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www.nanohub.org NCN Lecture 8: Density of  States Muhammad Ashraful Alam [email protected] Alam ECE606 S09 1

Principles of Semiconductor Devices-L8

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Page 1: Principles of Semiconductor Devices-L8

8/8/2019 Principles of Semiconductor Devices-L8

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www.nanohub.org

NCN 

Lecture 8: Density of  States

Muhammad Ashraful [email protected]

Alam  ECE‐606 S09 1

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Outline

1) Calculation 

of  

density 

of  

states

 

3) Characterization of 

 Effective

 Mass

4) Conclusions

Reference: Vol. 6, Ch. 3 (pages 88‐96)

Alam  ECE‐606 S09 2

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Density of  States

E

4

A single

 band

 has

 total

 of 

 N

‐states

n y a  rac on o  s a es are occup e

How  many  states are occupied  upto E? 

Or equivalently…

1

How  many  states  per  unit  energy  ?  (DOS)

Alam  ECE‐606 S09 3

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Density of  States in 1‐D Semiconductors

a

 

E1 1States between + 2&

k   E E E  

ΔΔ = ×

E1+ΔE

k1+Δkk

122

 Naπ 

Δ

= ×

  Na k  Δ

E1

k

a

π 2

k π 

δ  =

1   E π  Δ

Alam  ECE‐606 S09 4

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1D‐DOS N atomsL

States/unit energy @ N  k a

 E  E π 

Δ

a

( )2 20

0 2

2

*

*

m E E k   E E k  

m

−− = ⇒ =

E

( )2

02

*dk 

m

 E E  E 

=−

E1+ΔE

k1+Δkk

1

( )2

0

States/unit energy @2

*m

 E 

 L E 

 E π =

E1

unit lengthStates/unit energy/ @

1 *

 E 

m DOS≡ =

k

a

π 2

k π 

δ  =

Alam  ECE‐606 S09 5

0π  −

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1D‐DOS

E E2

1

2

*m

 DOS E E π 

=−

a

π 2

k π 

Δ =

DOS

Alam  ECE‐606 S09 6

 NaConservation of  DOS

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Density of  States in 2D Semiconductors

b

a

Show that 2D DOS is a constant independent of energy!

Alam  ECE‐606 S09 7

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Density of  States in 3D Semiconductors

( )

1 1

3 3

States between + &

4 4

  E E E  

k dk k  π π 

Δ

+ −

Macroscopic Sample

2

2 2 2 2 H 

k k 

 L W π π π  π 

= = Δ

L

W

2

2unit energStates/ @

2y

V k 

 E  E k 

d π 

Δ=

2π/W2π/H

( )

( )

2 20

0 2 2

0

2 2

* *

*

m E E  mk dk   E E k  

m dE E E  

−− = ⇒ = ⇒ =

k

2π/L

1States/unit energy/unit volume @

**

 E 

m

K+dk

Alam  ECE‐606 S09 8

02 32π −

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3D‐DOS

* *

E E

3 3 0

2 3

m m

 DOS π 

=

a

π 

a

π −

2k 

π Δ =

DOS

Alam  ECE‐606 S09 9

 NaConservation of  DOS

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Outline

1) Calculation of 

 density

 of 

 states

 

3) Characterization of 

 Effective

 Mass

4) Conclusions

Alam  ECE‐606 S09 10

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Density of  States of  GaAs: Conduction/Valence Bands

* *

( ) 2 32

n n c

cg E  π 

=

( )2 3

2

2

* *

hh hhm m E E  υ 

π 

⎧ −⎪

( )

2* *

lh lh

g E 

m m E E  

υ 

υ 

= ⎨⎪

11

2 32π ⎪⎩

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Four valleys inside BZ for Germanium

Alam  ECE‐606 S09 12

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Outline

1) Calculation of 

 density

 of 

 states

 

3) Characterization of 

 Effective

 Mass

4) Conclusions

Alam  ECE‐606 S09 15

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Measurement of  Effective Mass

ν0=24 GHz

(fixed)

B field variable …

IoutIin

k  z

con

 Bqm* =

0vπ 

k  xk  y

   I  o  u   t  -   I   i

  n

16BBcon

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Motion in Real Space and Phase Space

Energy=constant.

Liquid He temperature …x

(kx,0)0,k

k y

k

y

(0,-k y)(-kx,0) k  z

k  xk  y

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Derive the Cyclotron Formula 0

2

qm*

B

vπ 

=

For an particle in (x‐y) plane with B‐field in z‐direction, 

2m* B B

υ υ υ = × =

B

  …

0

0 0

 z zr 

qB r υ  =m*

02 2r  m*

 B

π  π τ 

υ = =

00

1

2

qB

m*ν 

τ π ≡ =

Alam  ECE‐606 S09 18

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Effective mass in Ge

B

[ ] [ ] [ ] [ ]111 111 111 111

[ ] [ ] [ ] [ ]111 111 111 111

4 angles between B field and the ellipsoids …

Recall the HW1

Alam  ECE‐606 S09 19

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Derivation for the Cyclotron Formula

Show that 

2 2

2 2

1

c t l t  

cos sin

m m m m

θ θ = + Given three mc and three θ,

we will Find mt, and ml

The Lorentz

 force

 on

 electrons

 in

 a B

‐field

 

[ ]d 

F q B M  

dt 

υ υ = × =

( ) * x  x y z z y t  

d F q B B m

dt 

υ υ υ = − =

In other words, 

( ) y*

  y z x x z t  

d F q B B m

dt 

υ υ υ = − =

Alam  ECE‐606 S09 20

( ) * z  z x y y x l

F q B B mdt 

υ υ υ = − =

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Continued …kz

Let (B)

 make

 an

 angle

 (θ)

 with

 longitudinal

 axis

 of 

 the

 

ellipsoid (ellipsoids oriented along kz)

ky( ) ( )0 00  x y z  B B cos , B , B B sin ,θ θ = = =

Differentiate (vy) and use other equations to find …

2 2 2 2 2

20 with

l

 y

 y t t sin cosdt 

  B B B

wω ω υ 

υ ω ω θ θ  ⎡ ⎤+ = ≡ +⎣ ⎦

0 lt * * *c t lm m mω  ω ω  ≡ ≡ ≡

2 21 sin cosθ θ 

Alam  ECE‐606 S0921( )

2 2*

l t t c

m m mm= +so that …

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Measurement of  Effective Mass

B=[0.61, 0.61, 0.5]

[110]

1qB 

1, 

2, 

3Three masses  mc1,mc2,mc3

Three unique angles: 7, 65, 73 

2 21

t c l t 

cos sinm mm m

θ θ = + 02c

vπ 

Alam  ECE‐606 S09 22

Known θ and mc allows calculation of  mt and ml.

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Valence Band Effective Mass

HW. Which peaks relate to valence band? 

Alam  ECE‐606 S09 23

 

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Conclusions

1) Measurement of 

 Effective

 mass

 and

 band

 gaps

 define

 

the energy‐band of  a material. 

2) Only a fraction of  the available states are occupied. The 

number of 

 available

 states

 change

 with

 energy.

 DOS

 captures this variation. 

3 DOS is an im ortant and useful characteristic of  a 

material that

 should

 be

 understood

 carefully.

 

Alam  ECE‐606 S09 24