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1 Recap Resonance Elements from the third period and beyond form compounds with 8 or more electrons around the atom. This flexibility may result in quite different resonance structure being possible. The resonance structure(s) with the greatest contribution to the actual structure can be identified using the valency of oxygen as a guide. Example: ClO 4 - O Cl O O O O Cl O O O O Cl O O O O Cl O O O O Cl O O O structure w ith greatest contribution to actualstructure

Recap Resonance

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Recap Resonance. Elements from the third period and beyond form compounds with 8 or more electrons around the atom. This flexibility may result in quite different resonance structure being possible. - PowerPoint PPT Presentation

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Page 1: Recap Resonance

1

Recap Resonance• Elements from the third period and beyond

form compounds with 8 or more electrons around the atom.

• This flexibility may result in quite different resonance structure being possible.

• The resonance structure(s) with the greatest contribution to the actual structure can be identified using the valency of oxygen as a guide.

Example: ClO4-

O

ClO

O

O

O

ClO

O

O

O

ClO

O

O

O

ClO

O

O

O

ClO

O

O

structure with greatestcontribution to actual structure

Page 2: Recap Resonance

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VSEPR TheoryLewis structures give bonding arrangements but do

not imply any molecular shape. For this we use:

Valence Shell Electron Pair Repulsion Theory

This relies on minimising repulsion between areas of electrons (bond pairs and lone pairs) around the central atom.

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VSEPR Theory1. Draw Lewis Structure.

2. Count number of electron pairs.• Count both bonding pairs and non-bonding

pairs.• Count multiple bonds as only one area of

electrons.

3. Determine the arrangement of electron pairs.• Electron pairs want to be as far away from

each other as possible.

4. Use atom positions to name molecular geometry.• This is the atom positions.

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Electron Pair Arrangements

• Two electron pairs:– Atoms at the opposite ends of a line.– 180 degrees between areas of

electrons.– Called linear.– eg CO2

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Electron Pair Arrangements

• Three electron pairs:– Atoms at the corners of a triangle.– 120 degrees between electron pairs.– Called trigonal planar.– Eg BF3

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Electron Pair Arrangements

• Four electron pairs:– Atoms at the corners of a

tetrahedron.– 109.5 degrees between electron

pairs.– Called tetrahedral.– Eg CH4

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Remove one arm from the electron pair arrangement for each lone pair present.

Trigonal Planar (3 e- pairs)

Molecular Geometry

Figure 10.4 Silberberg

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Tetrahedral (4 e- pairs)

Molecular Geometry

Figure 10.5 Silberberg

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Molecular Geometry• Repulsion: lone pair-lone pair > lone

pair-bond pair > bond pair-bond pair.

109.5 107 104.5

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Molecular GeometryFig

ure

10.9

Silb

erbe

rg

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Molecular Geometry - Example

• Molecules with multiple bonds eg COCl2 total 24 e-

3 areas of electrons about C, so trigonal planar arrangement of electrons

No lone pairs so molecular geometry is also trigonal planar

~120

Cl C

O

Cl

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Molecular Geometry - Example

• Cases when there is no single central atom– Just apply the VSEPR rules to each central

atom in turn.

C C

H

H

H

H3 areas of electrons about each C, so trigonal planar arrangement of electrons about each C

~120

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Dipole Moments• Any bond between two different atoms

will be polar.• A molecule has a permanent dipole

moment if it contains polar bonds and it is not a symmetrical shape.

• Note: Cations and anions are not polar – the overall charge overwhelms any local d+ vs d- effects.

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Dipole Moments• Polar molecules

• Non-polar moleculesHF H2O

CHCl3

N2 CO2

CCl4

Page 15: Recap Resonance

• By the end of this lecture, you should:− work out the number of bonding and non-

bonding pairs from the Lewis structure of a molecule

− predict the distribution of these pairs around an atom

− predict and describe the molecular shape− determine if a permanent dipole exists

− be able to complete the worksheet (if you haven’t already done so…)

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Learning Outcomes:

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Questions to complete for next lecture:

1. Draw the shapes of the following molecules and ions and give approximate bond angles(a)BH3

(b)NH4+

(c) CS2

(d)CH2O(e)CH3Cl(f) H3O+

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Questions to complete for next lecture:

2. What are the approximate C-C-C bond angles in the two molecules below?

3. Are these molecules flat?