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8/12/2019 Quantum Mechanics of NMR
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The Quantum Mechanics of MRI
Part 1: Basic concepts
David Milstead
Stockholm University
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Background reading
Fundamentals of Physics, Halliday,
Resnick and Walker (Wiley)
The Basics of NMR, J. Hornak
(http://www.cis.rit.edu/htbooks/nmr/inside.htm )
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Outline What is quantum mechanics
Wave-particle duality
Schrdingers equation
Bizarreness
uncertainty principle energy and momentum quantisation
precession of angular momentum
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What is quantum mechanics ?
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Basic concepts What is a wave ?
What is a particle ? What is electromagnetic radiation ?
What happens to a magnet in a magneticfield ?
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What is a wave ?
Double slit diffraction
Properties of waves:Superposition, no localisation (where is a wave??)
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What is electromagnetic radiation ?
EM radiation is made up of electromagnetic wavesof various wavelengths and frequencies
Radio frequency is of most interest to us
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Circularly polarised light
Radiation can be produced and filtered to produce a rotating magneticfield.
Rotating magnetic field
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Light is a wave!
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Photon
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Photons
346.626 10
Quanta of light:
Energy
=Planck's constant= Js
=frequency
= =wavelength, speed
E hf
h
f
vv
f
=
=
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Wave-particle Duality
3410
Particles also show wave-like properties
Wave-length = Energy=
=frequency, =momentum, =6.6 Js Planck's constant.
hhf
p
f p h
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Weve just learned a basic result of quantum mechanics.Now we move onto some maths.
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Fundamental equation of quantummechanics
( ) wave function=particle energy
=potential energy of particle
xE
U
=
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( )Re( )x
x
Free particle
0
Well defined wavelength and momentum but no preferential
position.
"Uncertainty on position":
"Uncertainty on momentum":
x
p
=
=
( )
2 2
2
2
2
0
2
cos sin
2
2
; Fixed
-
constant - particle can be anywhere!
; ;
fixed wavelength and momentum
U E
Em x
A kx i kx
h pp k E
m
=
=
= +
=
= = =
A particle not confined or subject to forces.
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Wave function of a confined particle
p
x
p
Eg particle trapped in a tiny region of space. How do we model thewave function ?
Solution to Schrdingers equation would besum lots of sine waves with different wavelengths/momenta.
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x
x
Similarly:y z
p y h p z h > >
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QuestionA 12-g bullet leaves a rifle at a speed of 180m/s. a) What is the wavelength of thisbullet? b) If the position of the bullet is known to an accuracy of 0.60 cm (radius ofbarrel), what is the minimum uncertainty in its momentum? c) If the accuracy of
the bullet were determined only by the uncertainty principle (an unreasonable
assumption), by how much might the bullet miss a pinpoint target 200m away?.
3434
34
31 1
3131
6.6 103.06 10
0.012 180
6.6 10 100.006
10200 200 9 10
0.12 180
(a) Wavelength m
(b) kgms
(c) Displacement m Tiny!
Because is so small, quantum effects are nev
h
p
hpx
p
p
h
= = =
er seen for macroscopicobjects.
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Hydrogen atomSolve Schrdingers equation for an electron around aproton in a hydrogen atom.The electron is confined due to a Coulomb potential.
2
04
proton chargee
U e
r
= =
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( )- , - 1 ,...., 1,
(2 1)
Component along one direction:
different states.
z l lL m m l l l l
l
= =
+
2
whereh
=
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Where is the electron ?Wave functions
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Orbiting electron as a current loop
2
1
2 2 2 2
2
Tiny current loop.
chargecurrent
period
Magnetic moment
area of loop
Angular momentum:
(parallel to angular momentum)
Gyrom
e
l
e
dq eI
dt T
IAn
A
v ev ev evRIA A R
T R R R
L m vr
eL
m
= = =
=
=
= = = = =
=
=
2agnetic ratio: =-l
e
e
L m
=
e
R
into the page.n
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Recall that the electron has fixed values of ZL
2 2
lzz z
emeLU B B
m m = =
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An atom in a magnetic field l=1 and therefore 2l+1 states
E
- -2
(1) 12 2
(2) 0 0 ; 0
(3) 12 2
; ( antiparallel with )
; ( parallel with )
Two states with
ll lz z lz
e
l lz z le e
l lz
l lz z z l
e e
emU B B
m
e em U B B
m m
m U
e em B U B B
m m
= = =
= = =
= = =
= = =
shifted energy one state with no energy shift.+
2 z zB(1)
(2)
(3)
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l=0
l=1
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( )( )
2
2 2 2 2 2 2
,
1
What happens when a circulating electron is placed
in a magnetic field.
