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7/28/2019 Project Tunnel
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Department Of Industrial
EngineeringProject management
Tunnel Project
Khamees Marwan(20090025070(
Mustafa Rozieh (20090025064(
)Zaid Ahmad Abo-elzait (20090025010
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Instructor: Eng Esraa saleh
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Introduction: scope and justification
it is known that the area aroundFiras Circle. Is one of the most
important regions in Amman city thats for a lot of reasons
including: -
1- Existence of Market Hussein
2- The area is filled with shoppers
3- This region is filled with hotels , restaurants; net cafs; game
shops coffee shops and of course a high population area
4- And a lot more reasons..
For those reasons a very annoying traffic jam is now a daily event
on Al-Hussein street "crowded traffic and accidents " which make a
lot of people wait for a really long time to get their homes ; class;
work places and other places
so we have considered to remove this jam but how !!!
the main target is to separate people going to Entertainmentspotsso we decided to build a tunnel under the existing Firas Circleand
remove the rotary which that would solve a very large part of our
problem and will not be stuck there for along time again.
Success and failure criteria:the project is considered successful if the traffic jam is reduced by
75 % for at least the next ten years and done by planned time>
If not the project is considered a failure.
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1D-Definition of the project:
a- Stake holders :
1- Shoppers and people and others.
2- Drivers for Public transportation (busses; taxies ..)
3- Workers at Restaurants , cafs, markets, book shops and other
shops
4- Municipal workers
5- Employees: engineers. workers , designers and others
6- People living around the working area
7- Real estate owners
8- Building materials seller
9- Workers at Banks in the area.
10-traffic department
11-police.
12-Garbage man
13-Tourists and Drs
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b- Strategic choices :time and quality is the most important strategic choices that wecare about as we see in fig 1
Fig 1 time and quality priority
c- Requirements of the project :
Input req. Process req. Outcome req.Shortest time Good work staff Traffic jam End
High quality Good teamwork Nice view
Good budget Firm work times Less accidents
Specified location equipment serve for very long time
Best designers Fast execution
Table 1
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d-Initial planning :
After getting the legal approval we start by closing the road
and making detour, then removing the rotary, cleaning area,
excavation operations and then foundation and columns are
to be laid.
in the mean while parts of tunnel are to be ready (beams) to
put on top of the columns and then we joint them together
and asphalting the tunnel .
We must take a look for the signs, lights and safety
measures.
The project will start 26/5/2012 and expected to be finished
01/8/2012.
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2D-design of the project:A-work breakdown structure:
activity
Activity DescriptionPredeces
sors
Duration
1 Start 1
2 getting legal approval and completing legalpapers from city hall
1 1
3 get the design of the tunnel by architect 2 5
4 make detour for Traffic 3 1
5 put guiding signs and flashy lights 4 1
6 Finally close the road around working area 5 1
7 cracking and drilling road asphalt 6 3
8 cracking and breaking al-Hussein circle 6 5
9 moving the breaked asphalt and other stufffrom the working area
"7;8" 2
10 a survey surveys the working area and makesigns on Excavation spots
9 1
11excavation operations using special digger"buclain" 10 5
12 planting steel inside holes 11 4
13 pouring concrete for foundation andColumns
12 8
14 painting concrete boundaries with petromin"special paint to resist salts from soil"
13 2
15 Pack filling holes with soil to street level 14 1
16 tunnel beam are pored with concrete oversteel and ready in near area
15 9
17 putting tunnel widthal beams over columnsusing crane
