Relation Between Central Angle

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    RELATION BETWEEN THE CENTRAL ANGLE,

    SECTOR AREA, AND THE LENGHT OF ARCSBETWEEN TWO SECTORS

    Look at the

    picture

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    RELATION BETWEEN THE CENTRAL ANGLE,THE LENGHT OF ARCS, and SECTOR AREA

    central AOB=

    The lenght of

    arc AB=

    The area of

    sector OAB

    central COD

    The lenght of

    arc CD

    The area of

    sector OCD

    Look at the

    picture

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    If central angle is compared to a full angle of circle

    that is ( 3600), then :

    O

    central AOB=

    The lenght of

    arc AB=

    The area of

    sector OAB

    3600

    Circumference

    of circle Area of circle

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    If the central angle that be compared to the full

    angle of circle ( 3600), then :

    O

    central AOB =

    The lenght of

    arc AB =

    the area of

    sector OAB

    3600 2r r2

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    Example 1 :

    O

    D

    C

    A

    B

    50

    0

    800

    Look at the picture beside,

    the lenght of arc AB = 40

    cm, AOB = 500, and

    AOB=800.

    Find the lenght of arc CD.

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    Solution :Given :

    AB = 40 cm, AOB = 500, AOB=800

    central AOB=

    The lenght of arc AB

    central COD The lenght of arc CD

    500=

    40 cm

    800 X cm

    X = ( 40 x 80 ) : 50 = 64.

    O

    D

    C

    A

    B

    500

    800

    Asking : Find the lenght of arc CD

    Answer:

    So, we get the lenght of arc CD = 64 cm

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    Given :

    AOB = 540, and radii = 20 cm

    central AOB=

    The area of sector OAB

    3600

    The area of circle540

    =x

    3600 r2

    X = ( 3 x 1256 ) : 20 = 188,4 cm2.

    So, we get the area of sector OAB = 188,4 cm2.

    3=

    x

    20 3,14 x 202

    Solution :

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    Question - 1

    Look at the picture, the

    lenght of arc PQ = 50 cm,

    the lenght of arc QR = 75

    cm and POQ = 450.

    Determine QOR.

    O

    P

    R

    450

    Q

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    Given :

    The lenght of arc PQ = 50 cmThe lenght of arc QR = 75 cm

    POQ = 450

    central POQ=

    The lenght of arc PQ

    central QOR The lenght of arc QR

    45=

    50

    x 75

    X = ( 3 x 45) : 2 = 135 : 2 = 67,50

    So, we get QOR = 67,50.

    45=

    2

    x 3

    Solution :

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    Question - 2

    Look at the picture,

    COD = 600, the lenght of

    OA = 12 cm and AC = 12 cm.

    Calculate the area of the

    shaded region.

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    Given :

    Radii (1) = 12 cm

    Radii (2) = 24 cm.

    AOB = 600

    Solution :

    Answer:Area of sector OAB = 60/360 x area of circle

    = 1/6 x 3,14 x 12 x 12

    = 3,14 x 24= 75,36 cm2

    Asking :the area of the shadedregion.

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    Area of sector OCD = 60/360 x area of circle

    = 1/6

    x 3,14 x 24 x 24

    = 3,14 x 96

    = 301,44 cm2

    The area of the shaded region:

    = area of sector OCD - area of sector OAB

    = 301,44 cm

    2

    - 75,36 cm

    2

    = 226,08 cm2.

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    Question - 3

    42 cm

    Calculate the area of the shaded

    region as shown in the figure above !

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    Solution:

    The area of circle that

    is shaded :

    L = r2

    = x 22/7 x 21 x 21

    = x 22 x 63

    = 11 x 63

    = 693 cm2

    42 cm

    The area of small circle that is shaded =

    The area of small circle that isnt shaded.

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    Quiz - 1

    Look at the picture, the area of

    sector OAB =60 cm2,

    AOB = 400 and BOC = 120o

    Find the area of sector OBC.

    O

    A

    C

    1200

    400

    B

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    Quiz - 2

    Calculate the area of the shaded

    region as shown in the figure above !

    14 cm

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    Given : AOB = 400 and BOC = 1200

    The area of sector OAB = 60 cm2

    Asking: The area of sector OBC.

    Answer:

    central AOB=

    The area of sector OAB

    central BOC The area of sector OBC

    400=

    60

    1200

    x

    X = 3 x 60 = 180 cm2.

    So we get the area of sector OBC = 180 cm2.

    1=

    60

    3 x

    Solution Quiz 1 :

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    Solution Quiz 2:

    The area of circle thatis shaded :

    Lb = r2

    = 22/7 x 7 x 7

    = 154 cm2

    Lk = r2

    = 22/7 x 3,5 x 3,5

    = 38,5 cm2

    The area of the shaded region = 154 - 38,5

    = 115,5 cm2

    14 cm

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