PROY3 Final

8/15/2019 PROY3 Final

1/153

Datos de Entrada

Cota Inicial= 1905.70 [m.s.n.m.] Prog.inicial= 2,859.30Cota fnal= 1905.6 [m.s.n.m.] Prog.Final= 2900.3

= !0.91 [m]

Qd = 0.13So = 0.002 [m"m] Vmax = 3 m"sn = 0.015 [#ormig$n Cicl$%&o] Vmin = 0.6 m"s

DIMENSIONAMIENTO DE LA SOLERA DEL CANAL:

'()ima *fci&ncia Canal&s +&ctanglar&s

b = 0.567 m. Asumimos Constructivamente 0.60

Cálculo del Tirante Normal con la base asumida

Si Yn = 0.6! m0.0!! = 0.0!! -/// & Igala

Cálculo del "orde libre#

"$ = 0.0% mSe asumirá un borde libre constructivo de# "$ = 0.&0

n= 0.27 [m]

c= 0.169 [m]= 0.161

P= 1.136 [m]

+ = 0.1!2 [m]

= 0.600 [m]

4= 0.268 [m]

F= 0.!99 [aim] +gim&n crtico

*= 0.301 [m]

m3"s

[m2]

T'A() &

DISEÑO CANAL

2

1

3

2

1SoRA

nQ ⋅⋅⋅= 2=

Y

b


2/153

:= 0.808 [m"s] - Cm%l&///

Dimensiones Constructivas#

= 0.60 m; = 0.37 m

& = 0.2 m

Detallamiento *inal#

1905.70

Yn=0,27

Prog=2859.30

o =0,002

Dimensionamiento *inal#

?= 0,1m

; = 0,37m n =0,27 m

&= 0.2 m

& = 0.2m = 0,6 m &= 0.2 m

T'A()


3/153

Datos de Entrada

Cota Inicial= 1905.60 [m.s.n.m.] Prog.inicial= 2,907.50Cota fnal= 1905.0 [m.s.n.m.] Prog.Final= 3161.2

= 25!.72 [m]




b = 0.5&+ m. Asumimos Constructivamente 0.60


Si Yn = 0. m0.03 = 0.03 -/// & Igala


"$ = 0.07 mSe asumirá un borde libre constructivo de# "$ = 0.&0

n= 0.22 [m]

c= 0.1!1 [m]

= 0.132

P= 1.0!0 [m]

+ = 0.127 [m]

= 0.600 [m]

4= 0.220 [m]

m3"s

[m2]

2

1

3

2

1SoRA

nQ ⋅⋅⋅= 2=

Y

b


4/153

F= 0.516 [aim] +gim&n crtico

*= 0.2!9 [m]

:= 0.758 [m"s] - Cm%l&///


= 0.60 m; = 0.32 m& = 0.2 m


1905.60

Yn=0,22

Prog=2907.50

o =0,002


?= 0,1m

; = 0,32m n =0,22 m

&= 0.2 m

& = 0.2m = 0,6 m &= 0.2 m

T'A() +


5/153

Datos de Entrada

Cota Inicial= 190!.80 [m.s.n.m.] Prog.inicial= 3,17!.60Cota fnal= 1903.9 [m.s.n.m.] Prog.Final= 355!.8

= 378.60 [m]

Qd = 0.1

So = 0.002 [m"m] Vmax = 3 m"sn = 0.015 [#ormig$n Cicl$%&o] Vmin = 0.6 m"s





Si Yn = 0. m0.03 = 0.03 -/// & Igala



n= 0.22 [m]

c= 0.1!1 [m]

= 0.132

P= 1.0!0 [m]

+ = 0.127 [m]

m3"s

[m2]

2

1

3

21

SoRAn

Q ⋅⋅⋅= 2=Y

b


6/153

= 0.600 [m]

4= 0.220 [m]


*= 0.2!9 [m]

:= 0.758 [m"s] - Cm%l&///


= 0.60 m; = 0.32 m& = 0.2 m


1904.80

Yn=0,22

Prog=3174.60

o =0,002


?= 0,1m

; = 0,32m n =0,22 m

&= 0.2 m

& = 0.2m = 0,6 m &= 0.2 m

T'A() ,


7/153

Datos de Entrada

Cota Inicial= 1902.5 [m.s.n.m.] Prog.inicial= 3,619.50

Cota fnal= 1901.90 [m.s.n.m.] Prog.Final= 3,913.90= 19!.88 [m]




b = 0.,76 m. Asumimos Constructivamente 0.50


Si Yn = 0.+ m0.03 = 0.03 -/// & Igala


"$ = 0.0! mSe asumirá un borde libre constructivo de# "$ = 0.&0

n= 0.23 [m]

c= 0.160 [m]

m3"s

2

1

3

2

1SoRA

nQ

⋅⋅⋅= 2=

Y

b


8/153

= 0.113

P= 0.952 [m]