16 1
18 pouring concrete over beams to make themhold together
17 6
19 asphalting the tunnel 18 4
20 asphalting the road over the tunnel 18 4
21 asphalting lanes on sides over the tunnel 18 4
22 side walks and trash cans "19;20;21" 1
23 putting Concrete barriers on sides of tunnel 18 3
24 power lines and light 23 4
25 put Caution street signs and signals 24 2
26 finishing and cleaning "25;22" 1
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27 delivering the project 26 1
Table2
Node diagram activities:
9
1
2
3
4
6
87
9
5
10
11
12
13
14
15
16
17
18
19
27
2622
25
24
23
21 20
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Critical path analysis
A) 1-2-3-4-5-6-7-9-10-11-12-13-14-15-16-17-18-23-24-25-26-27 = 63
B) 1-2-3-4-5-6-8-9-10-11-12-13-14-15-16-17-18-23-24-25-26-27 = 65
C) 1-2-3-4-5-6-7-9-10-11-12-13-14-15-16-17-18-21-22-26-27 = 59
D) 1-2-3-4-5-6-8-9-10-11-12-13-14-15-16-17-18-21-22-26-27 = 61
E) 1-2-3-4-5-6-7-9-10-11-12-13-14-15-16-17-18-20-22-26-27 = 59
F) 1-2-3-4-5-6-8-9-10-11-12-13-14-15-16-17-18-20-22-26-27 = 61
G) 1-2-3-4-5-6-7-9-10-11-12-13-14-15-16-17-18-19-22-26-27 = 59
H) 1-2-3-4-5-6-8-9-10-11-12-13-14-15-16-17-18-19-22-26-27 = 61
So we have path
B) 1-2-3-4-5-6-8-9-10-11-12-13-14-15-16-17-18-23-24-25-26-27 = 65
The longest path
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(Critical path)
task EST LST EFT LFT Slake1 0 0 1 1 0
2 1 1 2 2 0
3 2 2 7 7 0
4 7 7 8 8 05 8 8 9 9 0
6 9 9 10 10 0
7 10 12 13 15 2
8 10 10 15 15 0
9 15 15 17 17 0
10 17 17 18 18 0
11 18 18 23 23 0
12 23 23 27 27 013 27 27 35 35 0
14 35 35 37 37 0
15 37 37 38 38 0
16 38 38 47 47 0
17 47 47 48 48 0
18 48 48 54 54 0
19 54 57 58 61 3
20 54 57 58 61 321 54 57 58 61 3
22 58 61 59 62 1
23 54 54 57 57 0
24 57 57 61 61 0
25 61 61 63 63 0
26 63 63 64 64 0
27 64 64 65 65 0
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Time planning
Activity Optimistic Most
likely
pessimistic ,Mean
,Variance
1 0.5 1 3 1.25 0.17361
2 0.5 1 2 1.08333 0.0625
3 1 2.5 10 3.5 2.25
4 0.5 1 2 1.08333 0.0625
5 0.5 1 3 1.25 0.17361
6 0.5 1.5 2 1.41667 0.0625
7 2 3.5 5 3.5 0.25
8 3 4.5 7 4.66667 0.44444
9 1 1.5 5 2 0.44444
10 0.5 1 3 1.25 0.17361
11 2 3.5 7 3.83333
0.69444
12 2 4 7 4.1666
7
0.6944
413 2 3 29 3.5 20.25
14 1 2.5 6 2.83333
0.69444
15 0.5 1 3 1.25 0.17361
16 5 6 35 10.66667
11.11111
17 0.5 1 4 1.4166
7
0.3402
818 3 5 10 5.5 1.3611
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1
19 2 2.5 17 4.83333 6.25
20 2 2.5 17 4.8333
3 6.2521 2 2.5 17 4.8333
3 6.25
22 0.5 1 3 1.25 0.17361
23 1 2.5 6 2.83333
0.69444
24 2 4.5 7 4.5 0.69444
25 1 2 4 2.16667 0.25
26 0.5 1 2 1.08333 0.0625
27 0.5 1 3 1.25 0.17361
= 81.74999 days
= 60.21524 days
= = 7.759847937 days
*We use more than one program to do calculationfirst of them we use Microsoft
after that we check by Matlab and Microsoft Excel
programs
*We used the Excel program to plot Beta distribution*we check by using website adrees given in slides
http://www.tutor-
homework.com/statistics_tables/statistics_tables.html
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http://www.tutor-homework.com/statistics_tables/statistics_tables.htmlhttp://www.tutor-homework.com/statistics_tables/statistics_tables.htmlhttp://www.tutor-homework.com/statistics_tables/statistics_tables.htmlhttp://www.tutor-homework.com/statistics_tables/statistics_tables.html7/28/2019 Project Tunnel
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"Pert"
Finishing probabilities
Req. =65
=81.74999
*probability of finishing the project in time:
z = = 2.15855
Area corresponding to z = -2.15855 from tables 0.01545
* Probability of finishing the project in 90% of the time:
90 % of original time = 58.5 days
z = = 3
Area corresponding to z = 3 from tables 0.00135
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= 7.759847937
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Every sigma for 7.759847937 days
1 finishes between 74 and 88 days 68%
1 finishes between 67 and 95 days 95%
1 finishes between 60 and 102 days 99%
Time Cost Trade Off
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First able we most know the normal and crash cost and time to
calculate and get the cheapest crash way available:
T = time in days
c = cost in J.D.