We know that are fixed and known.
constant
By symmetry, same spread of results of
or when mea
Z
x y Z l
x y
L L
L L L L l l m
L L
+ = = + =
sin
1 1sin
sin sin
2
2
surements of made.
i.e. just as likely to find angular momentum and .
Magnetic field introduces a torque
=
i.e
l l
ll
e
le
X Y
dL
B B dt
Bd dLB
dt L dt L L
m eBL
e m
= = =
= = =
= =
.
2
. the angular momentum vector precesses around the magnetic
field ( -axis) with frequency This is Larmor precession.
Gyromagnetic ratio : e
z
e
B m
= =
LZ
UX
xy
z
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Angular momentum precession
LZconstant andL precesses around z-axis
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Question
.
Is it possible for an electron in a hydrogen atom to have ?
Show that this value can be approached for large values of
Would be possible using classical physics ?
No - it can never happen o
Z
Z
L L
l
L L
=
=
( )2 2 2 2 2
,
0
1
therwise we would "know" values of
i.e.
For largeMax
(comes close)
In classical physics there is no restriction on what we can and ca
x y
x y
Z l Z
Z
L L
L L
L l l l L l L l
L m L l
L L
= =
= + = == =
n't know.
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The mathematics of spin angular momentum is identical to orbital
angular momentum.
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FN
FS
FN
FS
Magnetic field
Magnetic field
Ignore force not parallel to North-South axis.
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Magnetic field
Magnetic field
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Zeeman effect with orbital and spin
angular momentum
In the presence ofa magnetic field,multiplicities of
spectral linesappear
10
2
2 1 2
Eg for ,
number of lines:
l s
n s
= =
= + =
2BB
Larmor precession for spin
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2
2
Identical to orbital case.
;
spin magnetic moment
Electron:
electron g-factor 2, electron mass.
Nucleus:
nuclear g-factor, proton mass.
(ne
s
s
e e
e
e e
N N p
p
S B
eg
m
g m
eg g m
m
= =
=
=
= =
= = =
xt lecture)
SZ
xy
z
Larmor precession for spin
S sin
S
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Summary Established basic quantum mechanics
theory needed for NMR wave-particle duality
Light is either photons or electromagnetic waves
Schrdingers equation and the wave functionat the heart of QM predictions
Energy and angular momentum are quantised Larmor precession
Angular momentum comes in two varieties(orbital and spin)
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Outline Spin - reminder
Fermions and bosons Nuclear energy levels
Spin
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2 2( 1)
2
2
Identical in form to orbital case.
spin magnetic moment
Electron:
electron g-factor 2, electron mass.
Nucleus:
nuclear g-factor,
z s
s
s
e e
e
e e
N N
p
S s s S m
B
S
eg
m
g m
eg g
m
= + =
=
=
=
=
= =
= =
proton mass.
(next lecture)
pm = SZ
xy
z
Spin
S sin
S
G ti ti
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Gyromagnetic ratio
Why do they have different values ?
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Fermions and bosons Fermions
Spin 1/2, 3/2, 5/2 objects Electrons, protons and neutrons have spin 1/2
Tricky bit comes when combining their spins
to form the spin of, eg, an atom or a nucleus
Bosons
Integer spin objects
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Usefulness for MRI Need isotopes with unpaired protons (to
produce signal for MRI) Most elements have isotopes with non-
zero nuclear spin
Natural abundance must be high enoughfor MRI to be performed.
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Spins of various nuclei
Now we can understand MRI
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Now we can understand MRI
0
1
1 0?
We know the basics:
A uniform magnetic field B
A short pulse of a rf field BA system out of equilibrium
measurement of return to equilibrium.
Why is
(a)
(b) The rf pulse shorter than recovery
B B
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No magnetic field
Apply an external magnetic field
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Apply an external magnetic field
.
, 0
1
2
Spins precess at Larmorfrequency
Gyromagnetic ratio:
Precessions incoherent:
Total spin Z x y
Z
B
S S S S
S
=
= = =
=
B0
In fact, there are continual transitions
and interactions from thermal energy.
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Another look at the system
Split into spin-zones.For uniform system we can regard the macroscopic system as giving
a single magnetisation.
Conventional to talk about magnetisation :
; no. dipoles, volumes
M
NM N V
V
= = =
Putting together what weve learned
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0
0 0 0
,2
1
2 2 4
2
2
Need to know its energy splitting.
