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Physics 2101 Section 6 November 8 th : finish Ch.16 Lecture Notes : http://www.phys.lsu.edu/classes/fall2012/phys2101-6/ Announcement: Exam # 3 (November 13 th ) Lockett 10 (6 – 7 pm) Nicholson 109, 119 (extra time 5:30 – 7:30 pm) Covers Chs. 11.7-15

Physics 2101 Section 6 November 8 finish Ch

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Page 1: Physics 2101 Section 6 November 8 finish Ch

Physics 2101 Section 6

November 8th: finish Ch.16

Lecture Notes: http://www.phys.lsu.edu/classes/fall2012/phys2101-6/

Announcement: •  Exam # 3 (November 13th) Lockett 10 (6 – 7 pm) Nicholson 109, 119 (extra

time 5:30 – 7:30 pm) Covers Chs. 11.7-15

Page 2: Physics 2101 Section 6 November 8 finish Ch

Transverse Traveling Wave

y(x,0) = ymax sin kx( )

k =2πλ

Spatially Periodic ( repeats ) : kλ = 2π

Wave number Wavelength

Transverse: Displacement of particle is perpendicular to the direction of wave propagation

Longitudinal: Displacement (vibration) of particles

is along same direction as motion of wave

Traveling Waves - they travel from one point to another Standing Waves - they look like they’re standing still

vwave =dxdt

=ωk

=λT

= λf

Wave Speed

vwave =τµ

= λf For transverse wave in physical medium

Page 3: Physics 2101 Section 6 November 8 finish Ch

k =2πλ

ω =2πT

phase : kx ±ωt

kx +ωt⇒

kx −ωt⇒ Wave traveling in + x direction

Wave traveling in - x direction

Page 4: Physics 2101 Section 6 November 8 finish Ch
Page 5: Physics 2101 Section 6 November 8 finish Ch

Interference  Waves  

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Problem  16-­‐33:  Interference  of  Waves  Two sinusoidal waves with the same amplitude ym=9.00 mm and the same wavelength λ travel together along a string that is stretched along the x axis. Their resultant wave is shown twice in the figure, as the valley A travels in the negative direction by a distance d=56.0 cm in Δt=8.0 ms. The tick marks along the x axis are separated by Δx=10 cm, and the height H is 8.0mm. Assume the first wave is given by Find (a) y’m, (b) k, (c) ω, (d) φ2, and the sign in front of ω.

y1(x,t) = ym sin(kx ±ωt)

The two waves have the same λ and kThey are in the same string so the velocity is the same

v =ωk

: so ω is same in both waves

y '(x,t) = 2ym cosφ2

2$

%&'

()sin(kx + ±1ωt ±2 ωt

2+φ2

2)

y 'm =H2= 2ym cos

φ22

cosφ22=

H4ymv ≡ ±1ω ±1 ω

2k=dΔt

need positive sign on both

ω =dkΔt

Page 7: Physics 2101 Section 6 November 8 finish Ch
Page 8: Physics 2101 Section 6 November 8 finish Ch

Standing  Waves  

Wavelength: Define:

Page 9: Physics 2101 Section 6 November 8 finish Ch

Standing  Waves  

frequency

wave velocity

Page 10: Physics 2101 Section 6 November 8 finish Ch

       Standing  Waves  

Page 11: Physics 2101 Section 6 November 8 finish Ch

Example  

Solution: use

T1 +T2 = 2T = Mg

T1 = T2 =12Mg

ν2 =T2µ2

=Mg2µ2

ν1 =T1µ1

=Mg2µ1

Page 12: Physics 2101 Section 6 November 8 finish Ch

Example  -­‐  con>nued  

Solution:

use

T1 = M1g

T2 = M2g

ν2 =T2µ2

=M2gµ2

ν1 =T1µ1

=M1gµ1

Page 13: Physics 2101 Section 6 November 8 finish Ch

Problem  16-­‐58  

b) If the mass of the block is m, what is the corresponding n?

Page 14: Physics 2101 Section 6 November 8 finish Ch

Problem  16-­‐49:  Standing  waves/resonances  

A nylon guitar string has a linear density of µ=7.20 g/m and is under a tension of τ=150 N. The fixed supports are a distance D=90. cm apart. It oscillates with the pattern shown in the figure. Calculate the (a) speed, (b) wavelength, and (c) frequency of wave.

