Preparation for Final_Exam Solutions SS2011

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  • 8/22/2019 Preparation for Final_Exam Solutions SS2011

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    Hochschule Ulm Prof. Dr. A. Beckmann

    University of Applied Sciences Control Technology

    Page 1

    Preparation for Final Exam - Solutions

    Describe using your own words:

    1. How can we assess whether the closed loop control system is stable or not?(2)

    If the plant is stable we can use the simple Nyquist criterion:

    We draw the frequency response locus of the open loop. If the critical point is always on the

    left side of the frequency response locus of the open loop then the closed loop is stable.

    2. What is the yquist plot? (4)

    In a Nyquist plot we plot the imaginary part of the frequency response as a function of its real

    part. If the critical point is always on the left side of the plot, the control system is stable.

    3. Describe the behaviour of the different parts of a PID-controller. (6)

    a) P-controller:

    The P-controller with gain KP,c is amplifying the error signal by a factor ofKP,c. This

    amplified signal is the input of the process. If the chosen gain is too high, the controlsystem may become unstable.

    b) I-controller:

    The I-controller with time constant Ti,c integrates the error signal of a time interval of

    length Ti,c. In this way the controller will respond to small deviations of the control

    systems output to the reference signal.

    c) D-controller:

    The D-controller with time constant Ti,c will compute the derivative of the error signal

    with respect of time. In this way the controller will respond to fast changes of the error

    signal, e.g. if a step input is applied or in case of disturbancies.

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    Hochschule Ulm Prof. Dr. A. Beckmann

    University of Applied Sciences Control Technology

    Page 2

    Preparation for Final Exam - Solutions

    4. The transfer functions of 2 dynamical systems are:

    93

    2)(1+

    =s

    ssG and55

    3)(2+

    =s

    sG .

    a) What type of element corresponds to system 1 and to system 2? (2)

    system 1 : DT1-element; system 2: PT1-element

    b) What is the transfer function, if the 2 elements are connected in series? Is this systemstable? (4)

    55

    3

    93

    2)()()( 21

    +

    +==

    ss

    ssGsGsGs

    1

    3

    3

    2

    15

    1

    +

    +=

    ss

    s

    2 poles: p1 = -3 ; p2 = -1 both have negative real part => stable

    c) What is the transfer function, if the 2 elements are connected in parallel? Is the

    system stable?

    55

    3

    93

    2)()()( 21

    ++

    +=+=

    ss

    ssGsGsGs

    1

    3

    5

    1

    3

    2

    3

    1

    ++

    +=

    ss

    s

    ( ) ( )( )( )31

    39110151

    ++

    +++=

    sssss

    ( )( )312791010

    15

    1 2

    ++

    +++=

    ss

    sss

    ( )( )31271910

    15

    1 2

    ++

    ++=

    ss

    ss

    2 poles: p1 = -3 ; p2 = -1 both have negative real part => stable

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    Hochschule Ulm Prof. Dr. A. Beckmann

    University of Applied Sciences Control Technology

    Page 3

    Preparation for Final Exam - Solutions

    5. A PT2-plant with( )( ) ( )( )1715

    1

    11

    1)(

    21 ++=

    ++=

    sssTsTsGP and an I-controller

    ssTsG

    c

    C12

    11)(

    ,1

    =

    = build up a unity negative feedback system.

    a) Calculate the spectral magnitude characteristics and the spectral phasecharacteristics for the open loop system.

    Transfer function:( )( ) sss

    sGsGsG CPOL12

    1

    1715

    1)()()(

    ++==

    ( ) ssssGOL

    12

    1

    11235

    1)(

    2

    ++

    =

    ssssGOL

    12144420

    1)(

    23++

    =

    Frequency Response:

    ( ) ( )3223 420121441

    12144420

    1)(

    +=

    +=

    iiiiGOL

    Trick 3: idcG +=

    1

    ;

    1

    22 dcG +=

    c

    d

    =tan

    ( ) ( )2322 42012144

    1)(

    +

    =iGOL

    36

    1053

    144

    42012)(tan

    2

    2

    3

    +=

    =

    b) Write down the transfer function of the closed loop control system and its systemparameters. (4)

    112144420

    1

    12144420

    12144420

    12144420

    11

    12144420

    1

    )(2323

    23

    23

    23

    +++=

    ++

    ++

    +++

    ++=

    ssssss

    sss

    sss

    ssssGcl

    System parameters: ;1;0;0;0;1;1;144;420 01230123 ======== bbbbaaaa

  • 8/22/2019 Preparation for Final_Exam Solutions SS2011

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    Hochschule Ulm Prof. Dr. A. Beckmann