+ = 0.119 [m]

= 0.500 [m]

4= 0.226 [m]

F= 0.59! [aim] +gim&n crtico*= 0.266 [m]

:= 0.885 [m"s] - Cm%l&///


= 0.50 m; = 0.33 m& = 0.2 m


1902.50

Yn=0,23

Prog=3619.50

o =0,003


?= 0,1m

; = 0,33m n =0,23 m

&= 0.2 m

& = 0.2m = 0,5 m &= 0.2 m

[m2]


9/153

Datos de Entrada

Cota Inicial= 1905.5 [m.s.n.m.] Prog.inicial= 3813.9Cota fnal= 1905.0 [m.s.n.m.] Prog.Final= 3,969.20

= 155.08 [m]




b = 0.,76 m. Asumimos Constructivamente 0.50


Si Yn = 0.+ m0.03 = 0.03 -/// & Igala


"$ = 0.0! mSe asumirá un borde libre constructivo de# "$ = 0.&0

m3"s

T'A() 6

2

1

3

2

1SoRA

nQ ⋅⋅⋅= 2=

Y

b


10/153

n= 0.23 [m]

c= 0.160 [m]

= 0.113

P= 0.952 [m]

+ = 0.119 [m]

= 0.500 [m]4= 0.226 [m]

F= 0.59! [aim] +gim&n crtico

*= 0.266 [m]

:= 0.885 [m"s] - Cm%l&///


= 0.50 m; = 0.33 m

& = 0.2 m


1905.50

Yn=0,23

Prog=3813.90

o =0,003


?= 0,1m

; = 0,33m n =0,23 m

&= 0.2 m

& = 0.2m = 0,5 m &= 0.2 m

[m2]


11/153

Datos de Entrada

Cota Inicial= 1900.5 [m.s.n.m.] Prog.inicial= !129.8Cota fnal= 1899.0 [m.s.n.m.] Prog.Final= !,769.!0

= 639.33 [m]






Si Yn = 0. m0.03 = 0.03 -/// & Igala


"$ = 0.07 m

m3"s

T'A() 7

2

1

3

2

1SoRA

nQ ⋅⋅⋅= 2=

Y

b


12/153

Se asumirá un borde libre constructivo de# "$ = 0.&0

n= 0.22 [m]

c= 0.1!1 [m]

= 0.132

P= 1.0!0 [m]

+ = 0.127 [m]

= 0.600 [m]

4= 0.220 [m]


*= 0.2!9 [m]

:= 0.758 [m"s] - Cm%l&///


= 0.60 m; = 0.32 m& = 0.2 m


1900.50

Yn=0,22

Prog=4129.80

o =0,002


?= 0,1m

; = 0,32m n =0,22 m

&= 0.2 m

& = 0.2m = 0,6 m &= 0.2 m

[m2]


13/153

Datos de Entrada

Cota Inicial= 1900.0 [m.s.n.m.] Prog.inicial= !769.!Cota fnal= 1899.! [m.s.n.m.] Prog.Final= !,826.10

= 57.07 [m]

Qd = 0.1

So = 0.011 [m"m] Vmax = 3 m"sn = 0.015 [#ormig$n Cicl$%&o] Vmin = 0.6 m"s



b = 0.+7+ m. Asumimos Constructivamente 0.,0


Si Yn = 0.&7 m0.01 = 0.01 -/// & Igala


m3"s

T'A() !

2

1

3

2

1SoRA

nQ ⋅⋅⋅= 2=

Y

b


14/153


n= 0.17 [m]

c= 0.185 [m]

= 0.070

P= 0.7!8 [m]

+ = 0.093 [m]

= 0.!00 [m]

4= 0.17! [m]

F= 1.100 [aim] Camiar &cci$n

*= 0.279 [m]

:= 1.!37 [m"s] - Cm%l&///


= 0.!0 m; = 0.27 m& = 0.2 m


1900.00

Yn=0,17

Prog=4769.40

o =0,011


?= 0,1m

; = 0,27m

n =0,17 m

&= 0.2 m

& = 0.2m = 0,! m &= 0.2 m

[m2]

T'A() %


15/153

Datos de Entrada

Cota Inicial= 1897.5 [m.s.n.m.] Prog.inicial= !92!.9Cota fnal= 1897.0 [m.s.n.m.] Prog.Final= !,999.30

= 57.07 [m]Qd = 0.1So = 0.009 [m"m] Vmax = 3 m"sn = 0.015 [#ormig$n Cicl$%&o] Vmin = 0.6 m"s



b = 0.+!7 m. Asumimos Constructivamente 0.,0


Si Yn = 0.&% m0.02 = 0.02 -/// & Igala

m3"s

2

1

3

2

1SoRA

nQ ⋅⋅⋅= 2=

Y

b


16/153



n= 0.19 [m] c= 0.185 [m]

= 0.075

P= 0.77! [m]

