Quadratic Equations (PPT)-SMK JUGRA

Embed Size (px)

Citation preview

  • 8/7/2019 Quadratic Equations (PPT)-SMK JUGRA

    1/12

    TOPIC: QUADRATIC EQUATIONS (SET 1)

    6 (a) Express the quadratic equation2(3 2) 5 x x x = + in its general form.

    Ungkapkan persamaan kuadratik2

    (3 2) 5 x x x = + dalam bentuk am.

    (2 marks)

    (b) Given1

    2and 5 are the roots of a quadratic equation. Write the quadratic

    equation in the form of 2 0ax bx c+ + =

    Diberi1

    2dan 5 ialah dua punca persamaan kuadratik. Tulis persamaan

    kuadratik dalam bentuk 2 0ax bx c+ + = . (2 marks)

    7. It is given that 2 is one of the roots of the quadratic equation 28 2 0h x x = .Find the value ofh.Diberi 2 ialah satu daripada punca bagi persamaan kuadratik 28 2 0h x x = .Cari nilai h. (2 marks)

    8. Given and are the roots of the quadratic equation 22 8 5 0x x+ + = .Diberi dan ialah punca persamaan kuadratik 22 8 5 0x x+ + = .

    (a) Find the values of + and .Cari nilai + dan .

    (b) Form the quadratic equation which has the roots 2 and 2 .Bentukkan persamaan kuadratik yang mempunyai punca 2 and 2 .

    (4 marks)

    9. Solve the quadratic equation (2 5) 2 1 x x x+ = + . Give the answer correct to three

    decimal places.

    Selesaikan persamaan kuadratik (2 5) 2 1x x x+ = + . Berikan jawapan betul kepadatiga tempat perpuluhan(3marks)

  • 8/7/2019 Quadratic Equations (PPT)-SMK JUGRA

    2/12

    10. The quadratic equation28 3 4 4 ,px p x+ = where p is a constant, has two equal

    roots. Find the values ofp .

    Persamaan kuadratik2

    8 3 4 4 ,px p x+ = di mana p ialah pemalar, mempunyai duapunca yang sama. Cari nilai p .

    (3 marks)

    11. One of the roots of the quadratic equations 24 3 0x kx + = is three times the otherroots, find the values of k.

    Satu daripada punca persamaan kuadratik 24 3 0x kx + = adalah tiga kali puncayang satu lagi. Cari nilai k.

    (3 marks)

  • 8/7/2019 Quadratic Equations (PPT)-SMK JUGRA

    3/12

    SKEMA JAWAPAN SET 1

    NO JAWAPAN MARKAH

    6 (a) 2

    3(3 2) 5x x = +

    29 6 5x x = + 2 9 11 0x x + =

    11

    6 (b) (2 1)( 5) 0x x + =22 10 5 0x x x+ =

    22 9 5 0x x+ =

    1

    1

    7 When x=2, 28 2 0h x x =

    28( 2) 2( 2) 0h =

    16 8 0h + = 8h =

    1

    1

    8 (a) 22 8 5 0x x+ + =

    2 5( 4) 0

    2x x + =

    Thus, + = 4

    =5

    2

    1

    1

    8 (b) The roots are 2 and 2

    SOR = 2 + 2 . POR = (2 ) ( 2 )= 2 ( + ) = 4 .

    = 2 (- 4 ) = 4 (5

    2)

    = - 8 = 10

    The quadratic equation is2 ( 8) 10 0x x + =

    2

    8 10 0x x+ + =

    1

    1

    9 (2 5) 2 1 x x x+ = +22 5 2 1 0x x x+ =

    22 3 1 0x x+ =

  • 8/7/2019 Quadratic Equations (PPT)-SMK JUGRA

    4/12

    x3 9 8

    4

    +=

    3 9 8

    4

    +=

    3 17

    4

    =

    0.281= or 1.781

    1

    1.1

    10 8 4 3 4 0 px x p+ + =

    2 4 0b ac =2

    4 4(8 )(3 4 ) 0p p =

    216 96 128 0p p + =

    (2 1)(4 1) 0x x =2 1 0x = or 4 1 0x =

    1

    2x =

    1

    4x =

    1

    1,1

    11 24 3 0x kx + =2 3 3

    04 4

    x x + =

    Let the roots be and 3

    + 3 =4

    k (3) =

    3

    4

    4 =4

    k

    2 334

    =

    1

    2 =

    When1

    2 = , 4

    4

    k =

    1

    4 2 4

    k

    = 8k=

    1

    1

    1

  • 8/7/2019 Quadratic Equations (PPT)-SMK JUGRA

    5/12

    QUADRATIC EQUATIONS (SET 2)

    6. Given the quadratic equation23 ( 4)x= .

    Diberi persamaan kuadratik2

    3 ( 4)x= .

