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PH0101 UNIT 1 LECTURE 4 1 PH0101 UNIT 1 LECTURE 4 • Non-Uniform Bending (Theory and Experiment) • I-Shape Girder

PH0101 UNIT 1 LECTURE 4

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PH0101 UNIT 1 LECTURE 4. Non-Uniform Bending (Theory and Experiment) I-Shape Girder. Non-Uniform Bending. If the beam is loaded at its mid-point, the depression produced will not form an arc of a circle. This type of bending is called non-uniform bending. - PowerPoint PPT Presentation

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Page 1: PH0101 UNIT 1 LECTURE 4

PH0101 UNIT 1 LECTURE 4 1

PH0101 UNIT 1 LECTURE 4

• Non-Uniform Bending (Theory

and Experiment)

• I-Shape Girder

Page 2: PH0101 UNIT 1 LECTURE 4

PH0101 UNIT 1 LECTURE 4 2

Non-Uniform Bending

If the beam is loaded at its mid-point, the depression produced will not form an arc of a circle. This type of bending is called non-uniform bending.

Page 3: PH0101 UNIT 1 LECTURE 4

PH0101 UNIT 1 LECTURE 4 3

Consider a uniform beam (or rod or bar) AB of length l arranged horizontally on two knife edges K1 and K2 near the ends A and B as shown in Figure.

E

K2K1

BA

W/2W/2

W

Page 4: PH0101 UNIT 1 LECTURE 4

PH0101 UNIT 1 LECTURE 4 4

• A weight W is applied at the midpoint E of the beam.

• The reaction at each knife edge is equal to W/2 in the upward direction and ‘y’ is the depression at the midpoint E.

• The bent beam is considered to be equivalent to two single inverted cantilevers, fixed at E each of length and each loaded at K1 and K2 with a weight

2

l

2

W

Page 5: PH0101 UNIT 1 LECTURE 4

PH0101 UNIT 1 LECTURE 4 5

In the case of a cantilever of length l and load W,

the depression =

Hence, for cantilever of length and load , the depression is

YI

lW

g3

3

2

2

W

YI

lW

g3

22

3

y=

Page 6: PH0101 UNIT 1 LECTURE 4

PH0101 UNIT 1 LECTURE 4 6

If M is the mass, the corresponding weight W is

YI

lWy

g48

3

or

W = Mg

If the beam is a rectangular, Ig = ,

where b is the breadth and d is the thickness of the beam.

12

3bd

Page 7: PH0101 UNIT 1 LECTURE 4

PH0101 UNIT 1 LECTURE 4 7

Ybd

glMy

3

3

48

12

ybd

glMY

3

3

4

Hence,

or

The value of young’s modulus, Y can be determined by the above equation.

Ybd

lMgy

1248

3

3

Page 8: PH0101 UNIT 1 LECTURE 4

PH0101 UNIT 1 LECTURE 4 8

Experiment The given beam AB of rectangular cross section

is arranged horizontally on two knife edges K1 and K2 near the ends A and B as shown in Figure

A

K1K2

B

Page 9: PH0101 UNIT 1 LECTURE 4

PH0101 UNIT 1 LECTURE 4 9

• A weight hanger is suspended and a pin is fixed vertically at mid-point .

• A microscope is focused on the tip of the pin. • The initial reading on the vertical scale of the

microscope is taken.

• A suitable mass M is added to the hanger.

Page 10: PH0101 UNIT 1 LECTURE 4

PH0101 UNIT 1 LECTURE 4 10

• The beam is depressed.

• The cross wire is adjusted to coincide with the tip of the pin.

• The reading of the microscope is noted.

• The depression corresponding to the mass M is found.

Page 11: PH0101 UNIT 1 LECTURE 4

PH0101 UNIT 1 LECTURE 4 11

• The experiment is repeated by increasing and decreasing the mass step by step.

• The corresponding readings are tabulated.

• The average value of depression, y is found from the observations.

Page 12: PH0101 UNIT 1 LECTURE 4

PH0101 UNIT 1 LECTURE 4 12

Load in Kg

Microscope readings for depression Mean depression,y

for a load of M

Load increasing

cm

Loaddecreasing

cmMean cm

W

W+50 gms

W+100 gms

W+150 gms

W+200 gms

W+250 gms

Page 13: PH0101 UNIT 1 LECTURE 4

PH0101 UNIT 1 LECTURE 4 13

The breadth b, the thickness d and length l of the beam are measured. The value of Y for the material of the beam is found by the relation.

ybd

gMY

3

3

4

Page 14: PH0101 UNIT 1 LECTURE 4

PH0101 UNIT 1 LECTURE 4 14

I Shape Girder

• A girder is a metallic beam supported at its two ends by pillars or on opposite walls.

• It should be so designed that it should not bend too much or break under its own weight.

Page 15: PH0101 UNIT 1 LECTURE 4

PH0101 UNIT 1 LECTURE 4 15

The depression (y) at the center of a beam of length l, breadth b and thickness d under a load Mg at its mid-point is given as

Ybd

lMgy

3

3

4

Page 16: PH0101 UNIT 1 LECTURE 4

PH0101 UNIT 1 LECTURE 4 16

• Hence to reduce the bending for a given load,Young’s modulus Y of the material of the beam should be large, b and d of the beam must also be large.

• The length should be as small as possible.

• Since depression y is inversely proportional to d3, the depression can be reduced more effectively by increasing the thickness d rather than increasing the breadth b of the beam.

Page 17: PH0101 UNIT 1 LECTURE 4

PH0101 UNIT 1 LECTURE 4 17

But on increasing the thickness, unless the load is at the centre, the beam may bend This is called buckling of the beam.

(a) Buckling

b

d

Page 18: PH0101 UNIT 1 LECTURE 4

PH0101 UNIT 1 LECTURE 4 18

• To prevent buckling, a large load-bearing surface is required.

• Hence, the beam is designed to have a large thickness to minimize bending and a large load bearing surface to prevent buckling.

• The shape which satisfies these conditions is I. So it is called the I section of the beam or girder.

Extra material

Removed (b) I shape

Page 19: PH0101 UNIT 1 LECTURE 4

PH0101 UNIT 1 LECTURE 4 19

Features of I shape girder

• As the layers of the beam at the upper and bottom are subjected to maximum stress, more material must be needed there to withstand the strain.

• As the stress around the neutral layer is small, material in these regions can be removed without loss of efficiency.

• This would save economy (cost of material of the girder).

Page 20: PH0101 UNIT 1 LECTURE 4

PH0101 UNIT 1 LECTURE 4 20

• Iron girders used in buildings can be easily made of I-section.

• This type of cross-section provides a high bending moment and a lot of material is saved.

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PH0101 UNIT 1 LECTURE 4 21

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