+ = 0.097 [m]

= 0.!00 [m]

4= 0.187 [m]


*= 0.278 [m]

:= 1.337 [m"s] - Cm%l&///


= 0.!0 m; = 0.29 m& = 0.2 m


1897.50

Yn=0,19

Prog=4924.90

o =0,009


?= 0,1m; = 0,29m

n =0,19 m

&= 0.2 m

& = 0.2m = 0,! m &= 0.2 m

[m2]

T'A() &0


17/153

Datos de Entrada

Cota Inicial= 189!.! [m.s.n.m.] Prog.inicial= 5,119.30Cota fnal= 1893.1 [m.s.n.m.] Prog.Final= 5,165.!0= 51.80 [m]




b = 0.+0 m. Asumimos Constructivamente 0.,0


m3"s

2

1

3

2

1 SoRAn

Q ⋅⋅⋅= 2=Y

b


18/153

Si Yn = 0.&+ m0.01 = 0.01 -/// & Igala


"$ = 0.0, m

Se asumirá un borde libre constructivo de# "$ = 0.&0

n= 0.13 [m]

c= 0.185 [m]

= 0.052

P= 0.660 [m]

+ = 0.079 [m]

= 0.!00 [m]

4= 0.130 [m]

F= 1.703 [aim] Camiar &cci$n*= 0.318 [m]

:= 1.923 [m"s] - Cm%l&///


= 0.!0 m; = 0.23 m& = 0.2 m


1894.40

Yn=0,13

Prog=5119.30

o =0,025


?= 0m

; = 0,23m n =0,13 m

&= 0.2 m

[m2]T'A() &&


19/153

& = 0.2m = 0,! m &= 0.2 m

Datos de Entrada

Cota Inicial= 1890.! [m.s.n.m.] Prog.inicial= 5,248.20Cota fnal= 1889.2 [m.s.n.m.] Prog.Final= 5,330.50

= 81.97 [m]




b = 0.+5 m. Asumimos Constructivamente 0.,0


m3"s

2

1

3

2

1SoRA

nQ ⋅⋅⋅= 2=

Y

b


20/153

Si Yn = 0.&6 m0.01 = 0.01 -/// & Igala



n= 0.16 [m]

c= 0.185 [m]

= 0.062

P= 0.710 [m]

+ = 0.087 [m]

= 0.!00 [m]

4= 0.155 [m]

F= 1.308 [aim] Camiar &cci$n

*= 0.288 [m]

:= 1.613 [m"s] - Cm%l&///


= 0.!0 m; = 0.26 m

& = 0.2 m


1890.40

Yn=0,16

Prog=5248.20

o =0,015


?= 0,1m

; = 0,26m n =0,16 m

[m2]


21/153

&= 0.2 m

& = 0.2m = 0,! m &= 0.2 m

Datos de Entrada

Cota Inicial= 1888.3 [m.s.n.m.] Prog.inicial= 5,351.70Cota fnal= 1886.0 [m.s.n.m.] Prog.Final= 5,725.90

= 377.05 [m]




b = 0.,&! m. Asumimos Constructivamente 0.50

m3"s

2

1

3

2

1SoRA

nQ ⋅⋅⋅= 2=

Y

b


22/153


Si Yn = 0.&! m0.02 = 0.02 -/// & Igala



n= 0.18 [m]

c= 0.160 [m]

= 0.088

P= 0.850 [m]

+ = 0.103 [m]

= 0.500 [m]

4= 0.175 [m]


*= 0.2!2 [m]

:= 1.1!3 [m"s] - Cm%l&///


= 0.50 m; = 0.28 m& = 0.2 m


1888.30

Yn=0,18

Prog=5351.70

o =0,006


?= 0,1m

; = 0,28m

[m2]


23/153

,

&= 0.2 m

& = 0.2m = 0,5 m &= 0.2 m


24/153

m.

m


25/153

1905.60

Prog=2900.30


26/153

m.

m


27/153

1905.00

Prog=3161.20


28/153

m.

m


29/153

1903.90

Prog=3554.80


30/153

m.

m


31/153

1901.90

Prog=3913.90


32/153

m.

m


33/153

1905.00

Prog=3969.20


34/153

m.


35/153

m

1899.00

Prog=4769.40


36/153

m.


37/153

m

1899.40

Prog=4826.10


38/153

m.


39/153

m

1897.00

Prog=4999.30


40/153

m.


41/153

m

1893.10

Prog=5165.40


42/153

m.


43/153

m

1889.20

Prog=5330.50


44/153

m.


45/153

m

1886.00

Prog=5725.90


46/153


47/153

DATOS :Qd = 0.1 m^3/sB = 0.5 mts.Y = 0.25 mts.

Cota A = 1905.5 m.s.n.m.Cota F = 1900.5 m.s.n.m.