    University of Applied Sciences Control Technology

    Page 4

    Preparation for Final Exam - Solutions

    6. A plant with the transfer function( )36

    3)(

    +=

    ssGP shall be controlled. The plant and

    the controller build up a unity negative feedback system. Check, if the transfer

    function of the closed loop control system will fulfill the requirement 1)0( =sGcl ,

    a) if we use a P-controller: transfer function of a P-controller: CPCP KsG ,, )( =

    ( ) ( )121

    36

    3)()()( ,,

    +=

    +==

    sK

    sKsGsGsG CPCPPCo

    ( )

    ( )

    ( )( )12

    12

    12

    1

    1

    12

    1

    )(1

    )()(

    ,

    ,

    +

    +

    ++

    +

    =+

    =s

    s

    sK

    sK

    sG

    sGsG

    CP

    CP

    o

    ocl

    CP

    CP

    clKs

    KsG

    ,

    ,

    12)(

    ++=

    CP

    CP

    CP

    CP

    clK

    K

    K

    KsG

    ,

    ,

    ,

    ,

    110)0(

    +=

    ++==

    The requirement cannot be fulfilled with a finite gain of the controller. We will

    have a constant control error in steady state. Therefore a P-controller is not a

    good choice for this plant.

    b) if we use an I-controller: transfer function I-controller:sT

    sGCI

    CI

    =

    ,

    ,

    1)(

    ( ) ( )1211

    36

    31)()()(

    ,, +

    =

    +

    ==

    ssTssTsGsGsG

    CICI

    PCo

    ( )

    ( )

    ( )

    ( )12

    12

    12

    11

    1

    12

    11

    )(1

    )()(

    ,

    ,

    ,

    ,

    +

    +

    +

    +

    +

    =

    +=

    ssT

    ssT

    ssT

    ssT

    sG

    sGsG

    CI

    CI

    CI

    CI

    o

    ocl

    ( ) 112

    1)(

    , ++=

    ssTsG

    CI

    cl

    12

    1)(

    ,

    2

    , ++=

    sTsTsG

    CICI

    cl

    11002

    1)0(

    ,,

    =++

    ==

    CICI

    clTT

    sG The requirement is fulfilled.

  • 8/22/2019 Preparation for Final_Exam Solutions SS2011

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    Hochschule Ulm Prof. Dr. A. Beckmann

    University of Applied Sciences Control Technology

    Page 5

    Preparation for Final Exam - Solutions

    7. The transfer function of a plant is:3

    22)(

    +

    +=

    s

    ssGP . It is controlled by a controller

    withs

    sGC6

    )( = . How can we find out whether the unity feedback system is stable or

    not.

    First we have to check whether the plant is stable itself:

    The transfer function of the plant is:3

    22)(

    +=

    s

    ssGP

    This transfer function has 1 pole: p1 = s = -3 pole has negative real part

    This plant is stable.

    Therefore we can apply the Simple Nyquist criterion:

    we have to check if the critical point is on the left of the frequency response locus. If this

    is true, the closed loop will be stable even if the open loop system is not stable.

    8. In the following diagram we see the frequency response locus of an open loop controlsystem. Is the closed loop control system stable?

    a) Im b) Im

    -2 -1 1 2 Re -1 -0,5 0,5 1 Re

    stable x not stable x stable not stable

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    Hochschule Ulm Prof. Dr. A. Beckmann

    University of Applied Sciences Control Technology

    Page 6

    Preparation for Final Exam - Solutions

    Bode Diagram

    Frequency (rad/sec)

    Phase(deg)

    Magnitude(dB)

    -40

    -20

    0

    20

    40

    60

    10-1

    100

    101

    -225

    -180

    -135

    -90

    Bode Diagram

    Frequency (rad/sec)

    Phase(deg)

    Magnitude(dB)

    -30

    -20

    -10

    0

    10

    10-1

    100

    101

    -90

    -45

    0

    45

    90

    135

    180

    225

    270

    9. Find out from the Bode plots the gain margin and the phase margin of each controlsystem.

    a)

    Gain margin: - 10 dB Phase margin: - 40

    Is the system stable? No

    b)

    Gain margin: + 25 dB Phase margin: + 90

    Is the system stable? Yes