(a) Speed of wave

v =τµ=

150N7.20x10−3kg / m

= 144.3ms

(b) Wavelengt λ: look at figure

D =3λ2

: λ= 23D = 0.60m

(c) frequency f= vλ

f =144.3m / s

0.6m= 241Hz

Page 15: Physics 2101 Section 6 November 8 finish Ch

Problem  16-­‐59  

Page 16: Physics 2101 Section 6 November 8 finish Ch

Solu>on  for  Problem  16-­‐59  

From

m = ρV = ρAL

ν2 =τµ2

=τρ2A

Page 17: Physics 2101 Section 6 November 8 finish Ch

Problem  16-­‐11  

From

ν 2 =τ 2µ2

=τ 2µ

ν1 =τ1µ1

=τ1µ

L1 = L =n1λ12

=n1v12 f

L2 = L =n2λ22

=n2v22 f

n1v1 = n2v2

n1n2

=v2v1

=τ 2τ1

Page 18: Physics 2101 Section 6 November 8 finish Ch

 

frequency

wave speed

Page 19: Physics 2101 Section 6 November 8 finish Ch

Chapter  18:  Temperature,  Heat,  and  Thermodynamics    

Definitions

“System”- particular object or set of objects

“Environment” - everything else in the universe

What is “State” (or condition) of system?

- macroscopic description - in terms of detectable quantities:

volume, pressure, mass, temperature (“State Variables”)

Study of thermal energy --> temperature

Page 20: Physics 2101 Section 6 November 8 finish Ch

Temperature  &  Thermometers  

Linear scale : need 2 points to define

Fahrenheit [° F] body temp and ~1/3 of body temp ~100 ° F ~33 ° F Celsius [° C] “freezing point” and “boiling point” of water 0 ° C 100 ° C

Conversion factors K→ ° C ° C → ° F

TF = 95TC + 32

TC =TK − 273.15 (1 ΔK = 1 ΔC)

Kelvin [K] Absolute zero and triple point of water 0 K 273.16 K

Page 21: Physics 2101 Section 6 November 8 finish Ch

18-­‐3:  Zeroth  Law  of  Thermodynamics    

Defines THERMAL EQUILIBRIUM If two systems are in thermal equilibrium with a third, then they are in

thermal equilibrium with each other T1 = T2 = T3

No Heat flow

In this case: a)  A is in thermal equilibrium with T

b) B is in thermal equilibrium with T

c) A & B are in thermal equilibrium

Page 22: Physics 2101 Section 6 November 8 finish Ch

18-­‐4:  Measuring  Temperature  

Phase Diagram of Water

Need two points and linear scale T=absolute zero

Water triple point.

Page 23: Physics 2101 Section 6 November 8 finish Ch

18-­‐4:  Measuring  Temperature  

Triple Point of Water: Defined as T3=273.16 K

A gas filled bulb is connected to a Hg manometer. The pressure volume can be maintained constant by raising or lowering the the Hg level in reservoir R.

The Constant-Volume Gas Thermometer

T of liquid defined at T=Cpp = p0 + ρg(−h)

T = T3pp3

!

"#$

%&= (273.16K ) p

p3

!

"#$

%&

(C=constant)

Page 24: Physics 2101 Section 6 November 8 finish Ch

18-­‐4:  Measuring  Temperature  

A gas filled bulb is connected to a Hg manometer. The pressure volume can be maintained constant by raising or lowering the the Hg level in reservoir R.

The Constant-Volume Gas Thermometer

T of liquid defined at T=Cpp = p0 + ρg(−h)

T = T3pp3

!

"#$

%&= (273.16K ) p

p3

!

"#$

%&

Still have a problem because answer depends upon p.

T = (273.16K ) lim p→0pp3

"

#$%

&'

Keep V fixed: Figure shows Measurement for boiling water

Page 25: Physics 2101 Section 6 November 8 finish Ch

Checkpoint  1:    The  figure  here  shows  three  linear  temperature  scales  with  the  freezing  and  boiling  points  of  water  indicated.        

18-­‐4:  Temperature  Scales  

(a) Rank the degrees on these scales by size, greatest first.

Page 26: Physics 2101 Section 6 November 8 finish Ch

Checkpoint  1:    The  figure  here  shows  three  linear  temperature  scales  with  the  freezing  and  boiling  points  of  water  indicated.        