L = 263.51 mts. [Longitud de la Tue!ia "ΔZ = 5 mts. [#esni$el ent!e los %untos de &nt!ada ' salida"

!"CALC#LO DEL AREA DE LA SECCION TRANSVERSAL DEL D#CTO :

Vd = 2.5 m/s (elo)idad en el #u)to [1,5 * 3 m/s" +o! no!ma * +agin

Ad = 0.040 m^2

$!"CALC#LO DEL DIAMETRO DE LA T#BERIA :

d = 0.225 mts.

d = 225.66 mm 8.88 -sumo=

Vd = 1. m/s

DISEÑO DEL SIFON INVERTIDO

d

dd

VQA =

4

2d%Ad

⋅=

AdQVd =


48/153

&!"'ERDIDA DE CAR(A 'OR LA RE)ILLA DE ENTRADA :

*b = 0.012 mts. [&s+eso! de las a!!as" 1/2-Sb = 0.1 mts. [&s+a)iamiento de las a!!as"+ = 60 [ngulo de in)lina)ion de la egilla"

F = 1. [a)to! de o!ma"

,-* = 0.00323 mts.

&!"CALC#LO DE LA LON(IT#D DE TRANSICION :

LT = 0.26 mts.

LT = 1.5000 mts.

.!"'ERDIDA 'OR TRANSICION EN LA ENTRADA :

Vd = 1. m/s [(elo)idad en la Tue!ia"V/ = 0.80 m/s [(elo)idad en el anal de ng!eso"

,t* = 0.06636 mts.

0!"NIVEL DE A(#A SOBRE EL '#NTO B :

Cota : 100.5 m.s.n.m.

100.680 m.s.n.m.

1!"'ROYECCION 2ORIZONTAL DEL DIAMETRO :

d = 254.000 mm [#iamet!o del ondu)to"3 = 2 [ngulo de n)lina)ion de la Tue!ia de ng!eso"

0.822 m

NAB =

D'E

+4*n5

V

4

*F, /

b

b-* ⋅⋅

⋅

⋅=

2

23

4

( )6TanDT

L T ⋅−=

2

( )

5

V/Vd, t*

⋅

−⋅=

2

4,0 22

tere B hh NA NA −−=

( )1

)os 3

DD'E =


49/153

7!"CALC#LO DEL 'ORCENTA)E DE A2O(AMIENTO :

a8 = 30 7 [%o!)entae de 9ogamiento :107 * 507;"100.680 m.s.n.m.0.822 mts.

Cota B = 100.105 m.s.n.m.

a = 0.24 mts.

a < 0,15 >%L&

9!"'ERDIDA 'OR ENTRADA EN EL D#CTO :

Vd = 1. m/s [(elo)idad en la Tue!ia"* = 0.5 [oe. de %e!dida +o! &nt!ada" tala 8,2*+ag113*+

a!istas )on angulo

,* = 0.0 mts.

;!"'ERDIDAS LOCALIZADAS :

Vd = 1. m/soei)ientes de %e!didas de a!ga +o! ))eso!ios

= 0. [odos de adio o!to" n = 1$ = 2.5 [(al$ula de eten)ion" n = 1& = 0.6 [odos de adio La!go" n = 1


50/153

R* = 4.6&?05

@ = 1.32&*02

,@ = 2.18 mts.

$!"'ERDIDA 'OR SALIDA :

Vd = 1. m/s [(elo)idad en el ondu)to"V* = V4aida = 0.80 m/s [(elo)idad de Salida al anal"

,4 = 0.1 mts.

&!"'ERDIDA DE CAR(A 'OR RE)ILLA :

*b = 0.004 mts. [&s+eso! de las a!!as" 3/8-Sb = 0.1 mts. [&s+a)iamiento de las a!!as"+ = 60 [ngulo de in)lina)ion de la egilla"

F = 1. [a)to! de o!ma"V4 = 0.80 m/s [(elo)idad de Salida al anal"

,-* = 0.002

!"'ERDIDA DE CAR(A TOTAL :

Lo5@ e

51,2

1,32

1

5d

VdLd@,@

⋅⋅⋅

⋅=2

2

==e

( )5

V4Vd,4 ⋅

−=

2

22

+4*n5

V

4

*F, S

b

b-* ⋅⋅

⋅

⋅=

2

23

4

∑ ∑ ++++++= -*4m@*t*-* ,,,,,,,,T


51/153

Cota F = 101.2 mts.

0!CALC#LO DE LA COTA DE SALIDA :

0.23 mts.:)anal de salida;

Cota NA F = 101.50 m.s.n.m.

1!"CALC#LO DEL NIVEL DE A(#A EN EL '#NTO E :

Cota NA E = 101.66 m.s.n.m.

7!"CALC#LO DEL A2O(AMIENTO DE SALIDA :

d = 225.65565554 mm

a4 = 0.038 mts.

