Project Tunnel

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    Department Of Industrial

    EngineeringProject management

    Tunnel Project

    Khamees Marwan(20090025070(

    Mustafa Rozieh (20090025064(

    )Zaid Ahmad Abo-elzait (20090025010

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    Instructor: Eng Esraa saleh

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    Introduction: scope and justification

    it is known that the area aroundFiras Circle. Is one of the most

    important regions in Amman city thats for a lot of reasons

    including: -

    1- Existence of Market Hussein

    2- The area is filled with shoppers

    3- This region is filled with hotels , restaurants; net cafs; game

    shops coffee shops and of course a high population area

    4- And a lot more reasons..

    For those reasons a very annoying traffic jam is now a daily event

    on Al-Hussein street "crowded traffic and accidents " which make a

    lot of people wait for a really long time to get their homes ; class;

    work places and other places

    so we have considered to remove this jam but how !!!

    the main target is to separate people going to Entertainmentspotsso we decided to build a tunnel under the existing Firas Circleand

    remove the rotary which that would solve a very large part of our

    problem and will not be stuck there for along time again.

    Success and failure criteria:the project is considered successful if the traffic jam is reduced by

    75 % for at least the next ten years and done by planned time>

    If not the project is considered a failure.

    4

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    1D-Definition of the project:

    a- Stake holders :

    1- Shoppers and people and others.

    2- Drivers for Public transportation (busses; taxies ..)

    3- Workers at Restaurants , cafs, markets, book shops and other

    shops

    4- Municipal workers

    5- Employees: engineers. workers , designers and others

    6- People living around the working area

    7- Real estate owners

    8- Building materials seller

    9- Workers at Banks in the area.

    10-traffic department

    11-police.

    12-Garbage man

    13-Tourists and Drs

    5

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    b- Strategic choices :time and quality is the most important strategic choices that wecare about as we see in fig 1

    Fig 1 time and quality priority

    c- Requirements of the project :

    Input req. Process req. Outcome req.Shortest time Good work staff Traffic jam End

    High quality Good teamwork Nice view

    Good budget Firm work times Less accidents

    Specified location equipment serve for very long time

    Best designers Fast execution

    Table 1

    6

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    d-Initial planning :

    After getting the legal approval we start by closing the road

    and making detour, then removing the rotary, cleaning area,

    excavation operations and then foundation and columns are

    to be laid.

    in the mean while parts of tunnel are to be ready (beams) to

    put on top of the columns and then we joint them together

    and asphalting the tunnel .

    We must take a look for the signs, lights and safety

    measures.

    The project will start 26/5/2012 and expected to be finished

    01/8/2012.

    7

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    2D-design of the project:A-work breakdown structure:

    activity

    Activity DescriptionPredeces

    sors

    Duration

    1 Start 1

    2 getting legal approval and completing legalpapers from city hall

    1 1

    3 get the design of the tunnel by architect 2 5

    4 make detour for Traffic 3 1

    5 put guiding signs and flashy lights 4 1

    6 Finally close the road around working area 5 1

    7 cracking and drilling road asphalt 6 3

    8 cracking and breaking al-Hussein circle 6 5

    9 moving the breaked asphalt and other stufffrom the working area

    "7;8" 2

    10 a survey surveys the working area and makesigns on Excavation spots

    9 1

    11excavation operations using special digger"buclain" 10 5

    12 planting steel inside holes 11 4

    13 pouring concrete for foundation andColumns

    12 8

    14 painting concrete boundaries with petromin"special paint to resist salts from soil"

    13 2

    15 Pack filling holes with soil to street level 14 1

    16 tunnel beam are pored with concrete oversteel and ready in near area

    15 9

    17 putting tunnel widthal beams over columnsusing crane

    16 1

    18 pouring concrete over beams to make themhold together

    17 6

    19 asphalting the tunnel 18 4

    20 asphalting the road over the tunnel 18 4

    21 asphalting lanes on sides over the tunnel 18 4

    22 side walks and trash cans "19;20;21" 1

    23 putting Concrete barriers on sides of tunnel 18 3

    24 power lines and light 23 4

    25 put Caution street signs and signals 24 2

    26 finishing and cleaning "25;22" 1

    8

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    27 delivering the project 26 1

    Table2

    Node diagram activities:

