang schang.fabien@voila.fr fschang@hse.ru National Research University, HSE

5th World Congress and School on Universal Logic (20-30 June 2015) Workshop: “Non-Classical Abstract Logics” (Fabien Schang, James Trafford) http://www.uni-log.org/start5.html