9!"CALC#LO DE LA COTA DEL '#NTO E :

d = 225.65565554 mm3 = 64 [ngulo de #eleAion de Salida del Sion"

D4 = 0.51 mts.

Cota E = 101.11 m.s.n.m.

YF

=

,TACota FCota ⋅−= 1,1

,-4YFCota NACota FF ++=

SFE ,NACota NACota +=

6

da4 ≅

( )3d

D4)os

=

a4D4NACota ECota E −−=


52/153


53/153

111* +!ona!

10 -254.000 mm


54/153


55/153

!ona!!e)tos


56/153

mts.

3.85 mts.

mts. BC DDD um+le


57/153


58/153


59/153

DATOS :

Cota ini/io 1893.1 +!og. 1= 5165.4/ota @ina 180.4 +!og. 2= 5248.2

Qd = 100 l/s [audal de #iseEo"So = 0.0251 m/m [%endiente del )anal"

2 = 2.00 mts. [#esni$el de la a+ida" < 2,5 Fue +e!mite la no!ma +o! eso seL = 84.40 mts. [Longit!ud de la a+ida" +ag*124*+!ona!

!"CALC#LO DEL CANAL DE IN(RESO :

Yn = mts.

B = 0.40 mts. onst!u)ti$amente=

$!"CALC#LO DE LA ENER(IA EN EL CANAL DE IN(RESO :

V = G#(/0D m/s

&!"CALC#LO DE LA SECCION DE CONTROL :

aso de se))ion e)tangula!

DISEÑO DEL DISIPADOR DE ENE

RAPIDA

2

1

3

2

1 SoRAn

Q ⋅⋅⋅=2=

Y

B

( )221 Yn

Q

⋅⋅⋅=

5

V

YE ⋅+= 2

2

1

5

V/Y/E

⋅+=2

2

1

3

1

2

5B

QdB

Qd

5B

QdE

⋅⋅

+

⋅

=

11

13

1

2

2

23

1

2

2

1


60/153

G#(/0D =B = 0.3 mts. sumoH 0.36

Y/ = 0.1864 mts.

0.1

!"CALC#LO DE LA LON(IT#D DE TRANSICION :

6 = 22.5

T = 0.40B = 0.3

LT = 0.00345 mts. LT =

l tene! un an)9o de )anal igual al an)9o de la !a+ida no eAiste t!ansi)iIn

.!"CALC#LO DE TIRANTES :

&)ua)ion Jene!al de T!amos ios

=5

/1B

=

( )65

BBL

T tan2

1

⋅

−=

SEESo E ⋅+=+⋅ 21

nV

5

VY

5

VYSo

+

⋅

⋅+⋅

+=⋅

++⋅

2

2

1

2

2

2

2

1

12

1

22

2

21 SESE

SE+

=

2

3

2

⋅=R

nVSE


61/153

0!"CALC#LO DEL BORDE LIBRE :

Y BL 2

0 0.1 0.63 0.81 0.13 0.64 0.82 0.14 0.64 0.83 0.14 0.64 0.84 0.14 0.64 0.8

0.14 0.64 0.80.14 0.64 0.80.14 0.64 0.80.14 0.64 0.8

0.14 0.64 0.80.14 0.64 0.8

1!"CALC#LO DE LA LON(IT#D Y LA 'ROF#NDIDAD DEL COLC2ON DISI'ADOR :

Y = 0.14 mts. [Ti!ante en el Fue las &ne!gias se igualan"Y = 0.00 mts. [Ti!ante del anal de &nt!ada"B = 0.36314543 mts. [ase del anal"

F = 1.61 < 1

Y$ = 0.25 mts.

* = 0.3 mts.

L4 = 0.56 mts.

7!"DIMENSIONAMIENTO FINAL :

1

YVBL ⋅⋅+= 031,061,0

1Y5

VF

⋅=

YnY* −⋅= 215,1

( )125 YYL4 −⋅=

4

1

1

2

2

12

22

2

Y

BY5

QdYY +

⋅⋅⋅

+−=


62/153

onst!u)ti$amente se ado+ta!aL4=$0 m


63/153


64/153


65/153


66/153


67/153

9a)e esta o!a

1 m

E = G#(/0D mts.

GIA

2

13

2

2

4

2So

Y

Y ⋅

⋅⋅

5⋅⋅2

2


68/153

0.26

m

TABLA DE C#RVA DE

Qd = 0.100 m^3/sL = 84.4 mts. B = 0.362 = 2. mts. n = 0.018

Y/ = 0.1864 mts.