    9

    1

    2

    3

    4

    6

    87

    9

    5

    10

    11

    12

    13

    14

    15

    16

    17

    18

    19

    27

    2622

    25

    24

    23

    21 20

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    Critical path analysis

    A) 1-2-3-4-5-6-7-9-10-11-12-13-14-15-16-17-18-23-24-25-26-27 = 63

    B) 1-2-3-4-5-6-8-9-10-11-12-13-14-15-16-17-18-23-24-25-26-27 = 65

    C) 1-2-3-4-5-6-7-9-10-11-12-13-14-15-16-17-18-21-22-26-27 = 59

    D) 1-2-3-4-5-6-8-9-10-11-12-13-14-15-16-17-18-21-22-26-27 = 61

    E) 1-2-3-4-5-6-7-9-10-11-12-13-14-15-16-17-18-20-22-26-27 = 59

    F) 1-2-3-4-5-6-8-9-10-11-12-13-14-15-16-17-18-20-22-26-27 = 61

    G) 1-2-3-4-5-6-7-9-10-11-12-13-14-15-16-17-18-19-22-26-27 = 59

    H) 1-2-3-4-5-6-8-9-10-11-12-13-14-15-16-17-18-19-22-26-27 = 61

    So we have path

    B) 1-2-3-4-5-6-8-9-10-11-12-13-14-15-16-17-18-23-24-25-26-27 = 65

    The longest path

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    (Critical path)

    task EST LST EFT LFT Slake1 0 0 1 1 0

    2 1 1 2 2 0

    3 2 2 7 7 0

    4 7 7 8 8 05 8 8 9 9 0

    6 9 9 10 10 0

    7 10 12 13 15 2

    8 10 10 15 15 0

    9 15 15 17 17 0

    10 17 17 18 18 0

    11 18 18 23 23 0

    12 23 23 27 27 013 27 27 35 35 0

    14 35 35 37 37 0

    15 37 37 38 38 0

    16 38 38 47 47 0

    17 47 47 48 48 0

    18 48 48 54 54 0

    19 54 57 58 61 3

    20 54 57 58 61 321 54 57 58 61 3

    22 58 61 59 62 1

    23 54 54 57 57 0

    24 57 57 61 61 0

    25 61 61 63 63 0

    26 63 63 64 64 0

    27 64 64 65 65 0

    11

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    Time planning

    Activity Optimistic Most

    likely

    pessimistic ,Mean

    ,Variance

    1 0.5 1 3 1.25 0.17361

    2 0.5 1 2 1.08333 0.0625

    3 1 2.5 10 3.5 2.25

    4 0.5 1 2 1.08333 0.0625

    5 0.5 1 3 1.25 0.17361

    6 0.5 1.5 2 1.41667 0.0625

    7 2 3.5 5 3.5 0.25

    8 3 4.5 7 4.66667 0.44444

    9 1 1.5 5 2 0.44444

    10 0.5 1 3 1.25 0.17361

    11 2 3.5 7 3.83333

    0.69444

    12 2 4 7 4.1666

    7

    0.6944

    413 2 3 29 3.5 20.25

    14 1 2.5 6 2.83333

    0.69444

    15 0.5 1 3 1.25 0.17361

    16 5 6 35 10.66667

    11.11111

    17 0.5 1 4 1.4166

    7

    0.3402

    818 3 5 10 5.5 1.3611

    12

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    1

    19 2 2.5 17 4.83333 6.25

    20 2 2.5 17 4.8333

    3 6.2521 2 2.5 17 4.8333

    3 6.25

    22 0.5 1 3 1.25 0.17361

    23 1 2.5 6 2.83333

    0.69444

    24 2 4.5 7 4.5 0.69444

    25 1 2 4 2.16667 0.25

    26 0.5 1 2 1.08333 0.0625

    27 0.5 1 3 1.25 0.17361

    = 81.74999 days

    = 60.21524 days

    = = 7.759847937 days

    *We use more than one program to do calculationfirst of them we use Microsoft

    after that we check by Matlab and Microsoft Excel

    programs

    *We used the Excel program to plot Beta distribution*we check by using website adrees given in slides

    http://www.tutor-

    homework.com/statistics_tables/statistics_tables.html

    13

    http://www.tutor-homework.com/statistics_tables/statistics_tables.htmlhttp://www.tutor-homework.com/statistics_tables/statistics_tables.htmlhttp://www.tutor-homework.com/statistics_tables/statistics_tables.htmlhttp://www.tutor-homework.com/statistics_tables/statistics_tables.html
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    "Pert"

    Finishing probabilities

    Req. =65

    =81.74999

    *probability of finishing the project in time:

    z = = 2.15855

    Area corresponding to z = -2.15855 from tables 0.01545

    * Probability of finishing the project in 90% of the time:

    90 % of original time = 58.5 days

    z = = 3

    Area corresponding to z = 3 from tables 0.00135

    17

    = 7.759847937

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    Every sigma for 7.759847937 days

    1 finishes between 74 and 88 days 68%

    1 finishes between 67 and 95 days 95%

    1 finishes between 60 and 102 days 99%

    Time Cost Trade Off

    18

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    First able we most know the normal and crash cost and time to

    calculate and get the cheapest crash way available:

    T = time in days

    c = cost in J.D.

