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Practice Test 1 2009
Practice Series 1 2009ADDITIONAL MATHEMATICS 2
TIME: 1 HourAnswer all questions :
Section A
1.Solve the simultaneous equations
[ 5 marks ]
2.A curve with gradient function passes through through the
point (3, 10)
a) Find the equation of the curve.
[ 3 marks ]
b) Find the turning points and determine whether it is a maximum or minimum point.
[ 5 marks ]
3.Sketch the curve for.
[3 marks]Using the same axis, sketch the curve and hence state the number of solutions for the equation for.
[ 2 marks ]
4. ABCD is a trapezium. Given,. M is a mid point of BD and. Find:
i)
ii)
iii)
iv)
Section B
5.Table below shows the values of variables x and y obtained from an experimentx13579
y1.822.072.312.652.72
It is known that x and y are related by the equation with h and k are constants. It is given that one of the values of y is wrongly stated.
a)Plot a graph of against x using a scale of 2cm to 1 unit on both axes . Hence, draw the line of best fit [4 marks]
c) Use your graph to findi) Value of hii) Value of kiii) State the value of y that is incorrectly stated and state its actual value. [6 marks]
Section C
6.Table below shows the cost for four items in the year 2002 and 2003 and their weightages and the corresponding price indices for the year 2003 using the year 2002 as the base year.ItemCostYear 2002CostYear 2003Price indicesYear 2003Weightage
A12x1501
BY241203
C3042z2
D1013130m
a) Findi) x
ii) y
iii) z [3 marks]b) Given the composite index for year 2003 based on 2002 is 131, find m [2 marks]c) The weekly expenditure for the items in the year 2003 is RM300. Calculate the corresponding expenditure in year 2002. [2 marks]d) If the cost of item A increases by 20% from year 2003 to 2004 whereas the cost of other items remain unchanged, using the same weightage , calculate the composite index for 2004 based on 2002. [3 marks]
1.
Eliminate y
Solving quadratic equationX = (2, (3
y = 0, 4
2.a)
b) Using
X= 0, 2
(0, 10),
Differentiate
And find
Max
Min
3. Shape of
Max = 1 and Min
2 rounds y = x /
4.
x13579
3.314.285.347.027.40
N1Plot (correct axis and scale uniform)
5 points ploted correctly
Best fit line
k = y-intercept
h = gradient
k=2.8
=0.5
y = 2.53
5. a) Using
x = 18
y = 20
z =140
b)
= 131
m = 4
c)
d)
=134
K1
P1
K1
N1
N1
Substitute (3, 10)
N1
K1
K1
K1
N1
K1
K1
N1
1
EMBED Equation.3
EMBED Equation.3
EMBED Equation.3
EMBED Equation.3
EMBED Equation.3
EMBED Equation.3
EMBED Equation.3
EMBED Equation.3
EMBED Equation.3
N1
K1
Sketch line EMBED Equation.3
No of solution = 3
P1
P1
P1
N1
K1
N1
N1
K1
N1
K1
N1
P1
K1
N1
N1
N1
K1
N1
K1
N1
N1
K1
A
D
B
C
ANSWER SCHEME Practice Series 1 2009
ADDITIONAL MATHEMATICS 2
PAGE 3
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