    (a) Express the given quadratic equation in the general form 2 0ax bx c+ + =Ungkapkan persamaan kuadratik yang diberi dalam bentuk am 2 0ax bx c+ + =

    (2 marks)

    (b) Hence, from your answer in (a) determine the types of roots.

    Seterusnya, daripada jawapan di (a), tentukan jenis punca.(2 marks)

    7. Form the quadratic equation which has roots 3 and 4 . Give your answer in the

    form0

    2=++ cbxax

    , where a, b and c are constants.Bentukkan persamaan kuadratik dengan punca -3 dan 4. Beri jawapan anda dalam

    bentuk 02 =++ cbxax , di mana a, b, dan c ialah pemalar.

    (2 marks)

    8. The quadratic equation2

    2 0x px q+ + = has roots 4 and 2 . FindPersamaan kuadratik

    22 0x px q+ + = mempunyai punca 4 dan 2 . Cari

    (a) the values ofp and q .

    nilai bagi p dan q

    (b) the range of the values ofk so that22x px q k + + = has no real roots.

    Cari julat nilai k jika22x px q k + + = tidak mempunyai punca nyata.

    (4 marks)

    9. Solve the quadratic equation h2 3h + 2 = 2(h 1).

    Selesaikan persamaan kuadratikh2 3h + 2 = 2(h 1).(3 marks)

  • 8/7/2019 Quadratic Equations (PPT)-SMK JUGRA

    6/12

    10. Given m and 2m are the positive roots of the quadratic equation2 18 0x px + = .

    Find the values ofm andp.

    Diberi m dan 2m ialah punca positif bagi persamaan kuadratik2 18 0x px + = .

    Cari nilai m dan nilai p.

    (3 marks)

    11. The quadratic equation2

    2 ( 2 ) 2x x p x p+ = has two distinct roots. Find the rangeof values ofp.

    Persamaan kuadratik2

    2 ( 2 ) 2 x x p x p+ = mempunyai dua punca yang berbeza.

    Cari julat bagi nilai p.

    (3 marks)

  • 8/7/2019 Quadratic Equations (PPT)-SMK JUGRA

    7/12

    SKEMA JAWAPAN SET 2

    NO JAWAPAN MARKAH

    6 (a) 2( 4) 3x =

    2 8 16 3x x + = 2 8 13 0x x + = 11

    6 (b) 2 24 ( 8) 4(1)(13)b ac =

    64 52

    12

    = => 0

    The equation has two different roots.

    1

    1

    7 ( 3)( 4) 0x x+ = 2 4 3 12 0x x x + =

    2 12 0x x =

    1

    1

    8(a) 22 0x px q+ + =

    2 0

    2 2

    p qx x

    + =

    From the roots -4 and 2

    SOR =2

    P POR =

    2

    q

    4 2 2

    p

    + = 4(2) 2q

    = 4p = 16q = 1,1

    8(b) 22 4 16x x k + = 22 4 16 0x x k + = 2 4b ac < 0

    2(4) 4(2)( 16 )k < 0

    16 + 128 + 8k < 0

    8k < 144

    k 0

    2 2(4 1) 4(2)(2 )p p > 0

    2 216 8 1 16p p p + > 0

    8p > 1

    p 3

    1

    1

    1

    10 23 9 5 0x x =2( 9) ( 9) 4(3)( 5)

    2(3)x

    =

    1

  • 8/7/2019 Quadratic Equations (PPT)-SMK JUGRA

    12/12

    9 141

    6x

    =

    3.479, 0.4791x = 1,1

    11 From2

    0x mx p m + + = , SOR = m POR =p+m

    Given 3 and p are the roots,

    3m p= + .(1) 3p m p+ = .(2)

    Substitute (1) into (2)3 3p p p+ + = when 3p = , 3 3m = +

    3p = 6=

    1

    1,1