TRAMO Δ So G V R

[ngulo de T!ansi)ion" 0 0 8.! 0.032 0.186! 1.352 0.06

mts. [n)9o del anal" 1 8.44 8.! 0.032 0.1268 1.88 0.0mts. [n)9o de la a+ida" 2 16.88 8.! 0.032 0.1388 1.816 0.082

3 25.32 8.! 0.032 0.1352 1.864 0.0804 33.6 8.! 0.032 0.1362 1.851 0.0815 42.2 8.! 0.032 0.1359 1.855 0.081

1.50 mts. 6 50.64 8.! 0.032 0.1360 1.853 0.081 5.08 8.! 0.032 0.1360 1.854 0.0818 6.52 8.! 0.032 0.1360 1.854 0.081 5.6 8.! 0.032 0.1360 1.854 0.081

10 84.4 8.! 0.032 0.1360 1.854 0.081

Y = 0.14 mts.

n

⋅

⋅2

2

2


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luo Su+e!)!iti)o

2


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76/153

REMANSO

RH$& E EJSo Δ SE SEm EJSEm*d Δ

0.210 0.280 0.546 0.013

0.182 0.328 0.583 0.03 0.026 0.221 0.540.188 0.30 0.56 0.030 0.035 0.21 0.58

0.186 0.312 0.5823 0.032 0.031 0.264 0.5

0.18 0.311 0.5808 0.032 0.032 0.21 0.582

0.18 0.311 0.5812 0.032 0.032 0.26 0.580

0.18 0.311 0.5811 0.032 0.032 0.20 0.581

0.18 0.311 0.5812 0.032 0.032 0.20 0.581

0.18 0.311 0.5811 0.032 0.032 0.20 0.581

0.18 0.311 0.5811 0.032 0.032 0.20 0.581

0.18 0.311 0.5811 0.032 0.032 0.20 0.581

9tt+H//KKK.!e

SEm Δ


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83/153


84/153

KetoKn.)om/gaigoisaigon/9tt+H//KKK.!eeKetoKn.)om/gaigoisaigon/


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93/153


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DAT)S DE$ CANA$ DE ENT'ADA

C@4 4* 4I*A- = 0.13 m"s

C-*FICI** 4* +@D-I44 = 0.015P*4I** 4* C = 0.0 Eo

* C#- 4* C = 0.60 m* 4*I:* G = 0.80 m

Progr&siHa inicial = 02900.3Progr&siHa fnal = 0 572.8

Cota inicial = 1905.60 mCota fnal = 1282.!0 m

DAT)S NECESA'-)S DE$ CANA$ DE ENT'ADA A'A E$ D-SE/) DE $A CA-DA

DAT)S#

n= 0.27 m

c= 0.17 [m]

B= 0.13 [m3"s]

= 0.002 [m"m]

n= 0.02 [aim]

*= 0.30 [m]

= 0.60 [m]

C1$C2$) DE $A SECC-3N DE C)NT')$.4

0.+0& m

? = 0.!61 m

smimosJ " = 0.,! m

c= 0.2 m

:c= 1.! m"s

Emin

=

D I S E Ñ O D E L A S C A I D A S V E RT I C A L E S

32

2

g B

QY c =

cc Y g V *=


100/153

$a lonitud de la transicin de entrada será.

$T= 0,6K0,!8 = 0,2 m2Ltan

0.& m

$a ro8undidad del colc9n disiador será.

e= = NNN0.8NN 0.27 m3 3

%or motiHos constrctiHose= 0.+ m

ara el cálculo de la lonitud del colc9n disiador: calculamos el numero de c

=NNNNNNN0.13ONNNN= 0.0056 m

D= &.000 m

$= &+.5 m

-tro crit&rio, &l %roc&imi&nto s& calcla con &l ti&m%o & caa &l c;orro & aga.

t = 0.,7 s

Con &st& Halor s& calcla la istancia ;oriontal r&corria %or &l c;orro & aga &n s ca


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$ = &., m

D-(ENS-)NA(-ENT) *-NA$ DE $A CA-DA E'T-CA$

DATOS PARA LA GRAFICA

Yn > m? Yc > m? T > m? " > m? So > m@m? $T > m? B > m? e>m?0.268 0.169 0.60 0.!8 0.0020 0.1 0.8 0.3

&gQn la to%ograRa &l t&rr&no %or on& %asa n&stra conccion, s& ;a o%tao %or co& man&ra cons&ctiHa cSo is&To &s &l mismo %ara las tr&s, %or lo U& la sigi&nt& %linicara la icaci$n & caa no & &llos

CI4 Cota inicial Cota fnal Prog Inicial Prog Final ; < m> < m>

1 1905.60 190!.50 0!63.76 0500.06 1.1 1.!

2 190!.80 1903.70 0500.06 0536.39 1.1 1.!

3 190!.00 1282.!0 0536.39 0572.80 1.1 1.!

128!.71282.!

∆Z

LE

So

V


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'T-CA$


103/153

a;das.

a lir&J


104/153

m? $ > m?0.7 1.!

locar tr&s caias nilla nos

< m>

36.3

36.3

36.3


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107/153


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M 3 ? 45 H 3 ? 600

1? 100

!"CALC#LO DE LA 'ENDIENTE MAIMA :

Qd = 0.100 m^3/s [audal de #iseEo"B = 0.400 mts. [n)9o del anal de ng!aso", = 0.500 mts. [ltu!a del &s)alon sumo"

Y/ = 0.1 mts.