18-­‐4:  Temperature  Scales  

(b) Rank the following temperatures, highest first: 50oX, 50o W and 500 Y

Page 27: Physics 2101 Section 6 November 8 finish Ch

Thermal  expansion  Most substances expand when heated

and contract when cooled

ZrW2O8 is a ceramic with negative thermal expansion over a wide temperature range, 0-1050 K

The change in length, ΔL ( = L - L0 ), of almost all solids is ~ directly proportional to the change in temperature, ΔT ( = T - T0 )

ΔL =αL0ΔTL = L0 1+αΔT( )

α = coefficient of thermal expansion

What causes thermal expansion?

Page 28: Physics 2101 Section 6 November 8 finish Ch

Thermal  expansion  of  the  Brooklyn  Bridge  

Problem 1: Brooklyn Bridge Expansion The steel bed of the main suspension bridge is 490 m long at + 20°C. If the extremes in temperature are - 20°C to + 40°C, how much will it contract and expand?

α steel =12 ×10−6(°C)–1

ΔL =α steelL0ΔT=12 ×10−6(°C)–1(490m)(60°C)= 35 cm

The solution is to use expansion joints

Page 29: Physics 2101 Section 6 November 8 finish Ch

Thermal  expansion  and  a  Pendulum  Clock  

A pendulum clock made of brass is designed to keep accurate time at 20°C. If the clock operates at 0°C, does it run fast or slow? If so, how much?

Problem 2: Pendulum Clock

If the original period was 1 second

T = 2π Lg

L = L0 + ΔL= L0 +αbrassL0ΔT

L0 =1s2π#

$ %

&

' ( 2

g = 24.824 cm

L = 24.824 cm 1+ (19 ×10−6 /°C)(−20°C)( )= 24.824 cm 0.9996( )= 24.814

The new period is:

T = 2π 24.8149.8

= 0.9998 s

It runs slow (less time per tick) at 20°C at 0°C: fewer ticks = 1.7hr/yr

# ticks = 24 *60*60 = 86400# ticks = 86400 *0.999 = 86383

Page 30: Physics 2101 Section 6 November 8 finish Ch

Example:  Bimetal  Strip      

Common device to measure and control temperature

F = kx = kL0 1+αΔT( )

Page 31: Physics 2101 Section 6 November 8 finish Ch

18-­‐6  Area  Expansion    

Expansion in 1-D

ΔL =αL0ΔTL = L0 1+αΔT( )

A = L0 1+αΔT( )#$ %& W0 1+αΔT( )#$ %&Expansion in 2-D

ΔA = A0 1+αΔT( )2 − A0= A0 2αΔT + αΔT( )2( )≅ A0 2α( )ΔT≅ A0βΔT

β = 2α

Page 32: Physics 2101 Section 6 November 8 finish Ch

Thermal  expansion  of  holes  

Do holes expand or contract when heated?

Does radius increase or decrease

when heated?

The hole gets larger too!

Page 33: Physics 2101 Section 6 November 8 finish Ch

When  the  temperature  of  the  piece  of  metal  shown  below  is  increased  and  the  expands    metal  expands,  what  happens  to  the  gap  between  the  ends?    

1.  It  becomes  narrower  2.  It  becomes  wider  3.  It  remains  unchanged  

Clicker Question

Page 34: Physics 2101 Section 6 November 8 finish Ch

Volume  expansion  

Expansion in 1-D

ΔL =αL0ΔTL = L0 1+αΔT( )

width

heig

ht

Expansion in 3-D

V = L0 1+αΔT( )[ ] W0 1+αΔT( )[ ] H 0 1+αΔT( )[ ]

ΔV =V0 1+αΔT( )3 −V0=V0 3αΔT + 3 αΔT( )2 + αΔT( )3( )

≅V0 3α( )ΔT≅V0βΔT β = coefficient of volume expansion

Problem 3: Gas tank in the sun The 70-L steel gas tank of a car is filled to the top with gasoline at 20°C. The car is then left to sit in the sun, and the tank reaches a temperature of 40°C. How much gasoline do you expect to overflow from the tank? [gasoline has a coefficient of volume expansion of 950×10-6/°C ]

Volume expansion coefficients

solids : 1− 87 ×10−6 C liquids : 210 −1100 ×10−6 C gasses : 3400 ×10−6 C