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Population Genetics

Population Genetics

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Population Genetics. Macrophage. CCR5 CCR5- D 32. What accounts for this variation? Random? Past epidemics (plague, smallpox)?. What will happen to this variation in the future? Will D 32 allele increase in frequency?. - PowerPoint PPT Presentation

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Page 1: Population Genetics

Population Genetics

Page 2: Population Genetics
Page 3: Population Genetics

Macrophage

Page 4: Population Genetics

CCR5 CCR5-32

Page 5: Population Genetics
Page 6: Population Genetics

What accounts for this variation? Random? Past

epidemics (plague, smallpox)?

What will happen to this variation in the future? Will 32 allele

increase in frequency?

Page 7: Population Genetics

These are the questions that “population genetics” is designed to address

Page 8: Population Genetics

Hardy-Weinberg Principle

1. Allele frequencies remain constant from generation to generation unless some outside force is acting to change them

2. When an allele is rare, there are many more heterozygotes than homozygotes (if p is small, then ____ is very small)

Page 9: Population Genetics

Assumptions of H-W1) Mating is random across the entire population.2) All genotypes have equal viability and fertility (no

selection).3) Migration into the population can be ignored.4) Mutation does not occur, or is so rare it can be ignored.5) Population is large enough that the allele frequencies

do not change from generation to generation due to chance (random genetic drift).

6) Allele frequencies are the same in females and males.

Page 10: Population Genetics

Usefulness of H-WIf you know the allele frequencies, you can

predict the genotype frequencies:

Q: In S. France, the frequency of the 32 allele is 10% (i.e., q=0.10). What proportion of individuals will be homozygous for the allele? What proportion will be heterozygous?

AA Aa aa

p2 2pq q2

Page 11: Population Genetics

Usefulness of H-WIf you know the frequency of one of the

homozygous genotypes, you can estimate allele frequencies, and predict the frequencies of the other genotypes.

Q: Among individuals of European descent, 1/1700 newborns have cystic fibrosis (a recessive genetic disorder). What proportion of this population are heterozygous carriers?

Hint: q2 = 1/1700 = 0.00059

A:

Page 12: Population Genetics

Multiple Alleles: ABO blood types

p = freq of A alleleq = freq of B alleler = freq of O allele

Expansion of [p + q + r]2 = p2 + q2 + r2+ 2pq + 2pr + 2qr

Page 13: Population Genetics

Assumptions of H-W1) Mating is random across the entire population.2) All genotypes have equal viability and fertility (no

selection).3) Migration into the population can be ignored.4) Mutation does not occur, or is so rare it can be

ignored.5) Population is large enough that the allele

frequencies do not change from generation to generation due to chance (random genetic drift).

6) Allele frequencies are the same in females and males.

Page 14: Population Genetics

What happens when any of these assumptions are

violated?SelectionMutationNon-random mating______________________________

If any of these processes are occurring, will tend to get ____________ from H-W expected proportions

Page 15: Population Genetics

How can we detect deviation from H-W expectations?

Do observed genotype frequencies match HW expectations?

Page 16: Population Genetics

Do observed genotype frequencies match HW expectations?

MM MN NNp2 2pq q2

0.294 0.496 0.209

Genotypes Expected Observed MM 294.3 298 MN 496.4 489 NN 209.3 213

p=.5425 q=.4575

Page 17: Population Genetics

Test for H-W Genotype Frequencies

Genotypes Expected Observed MM 294.3 298 MN 496.4 489 NN 209.3 213

Page 18: Population Genetics

Importance of H-WH-W is an important tool for population

genetics.If assumptions are met, we can use it to

estimate allele and genotype frequencies that would otherwise be difficult to measure.

If assumptions are not met (can be tested statistically), then we know that some outside force is perturbing allele or genotype frequencies.

Page 19: Population Genetics

Change in allele frequencies over generations

Evolution is defined as a change in allele (or genotype) frequencies

over generations, and evolution will be caused by violation of any

of the assumptions of H-W.

Page 20: Population Genetics

Forces that cause deviation from H-W (evolution)

1. Selection2. Mutation3. Genetic Drift4. Nonrandom Mating5. Gene Flow (Migration)

Page 21: Population Genetics
Page 22: Population Genetics

Genotype A has a constitutive mutation for enzyme production in the lactose operon.

B is the normal inducible lactose operon.

A and B grown together in environment with limited lactose.

Page 23: Population Genetics
Page 24: Population Genetics

p = 0.5, q = 0.5

Genotypes Number:

AA 25

Aa 50

aa 25

Survival to reproduction

25100% = 1

50100% = 1

2080% = 0.8

Gamete contribution

25/95 A 25/95 A; 25/95 a

20/95 a

New allele frequencies?

New genotype frequencies (assume random mating):

p = = ____ q = = ____

AA Aa aa0.28 0.50 0.22

Page 25: Population Genetics

Consistent differences in survival or reproduction between genotypes = genotypic-specific differences in fitness

When fitness values are expressed on a scale such that highest fitness=1, then the values are called relative fitness

To conveniently calculate change in allele frequency due to selection, need concept of average fitness

Page 26: Population Genetics

Change in allele frequencyGenotype AA Aa aa

Genotype Frequency p2 2pq q2

Relative Fitness WAA WAa Waa

W=average fitness= (p2WAA)+ (2pqWAa)+ (q2WAa)

Freq of A after one gen. of selection: p' = p2 WAA/W + pqWAa/W

Freq of a after one gen. of selection: (1-p’) or:

q'= q2 Waa/W + pqWAa/W

Page 27: Population Genetics

CCR5 Example; p(+)=0.9; q(32)=0.1Genotype frequency:

+/+ p2=0.81

+/32 2pq=0.18

32/32 q2=0.01

Relative Fitness W+/+=0.99 W+/32=0.99 W32/32=1.0Average fitness W = 0. 81*0.99 + 0.18*0.99 + 0.01*1 = 0.9901

q'=q2W32/32/W + pqW+/32 /W=0.01009 +0.089991=0.100091

p’= 1-q’ = 0.89999

Next generation genotype freq.

p2

0.809982pq

0.18016q2

0.01002

Page 28: Population Genetics

q q2

Page 29: Population Genetics

Selection will increase the frequency of 32 allele

Selection is relatively weak

The favored allele is recessive

and the favored genotype is very rare

The change in allele frequency (response to selection) will be relatively slow

Page 30: Population Genetics

Response to selection can be fast!

Selection is strong

Favored allele is partially dominant

Both alleles are common

Page 31: Population Genetics
Page 32: Population Genetics

Selection is not always “Directional”

Heterozygote advantageFrequency dependence

Selection varying in space or time

Page 33: Population Genetics

Heterozygote advantage

Fitness A a a aA A

Page 34: Population Genetics

HbA/HbA HbA/HbS HbS/HbS

Relative Fitness 0.88 1.0 0.14

Fitness (in symbols) 1-t 1 1-s

Selection coefficients t=0.12 s=0.86

Relative fitness of hemoglobin genotypes in Yorubans

Equilibrium frequencies:peq = s/(s+t) = 0.86/(0.12+0.86) = 0.88qeq = t/(s+t) = 0.12/(0.12+0.86) = 0.12Predict the genotype frequencies (at birth):HW proportions 0.774 0.211 0.0144

Page 35: Population Genetics

Variable selection: genotypes have different fitness effects in different environments

0.4

0.5

0.6

0.7

0.8

0.9

1

Env. 1 Env. 2 Env. 3

AAAaaa

Fitness

Page 36: Population Genetics

Frequency-dependent selection

Page 37: Population Genetics

Other Examples of Freq-dep. Selection