Task # Normal t Crash t Normal c Crash c C/t
1 1 - 50 - -
2 1 - 100 - -
3 5 3 75 100 12.5
4 1 - 30 - -
5 1 - 95 - -
61
- 150 - -7 3 2 200 300 100
8 5 2 400 160 80
9 2 1 80 130 50
10 1 - 50 - -
11 5 4 350 450 100
12 4 3 250 300 50
13 8 3 700 1075 75
14 2 - 100 - -15 1 - 75 - -
16 9 5 1500 2500 250
17 1 - 20 - -
18 6 2 450 580 32.5
19 4 3 300 420 120
20 4 3 300 420 120
21 4 3 300 420 120
22 1 - 45 - -23 3 1 230 300 35
24 4 2 460 580 60
25 2 1 100 185 85
26 1 - 20 - -
27 1 - 80 - -
total - - 6510 - -
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We used law:
Crash cost - Normal costNormal time crash time
We want to complete project in 75 % of its
estimated time so:
want to crash 17 days of critical path.
We have the approach of "crashing of activities"
*we start by the critical path
B) 1-2-3-4-5-6-8-9-10-11-12-13-14-15-16-17-18-23-24-25-26-27 = 65
This is what we start with
so:
we have considered the cheapest crash cost per
crash time
we notice that a lot of our reduced tasks are in
other tasks we hit two birds with one stone "
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1- Crash 2 days from activity # 3
total cost = 6510 + 2(12.5) =6535
2 Crash 4 days from activity #18
Total cost = 6535 + 4(32.5) =6665
3 Crash 2 days from activity #23
Total cost = 6665 + 2(35) =6735
4 Crash 2 days from activity #9
& crash 2 days from activity #12
Total cost = 6735 + (2+2) (50) =6935
5 Crash 2 days from activity #24
Total cost = 6935+ 2(60) =7055
6 Crash 5 days from activity #13
Total cost = 7055+ 5(75) =7430
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So our paths now:
A) 1-2-3-4-5-6-7-9-10-11-12-13-14-15-16-17-18-23-24-25-26-27 = 46
B) 1-2-3-4-5-6-8-9-10-11-12-13-14-15-16-17-18-23-24-25-26-27 = 48
C) 1-2-3-4-5-6-7-9-10-11-12-13-14-15-16-17-18-21-22-26-27 = 46
D) 1-2-3-4-5-6-8-9-10-11-12-13-14-15-16-17-18-21-22-26-27 = 48
E) 1-2-3-4-5-6-7-9-10-11-12-13-14-15-16-17-18-20-22-26-27 = 46
F) 1-2-3-4-5-6-8-9-10-11-12-13-14-15-16-17-18-20-22-26-27 = 48
G) 1-2-3-4-5-6-7-9-10-11-12-13-14-15-16-17-18-19-22-26-27 = 46
H) 1-2-3-4-5-6-8-9-10-11-12-13-14-15-16-17-18-19-22-26-27 = 48
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Source leveling:
Now in our projects we need to deal with workers
as little as we can and as less time as we can also:
tasks 21 and 23 are concurrent and 23 is in the
critical path and each needs 4 workers the whole
time until it finishes :
8 8 8 8
23
23
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so by source leveling and without wasting any
time we move task 21 3 days as its slack give uspermission to reduce # of workers to 4 each day
accept one day :
4 4 4 8 4 4 4
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21
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IMPORTANT NOTE:
All calculations were done at our hand and we
check by using programs
First of these programs are Microsoft project
also we done it by matlab and Excel
Each student in this project had taken one of
these programs and he was done calculations to
ensure that all student work in team and all of
whom participated in the completion of the project
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The end of project
Thanks