8.68 7

$!"CALC#LO DEL ANC2O MINIMO DE CADA ESCALON :

, = 0.5 mts. [ltu!a del &s)alon sumo"K,L = 0.86815863 [%endiente del &s)alon"

L = 0.55528084 mts.

b = 12.80 mts.

K,Lmax =

DISEÑO DEL DISIPADOR DE ENERGIA

RAPIDAS ESCALONADAS

13

1

maA

0/,0

⋅=

Y/

,

L

,

3

1

2

=

5

DY/

5,1/

18

02,0 L5

,Qdb

⋅⋅

⋅=

=

L,

,L


109/153

&!"DIMENSIONAMIENTO FINAL :

0.512.8

0.6


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1 ? 06


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119/153


120/153

DAT)S #d = 0.1 m3"s

" = 0.50 mts.

b = 0.7 mts. anc;o & la camara & s&im&ntacion

&.4D-A(ET') DE $A A'T-C2$A: E$)C-DAD DE SED-(ENTAC-)N #

D = 0.2 mm s = 5.! cm"stala15,3 K%ag200 K%ronar

.4CA$C2$) DE $A E$)C-DA DE ESC2''-(-ENT) #

D = 0.2 mm [4iam&tro & la Particla smia]a = !! [Co&R. & 4&cantacion] talaK15,2 K%ag199 K%ronar

d = 0.20 m"s

+.4CA$C2$) DE $A A$T2'A DE $A CA(A'A DE SED-(ENTAC-)N #

= 0.73 mts.

0,8@ 0.96!19 W1 C@'P*

,.4CA$C2$) DE$ T-E() DE 'ETENC-)N #

ts = 13.!! s&g.

5.4CA$C2$) DE $A $)N-T2D (-N-(A DE $A CA(A'A #

F = 1.25 [Co&R. & &gria talaK15,!K%ag201K%ronar

$ = 3.3 mts.

0,8 W


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6.4CA$C2$) DE $A $)N-T2D DE T'ANS-C-)N #

G = 22.5 M [nglo & ransicion] 0.55785"=T& 0.50 mts.b=T 0.7 mts.

$T = 0.!9 mts.

$T = 1.50 mts. [smo como longit mini

7.4D-(ENS-)NA(-ENT) *-NA$ #1.50

0.50 0.7

3.31

( )65Bb

LTtan2 ⋅

−=


122/153

DAT)S #d = 0.1 m3"s

" = 0.50 mts.b = 0.7 mts. anc;o & la camara & s&im&ntacion

&.4D-A(ET') DE $A A'T-C2$A: E$)C-DAD DE SED-(ENTAC-)N #

D = 0.2 mm s = 5.! cm"stala15,3 K%ag200 K%ronar

.4CA$C2$) DE $A E$)C-DA DE ESC2''-(-ENT) #

D = 0.2 mm [4iam&tro & la Particla smia]a = !! [Co&R. & 4&cantacion] talaK15,2 K%ag199 K%ronar

d = 0.20 m"s

+.4CA$C2$) DE $A A$T2'A DE $A CA(A'A DE SED-(ENTAC-)N #

= 0.73 mts.

0,8@ 0.96!19 W1 C@'P*

,.4CA$C2$) DE$ T-E() DE 'ETENC-)N #

ts = 13.!! s&g.

5.4CA$C2$) DE $A $)N-T2D (-N-(A DE $A CA(A'A #

F = 1.25 [Co&R. & &gria talaK15,!K%ag201K%ronar

$ = 3.3 mts.

0,8 W


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6.4CA$C2$) DE $A $)N-T2D DE T'ANS-C-)N #

G = 22.5 M [nglo & ransicion] 0.55785"=T& 0.50 mts.b=T 0.7 mts.

$T = 0.!9 mts.

$T = 1.50 mts. [smo como longit mini

7.4D-(ENS-)NA(-ENT) *-NA$ #1.50

0.50 0.7

3.31

( )65Bb

LTtan2 ⋅

−=


124/153


125/153


126/153

a]

0.7


127/153


128/153

a]

0.7


129/153


130/153

DATOS :

Qd = 0.1 m^3/s [audal de #iseEo"Q = 0.030 m^3/s [sumo audal Fue se (ie!te"Qmax= 0.130 m^3/s :audal maAimo;

Y = 0.30 mts. [ltu!a del anal"B = 0.60 mts. [ase del anal"n = 0.015 [oe. de ugosidad de >annig"L = N mts. [Longitud de la !esta del (e!tede!o"

So = 0.002 m/m [%endiente del anal"

!"CALC#LO DEL TIRANTE NORMAL

-terando se tiene# 0.7 m0.0!! = 0.0!! -/// & Igala

$!"VERIFICACION DEL TI'O DE RE(IMEN:

= 0.21 m^3/s/m

Y/ = 0.16 mts.

