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POINT OF DISCONTINUITYNotes 11.3
A point of discontinuity is the __________________ of a point where the graph of a function f(x) is ________ ______________________
Points of discontinuity have already been introduced in this unit as asymptotes in the reciprocal function graph . In this section, we will look at many rational
functions. We will identify additional points of discontinuity called “holes” in graphs.
x-coordinate
not continuous
REMOVABLE AND NON-REMOVABLEDISCONTINUITY
Removable Non-removable ________ in the graph Could be ________________ if
_____________ the function at that point
The hole occurs in the equation where there is a common factor in the numerator and denominator, thus the ______________ function is ______________ at a specific
x-value
Holecontinuous
redefine
ORIGINALundefined
____________ in the graph There is no way to if
___________ the function at that point to make it continuous
Asymptote
redefine
By the way, continuous graphs have no jumps, breaks, holes or asymptotes!!
FIND POINT OF DISCONTINUITY : ASYMPTOTES
If Exponent is:
y=___ BOB0
BOTN
EATS DC
Y=0
No H.A.
Divide Coefficients of leading term
Simplify Function and set denominator equal to zero and solve for x
Bigger on bottom…0
Bigger on top…none
Exponents are the same
x=___Vertical Asymptote:
Horizontal Asymptote: Asymptote is
H.
Asymptote:
V. Asymptote:
24
1)(
x
xxf
y = 3
X = -4
X Y
-6
-5
-4
-3
-2
4.5
1.5
6
0
und
EATS DC
Set denominator equal to 0
Ex.
Divide coefficients and get 1 for the fraction but then add the constant of 2
Pick 2 x-values to left and right of V.A.
This is non-removable discontinuity bc you can’t redefine the fcn and make the graph continuous
FIND POINT OF DISCONTINUITY : HOLE(S)
1. Look at the given equation. 2.Factor the numerator and denominator3. If there is a common factor, set that factor equal to zero and solve for x.4.This x-value is where there will be a hole in the graph.
Graph)3(
)32( 2
x
xxy
)3(
)1)(3(
x
xx
BOTN so no H.A.
x+3 either causes a V.A. or a hole…
Because x+3 factors out, there is a hole in the graph at x = – 3
1xEX:
This is removable discontinuity bc you can redefine the fcn at f(-3)=-4 and make the graph continuous
H. Asymptote:
Hole:
V. Asymptote:
4
122
2
x
xxy
y = 1
x = 2 and x = – 2
X Y
-4
-3
-1
0
1
3
4
4
3
2/3
0
10/3
EATS DC
Set denominator factors equal to 0
Ex
Divide leading coefficients and get 1 for the fraction
Pick x-values to left and right of V.A..
This is non-removable discontinuity bc you can’t redefine the fcn and make the graph continuous
Factor to see if anything factors out.
)2)(2(
)3)(4(
xx
xx
Nothing factors out so there is no hole in the graph.
0
-1.2
THE FUNCTION BELOW GIVES THE CONCENTRATION OF THE SALINE SOLUTION
AFTER ADDING X ML OF THE 0.5% SOLUTION TO 100 ML OF THE 2% SOLUTION.
How many mL of the 0.5% solution must you add for the combined solution to have a concentration of 0.9%?
solutionagetto
solutionofmL
%9.
%5.0275
x
xy
100
)005.0()02.0)(100(
xx 005.2)100(009.0
xx 005.2009.9.
1.1004. x
275x
You can also check this on the graphing calculator. Type the right side of equation into y1 and input 0.009 into y2. Use the intersection function (2nd calc 5) to solve for x.
H.
Asymptote:
y=x-5 R12
BOTN Divide using synthetic division
Oblique Asymptote(not tested)Opt
Bigger by one degree so there is an oblique asymptote
3
32)(
2
x
xxxf
1 – 2 – 3
–3
1
–3
–5
15
12y = x – 5 is the oblique asymptoteGraph on the TI84 to see what it looks like.
11.3 Vocabulary Support Attributes of Rational Functions Concept List
Choose the concept from the list above that best represents the item in each box.
1. the line that a graph approaches as y increases in absolute value
2. In the denominator, these reveal the points of discontinuity.
3. This type of discontinuity appears as a hole in the graph.
4. This type of graph has no jumps, breaks, or holes.
5. a function that you can write in the form
Vocab clarification : Match the following then discuss