=spin angular momentum nuclear g-factor proton mass.
;
Frequency of light need
sN p
p
sZ sZ z N N
p p
p
sZ
p
e g S g mS m
e eE B S g g
m m
g eE B B
m
= = = =
= = = =
= = =
0 0
00 0
2
2
ed for excitation
Larmor frequency:
How many nuclei can be excited ?
p
p
N
p
g eB
m
eBB g
m
=
= = =
0
0
Energy level population
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e gy e e popu at o
Nature has a preference for the lowest energy states.
In thermal equilibrium the lowest states are a bit more
populated than the higher energy states.
2
1 ...2!
Taylor expansion: xx
e x= + + +
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23
0 0 0
6 26
0
2!
1
2
1.5 42.576 10 2 4.2 10
Boltzmann's constant = 1.38 10 J/K=room temperature 310 K
T J
B B
B
p
p
N E Ee
N k T k T
kT
g eE B B
m
B E
N
N
= +
=
= = =
= = =
0
1.000009
1
2 2
p
p B
g eN NN N N N B
N m k T
=
= =
Changing the spin populations
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Changing the spin populations
15
Tiny differences in, eg, 0.02ml of water
expect 610 more in parallel state.
Question
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QuestionChemists can excite certain samples using UV light. Would you expect
to be substantially different in this case ? What does this imply for
the relative size of the sample of a MRI scan and a test
N
N
88 16 1
8
34 16 17
17
23
3 1010 3 10
10
6.6 10 3 10 2 10
2 101 1 1 5000
1.4 10 300
made by
chemists with infrared light ?
UV-light m s
J
In fact, approximation no longer valid since it
B
cf
E
N E
N k T
= = =
=
+ + +
is no longer a
small difference!!
A chemist can use far smaller samples since the energy gap
is larger and there are far more in the lower energy state.
Exciting the nuclei - Rf pulse
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Rotating magnetic fieldB1
Typical pulse duration ~1ms.Two ways to think about the pulse. Both are needed to understand MRI.
Excitation
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Rotating magnetic fieldB1
B0
Pulse of rf-
1
0.
The rf pulse acts in two ways:
(1) The photons are absorbed, saturating the system and reducing(2) The rotating magnetic field acts on the magnetisation vector
to rotate into the complex plan
ZMB
1 1
1
1
1
e.
Individual dipole: ;
Use magnetisation: - simple form of the Bloch equations.
ss s
ddSB B
dt dt
dM M Bdt
= = = =
=
B1
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Rotating frame of reference
, ', '
'
Easier to understand if a rotating frame of reference
(with Larmor frequency) is used.
Rotate co-ordinates
Magnetic field constant on axis.
x y x y
x
B0
B1
X y
Different types of pulses
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90o 180o
1
1
1
5
1 3 6
0
2
2 42.58
1 110
10 42.58 10
1
Duration of pulse and size of B determine angle of rotation of magnetisation:
Spins precess around
Consider a full rotation of in 1ms
MHz/T
T
B
Bt
B
B T
= =
=
=
=
1 0. B B
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Question11 0
.
When applying a new magnetic field is obtained:
Why don't the protons just align with respect to that field ?
n
B
B B B= +
0B n
B
What happens next ?
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-
.
Consider a 90 rotation.
The magnetisation vector is in the plane.
The -pulse is turned off.
The system must return to equilibrium.
We have two components: and
o
Z xy
x y
rf
M M
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Longitudinal relaxation
Spin-lattice effect:
higher energy state interacts with lower energy state due and lose
energy through rotation and vibration .
Relaxation times for different materials
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Transverse relaxation
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In the laboratory frame
Dipole moments are initially in phase.
M precesses and decays.
As it precesses phase decoherence occurs.
Complicated process: contributing factor non-uniform magnetic
field ove
xy
r sample different precession rates for different regions.
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Free induction decay
*
2.
As the transverse magnetisation decays, a changing magnetic
field is produced:
=- an emf is produced in a receiver.
The signal is a decaying sinusoidal wave with lifetime
Measurement of gives
t
T
information on composition of sample.
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Free induction decay
Easier to interpret a single line on a "frequency" spectrum.
Use a Fourier transform to move from damped exponential to
signal.
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Summary Basic quantum mechanics at the heart of
nuclear magnetic resonance Angular momentum quantisation
Energy quantisation
Features of a MRI experimentinvestigated.