Y = 0.30 mts. Y/ = 0.16

&!"DETERMINACION DEL TIRANTE A(#AS ABA)O :

Qd = 0.100 m^3/s

Y &=Yn =

DISEÑO VERTEDERO

31

2

=

5

Y/

B

QD =

12


131/153

Y = 0.22

!"VERIFICACION DEL TI'O DE RE(IMEN A(#AS ABA)O DEL VERTEDERO:

0.16 m^3/s/m

Y/ = 0.141 mts.

Y = 0.22 mts. Y/ = 0.141

.!"CALC#LO DEL TIRANTE AL COMIENZO DEL VERTEDERO :

Y$ =

0!"CALC#LO DE LA CRESTA DEL VERTEDERO :

Q$ = 0.03 m^3/s/m [audal Fue se (ie!te"d = 1. [oe. de #es)a!ga 1, o!de e)tangula!"s = 0.1

L 1.2

1!"DIMENSIONAMIENTO FINAL :

0.30 1.20.1

0.1

$ =

23 SoRAn

Q ⋅⋅⋅=

3

1

2

4

=

5

DY/

B

Q =

42 EE = 5VY

5VY

⋅+=⋅+ 22

2

44

2

22

−−−

−−

−⋅

−

⋅=2

5

4

1

4

1

2

3

1 1

1

)(*

2

5

S Y S y

S Y

S y

S yC d

Q v L


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135/153


136/153

mts. O


137/153

mts.

mts. O

0.1 mts.

mts.

0.22


138/153


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140/153


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DATOS :

Qd = 100 l/sn = 0.015

S/ = 0.014 m/m [%endiente del %uente anal"So = 0.002 m/m [%endiente del anal de &nt!ada "L = 14.51 mts. [Longitud del %uente anal"

B = 0.5 mts. B = 0.5S*//ion S*//ion

Y = 0.25 mts. Y = 0.25

B$ = 0.4 mts. B& = 0.4S*//ion $ S*//ion &

Y$ = 0.1 mts. Y& = 0.2

1= 0.125(n1= 0.8&min1= 0.282616

2= 0.303881 m.

4= 0.125(n4= 0.8&min3= 0.282616

3= 0.303881 m.

2ENTE CANA$ &

DISEÑO PUENTE CANA

g E Qb⋅⋅

⋅=

3

min

2

8

27

g E

Qb

⋅⋅⋅

=3

min

2

8

27


143/153

!" CALC#LO DE LA VELOCIDAD :

V = 0.80 m/s

$!"CALC#LO DEL N#MERO DE FRO#D :

F = 0.51 @ 1 luo Su)!iti)o BO DDDD

&!"CALC#LO DE LA TRANSICION DE ENTRADA :

T = 0.5 mts.b = 0.4 mts.3 = 22.5

LT = 0.12 mts.

LT = 1.5 mts. [sumo +o! longitud minima"

!"CALC#LO DEL TIRANTE EN LA SECCION & :

S/ = 0.014 m/mLT = 1.5 mts.

4 = 0.5 [ei)iente de +e!dida +o! Salida en Linea e)ta"

Y& = 0.2 mts.

.!"CALC#LO DEL N#MERO DE FRO#D EN LA SECCION & :

F& = 0.8 @ 1 luo Su)!iti)

9!"CALC#LO DEL TIRANTE EN LA SECCION $ :

A

QV =4

4

4

4

Y5

VF

⋅=

( )3Tan5bT

L T ⋅−

=2

⋅

−

⋅+⋅+=⋅++⋅− 5

VV:4

5

VY

5

VYLS

T 222

2

4

2

3

2

4

4

2

3

343

3

3

3

Y5

VF

⋅=

(

( )RR

VVn

5

VY

5

VYLS/

+

+⋅⋅+

⋅+=

⋅++⋅

3

2

32

32

2

3

3

2

2

2

/3,0

22


144/153

Y$ = 0.1 mts.

;!"CALC#LO DEL TIRANTE EN LA SECCION :

S/ = 0.014 m/mLT = 1.5 mts.

* = 0.3 [ei)iente de +e!dida +o! &nt!ada en Linea e)ta"

Y = 0.22 mts.

!"DIMENSIONAMIENTO FINAL :

Y = 0.22Y$ = 0.1

Y& = 0.2 Y =

P= *0.03 m

# = 1 K !

⋅−

⋅+⋅

+=⋅

++⋅−5

VV:*

5

VY

5

VYLS T

222

2

1

2

2

2

2

2

2

1

121


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mts.

mts.

mts.

mts.


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[&s+eo de agua en el )anal"[n)9o en el %uente"[ngulo de T!ansi)ion"

o BO DDDD

)L⋅

2


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Documents

PROY3 Final