    Task # Normal t Crash t Normal c Crash c C/t

    1 1 - 50 - -

    2 1 - 100 - -

    3 5 3 75 100 12.5

    4 1 - 30 - -

    5 1 - 95 - -

    61

    - 150 - -7 3 2 200 300 100

    8 5 2 400 160 80

    9 2 1 80 130 50

    10 1 - 50 - -

    11 5 4 350 450 100

    12 4 3 250 300 50

    13 8 3 700 1075 75

    14 2 - 100 - -15 1 - 75 - -

    16 9 5 1500 2500 250

    17 1 - 20 - -

    18 6 2 450 580 32.5

    19 4 3 300 420 120

    20 4 3 300 420 120

    21 4 3 300 420 120

    22 1 - 45 - -23 3 1 230 300 35

    24 4 2 460 580 60

    25 2 1 100 185 85

    26 1 - 20 - -

    27 1 - 80 - -

    total - - 6510 - -

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    We used law:

    Crash cost - Normal costNormal time crash time

    We want to complete project in 75 % of its

    estimated time so:

    want to crash 17 days of critical path.

    We have the approach of "crashing of activities"

    *we start by the critical path

    B) 1-2-3-4-5-6-8-9-10-11-12-13-14-15-16-17-18-23-24-25-26-27 = 65

    This is what we start with

    so:

    we have considered the cheapest crash cost per

    crash time

    we notice that a lot of our reduced tasks are in

    other tasks we hit two birds with one stone "

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    1- Crash 2 days from activity # 3

    total cost = 6510 + 2(12.5) =6535

    2 Crash 4 days from activity #18

    Total cost = 6535 + 4(32.5) =6665

    3 Crash 2 days from activity #23

    Total cost = 6665 + 2(35) =6735

    4 Crash 2 days from activity #9

    & crash 2 days from activity #12

    Total cost = 6735 + (2+2) (50) =6935

    5 Crash 2 days from activity #24

    Total cost = 6935+ 2(60) =7055

    6 Crash 5 days from activity #13

    Total cost = 7055+ 5(75) =7430

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    So our paths now:

    A) 1-2-3-4-5-6-7-9-10-11-12-13-14-15-16-17-18-23-24-25-26-27 = 46

    B) 1-2-3-4-5-6-8-9-10-11-12-13-14-15-16-17-18-23-24-25-26-27 = 48

    C) 1-2-3-4-5-6-7-9-10-11-12-13-14-15-16-17-18-21-22-26-27 = 46

    D) 1-2-3-4-5-6-8-9-10-11-12-13-14-15-16-17-18-21-22-26-27 = 48

    E) 1-2-3-4-5-6-7-9-10-11-12-13-14-15-16-17-18-20-22-26-27 = 46

    F) 1-2-3-4-5-6-8-9-10-11-12-13-14-15-16-17-18-20-22-26-27 = 48

    G) 1-2-3-4-5-6-7-9-10-11-12-13-14-15-16-17-18-19-22-26-27 = 46

    H) 1-2-3-4-5-6-8-9-10-11-12-13-14-15-16-17-18-19-22-26-27 = 48

    22

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    Source leveling:

    Now in our projects we need to deal with workers

    as little as we can and as less time as we can also:

    tasks 21 and 23 are concurrent and 23 is in the

    critical path and each needs 4 workers the whole

    time until it finishes :

    8 8 8 8

    23

    23

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    so by source leveling and without wasting any

    time we move task 21 3 days as its slack give uspermission to reduce # of workers to 4 each day

    accept one day :

    4 4 4 8 4 4 4

    24

    21

    23

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    IMPORTANT NOTE:

    All calculations were done at our hand and we

    check by using programs

    First of these programs are Microsoft project

    also we done it by matlab and Excel

    Each student in this project had taken one of

    these programs and he was done calculations to

    ensure that all student work in team and all of

    whom participated in the completion of the project

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    The end of project

    Thanks